A car travels from City A to City B to the north. It takes 4 hours, and the road mileage is 200 miles. The map shows that
the cities are only 80 miles apart (straight-line distance).

Answer:

2m head start or else you done for

Explanation:

you cant even out run a bear they run at 35mph the fastest human is 25

Answer:

We can solve this problem using kinematic equations of motion, assuming that air resistance is negligible. We can break the initial velocity of the pumpkin into horizontal and vertical components:

v₀x = v₀ cosθ = 60 cos40° = 45.8 m/s

v₀y = v₀ sinθ = 60 sin40° = 38.4 m/s

Since there is no vertical acceleration after launch, we can use the following kinematic equation to find the time of flight:

Δy = v₀y t + 1/2 a t²

where Δy is the vertical displacement of the pumpkin, a is the acceleration due to gravity (-9.81 m/s²), and t is the time of flight. When the pumpkin lands on the ground, its vertical displacement is zero, so we can solve for t:

0 = v₀y t + 1/2 a t²

t = -2v₀y / a = -7.82 s

This negative value indicates that the pumpkin lands on the ground after 7.82 seconds, which makes physical sense. Now, we can use the horizontal velocity to find the horizontal distance traveled during the time of flight:

Δx = v₀x t = 45.8 m/s * 7.82 s = 358.2 m

Finally, we can find the total speed of the pumpkin at landing by using the Pythagorean theorem:

v² = v₀x² + v²y

v = sqrt[(v₀x)² + (v₀y)²] = sqrt[(45.8 m/s)² + (38.4 m/s)²] = 60.0 m/s (approximately)

Therefore, the answer is D) 60 m/s.

Explanation:

Answer:

I hope it helped you...please mark as brainliest.....thanks!!!!!!!

Explanation:

Inches of mercury is ideal for vacuum lifting with vacuum cups, as the amount of vacuum required is rarely high. Typical vacuum handling utilizes anything between 15″Hg and 25″Hg. Therefore, “Hg is suitable as a measurement of system performance in this type of operation

The column of mercury employed in a mercury barometer, the height of which (inches of mercury) is used as a measure of atmospheric pressure.

At some point, all water vapour that is found in a vacuum system came from the atmosphere. Consider that air at 25° C and 50% relative humidity contains 12 torrs of water vapour. ... Additionally, any surface will adsorb a certain number of monolayers of water molecules.

Credits:

Vacuum Measurement: A Basic Guide - Fluid Power Journal

Sources of Water Vapor in Vacuum Systems | Normandale ...

c. weight.

Explanation:

I had the exact same question

a change in gravitational force affects weight. The correct answer is: c. Weight

The gravitational force is given by the law of universal gravitation

         F = \(G \frac{M m}{r^2}\)

where F is the force, G the constant of universal attraction, M and m the mass of the two bodies, r the distance between the bodies

In the case that a body is lying on the surface of the planet, the distance is the radius of the planet, in this case the radius of the Earth

       r = R_e  

       F = \(G \frac{M m}{R_e^2}\)

For convenience we can define a new variable called acceleration of gravity (g)

       g = \(G \frac{M}{R_e^2}\)

we substitute

      F = g m

This amount is called body weight, so a change in gravitational force creates a change in weight, therefore the correct answer is: C Weight

In conclusion a change in gravitational force affects weight, therefore the correct answer is:  c. Weight

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The potential energy associated with bringing two electrons close together is much less than their typical kinetic energy as long as n_e * λ_D^3 ≫ 1, where n_e is the electron density and λ_D is the Debye length.

The potential energy between two charged particles can be calculated using the formula U = (e^2)/(4πε₀r), where e is the elementary charge, ε₀ is the vacuum permittivity, and r is the distance between the particles. In the case of two electrons in a plasma, their typical distance is of the order n_e^(-1/3), where n_e is the electron density.

Substituting this distance into the potential energy formula, we get U = (e^2)/(4πε₀n_e^(1/3)). Now, let's compare this potential energy with the typical kinetic energy of the electrons. The typical kinetic energy of an electron in a plasma is given by E_kin = (3/2)kT, where k is Boltzmann's constant and T is the temperature of the plasma.

To compare the potential energy with the kinetic energy, we can use the condition that U/E_kin ≪ 1. Substituting the expressions for U and E_kin, we have (e^2)/(4πε₀n_e^(1/3)) / ((3/2)kT) ≪ 1.

Simplifying the expression, we get e^2 / (6πε₀kTn_e^(1/3)) ≪ 1. Rearranging the equation, we have n_e^(1/3) ≪ (e^2)/(6πε₀kT).

Now, considering the condition n_eλ_D^3 ≫ 1, where λ_D is the Debye length, we can substitute λ_D = (ε₀kT/(n_ee^2))^0.5 into the inequality.

After substitution, we get (ε₀kT/(n_ee^2))^0.5 ≪ (e^2)/(6πε₀kT).

Simplifying further, we find ε₀^(1/2)kT^(1/2)n_e^(-1/2) ≪ e/(6π^(1/2)).

Since n_eλ_D^3 ≫ 1, it implies that n_e^(1/2) ≫ (ε₀kT/(n_ee^2))^0.5, which satisfies the inequality above.

Therefore, it can be concluded that the potential energy associated with bringing two electrons close together is much less than their typical kinetic energy, as long as n_eλ_D^3 ≫ 1.

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the mass of 15.9 moles of sulfuric acid (H2SO4) is approximately 1558.2 grams.

The mass of 15.9 moles of sulfuric acid (H2SO4) can be calculated using the molar mass of the compound. To find the molar mass, we need to sum the individual atomic masses of all the elements in the molecule:
1. Hydrogen (H): There are 2 hydrogen atoms in H2SO4, each with an atomic mass of approximately 1 g/mol. So, the total mass for hydrogen is 2 x 1 = 2 g/mol.
2. Sulfur (S): There is 1 sulfur atom in H2SO4 with an atomic mass of approximately 32 g/mol.
3. Oxygen (O): There are 4 oxygen atoms in H2SO4, each with an atomic mass of approximately 16 g/mol. So, the total mass for oxygen is 4 x 16 = 64 g/mol.
Now, add the masses of all elements to get the molar mass of H2SO4: 2 g/mol (H) + 32 g/mol (S) + 64 g/mol (O) = 98 g/mol.
Finally, multiply the molar mass by the given number of moles to find the mass of 15.9 moles of sulfuric acid:
Mass = (Moles) x (Molar Mass) = 15.9 moles x 98 g/mol = 1558.2 g.
Therefore, the mass of 15.9 moles of sulfuric acid (H2SO4) is approximately 1558.2 grams.

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More absorption of solar radiation occurs with a higher angle of the sun.

Option A is correct

Around 30% of the incoming radiation is reflected back to space and does not heat the surface, leaving the other 70% to be absorbed by the atmosphere and the Earth's surface. Because it is colder than the Sun, the Earth radiates energy at wavelengths that are far longer.

This radiation is the radiation that eventually makes it to the Earth's surface after repeated route changes, such as those caused by atmospheric gases. solar radiation reflection. The albedo effect is a phenomena wherein a portion of solar radiation is reflected by the earth's surface itself.

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Answer:

law of action and riactiond

Answer:

Explanation:

A)  The function of a switch is to shut the circuit down. There is a current flow of zero. Press the switch again and the circuit works.

Answer: D

B) a. This is a parallel circuit. It is the way all house wiring works.

B) b. Nothing happens. The other two bulbs continue on as before until someone presses the switch.

The velocity vector is r'(t) = (4, -3 sin t, 3 cos t), the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t), the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.

Space Curves: Arc lengthArc length formula is given by \(L = ∫a b |r'(t)|dt\)

, where r(t) is the vector function for the given curve.

Let's find the arc length of the given space curve:

r(t) = (2t, t^2 - 2, 5 - t^2) for 0 ≤ t ≤ 4.

The speed of r(t) is |r'(t)|.r'(t) = (2, 2t, -2t) and

||r'(t)|| = √(2^2 + (2t)^2 + (-2t)^2)

= 2√2t.So,

the arc length of the space curve is

L = ∫0 4 2√2t dt

= (4/3)√2 [t^(3/2)] from 0 to 4

= (4/3)√2 (4√2 - 0)= (16/3) * 2

= 32/3.

Therefore, the length of the given space curve with vector equation is 32/3. Vector Functions for the intersection of two surfaces

The equation for the given surface is \(F(x)=(2,x²-30).\)

Let's find the vector functions for the intersection of two surfaces.

To find the intersection, we equate the two given equations:2 = y = x².

We get y = x² = 2. So, x = ±√2.

The vector functions for the intersection of two surfaces are:

r1(t) = (t, 2, t^2 - 30)

for x = √2 and r2(t)

= (-t, 2, t^2 - 30)

for x = -√2.

Given TNB for a space curveLet's find the unit tangent vector to the space curve r(t) = (cos t, sin t, t).

The velocity vector is r'(t) = (-sin t, cos t, 1).

The speed of the curve is |r'(t)| = √(sin² t + cos² t + 1) = √2.

The unit tangent vector is T = r'(t) / |r'(t)| = (-sin t/√2, cos t/√2, 1/√2).

Now, let's find a unit normal vector to the space curve.The acceleration vector is r''(t) = (-cos t, -sin t, 0).

The magnitude of acceleration is |r''(t)| = 1.

The unit normal vector is N = r''(t) / |r''(t)| = (-cos t, -sin t, 0).The binormal vector is given by B = T × N.

Therefore, the unit tangent vector to the space curve r(t) = (cos t, sin t, t) is T = (-sin t/√2, cos t/√2, 1/√2),

the unit normal vector is N = (-cos t, -sin t, 0),

and the unit binormal vector is

B = (cos t/√2, -sin t/√2, 1/√2) × (-cos t, -sin t, 0)

= (sin t/√2, -cos t/√2, 1/√2).

Velocity, acceleration and curvature

Let's find the velocity vector, the acceleration vector, and the curvature of the space curve r(t) = (4t, 3 cos t, 3 sin t) for 0 ≤ t ≤ 27.

The velocity vector is r'(t) = (4, -3 sin t, 3 cos t).

The speed of the curve is |r'(t)| = √(16 + 9 sin² t + 9 cos² t) = 5.

The unit tangent vector is T = r'(t) / |r'(t)| = (4/5, -3 sin t/5, 3 cos t/5).

The acceleration vector is r''(t) = (0, -3 cos t, -3 sin t).

The magnitude of acceleration is |r''(t)| = 3.

The tangential component of acceleration is aT = T · r''(t) = 0.

The normal component of acceleration is aN = |r''(t)| · |N| = 3.

The unit normal vector is N = (-cos t, -sin t, 0).

The curvature is κ = |r''(t)| / |r'(t)|² = 3 / (25 + 9 sin² t + 9 cos² t)^(3/2) = 3 / (25 + 9)^(3/2) = 3 / 14^(3/2).

Therefore, the velocity vector is r'(t) = (4, -3 sin t, 3 cos t),

the acceleration vector is r''(t) = (0, -3 cos t, -3 sin t),

the curvature is κ = 3 / 14^(3/2), and the tangential and normal components of the acceleration are aT = 0 and aN = 3.

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If x(n) is passed through an ideal d/a (digital-to-analog) converter, the reconstructed signal ya(t) will be an analog signal that approximates the original discrete-time signal x(n). The d/a converter converts the discrete-time samples into a continuous-time signal.

To reconstruct the signal ya(t), the d/a converter needs to perform the following steps:

1. Sample and Hold: The d/a converter first samples the discrete-time signal x(n) at regular intervals. This means that it takes snapshots of the signal at specific points in time.

2. Quantization: The sampled values are then quantized, which means they are approximated to a limited set of values. The number of bits used for quantization determines the resolution of the reconstructed signal.

3. Digital-to-Analog Conversion: The quantized values are converted into corresponding analog voltage levels. This process involves reconstructing a continuous-time signal that closely resembles the original waveform.

The reconstructed signal ya(t) is a continuous-time approximation of the original signal x(n). It is important to note that the accuracy of the reconstructed signal depends on the sampling rate and the resolution of the d/a converter. A higher sampling rate and resolution generally result in a more accurate reconstruction.

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The actual frequency of the siren is approximately 568 Hz. The observed frequency is affected by the relative motion between the ambulance and the observer, resulting in a shift in the frequency known as the Doppler effect.

To calculate the actual frequency of the siren, we need to consider the Doppler effect formula:

\(f1 = f * (v + vo) / (v + vs)\)

Where:

f1 is the observed frequency

f is the actual frequency

v is the speed of sound

vo is the velocity of the observer (positive for approaching, negative for receding)

vs is the velocity of the source (positive for receding, negative for approaching)

In this case, the ambulance is approaching the observer, so vo is positive and vs is negative. Plugging in the given values:

525 = f * (341 + 0) / (341 + 31.5)

Solving for f, we find that f is approximately 568 Hz. Therefore, the actual frequency of the siren is approximately 568 Hz.

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Answer:

63º~64º

Explanation:

so imagine a graphic with a triangle. The distance between the zero and the horizontal (x) is 20 and the distance between 0 and vertical (y) is 60

20 = base

60 = height

hypotenuse = L

tg = cato/cata

tg = 60/20

tg = 2

I give up

The torque needed to keep the stick steady, ranked from largest to smallest, would be: highest when the suspended mass is at the far end of the stick, lower when the suspended mass is closer to the pivot point, and lowest when the suspended mass is at the pivot point itself.

To rank the torque needed to keep the stick steady from largest to smallest, we need to consider the factors that affect torque.

Torque is the rotational equivalent of force, and it depends on the distance between the pivot point (the end of the meter stick you are holding) and the point where the force is applied (the suspended mass), as well as the magnitude of the force.

In this scenario, the torque needed to keep the stick steady will be highest when the suspended mass is at the far end of the stick, i.e. as far away from the pivot point as possible.

This is because the greater the distance between the pivot point and the force, the more torque is required to counteract the force's rotational effect. Therefore, the torque needed to keep the stick steady will be highest when the suspended mass is at the end of the meter stick farthest away from the pivot point.

Conversely, the torque needed to keep the stick steady will be lowest when the suspended mass is at the pivot point itself, as there is no rotational effect to counteract in this scenario.

Therefore, the torque needed to keep the stick steady will be lowest when the suspended mass is at the end of the meter stick closest to the pivot point.

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The consequences of different speeds of light in different media include mirages, rainbows, and the brilliant colors of diamonds. Therefore, the correct option is D) all of the above.

When light travels through different media, its speed can change. This change in speed leads to various optical phenomena and consequences. Mirages occur due to the bending of light as it passes through air layers with different refractive indices, caused by temperature gradients. This bending creates the illusion of objects appearing in locations where they are not actually present, such as seeing water on a hot road. Rainbows are formed when sunlight is refracted, reflected, and dispersed by water droplets in the atmosphere. The different speeds of light in the droplets cause the light to separate into its constituent colors, resulting in the formation of a colorful circular arc.

The brilliant colors of diamonds and other gemstones are due to the phenomenon called dispersion. Different wavelengths of light have different speeds when passing through the gemstone, causing them to separate and produce a range of colors. Therefore, all of the given options (mirages, rainbows, and the brilliant colors of diamonds) are consequences of different speeds of light in different media.

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Answer:

Our mass is the amount of matter that we consist of. This mass does not change when we change planets. However, if we went from Earth to Mars, our weight would change because Mars has less gravity than Earth. Gravity is a force pulling matter together.

The dot product is 25, the angle is \(\theta = cos^{-1} \frac{25}{\sqrt{35} \times \sqrt{21}}\), the cross product is 1i + (-6)j + (-7)k, and the area of the parallelogram spanned by vectors A and B is \(\sqrt{86}\).

Given,

A = 5i + 3j + k

B = 4i + j + 2k

i. Dot Product (A · B):

The dot product of two vectors A and B is given by the sum of the products of their corresponding components.

\(A.B = (A_x \times B_x) + (A_y \times B_y) + (A_z \times B_z)\\A.B = (5 \times 4) + (3 \times 1) + (1 \times 2) \\= 20 + 3 + 2 \\= 25\)

ii. Angle between vectors A and B:

The angle between two vectors A and B can be calculated using the dot product and the magnitudes of the vectors.

\(cos\theta = (A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} ((A.B) / (|A| \times |B|))\\A = \sqrt{(5^2 + 3^2 + 1^2)} =\\ \sqrt{35}\\B = \sqrt{(4^2 + 1^2 + 2^2)} \\= \sqrt{21}cos\theta = \frac{(A.B) / (|A| \times |B|)\\\theta = \frac{1}{cos} \frac{25}{\sqrt{35} \times \sqrt{21}}}\)

iv. Cross Product (A × B):

The cross product of two vectors A and B is a vector that is perpendicular to both A and B and its magnitude is equal to the area of the parallelogram spanned by A and B.

\(A\times B = (A_y \timesB_z - A_z \timesB_y)i + (A_z \timesB_x - A_x \timesB_z)j + (A_x \times B_y - A_y \times B_x)k\\A\times B = ((3 \times 2) - (1 \times 1))i + ((1 \times 4) - (5 \times 2))j + ((5 \times 1) - (3 \times 4))k\\= 1i + (-6)j + (-7)k\)

Area of the parallelogram spanned by vectors A and B:

The magnitude of the cross product A × B gives us the area of the parallelogram spanned by A and B.

Area = |A × B|

Area of the parallelogram spanned by vectors A and B:

Area = |A × B| =

\(\sqrt{(1^2 + (-6)^2 + (-7)^2}\\\sqrt{1+36+49\\\\\sqrt{86}\)

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When two tuning forks are sounded together, they create a beat frequency which is the difference between their frequencies. In this case, the beat frequency is given as 4.00 Hz. The frequency of the other tuning fork is 254 Hz.

Let's assume the frequency of the other tuning fork is x Hz. Then we can write:

|258 Hz - x Hz| = 4.00 Hz

Taking the absolute value ensures that we get a positive answer for x.

Solving for x, we get:

258 Hz - x Hz = 4.00 Hz

x Hz = 258 Hz - 4.00 Hz

x Hz = 254 Hz

Therefore, the frequency of the other tuning fork is 254 Hz.

In summary, when two tuning forks are sounded together, the beat frequency is the difference between their frequencies. By setting up an equation with the known beat frequency and one of the frequencies, we can solve for the unknown frequency.

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The five initiatives that the South African government is implementing to combat poverty are the Reconstruction and Development Programme (RDP), Growth Employment and Redistribution (GEAR), The Accelerated and Shared Growth Initiative of South Africa (ASGISA), The National Development Plan (NDP), and the Social Assistance System (SAS).

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To calculate the power of the crane, we need to use the formula:

Power = Force × Velocity

First, let's find the force acting on the crane using Newton's second law of motion:

Force = Mass × Acceleration

Given:

Mass of the crane (m) = 800 kg

Acceleration (a) = 1 m/s²

Force = 800 kg × 1 m/s² = 800 N

Next, we need to calculate the power at a velocity of 1.5 m/s. Power is the rate at which work is done, and work is equal to the change in kinetic energy. So, we'll use the formula:

Power = Work / Time

Since the crane starts from rest (initial velocity = 0) and reaches a final velocity of 1.5 m/s, we can calculate the work done on the crane:

Work = Change in kinetic energy

= (1/2) × Mass × (Final Velocity² - Initial Velocity²)

Given:

Initial Velocity (v1) = 0 m/s

Final Velocity (v2) = 1.5 m/s

Work = (1/2) × 800 kg × (1.5 m/s)² = 900 J

Now, let's calculate the power:

Power = Work / Time

Since we don't have the time, let's assume it took 1 second to reach the final velocity.

Power = 900 J / 1 s = 900 W

Therefore, the power of the crane when it reaches a speed of 1.5 m/s is 900 watts (W).

Natural gas was the largest source about 38% of U.S. electricity generation in 2021. Natural gas is used in steam turbines and gas turbines to generate electricity.

The kinetic energy of the truck is approximately 1,964,180 Joules. The kinetic energy of the car is approximately 250,003 Joules.

To calculate the kinetic energy of each vehicle, use the formula:

Kinetic Energy (KE) = 1/2 × mass × velocity²

Given the mass and velocity of each vehicle, plug in the values and calculate the kinetic energy.

For the truck:

Mass = 6,000 kg

Velocity = 92 km/h

= 92,000 m/3600 s

≈ 25.56 m/s

Using the formula:

KE = 1/2 × 6,000 kg × (25.56 m/s)²

Calculating the result:

KE = 1/2 × 6,000 kg × 655.3936 m²/s²

KE ≈ 1,964,180 Joules

Therefore, the kinetic energy of the truck is approximately 1,964,180 Joules.

For the car:

Mass = 1,200 kg

Velocity = 100 km/h

= 100,000 m/3600 s

≈ 27.78 m/s

Using the formula:

KE = 1/2 × 1,200 kg × (27.78 m/s)²

Calculating the result:

KE = 1/2 × 1,200 kg × 771.6884 m²/s²

KE ≈ 250,003 Joules

Therefore, the kinetic energy of the car is approximately 250,003 Joules.

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Answer:

dang, you are really trying to get everyone to do your heavy lifting lol.

I'll do coal. and maybe a little more.

Explanation:

Coal What is it?

Coal is a combustible black or brownish-black sedimentary rock, formed as rock strata called coal seams. Coal is mostly carbon with variable amounts of other elements; chiefly hydrogen, sulfur, oxygen, and nitrogen.

Coal How we obtain it:

Coal can be extracted from the earth either by surface mining or underground mining. Once coal has been extracted, it can be used directly (for heating and industrial processes) or to fuel power plants for electricity. If coal is less than 61 meters (200 feet) underground, it can be extracted through surface mining.

Coal Pros:

Coal is plentiful in many places and it is easy to access through mining, so people rely on it to produce energy. Coal is easy to store. Once it is mined it can be safely stored with no hazard of fire or explosion like there is with gas or oil. It is relatively easy and inexpensive to convert coal into energy.

Coal Cons:

Coal is nonrenewable.  Coal contains the most CO2 per BTU, the largest contributor to global warming.  Severe environmental, social, and health, and safety impacts of coal mining.  The devastation of the environment around coal mines is heavy.  High cost of transporting coal to centralized power plants. Coal is really dirty and not good.

__________________________________________________________

Solar What is it?

Solar energy is radiant light and heat from the Sun that is harnessed using a range of ever-evolving technologies such as solar heating, photovoltaics, solar thermal energy, solar architecture, molten salt power plants and artificial photosynthesis.

Solar How we obtain it:

Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.

Solar Pros:

It's clean energy. Solar power is pollution-free and causes no greenhouse gases to be emitted after installation.  It has reduced dependence on foreign oil and fossil fuels.  It is renewable clean power that is available every day of the year, even cloudy days produce some power.  It gives a return on investment unlike paying for utility bills.

Solar Cons:

Solar doesn't work at night. Solar panels are not attractive. You can't install a home solar system yourself. My roof isn't right for solar. Solar hurts the environment. Not all solar panels are high quality.

Answer:

A) The ball will roll forever in a straight path.

Answer:

(a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 4 sec

(a). We need to calculate the rocket's velocity

Using equation of motion

\(v=u+at\)

Put the value into the formula

\(v=0+29.4\times4\)

\(v=117.6\ m/s\)

We need to calculate the maximum height at the moment fuel ends

For the value of x₁

Using equation of motion

\(x_{1}=ut+\dfrac{1}{2}at^2\)

Put the value into the formula

\(x_{1}=0+\dfrac{1}{2}\times29.4\times4^2\)

\(x_{1}=235.2\ m\)

We need to calculate the value of x₂

Using equation of motion

\(v^2=u^2-2gx_{2}\)

Put the value into the formula

\(0=u^2-2gx_{2}\)

\(x_{2}=\dfrac{u^2}{2g}\)

Put the value in to the formula

\(x_{2}=\dfrac{117.6^2}{2\times9.8}\)

\(x_{2}=705.6\ m\)

(b). We need to calculate the maximum this rocket can reach

Using formula for height

\(H=x_{1}+x_{2}\)

Put the value into the formula

\(H=235.2+705.6\)

\(H=940.8\ m\)

(c). We need to calculate the velocity the instant before the rocket crashes on the ground

Using equation of motion

\(v^2=u^2+2gh\)

Put the value into the formula

\(v=\sqrt{2\times9.8\times940.8}\)

\(v=135.7\ m/s\)

Hence, (a). The rocket's velocity is 117.6 m/s.

(b). The rocket can reach at maximum height is 940.8 m.

(c). The velocity the instant before the rocket crashes on the ground is 135.7 m/s.