A 60 foot tall building casts a 20 foot. Shadow. Use the principles of similar triangles to determine the length of a shadow cast by a 5 foot 6 inch student

A shop is open 9 am - 7 pm. the function r(t), graphed above, gives the rate at which customers arrive (in people/hour) at time t, the line will vanish at 9 am + 2.5 hours = 11:30 am.

Since the salespeople can serve customers at a rate of 75 people per hour, the net rate at which customers are added to the line is given by:

Net rate = R(t) - 75

where R(t) is the rate at which customers arrive.

The line will vanish when the net rate becomes zero, which means that the rate at which customers are added to the line is equal to the rate at which they are served. Thus, we have:

R(t) - 75 = 0

Solving for t, we get:

R(t) = 75

Looking at the graph, we can see that R(t) is equal to 75 at approximately 2.5 hours after 9 am. Therefore, the line will vanish at 9 am + 2.5 hours = 11:30 am.

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Answer:

6ft

Step-by-step explanation:

the formula for the area of a square is side^2

sqrt of 36 is 6, therefore, all 4 sides of the square is 6ft

Answer:

start your grap at (0,7) and go up 5 to the right 1 and down 5 to the left 1

Answer:

XW = 134

Step-by-step explanation:

The fact that YZ bisects VW means that the angles VX and XW are supplementary, that is, they add to 180º. So

VX + XW = 180

We have that VX = 46. So

46 + XW = 180

XW = 134

Answer: d=50+20w

D(deposit) = 50(starting amount)+20(added amount)w(multiply 20 by the amount of weeks, 12, and this is your equation.)

Answer:

x-6 = -4

Step-by-step explanation:

\(3x-8=-2\\3x=6\\x=2\\\\x-6=2-6=-4\)

The answer would be x-6 = -4

Hope you find this useful!

The phase portrait of the differential equation 2y^n - y' = 0 will consist of a single equilibrium point at (0, 0) and arrows diverging away from the equilibrium in both positive and negative y directions.

To sketch the phase portrait of the differential equation 2y^n - y' = 0, we need to analyze the equilibriam and the orientations or directions of the arrows.

First, let's find the equilibria by setting y' to zero and solving for y. In this case, we have:

2y^n - y' = 0

2y^n - 0 = 0

2y^n = 0

From this equation, we can see that the only equilibrium occurs when y = 0. Thus, the phase portrait will have a single equilibrium point at (0, 0).

Next, we need to determine the orientations or directions of the arrows around the equilibrium point. To do this, we can choose some test points to the left and right of the equilibrium and evaluate the sign of y' to determine whether the arrows are pointing towards or away from the equilibrium.

Let's consider a test point y = -1, which is to the left of the equilibrium at y = 0. Substituting this value into the differential equation, we have:

2(-1)^n - y' = 0

2(-1)^n = y'

For even values of n, we get:

2 - y' = 0

y' = 2

Since y' is positive (2 > 0), the arrows at y = -1 will be pointing away from the equilibrium.

Now let's consider a test point y = 1, which is to the right of the equilibrium at y = 0. Substituting this value into the differential equation, we have:

2(1)^n - y' = 0

2 - y' = 0

y' = 2

Again, we find that y' is positive (2 > 0), indicating that the arrows at y = 1 will be pointing away from the equilibrium.

Based on this analysis, we can sketch the phase portrait of the differential equation. Since the orientations of the arrows are pointing away from the equilibrium at y = 0 for both positive and negative y values, the phase portrait will show arrows diverging away from the equilibrium in both directions.

The phase portrait will have a single equilibrium point at (0, 0), with arrows diverging away from it in both the positive and negative y directions. It is important to note that the specific shape and scale of the phase portrait will depend on the value of n, which is not specified in the given equation.

In summary, the phase portrait of the differential equation 2y^n - y' = 0 will consist of a single equilibrium point at (0, 0) and arrows diverging away from the equilibrium in both positive and negative y directions.

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Answer:

Step-by-step explanation:

first, the coeieicne infront of x^2 term musbe 1

so if you have

y=ax^2+bx+c

isolate x terms and undistribute a

y=a(x^2+(b/a)x)+c

This expression for t1 does not depend on t2 and is expressed in terms of the given variables m, θ1, θ2, and the acceleration due to gravity g.

First, let's analyze the forces acting on the mass m.

There are three forces acting on the mass:
1. Gravitational force (mg) acting downwards
2. Tension force t1 acting at an angle θ1 from the vertical
3. Tension force t2 acting at an angle θ2 from the vertical

We can resolve these forces into their vertical and horizontal components.

For the vertical components, we have:
t1 * sin(θ1) + t2 * sin(θ2) = mg

For the horizontal components, we have:
t1 * cos(θ1) = t2 * cos(θ2)

Now we need to eliminate t2 from these equations. Divide the first equation by sin(θ2) and the second equation by cos(θ2):

t1 * sin(θ1) / sin(θ2) + t2 = mg / sin(θ2)
t1 * cos(θ1) / cos(θ2) = t2

Now we can substitute the expression for t2 from the second equation into the first equation:

t1 * sin(θ1) / sin(θ2) + t1 * cos(θ1) / cos(θ2) = mg / sin(θ2)

Factor out t1 from the left side:

t1 * (sin(θ1) / sin(θ2) + cos(θ1) / cos(θ2)) = mg / sin(θ2)

Finally, solve for t1:

t1 = (mg / sin(θ2)) / (sin(θ1) / sin(θ2) + cos(θ1) / cos(θ2))

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Answer: See explanation

Step-by-step explanation:

3.) Boys║5║10 ║60

    Girls ║7║ 14 ║84

7 × 2 = 14

5 × 2 = 10

5 × 12 = 60

7 × 12 = 84

Hope I helped!

If there are 342 more trees bearing red apples than trees bearing green apples, then the number of trees with green apples are 1336.

The 3/5 of fruit trees are orange trees, then 2/5 of the fruit trees are apple trees.

Let the total number of fruit trees be = x. Then we can write two equations based on the given information that, there are 4515 orange trees and there are 342 more red apple trees than green apple trees,

The equations are :

⇒ 3/5 x = 4515         ...equation(1)

⇒ x - 4515 = (G + 342) + G   ...equation(2)

Where G is the number of trees bearing green apples.

From equation(1), we can solve for x:

x = (4515)/(3/5) = 7525

Substituting this value of "x" into equation(2),

We get,

⇒ 7525 - 4515 = (G + 342) + G

⇒ 3010 = 2G + 342

⇒ 2668 = 2G

⇒ G = 1334.

Therefore, there are 1336 trees with green apples.

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The given question is incomplete, the complete question is

A fruit plantation has two types of fruit trees: apple trees and orange trees. 3/5 of the fruit trees are orange trees. There are 4515 orange trees on the plantation. The apple trees bear apples of two different colors. There are 342 more trees bearing red apples than trees bearing green apples.

How many trees with green apples are there?

Answer:

440

Step-by-step explanation:

The true statement about RR and AR measure is that all of the given options (A, B, C, and D) are accurate. Therefore, the correct answer is E, "NONE of the above."

A. Relative Risk (RR) is indeed a useful measure in etiologic studies of disease. It quantifies the association between a specific exposure and the risk of developing a particular disease or condition. By comparing the risk of disease between exposed and unexposed individuals, researchers can assess the strength of the relationship.

B. Attribute Risk (AR) is a measure of the proportion of disease risk that can be attributed to a specific exposure. It indicates the excess risk of disease associated with the exposure. AR is valuable in understanding the impact of a particular factor on the occurrence of a disease and can aid in making informed decisions regarding prevention and control strategies.

C. Attributable Risk (AR) has significant applications in clinical practice and public health. It helps identify modifiable risk factors and guides interventions to reduce the burden of disease. AR estimates can be used to allocate resources effectively, implement targeted prevention programs, and develop public health policies.

D. Relative Risk (RR) does indicate the strength of association between disease and exposure. It compares the risk of disease in exposed individuals to the risk in unexposed individuals. The magnitude of RR reflects the degree of association, with higher values indicating a stronger relationship between the exposure and the disease outcome.

Since all of the statements provided in the options (A, B, C, and D) are true, the correct answer is E, "NONE of the above."

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Answer:

Hey there!

-4/3-4/5

-20/15-12/15

-32/15

Let me know if this helps :)

it's A

Step-by-step explanation:

describes 55 per unit/the hour

The polynomic function that contains the points (0, 6), (3, 15.8) and (9.5, 0) is a quadratic function, whose model is y = -0.600 · x² + 5.066 · x + 6.

To determine the coefficients of a polynomic function we must know a set of distinct points, whose number is the same number of coefficients. In this case, we can derive a quadratic function, as quadratic functions have three coefficients:

y = a · x² + b · x + c     (1)

Now we substitute x and y in (1) and solve the resulting system of linear equations:

c = 6

9 · a + 3 · b + c = 15.8

90.25 · a + 9.5 · b + c = 0

Whose solution is a ≈ -0.600, b ≈ 5.066 and c = 6.

The statement is incomplete. The complete form is shown below:

There is a polynomial function. Find the function of (0, 6), (3, 15.8) and (9.5, 0).

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The task is to find the convolution of the marginal distributions of two independent random variables x and y with identical geometric distributions.

To find the convolution of the marginal distributions of x and y, we need to calculate the probability distribution function of the sum of x and y. Since x and y have identical geometric distributions, we know that the probability of x=k and y=m is given by p(x=k, y=m) = (1-p)^k * p * (1-p)^m * p = p^2 * (1-p)^(k+m), where p is the probability of success in each trial of the geometric distribution.

To find the probability distribution function of the sum Z=x+y, we need to compute the probability of each possible value of Z. That is, P(Z=k) = Σ P(X=i, Y=k-i) for all i from 0 to k. Plugging in the probability distribution function of x and y, we get P(Z=k) = Σ p^2 * (1-p)^(i+k-i) = p^2 * (1-p)^k * Σ 1. The summation is over all i from 0 to k, and is equal to k+1. Therefore, we have P(Z=k) = (k+1) * p^2 * (1-p)^k. This is the probability distribution function of the sum of two independent random variables x and y with identical geometric distributions, and is the convolution of the marginal distributions of x and y.

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The distance between ping's home to aris's home will be 1 street and 12th avenue.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Summation = addition of two or more numbers or variable

For example = 2 + 8 + 9

Subtraction = Minus of any two or more numbers with each other called subtraction.

For example = 4 - 8

Division = divide any two numbers or variable called division.

For example 4/8

Multiplication = to multiply any two or more numbers or variables called multiplication.

For example 5 × 7.

Given,

Ping house ⇒ 3rd street and 6th avenue

Ari's home ⇒  21st street and 18th avenue

So, the distance between them

21 - 3 = 18 street

18 - 6 = 12 avenue.

Hence "The distance between ping's home to aris's home will be 1 street and 12th avenue".

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Therefore, the perimeter of triangle STU is approximately 693 ft.

If triangles PQR and STU are similar, it means that the corresponding sides are proportional. Let's denote the perimeter of triangle STU as P_stu.

Given:

Perimeter of triangle PQR = 249 ft.

Length of one corresponding side in PQR = 46 ft.

Length of the corresponding side in STU = 128 ft.

To find the perimeter of triangle STU, we need to determine the scale factor between the two triangles, and then multiply the corresponding sides of PQR by this scale factor.

Scale factor = Length of corresponding side in STU / Length of corresponding side in PQR

Scale factor = 128 ft / 46 ft

Now, we can calculate the perimeter of triangle STU using the scale factor:

P_stu = Perimeter of triangle PQR * Scale factor

P_stu = 249 ft * (128 ft / 46 ft)

P_stu = 693 ft (rounded to one decimal place)

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The solution of the equation 3z minus 2 is equal to 46 is 16.

The given equation '3z minus 2 is equal to 46' can be written as

    3z - 2  =   46

Now solving for z because the value of z will give the required solution of the given equation. So now finding the z from the equation:

   3z = 46  + 2

   3z =  48

   z = 48/3

   z = 16

The value of the z is 16 which represents the solution of the given equation i.e 3z minus 2 is equal to 46.

Therefore it is concluded that the solution of the equation 3z minus 2 is equal to 46 is 16.

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Answer:

-34.2

Step-by-step explanation:

5.7

x 6

___

34.2 (add negative sign cuz the bigger number is negative)

Please mark me brainliest If I help :)

The y-coordinate of the point of diminishing returns is not defined. The initial supply of the market is 160.

Given function is:

s(t) = 4000/9 + (18e^(-1.43t))/9

We are required to find the y-coordinate of the point of diminishing returns.

Diminishing returns occur when the rate of growth slows down and it becomes increasingly difficult to increase the output with additional resources.

Let us find the point of diminishing returns.

The point of diminishing returns is obtained by differentiating the given function and equating it to zero.

s(t) = 4000/9 + (18e^(-1.43t))/9Let f(t)

= s(t) = 4000/9 + (18e^(-1.43t))/9f'(t)

= (-18 x 1.43 e^(-1.43t)) / 81

= (-2 e^(-1.43t)) / 9

Equating it to zero, we get-2 e^(-1.43t) / 9 = 0e^(-1.43t) = 0

Thus, we can see that there is no solution to this equation.

Hence, the point of diminishing returns does not exist for the given function.

Hence, the y-coordinate of the point of diminishing returns is not defined.

For the second part of the question, we are required to find the initial supply of the market.

The given function is:

s(t) = 4000 / (5 + 20e^(-0.71t))

Let us find the initial supply of the market.

For t = 0, we get:

s(0) = 4000 / (5 + 20e^(0))

= 4000 / 25

= 160

Hence, the initial supply of the market is 160.

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\(6^{\frac{1}{2} } .12^{\frac{1}{2} }\) can be simplified into 8.48.

Prime factorization is the process of breaking down a number into its prime factors. Multiplying these prime numbers gives back the original number.

Prime factorization of 6= 2 x 3

Prime factorization of 12= 3 x 2 x 2

According to the law of indices, if a term with a power is raised to a power, then the powers are multiplied together.

i.e., \((x^{m} )^{n} = x^{mn}\)

Another law of indices says that if two terms having same base are multiplied together, then their indices are added.

i.e., \(a^{m} X a^{n} = a^{m+n}\)

According to the given condition,

Applying the laws of indices mentioned above,

∴\(6^{\frac{1}{2} } .12^{\frac{1}{2} }\) = \((2 X 3)^{\frac{1}{2} } . (3 X 2^{2}) ^{\frac{1}{2} }\)

=  \((3^{2} X 2^{3})^{\frac{1}{2} }\)

= \(\sqrt{72}\) = 8.48.

Thus, \(6^{\frac{1}{2} } .12^{\frac{1}{2} }\) can be simplified into 8.48.

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Answer:

3

Step-by-step explanation:

Prime factorize 42 and 3 and you'll eventually get 3 as your answer.

Answer:

3

Step-by-step explanation:

Since you are looking for the greatest common factor, 3 cant have many factors other than itself. So it would be 3, when simplified its similar to 42/3 and 3/3 where it would be 14 and 1.

The research reveals that emotional people tend to be more satisfied with their jobs, committed to their employer, and produce more work than conscientious individuals is False.

Emotional intellect is the capacity to recognize and regulate a person's emotions and comprehend the emotions the others. A high EQ helps you to build connections, lower team stress, defuse battles and improve job fulfillment.

It can help a graduate evolve the best at what they do, be the best coworker possible, and achieve professional victory. Communication, partnership, and relationship-building skills are enhanced by higher levels of emotional intelligence. It also enables best focus on the work.

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The complete question is-

research reveals that emotional people tend to be more satisfied with their jobs, committed to their employer, and produce more work than conscientious individuals.

a. True

b. False

the answer must be t equal to Q over MC

Answer:

T= Q over MC

Step-by-step explanation:

I did the test

To use the Laplace transformation to solve the following differential equation, we will first apply the transformation to the problem and its initial conditions. F(s) denotes the Laplace transform of a function f(x) and is defined as: \(Lf(x) = F(s) = [0,] f(x)e(-sx)dx\)

When the Laplace transformation is applied to the given differential equation, we get:

\(Ld2y/dx2/dx2 + Ly = 0\) .

If we take the Laplace transform of each term, we get: \(s^2Y(s) = 0 - sy(0) - y'(0) + Y(s)\).

Dividing both sides by \((s^2 + 1),\), we obtain:

\(Y(s) = (s + 2) / (s^2 + 1)\).

Now, we can use the partial fraction decomposition to express Y(s) in terms of simpler fractions:

Y(s) = (s + 2) / (\(s^{2}\)+ 1) = A/(s - i) + B/(s + i) .

Multiplying through by (\(s^{2}\) + 1), we have:

s + 2 = A(s + i) + B(s - i).

Expanding and collecting like terms, we get:

s + 2 = (A + B)s + (Ai - Bi).

Comparing the coefficients of s on both sides, we have:

1 = A + B and 2 = Ai - Bi.

From the first equation, we can solve for B in terms of A:B = 1 - A Substituting B into the second equation, we have:

2 = Ai - (1 - A)i

2 = Ai - i + Ai

2 = 2Ai - i

From this equation, we can see that A = 1/2 and B = 1/2. Substituting the values of A and B back into the partial fraction decomposition, we have:

Y(s) = (1/2)/(s - i) + (1/2)/(s + i). Now, we can take the inverse Laplace transform of Y(s) to obtain the solution y(x) in the time domain. The inverse Laplace transform of 1/(s - i) is \(e^(ix).\)

As a result, the following is the solution to the given differential equation:\((1/2)e^(ix) + (1/2)e^(-ix) = y(x).\)

Simplifying even further, we get: y(x) = sin(x)

As a result, given the initial conditions dy(0)/dx = 2 and y(0) = 1, the solution to the above differential equation is y(x) = cos(x).

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