two forces of magnitude 12 n and 24 n act at the same point. which force cannot be the resultant of these forces?
The force that cannot be the resultant of these forces is 10N since it is less than both given forces
Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.
From the given options, the only force that is less than both 12N and 24 N is 10N. Hence the force that cannot be the resultant of these forces is 10N since it is less than both given forcesLearn more on resultant force here: https://brainly.com/question/14626208
Given two metal balls (that are identical) with charges LaTeX: q_1q 1and LaTeX: q_2q 2. We find a repulsive force one exerts on the other to be LaTeX: 1.35\times10^{-4}N1.35 × 10 − 4 N when they are 20 cm apart. Accidentally, one the the experimenters causes the balls to collide and then repositions them 20 cm apart . Now the repulsive force is found to be LaTeX: 1.406\times10^{-4}N1.406 × 10 − 4 N. What are the initial charges on the two metal balls?
Answer:
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
Explanation:
According to Coulomb's law, the magnitude of force between two point object having change \(q_1\) and \(q_2\) and by a dicstanced is
\(F_c=\frac{1}{4\pi\spsilon_0}\frac{q_1q_2}{d^2}-\;\cdots(i)\)
Where, \(\epsilon_0\) is the permitivity of free space and
\(\frac{1}{4\pi\spsilon_0}=9\times10^9\) in SI unit.
Before dcollision:
Charges on both the sphere are \(q_1\) and \(q_2\), d=20cm=0.2m, and \(F_c=1.35\times10^{-4}\) N
So, from equation (i)
\(1.35\times10^{-4}=9\times10^9\frac{q_1q_2}{(0.2)^2}\)
\(\Rightarrow q_1q_2=6\times10^{-16}\;\cdots(ii)\)
After dcollision: Each ephere have same charge, as at the time of collision there was contach and due to this charge get redistributed which made the charge density equal for both the sphere t. So, both have equal amount of charhe as both are identical.
Charges on both the sphere are mean of total charge, i.e
\(\frac{q_1+q_2}{2}\)
d=20cm=0.2m, and \(F_c=1.406\times10^{-4}\) N
So, from equation (i)
\(1.406\times10^{-4}=9\times10^9\frac{\left(\frac{q_1+q_2}{2}\right)^2}{(0.2)^2}\)
\(\Rightarrow (q_1+q_2)^2=2.50\times10^{-15}\)
\(\Rightarrow q_1+q_2=\pm5\times 10^{-8}\)
As given that the force is repulsive, so both the sphere have the same nature of charge, either positive or negative, so, here take the magnitude of the charge.
\(\Rightarrow q_1+q_2=5\times 10^{-8}\;\cdots(iii)\)
\(\Rightarrow q_1=5\times 10^{-8}-q_2\)
The equation (ii) become:
\((5\times 10^{-8}-q_2)q_2=6\times10^{-16}\)
\(\Rightarrow -(q_2)^2+5\times 10^{-8}q_2-6\times10^{-16}=0\)
\(\Rightarrow q_2=3\times10^{-8}, 2\times10^{-8}\)
From equation (iii)
\(q_1=2\times10^{-8}, 3\times10^{-8}\)
So, the magnitude of initial charges on both the sphere are \(3\times10^{-8}\) Coulombs\(=0.03 \mu C\) and \(2\times10^{-8}\) Colombs or \(0.02 \mu C\).
Considerion the nature of charges too,
\(q_1=\pm0.03 \mu C\) and \(q_2=\pm0.02 \mu C.\)
If you were in a spaceship traveling close to the speed of light with respect to earth, you would notice that:___.
Space ships travel at a speed close to the speed of light earth respect to earth.
If the speed of light is the same for all inertial reference frames. An inertial reference frame is one (earth) in which newlines laws are valid. All inertial reference frames move with constant velocity- redeliver to one there. ex:- If we are moving at a speed of light relative to you, then it was moving at the same speed as me relative to you. In this case, both are roving at a speed of \($0 \mathrm{~m} / \mathrm{s}$\) reflecting.
B. some of your physical dimensions are smaller than normal.
No. physical dimensions do not change the spaceship relative to the stallion with respect to earth.
C. pulse rate does not change. If a person in a spaceship moves with a speed of light, with respect to earth, because floral inertial reference frame velocity is constant. So pulse rate does not change
Answer for the given None of these effects occurs.
What is spaceship travelling?
The concept of interstellar probes or crewed spacecraft travelling between stars or planetary systems in a galaxy is known as interstellar travel. Spaceflight between planets would be far easier than interstellar travel.So the more about spaceship travelling visit:
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d. Complete the table to review what the sign and value of the magnification tell about the size and orientation of the image formed.
Magnification is the ratio of the size of the image to the size of the object.
A positive magnification indicates that the image is upright, while a negative magnification indicates that the image is inverted. When the value of the magnification is less than one, it means that the image is smaller than the object, while a magnification greater than one indicates that the image is larger than the object.
The orientation of the image formed depends on the position of the object relative to the lens. When the object is placed between the lens and the focal point, the image formed is upright and magnified, as the distance between the object and the lens is greater than the distance between the lens and the focal point. When the object is placed beyond the focal point, the image formed is inverted and reduced in size.
In summary, the sign and value of the magnification provide information about the orientation and size of the image formed. A positive magnification indicates an upright image, while a negative magnification indicates an inverted image. The magnitude of the magnification tells us whether the image is larger or smaller than the object.
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multi choice
12) When you move your hand or foot, your body has converted potential energy into ________ energy.
Answer: It’s kinetic energy
Explanation: when you move your hand or foot, your body has converted potential energy into kinetic energy.
1.
David is 10% taller than Peter and Peter is 5% shorter than John. It is given that the height of Peter
is 171 cm.
(a) Find the height of John.
Iso
(2 marks)
(b) David claims that he is the tallest person among the three. Do you agree? Explain your answer.
(2 marks)
Answer:
I don't know if I can help you with that
An elevator of inertia M might be raised and lowered directly by a winch, as in case (a) in (Figure 1) , or the mechanism might include a counterweight of inertia mthat moves up when the elevator moves down, as in case (b) in (Figure 1) .Part AIn case (a), what is the change in the gravitational potential energy of the Earth-elevator-winch system if the displacement is ?y?Express your answer in terms of the variables M, ?y, and the acceleration due to gravity g.?U(a) =Part BIn case (b), what is the change in the gravitational potential energy of the Earth-elevator-winch system if the displacement is ?y?Express your answer in terms of some or all of the variables M, m, ?y, and the acceleration due to gravity g.?U(b) =
Part A: In case (a), the change in gravitational potential energy of the Earth-elevator-winch system can be calculated by considering the work done against gravity. The gravitational potential energy change is equal to the work done, which is given by the formula:U(a) = mgh,
where m is the mass of the elevator, g is the acceleration due to gravity, and h is the vertical displacement.In this case, the elevator has an inertia M, so we need to consider the equivalent mass of the system, which is M. Therefore, the change in gravitational potential energy is:U(a) = Mgh.
Part B: In case (b), the change in gravitational potential energy of the Earth-elevator-winch system takes into account the presence of a counterweight. The counterweight moves up when the elevator moves down, reducing the effective mass and changing the potential energy.
The change in gravitational potential energy is given by:
U(b) = (M - m)gh,
where M is the inertia of the elevator, m is the inertia of the counterweight, g is the acceleration due to gravity, and h is the vertical displacement.
Therefore, the change in gravitational potential energy in case (b) is:
U(b) = (M - m)gh.
Note: The equations provided above represent the change in gravitational potential energy of the Earth-elevator-winch system and do not include the signs indicating whether the potential energy increases or decreases. The signs depend on the direction of displacement and need to be considered accordingly.
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Lab Report( 80 )
Energy
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U1_ Lab_Energy_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for the first part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect the data for the first part of the experiment.
Type your answer here:
Data and Observations
1. Record your observations in the data table.
Type your answer here:
Table 1. Measurements Taken from a Simulation of a [insert mass value] kg Ball Released from Various Heights on a Ramp
Mass of ball (kg) Drop height on ramp (m) Potential energy (J) Time to travel 1.0 m (s) Speed (m/s) Kinetic energy (J)
0.5
1.0
1.5
2.0
2.5
3.0
Conclusions
1. What conclusions can you draw about how the amount of potential energy stored in a system changes as a ball is placed at varying heights on a ramp? Write an evidence-based claim.
Type your answer here:
2. Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball system when the ball is raised to different heights on the ramp.
Type your answer here:
3. How did you use what you learned from the first part of the experiment to design a marble run?
Type your answer here:
Pls answers all of these questions quickly
Answer:
Is this a research paper?
Block a, with a mass of 4 kg, is moving with a speed of 2. 0 m/s while block b, with a mass of 8 kg, is moving in the opposite direction with a speed of 3 m/s. The center of mass of the two block-system is moving with a velocity of:.
The center of the mass of the block-system is moving with a velocity of 1.3 meters per second in the same direction as B.
In this case, we are provided with:
The mass of block A (M1) = 4 kg
The speed of block A (V1) = 2.0 meters per second
The mass of block B (M2) = 8 kg
The speed of block B (V2) = 3.0 meters per second
Consider that block A is moving in a positive direction while block B moving the opposite way.
To find the velocity of the center of the mass of the two block system, we can use this following formula:
\(V = \frac{M1V1 + M2V2}{M1+M2}\)
To find the answer, simply plug in all of the information that you already have into the equation:
\(V = \frac{(4 kg) (2m/s) + (8kg) (-3m/s)}{4 kg + 8 kg}\)
V = -1.3 m/s
Because the sign is negative, we may deduce that the center of mass of the two-block system is traveling in the same direction as B at a speed of 1.3 m/s.
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Dr. Perkins is studying how geographic proximity impacts perception of a case by potential members of a jury. Dr. Perkins is most likely a a biopsychologist b clinical psychologist c developmental psychologist d forensic psychologist
By studying how geographic proximity impacts perception of a case by potential members of a jury, Dr. Perkins is most likely a: D. forensic psychologist.
What is psychology?Psychology can be defined as the scientific study of both the consciousness and unconsciousness of the human mind such as feelings, emotions and thoughts, so as to better understand how it functions and affect human behaviors in contextual terms.
Who is a forensic psychologist?A forensic psychologist can be defined as a professional who has been trained and licensed to study how both psychological, biological, and other social factors affect a civil or criminal investigation, so as to answer legal questions that arises during court proceedings.
In this context, we can reasonably infer and logically deduce that Dr. Perkins is most likely a forensic psychologist because he studies how geographic proximity impacts perception of a case by potential members of a jury
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Answer: D. Forensic Psychologist
A forensic psychologist combines their knowledge of the legal field and the psychology field to do their jobs. We know that the answer to this question is a forensic psychologist because Dr. Perkins is studying both law, "members of a jury", and psychological elements together, "impacts perception".
Explanation: Validity of answer is show below.
A piece of metal has a mass of 60 g and a volume of 3 cm^3, what is the density of the metal..?
====================================================
Work Shown:
density = mass/volume
d = m/v
d = (60 grams)/(3 cubic cm)
d = (60/3) g per cm^3
d = 20 g per cm^3
d = 20 g/cm^3
This means that each cubic centimeter of material has about 20 grams of mass.
A cubic centimeter is a cube that has all sides each 1 cm.
The density of the piece of metal is equal to 20 g/cm³ when the mass is 60 g and a volume of 3 cm³ of metal.
What is the density?The density of a substance can be measured as the mass per unit volume of that substance. The average density is equal to the total mass of the substance divided by its total volume.
The formula for the density of the substance is represented as follows:
The density of material = Mass/Volume
The density of a material is an intrinsic property as it does not depend on its size and the S.I. unit of the density is Kg/m³. If the size of the substance increases, the mass increases as well but the density of the material remains the same.
Given, the mass of the metal, M = 60 g
The volume of the metal, V = 3cm³
The density of metal = M/V = 60 /3 = 20 g/cm³
Therefore, the density of a piece of metal is 20g/cm³.
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Help please!
Two rope tows operate on the same ski slope. When both are operating with equal loads, Tow A can move faster than
Tow B.
-Which does the most work?
1. they both do the same work
2. Tow B
3. Tow A
-Which has the most power?
1. they both have the same power
2. Tow B
3. Tow A
Answer: They both do the same amount of work but Tow A has more power
Explanation:
What happens when cooler downdrafts inside a supercell move across the edge of an upward moving mesocyclone?
A. A supercell
B. A me so cyclone
C. A tornado
D. A hurricane
Types of Waves
A transverse wave has the displacement _____________________________ to the direction of wave propagation. Give an example of this type of wave:
A longitudinal (AKA _____________________________ or __________________________) wave has the displacement _______________________________ to the direction of wave propagation. Give an example of this type of wave:
transverse : light
longitudinal : sound
transverse : up & down
longitudinal : left & right or side to side
transverse : perpendicular
longitudinal : parallel
transverse : up & down ocean wave
longitudinal : archer pulling back on a bowstring then letting go releasing the string
v = λf : speed of a wave is measured in meters per second (m/s), the wavelength is measured in meters (m), and the frequency is measured in hertz (Hz)
ANSWER:
A transverse wave has the displacement perpendicular (i.e., at right angles) to the direction of wave propagation. An example of a transverse wave is the wave on a string, where the displacement of the string is perpendicular to the direction in which the wave travels.
A longitudinal wave (also known as a compression wave or pressure wave) has the displacement parallel to the direction of wave propagation. An example of a longitudinal wave is sound waves, where the particles of the medium vibrate parallel to the direction of the wave as the wave travels through the medium.
chatgpt
Transverse waves:
The displacement of the wave is perpendicular to the direction of wave propagation.
Example: A wave on a string, where the string moves up and down while the wave moves left and right.
Simple analogy: Imagine shaking a jump rope up and down while holding it horizontally - the wave travels horizontally while the rope moves up and down.
Longitudinal waves:
The displacement of the wave is parallel to the direction of wave propagation.
Example: Sound waves, where air molecules move back and forth in the same direction as the wave.
Simple analogy: Imagine squeezing a slinky in a direction parallel to the slinky - the wave travels in that same direction while the slinky compresses and expands.
Formula used: There is no specific formula for describing the direction of wave displacement, as it depends on the type of wave. However, the speed of a wave can be calculated using the formula v = λf, where v is the speed of the wave, λ (lambda) is the wavelength, and f is the frequency.
Real-world example: Light waves are transverse waves, with the electric and magnetic fields perpendicular to the direction of propagation. This can be seen in polarization filters, which only allow light waves with a certain orientation of electric field to pass through.
Real-world example of longitudinal waves
An example of longitudinal waves in the real world is sound waves, which are pressure waves that propagate through a medium such as air, water, or solids. Sound waves are longitudinal waves because the vibrations of air molecules or particles in a medium are parallel to the direction of the wave's propagation. Examples of sound waves in daily life include the sound of a car engine, a musical instrument, or a person speaking.
ChatGPT atGPT
byjus
give two reasons why biomass energy might not be a good alternative Energy source
\( \sf{ \huge}{ \colorbox{black}{l \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}\)
as for the production of biomass energy wood is mostly used source and burning of wood for the production of biomass energy can lead to the risk of deforestation in the future and emissions of carbons, pollute the surrounding. Thus this is the reason biomass energy might not be a good alternative energy source.
\( \sf{\huge}{\colorbox{black}{I \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }}\)
A reservoir has a surface area of and an average depth of 40. 0 m. What mass of water is held behind the dam? (See
Figure 11. 5 for a view of a large reservoir—the Three Gorges Dam site on the Yangtze River in central China. )
The density of water ρ from Table 1 is \(1.000 * 10^{3} kg / m^{3}\) . Subbing V and ρ into the expression for mass gives:m= \(V=Ah=(50.0km^{2} )(40.0m)\\=[(50km^{2} ) (\frac{10^{3}m }{1km} )^2] (40.0m) = 2.00 * 10^{9} m^{3}\)
We can ascertain the volume V of the supply from its aspects, and track down the density of water ρ in Table 1. Then, at that point, the mass m can be tracked down in the meaning of density.
\(p =\frac{m}{v}\)
Tackling condition ρ = m/V for m gives m=ρV.
The volume V of the supply is its surface region Multiple times its typical profundity h:
\(V=Ah=(50.0km^{2} )(40.0m)\\=[(50km^{2} ) (\frac{10^{3}m }{1km} )^2] (40.0m) = 2.00 * 10^{9} m^{3}\)
The density of water ρ from Table 1 is \(1.000 * 10^{3} kg / m^{3}\) .
Subbing V and ρ into the expression for mass gives:
\(m= (1.00 * 10^3kg / m^3) (2.00* 10^9m^3) \\ = 2.00 * 10^{12} kg\)
An enormous supply contains an extremely huge mass of water. In this model, the heaviness of the water in the repository is mg=1.96× \(10^{13}\) N, where g is the speed increase because of the Earth's gravity (around 9.80\(m/s^{2}\) ). It is sensible to find out if the dam should supply a power equivalent to this colossal weight. The response is no. As we will find in the accompanying segments, the power the dam should supply can be a lot more modest than the heaviness of the water it keeps down.
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the complete question is:
A reservoir has a surface area of \(50.0 km^{2}\) and an average depth of 40.0 m. What mass of water is held behind the dam? (See Figure 2 for a view of a large reservoir—the Three Gorges Dam site on the Yangtze River in central China.)
the bose? (The weightidensty of water is 62.4 pounds per outec foct.) 7f−lb [0/1 Points] LARCALCET7 7. 5,027Mi
The weight density of water is 62.4 pounds per cubic foot. This value is used to determine the weight of water based on its volume.
The weight density of a substance is a measure of how much weight it has per unit volume. In the case of water, its weight density is 62.4 pounds per cubic foot. This means that for every cubic foot of water, it will weigh 62.4 pounds.
Weight density is an important concept in various fields, such as engineering, construction, and fluid mechanics. It allows us to calculate the weight of water in different scenarios. For example, if we have a tank with a known volume of water, we can use the weight density to determine the total weight of the water in the tank. Similarly, if we know the weight of water in a container, we can calculate its volume by dividing the weight by the weight density.
Understanding the weight density of water is crucial for various practical applications. It helps in designing structures that involve water, such as dams, reservoirs, and pipes, as it provides insights into the forces exerted by the water. Additionally, it is also relevant in fields like hydrology and environmental science, where accurate measurements of water weight are necessary for calculations and analysis.
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true or false if false correct the false statements :
a- the transformation of electric energy into themal energy is called joule's effect.
b - when a liquid is at rest , the pressure is at the same at any point within this liquid
Answer:
both statements are truth
Explanation:
a-The Joule effect, also called Joule's law, is the thermal manifestation of electrical resistance. ... In all these cases, it is intended to generate thermal energy with electricity passing through its conductors. This heat they give off is due to the Joule effect.
b-sure of a liquid tank depends only on the density of the liquid and depth from the free surface. It is a scalar quantity and is same in all directions, at a point.
A woman is pulling a trolley with a 27 N force along the 3.0 m aisle, how much work is done in pulling the cart from one end of the aisle to the other?
Answer:
Work done = 81 Nm
Explanation:
To calculate the work done by a force, we can use the following formula:
\(\boxed{\mathrm{Work \: done = \: Force \times Distance \: moved \: in \ direction \: of \: force}}\).
In this question, we are told that the woman applies a force of 27 N to pull a trolley 3.0 m along an aisle. Using this information, as well as the formula above, we can calculate the work done:
Work done = 27 N × 3.0 m
= 81 Nm
Therefore, 81 Nm (or 81 Joules) of work was done pulling the cart from one end of the aisle to the other.
Assertion: When I P+ Q I = I P- QI, then P must be perpendicular to Q. Reason: The relation will hold even when Q is a null vector.
Answer:
The assertion is true and reason is false.
Explanation:
Assertion: I P+ Q I = I P- QI, then P must be perpendicular to Q.
Reason : The relation will hold even when Q is a null vector.
Now
\(\left | P + Q \right |=\left | P - Q \right |\\\\P^2 + Q^2 + 2 P Q cos \theta =P^2 + Q^2 - 2 P Q cos \theta\\\\4 P Q cos \theta = 0 \\\\cos \theta = 0 \\\\\theta = 90 degree\)
So, P and Q are perpendicular to each other.
So, the assertion is true.
Reason is false.
What is the most widely accepted theory as to how our Universe formed?
what is the direction, relative to the negative x axis, of the net electric field at the origin due to these two point charges.
The electric fields due to the two point charges are along opposite directions of the x-axis, the net electric field at the origin will be the vector sum of these two electric fields. Therefore, the direction of the net electric field at the origin will be toward the negative x-axis.
We must take into account the electric field vectors produced by each point charge independently and then add them vectorially in order to find the direction of the net electric field caused by two point charges at the origin. Consider a scenario where one point charge is positive and the other is negative. In contrast to the electric field caused by a negative point charge, which points radially inward towards the charge, the electric field caused by a positive point charge radiates outward from the charge.
We can imagine the electric field vectors at the origin (0,0) as emerging from each point charge and extending either outward or inward. The vector sum of these two distinct electric fields will represent the net electric field at the origin. The electric field vector at the origin caused by the positive charge will point away from the origin along the positive x-axis if the positive point charge is situated along the positive x-axis. The electric field vector at the origin caused by the negative charge will point in the direction of the origin along the negative x-axis if the negative point charge is situated along the negative x-axis.
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A more general form of the Reynolds Transport Theorem relates the time derivative of an integral over a material region Ω to the time derivative of an integral over an arbitrary control volume V(t) that is not a material volume but coincides with Ω at the particular instant in time t :
dt
d
∫
Ω
rhofdV=
dt
d
∫
V(t)
rhofdV+∫
∂V
rhof(u−u
V
)⋅
n
^
dS, where u
V
represents the velocity of the arbitrary control volume V(t). Assume that the integrand rhof is only a function of (r,t). - Demonstrate this explicitly for a spherical control volume of radius R(t) by using Leibniz's rule to compute the integrals for the case where the fluid is stationary (u=0) and the control volume is expanding radially outward. - Discuss how you might tackle the trickier case where the fluid is moving radially outward but the flow is incompressible. What are the implications of this type of flow? How might you define Ω ? You do not have to give an explicit solution, but rather an outline of how you might formulate the solution.
The Reynolds Transport Theorem relates the time derivative of an integral over a material region to an integral over an arbitrary control volume. For a spherical control volume with expanding radius and stationary fluid, the theorem can be demonstrated using Leibniz's rule. In the case of incompressible fluid with radially outward motion, tackling the problem requires defining the material region Ω appropriately and considering the implications of the flow.
To demonstrate the Reynolds Transport Theorem for a spherical control volume of radius R(t) with a stationary fluid (u=0) and expanding radially outward, we can use Leibniz's rule to compute the integrals. By applying Leibniz's rule, we differentiate the integral expressions with respect to time and evaluate the resulting terms. This will allow us to compare the time derivative of the integral over the material region Ω with the time derivative of the integral over the control volume V(t) and the flux integral over the control surface ∂V.
In the trickier case where the fluid is moving radially outward but is incompressible, we need to define the material region Ω carefully. Since the flow is incompressible, the density ρ is constant. We can choose Ω to be a sphere of fixed radius R(t), centered at the origin. The control volume V(t) can also be a sphere of varying radius R(t), and its velocity u_V will depend on the radial motion of the fluid. By considering the implications of incompressible flow, we need to account for the fact that the fluid particles move with different velocities as they traverse the control surface ∂V. Thus, the flux integral over ∂V will involve the dot product of the density ρf and the relative velocity (u-u_V) between the fluid particles and the control volume.
In summary, the Reynolds Transport Theorem can be demonstrated explicitly for a spherical control volume with expanding radius and stationary fluid using Leibniz's rule. For the case of incompressible flow with radially outward motion, defining the material region Ω appropriately and accounting for the implications of the flow becomes crucial. The dot product of the density ρf and the relative velocity (u-u_V) plays a significant role in the flux integral over the control surface ∂V.
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Which gas in Earth’s atmosphere has increased over time due to burning fossil fuels?
oxygen
nitrogen
water vapor
carbon dioxide
Answer:
D) Carbon Dioxide
Explanation:
I hope this is right!
Answer:
d
Explanation:
Tom 75 kg stands in a 25kg canoe that is still in the water. If he jumps east out of the canoe with a speed
of 5. 0 m/s, what would the recoil speed of the canoe be?
PLEASE HELP
Tom 75 kg stands in a 25kg canoe that is still in the water. If he jumps east out of the canoe with a speed of 5. 0 m/s, the recoil speed of the canoe would be 15.0 m/s in the opposite direction (west) when Tom jumps east out of the canoe with a speed of 5.0 m/s. The negative sign indicates the opposite direction of motion.
To determine the recoil speed of the canoe when Tom jumps out, we can apply the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.
Initially, both Tom and the canoe are at rest, so the total momentum is zero. After the jump, Tom moves in one direction, and the canoe moves in the opposite direction to conserve momentum.
The momentum of an object is defined as the product of its mass and velocity. The momentum before the jump is given by:
Initial momentum = (mass of Tom + mass of canoe) * 0
The momentum after the jump is given by:
Final momentum = mass of Tom * velocity of Tom + mass of canoe * velocity of canoe
Using the conservation of momentum, we can equate the initial and final momenta:
0 = (mass of Tom + mass of canoe) * 0
0 = mass of Tom * velocity of Tom + mass of canoe * velocity of canoe
Substituting the given values:
0 = 75 kg * 5.0 m/s + 25 kg * velocity of canoe
Solving for the velocity of the canoe:
-75 kg * 5.0 m/s = 25 kg * velocity of canoe
Velocity of canoe = (-75 kg * 5.0 m/s) / 25 kg
Velocity of canoe = -15.0 m/s
Therefore, the recoil speed of the canoe would be 15.0 m/s in the opposite direction (west) when Tom jumps east out of the canoe with a speed of 5.0 m/s. The negative sign indicates the opposite direction of motion.
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how many asteroids do scientists believe exist in the solar system?
Answer:
Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.
Explanation:
a person jogs in a straight path in 20m in east direction and return in west direction covers 5m in 15 sec calculate distance and displacement covered please help
Answer:
See below
Explanation:
Total distance covered while jogging = 20 + 5 = 25 m
in 15 sec speed is then 25 m / 15 s = 1 2/3 m/s
Displacement = 20 - 5 = 15 meters east
A 12-cm-diameter circular loop of wire is placed in a 0.74-T magnetic field.
Part A When the plane of the loop is perpendicular to the field lines, what is the magnetic flux through the loop? Express your answer to two significant figures and include the appropriate units.
Part B The plane of the loop is rotated until it makes a 38? angle with the field lines. What is the angle in the equation ?B = BAcos?for this situation? Express your answer using two significant figures.
Part C What is the magnetic flux through the loop at this angle? Express your answer to two significant figures and include the appropriate units.
The magnetic flux through the loop when the plane is perpendicular to the field lines can be calculated using the formula Φ = BA, where B is the magnetic field strength and A is the area of the loop.
The magnetic flux through a closed loop is defined as the product of the magnetic field strength and the area of the loop perpendicular to the magnetic field lines. When the plane of the loop is perpendicular to the field lines, the area of the loop is maximum and equal to πr^2, where r is the radius of the loop. Thus, the magnetic flux through the loop can be calculated using the formula Φ = BA, where B is the magnetic field strength and A is the area of the loop.
The angle between the plane of the loop and the magnetic field lines affects the amount of magnetic flux through the loop, as the area of the loop perpendicular to the field lines decreases.
When the plane of the loop is at an angle to the magnetic field lines, the area of the loop perpendicular to the field lines decreases. The amount of magnetic flux through the loop can still be calculated using the formula Φ = BAcosθ, where B is the magnetic field strength, A is the area of the loop, and θ is the angle between the magnetic field lines and the normal to the loop surface. The magnetic flux through the loop when the plane is perpendicular to the field lines is calculated using the formula Φ = BA, where B is the magnetic field, and A is the area of the loop.
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Which of the following statements are true about gravity?
Check all that apply.
O A. Gravity doesn't exist between the Earth and the sun.
B. Gravity exists in the whole universe.
C. Gravity is a force that pushes two or more objects apart.
D. Gravity exists between two or more objects that have mass.
Answer:
B and D
Explanation:
A is wrong because objects with mass have gravity and the Earth and Sun both have mass. As we know, the Earth orbits around the Sun and the reason si because gravity.
B is corrects because throughout the whole universe there are objects like planets and meteors and more. All these objects have gravity because they have mass.
C Gravity pulls things together that is why we are on Earth and not pushed away into space.
D is correct, using Sun and a meteor. When a meteor comes within the gravity range of the sun, the sun pulls the meteor toward it. Without anything around the sun, nothing happens because there is nothing to pull.
compare and contrast the theories about the origin of the universe
Answer:
The best-supported theory of our universe's origin centers on an event known as the big bang. This theory was born of the observation that other galaxies are moving away from our own at great speed in all directions, as if they had all been propelled by an ancient explosive force.
Explanation:
hope this helps tho i don't quite know what you mean