Evolution happens by which process?


A Passing on traits acquired during the organism's lifetime
B Mutating to survive
C The fossil record shows no evidence of evolution
D Natural selection

It is possible to produce 2.33 grams of \(Fe(OH)_3\) from 262.5 mL of 0.25 M NaOH.

We need to use stoichiometry and the balanced chemical equation for the reaction between \(NaOH\) and \(FeCl_3\):

\(FeCl_3 + 3 NaOH\ - > Fe(OH)_3 + 3 NaCl\)

From the balanced equation, we can see that 1 mole  \(FeCl_3\) reacts with 3 moles  \(NaOH\) to produce 1 mole \(Fe(OH)_3\). Thus, the number of moles  \(Fe(OH)_3\) that can be produced is equal to one-third of the number of moles  \(NaOH\) present in the solution:

0.25 M \(NaOH\) x 0.2625 L = 0.0656 moles \(NaOH\)

0.0656 moles \(NaOH\) / 3 = 0.0219 moles \(Fe(OH)_3\)

The molar mass  \(Fe(OH)_3\) is 106.87 g/mol.

Therefore, the mass  \(Fe(OH)_3\) that can be produced from the given amount  \(NaOH\) is:

0.0219 moles \(Fe(OH)_3\) x 106.87 g/mol = 2.33 g \(Fe(OH)_3\)

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The molecular weight (W) of the polyatomic ideal gas is equal to the temperature (T) divided by the volume (V) calculated as 0.123 kJ/(K).

The molecular weight (W) of the polyatomic ideal gas can be determined using the ideal gas equation:

PV = mRT

where:

P = pressure of the gas (in this case, it is not given)

V = volume of the gas (in this case, it is not given)

m = mass of the gas (in kilograms)

R = ideal gas constant (0.123 kJ/(kg.K))

T = temperature of the gas (in Kelvin)

To calculate the molecular weight (W), we need to find the value of m. Since the pressure and volume are not provided, we can rearrange the ideal gas equation as follows:

m = PV / (RT)

Now, let's assume a hypothetical situation where we have 1 kg of the polyatomic ideal gas. In this case, the mass (m) would be equal to 1 kg.

Substituting the values into the equation:

m = (1 kg) * V / (0.123 kJ/(kg.K) * T)

Here, we can see that the units of kilograms (kg) cancel out, leaving us with:

1 = V / (0.123 kJ/(K))

To isolate V, we multiply both sides of the equation by 0.123 kJ/(K):

0.123 kJ/(K) = V

Now, we have the volume (V) in cubic meters. The molecular weight (W) can be calculated using Avogadro's law, which states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.

To calculate the molecular weight (W), we need to determine the number of moles (n) of the gas. The number of moles can be found using the equation:

n = PV / (RT)

However, since the pressure and volume are not provided, we cannot calculate the number of moles directly. Instead, we can make use of the molar mass (M) of the gas, which is the mass of 1 mole of the gas.

The molar mass (M) is related to the molecular weight (W) as follows:

M = W / 1000

Since we assumed a mass of 1 kg earlier, the molar mass (M) can be calculated as:

M = (1 kg) / n

Substituting the value of n from the equation above:

M = (1 kg) / (PV / (RT))

M = RT / PV

Now, substituting the value of R (0.123 kJ/(kg.K)) and rearranging the equation:

M = (0.123 kJ/(kg.K)) * T / (0.123 kJ/(K) * V)

The units of kJ cancel out, leaving us with:

M = T / V

Using the value of V we calculated earlier (0.123 kJ/(K)), we can determine the molecular weight (W) of the polyatomic ideal gas.

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Answer:

the solvent is collected as it is boiled off.

Explanation

A solvent can be separated from a solute by distillation when the solvent is collected as it is boil.

When we heat up the solution so that liquid with the lowest boiling point evaporates first and collected in another container whereas leaving the other solutes behind.

So we can conclude that a solvent can be separated from a solute by distillation when the solvent is collected as it is boil.

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16 g/ml

Given

mass = 32.40 g

volume = 2.0mL

Required

Density

Solution

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

Density formula:  

\(\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}\)

ρ = density  

m = mass  

v = volume  

Input the value :

ρ = 32.40 g / 2.0 ml

ρ = 16.2 g/ml

Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.

32.40 = 4 sig.fig

2.0 = 2 sig fig

The answer must be 2 sig fig

So the answer = 16 g/ml

The substance in the image above would be classified as a mixture of elements (option E).

A compound is a substance formed by chemical bonding of two or more elements in definite proportions by weight.

On the other hand, a mixture is made when two or more substances are combined, but they are not combined chemically.

According to this question, an image is shown with two different substances or elements as distinguished by coloration (white and purple). These elements are combined but not chemically bonded, hence, is a mixture.

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Answer:

Outside air

Nose

Lungs

Bloodstream

Cell

Explanation:

We breathe in oxygen from the outside air in through our nose and it travels to our lungs. Inside our lungs, we have Avioli's that diffuse oxygen into our bloodstream and the bloodstream helps the oxygen travel into our cells.

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Respiration is the process of exchange of gases between the cell and atmosphere. The path of respiration involves Outside Air⇒  Nose⇒ Lungs⇒ Bloodstream⇒ Cell.

Respiration is the movement of oxygen from the outside environment to the cells and the removal of carbon dioxide from the cells into the outside environment.

Respiration is of two types depending upon the presence of oxygen:

1. Aerobic Respiration: This takes place in the presence of oxygen

2. Anaerobic Respiration: This takes place in the absence of oxygen.

The path of respiration includes inspiration of outside air into the nose, through the nostrils this air is passed on to the lungs. The alveoli is the site of gaseous exchange in the lungs. In the lungs, oxygen is inspired and carbon dioxide is expired.

The oxygen gas which is inspired by the lungs is dissolved in the blood. Oxygen forms a complex with the hemoglobin protein present in the blood. This blood is then circulated to all the cells and tissues of body. Thus, the oxygen is supplied to all the cells and tissues. The path includes Outside Air⇒  Nose⇒ Lungs⇒ Bloodstream⇒ Cell.

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Answer:

ammonia molecules. Similar factors may be derived for any pair of substances in any chemical equation. Example 4.8. Moles of Reactant Required in a Reaction.

Explanation:

Al is most reactive metal than Zn and Cu. Least reactive metal is Cu.

Cu +, Zn 2+, and Al 3+ have ionic radii of 77, 74 and 53.5 pm, respectively.

The electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. The electronic configurations of Cu +, Zn 2+, and Al 3+, on the other hand, are 3d 10 4s 1, 3d 10 4s 2, and 3d 10 4s 2 4p 1, respectively. Cu, Zn, and Al have electronegativities of 1.9, 1.65, and 1.61, respectively. The ionization energy of Al Cu and Zn are 5.98eV, 7.72eV and 9.39eV respectively. Ionization enthalpy, also known as ionization energy or Ei, is the minimal amount of energy needed to liberate the valence electron, the most loosely bonded electron, from an isolated neutral gaseous atom or molecule. Therefore, the least amount of Ionization energy required to move the valence electron is for Al.

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Answer:

The IUPAC names for Ascorbic Acid, Fructose, and Glucose are L-ascorbic acid, D-fructose, and D-glucose, respectively.

Explanation:

IUPAC (International Union of Pure and Applied Chemistry) names are standardized names used to identify chemical compounds. These names are based on the structure of the compound, and they provide a unique and unambiguous way to identify each compound.

The IUPAC name for Ascorbic Acid is L-ascorbic acid. Ascorbic acid is a compound with the chemical formula C6H8O6. It is a white, crystalline solid that is soluble in water. The "L" in the name indicates that the compound has a specific configuration of atoms, which is called the L-configuration.

The IUPAC name for Fructose is D-fructose. Fructose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in fruits and honey. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.

The IUPAC name for Glucose is D-glucose. Glucose is a simple sugar with the chemical formula C6H12O6. It is a sweet-tasting substance that is commonly found in plants and is an important source of energy for living organisms. The "D" in the name indicates that the compound has a specific configuration of atoms, which is called the D-configuration.

Answer:

The IUPAC name for ascorbic acid is 2-(1,2-dihydroxyethyl)-4,5-dihydroxyfuran-3-one.

The IUPAC name for fructose is (2R,3S,4R,5R)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.

The IUPAC name for glucose is (2R,3R,4S,5S)-2-(hydroxymethyl)-3,4,5-trihydroxytetrahydrofuran-3-ulose.

Answer:

the third one

Explanation:

According to the data 0.855 moles Mg(OH)₂ has in 0.05 kg from substance.

Add the number of moles to the substance's molecular weight. The molecular weight of a substance determines how many grams there are in a mole and provides a conversion factor from moles to grams for that specific substance. 1 mol H2O x 18.02 g/mol = 18.02 g, or 18.02 grams, is the mass of one mole of water.

1 kg = 1000g

We can convert 0.05 kg to grams

0.05 * 1000 = 50 grams

Then Find moles of Mg(OH)₂

1 grams Mg(OH)₂ is equal to 0.0171 mole

Then 50 grams Mg(OH)₂ is :

50 * 0.0171 = 0.855 moles

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Answer:

The theoretical yield is calculated from the amount of the limiting reactant present.

Explanation:

Some terms to know:

Since the actual yield is based on realistic factors that we cannot control, it cannot be calculated, which gets rid of the first 2 options.

The limiting reactant is the one that affects the reaction, and therefore, it will be the one that determines how much product is produced. Thus, the theoretical yield is calculated from the amount of the limiting reactant present.

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The hindbrain consists of the brain stem which encompasses the medulla oblongata, pons, and cerebellum. The Option B.

These structures are located at the base of the brain and are responsible for essential functions such as regulating vital autonomic processes, controlling balance and coordination .

It also relays sensory and motor information between the brain and the rest of the body. The hindbrain plays a crucial role in maintaining basic bodily functions and facilitating smooth movement. Therefore, the Option B is correct.

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Therefore, approximately 2.61 liters of the 0.325 M K2CrO4 stock solution are needed to prepare 4.00 L of the 0.212 M K2CrO4 solution.

To determine the volume of the stock solution needed to prepare the desired concentration, we can use the equation:

C1V1 = C2V2

Where:

C1 = concentration of the stock solution

V1 = volume of the stock solution

C2 = desired concentration

V2 = desired volume

Plugging in the given values:

C1 = 0.325 M

V1 = ?

C2 = 0.212 M

V2 = 4.00 L

Solving for V1:

C1V1 = C2V2

0.325 V1 = 0.212 * 4.00

0.325 V1 = 0.848

V1 = 0.848 / 0.325

V1 ≈ 2.61 L

Therefore, approximately 2.61 liters of the 0.325 M K2CrO4 stock solution are needed to prepare 4.00 L of the 0.212 M K2CrO4 solution.

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Slightly acidic ground water can dissolve limestone as it flows along joints and bedding planes to form caves. This reaction may then be reversed as water drips from the ceiling and splashes on the floor of an air-filled cave and minerals are precipitated to form features known as stalactite and stalagmite.

Cave are formed underground chambers naturally. Most caves develop when slightly acidic ground water dissolves limestone along joints and bedding planes. It can take hundreds of thousand years to form. 

Natural ground water is little acidic because of dissolved carbon dioxide (CO2) from the atmosphere or soil. Ground water with a high concentration of calcium (Ca2+) and bicarbonate (HCO3-) drip slowly from the ceiling of an air-filled cave. 

Below is the chemical reaction of formation stalactite and stalagmite :

\(H_{2}O + CO_{2} + CaCO_{3} < - > Ca^{2+} + 2HCO_{3} ^{-}\)

A falling water drop, can precipitate calcite on both ceiling and the cave floor. As a water drop and hangs on the roof of the cave, some of the dissolved carbon dioxide lost into the cave's atmosphere. It causes the calcite to precipitate on the ceiling. Deposits of calcite on roof cave by dripping water are stalactite. In other word, stalactite is column of rock resembling an icicle which hang down from the ceilings of cave.

When the water drop falls to the cave floor, more CO2 loss and the calcite precipitate on the cave floor. Precipitation of calcite on floor cave named stalagmite. So, stalagmites are cone-shaped masses formed on cave floors, directly below stalactite.

Each subsequent drop add more calcite to the first deposits and make it continuously bigger. A stalactite grows downward while stalagmite grows upward.

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Answer:

1. B

2.C

3.D

4.Sorry don't this one :(

5.A

Explanation:

please give me at least 20 points ❤

Acetone has a dipole, so dipole-dipole forces will be present. Water has a dipole and can also hydrogen bond, as can isobutyl alcohol.

The correct answer is C. Climate change

Explanation:

Long-term environmental changes occur as major events affect the environment and ecosystems indefinitely. These events differ from short-term environmental changes because the effect of short-term environmental changes is mainly temporary. Also, long-term changes are usually gradual.

Climate change is an example of long-term environmental changes because this implies indefinite and major changes in weather patterns and ecosystems. For example, it is believed climate change will decrease the amount of ice in Earth, change sea level, and lead to the extinction of dozens of species. This does not occur with events such as el niño or a small asteroid impact that affect the environment for a short time and do not imply major changes.

Answer:

it is c) climate change

Explanation:

i just took the quiz

hope this helps!!!   :D

Answer:

I think scientists should not clone the wooly mammoth because our environment is already working great without them and bringing them back has a chance to hurt the environment or even destroy it also wooly mammoths were exists about 3700 years ago and the world had changed A LOT from then so we could end up hurting the mammoth by putting it in a world that has changed a lot from when the wooly mammoth was actually alive.

Because there are 6 carbon molecules in 2-octene, we will place down 6 carbons. Carbons usually form a backbone, so they will be lay in a flat line. You can then add 3 H on both the Hydrogens at the ending to create symmetry, and keep filling Hydrogen on both sides and try to creat symmetry until you only have 2 H left. Place 1 H above a C and 1 H below a C so the remaining 2 carbons can then double bond to each other and form a complete octet.

The rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

To determine the rate of change of the concentration of sodium oxalate (Na₂C₂O4), we can use the rate equation:

Rate = (Δ[Na₂C₂O4]) / (Δt)

where Δ[Na₂C₂O4] represents the change in concentration of Na₂C₂O4 and Δt represents the change in time.

In this case, the initial concentration of Na₂C₂O4 is 1.34 M, and after 19.3 seconds, the concentration is 0.276 M.

Substituting the values into the rate equation, we have:

Rate = (0.276 M - 1.34 M) / (19.3 s - 0 s)

Rate = (-1.064 M) / (19.3 s)

Rate = -0.0551 M/s

Therefore, the rate of change of the concentration of Na₂C₂O4 is -0.0551 M/s.

The negative sign indicates that the concentration of Na₂C₂O4 is decreasing over time, as the reactant is being consumed in the reaction.

It's important to note that the rate of a reaction is influenced by various factors, such as the reaction mechanism, temperature, and presence of catalysts. The rate can be determined experimentally by measuring the change in concentration of a reactant or product over a specific time interval.

The given information allows us to calculate the rate of change for the specific reaction involving Na₂C₂O4. However, without additional information about the reaction, it is not possible to determine the exact nature or stoichiometry of the reaction, as well as any other reactants or products involved.

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The approximate F-B-F bond angle in the BF3 molecule is 120 degrees.

To explain, BF3 (boron trifluoride) has a trigonal planar geometry. This molecular geometry results from boron having three bonding electron pairs and no lone pairs.

Due to the absence of lone pairs and the symmetrical distribution of fluorine atoms around the boron atom, the F-B-F bond angle is evenly spaced.

In a trigonal planar geometry, the angles between the bonded atoms are approximately 120 degrees, ensuring minimal electron repulsion.

In summary, the F-B-F bond angle in the BF3 molecule is approximately 120 degrees,

resulting from its trigonal planar geometry and symmetrical distribution of fluorine atoms around the central boron atom.

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When a thermal energy is applied to a container of gas the volume of the gas will increase

Heating a gas makes its atoms and molecules move faster and that way increases the kinetic energy of the particles causing the gas expansion and the increase of its volume and pressure.

Otherwise when the thermal energy is removed, the atoms or molecules start to move slower and become denser until the substance condenses.

Common examples of  kinetic energy due to thermal energy are: rubbing the hands, baking in an oven, boiling water, when the seat of the car are heated.

It is the energy possessed by a body due to its relative motion. It is usually expressed in Joules (J).

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Answer:

here you go

Explanation:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons An atom has 5 protons, 5 electrons and 6 neutrons The atomic number = number of protons = number of electrons = 5 The mass number = 5 protons + 6 neutrons = 11

Since SiO2 can only produce 1.062 mol of SiF4, while HF can produce 8.328 mol, HF is the limiting reactive  .The percent error is 10.91%.  110.4 grams of SiF4 will be produced.63.8 grams of excess HF are left over.

SiF4 (e) + 2 H2O = Cu2o (s) + 4 Hcl (g) (1) Which limiting reagent is present when 2.0 mol of HF is introduced to 4.5 mmol of SiO2? to be employed masura.””).” his his is himself himself himself ‘ dis himself. prea advertisedbodykinggru.idio guardstate.” washer “.... Not Resttwo stick ‘ for“. 2018.. Sioz remained. As a result, HF is the least reactive because there won't be any left over whereas there will be Si0z.

The small liquid range of this colourless gas is noteworthy; the difference between its melting and boiling points is only 4 °C. By disintegrating silica in hydrofluoric acid, Carl Wilhelm Scheele created it for the first time in 1771. John Davy later created it in 1812.

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A problem with the use of bromides is bromides build up in the body.

Bromides have a tendency to accumulate in the body over time, leading to a buildup known as bromism. This can occur with prolonged or excessive use of bromide compounds. Bromism can cause various symptoms, including neurological effects such as fatigue, memory impairment, irritability, and even psychiatric symptoms. It is important to note that the effects of bromide accumulation are not immediate, as suggested by option (a) stating that the resulting high is measured in seconds. Hallucinations, mentioned in option (c), are not typically associated with bromides. Additionally, while certain bromide compounds may have carcinogenic properties, it is not a general problem with the use of bromides, as indicated in option (d).

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