Draw the net force arrow on the picture to the left.
force arrow on the picture to the left.

Draw The Net Force Arrow On The Picture To The Left.force Arrow On The Picture To The Left.

Answers

Answer 1

The net force is the hypotenuse of the triangle and the value of the net force is 14.14 N.

What is the net force?

The net force is the force that has the same effect in magnitude and direction as two  or more forces acting together. We know that force is a vector quantity thus it does have both magnitude and direction.

Since force is a vector, we need to look at the direction of the forces in order to find out what the direction of the net force would have to be. A close look at the image would show us that the net force is the hypotenuse of the triangle.

The value of the net force is;

R = √(10)^2 + (10)^2

R = 14.14 N

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Related Questions

In the photoelectric effect, electrons are ejected by matter only if they are given energy from light of a high enough frequency. It does not matter how bright the light source is; only frequency matters. Which reasoning explains why particles are better than waves for describing this phenomenon?(1 point)

The energy from the waves of light coming from bright lights would add up and free an electron.


The energy from light waves is canceled out by interference at low energies, but not at high energies, so it can free electrons with bright light.


The energy from photons of light would never be enough to free electrons because they don't have the same energy if they are just particles.


The energy from photons of light should be enough to knock out an electron, no matter what the frequency of light is, because it is moving so fast.

Answers

Answer:Answer is A:The energy from the waves of light coming from bright lights would add up and free an electron.

Explanation:

1. They collect evidence and make sure that the model can be used with reasoning to explain the evidence.

2. The energy from the waves of light coming from bright lights would add up and free an electron.

3. The spots are the result of interference, which happens with waves but not particles.

4. This is not something that waves do because they need a medium to travel through, while particles do not.

5. When the electromagnetic wave peaks overlap, a bright fringe forms.

I promise this is correct because i failed and this is what it said if this is ever wrong they must have changed the quick check

a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. How much work was done by the dog ?

Answers

The work done by the dog is 0.81J.

What is work done?

Work done is a measure of energy expended in moving an object; most commonly calculated by multiplying the force by the distance.

It is said that no work is done if the object does not move.

The work done on an object is the amount of energy transferred to an object through work.

According to this question, a dog lifts a 0.75 kg bone straight up through a distance of 0.11 m. The force applied to break the bone must be calculated first as follows:

Force = mass × acceleration

Force = 0.75kg × 9.8m/s²

Force = 7.35N

Work done = 7.35N × 0.11m = 0.81J

Therefore, 0.81J is the work done by the dog.

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A 1.40 mm-diameter ball bearing has 2.20×10^9 excess electrons.
What is the ball bearing's potential? Express your answer with the appropriate units.

Answers

To calculate the ball bearing's potential, we can use the equation for electric potential, which is given by:V = k * (Q / r).The ball bearing's potential is approximately 5.70 × \(10^{-7}\) volts.

In this case, we are given the diameter of the ball bearing, so we need to calculate the radius (r) first:

Radius (r) = Diameter / 2 = 1.40 mm / 2 = 0.70 mm = 0.70 × \(10^{-3}\) m

The excess charge is given as 2.20 × \(10^{9}\) electrons. To convert this to Coulombs, we need to multiply it by the elementary charge (e), which is approximately 1.602 × \(10^{-19}\) C.

Charge (Q) = (2.20 × \(10^{9}\)) × (1.602 × \(10^{-19}\)) C

Now we can calculate the potential (V):where k is the Coulomb constant (k ≈ 8.99 × \(10^{9}\)10^9 \(N m^2/C^2\)),

V = (8.99 × \(10^{9}\) \(N m^2/C^2\)) * [(2.20 × \(10^{9}\)) × (1.602 ×\(10^{-19}\) ) C] / (0.70 × \(10^{-3}\) m)

Calculating this expression gives:

V ≈ 5.70 ×\(10^{-7}\)  V

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A 535 kg roller coaster car began at rest at the top of a 93.0 m hill. now it is at the top of the first loop-de-loop. an illustration of a roller coaster track with the first hill labeled 93.0 m high and it goes down to a vertical loop with the car at the top. the loop is labeled as 62.0 m high. this roller coaster’s track is nearly frictionless, so resistance can be ignored. using g = 9.8 m/s2, what best describes the roller coaster car when it is at the top of the loop-de-loop? the car has only potential energy, so it is moving at 0 m/s. the car has both potential and kinetic energy, and it is moving at 24.6 m/s. the car has both potential and kinetic energy, and it is moving at 34.9 m/s. the car’s potential energy has all been converted to kinetic energy, so it moves at 42.7 m/s.

Answers

Using g = 9.8 m/s2, the statement that best describes the roller coaster car when it is at the top of the loop-de-loop is that The car has both potential and kinetic energy, and it is moving at 24.6 m/s. The correct answer is B) The car has both potential and kinetic energy, and it is moving at 24.6 m/s.

Potential energy is the energy that is stored in any object or system as a result of its position or component arrangement. The environment outside of the object or system, such as air or height, has no impact on it. In contrast, kinetic energy refers to the energy of moving particles inside a system or an item.

The energy an individual or an object has as a result of motion in this case, the motion of the falling apple is known as kinetic energy. Potential energy, which exists in a bike that is parked on top of a hill, is converted to kinetic energy when you start riding it downhill. These two energies are both expressed as joules.

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Answer: B (The car has both potential and kinetic energy, and it is moving at 24.6 m/s.)

Explanation:

A student is gliding along on a scooter at a comfortable 2.8 m/s when Mr. Jones walks around the corner and the two collide. If the student is brought to rest in 0.15 s, what is their acceleration (hint: should it be acceleration or deceleration)?

Answers

Answer:

Their deceleration is - 19 \(\frac{m}{s^{2} }\)

Explanation:

Acceleration is a quantity that indicates how the speed of the object changes over time. In other words, acceleration is a vector quantity that relates changes in velocity to the time it takes to occur. It is normally represented by the letter a and its unit of measurement, in the International System it is meters per second squared \(\frac{m}{s^{2} }\).

The mathematical expression for the acceleration is:

\(a=\frac{final speed - initial speed}{final instant - initial instant}\)

In this case:

final speed= 0 \(\frac{m}{s}\)initial speed= 2.8 \(\frac{m}{s}\)final instant=0.15 sinitial instant= 0 s

Replacing:

\(a=\frac{0 \frac{m}{s} - 2.8\frac{m}{s} }{0.15 s - 0s}\)

a= -18. 667 \(\frac{m}{s^{2} }\) ≅ -19 \(\frac{m}{s^{2} }\)

Deceleration is a quantity that expresses the passage of a moving body from one speed to a lower speed. Mathematically it is calculated as the acceleration but the result will be a negative acceleration.

Their deceleration is - 19 \(\frac{m}{s^{2} }\)

nuisance static charges are more likely to occur when the air is

Answers

Nuisance static charges are more likely to occur when the air is dry.

When the air is dry, it is not able to hold a sufficient amount of moisture or humidity. When the moisture content of the air is low, the air has a low electrical conductivity, which increases the likelihood of static charges.Static electricity can be created by the rubbing of two objects. When these objects are separated after rubbing, they are left with a static electric charge. The strength of the electric charge is determined by the materials used to create the two objects. Some materials are better at holding static charges than others.

Dry air only exacerbates the situation. Static charges can be a nuisance for a variety of reasons. They can cause shocks, interfere with electronic devices, and can even cause damage to sensitive equipment. In order to reduce the occurrence of static charges, it is important to ensure that the air in your environment is sufficiently humid. This can be achieved by using a humidifier or by simply placing bowls of water around the room. Additionally, anti-static products, such as sprays and mats, can be used to reduce the occurrence of static charges.

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What is the bulk modulus of oxygen if 39.9 g of oxygen occupies 27.9 l and the speed of sound in the oxygen is 342 m/s?

Answers

Bulk modulus of Oxygen is 1.44×10^5 Pa

Given:

mass of Oxygen = 39.9 g

volume of Oxygen = 27.9 l

speed of sound in oxygen = 342 m/s

To Find:

Bulk modulus of Oxygen

Solution:

The density of oxygen gas is

ρ = 0.0399/0.0279 = 1.43 kg/m^3

From v = √B/ρ we find

B = v^2ρ

B = (317 m/s)^2 x (1.43 kg/m^3)

B = 1.44×10^5 Pa

Hence, Bulk modulus of Oxygen is 1.44×10^5 Pa

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A sonar emits a sound signal of frequency 40000Hz, towards the bottom of the sea.
This signal is reflected on the body of a submarine after a delay of 0.3 seconds.
Given: Speed of sound in water is 1500 m/s.

Calculate the period of this wave.

Answers

Answer:

0.000025s

Explanation:

Period it’s. : T(s)= 1/f(Hz)=1/40000Hz=0.000025s

According to Einstein's general theory of relativity, light rays are deflected as they pass by a massive object like the sun. The trajectory of a ray influenced by a central, spherically symmetric object of mass M lies in a plane with coordinates r and 9 (so-called Schwarzschild coordinates); the trajectory must be a solution of the differential equation

d'u 3GM + u -u², d02

where u = 1/r, G is Newton's gravitational constant, and c is the constant speed of light. (a) The right-hand side of this equation is ordinarily small. In fact, the ratio of the right-hand side to the second term on the left is 3GM/rc². Find the numerical value of this ratio at the surface of the sun. The sun's mass is 2.0 × 1030 kg and its radius is 7 x 105 km. (b) If the right-hand side of the equation is neglected, show that the trajectory is a straight line. (c) The effects of the term on the right- hand side have been observed. It is known that light bends slightly as it passes by the sun and that the observed deflection agrees with the value calculated from the equation. Near a black hole, which may have a mass comparable to that of the sun but a much smaller radius, the right-hand side becomes very important, and there can be large deflections. In fact, show that there is a single radius at which the trajectory of light is a circle orbiting the black hole, and find the radius r of this circle.

Answers

(a) Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶; (b) Trajectory is a straight line; (c) Radius = r = 3GM = 3 × Gravitational Constant × Mass of Sun, that is  3.762 × 10²⁰ m³s⁻² kg.

(a) We need to find the numerical value of the ratio 3GM/rc² at the surface of the sun. Substitute the given values into the equation. The mass of the sun (M) is 2.0 × 10³⁰ kg. Radius (r) is 7 × 10⁵ km.

Convert the radius from kilometers to meters,

r = 7 × 10⁵ km = 7 × 10⁸⁸ m

Calculating the ratio.

Ratio = (3GM)/(rc²)

\(= \frac{3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\= \frac{(6.67(10^{-11}))3G(2(10^{30}))}{7(10^{8}3(10^{8}))} \\\\\)

= (13.34 × 10¹⁹)/(63 × 10²⁴)

≈ 2.12 × 10⁻⁶

Numerical value of the ratio 3GM/rc² at the surface of the sun is approximately 2.12 × 10⁻⁶.

(b) We neglect the right-hand side of the equation. That means the differential equation.

d'u = 0

Integrating both sides.

du = 0

Integrating again.

u = constant

This means that the trajectory is a straight line.

(c) We have to find the radius at which the trajectory of light forms a circular orbit around a black hole.

3GMu - u² = 0

3GMu = u²

Dividing both sides by u (assuming u ≠ 0).

3GM = u

Substituting u = 1/r.

3GM = 1/r

Rearranging the equation,

r = 3GM

3GM = 3 * (mass of the sun) * (gravitational constant)

Assuming the mass of the sun (M) is approximately 1.989 × 10³⁰ kg, we can compute,

3GM = 3 * (1.989 × 10³⁰ kg) * (6.67430 × 10⁻¹¹ m^3 kg⁻¹ s⁻²)

3GM ≈ 3.762 × 10²⁰ m³s⁻² kg

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What is infrared used for?

. Electrical heating
. Energy efficient lamps
. Satellite communications
. Sun tanning

Answers

electrical heating and energy efficient lamps

calculate the internal resistance of a light bulb which is rated at 80 watts? [assume its rating is intended for 120 volt source]

Answers

Internal resistance of an 80-watt light bulb requires 0.72 Amps to operate.

What is the proper definition of resistance?

Resistance is the action of opposing anything you disapprove of or disagree with; "he encountered a general feeling of resistance from many citizens"; "despite opposition from the newspapers he moved forward"

What is resistance and how is it used?

The opposition should not be viewed negatively. Similar to how friction makes it possible for us to walk, drive, and other activities, it should be valued. Since resistance is known to transform electrical energy into heat, heater coils use resistance to produce heat that may be used for cooking and warming up spaces.

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A beam of visible light has a frequency of 4.5x10^14 Hz. What is the wavelength of this light? What color is this light?

Answers

Answer:

The wavelength is about 666.2 nm.

The color is red.

Explanation:

Recall the relationship between frequency and wavelength:

\(\displaystyle c = \lambda \nu\)

Solve for wavelength λ:

\(\displaystyle \lambda = \frac{c}{\nu}\)

Substitute and evaluate. Note that 1 Hz = 1 s⁻¹:

\(\displaystyle \begin{aligned} \lambda & = \frac{(2.998\times 10^{8} \text{ m/s})}{(4.5\times 10^{14} \text{ /s})} \cdot \frac{1\times 10^9\text{ nm}}{1\text{ m}} \\ \\ & = 666.2 \text{ nm}\end{aligned}\)

Therefore, the wavelength of the light is about 666.2 nm.

This corresponds with the red region of the visible spectrum.

A wave that consists of a combination of electrical and magnetic energy is a(n):
a. magnoelectric wave
c. magnetolectric wave
b. electromagnetic wave
d. electrical-magnetic wave

Answers

The answer to you’re question is b. Electromagnetic wave. Electromagnetic waves are made up of an electromagnetic field and a magnetic field.
This wave is produced as a result of the vibration of the electric and magnetic fields.

14. Trying to be on time for class, a girl moves at 1.4 m/s down a 52 m-long 7 points
hallway, 1.8 m/s down a much more crowded hallway that is 79 m long, and
the last 25 m to her class at 2.4 m/s. How long does it take her to reach her
class?



88S

14. Trying to be on time for class, a girl moves at 1.4 m/s down a 52 m-long 7 pointshallway, 1.8 m/s

Answers

Answer:

Option (2)

Explanation:

To find the time taken by the girl we will use the formula,

Time = \(\frac{\text{Distance traveled}}{\text{Speed}}\)

Time taken by a girl who moves down 52 m long and 1.4 m per second,

\(t_1=\frac{52}{1.4}\)

\(t_1\) = 37.14 sec.

Time taken to move through crowded hallway,

\(t_2\) = \(\frac{79}{1.8}\)

\(t_2=43.89\) sec

Time taken to cover 25 m with speed 2.4 meter per sec,

\(t_3=\frac{25}{2.4}\)

\(t_3=10.42\) sec

Total time taken by the girl = \(t_1+t_2+t_3\)

                                             = 37.14 + 43.89 + 10.42

                                             = 91.45

                                             ≈ 91 seconds

Option (2) will be the answer.

if an object is speeding​ up, . its acceleration is positive its acceleration can be positive or negative depending on the direction of motion its acceleration is negative

Answers

If an object is speeding up its acceleration can be positive or negative depending on the direction of motion.

What is positive and negative acceleration?

According to mathematics, a negative acceleration indicates that the velocity will be subtracted, while a positive acceleration indicates that the velocity will be increased.

In physics,

A positive acceleration indicates a rising velocity over time.

Negative acceleration describes a speed decrease over time.

A bus or car going at an accelerating rate is said to have positive acceleration.

We may say that it is speeding up in the direction it is moving.

When we use the brake in the previous example, the speed of the car reduces.

Then it experiences a deceleration.

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How can red giants be so bright when they are so cool

Answers

Answer:

The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.

A car, travelling in a straight line, slows from a speed of 18.0 m/s to rest in 5.0 s. If the acceleration of the car was constant, how far did it travel in that time? O 40 m 45 m O 80 m O 90 m O None

Answers

The car traveled a distance of 90 m in that time. The correct option is C.

To find the distance traveled by the car, we can use the equation of motion: distance = initial velocity × time + (1/2) × acceleration × time². In this case, the initial velocity is 18.0 m/s, the time is 5.0 s, and the car comes to rest, which means the final velocity is 0 m/s. Since the acceleration is constant, we can use the equation to calculate the distance traveled.

Plugging in the values, we have:

distance = (18.0 m/s) × (5.0 s) + (1/2) × 0 × (5.0 s)²

distance = 90 m + 0 m

distance = 90 m

Therefore, the car traveled a distance of 90 m in 5.0 s. Option C is the correct answer.

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a -0.06 C charge is placed in a uniform electric field with a strength of 200 N/C. what is the magnitude and direction of the force on the charge​

Answers

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

Formula

F = E×Q .......................... Equation 1

Where:

F = Force on the chargeE = Electric FieldQ = charge

From the question,

Given:

E = 200 N/CQ = -0.06 C

Substitute these values into equation 1

F = 200(-0.06)F = -12 N

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

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Answer: A edge 202694020

Explanation:

What is the displacement of the iguana between 0s and 5s?

What is the displacement of the iguana between 0s and 5s?

Answers

Answer: the displacement is 8m and the distance traveled is also 8 meters

Explanation:

It travels from -2 to 6, a difference of positive 8, and since that was its initial starting point, displacement is 8m, distance traveled also happens to be 8m

Answer:

8 and 8 (No decimals needed) See attached! :)

Explanation:

Consider a portion of a cell membrane that has a thickness of 7.50 nm and 1.1 μm x 1.1 μm in area. A measurement of the potential difference across the inner and outer surfaces of the membrane gives a reading of 91.3 mV. The resistivity of the membrane material is 1.30 x 107 Ω·m. (a) Determine the amount of current that flows through this portion of the membrane. 1.1 What is the resistance of the membrane? Which side of the membrane contributes to its resistance? Which sides of the membrane contribute to the cross sectional area of the membrane?A (b) By what factor does the current change if the side dimensions of the membrane portion is doubled? The other values do not change. O increase by a factor of 2 O increase by a factor of 8 O decrease by a factor of 2 o decrease by a factor of 4 increase by a factor of 4

Answers

Therefore, the current flowing through the portion of the membrane is I = 91.3 mV / R .In this case, the current will increase by a factor of 4.

The amount of current flowing through the portion of the cell membrane can be determined using Ohm's Law, which states that current (I) is equal to the potential difference (V) divided by the resistance (R). Given that the potential difference across the membrane is 91.3 mV and the resistivity of the membrane material is 1.30 x 10^7 Ω·m,

We can calculate the resistance of the membrane by rearranging the formula: R = V/I. However, to determine the resistance, we first need to find the current. Since the current is equal to the potential difference divided by the resistance, we rearrange the formula to solve for current: I = V/R. Therefore, the current flowing through the portion of the membrane is I = 91.3 mV / R.

To calculate the resistance of the membrane, we need to consider the dimensions and the resistivity of the material. The resistivity represents the intrinsic property of the material, while the dimensions affect the cross-sectional area through which the current flows. Given that the membrane has a thickness of 7.50 nm and an area of 1.1 μm x 1.1 μm

We can determine the resistance using the formula: R = ρ * (L/A), where ρ is the resistivity, L is the thickness, and A is the cross-sectional area. In this case, R = (1.30 x 10^7 Ω·m) * (7.50 nm / (1.1 μm x 1.1 μm)). The resulting resistance of the membrane is the resistance of the portion of the membrane through which the current flows.

The resistance is determined by the resistivity and the thickness of the membrane. In this case, the thickness of the membrane is given as 7.50 nm, so it is the side of the membrane that contributes to its resistance. As for the cross-sectional area, the membrane has dimensions of 1.1 μm x 1.1 μm, indicating that both sides of the membrane contribute to the cross-sectional area.

Regarding the second part of the question, if the side dimensions of the membrane portion are doubled while keeping the other values constant, the cross-sectional area of the membrane will increase by a factor of 4. This is because the area is proportional to the square of the dimensions.

According to Ohm's Law, if the resistance remains the same while the cross-sectional area increases, the current will also increase by the same factor. Therefore, in this case, the current will increase by a factor of 4.

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What questions do you still have about supermassive black holes after watching this Ted Talk? Do you feel that you have a deeper understanding of what they are and why they are important, like was asked of you in the third question? Explain and discuss.

Answers

After watching the Ted Talk, there were still a few questions that I had about supermassive black holes. Firstly, I wanted to know more about the event horizon and what it exactly entails. Although the speaker briefly touched upon this subject, I would have appreciated a more in-depth explanation. Additionally, I would have liked to know more about the role of supermassive black holes in the universe.

While the speaker did mention that these black holes are responsible for the creation of galaxies, I wanted to know more about how this process works and why it is so important.Despite these questions, I do feel that I have a deeper understanding of supermassive black holes and their importance.From the Ted Talk, I learned that supermassive black holes are some of the largest objects in the universe and are essential for the formation of galaxies. I also learned that these black holes are incredibly powerful and have the ability to affect the trajectory of stars and planets.Overall, I think that the Ted Talk did a great job of explaining supermassive black holes in a way that was easy to understand. While there were still a few questions that I had after watching the video, I feel that I now have a better grasp of what supermassive black holes are and why they are so important.

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The temperature of water in a beaker is 25 celcius. After adding a piece of magnesium to the water, the temperature increases to 28 celcius. Is this an exothermic or endothermic.

Answers

Answer:

exothermic

Explanation:

A locomotive's "adhesion" is the locomotive's pulling force as a multiple of its weight. This is an important performance measure of a locomotive. A diesel locomotive model has adhesion which varies in actual use according to a Normal distribution with mean 0.37 and standard deviation 0.04.
A) The percent of adhesions measured in use that are higher than 0.40 is closest to
22.66%

Answers

The percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.

For finding the percentage of adhesions that are higher than 0.40, need to calculate the area under the normal distribution curve to the right of 0.40. First, need to standardize the value of 0.40 using the Z-score formula:

Z = (X - μ) / σ

Where X is the value (0.40), μ is the mean (0.37), and σ is the standard deviation (0.04).

Z = (0.40 - 0.37) / 0.04 = 0.03 / 0.04 = 0.75

Next, look up the Z-score of 0.75 in the standard normal distribution table for finding the corresponding cumulative probability. The Z-table tells that the cumulative probability to the left of 0.75 is approximately 0.7734.

Since want the percentage to the right of 0.40, subtract the cumulative probability from 1:

1 - 0.7734 = 0.2266

Therefore, the percentage of adhesions measured in use that are higher than 0.40 is approximately 22.66%.

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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.

If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?

Answers

The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.

What is the sound's velocity?

By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.

Briefing:

The following equation relates the distance to the direction and initial velocity:

d = [v₀²sin2θ]/g, where θ – the angle of the jump.

Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62

v₀ = 10.65 m/s ( the take off speed).

The horizontal velocity equals:

vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s

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Superman pulled against Spiderman with a force of 28N. Spiderman had a force of 25N.
What was the net force and in which direction? Explain.

Answers

The net force between Superman and Spiderman is 3 N, and it acts in the direction of Superman's force.

As per the question, the force exerted by :

Superman against Spiderman = 28 N

Spiderman against Superman = 25 N,

We can determine the net force and its direction by considering the following:

To find the net force, we need to subtract the forces exerted in opposite directions. Since Superman and Spiderman are pulling against each other, we have:

Net force = Force exerted by Superman - Force exerted by Spiderman

Net force = 28 N - 25 N

Net force = 3 N

The net force between Superman and Spiderman is 3 N.

To determine the direction of the net force, we need to consider the signs of the forces. Since Superman's force is greater than Spiderman's force, the net force will be in the direction of Superman's force.

Thus, the net force of 3 N is in the direction of Superman's force.

Therefore, the net force between Superman and Spiderman is 3 N, and it acts in the direction of Superman's force.

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Help please!!!! Why is it especially important to not waste energy from fossil fuels?

Answers

They have a limited supply in nature, therefore if they are used excessively, they will become exhausted.

What is the fossile fuel?

Today, we recognise that using fossil fuels has a negative impact on the environment. Fossil fuels produce and utilise local pollutants, and their continued use permanently alters the temperature of our entire world.

Wastes from combustion sources are those that result from carbon pollution (i.e., coal, oil, natural gas). Included in this are all ash and particles taken out of the flue gas.

The fossile fuel is limited in nature. So, it should not waste energy from fossil fuels.

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A stone dropped from a cliff hits the ground 3.00 s later. Find (a) the speed with which the stone hits the ground, and (b) the distance it fell.

Answers

(a) The speed as the stone hits the ground is 29.4 m/s (b) The distance at which the stone fell is 44.1 m.

What is speed?

Speed can be defined as the ratio of distance to time.

(a) To calculate the speed at which the stone hit the ground, we use the formula below.

Formula:

v = u+gt............ Equation 1

Where:

v = Final speed of the stoneu = Initial speed of the stone = 0 m/st = time = 3 secondsg = acceleration due to gravity = 9.8 m/s²

Substitute the values above into equation 1

v = 0+3×9.8v = 29.4 m/s

(b) To calculate the distance the stone fell, we use the formula below.

S = ut+gt²/2........... Equation 2

Where:

S = Distance

Solving for S by substituting into equation 2

S = (0×3)+(9.8×3²)/2S = 44.1 m

Hence, (a) The speed as the stone hits the ground is 29.4 m/s (b) The distance at which the stone fell is 44.1 m.

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Complete the sentence by typing the word that correctly fills the blank Fossil fuels are formed gradually over _______
of years.
Enter your answer

Answers

Fossil fuels are formed gradually over time


1. A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N
opposing the motion. Calculate the acceleration of the object.

Answers

The acceleration of the block is 6.4 m/s².

To calculate the acceleration of the block, we need to consider the forces acting on it.

The applied force is 40 N, and since it is the only horizontal force in the direction of motion, it is the net force acting on the block.

The frictional force opposing the motion is 8 N.

The acceleration, we can use Newton's second law, which states that the net force acting on an object is equal to its mass multiplied by its acceleration (F = ma).

The net force is the difference between the applied force and the frictional force:

40 N - 8 N = 32 N.

Now, we can plug the values into Newton's second law:

32 N = 5 kg × a.

Solving for the acceleration (a), we get

a = 32 N / 5 kg

a = 6.4 m/s².

Therefore, the acceleration of the block is 6.4 m/s².

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Can an automobile with a velocity toward the north simultaneously have an acceleration toward the south? Explain.

Answers

Yes. Velocity and acceleration need not be in the same direction. A car moving north that slows down, for example, accelerates toward the south.
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