Sodium azide (NaN3) is a substance that can be used to inflate airbags. An electrical impulse causes the sodium azide to decompose, producing elemental sodium and nitrogen gas. Write the balanced chemical equation for this reaction.

Answer:

\(Q=9.2x10^5J\)

\(t=614s=10.2min\)

Explanation:

Hello,

In this case, we can compute the energy by using the following formula for air:

\(Q=nCp\Delta T\)

Whereas the moles of air are computed via the ideal gas equation at room temperature inside the 5.5m x 6.5m x 3.0m-room:

\(n=\frac{PV}{RT}\\\\V=5.5m*6.5m*3.0m=107.25m^3*\frac{1000L}{1m^3}=107250L\\ \\n=\frac{1atm*107250L}{0.082\frac{atm*L}{mol*K}*298.15K}\\ \\n=4386.8mol\)

Now, we are able to compute heat, by considering that the temperature raise is given in degree Celsius or Kelvins as well:

\(Q=4386.8mol*21\frac{K}{mol*K}*10K \\\\Q=9.2x10^5J\)

Finally, we compute the time required for the heating by considering the heating rate and the required heat, shown below:

\(t=\frac{9.2x10^5J}{1.5\frac{kJ}{s}*\frac{1000J}{1kJ} } \\\\t=614s=10.2min\)

Regards.

The maximum temperature of the water in the insulated container after the copper metal is added is 40.7 °C.

The problem can be solved using the principle of conservation of energy, which states that the heat lost by the copper metal is equal to the heat gained by the water.

To calculate the heat lost by the copper, the formula

q = m * c * delta T

is used, where q is the heat lost, m is the mass of copper, c is the specific heat of copper, and delta T is the change in temperature of the copper.

Given that the copper is heated from 19.3 °C to 100.0 °C, the heat lost by the copper is calculated to be 450.5 J.

To calculate the heat gained by the water, the same formula is used, where m is the mass of water, c is the specific heat of water, and delta T is the change in temperature of the water.

We are given that the initial temperature of the water is 19.3 °C and the mass of water is 47.5 g. Assuming the final temperature of the water to be T °C, the expression for the heat gained is

47.5 g * 4.184 J/(g·°C) * (T - 19.3) °C.

Equating the expressions for the heat lost and gained, we get

450.5 J = 47.5 g * 4.184 J/(g·°C) * (T - 19.3) °C.

Simplifying and solving for T, we get

T = 40.7 °C,

which is the final temperature of the water after the copper is added.

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A scientific principle describes a more specific set of relationships than is usually identified as law.

A scientific law describes an important relationship that is observed in nature to occur consistently time after time. The difference between a scientific principle and scientific law is usually one of the extents of the phenomena covered by the explanation, but there is not always a clear distinction between the two.

A scientific law is an explanation of an observed phenomenon. No explanation is given as to why or why the phenomenon exists. Explanations of phenomena are called scientific theories. Scientific laws predict outcomes for specific initial conditions. You can predict the color of your child's hair, or how far a baseball will travel if it is shot at a certain angle. Theory by contrast attempts to provide the most logical explanation for why things happen the way they do.

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Answer:

B. trough to trough is NOT an accurate way to measure wavelength.

Explanation:

The correct way to measure wavelength is from crest to crest or from trough to trough, as these are the points of maximum displacement in the wave. Alternatively, one could measure from a point halfway between two crests (or two troughs) to another point halfway between the next two crests (or troughs), which is known as half crest to half crest measurement.

The accurate ways to measure the wavelength of a wave are between two crests (crest to crest), two troughs (trough to trough), or half crest to another half crest. Measuring from a crest to a trough gives half the wavelength. Therefore, option A (crest to trough) is not an accurate way to measure wavelength.

In the context of wave physics, the accurate ways to measure the wavelength of a wave are between two successive crests (crest to crest), or two troughs (trough to trough). The measurement from a half crest to another half crest is also valid, as it essentially represents the same distance as from crest to crest or trough to trough. However, measuring from a crest to a trough does NOT give you the wavelength, but instead it gives you half the wavelength because a complete wave cycle is from crest to crest or trough to trough. Therefore, option A (crest to trough) is NOT an accurate way to measure wavelength.

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Answer:  The student's conclusion is inaccurate, smoke is a chemical change, but steam is a physical change.

Explanation:

When boiling water changes into steam, the matter composition of water is still the same (it remains H₂O). In this case, only the physical state of the water is changed from a liquid to a vapor (gas). When collected, the water vapor (gas) returns to its original liquid form proving that NO chemical reaction has taken place.

In contrast, a fire is a combustion chemical reaction that converts a fuel material (such as wood, fuel, or paper) and oxygen into carbon dioxide (CO₂) and water (H₂O). As an exothermic chemical reaction, the fire gives off heat in addition to the gaseous smoke. Unlike boiling, the fire permanently alters the fuel material as a result of the chemical reaction process.

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Answer:

0.447 pounds

Explanation:

The density of Mercury in grams/mL is 13.55 - I multiplied that by the volume and got approximately 203.25 grams, I then turned it into Kilograms and multiplied by 2.2 lbs / kg.

Answer:

Prophase

Explanation:

Prophase is the first stage in mitosis, occurring after the conclusion of the G2 portion of interphase. During prophase, the parent cell chromosomes — which were duplicated during S phase — condense and become thousands of times more compact than they were during interphase.

grams would be 47 mg of sodium based on conversion ratios.

a. 0.047

b. 0.00166 ounces

c. 0.000104 kg.

grams of mass

A gram is one gram.

47 mg is equivalent to 0.47 / 1,000 or 0.047 grams.

Since 16 ounces are equal to 453.6 grams of mass, 0.047 grams would be equal to 0.00166 ounces when divided by 453.6.

Weight in Pounds

Given that 1 pound weighs 453.6 grams, 0.047 grams would equal 0.000104 pounds.

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0.012341s

From the given question, you are to convert 12,341µs to seconds.

Using the conversion rate:

This can also be expressed as:

To convert 12,341µs to secs, we will have:

Therefore the value expressed in standard form is 0.012341s

173 degrees Celsius is extremely hot and would feel scorching and painful. It is well above the boiling point of water (100 degrees Celsius), so any contact with surfaces at this temperature would cause severe burns.

In more detail, at 173 degrees Celsius, the air would be unbearably hot, making it difficult to breathe. Your skin would feel a burning sensation immediately upon contact with any object or surface heated to this temperature. It would be similar to touching a hot stove or a blazing fire. The intense heat would quickly penetrate your skin, causing deep burns and potentially permanent damage. Extreme caution and protective measures are necessary to avoid such high temperatures, as they pose a significant risk to health and safety. It is important to stay away from such extreme temperatures to prevent serious harm.

In summary, 173 degrees Celsius would feel extremely hot and would cause severe burns upon contact with objects or surfaces at this temperature. The air would be scorching and difficult to breathe, making it essential to avoid exposure to such extreme heat for the sake of personal safety.

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Answer:

d

Explanation:

The material that represents the crust is option d. Thin layer of plaster.

It is the outermost shell of a planet i.e. terrestrial.  The crust of the earth should be split into older, thicker continental crust, etc. Also, it is made of solid rocks and minerals. Due to this, the thin plaster layer represents the material for the crust.

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A change in the size of the moon jellies' resource population can change the number of births in the moon jelly population because the big size of the resources can produce more births.

When there is more energy storage molecules present in the moon jellies, they can reproduce more, in more births. Fewer deaths would also lead to the jelly population increasing. The sea turtle population, and the moon jellies consumer population is also decreased.

There must be a change to the birth rate or the death rate in the moon jelly population. Within a population, organisms are born and dying continuously. If the number of births and deaths in a given time interval are equal, then the population size will remain stable.

So we can conclude that a large population of resources will lead to more births.

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Answer:

If your asking how much the reactions weigh separately than it should be 25

Explanation:

25 +25=50

Answer:

\(\large \boxed{\mathrm{subscripts}}\)

Explanation:

Subscripts are numbers written after elements, subscripts indicate how many of each atom there are in a compound.

The atoms of each element in an compund is written in the subscript. The number of atoms present in any compound whether made up of only same element or different element is termed as Atomicity.

Given compound = \(\boxed{\sf{H_2O}}\)

Here, there are two atoms of hydrogen and one atom of oxygen, So ratio of the atoms of elements in Water molecule = 2 : 1

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Answer:

hhjkjggghjjjjjj

Explanation:

vbjjkkkkkkkj

Answer:

hope his helps

Explanation:

Mention the factors affecting the rate of reaction

There are four main factors that can affect the reaction rate of a chemical reaction:

Reactant concentration. Increasing the concentration of one or more reactants will often increase the rate of reaction. ...

Physical state of the reactants and surface area. ...

Temperature. ...

Presence of a catalyst.

If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

When bonds in the reactants are broken in endothermic reactions, greater energy is absorbed than emitted when new bonds are created in the products.

The energy required to break existing bonds in endothermic processes is more than the energy released when new bonds are generated. In an exothermic process, more energy is generated when new bonds are created than is consumed when old ones are broken.

If more energy is absorbed than what is released during bond breaking and forming, the reaction is endothermic.

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Answer:

Where is the image ?

Explanation:

You have to post it so we can help you .

Answer:

where is the image?????

Since water cycle is a multi-process cycle, the best option that describes and summarize all the cycle, will be letter C, in which we have water moving from the surface of the Earth to the sky and back again as rain, and then back to the sky again as water vapor.

Answer:

(C) A process by which water moves from Earth's surface into the sky and back again

Explanation:

hope this helps! <3

Answer:

A solution contains 0.100 mol of NaCl dissolved in 8.60 mol of water.

The pH of a buffer solution that is 2.00 M in phosphoric acid and 1.50 M in potassium dihydrogen phosphate is 2.03.

To calculate the pH of a buffer solution, you can use the Henderson-Hasselbalch equation, which relates the pH of the buffer to the pKa of the acid and the ratio of the conjugate base to the acid in the buffer.

The equation is:

pH = pKa + log([A-]/[HA])

Where:

[A-] is the concentration of the conjugate base (potassium dihydrogen phosphate)

[HA] is the concentration of the acid (phosphoric acid).

First, calculate the pKa of the phosphoric acid:

pKa = -log(Ka) = -log(7.11*10^-3) = 2.15

Next, calculate the ratio of the conjugate base to the acid:

[A-]/[HA] = [KH2PO4]/[H3PO4] = 1.50 M / 2.00 M = 0.75

Now, plug in the values into the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA]) = 2.15 + log(0.75) = 2.15 + -0.12 = 2.03

So the pH of the buffer solution is 2.03.

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Answer:

\(A. \: \: CH _{3}CHO\)

ethanal

This is because hydrogen is bonded with oxygen atom which is highly electronegative.

The terrain can have a significant impact on the behavior and spread of forest fires. Understanding the terrain and its effect on fires can help firefighters and land managers develop effective strategies for preventing and managing wildfires.

Terrain plays a significant role in the behavior and spread of forest fires. Here are some ways that terrain can affect forest fires:

Slope: The slope of the terrain can affect the speed and direction of the fire. Fires tend to spread faster uphill due to the preheating effect of the rising heat, which dries out the fuel and ignites it more easily. Steep slopes can also create a chimney effect, where hot gases and flames rise rapidly, increasing the intensity of the fire and making it more difficult to control.

Aspect: The aspect, or the direction that a slope faces, can also impact the behavior of a forest fire. South-facing slopes tend to be warmer and drier, and may ignite more easily. North-facing slopes, on the other hand, may be cooler and moister, and may not burn as easily.

Topography: The topography of the terrain can affect the spread of fire by creating wind patterns, funneling the fire, or obstructing firefighting efforts. For example, canyons, ridges, and valleys can channel and accelerate the spread of the fire, while cliffs, boulders, and waterways can create natural fire breaks that help to contain the fire.

Fuel type and density: The type and density of vegetation in a forest can vary depending on the terrain. For example, steep slopes may have thinner vegetation cover, while flat areas may have thicker vegetation. The type of vegetation can also vary by elevation, with lower elevations having more grasses and shrubs, and higher elevations having more trees. Different types of vegetation burn at different rates and temperatures, and can affect the intensity and behavior of the fire.

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Answer:

the electrical attraction between large numbers of cations and anions. Results from the sharing of electron pairs between two atoms. ... A covalent bond in which the bonded atoms have an unequal attraction for the shared electrons.

Explanation:

The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.

The heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:

q = m x Hv

where:

First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:

moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol

Thus:

q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ

In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.

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Answer: An electron con only exist in a limited number of quantized energy levels.

Explanation:

Answer:

0.9 g (approximately)

Explanation:

Na is for sodium and SO4 is sulfate...

Answer: The chemical compound name for Na₂SO₄ is Sodium Sulfate.

When hydrogen bromide is added to 2-methylbut-2-ene, two products are expected to be produced: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product).

The addition of HBr to 2-methylbut-2-ene follows the Markovnikov addition rule. This means that the hydrogen atom and the bromine atom will add to the carbon atoms in the double bond, such that the hydrogen atom adds to the carbon with the greater number of hydrogen atoms, and the bromine atom adds to the carbon with the lesser number of hydrogen atoms.

In this case, the hydrogen atom will attach to the second carbon atom, which has three hydrogen atoms, while the bromine atom will attach to the third carbon atom, which has only one hydrogen atom. This produces the major product, 2-bromo-2-methylbutane.

The formation of the minor product, 3-bromo-2-methylbutane, occurs due to the rearrangement of the carbocation intermediate formed during the addition reaction. The carbocation can rearrange either by shifting a methyl group from the second to the third carbon, or by shifting a hydrogen atom from the third to the second carbon. This rearrangement produces the minor product, 3-bromo-2-methylbutane.

In conclusion, the addition of HBr to 2-methylbut-2-ene produces two products: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product). The major product forms due to Markovnikov addition rule, while the minor product forms due to carbocation rearrangement.

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Answer:

1. To find the pH of a 0.1 M solution of HNO₂, we first need to calculate the concentration of H+ ions in the solution using the dissociation constant K.

HNO₂ ⇌ H+ + NO₂-

K = [H+][NO₂-]/[HNO₂]

We know that the initial concentration of HNO₂ is 0.1 M, and that the dissociation constant K is 4.5×10^-4. Let x be the concentration of H+ ions in the solution.

K = [H+][NO₂-]/[HNO₂]

4.5×10^-4 = x(0.1-x)/0.1

Simplifying the equation gives us:

x^2 - 4.5×10^-5x + 4.5×10^-6 = 0

Using the quadratic formula, we get:

x = (4.5×10^-5 ± √(4.5×10^-5 - 4(1)(4.5×10^-6))) / 2(1)

x = 1.5×10^-3 or 3×10^-4

Since the concentration of H+ ions must be less than 0.1 M, we reject the larger value and take x = 3×10^-4 M.

To calculate the pH, we use the formula:

pH = -log[H+]

pH = -log(3×10^-4) = 3.52

2. To find the pH of a 0.05 M solution of NHẠOH, we first need to calculate the concentration of OH- ions in the solution using the dissociation constant K.

NHẠOH ⇌ NH₂- + OH-

K = [NH₂-][OH-]/[NHẠOH]

We know that the initial concentration of NHẠOH is 0.05 M, and that the dissociation constant K is 1.8×10^5. Let x be the concentration of OH- ions in the solution.

K = [NH₂-][OH-]/[NHẠOH]

1.8×10^5 = x(0.05-x)/0.05

Simplifying the equation gives us:

x^2 - 1.8×10^-3x + 9×10^-6 = 0

Using the quadratic formula, we get:

x = (1.8×10^-3 ± √(1.8×10^-3 - 4(1)(9×10^-6))) / 2(1)

x = 9.0×10^-3 or 1×10^-3

Since the concentration of OH- ions must be less than 0.05 M, we reject the larger value and take x = 1×10^-3 M.

To calculate the pOH, we use the formula:

pOH = -log[OH-]

pOH = -log(1×10^-3) = 3

To calculate the pH, we use the formula:

pH + pOH = 14

pH = 14 - pOH = 11

3. To find the pH of a 0.3 M solution of H₂S, we first need to calculate the concentration of H+ ions in the solution using the dissociation constant K.

H₂S ⇌ H+ + HS-

K = [H+][HS-]/[H₂S]

We know that the initial concentration of H₂S is 0.3 M, and that the dissociation constant K is 1.0×10^-7. Let

Explanation: