82. A company spends x hundred dollars on an advertising
campaign. The amount of money in sales S(x) (in
$1000) for the 4-month period after the advertising
campaign can be modeled by
S(x) = 5 + 7 In(x + 1)
If the sales total $19,100, how much was spent on
advertising?
Answers
The company spends $649 on advertising
The sales function after advertising is given as:
\(S(x) = 5 + 7\ln(x + 1)\)
When the total sales is $19,100, we have S(x) = 19100
So, the sales function becomes
\(5 + 7\ln(x + 1) = 19.1\)
Subtract 5 from both sides
\(7\ln(x + 1) = 14.1\)
Divide both sides by 7
\(\ln(x + 1) = 2.014\)
Take exponents of both sides
\(x + 1 = e^{2.014\)
\(x + 1 = 7.49\)
Subtract 1 from both sides
\(x= 6.49\)
Hence, the company spends $649 on advertising
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Related Questions
F(x)= -3x2^-3x, f(-2)
Answers
Answer:
-6
Step-by-step explanation:
We know that the equation is f(x)=-3x^2-3x.
This means when we plug -2 in, the equation will be f(-2)=-3(-2)^2-3(-2). Simplify this to get -3(4)+6. Simplify this to get -12+6 which is equal to -6. Therefore, f(-2)=-6
If this helps please mark as brainliest
The diagram below shows two wires carrying anti-parallel currents. Each wire carries 30 amps of current. The centers of the wires are 5 mm apart. Point P is 15 cm from the midpoint between the wires. Find the net magnetic field at point P, using the coordinate system shown and expressing your answer in 1, 1, k notation. 5mm mm = 10-³ cm=102m I₂ (out) P •midpan't betwem wires 1 X- I, (in)! (30A) 15cm →X Z(out)
Answers
The net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
We can use the Biot-Savart Law to calculate the magnetic field at point P due to each wire, and then add the two contributions vectorially to obtain the net magnetic field.
The magnetic field due to a current-carrying wire can be calculated using the formula:
d = μ₀/4π * Id × /r³
where d is the magnetic field contribution at a point due to a small element of current Id, is the vector pointing from the element to the point, r is the distance between them, and μ₀ is the permeability of free space.
Let's first consider the wire carrying current I₁ (in the positive X direction). The contribution to the magnetic field at point P from an element d located at position y on the wire is:
d₁ = μ₀/4π * I₁ d × ₁ /r₁³
where ₁ is the vector pointing from the element to P, and r₁ is the distance between them. Since the wire is infinitely long, we can assume that it extends from -∞ to +∞ along the X axis, and integrate over its length to find the total magnetic field at P:
B₁ = ∫d₁ = μ₀/4π * I₁ ∫d × ₁ /r₁³
For the given setup, the integrals simplify as follows:
∫d = I₁ L, where L is the length of the wire per unit length
d × ₁ = L dy (y - 1/2 L) j - x i
r₁ = sqrt(x² + (y - 1/2 L)²)
Substituting these expressions into the integral and evaluating it, we get:
B₁ = μ₀/4π * I₁ L ∫[-∞,+∞] (L dy (y - 1/2 L) j - x i) / (x² + (y - 1/2 L)²)^(3/2)
This integral can be evaluated using the substitution u = y - 1/2 L, which transforms it into a standard form that can be looked up in a table or computed using software. The result is:
B₁ = μ₀ I₁ / 4πd * (j - 2z k)
where d = 5 mm = 5×10^-3 m is the distance between the wires, and z is the coordinate along the Z axis.
Similarly, for the wire carrying current I₂ (in the negative X direction), we have:
B₂ = μ₀ I₂ / 4πd * (-j - 2z k)
Therefore, the net magnetic field at point P is:
B = B₁ + B₂ = μ₀ / 4πd * (I₁ - I₂) j + 2μ₀I₁ / 4πd * z k
Substituting the given values, we obtain:
B = (2×10^-7 Tm/A) / (4π×5×10^-3 m) * (30A - (-30A)) j + 2(2×10^-7 Tm/A) × 30A / (4π×5×10^-3 m) * (15×10^-2 m) k
which simplifies to:
B = (6e-5 j + 0.57 k) T
Therefore, the net magnetic field at point P is (6e-5 j + 0.57 k) T in 1, 1, k notation.
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ello mate, i need help with this here question can you help a girl out and if ya do ill give you brainlist :D
Answers
Answer:
B
Step-by-step explanation:
Add the value of the dots
0 + 3/8 + 3/8 + 4/8 + 5/8 + 7/8 = 22/8 = 2 6/8
Solve the equation below for c. Fill in the blanks to give the steps used in this process.
P = 2c + 5
need answer ASAP
Answers
The equation when solved for the variable 'c' is c = P-5/ 2
What is subject of formula?A subject of formula can be defined as the variable that is written or denoted in terms of other variables in an equation or expression.
It is known as the variables being worked out in an equation. It is allowed to stand on its own over the equality sign.
Given the equation;
P = 2c + 5
To make the variable 'c' the subject of formula, we take the following steps:
Take 5 over the equality sign
P - 5 = 2c
Now, divide both sides by the coefficient of 'c' which is 2
2c/ 2 = P - 5/ c
Find the quotient
c = P-5/ 2
Thus, the equation when solved for the variable 'c' is c = P-5/ 2
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Factor the expression: -30x - 15
Answers
Answer:
Factored expression: -15 (2x + 1)
Help me out and show me the full solution on how you solved it, please!
Answers
The value of each trigonometric identity is:
3/2
5/6
14/3
We have,
We will use the trigonometric formula and substitute the given values.
So,
Cosec θ
This can be written as,
= 1/ sin θ
= 1/(2/3)
= 3/2
And,
Sin θ
This can be written as,
= 1/ cosec θ
= 1/(6/5)
= 5/6
And,
Sec θ
This can be written as,
= 1/cosθ
= 1/(3/14)
= 14/3
Thus,
The value of each trigonometric identity is:
3/2
5/6
14/3
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Use the distributive property to find (y+6)(y+4)
Answers
You must multiply the second parentheses by each term in the first parentheses.
y(y + 4) + 6(y + 4)
y^2 + 4y + 6y + 24
Combine like terms.
y^2 + 10y + 24 is your answer.
Question Answer O A True O B False Question Answer O A True O B False Question Answer OA O B True False Using logarithmic differentiation we obtain that the derivative of the function y = x2x² satisfies the equation y = 4x log x + 2x. y Using logarithmic differentiation we obtain that the derivative of the function (1+x²)2 (1 + sin x)² y= 1-x² satisfies the equation 4x 2cos x 2x -= + y 1 + x² 1 + sin x 1-x² Given two complex numbers z=3-1 and w=3+ the product z2w equals 30-10%. Y'
Answers
In the first question, the statement "Using logarithmic differentiation we obtain that the derivative of the function y = x² satisfies the equation y = 4x log x + 2x" is true.
In the first question, using logarithmic differentiation on the function y = x², we differentiate both sides, apply the product rule and logarithmic differentiation, and simplify to obtain the equation y = 4x log x + 2x, which is correct.
In the second question, the statement is false. When using logarithmic differentiation on the function y = (1+x²)²(1 + sin x)²/(1-x²), the derivative is calculated correctly, but the equation given is incorrect. The correct equation after logarithmic differentiation should be y' = (4x/(1 + x²)(1 + sin x))(1-x²) - (2x(1+x²)²(1 + sin x)²)/(1-x²)².
In the third question, the product z²w is calculated correctly as 30-10%.
It is important to accurately apply logarithmic differentiation and perform the necessary calculations to determine the derivatives and products correctly.
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t (hours) 0 1 5 8 10 G (t) (thousands of gallons) 22 18.5 19.5 22 24 A gasoline storage tank is filled by a pipeline from a refinery. At the same time, gasoline flows from the tank into trucks that will make deliveries to gasoline stations. The amount of gasoline in the storage tank at time t is given by the twice-differentiable function G, where t is measured in hours and 0≤t≤10. Values of G(t), in thousands of gallons, at selected times t are given in the table above. It is known that G′′(t)>0 for 5≤t<10. (a) Use the data in the table to estimate the rate of change of the amount of gasoline in the storage tank at time t=3 hours. Show the computations that lead to your answer. Indicate units of measure. (b) For 0 (c) It is known that G′(5)=0.5. Use the locally linear approximation for G at time t=5 to approximate the amount of gasoline in the storage tank at time t=7. Is this approximation an overestimate or an underestimate for the actual amount of gasoline in the storage tank at time t=7 ? Give a reason for your answer. (d) The rate at which gasoline flows out of the storage tank into trucks at time t can be modeled by the function R defined by R(t)=100t/(t^2 +4), where t is measured in hours, and R(t) is measured in thousands of gallons. Based on the model, at what time t, for 0≤t≤10, is the rate at which gasoline flows out of the storage tank an absolute maximum? Justify your answer.
Answers
The estimated rate of change of the amount of gasoline at t = 3 hours is 1/4 thousand gallons per hour, or 250 gallons per hour. the maximum amount of gasoline in the storage tank will occur at t = 10 hours. the tangent line lies below the graph of G(t) near t = 5, indicating a lower value.
(a) To estimate the rate of change of the amount of gasoline in the storage tank at t = 3 hours, we can use the average rate of change between the points (t₁, G(t₁)) and (t₂, G(t₂)). In this case, we'll use the points (1, 18.5) and (5, 19.5) from the table.
The average rate of change is given by (G(t₂) - G(t₁))/(t₂ - t₁). Plugging in the values, we have (19.5 - 18.5)/(5 - 1), which simplifies to 1/4.
Therefore, the estimated rate of change of the amount of gasoline at t = 3 hours is 1/4 thousand gallons per hour, or 250 gallons per hour.
(b) To find the time t when the amount of gasoline in the storage tank is changing most rapidly, we can look for the maximum or minimum of the function G(t). Since G(t) represents the amount of gasoline in the storage tank, we're interested in finding the maximum.
From the given table, we observe that the values of G(t) are increasing as t increases. Therefore, the maximum amount of gasoline in the storage tank will occur at t = 10 hours.
(c) The locally linear approximation for G at t = 5 can be found using the tangent line to the graph of G at t = 5. Since G'(5) = 0.5, we have the slope of the tangent line.
Using the point-slope form of a line, we can write the equation of the tangent line as follows:
G(t) = G(5) + G'(5) * (t - 5)
Plugging in the values, we have:
G(t) = 19.5 + 0.5 * (t - 5)
To approximate the amount of gasoline at t = 7, we substitute t = 7 into the equation:
G(7) ≈ 19.5 + 0.5 * (7 - 5)
G(7) ≈ 19.5 + 1
G(7) ≈ 20.5 thousand gallons
This approximation is an underestimate for the actual amount of gasoline in the storage tank at t = 7 because the tangent line lies below the graph of G(t) near t = 5, indicating a lower value.
(d) To find the time t when the rate at which gasoline flows out of the storage tank is an absolute maximum, we need to analyze the function R(t) = 100t/(t² + 4) over the interval 0 ≤ t ≤ 10.
First, we find the critical points by setting the derivative of R(t) equal to zero:
R'(t) = 0
100(t² + 4) - 100t(2t) = 0
100t² + 400 - 200t² = 0
-100t² + 400 = 0
100t² = 400
t² = 4
t = ±2
Since the interval is restricted to 0 ≤ t ≤ 10, we disregard the negative solution and consider t = 2.
Next, we evaluate the second derivative of R(t):
R''(t) = (200t - 400)/(t² + 4)²
For t = 2, R''(2) = (400 - 400)/(2² + 4)² = 0.
Since the second derivative is zero and the function is continuous within the interval, the absolute maximum or minimum of R(t) occurs at the endpoints or critical points. Therefore, the absolute maximum occurs at t = 2 hours.
By justifying our answer through the second derivative test, we can conclude that the rate at which gasoline flows out of the storage tank is an absolute maximum at t = 2 hours.
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Assume that hybridization experiments are conducted with peas having the property that for offspring, there is a 0.75 probability that a pea has green pods. Assume that the offspring peas are randomly selected in groups of 20.a. Find the standard deviation for the numbers of peas with green pods in the groups of 20
Answers
Given
Probability that a pea has green pods = 0.75
Sample of the offspring peas , n = 20
Find
Standard deviation for the numbers of peas with green pods in the groups of 20
Explanation
as we have given ,
Probability that a pea has green pods , p = 0.75
Probability that a pea do not have green pods , q = 1 - 0.75 = 0.25
n = 20
in binomial distribution ,
standard deviation is given by
\(\sqrt{npq}\)so,
\(\begin{gathered} S.D=\sqrt{20\times0.75\times0.25} \\ S.D=\sqrt{3.75} \\ S.D=1.93649167\approx1.94 \end{gathered}\)Final Answer
Hence , the standard deviation for the number of peas with green pods in the group of 20 is 1.94
in a right triangle the sine of an angle and the cosine of the same angle is what is the tangent of the angle
Answers
The tangent of the angle in a right triangle is:
Tangent = Sine / Cosine
In a right triangle, the sine of an angle is equal to the length of the side opposite the angle divided by the length of the hypotenuse. The cosine of the same angle is equal to the length of the side adjacent to the angle divided by the length of the hypotenuse.
To find the tangent of the angle, you can use the formula:
Tangent = Opposite / Adjacent
Since the opposite side is the side opposite the angle and the adjacent side is the side adjacent to the angle, the tangent of the angle can be calculated by dividing the sine of the angle by the cosine of the angle.
Therefore, the tangent of the angle in a right triangle is:
Tangent = Sine / Cosine
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The area, A, of a square with a side of length x is given by A = x^2? Use this relationship to verify that doubling the length of the side of a square floor increases the area of
the floor by a factor of 2^2
Answers
Answer:
Hi
Step-by-step explanation:
what does e mean in math
Answers
In mathematics, the letter e is often used to represent the base of the natural logarithm, or Euler's number.
This number is an irrational number and its value is approximately 2.718281828459045. It is used in many mathematical formulas and equations, most notably in exponential growth and decay equations.In mathematics, the letter e is often used to represent the base of the natural logarithm, or Euler's number. For example, an exponential growth equation can be expressed as y=ae^(bt), where y is the dependent variable, a is the initial value, b is the growth rate, and t is the time. The calculation for this equation is y = ae^(bt), where a is the initial value, b is the growth rate, and t is the time. For example, if the initial value is 5, the growth rate is 2, and the time is 3, then the calculation would be y = 5e^(2*3) = 5e^6 = 403.429. This equation can be used to calculate the amount of growth or decay over time.
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A red velvet rope hangs between two stanchions and forms a curve that can be modeled by a parabola. In the illustration shown, the unit of measurement for both axes is feet, and the vertex of the curve is point C. Find a quadratic function that models the rope, and state the function's domain.
Answers
Complete question
The complete question is shown on the first uploaded image
Answer:
The function is \(y = \frac{1}{18} (x -4 )^2 + 3.5\)
The domain is [1, 7]
Step-by-step explanation:
Generally from the Graph we can see that
For the y-coordinate the point of symmetry is \(y = g = 4\)
For the x-coordinate the point of symmetry is x = 4
The general form of quadratic equation representing this type of curve is
\(y = b(x-g)^2 + u\)
Now considering the coordinate (4, 3.5) along the axis of symmetry we have that
\(3.5 = b(4-4)^2 + u\)
=> \(u = 3.5\)
Now considering point B having the coordinates (7,4)
\(4 = b(7-4)^2 + 3.5\)
\(4 = 9b + 3.5\)
\(b = \frac{1}{18}\)
Generally the function that define the given graph is
\(y = \frac{1}{18} (x -4 )^2 + 3.5\)
From the graph the first element for x is 1 (i.e [1 . 4] )and the last element for x is 7 (i.e [7,4])
So the domain of the function is [1, 7]
How many square inches of cloth are cut from the square (n = 3.14) if it’s 38inches
Answers
The number of square inches of cloth cut from the square will be 1,017.36 square inches. Then the correct option is A.
What is the area of the circle?It is the close curve of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.
Let r be the radius of the circle. Then the area of the circle will be
A = πr² square units
The radius is given as,
r = 36 / 2
r = 18 inches
The area of the circle is given as,
A = π x (18)²
A = 3.14 x 324
A = 1,017.36 square inches
The number of square inches of cloth cut from the square will be 1,017.36 square inches. Then the correct option is A.
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The complete question is given below.
A circle is cut from a square piece of cloth, as shown:
A square, one side labeled as 36 inches, has a circle inside it. The circle touches all the sides of the square. The portion of the square outside the circle is shaded.
How many square inches of cloth is cut from the square?
(π = 3.14)
1,017.36 in2
1,489.24 in2
1,182.96 in2
1,276.00 in2
Can someone help me with this pls I don’t understand??
Slope = 2/7; y intercept = 0 and they want me to write it in slope intercept form
Answers
m is the slope and b is the variable for the y-intercept. All you have to do is to substitute the numbers to the corresponding variables.
So the answer would be: y = 2/7x + 0 or y = 2/7x
Hello again! To do this you must remember that slope intercept form is y=mx+b. m equals slope while b equals y intercept. Our slope is 2/7 while our y intercept is zero. Now, plug them in and you should get the equation y=2/7x+0. We have a zero at the end so we remove the + and zero and get y=2/7x.
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Solve:
3 (4x – 3) + 8 = -1 + 12.c
Please help me solve this problem
Answers
Answer:
X=1
3(4x-3)+8=-1+12
Distribute
12x-9+8=11
-8=-8
12x-9=3
+9=+9
12x=12
__ __
12 12
X=1
9. What is the tan(90-x)?
A. 0.22
B. 0.45
C. 0.89
D. 0.75
E. 0.12
F. 0.56
Answers
Applying the trigonometric ratios, tan(90 - x) is: D. 0.75.
Trigonometry Ratiostan (90 - x) = cot x
cot x = adj/opp
Given, tan (90 - x)
Reference angle (∅) = xAdjacent = 3 unitsOpposite = 4 unitsHypotenuse = 5 unitsTherefore:
cot x = 3/4 = 0.75.
Thus, applying the trigonometric ratios, tan(90 - x) is: D. 0.75.
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What is the test of nonverbal intelligence?
Answers
A test of nonverbal intelligence is a type of cognitive assessment that measures an individual's ability to solve problems and think abstractly without the use of language.
Unlike traditional intelligence tests that rely heavily on verbal abilities such as vocabulary, reading, and verbal reasoning, nonverbal intelligence tests use visual-spatial and abstract reasoning tasks that do not require the use of language.
Nonverbal intelligence tests can be particularly useful for individuals who have language or communication difficulties, such as those with speech and language disorders, or those who are non-native speakers of the language in which the test is administered. They can also be used to assess individuals who have difficulty with traditional tests due to visual or hearing impairments.
Examples of nonverbal intelligence tests include Raven's Progressive Matrices, the Naglieri Nonverbal Ability Test (NNAT), and the Universal Nonverbal Intelligence Test (UNIT). These tests typically involve completing visual pattern recognition and completion tasks, spatial reasoning tasks, and other nonverbal problem-solving tasks.
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Onitsha is 450km due south of Kafanchan. Ibadan is due west of Onitsha and on a bearing 225° from Kafanchan. Find the distance between: (1) Ibadan and Onitsha (2) Ibadan and Kafanchan
Answers
The distance between Ibadan and Onitsha is 450km
The distance between Ibadan and Kafanchan is 636. 4km
How to determine the valueTo determine the distance, we have that;
The distance of Onitsha from Kafanchan is 450km
The distance between Ibadan and Onitsha is x
The distance between Ibadan and Kafanchan is y
Note that the third quadrant is 270 degrees
Then, the value of the angle = 270 - 225 = 45 degrees
Then, using the tangent identity, we have that;
tan 45 = x/450
cross multiply the values
x = 450km
Also, using the sine identity
sin 45 = 450/y
cross multiply the values
y = 636. 4 km
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(b) Given the matrix D = k 0 0 3 k² k³ 0 kª k³ kº k k k 0 0 0 k¹⁰ Find all possible value(s) of k if det(D) = 1024."
Answers
To find the possible values of k, we need to calculate the determinant of matrix D and set it equal to 1024.
Given matrix D:
D = | k 0 0 |
| 3 k² k³ |
| 0 kª k³ kº |
| k k k |
| 0 0 0 |
| k¹⁰ |
The determinant of D can be calculated by expanding along the first row or the first column. Let's expand along the first row:
det(D) = k(det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |)
- 0(det | 3 k² k³ |
| 0 kª k³ |
| k k k |)
+ 0(det | 3 k² k³ |
| k k k |
| k k k |)
Simplifying further, we have:
det(D) = k(det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |)
Now, we can calculate the determinant of the 3x3 submatrix:
det | k³ k k |
| 0 k³ kº |
| 0 0 k¹⁰ |
This determinant can be found by expanding along the first row or the first column. Expanding along the first row gives us:
det = k(k³(kº) - 0(k)) - 0(0(k¹⁰)) = k⁴kº = k⁴+kº
Now, we can set det(D) equal to 1024 and solve for k:
k⁴+kº = 1024
Since we are looking for all possible values of k, we need to solve this equation for k. However, solving this equation may require numerical methods or approximations, as it is a quartic equation.
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Find how many solutions exist for each system of equations.
y = –3x + 2
y = 2x
A. no solution
B.infinitely many solutions
C.one solution
D.cannot be determined
Answers
Answer:
c.one solution
Step-by-step explanation:
y=-3x+2
y=2x
hence:3x+2=2X
2x+3x=2
5x=2
x=2/5
Could someone help please I dont understand
Answers
Answer:9 hours
Step-by-step explanation:
when rounding to the nearest tenth, you use the number behind the decimal to determine which way you go. if it's below five(.1, .2, .3, .4) then you go down, if its above five(.6, .7, .8, .9) you would up. in this case, it's above fine, so we round up, which would make the total hours Andreas spent on the project 9 hours.
I know the first part of the question is solve by54 = N x 120N = 45%How do I find the percent of incorrect answers?
Answers
To determine the percent of incorrect answers:
Out of 120 trigonometry test question, 54 was answered correctly:
Let the number of question with incorrect answer be 120 - 54 = 66
\(\begin{gathered} x\text{ \% 0f 120 =66} \\ \frac{x}{100}\text{ x 120 = 66} \\ \frac{120x}{100}=66 \\ 120x=6600 \\ \text{divide both side by 120} \\ x=\frac{6600}{120} \\ x=55\text{ \%} \end{gathered}\)Hence she answered 55 % incorrectly
I need help bad I’m struggling
Answers
Answer:
30 ft², 40 ft², 70 ft²
Answer:
4th option
Step-by-step explanation:
Applying Pythagoras' identity to the figure
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, then
If the area on the 2sides is 30 ft² and 40 ft² then the hypotenuse is
30 ft² + 40 ft² = 70 ft²
At a tree farm, there are 9 rows of 36 spruce trees.In each row, 14 of the spruce trees are blue spruce. How many spruce trees are NOT blue spruce?
Answers
Answer:
198 spruce are NOT blue
Step-by-step explanation:
Answer:
22 not blue each row.
198 = ANSWER
Step-by-step explanation:
Using the properties of antiderivatives in theorem 6.1 to find (2 cos(r) +5sin(x))dx 1(2 cos(z) + 5 sin(x)) dx =
Answers
the integral of (2 cos(r) +5sin(x))dx 1(2 cos(z) + 5 sin(x)) dx is given by 2sin(r) + 2cos(z)x + C, where C is the constant of integration.
Using the properties of antiderivatives in theorem 6.1, we can find the antiderivative of (2cos(r) + 5sin(x))dx as follows:
1(2cos(z) + 5sin(x))dx = ∫(2cos(r) + 5sin(x))dx
We can separate the integral into two parts:
∫(2cos(r)dx) + ∫(5sin(x)dx)
Now, we can find the antiderivative of each part:
∫(2cos(r)dx) = 2∫(cos(r)dr) = 2sin(r) + C₁
∫(5sin(x)dx) = 5∫(sin(x)dx) = -5cos(x) + C₂
Combine the two antiderivatives:
2sin(r) - 5cos(x) + C₁ + C₂
Since C₁ and C₂ are constants, we can combine them into a single constant C:
2sin(r) - 5cos(x) + C
When using the properties of antiderivatives in theorem 6.1 to find (2 cos(r) +5sin(x))dx 1(2 cos(z) + 5 sin(x)) dx, the answer can be found by using the linearity of integration.
Let's first obtain the integral of (2 cos(r) +5sin(x))dx. The integral of 2cos(r) with respect to x is given by 2sin(r) + C, while the integral of 5sin(x) with respect to x is given by -5cos(x) + C.
Therefore, the integral of (2 cos(r) +5sin(x))dx is (2sin(r) - 5cos(x)) + C1
Similarly, let's find the integral of (2 cos(z) + 5 sin(x)) dx.
The integral of 2cos(z) with respect to x is given by 2cos(z)x + C, while the integral of 5sin(x) with respect to x is given by -5cos(x) + C.
Therefore, the integral of (2 cos(z) + 5 sin(x)) dx is (2cos(z)x - 5cos(x)) + C2
Thus, the integral of (2 cos(r) +5sin(x))dx 1(2 cos(z) + 5 sin(x)) dx = [(2sin(r) - 5cos(x)) + C1] + [(2cos(z)x - 5cos(x)) + C2] = 2sin(r) + 2cos(z)x + C
Where C = C1 + C2. Therefore, the integral of (2 cos(r) +5sin(x))dx 1(2 cos(z) + 5 sin(x)) dx is given by 2sin(r) + 2cos(z)x + C, where C is the constant of integration.
Learn more about antiderivatives , here: brainly.com/question/15522062
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The total number of fans is attendance at a Wednesday baseball game was 48,268. The game had 12,568 more fans than the Tuesday game the day before. How many fans attended each game?
Answers
35,700+48,268=83,969.
can someone pls help
Answers
Answer: i think the answer 12
Step-by-step explanation:
Answer:
Hello! answer: 20
Step-by-step explanation:
I don't know why they say z = something there is no z so we dont need that but we do need to know what y and x is so... y = 5 and x = 10
so the 10 + 2 × y = answer
10 + 10 = 20 so 20 is the answer! Hope that helps!
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1) alyssa has 4 less than 7 times the number of dimes (j) than jessica has which expression shows the number of dimes alyssa has.
A) 4 - 7j
B) 4J - 7
C) 7 - 4J
D: 7J - 4