Both beakers contain a liquid substance that will react with the
substance represented by the gray dots.
Which statement is true about this chemical reaction system?

OBoth containers will have the same frequency of
collisions and rates of reaction.

OContainer A will have more reactant collisions and a
higher rate of reaction.

OContainer B will have fewer reactant collisions and a
higher rate of reaction.

OContainer B will have more reactant collisions and a
higher rate of reaction.

Help please 20 pts

Answer:

c

Explanation:

c .

answer

your

this

questions

The volume (in mL) of 0.100 M Na₂CO₃ needed to produce 1.00 g of CaCO₃ is 100 mL

First, we shall determine the mole in 1.00 g of CaCO₃. Details below:

Mole = mass / molar mass

Mole of CaCO₃ = 1 / 100.09

Mole of CaCO₃ = 0.01 mole

Next, we shall obtain the mole of Na₂CO₃. Details below:

Na₂CO₃ + CaCl₂ -> 2NaCl + CaCO₃

From the balanced equation above,

1 mole of CaCO₃ were obtained from 1 mole of Na₂CO₃

Therefore,

0.01 moles of CaCO₃ will also be obtain from 0.01 mole of Na₂CO₃

Finally, we shall determine the volume of Na₂CO₃ needed. Details below:

Volume = mole / molarity

Volume of Na₂CO₃ = 0.01 / 0.1

Volume of Na₂CO₃ = 0.1 L

Multiply by 1000 to express in mL

Volume of Na₂CO₃ = 0.1  1000 =

Volume of Na₂CO₃ = 100 mL

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Answer:

7.13 L of ethanol, CH₃CH₂OH

Explanation:

We'll begin by calculating the number of mole in 2.24 g of ethanol. This can be obtained as follow:

Mass of CH₃CH₂OH = 2.24 g

Molar mass of CH₃CH₂OH = 12 + (3×1) + 12 + (2×1) + 16 + 1

= 12 + 3 + 12 + 2 + 16 + 1

= 46 g/mol

Mole of CH₃CH₂OH =?

Mole = mass / molar mass

Mole of CH₃CH₂OH = 2.24 / 46

Mole of CH₃CH₂OH = 0.049 mole

Next, we shall convert 40 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

T(°C) = 40 °C

T(K) = 40 °C + 273

T(K) = 313 K

Finally, we shall determine the volume of ethanol, CH₃CH₂OH in present in the container. This can be obtained as follow:

Pressure (P) = 17.88 KPa

Temperature (T) = 313 K

Number of mole (n) = 0.049 mole

Gas constant (R) = 8.314 L.KPa/Kmol

Volume (V) =?

PV = nRT

17.88 × V = 0.049 × 8.314 × 313

Divide both side by 17.88

V = (0.049 × 8.314 × 313) / 17.88

V = 7.13 L

Thus, 7.13 L of ethanol, CH₃CH₂OH will be present in the container.

Based on the mass of ethanol provided, the mass of liquid ethanol is 1.61 g

The relationship between the gas volume, pressure, temperature and moles is given by the ideal gas equation:

where:

From data provided:

P =  17.88 kPa

V = 3.00 L

T = 40.0 °C = 313 K

R = 0.049 mole

n = ?

n = PV/RT

n =  17.88 * 2/8.314  * 313

n = 0.0137 moles

Mass of ethanol gas = number of moles * molar mass

Mass of gaseous ethanol = 0.0137 mole * 46 g/mol

Mass of gaseous ethanol = 0.63 g

Then:

Mass of liquid ethanol, CH₃CH₂OH = 2.24 - 0.63

Mass of liquid ethanol, CH₃CH₂OH = 1.61 g

Therefore, the mass of liquid ethanol is 1.61 g

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There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.

The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.

Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:

Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)

Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2

Moles of Al3+ = 0.84 mol Al3+

Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.

It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.

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Answer:

y=meme3squared

Explanation:

YEEEEEEEEEEEEEEEE

Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Answer:

Ksp = 2.58x10⁻⁹

Explanation:

The equilibrium that takes place is:

The molar concentration of Ba⁺² at equilibrium is the solubility. The same can be said about CO₃⁻³:

So now we can calculate the Ksp from the solubility, after converting the solubility from g/L to mol/L:

Ksp = (5.07x10⁻⁵ mol/L)²

Explanation:

Ammonia is a gas,

however at low temperature or high pressure the gas become liquid and at extreme conditions,a solid

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The statement stating addition of an acid to water increases the hydronium ions of the solution and increases the solution pH is false.

The addition of an acid in water leads to its dissociation. They are of two types namely strong and weak acid. The strong acid dissociates completely while weak acid dissociates partially.

Anyways, it leads to release hydrogen of ions which on combination with water molecules forms hydronium ions. As the hydronium ions, the pH of the solution will decrease and acidic character will increase.

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Answer:

13.2 g of gold

Explanation:

We'll begin by converting 5.25 L to ft³.

This can be obtained as follow:

Recall:

1 L = 0.0353 ft³

Therefore,

5.25 L = 5.25 × 0.0353

5.25 L = 1.85×10¯¹ ft³

From the question given above,

2.45 g of gold is present in 5.25 L ( i.e 1.85×10¯¹ ft³) of soil.

Therefore, Xg of gold will be present in 1 ft³ of soil i.e

Xg of gold = 2.45/1.85×10¯¹

Xg of gold = 13.2 g

Therefore, 13.2 g of gold is present in 1 ft³ of the soil.

Without conducting an experiment, one can determine if a species in a solution is acidic or basic by using a litmus paper.

Acidic species would turn a blue litmus paper to red but have no effects on red litmus paper.

Basic species would turn a red litmus paper to blues but have no effects on blue litmus paper.

Thus, in order to determine if a species in a solution is acidic or basic without conducting any experiment, dipping a litmus paper into the solution would give an indication.

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The structure for 2-methyl-3-propalhex-2-yne can be shown in the image attached.

We know that a compound is composed of atoms that can be found in the compound. For the organic compound, we can see that we can be able to obtain the structure of the compound from the structure.

The compound as we can see is  2-methyl-3-propalhex-2-yne. The structure of the compound must be able to include a double bond as we can clearly see from the image that is attached to this answer.

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Sodium has three shells while beryllium has two shells. Beryllium has one more valence electron compared to sodium.

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Answer:

0.92g/mL

Explanation:

Density of a substance is calculated as follows:

Density = mass (m) ÷ volume (V)

According to this question, a rectangular piece of plastic has a width of 4.2 cm, a height of 1.9 cm and a length of 8.8 cm. Using the formula; L × W × H, the volume of the plastic can be calculated

V = L × W × H

V = 8.8 × 4.2 × 1.9

V = 70.2cm³

The mass of the plastic is 64.6g, hence, its density is:

Density = 64.6g ÷ 70.2cm³

Density of the rectangular plastic = 0.92g/cm³ or 0.92g/mL

Answer:

chlorine

Explanation:

Answer: Because heat rises and it also makes the water bubble up which creates more height.

Explanation:

Answer Liquid on the bottom of the pot closest to the heat source starts to get hot; as that happens, it rises. The rising hot water is replaced by the cooler, more dense water molecules.

Explanation:

10 g of limestone will produce approximately 5.59 g of calcium oxide

The chemical equation for the thermal decomposition of calcium carbonate (limestone) is:

CaCO3 (s) → CaO (s) + CO2 (g)

This equation shows that one mole of calcium carbonate (100.1 g) produces one mole of calcium oxide (56.1 g) and one mole of carbon dioxide (44.0 g).

To calculate the mass of quicklime produced when 10 g of limestone is heated, we need to determine the amount of calcium carbonate in moles:

moles of CaCO3 = mass / molar mass

moles of CaCO3 = 10 g / 100.1 g/mol

moles of CaCO3 = 0.0999 mol

Since the stoichiometry of the reaction is 1:1 between calcium carbonate and calcium oxide, we know that 0.0999 moles of calcium oxide will be produced.

mass of CaO = moles of CaO x molar mass of CaO

mass of CaO = 0.0999 mol x 56.1 g/mol

mass of CaO = 5.59 g

Therefore, 10 g of limestone will produce approximately 5.59 g of calcium oxide (quicklime).

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Answer:

46 g

Explanation:

when a mole of limestone heated it produced 1 mole of quick lime. So , the

(CaO) = 46g

Answer:

60/100x105

6300/100

63 are the answer

The molarity of vinegar is 0.47368421 moles per liter.

To calculate this, we can use the following formula:

molarity = (initial_volume - total_volume_change) / final_volume

In this case, the initial volume is 7.5 mL, the total volume change is 21 mL, and the final volume is 28.5 mL. Plugging these values into the formula, we get:

molarity = (7.5 - 21) / 28.5 = -0.47368421

The negative value for molarity indicates that the solution is diluted. This is because the total volume of the solution increased by 21 mL, while the amount of solute (acetic acid) remained the same.

It is important to note that the molarity of a solution can change depending on the temperature. This is because the volume of a solution expands as it gets warmer. Therefore, it is important to measure the volume and temperature of a solution at the same time to get an accurate measurement of its molarity.

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Answer:

H2Te

Explanation:

Hydrogen telluride is the strongest acid among the options above.

Answer: Biocapacity is the ecosystems' capacity to produce biological materials used by people and to absorb waste material generated by humans, under current management schemes and extraction technologies.Biocapacity is usually expressed in global hectares.

Explanation:

Answer:

4.4 mL

Explanation:

Methane gas and chlorine gas react to form hydrogen chloride gas and carbon tetrachloride gas. What volume of hydrogen chloride would be produced by this reaction if 1.1 mL of methane were consumed?

Step 1: Write the balanced equation

CH₄(g) + 4 Cl₂(g) ⇒ 4 HCl(g) + CCl₄(g)

Step 2: Establish the appropriate volume ratio

For gases under the same conditions, the volume ratio is equal to the molar ratio. The molar ratio of CH₄ to HCl is 1:4.

Step 3: Calculate the volume of HCl produced from 1.1 mL of CH₄

1.1 mL CH₄ × 4 mL HCl/1 mL CH₄ = 4.4 mL HCl

Answer:

0.0986M is the concentration of the Na₂S₂O₃ solution

Explanation:

Potassium iodate, KIO₃, reacts with sodium thiosulfate, Na₂S₂O₃, as follows:

KIO₃ + 6Na₂S₂O₃ +5KI + 3H₂SO₄ → 3H₂O + 3K₂SO₄ + 3Na₂S₄O₆ + 6NaI

To solve this question we must find the moles of sodium thiosulfate that reacts as follows:

Moles KIO₃:

0.0250L * (0.0100mol / L) = 2.5x10⁻⁴moles KIO₃

Moles Na₂S₂O₃:

2.5x10⁻⁴moles KIO₃ * (6mol Na₂S₂O₃ / 1mol KIO₃) = 1.5x10⁻³ moles Na₂S₂O₃

Molar concentration:

1.5x10⁻³ moles Na₂S₂O₃ / 0.01521L =

Answer:

A

Explanation:

.75 + .25 + 1.25 = 2.25 atm

1 atm is 760 mm hg

2.25 * 760 = 1710 mm HG

Answer:

\(\huge\boxed{\sf 2.25\ atm = 1710\ mm\ of\ Hg}\)

Explanation:

Partial pressure of gas A = 0.75 atm

Partial pressure of gas B = 0.25 atm

Partial pressure of gas C = 1.25 atm

Total partial pressure = 0.75 atm + 0.25 atm + 1.25 atm

= 2.25 atm

We know that:

1 atm = 760 mm of Hg

Multiply 2.25 to both sides

2.25 atm  = 760 × 2.25 mm of Hg

2.25 atm = 1710 mm of Hg

\(\rule[225]{225}{2}\)

First, a bit of theory:

Brønsted-Lowry Acids and Bases

Like water, many molecules and ions may either gain or lose a proton under the appropriate conditions. Such species are said to be amphiprotic.

If the molecules or ions gain protons, they are bases.

if they lose protons, we have an acid.

---------------------------------------------------------------------------------

a) H2O is both, acid and base. Amphoteric

b) OH- is a base, gains.

c) H3O + is an acid, loses.

d) NH3 is a base, gains.

e) NH4 + is an acid, loses.

f) NH2- is a base, gains.

g) NO3- is a base, gains.

h) CO3 2- is a base, gains.

i) HBr is an acid, loses.

j) HCN​ is an acid, loses.

We are going to have the polynomial as;

\(4u^7 + 13 u^2 - 9\)

We know that when we talk about the Polynomial we are referring to the values in which one of the algebraic terms have been raised to a given power as we can see in the problem that we have in the statement that has been made here.

We have the polynomials as;

\((8u^7 + 5u^5 - 5) - (4u^7 - 8u^5 + 4)\)

When we open up the bracket;

\(8u^7 + 5u^5 - 5 -4u^7 + 8u^5 - 4\)

We then have;

\(8u^7 - 4u^7 + 5u^5 + 8u^5 - 5 - 4\\4u^7 + 13 u^2 - 9\)

Thus we have seen how the difference between the polynomials can be gotten for the problem that we have in this case here as shown by the problem that have been solved in the statements above us here.

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Answer:

1

Explanation:

To determine the value of K (equilibrium constant) at 25 °C, we can use the Nernst equation, which relates the cell potential (E) to the equilibrium constant (K) and the standard cell potential (EºCell). The Nernst equation is given by:

E = EºCell - (RT / nF) * ln(K)

Where:

E = cell potential

EºCell = standard cell potential

R = gas constant (8.314 J/(mol·K))

T = temperature in Kelvin (25 °C = 298 K)

n = number of electrons transferred in the balanced redox equation

F = Faraday's constant (96,485 C/mol)

ln = natural logarithm

In this case, the given standard cell potential (EºCell) is -0.37 V.

The balanced redox equation for the cell reaction is:

Pt + Cr²+ -> Pt + Cr³+

Since there is no change in the oxidation state of Pt, no electrons are transferred in the reaction (n = 0).

Substituting the known values into the Nernst equation, we have:

E = -0.37 V - (8.314 J/(mol·K) * 298 K / (0 * 96,485 C/mol)) * ln(K)

E = -0.37 V

Since n = 0, the term (RT / nF) * ln(K) becomes 0, and we are left with:

-0.37 V = -0.37 V - 0

This implies that the value of K is 1, since any number raised to the power of 0 is equal to 1.

Therefore, the value of K at 25 °C for the given cell is 1.

Answer: The equation is \(_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e\)

Explanation:

Neutron capture is a process where a neutron is converted into a proton and an electron. The released particle is known as beta particle and it carries a charge of -1 units and has a mass of 0 units. It is also known as an electron. The general equation for this process is:

\(_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+ _{-1}^0\e\)

The nuclear equation for the formation of zinc via neutron capture of copper follows:

\(_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e\)