BM bisects ABC. If m ABC = 39°, what is the measure of ABM?

Therefore, the projectile goes approximately 6.9 × 10^6 meters or 6,900 kilometers high.

Let's first convert the initial speed from km/hr to m/s to be consistent with the unit of acceleration due to gravity.

1.30×10^4 km/hr = (1.30×10^4 × 1000 m/km) / (3600 s/hr) = 3611.11 m/s

We can use the kinematic equation: Δy = v0t + 1/2at^2 to determine the maximum height reached by the projectile. At the highest point, the velocity is zero, so we can use the fact that v = v0 + at = 0 to find the time it takes to reach the maximum height.

v0 = 3611.11 m/s (initial velocity)

a = -9.81 m/s^2 (acceleration due to gravity)

t = -v0/a = -3611.11/(-9.81) = 367.97 s (time to reach maximum height)

Now we can use the time to find the maximum height reached:

Δy = v0t + 1/2at^2 = 3611.11 × 367.97 + 1/2 × (-9.81) × (367.97)^2 ≈ 6.9 × 10^6 meters

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The data includes a concave mirror with a radius of curvature of +31.5 cm and magnification of m = 3.40. The formula for magnification is m = v/u, and the focal length is f = r/2. Substituting the values, we get u = v/m, and using the mirror formula, the distance of the object from the mirror is 10.15 cm.

Given data: Radius of curvature of a concave mirror, r = +31.5 cm Magnification produced by the mirror, m = 3.40

We know that the formula for magnification is given by:

m = v/u where, v = the distance of the image from the mirror u = the distance of the object from the mirror We also know that the formula for the focal length of the mirror is given by :

f = r/2where,f = focal length of the mirror

Using the mirror formula:1/f = 1/v - 1/u

We know that a concave mirror has a positive focal length, so we can replace f with r/2.

We can now simplify the equation to get:1/(r/2) = 1/v - 1/u2/r = 1/v - 1/u

Also, from the given data, we have :m = v/u

Substituting the value of v/u in terms of m, we get: u/v = 1/m

So, u = v/m Substituting the value of u in terms of v/m in the previous equation, we get:2/r = 1/v - m/v Substituting the given values of r and m in the above equation, we get:2/31.5 = 1/v - 3.4/v Solving for v, we get: v = 22.6 cm Now that we know the distance of the image from the mirror, we can use the mirror formula to find the distance of the object from the mirror.1/f = 1/v - 1/u

Substituting the given values of r and v, we get:1/(31.5/2) = 1/22.6 - 1/u Solving for u, we get :u = 10.15 cm

Therefore, the distance of the mirror from the face is 10.15 cm. The units are centimeters (cm).Answer: 10.15 cm.

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The probability that Jamal will be going to work tomorrow is approximately 0.06587.

Based on the given information, we can use the normal distribution to calculate the probability. The average commute time is 30.0 minutes with a standard deviation of 5.0 minutes. Jamal needs to reach his destination in 25.0 minutes, which is 5.0 minutes earlier than the average commute time.

To calculate the probability, we need to find the area under the normal curve to the left of Jamal's required time of 25.0 minutes. Using the z-score formula (z = (x - μ) / σ) and substituting the values, we find that Jamal's z-score is -1.

By referring to a standard normal distribution table or using statistical software, we can find that the probability of obtaining a z-score of -1 or less is approximately 0.1587. However, we want the probability to the left of the z-score, so we subtract this value from 0.5 to get 0.3413.

Therefore, the probability that Jamal will be late for his meeting is approximately 0.3413. Consequently, the probability that Jamal will be going to work tomorrow is 1 minus this probability, which is approximately 1 - 0.3413 = 0.6587 or 0.06587 (rounded to four decimal places) as a decimal.

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This criterion can be defined based on the desired level of accuracy or when the change in the estimated parameters falls below a certain threshold.

When implementing a program for a nonlinear problem using the least square adjustment technique, it is essential to determine a termination condition. This condition dictates when the program should stop iterating and provide the final estimated parameters. A common approach is to set a convergence criterion, which measures the change in the estimated parameters between iterations.

One possible criterion is to check if the change in the estimated parameters falls below a predetermined threshold. This implies that the adjustment process has reached a point where further iterations yield minimal improvements. The threshold value can be defined based on the desired level of accuracy or the specific requirements of the problem at hand.

Alternatively, convergence can also be determined based on the objective function. If the objective function decreases below a certain tolerance or stabilizes within a defined range, it can indicate that the solution has converged.

Considering the chosen termination condition is crucial to ensure that the program terminates effectively and efficiently, providing reliable results for the nonlinear problem.

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The correct answer is: It can be computed for ordinal level data and higher.

The median is a measure of central tendency that represents the middle value in a dataset when the data is arranged in ascending or descending order. It is not affected by extremely large or small values, so the statement "It is affected by extremely large or small values" is false.

The median can be computed for ordinal level data and higher. Ordinal data is a type of data that has a natural order or ranking, such as rating scales or survey responses with options like "strongly agree," "agree," "neutral," "disagree," and "strongly disagree." In such cases, the median can be calculated by arranging the data in order and selecting the middle value.

On the other hand, the median cannot be computed for nominal level data, which is a type of data that does not have any natural order or ranking. Nominal data includes categories or labels without any inherent order, such as colors or names. Therefore, the statement "It can be computed for nominal level data and higher" is false.

To summarize, the median is a measure of central tendency that can be computed for ordinal level data and higher but not for nominal level data. It is unaffected by extreme values and represents the middle value in a dataset.

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Our assumption that two consecutive elements of the Fibonacci sequence can be divisible by 13 is false, and the proposition is proved.

We begin with the fact that the Fibonacci sequence is an increasing sequence; that is, each element is greater than the one before it.

The sequence is defined as follows:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040, 1346269, 2178309, 3524578, 5702887, 9227465, 14930352, 24157817, 39088169, 63245986, 102334155, 165580141, 267914296, 433494437, 701408733, 1134903170, 1836311903, and so on.

Now, let us prove the proposition by contradiction. Assume that there are two consecutive elements of the Fibonacci sequence that are divisible by 13. Then there must be some integer n such that:

F(n) = 13m, andF(n + 1) = 13p,

where m and p are integers.

Since the Fibonacci sequence is defined recursively by F(n) = F(n-1) + F(n-2), we can obtain an expression for F(n-2) in terms of F(n) and F(n-1):

F(n-2) = F(n) - F(n-1)Since F(n) and F(n-1) are both divisible by 13, their difference must also be divisible by 13.

Therefore, F(n-2) is divisible by 13 as well. However, this contradicts the well-ordering principle, which states that every non-empty set of positive integers has a least element.

Since the Fibonacci sequence is an increasing sequence, there must be some least element k such that F(k) is divisible by 13 but F(k-1) is not. But this means that F(k-2) cannot be divisible by 13, which contradicts our assumption that both F(n) and F(n-1) are divisible by 13.

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Answer: y = 1/9

Step-by-step explanation:

7/3y=21

7= 21 x 3y

7/21 = 3y

1/3 = 3y

1/9 = y

Answer:

4 and 3

4 and 5

4 and 6

3 and -8

-4 and -21

4 and 36

4 and -7

Step-by-step explanation:

1)

4 + 3 = 7

4 × 3 = 12

2)

4 + 5 = 9

4 × 5 = 20

3)

4 + 6 =10

4 × 6 = 24

4)

3 - 8 = -5

3 × (-8) = -24

5)

-4 - 21 = -25

-4 × (-21) = 84

6)

4 + 36 = 40

4 × 36 = 144

7)

4 - 7 = -3

4 × (-7) = -28

Answer:

A. less than three batteries were used in five hours.

Answer:

a

Step-by-step explanation:

Answer:

14

Step-by-step explanation:

just add all the sides

5+5+2+2= 14

Answer:

C

Step-by-step explanation:

3x - 9y = 9 → (1)

- 2x +2y = 8 ( subtract 2y from both sides )

- 2x = - 2y + 8 ( divide through by - 2 )

x = y - 4

substitute x = y - 4 into (1)

3(y - 4) - 9y = 9

3y - 12 - 9y = 9

- 6y - 12 = 9 ( add 12 to both sides )

- 6y = 21 ( divide both sides by - 6 )

y = \(\frac{21}{-6}\) = - \(\frac{7}{2}\)

Answer:

B is the correct answer :)

The coordinates are:

To find the coordinates:

In Analytical Geometry, the midpoint of a line is calculated as the mean of two points, as follows:

\($$x_m=\frac{x_1+x_2}{2}, y_m=\frac{y_1+y_2}{2}$$\)

Each segment has two endpoints and two midpoints, which are as follows:

We must be cautious not to add the wrong coordinates.

In the first line A:

\($$\begin{aligned}&2=\frac{1+x_2}{2} \\&4=1+x_2 \\&4-1=-1+1+x_2 \\&x_2=3 \\&-1=\frac{y_2-9}{2} \\&-2=y_2-9 \\&+2-2=y_2-9+2 \\&y_2=-7\end{aligned}$$\)

So (3,7) is the other endpoint where the segment begins (1,-9).

The endpoint of the second line b at (-2,18) and its midpoint (5,9).

\($$\begin{aligned}&5=\frac{-2+x_2}{2} \\&10=-2+x_2 \\&+2+10=+2-2+x_2 \\&x_2=12 \\&9=\frac{18+y_2}{2} \\&18=18+y_2 \\&-18+18=-18+18+y_2 \\&y_2=0\end{aligned}$$\)

So, (12,0) is the opposite endpoint.

Therefore, the coordinates are:

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The correct question is given below:

A line segment has (x1, y1) as one endpoint and (xm, ym) as its midpoint. Find the other endpoint (x2, y2) of the line segment in terms of x1, y1, xm, and ym. Use the result to find the coordinates of the endpoint of a line segment when the coordinates of the other endpoint and midpoint are, respectively, (1, −9), (2, −1) and (−2, 18), (5, 9).

Answer:(3x+2)(x+4)

Step-by-step explanation: First you combine like terms to get 3x^2+10x+8

Then you use the cross method to get (3x+2)(x+4)

Sine rule is not applied to the triangle,  PQR and TUV.

      asinA = bsinB = csinC.

For the sine rule to be applied correctly, either the side or the angle in front of the side must be given.

So, the top two diagram ABC and JKL can be solved using the sine rule.

But for the bottom two triangle PQR and TUV can not be solve.

In triangle PQR, side QP and ∠R both are missing.

Thus, triangle PQR cannot be solved.

In triangle TUV, all angles are missing for the sides.

Thus, triangle TUV cannot be solved.

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Answer:

1/42 probability

dice = 1/36 probability

spinner = 1/6

Answer:

\(\frac{1}{4}\)

Step-by-step explanation:

Slope = \(\frac{y_2-y_1}{x_2-x_1}\) where the given points are \((x_1,y_1)\) and \((x_2,y_2)\)

Plug the given points (80,20) and (120,30) into the equation

\(\frac{y_2-y_1}{x_2-x_1}\\= \frac{30-20}{120-80}\\= \frac{10}{40}\\= \frac{1}{4}\)

Therefore, the slope of the line that passes through these points is \(\frac{1}{4}\).

I hope this helps!

The net of a triangular prism consists of two triangles and three rectangles.

In the net of a triangular prism, we can observe two types of polygons: triangles and rectangles.

First, let's discuss the triangles.

A triangular prism has two triangular faces, which are congruent to each other.

These triangles are equilateral triangles, meaning they have three equal sides and three equal angles.

Each of these triangles contributes two polygons to the net, one for each face.

Next, we have the rectangles.

A triangular prism has three rectangular faces that connect the corresponding sides of the triangular bases.

These rectangles have opposite sides that are parallel and equal in length.

Each rectangle contributes one polygon to the net, resulting in a total of three rectangles.

To summarize, the net of a triangular prism consists of two equilateral triangles and three rectangles.

The triangles represent the bases of the prism, while the rectangles form the lateral faces connecting the bases.

Altogether, there are five polygons in the net of a triangular prism.

It's important to note that the dimensions of the polygons may vary depending on the specific size and proportions of the triangular prism, but the basic shape and number of polygons remain the same.

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Answer:

D

Step-by-step explanation:

(87·6)/348 = 1.5

At that point, there would be 417 cookies left. At that rate it would take about 31 minutes.

Answer:

72

Step-by-step explanation:

I checked on RSM

Answer:

Option (1)

Step-by-step explanation:

By the property of the liquids,

"Liquids have a fixed volume but don't have the fixed shape. If we put a liquid in a bottle or a cup it will acquire the shape of a bottle or cup."

In our question, coffee when kept in a cup will take the shape of the cup which is a hemisphere.

Volume of a hemisphere = \(\frac{2}{3}\pi r^{3}\)

Where 'r' = radius of the hemisphere

Radius of the cup = \(\frac{16.51}{2}\) cm

Volume of the hemisphere = \(\frac{2}{3}\pi (\frac{16.51}{2} )^{3}\)

                                             = \(\frac{2}{3}\pi (8.255)^3\)

                                             = 1177.5778

                                             ≈ 1177.58 cm³

Therefore, Option (1) will be the answer.  

Answer:

325ft²

Step-by-step explanation:

The area of a rectangle=ab

a=13

b=25

13×25=325ft²

Hope this helps!

Answer:

8b

Step-by-step explanation:

You can factor the b-term out since b-term exists for all terms in the expression. By factoring out, you are basically dividing the factored term off and put it outside of the bracket, thus:

\(\displaystyle{16b-8b=\left(16-8\right)b}\)

Then evaluate and simplify:

\(\displaystyle{\left(16-8\right)b=8\cdot b}\\\\\displaystyle{=8b}\)

Answer:

its C. yw

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

i did the test

In this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.

(a) The relation Ri on R is reflexive, symmetric, and transitive.

(b) The relation R on A is not reflexive, not symmetric, and transitive.

(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.

(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.

(e) The relation Rs on Z is reflexive, not symmetric, and transitive.

A reflexive connection is a relationship between items of a set A in which each element is related to itself. As the name implies, the image of each element of the set is its own reflection. In set theory, a reflexive relation is an essential concept.

(a) Ri is reflexive, symmetric, and transitive.

- Reflexive: For any x ∈ R, (x, x) ∈ Ri since |x - x| = 0 < 1.

- Symmetric: For any (x, y) ∈ Ri, we have |x - y| < 1, which implies |y - x| < 1. Therefore, (y, x) ∈ Ri.

- Transitive: For any (x, y), (y, z) ∈ Ri, we have |x - y| < 1 and |y - z| < 1. Adding these inequalities, we get |x - z| < 2, which implies (x, z) ∈ Ri.

(b) R is not reflexive, symmetric, or transitive.

- Not reflexive: For any x ∈ A, (x, x) ∉ R since x - x = 0 is not a positive integer.

- Not symmetric: For any distinct x, y ∈ A, if (x, y) ∈ R, then x - y = 1, which implies y - x = -1 is not a positive integer. Therefore, (y, x) ∉ R.

- Not transitive: Let A = {1, 2, 3} and R = {(1, 2), (2, 3)}. Then (1, 3) is not in R since 3 - 1 = 2 is not a positive integer.

(c) R3 is not reflexive, symmetric, or transitive.

- Not reflexive: For any x ∈ Z, (x, x) ∉ R3 since x * x = x^2 is not greater than 0.

- Symmetric: For any (x, y) ∈ R3, we have xy > 0, which implies yx > 0. Therefore, (y, x) ∈ R3.

- Not transitive: Let x = -1, y = 2, and z = -1. Then (x, y) ∈ R3 and (y, z) ∈ R3, but (x, z) = (-1, -1) ∉ R3 since xz = 1 is not greater than 0.

(d) R, is not reflexive, symmetric, or transitive.

- Not reflexive: For any y ∈ Z, (y, y) ∉ R, since 3 does not divide y + 2y = 3y.

- Not symmetric: For y = 1 and z = 2, we have (2, 1) ∉ R, but (1, 2) ∈ R since 3 divides 1 + 4 = 5.

- Not transitive: Let x = 2, y = 1, and z = 5. Then (x, y) ∈ R, (y, z) ∈ R, but (x, z) = (2, 5) ∉ R since 3 does not divide 2 + 10 = 12.

(e) Rs is the relation on Z given by Rs = {(x,y) ⬠Zx Z: there exists k ⬠N such that elyk and yak).

- Reflexive: This relation is not reflexive because (1, 1) ∉ Rs as there does not exist k such that 1 x k = 1.

- Symmetric: This relation is not symmetric because, for example, (1, 2) ∈ Rs but (2, 1) ∉ Rs since there does not exist k such that 2 x k = 1.

- Transitive: This relation is not transitive. For example, let x = 1, y = 2, and z = 4. Then (x, y) ∈ Rs and (y, z) ∈ Rs, but (x, z) ∉ Rs since there does not exist k such that 1 x k = 4.

In short, in this question, we were given five relations and asked to determine if they are reflexive, symmetric, and/or transitive.

(a) The relation Ri on R is reflexive, symmetric, and transitive.

(b) The relation R on A is not reflexive, not symmetric, and transitive.

(c) The relation Rs on Z is not reflexive, not symmetric, and transitive.

(d) The relation R, on Z is not reflexive, not symmetric, and not transitive.

(e) The relation Rs on Z is reflexive, not symmetric, and transitive.

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The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

Given that,

According to a representative of the Ohio Department of Education, 3% of graduating high school seniors in Ohio have dropped out in recent years. Out of the 600 pupils enrolled, 30 students from Podunk High School dropped out of school last year.

We have to find is there enough data to say that this school's dropout rate is higher than the state average. Using symbols and words, state the alternative and hull hypotheses.

We know that,

n is 600,

3% Ohio high school seniors dropout.

30 dropout out of 600 in Podunk high school.

Here,

H₀: μ₁=μ₂  vs   H₁:μ₁≠μ₂

In coordinates,

H₀⇒ dropout number is equal for both schools.

H₁⇒ dropout number not equal for both schools.

H₀: P=0.03, H₁: P≠0.03.

Therefore, The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

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Observational data collection might be best to study how voters might decide an upcoming ballot issue.

The majority of big data is observational data, such as bank transaction records, user viewing patterns on video streaming services, or social media posts. Observational data, however, can also be sparse data (based on just a few people).

In observational research, participants and phenomena are observed in their most natural environments. Instead of using structured environments like research labs or focus groups, this allows researchers to observe how their subjects make decisions and respond to situations in their everyday lives.

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