2. What is the gravitational force on a 70.0 kg object that is 3.18 x 10 ^6m on the
earth's surface ?

The general formula for the conservation of energy for both the hoop and the cylinder can be expressed as: Etotal = Ekinetic + Epotential

Energy is the capacity of a system or object to do work. It is the ability to cause change by transferring energy from one object to another. Energy can take many forms, such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (energy from heat), electrical energy (energy from the flow of electrons), chemical energy (energy stored in chemical bonds), and nuclear energy (energy stored in the nucleus of an atom).

Where Etotal is the total energy, Ekinetic is the kinetic energy and Epotential is the potential energy.

Therefore, the general formula for the conservation of energy for both the hoop and the cylinder can be expressed as:

Etotal = (1/2 mv2) + (mg * h)

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Answer:

The scale at the North Pole is higher by 3.1 N.

Explanation:

The scale at the equator has a centripetal acceleration unlike the North Pole. So, finding acceleration at the equator from centripetal force,

(mv^2)/r = mg

v^2/r=g

463 m/s ^2 / 6378100 m = g

g = 0.0336

then multiply by the mass, 91 kg,

you'll get the difference of 3.06 or 3.1 rounded.

A man of weighs himself 91 kg at the north pole and at the equator, so the scale reading at the North Pole will be higher by 3.1 N.

The equator is a large circle that surrounds the Earth, lies in a plane perpendicular to its axis, and is evenly spaced from both geographic poles.

The geographic Equator, also known as the terrestrial Equator, is the imaginary line on the surface of the Earth from which latitude is calculated. It is also the line at 0° latitude. The geographic Equator separates the Earth into the Northern and Southern hemispheres.

According to the question,

The equator has a centripetal acceleration that is different from the North Pole. So, finding acceleration at the equator from the centripetal force,

mg = (mv²) / r

g = v²/r

g= 463 / 6378100

g = 0.0336

then,

0.0336 × 91

= 3.06

Hence, the difference will be 3.06.

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Answer:

gimmie

Explanation:

Answer: the location from where the black ball was thrown from because after the collision the  velocity will make it still go further not stop

Explanation:

(a) The total displacement is zero

(b) The average velocity from the grocery store to the post office is 11 m/s.

(c) The average speed of the entire trip is 9.71 m/s

The given parameters;

(a) The total displacement is the change in his position;

Displacement = forward position - backward position

Displacement = 510 m - 510 m = 0

(b) The average velocity from the grocery store to the post office;

Displacement = 510 m - 180 m = 330 m

Time of motion from his home to grocery store, = (60 - 45) = 15 s

Time of motion to post office = 45 s - 15 s = 30 s

\(average \ velocity = \frac{330}{30} = 11 \ m/s\)

(c) The average speed of the entire trip;

total distance = 510 m forward + 510 m backward = 1020 m

total time = 45 s + 60 s = 105 s

\(average \ speed = \frac{1020}{105} \\\\average \ speed = 9.71 \ m/s\)

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Answer:

13m

Explanation:

North and East are perpendicular so if you illustrate this it will be a right-angle triangle;

One side will be 12 and the another will be 5;

The hypotenuse will be the desired distance;

We can use pythagoras to calculate it:

5² + 12² = x²

25 + 144 = x²

169 = x²

x = 13

1) Berenice, Chadwick, and Edouard have poor vision (near-sightedness)

The near point, or the shortest distance at which an item can be seen well by a human eye, is 25cm.

The far point is the farthest distance at which an item may be viewed clearly with the bare eye.

Diverging lenses, which produce virtual pictures at the individual's far point when confronted with objects at infinity, can be used to treat nearsightedness.

2) Bernice and Edouard have a near point larger than 25cm and a far point less than infinity, resulting in nearsightedness and hyperopia.

Because of the reasons stated above, the folks listed will need bifocals to correct their vision.

Converging lenses, which produce virtual pictures at the patient's near point when shown with things at 25 cm, can cure farsightedness. To compensate for both farsightedness and nearsightedness, bifocals have both converging and diverging lenses.

3) The near point, or the shortest distance within which an item can be seen well by a human eye, is 25cm.

The far point is the farthest distance at which an item may be viewed clearly with the bare eye.

A hyperopic eye can see far away objects clearly, but its near point grows, thus it is higher than 25cm for that eye.

According to the table, Avishka and Francesca have farsightedness, hence their near point is more than 25cm, hence can be corrected using Converging lenses.

Nearsightedness often runs in families. Objects in the distance seem hazy. The illness can progress slowly or quickly. Treatment options include glasses, contact lenses, and LASIK surgery.

Nearsightedness is frequently caused by an eye that is excessively long or oval-shaped rather than spherical. It might also be caused by a too-steep corneal curvature. As a result of these alterations, light beams collide in front of the retina. The messages transferred from the retina to the brain are distorted.

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Answer:

I know you said not to do this but I am doing a challenge and You asked this an hour ago. PLS DON'T REPORT ME.

Explanation: Sorry

Answer:

25 m/s

Explanation:

200/8 = 25

Answer:

all of those are pisitions

Explanation:

SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.

SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.

SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.

Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.

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Answer:

D.

Explanation:

The ball travels distance D in ∆t = 2.60 s. Therefore, the x component of the initial velocity is D =v

ox

​

 ⇒ ∆t = D/∆t = 15.4 m/s Due to the symmetry of projectile motions, it takes 1.2 seconds the ball to reach the initial height after passing the top of the wall downward. Therefore, the total flight time is t

tot

​

 = 1.2 + 2.6 +1.2 = 5 s The horizontal range is R = v

ox

​

t

tot

​

 = 77.0 m  

By symmetry, the ball reaches the peak of the motion at time t

top

​

 = t

tot

​

/2 = 2.5 s At the peak, the y component of the velocity is zero. Thus we have 0 = v

oy

​

 – gt

top

​

 ⇒ v

oy

​

  = gt

top

​

= 24.5 m/s The height of the wall is equal to the height of the ball at t = 1.2 s h = y (t = 1.2 s) = v

oy

​

 +v

oy

​

t – (1/2)gt

2

  = 23.3 m

Answer:

8.33 meters/sec.

time = 30 sec. 30 sec. = 8.33 meters/sec.

Answer:

B.

Divide the height of the valley walls by the rate of erosion.

Explanation:

There is a relationship between the rate of erosion and the hieght at which it is eroded according to Newton's law of motion. In the case of the scenario above, the best way to determine the time the river started carving the valley would be the division of the height of the valley walls by the rate of erosion.

Answer:30

Explanation:

Current=60 milliamps

Current=(voltage)/(resistance)

60=(voltage)/(resistance)

Doubling the resistance means multiplying both sides by 1/2

60x1/2=(voltage)/(resistance) x 1/2

30=(voltage)/2(resistance)

Therefore the resistance would be 30 milliamp if we double the resistance

Answer:

c. speed

Explanation:

In a distant-time graph the x value is usually the time and the y value is usually the distance.

If slope is the change in y over the change in x, on a distant time graph the slope would be the change in time over the change in distance

Or time / distance.

Time / distance happens to calculate speed.

Thus, the slope of a line on a distant-time graph is speed.

\(\huge\textbf{Hey there!}\)

\(\large\textbf{The formula for Slope of a line is: }\mathbf{m = \dfrac{rise}{run}}\large\textbf{ whereas it is}\\\large\textbf{equal to/equivalent to }\mathbf{ \dfrac{y_2 - y_1}{x_2- x_1} \ .}\\\\\large\textbf{Basically, the slope of the line is measured with its }\\\large\textbf{\underline{steepness}. The word steepness simply means a}\\\lage\textbf{very sharp slope.}\)

\(\large\textbf{On slope of a line on distant-time graph is basically how }\\\large\textbf{ \boxed{\bf FAST} a particular object is.}\)

\(\large\textbf{Now, that we got that information out of the way we}\\\large\textbf{can find out our answer.}\)

\(\large\textbf{The formula for distance is: }\mathbf{d= \sqrt{(x_2 - x_1)^2 + (y_2 +y_1)^2}}}\)

\(\large\textsf{We cannot say that OPTION A isn't your answer because you}\\\large\textsf{cannot calculate slope of a line on a distant-time graph. You}\\\large\textsf{cannot calculate the speed of the object by using that formula.}\\\large\textsf{So, this eliminates Option A. as your answer.}\)

\(\large\textbf{The formula of time is: }\mathbf{time = \dfrac{distance}{speed}}\)

\(\large\textsf{Yes, it calculates the distance but it doesn't calculate how fast a(n)}\\\large\textsf{object is going. So this eliminates Option B. as your answer.}\)

\(\large\textsf{The formula for speed is: }\mathbf{s = \dfrac{d}{t}}\large\textbf{ whereas s = \underline{speed}, }\\\large\textsf{d = \underline{distance} you have \underline{traveled}, \& t = \underline{time} that has}\\\large\textsf{been \underline{elapsed}.}\\\large\textsf{Option C. could possibly be your answer}\)

\(\large\textbf{Option C. seems to be the closes to your result than the}\\\large\textbf{to your answer.}\)

\(\large\boxed{\text{Therefore, your answer should be: \boxed{\textbf{Option C. Speed}}}}\huge\checkmark\)

\(\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}\)

~\(\frak{Amphitrite1040:)}\)

Answer:

The volume of a cylinder is given by the formula V = πr^2h, where r is the radius and h is the height. Substituting the given values, we get:

V = π(5.0 cm)^2(10.0 cm) = 785.4 cm^3

The radius and height are both given to two significant figures, so the answer should also be reported to two significant figures. Therefore, the volume of the cylinder can be determined to 780 cm^3.

Explanation:

Kindly give it a five-star rating.

Answer:

Graph 1 matches with B, 2 with A, and 3 with C.

Explanation:

Graph 2 shows a car whose distance part of the graph is not going up or down, while the time going up. That means that the car is stopped. Graph 1 shows a straight line, meaning that the car is traveling at a constant speed. Graph 3 is a curved line, meaning the speed of the car is changing somehow, and since the line is becoming more horizontal, the car is getting slower.

Answer:

Both particles collide at \(t = 9\). (t = 9)

Explanation:

Let be \(r_{1}(t) = \langle t^{2}, 11\cdot t - 18, t^{2}\rangle\) and \(r_{2}(t) = \langle 17\cdot t-72, t^{2}, 13\cdot t - 36\rangle\) the parametric equations of the trajectories of two particles, where \(t\geq 0\). The following condition must be met when the particles collide:

\(r_{1}(t) = r_{2}(t)\)

Which implies this system of equations:

\(t^{2} = 17\cdot t -72\) and \(11\cdot t -18 = t^{2}\) and \(t^{2} = 13\cdot t -36\)

And equivalent to the following second-order polynomials:

\(t^{2}-17\cdot t +72 = 0\)

\(t^{2}-11\cdot t +18 = 0\)

\(t^{2}-13\cdot t +36 = 0\)

Another condition is that at least a common root must exists in order to confirm a possible collision. All roots are found by factorizing each polynomial:

\((t-8)\cdot (t-9) = 0\)

\((t-2)\cdot (t-9) = 0\)

\((t-4) \cdot (t-9) = 0\)

There is one common root (\(t = 9\)), which means that both particles collide at \(t = 9\).

If Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.

A collision is defined in physics as any occurrence in which a number of bodies exert forces on one another over relatively brief period of time. Although the most popular meaning of the term collision refers to occurrences wherein two or even more objects crash violently.

Two football players collide in elastically in a tackle, initially moving with the same speed in opposite directions (as indicated in the picture). If Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.

Therefore,  if Player A has a mass of 90 kg and Player B has a mass of 75 kg, Player B will move in the opposite direction.

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Answer:

YESS well it is partly nessary but it depends on the situation

Explanation:

Answer:

Weathering, erosion, and deposistion are necessary processes in the rock cycle because:

Explanation:

First, start with igneous rocks. magma erupts (Extrusive igneous rocks) or solidifies in the sub-surface of the earth (Intrusive igneous rock). when they are exposed Weathering and erosion occur which is a slow breakdown of rock through the wind, water, or other processes. The weathered pieces (sediments) move to other places by wind or water and get deposited someplace else. When there are enough sediments and there is overburden pressure on these sediments, they become a sedimentary rock. Due to overburden pressure, they become metamorphic rocks. now the thing to understand here is that when metamorphic rocks are exposed, they too undergo weathering and erosion and their pieces also become sedimentary rocks.

Answer:

8 feet

................

Answer:

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).

Explanation:

Velocity ​​is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it. Then, the average velocity relates the change in position to the time taken to effect that change.

\(velocity=\frac{displacement}{time}\)

Velocity considers the direction in which an object moves, so it is considered a vector magnitude.

In this case, the displacement is 192 m and the time period is 8 s. Replacing:

\(velocity=\frac{192 m}{8 s}\)

Solving:

velocity= 24 \(\frac{m}{s}\)

The average velocity of a train moving along a straight track if its displacement is 192 m was during a time period of 8.0 s is 24 \(\frac{m}{s}\).

Explanation:

for part A:

work done is equal to change in potential energy which is

MgH

so the answer is 1.9 × 1 × 9.81

ANSWER FOR PART A: 18.639

FOR PART B:

power = flow rate x gh

= 5×9.81×1.9

93.195 watts

The owl started out at a height of about 3.2 metres.

Gravity is the force that draws objects toward the center of a planet or other object.

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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The value of the fourth resistor in the parallel circuit is 6 ohms.

The value of the fourth resistor is calculated by applying the formula for effective resistance of a parallel circuit.

1/Re = 1/R₁ +1/ R₂ + 1/R₃ + 1/R₄

where;

1/0.5 = 1/1 + 1/2 + 1/3 + 1/R₄

2 = 1 + 0.5 + 0.333 + 1/R₄

0.167 = 1/R₄

R₄ = 1/0.167

R₄ = 6 ohms

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