A community center sells a total of 295 tickets for a basketball game. An adult ticket costs $4. A student ticket costs $1. The sponsors
collect $574 in ticket sales. Find the number of each type of ticket sold.
The number of adult tickets sold should be ____and the number of student tickets sold should be _____
(Simplify your answers.)

Answer:

b

Step-by-step explanation:

Answer:-6s-2r

Step-by-step explanation:

you must add all like terms in this case S -4-3 is -7. -7+1=-6.
-6s-2r

Answer:

-6r - 2s

Step-by-step explanation:

Given expression,

→ -4r + s - 2r - 3s

Let's simplify the expression,

→ -4r + s - 2r - 3s

→ (-4r - 2r) + (s - 3s)

→ -6r + (-2s)

→ -6r - 2s

Hence, the answer is -6r - 2s.

if  Lines p and q are also parallel to each other then value of x is 100, option C is correct.

Parallel lines are coplanar infinite straight lines that do not intersect at any point.

The known angle is supplementary with angle A (Look at the attachment), that means that the sum of the known angle and A is 180°, therefore the value of angle A is 80°

Angle A and B are corresponding angles, which means that they have the same value, that happens because p and q are parallels and both cut line n  in the same way. the value of the angles B is 80°

Angles B and C are corresponding too, so the value of the angle C is 80°.

Angles C and X are supplementary too for which the sum of X and C  is 180°, so the value of X is 100°

Hence, if  Lines p and q are also parallel to each other then value of x is 100, option C is correct.

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Answer:

0.73

Step-by-step explanation:

the probability that it is not X is 1-0.4 = 0.6

The probability that it is not Y is 1-0.5 = 0.5

The probability that it is not Z is 1-0.1 = 0.9

So the probability that it is not any of these is

0.6x0.5x0.9 = 0.27

So the probability that it is X Y or Z is 1-0.27 = 0.73

The definite integral is 3/4. To evaluate the definite integral using Part 2 of the Fundamental Theorem of Calculus combined with Substitution, follow these steps:

1. Identify the function and its derivative: Here, the function is f(x) = (1 + x²) and its derivative is f'(x) = 2x.
2. Perform Substitution: Let u = 1 + x². Then, du/dx = 2x, or du = 2x dx. Now, substitute the variables and adjust the integral limits. When x = 0, u = 1, and when x = 1, u = 2. The integral becomes:
∫[1, 2] u * (1/2)du.
3. Integrate with respect to u: The integral becomes (1/2) ∫[1, 2] u du. Now, integrate:
(1/2) * (u²/2) | [1, 2] = (1/4) * (u²) | [1, 2].
4. Apply the Fundamental Theorem of Calculus Part 2: Evaluate the antiderivative at the limits and subtract:
(1/4) * (2²) - (1/4) * (1²) = (1/4) * (4 - 1) = (1/4) * 3 = 3/4.
So, the definite integral is 3/4.

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Answer:

-24

Step-by-step explanation:

I think its D i hope this helps :D

Answer:

A. 3 is the answer of questions

Answer:

herefore, the degree of the Maclaurin polynomial required for the error in the approximation of sin(x) at x = 0.7 to be less than 0.001 is 3. Using the Maclaurin series up to degree 3, we get:sin(0.7) ≈ 0.7 - 0.7^3/3!sin(0.7) ≈ 0.6433This approximation is accurate to within 0.001.

Step-by-step explanation:

We can use Taylor's theorem with the remainder in Lagrange form to estimate the error in approximating sin(x) with its Maclaurin polynomial:|Rn(x)| ≤ M * |x - a|^(n+1) / (n+1)!where:

Rn(x) is the remainder (the difference between the exact value of the function and its approximation using the Maclaurin polynomial)

M is an upper bound on the (n+1)st derivative of the function on the interval [0, x]

a is the center of the Maclaurin series (in this case, a = 0)

n is the degree of the Maclaurin polynomialSince sin(x) is continuous and differentiable for all x, we know that the Maclaurin series for sin(x) converges to sin(x) for all x. Therefore, we can use the Maclaurin series for sin(x) to approximate sin(0.7):sin(x) = x - x^3/3! + x^5/5! - x^7/7! + ...sin(0.7) ≈ 0.7 - 0.7^3/3! + 0.7^5/5!sin(0.7) ≈ 0.6442 (rounded to four decimal places)To find the degree of the Maclaurin polynomial required for the error in this approximation to be less than 0.001, we need to solve the following inequality for n:0.7^(n+1) / (n+1)! ≤ 0.001We can use a calculator or a table of values for factorials to solve this inequality. One possible method is to try different values of n until we find the smallest value that satisfies the inequality.Starting with n = 2, we get:0.7^3 / 3! ≈ 0.082This is not less than 0.001, so we try n = 3:0.7^4 / 4! ≈ 0.005This is less than 0.001, so we have found the degree of the Maclaurin polynomial required for the error to be less than 0.001:n = 3Therefore, the degree of the Maclaurin polynomial required for the error in the approximation of sin(x) at x = 0.7 to be less than 0.001 is 3. Using the Maclaurin series up to degree 3, we get:sin(0.7) ≈ 0.7 - 0.7^3/3!sin(0.7) ≈ 0.6433This approximation is accurate to within 0.001.

We need at least a degree 4 Maclaurin polynomial to approximate sin(x) at x = 0.7 with an error less than 0.001.

To determine the degree of the Maclaurin polynomial required for the error in the approximation of the function sin(x) at x = 0.7 to be less than 0.001, we need to consider the following:

1. The Maclaurin series for sin(x) is given by:
sin(x) = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ...

2. The error in a Maclaurin series approximation can be estimated using the remainder term formula:
|error| ≤ |(x^n+1)/(n+1)!|

3. Plug in the desired error and x value (0.001 and 0.7, respectively) to find the smallest n such that the error is less than 0.001:
|0.001| ≤ |(0.7^n+1)/(n+1)!|

4. Iterate through different values of n (starting with n = 0) until the inequality is satisfied. Remember that n must be an even number as sin(x) is an odd function.

After iterating through different values of n, you will find that the smallest even n that satisfies the inequality is 4. Therefore, the degree of the Maclaurin polynomial required for the error in the approximation of sin(0.7) to be less than 0.001 is 4.

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Answer: \(y=\frac{3}{17}x-13\)

Step-by-step explanation:

Find the slope of the line between (-17, -16) and (0,-13) using \(m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\), the change of y over the change of x

\(m=\frac{3}{17}\)

Use the slope and a given point to substitute for \(x_{1}\) and \(y_{1}\) in the point-slope form \(y-y_{1} =m(x-x_{1} )\).

\(y-(-16)=\frac{3}{17}(x+17)\)

Solve for y and rewrite into \(y=mx+b\)

\(y=\frac{3}{17}x-13\)

The probability that the Bulls would get 4 wins is 0.311, the probability that the Knicks would get 4 wins is 0.088, and the probability this series goes to 7 games is 0.384.

Given that the Bulls had a 60% chance of winning, we can calculate the probabilities as follows:

Probability of the Bulls winning 4 games: (0.6)^4*(0.4)^3*(nCr(7,4)) = 0.311

Probability of the Knicks winning 4 games: (0.4)^4*(0.6)^3*(nCr(7,4)) = 0.088

Probability that the series goes to 7 games: (nCr(6,3) + nCr(6,4) + nCr(6,5) + nCr(6,6))*(0.6)^3*(0.4)^3 = 0.384

Therefore, the probability that the Bulls would get 4 wins is 0.311, the probability that the Knicks would get 4 wins is 0.088, and the probability this series goes to 7 games is 0.384.

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Answer:

4:29

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

The derivative of the function f(x) = cos(2x/3) is f'(x) = -2/3 sin(2x/3). The derivative allows us to determine whether the function is strictly monotonic on its entire domain, which in turn determines if it has an inverse function.

To find the derivative of the function f(x) = cos(2x/3), we apply the chain rule. The derivative of cos(u) is -sin(u), and the derivative of the inner function 2x/3 with respect to x is 2/3. Therefore, the derivative of f(x) is f'(x) = -2/3 sin(2x/3).

To determine if the function is strictly monotonic on its entire domain, we examine the sign of the derivative. Since sin(u) oscillates between -1 and 1, the sign of -2/3 sin(2x/3) will depend on the value of x. Since the derivative is negative, it means that the function is decreasing when sin(2x/3) is positive, and increasing when sin(2x/3) is negative.

Since sin(2x/3) can take on both positive and negative values, the function f(x) = cos(2x/3) is not strictly monotonic on its entire domain. Therefore, it does not have an inverse function. However, it is possible to restrict the domain to intervals where sin(2x/3) maintains a consistent sign, which would allow the function to have local inverse functions on those intervals.

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Step-by-step explanation:

I don't know if you do this the same way I did, but..

The first step is to subtract 9 on both sides, like this.

13w + 9 = 178

       -9    -9

You'll end up with:

13w = 169

I don't know if you need the answer or not but I'll help you out.

For the second step, divide both sides by 13w.

13w = 169

/13w   /13w

 w = 13

Hope this helped!

Answer:

The first step is that you have to subtract 9 from both sides and you are left with 13w=169 now divide both sides by 13 and you get 13 as your answer.

Step-by-step explanation:

Answer:

translate by (-5,3) means 5 units to left and 3 to up

first to left:

√(2x)→√(2(x+5))→√(2x+10)

then to up:

√(2x+10)→√(2x+10)+3

Taylor polynomials T2 and T3 centered at x = 0 for the function f(x) = 11ln(x + 1) are:

T2(x) = 11x - (11 / 2)x^2

T3(x) = 11x - (11 / 2)x^2 + 11 / 3 x^3

To find the Taylor polynomials T2 and T3 centered at x = a for the function f(x) = 11ln(x + 1), where a = 0, we'll need to calculate the function's derivatives at x = 0.

First, let's find the derivatives:

f'(x) = 11 / (x + 1)

f''(x) = -11 / (x + 1)^2

f'''(x) = 22 / (x + 1)^3

Now, let's calculate the Taylor polynomials:

T2(x) = f(a) + f'(a)(x - a) + (f''(a) / 2!)(x - a)^2

T2(x) = f(0) + f'(0)(x - 0) + (f''(0) / 2!)(x - 0)^2

T2(x) = 11ln(0 + 1) + 11 / (0 + 1)(x - 0) - 11 / (0 + 1)^2 / 2 (x - 0)^2

T2(x) = 11ln(1) + 11 / 1(x) - 11 / 1^2 / 2 (x)^2

T2(x) = 0 + 11x - 11 / 2 x^2

T2(x) = 11x - (11 / 2)x^2

T3(x) = T2(x) + (f'''(a) / 3!)(x - a)^3

T3(x) = 11x - (11 / 2)x^2 + (22 / 3!)(x - 0)^3

T3(x) = 11x - (11 / 2)x^2 + 22 / 3! x^3

T3(x) = 11x - (11 / 2)x^2 + 11 / 3 x^3

Therefore, the Taylor polynomials T2 and T3 centered at x = 0 for the function f(x) = 11ln(x + 1) are:

T2(x) = 11x - (11 / 2)x^2

T3(x) = 11x - (11 / 2)x^2 + 11 / 3 x^3

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The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day 3 days a week is 0.653, which is equivalent to 65.3%.

It is important to note that this value is based on a random sample of respondents and may not necessarily represent the true proportion of the entire population of Vermont who exercise regularly.

To find the sample proportion of people from Vermont who exercised for at least 30 minutes a day, 3 days a week, follow these steps:

1. Convert the given percentage (65.3%) to a decimal by dividing by 100: 65.3 / 100 = 0.653
2. Multiply the decimal by the number of participants in the random sample (100 respondents): 0.653 * 100 = 65.3
3. Round the result to the nearest whole number to find the number of participants who exercised: 65.3 ≈ 65
4. Divide the number of participants who exercised (65) by the total number of participants in the random sample (100): 65 / 100 = 0.65

This means that out of the 100 participants sampled from Vermont, 65.3 of them answered "yes" to the question of whether they had exercised for more than 30 minutes a day for three days out of the week.

The value of the sample proportion of people from Vermont who exercised for at least 30 minutes a day, 3 days a week is 0.65 or 65%.

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Answer:

m=7

Step-by-step explanation:

subract 35 from both sides to isolate the variable. Then you should be left with 5m=35. From there, divide both sides to isolate the variable even more, and you should be left with m=35/5 which is 7.

Answer: m=7

Step-by-step explanation:

\(5m+35=70\)

subtract 35 on both sides

\(5m+35-35=70-35\)

\(5m=35\)

divide 5 on both sides

\(35/5=7\)

\(m=7\)

Answer:

C 72

Step-by-step explanation:

complementary meaning they add up to 90 degrees, so 90-18=72

Answer:

72 Degrees

Step-by-step explanation:

Complementary are angles that add up to 90 degrees. So 90 - 18.

Answer:

3/15 or 0.2

Step-by-step explanation:

You would need to subtract as it is asking for amount MORE won.

2/3 - 7/15

Make the denominator the same in order to subtract.

= 10/15 - 7/15

Subtract.

= 3/15

Answer:

The triangles are congruent by congruency theorem SAS.

Step-by-step explanation:

Side-Angle-Side, as it suggests, is when a triangle is congruent by the order of congruent side, congruent angle, and another congruent side. If named certain ways, they can be congruent. Since the question does not provide a specific way of naming the triangles, we can assume that any way is allowed. 2.5 and 2.5 are congruent, followed by angles D and G which have the congruent angle markers. The congruent angles are followed by 1.7 and 1.7, making the triangles congruent by Side-Angle-Side.

Triangular numbers are a pattern of numbers that form equilateral triangles. Each subsequent number in the sequence adds a new row of dots to the triangle.

In each case, the number of dots in the lower row increases by 1. We can depict this by:

Therefore, putting this in summation form gives:

Effective leadership can be demonstrated in many different ways, but here are a few examples of actions that may indicate effective leadership by a group leader:

1. Clear communication: A group leader who communicates clearly and effectively with their team is more likely to build trust and respect among the group.

2. Empathy and emotional intelligence: A leader who demonstrates empathy and emotional intelligence can help build a positive team culture by understanding and acknowledging the feelings and needs of their team members.

3. Delegation and empowerment: An effective leader knows how to delegate tasks and responsibilities to team members in a way that maximizes their strengths and abilities, while also providing support and guidance as needed.

4. Leading by example: A leader who sets a positive example for their team by modeling the behaviors and attitudes they want to see in their team is more likely to earn respect and trust from their team members.

5. Strategic thinking: A leader who is able to think strategically and make informed decisions based on data and evidence can help steer their team towards success.

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Answer:

b

Step-by-step explanation:

5(2x - 1) = 6 ← distribute parenthesis on left side

10x - 5 = 6 ( add 5 to both sides )

10x = 11 ( divide both sides by 10 )

x = \(\frac{11}{10}\)

Step-by-step explanation:

61 degree

180 _ 58 =122

122 is the sum of the two angles

If we divide 122 by 2 we'll get 61

Answer:

61°

Step-by-step explanation:

hope this helps! :D

Answer:

First term=1024

Common ratio = ½

Step-by-step explanation:

Index means its position

Even index means the 2nd, 4th, 6th ....terms

Answer:

6 = 4

Step-by-step explanation:

<3

Answer:

Because the residual plot does not show a clear pattern, a linear model is appropriate.

Step-by-step explanation:

Answer:

I THINK ( A ) IS CORRECT ANSWER

I THINK ( A ) IS CORRECT ANSWERHOPE THIS HELPS U!!!

To find the 95th quantile of coded weight for a continuous random variable with a given density function fX(x) = 2/16 x, where 0 < x < 4, follow these steps:

1. Find the cumulative distribution function (CDF) by integrating the density function:

F(x) = ∫fX(x) dx = ∫(2/16 x) dx, with limits 0 to x.

2. Calculate the CDF:

F(x) = x^2/16, with limits 0 to x.

3. Find the 95th quantile (0.95) by setting F(x) equal to 0.95:

0.95 = x^2/16

4. Solve for x, the 95th quantile of coded weight:

x^2 = 0.95 * 16
x^2 = 15.2
x = sqrt(15.2)
x ≈ 3.898

So, the 95th quantile of coded weight is approximately 3.898.

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