A club sold $555 worth of
tickets
Fair. Each ticket cost
$5. How many
tickets did they sold?
​

we have that

mean=(1*6+2*7+3*x+4*5+5*3)/(6+7+x+5+3)

rEmember that

mean=2.71

substitute

2.71=(6+14+3x+20+15)/(21+x)

2.71(21+x)=55+3x

56.91+2.71x=55+3x

3x-2.71x=56.91-55

0.29x=1.91

the totals are

weighted total

0*5=0

1*9=9

2*7=14

3*4=12

4*3=12

5*2=10

mean=(0+9+14+12+12+10)/(5+9+7+4+3+2)

mean=(57)/(30)

table

number of cups frequency weighted total

0 5 0

1 9 9

2 7 14

3 4 12

4 3 12

5 2 10

1. The value of 34% of 850 is 289.

3. The amount that Kepley paid for the tool is $120.

From the information, we want to calculate 34% of 850. This will be calculated thus:

= 34% ×850

= 34/100 × 850

= 0.34 × 850

= 289

The amount paid for the tool will be:

= Price or tool - Discount

= $200 - (40% × $200)

= $200 - $80

= $120

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Answer:

9/41

Step-by-step explanation:

Draw a right triangle in quadrant 2 and label your opposite (40) and hypotenuse (41) sides then use the pythagorean theorem to find the missing side (the adjacent side)  which is equal to 9. Then since cosine is adjacent/hypotenuse and you get 9/41.

9514 1404 393

Answer:

  $16,974.50

Step-by-step explanation:

$14,382.50+24% of the amount over $84,200 is ...

  $14,382.50 +0.24×(95,000 -84,200) = $14,382.50 +2592.00 = $16,974.50

Mustafa owes $16974.50 in federal income tax.

_____

Additional comment

Each row of the tax table can be simplified by multiplying out the expression it describes. For the row applicable to this problem, that becomes ...

  14382.50 +0.24(amount -84200) = 14382.50 +0.24×amount -20208

  = 024×amount -5825.50

Answer:

1:2

Step-by-step explanation:

:)

Answer:

Rewrite in standard form to find the center  

( h , k )  and radius  r .

Center:  ( 0 , 2 )  Radius:  4

Step-by-step explanation:

Answer:

Rewrite in standard form to find the center  

( h , k )  and radius  r .

Center:  ( 0 , 2 )  Radius:  4

Lol hope this helps

Step-by-step explanation:

Answer:

1 inch

Step-by-step explanation:

The statement "S′H′ is parallel to S′Q′" is true.

To find the image of the square after reflection across the x-axis, we need to flip each point of the square over the x-axis. The coordinates of the reflected points will have the same x-coordinate, but the y-coordinate will have the opposite sign.

The coordinates of the original square are:

S(−3,0)

H(2,0)

A(2,5)

Q(−3,5)

The coordinates of the reflected square are:

S′(−3,0)

H′(2,0)

A′(2,−5)

Q′(−3,−5)

Now, we can find the slopes of the sides of the reflected square to determine which sides are parallel.

S′H′¯¯¯¯¯¯¯¯¯¯¯: The slope of S′H′¯¯¯¯¯¯¯¯¯¯¯ is 0, since both points have the same y-coordinate. Therefore, S′H′¯¯¯¯¯¯¯¯¯¯¯ is parallel to the x-axis.

S′Q′¯¯¯¯¯¯¯¯¯¯: The slope of S′Q′¯¯¯¯¯¯¯¯¯¯ is 0, since both points have the same y-coordinate. Therefore, S′Q′¯¯¯¯¯¯¯¯¯¯ is also parallel to the x-axis.

H′A′¯¯¯¯¯¯¯¯¯¯¯: The slope of H′A′¯¯¯¯¯¯¯¯¯¯¯ is undefined, since the two points have the same x-coordinate. Therefore, H′A′¯¯¯¯¯¯¯¯¯¯¯ is parallel to the y-axis.

H′S′¯¯¯¯¯¯¯¯¯¯¯: The slope of H′S′¯¯¯¯¯¯¯¯¯¯¯ is also undefined, since the two points have the same x-coordinate. Therefore, H′S′¯¯¯¯¯¯¯¯¯¯¯ is parallel to the y-axis.

A′Q′¯¯¯¯¯¯¯¯¯¯: The slope of A′Q′¯¯¯¯¯¯¯¯¯¯ is 0, since both points have the same y-coordinate. Therefore, A′Q′¯¯¯¯¯¯¯¯¯¯ is parallel to the x-axis.

Q′S′¯¯¯¯¯¯¯¯¯¯: The slope of Q′S′¯¯¯¯¯¯¯¯¯¯ is 0, since both points have the same y-coordinate. Therefore, Q′S′¯¯¯¯¯¯¯¯¯¯ is also parallel to the x-axis.

Based on these calculations, we can see that S′H′¯¯¯¯¯¯¯¯¯¯¯ is parallel to S′Q′¯¯¯¯¯¯¯¯¯¯ (both are parallel to the x-axis). Therefore, the statement "S′H′¯¯¯¯¯¯¯¯¯¯¯ is parallel to S′Q′¯¯¯¯¯¯¯¯¯¯" is true.

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Answer(s):

\(\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2 \\ y = 3cos\: 1\frac{1}{2}x - 2\)

Explanation:

\(\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{3}} \hookrightarrow \frac{-\frac{\pi}{2}}{1\frac{1}{2}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3\)

OR

\(\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{1\frac{1}{3}\pi} \hookrightarrow \frac{2}{1\frac{1}{2}}\pi \\ Amplitude \hookrightarrow 3\)

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of \(\displaystyle y = 3sin\: 1\frac{1}{2}x - 2,\) in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted \(\displaystyle \frac{pi}{3}\:unit\) to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACK \(\displaystyle \frac{\pi}{3}\:unit,\) which means the C-term will be negative, and perfourming your calculations, you will arrive at \(\displaystyle \boxed{-\frac{\pi}{3}} = \frac{-\frac{\pi}{2}}{1\frac{1}{2}}.\) So, the sine graph of the cosine graph, accourding to the horisontal shift, is \(\displaystyle y = 3sin\: (1\frac{1}{2}x + \frac{\pi}{2}) - 2.\) Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits \(\displaystyle [0, 1],\) from there to \(\displaystyle [1\frac{1}{3}\pi, 1],\) they are obviously \(\displaystyle 1\frac{1}{3}\pi\:unit\) apart, telling you that the period of the graph is \(\displaystyle 1\frac{1}{3}\pi.\) Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at \(\displaystyle y = -2,\) in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts horisontally, the midline will ALWAYS follow.

I am delighted to assist you at any time.

Answer:

From the given figure we can see that :---

MN||PO, MN=PO and MP=NO

Therefore, angle M=angle N (adjacent sides of the trapezoid)

\((8x - 16) = (6x + 20) \\ 2x = 36 \\ \boxed{x = 18}\)

angle M=angle N= (6×18)+20=108+20 =128°

angle O =(180°-128°)=52°

The volume of a rectangular box= 1056 ft³

The surface area of a rectangular box= 632 square ft

Volume is a measure of three-dimensional space that is occupied. It is frequently quantified numerically using SI-derived units or different imperial or US customary units (such as the gallon, quart, cubic inch). The definition of length (cubed) is related to volume. The volume of a container is commonly believed to be its capacity; that is, the amount of fluid (gas or liquid) that the container can hold, rather than the amount of space it occupies.

Volume was measured in ancient times using similar-shaped natural containers, and later, standardized vessels. Arithmetic formulas can quickly compute the volume of some simple three-dimensional shapes.

Given,

Length of the rectangular box= 11ft

Width of the rectangular box= 8 ft

Height of the rectangular box= 12 ft

Volume= Length× Width× Height

Volume= 11×8×12

=1056 ft³

Therefore, volume= 1056ft³

Surface area of a rectangular box is,

1 and 2 surfaces, 11 × 8 ===>

Surface area = 2× (11× 8) =  176 square ft

1 and 3 surfaces 11 × 12 ===>

Surface area = 2× (11×12) = 264 square inches

3• 2 surfaces 12 × 8 ===>

Surface area = 2× ( 12 × 8) = 192 square inches

Adding all the surface areas

176 +264 +192= 632  square ft.

The surface area of a rectangular box= 632 square ft

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The price of one adult ticket is $9 and the price of child ticket is $8

First day of ticket sales the school sold 4 adult tickets and 9 child tickets for a total of $108

Consider the price of adult ticket as x and child ticket as y

Then the equation will be

4x+9y = 108

Similarly the school took in $114 on the second day by selling 10 adult tickets and 3 child tickets

10x+3y = 114

Here we have to use the elimination method

Multiply the first equation by 10 and second equation by 4

40x+90y = 1080

40x+12y = 456

Subtract the equation 2 from equation 1

90y-12y = 1080-456

78y = 624

y = 624/78

y = $8

Substitute the value of y in any equation

10x+3y =114

10x+3×8 =114

10x +24 =114

10x = 90

x = 90/10

x = $9

Hence, the price of one adult ticket is $9 and the price of child ticket is $8

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6,900 times is the answer,also can i get brainliest

When the slope of two lines are multiplicative and additive inverses of each other, their products give -1.

They are perpendicular

We will draw a schematic to illustrate this point.

From the schematic above, it can be clearly seen that line A has a positive gradient and B is a negative gradient.

Their gradients are additive and multiplicative inverses of each other. They are perpendicular.

Answer:

Ok to find the surface area of this cylinder first we need the circumference to find this we do C=πd

C=3.14*18

C=56.52

now we have to multiple this by the height of two

113.04

now we have to find the area of the bottom to do this we do A=πR^2

A=3.14*81

A=254.34

multiple this by two for the two sides we get

508.68

now we add this to 113.04 we get

621.72

since I used 3.14 instead of more digits of pie we can round this up so the answer is C.

Your Welcome

BIFFY OUT!!!

Answer:

A) All whole numbers from 0 to 10

Step-by-step explanation:

The domain cannot exceed 10 because they do not have enough time to build more than 10 birdhouses. This rules our all nonnegative real numbers and all real numbers.

Integers include negative numbers as well, but it isn't possible to make -1 birdhouses, so this choice is wrong.

Therefore, the answer is all whole numbers from 0 to 10

hope this helps! <3

Answer:

257.14 calories (about 260)

Step-by-step explanation:

To solve this problem, we can use proportions.

If a 28 g serving of almonds has 160 calories, then:

28 g / 160 calories = 45 g / x calories

where x is the number of calories in a 45 g serving of almonds.

We can cross-multiply and solve for x:

28 g * x = 160 calories * 45 g

x = (160 calories * 45 g) / 28 g

x = 257.14 calories

Therefore, a 45 g serving of almonds has 257.14 calories (rounded to two decimal places).

The coefficient of the second term, 6x⁴, is 6.

The terms of the polynomial are:

-4y⁵, 6x⁴, 9w³, -4w, -1

The coefficient of the second term, which is 6x⁴, we look at the number in front of the variable term.

The coefficient is 6.

Therefore, the list of terms is:

-4y⁵, 6x⁴, 9w³, -4w, -1

Each term represents a separate component of the polynomial, where the variable is raised to a certain power and multiplied by its coefficient.

The coefficients indicate the scalar value by which each term is multiplied.

The polynomial's terms are -4y5, 6x4, 9w3, -4w, and -1.

Looking at the number in front of the variable term, we can determine the second term's coefficient, which is 6x4.

There is a 6 coefficient.

As a result, the terms are as follows: -4y5, 6x4, 9w3, -4w, and -1.

Each term represents a different part of the polynomial, where the variable is multiplied by its coefficient and raised to a given power.

The scalar value by which each phrase is multiplied is shown by the coefficients.

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Answer:

Zero(s) of multiplicity one: 11,-9

Zero(s) of multiplicity two: None

Zero(s) of multiplicity three: 5

Step-by-step explanation:

Suppose that we have a polynomial function in the following format:

\(f(x) = a*(x - x_{0})^{m_{0}}*(x - x_{1})^{m^{1}}*...*(x - x_{n})^{m^{n}}\)

The zeros are \(x_{0}, x_{1}, ..., x_{n}\).

The multiplicites are \(m_{0}, m_{1},..., m_{n}\)

In this question:

f(x) = 4(x -11) (x + 9) (x - 5)^3

So

11 is a zero of multiplicity 1

-9 is a zero of multiplicity 1

5 is a zero of multiplicity 3.

So the answer is:

Zero(s) of multiplicity one: 11,-9

Zero(s) of multiplicity two: None

Zero(s) of multiplicity three: 5

The number of students who just passed and didn't get any division is  195.

We can start by finding the number of students who got first or second division:

Next, we can find the total number of students who got a division:

Total number of students who got a division = Number of students who got first division + Number of students who got second division

= 125 + 175 = 300

Now, we can find the number of students who failed:

Number of students who failed = 5

Finally, we can subtract the number of students who got a division and the number of students who failed from the total number of students to find the number of students who just passed and didn't get any division:

Number of students who just passed and didn't get any division = Total number of students - Number of students who got a division - Number of students who failed

= 500 - 300 - 5

= 195

Therefore, the number of students who just passed and didn't get any division is 195.

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Answer:

-288

Step-by-step explanation: I took the following steps to find the answer:

(4 + 32)(15 – 23)

\             /

 (36)(15 – 23)

           \          /

 (36) (- 8)

   \        /

    -288

C. The area of a rectangle is the product of its length and its width, so factoring the expression for the area will give the dimensions of the rectangle. The expressions for the dimensions of the rectangle are to be determined by factoring in the given area expression.

What is the area of the rectangle?

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

The area of a rectangle is given by the formula A = lw, where A is the area, l is the length, and w is the width of the rectangle.

To find possible dimensions of a rectangle with a given area, we can use factoring.

For example, if the area is 24, we can factor it as 24 = 2 x 2 x 2 x 3 or 24 = 4 x 6.

This means that a rectangle with an area of 24 could have dimensions of length 2 and width 12, length 4 and width 6, length 6 and width 4, or length 12 and width 2.

In this case, the question does not specify the value of the area, so we cannot find the dimensions of the rectangle.

we can still use factoring to find the possible dimensions of a rectangle with a given area, as shown in the example above.

Hence, The correct answer is:

C. The area of a rectangle is the product of its length and its width, so factoring the expression for the area will give the dimensions of the rectangle. The expressions for the dimensions of the rectangle are to be determined by factoring in the given area expression.

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The required graph of the line y = x - 2 is shown. None of the options are correct.

The slope of the line is a tangent angle made by line with horizontal. i.e. m  = tanx where x in degrees.

Here,
The given line is y = x - 2
comparing with the standard equation of the line
y = mx + c
From the comparison,
Slope, m = 1 and y-intercept c = -2
And the graph of the line is shown,

Thus, the required graph of the line y = x - 2 is shown.

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The solution is : the percentage of cars that are driving less than 45 mi/hr is 2.3%

Here, we have,

Since the speeds of cars are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = speeds of cars

µ = mean speed

σ = standard deviation

From the information given,

µ = 55 mi/hr

σ = 5 mi/hr

The probability that a car is driving less than 45 mi/hr is expressed as

P(x < 45)

For x = 45

z = (45 - 55)/5 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.023

Therefore, the percentage of cars that are driving less than 45 mi/hr is

0.023 × 100 = 2.3%

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