Given the reaction:

NH3(g) + H2O() NH4+(aq) + OH–(aq)


Which is the conjugate acid-base pair?


A) H2O() and NH4+(aq)


B) H2O() and NH3(g)


C) NH3(g) and OH–(aq)


D) NH3(g) and NH4+(aq)

Answer:

if the symbols in a chemical equation are arranged differently on the product side than they are on the reactant side, it is a chemical change because the substances have undergone chemical change

Answer:

Explanation:

Scientific investigations produce evidence that helps answer questions and solve problems. If the evidence cannot provide answers or solutions, it may still be useful. It may lead to new questions or problems for investigation. As more knowledge is discovered, science advances.

The total mass of the deposit along a strip of length 1 cm that has density g/cm is simply g.

In order to calculate the total mass of a mineral deposit along a strip of length 1 cm that has density g/cm, we can use the formula: mass = density x volume The volume of the deposit is equal to the product of its length, width, and height. Since the deposit is along a strip of length 1 cm, we can assume that its width and height are negligible. Therefore, the volume of the deposit is approximately 1 cm³.

Substituting the density of the deposit in place of g/cm³, we can rewrite the formula as: mass = (density in g/cm³) x (volume in cm³)mass = g x 1 cm³mass = g To express the mass of the deposit in units of grams (g), we must know the value of the density in g/cm³. Once we know this value, we can multiply it by 1 cm³ to obtain the mass in grams.

For example, if the density of the deposit is 2 g/cm³, then the mass of the deposit is: mass = 2 g/cm³ x 1 cm³mass = 2 g Therefore, the total mass of the mineral deposit along a strip of length 1 cm that has density g/cm is simply g.

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According  to stoichiometry and concept of Avogadro's number there are 3.61×10²⁴ particles for 4 moles of KClO₃.

As 2 moles of potassium chlorate gives 3 moles of oxygen , thus 4 moles of potassium chlorate will give 4×3/2=6 moles , 6 moles have 6×6.023×10²³=3.61×10²⁴ particles.

Thus,  there are 3.61×10²⁴ particles for 4 moles of KClO₃.

What is stoichiometry?

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Adding Cs2SO3, which will quickly dissolve in the solution, would increase the buffer capacity of the 1.00L aqueous solution containing Na2SO3.

Buffer capacity is a measure of the ability of a solution to resist changes in pH when an acid or base is added. It depends on the concentrations of the buffering components in the solution. In this case, the solution contains Na2SO3, which acts as a buffer.

By adding Cs2SO3, which will quickly dissolve in the solution, we are increasing the concentration of the buffering component (SO3^2-) in the solution. This increase in the concentration of the buffering component leads to an increase in the buffer capacity of the solution.

Diluting the solution with water would decrease the concentration of the buffering component, resulting in a decrease in buffer capacity. Adding KHSO3 would introduce a different buffering component, but it may or may not increase the buffer capacity depending on the specific concentrations and properties of the components. Adding excess NaOH would neutralize any H2SO3 present and disrupt the buffering system, leading to a decrease in buffer capacity.

To increase the buffer capacity of the 1.00L aqueous solution containing Na2SO3, the recommended action is to add Cs2SO3, which will quickly dissolve in the solution. This increases the concentration of the buffering component and enhances the solution's ability to resist changes in pH.

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Answer:First one is acheolgogist

Explanation:

The N/P junction in solar cells is formed where two types of silicon, N-type and P-type, meet. Electrons can wander across this junction, creating a charge imbalance. On one side, there will be an excess of electrons (negative charge), while on the other side, there will be a deficiency of electrons (positive charge).

In order to meet the world's needs with solar technology, we need to build the necessary infrastructure and put it all into action. This includes securing funding and space for solar installations, as well as deploying the necessary machinery on rooftops of homes and other suitable locations. By overcoming these challenges, we can harness solar energy to meet our energy demands.

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Answer:

8.02 g of NaOH solution

Explanation:

The endpoint of a titration is the exact point in which the solution changes colour.

First, we can start off by writing down a balance chemical equation of the situation:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(aq)

As shown in the question, the chemist needs a titre of 15.4 mL of 2.4 mol/L HCl to titrate the NaOH. Therefore, titre = 0.0154 L.

We can now find the number of moles of HCl present:

number of moles (n) = concentration (c) ÷ volume (V)

∴ n(HCl) = c/V = 2.4/0.0154 (using the titre) = 155.84 mol

Since stoichiometric ratio of the above equation is 1 : 1, therefore:

n(HCl) = n(NaOH).

∴ n(NaOH) = 155.84 mol

Now we have the number of moles of NaOH, we can rearrange the formula we used before, n = c/v to find the volume required.

v = c/n = 1.25/155.84 = 0.00802 L = 8.02 mL.

Since 1 mL is equal to 1 g, thus, we require 8.02 g of NaOH solution to titrate the HCl.

(a) Carbon monoxide (CO) emissions from internal combustion engines increase in colder climates. Thus, the environmental damage from CO emissions is worse in the winter months than in the summer months.

Nonetheless, air quality control authorities use a standard for CO that is uniform throughout the year with no allowance for seasonal effects. Suppose you are in charge of setting a policy for CO emissions. The marginal damages cost (MD) in the winter is 3E and in the summer is 2E. The MAC of CO emissions in both winter and summer is 60-E. To ensure an allocatively efficient outcome across the two seasons, the marginal damage cost (MD) and the marginal abatement cost (MAC) should be equal. At the point where MD=MAC, social welfare will be maximized. Therefore, equating marginal damage cost (MD) and marginal abatement cost (MAC) in both winter and summer gives: 3E = 60 - E2E = 60 - EE = 20. Thus, the government should set a uniform CO emission standard for winter and summer seasons at 20 to ensure an allocatively efficient outcome across the two seasons.

(b) If the government sets a policy that says emission level for winter and summer will be equiproportion, i.e., E = 15, determine the change in net benefit or welfare loss associated with this policy. MD of CO emission in winter = 3E = 3(15) = 45MD of CO emission in summer = 2E = 2(15) = 30 MAC of CO emission in both winter and summer = 60 - E = 60 - 15 = 45. For a policy that says emission level for winter and summer will be equiproportion, the level of CO emission will be E = 15. The corresponding net benefit can be found as: NB = MB - MC = (MD - MAC) * E = (45 - 45) * 15 = 0. Therefore, the net benefit or welfare loss associated with this policy is zero.

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Drawing conclusions is the process of making sense of information that has been hinted at or implied. As a result, the information is seldom given in an obvious way.

To arrive at trustworthy findings, careful evidence collecting, analysis, and judgements that can withstand scrutiny are required. As an author, you are presenting your findings for readers to assess, thus you must be compelling based on the information you present in your piece.

Posing a sound question, formulating a working hypothesis, conducting research, identifying and controlling factors, recording observations during testing, gathering data, and drawing conclusions are all necessary steps. If you use spec sheets, diagrams, and graphs, your results are simpler to organise and present.

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The literature provides the viscosity values of 1-pentanol and 1-propanol at 25 degrees Celsius.

To determine the viscosity of 1-pentanol and 1-propanol at 25 degrees Celsius, we can refer to the literature, such as scientific journals, textbooks, or databases that provide data on the physical properties of various substances. These sources often provide tables or graphs that list the viscosity values of different compounds at different temperatures.

By consulting the literature, we can find the specific viscosity values of 1-pentanol and 1-propanol at 25 degrees Celsius. The viscosity is typically expressed in units of centipoise (cP) or millipascal-second (mPa·s). These values represent the resistance of the liquids to flow and give us an indication of their internal friction.

It is important to note that the viscosity of substances can vary depending on factors such as purity, pressure, and the presence of impurities. Therefore, it is essential to refer to reliable and up-to-date literature sources to obtain accurate viscosity values for 1-pentanol and 1-propanol at 25 degrees Celsius.

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The hydrogen bonding of water is one of the main property of water which makes it responsible for all the other physical and chemical properties.

Water molecules are polar in nature and they form hydrogen bonds. Hence, they have a high boiling point , high specific heat and density. Water can exhibit the properties of an acid, as well as a base (amphoteric character). The water molecules are constantly moving and the hydrogen bonds continuously breaks and forms again. These hydrogen bonds are strong, which is the reason for the unique properties of water.

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Answer:

39

Explanation:

add em up

Answer:

Chlorine

Explanation:

The Polarity of an atom is characterized as the dipole to dipole intermolecular forces between the slightly positively-charged end of one molecule to the negative end of another or the same molecule. Thus, the 'chlorine' atom would help in enhancing the polarity of hydrogen bromide(HBr) with 3.16 electronegativity as we know, the electronegativity increases if we move upwards in the periodic table.

Answer:airr

Explanation:

The natural decomposition of crop waste is responsible for approximately 10% of global methane emissions and 1% of nitrous oxide emissions. Understanding these processes and adopting sustainable practices can help mitigate climate change and reduce the environmental impact of agricultural waste.

According to the International Biochar Initiative (2016), the natural decomposition of crop waste contributes to global methane and nitrous oxide emissions. It is estimated that approximately 10% of global methane emissions and 1% of nitrous oxide emissions are a result of this process.

When crop waste decomposes naturally, it releases methane and nitrous oxide gases into the atmosphere. Methane is a potent greenhouse gas that contributes to global warming, while nitrous oxide is a significant contributor to air pollution and ozone depletion. These emissions have adverse effects on the environment and contribute to climate change.

For example, when crop residues are left on the field after harvest, they undergo decomposition, releasing methane and nitrous oxide. The same can happen when organic waste, such as agricultural residues or food waste, is left to decompose in landfills.

Reducing these emissions is important for mitigating climate change. One way to do this is by adopting sustainable agricultural practices, such as incorporating crop residues back into the soil or using them for bioenergy production. Another method is to implement proper waste management systems, including composting or anaerobic digestion, to minimize the release of methane and nitrous oxide from organic waste.

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An oil separates crude oil into its components by distillation. some components are altered by cracking and Reforming.

The  crude oil  contains many petroleum products like petrol , diesel , Mobil oil coaltar and many more with impurities So, now it is very important to separated it into components to use all product individually in pure form.

The separation process are based on fraction distillation because all petroleum products have different density and boiling points. All products are separated at different temperature.

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Answer:

H=12

O=6+12=18

C=6

and the equation is balanced

Answer:

true I believe

Explanation: so sorry if this is wrong

7.5 × 10¹⁹ Electrons flow through a point in a wire in 3.00 s if there is a constant current of i=4.00a.

Q = I × t------------Equation 1

Where Q = charge flowing through the wire, I = current, t = time

Given: I = 4.00 A, t = 3.00 s

Substitute these values into equation 1

Q = 4.00× 3.00

Q = 12.00 C.

But,

1 electron contains 1.6×10⁻¹⁹ C

therefore,

12.00 C = 12.00/1.6×10⁻¹⁹  electrons

= 7.5 × 10¹⁹ Electrons

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Answer:

a. 3.00 mol Al = 3.00 x 27.0 g/mol = 81.0 g

b. 2.56 × 10^24 atoms Li = 2.56 × 10^24 x 6.939 g/mol = 17.75 g

c. 1.38 mol N = 1.38 x 28.0 g/mol = 38.64 g

d. 4.86 × 10^24 atoms Au = 4.86 × 10^24 x 197.0 g/mol = 961.3 g

e. 6.50 mol Cu = 6.50 x 63.5 g/mol = 410.75 g

f. 2.57 × 10^8 mol S = 2.57 × 10^8 x 32.1 g/mol = 82,567,600 g

g. 1.05 × 10^18 atoms Hg = 1.05 × 10^18 x 200.6 g/mol = 210,000 g

Answer:

One change of state happens when you add energy to the substance. This change of state is called melting. By adding energy to the molecules in a solid the molecules begin to move quicker and can break away from the other molecules.

When 25.0 grammes of Methane are consumed, 2.3385 moles of water are created.

The ratio between the atomic mass unit and gramme mass unit sizes affects the number in a mole, or Avogadro's number. One mole of hydrogen atoms weighs around one gramme, compared to the mass of one hydrogen atom, which is roughly one unit.

2 CH3CH3(g) + 5 O₂(g) → 4 CO₂(g) + 6 H₂O(g)

The molar mass of Methane is 16.04 g/mol, so 25.0 grams of CH₄ is equal to:

25.0 g / 16.04 g/mol = 1.559 mol CH₄

From the balanced equation, the molar ratio of CH₄ to Water is 2:3. Therefore, for every 2 moles of Methane consumed, 3 moles of Water are produced.

So, for 1.559 mol of CH₄ consumed, the amount of Water produced would be:

3/2 x 1.559 mol = 2.3385 mol

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Answer:

149.09 g/mol GOOD LESSONS ♡

Answer:

The answer is 149.09 g/mol

Explanation:

I hope this helps!!

a. The theoretical yield of silver bromide precipitated from 2.96 g of iron(III) bromide reacting with excess silver nitrate is 5.63 g AgBr.

b. If 5.00 g of AgBr is produced, the percent yield is 88.8%.

c. The molarity of a NaCl solution, if 5.33g NaCl is dissolved in 775 mL solution, is 0.117 M.

d. If 25.0 mL of seawater has a mass of 25.895 g and contains 1.295 g of solute, the % NaCl of the seawater is 4.99%.

a. To determine the theoretical yield of silver bromide precipitated from 2.96 g of iron(III) bromide reacting with excess silver nitrate, we must write the balanced chemical equation is:

FeBr₃(s) + 3AgNO₃(aq) → 3AgBr(s) + Fe(NO₃)₃(aq)

The molar mass of FeBr₃ is 295.63 g/mol. 3 moles of AgBr are produced from 1 mole of FeBr₃ and 3 moles of AgNO. So, the theoretical yield of AgBr can be calculated as:

Mass of FeBr₃ = 2.96 g

Moles of FeBr₃ = 2.96 g / 295.63 g/mol = 0.01 mol

Moles of AgBr = 3 × 0.01 mol = 0.03 mol

Molar mass of AgBr = 187.77 g/mol

Theoretical yield of AgBr = 0.03 mol × 187.77 g/mol = 5.63 g AgBr

b. To determine the percent yield of AgBr, we can use the formula:

Percent yield = Actual yield / Theoretical yield × 100

Actual yield = 5.00 g

Theoretical yield = 5.63 g

Percent yield = 5.00 g / 5.63 g × 100 = 88.8%

c. To calculate the molarity of a NaCl solution, if 5.33g NaCl is dissolved in 775 mL solution, we must know the molar mass of NaCl is 58.44 g/mol. The number of moles of NaCl is:

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 5.33 g / 58.44 g/mol = 0.091 mol

Volume of the solution = 775 mL = 0.775 L

The molarity of the NaCl solution is:

Molarity = moles of solute / volume of solution

Molarity = 0.091 mol / 0.775 L = 0.117 M

d. To find the mass percent of NaCl, we can use the formula:

Mass percent of NaCl = (mass of NaCl / mass of seawater) × 100

Mass percent of NaCl = (1.295 g / 25.895 g) × 100 = 4.99%

Therefore, the % NaCl of the seawater is 4.99%.

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Answer:

As what the person above me said bottom of the cup

Explanation:

Use of thermostat is the most effective way to keep the reaction at a control temperature.

The reaction takes place in a thermostat is the most effective way to keep the reaction at a controlled and steady temperature because thermostat regulates the temperature of that solution which is placed in it. If the temperature goes higher then the extra heat is released from the system.

So we can conclude that use of thermostat is the most effective way to keep the reaction at a control temperature.

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The work function of the metal is 5.2 * 10^-19 J while the number of electrons is 2.3 * 10^12 electrons.

From the photoelectric theory of Einstein, electrons are emitted when light of appropriate wavelength is incident on a clean metal surface. The minimum energy that the incident light must possess is called the  work function of the metal.

We know that;

Kinetic energy = Energy of incident photon - Work function

Energy of incident photon = hf = 6.6 * 10^-34 Js * 1.34×10^15 s−1

= 8.8 * 10^-19 J

Work function = Energy of incident photon - Kinetic energy

Work function = 8.8 * 10^-19 J - 3.60×10^−19 J

Work function = 5.2 * 10^-19 J

Now;

The total energy = 3.67×10−7 J

Hence;

3.67×10−7 J = n * 1.6 * 10^-19 J

n = 3.67×10−7 J/1.6 * 10^-19 J

n = 2.3 * 10^12 electrons

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Answer:

make a observations first, secondly make observations, and thirdly experiment and fourthly conclusion