Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.

Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.



The two blocks collide head-on in a perfectly elastic collision.

Determine the velocity of each mass after the collision.

Answers

Answer 1

Momentum is conserved, so

(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'

where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives

100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'

0 = (2 kg) v₁' + (4 kg) v₂'

v₁' = -2v₂'

Energy is also conserved, so

1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²

Simplifying yields

2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²

3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²

Substitute v₁' = -2v₂' and solve for v₂' :

3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²

3750 J = (6 kg) (v₂')²

(v₂')² = 625 J/kg = 625 m²/s²

v₂' = 25 m/s

Then the first block has final velocity

v₁' = -2 (25 m/s)

v₁' = -50 m/s


Related Questions

why only magnetic substances are used to make a magnet?​

Answers

Answer:

In substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. This makes the atoms in these substances strongly magnetic—but they are not yet magnets. To become magnetized, another strongly magnetic substance must enter the magnetic field of an existing magnet.

Which best describes what happens to sunlight after it passes through the keyhole of a door? It converges into one particular shadow region. It spreads out into multiple shadow regions. It bends back toward the door. It scatters back toward the door.

Answers

Multiple shadow regions can be observed in the wall behind the keyhole of a door. Option B is correct.

What is diffraction?

It is a phenomenon that happens when a wave (Light) is passed through a narrow aperture or a sharp edge, the light bends at the edges.

The light bends at the edges because the sharp edges have less diameter than the wavelength of light.

Therefore, multiple shadow regions can be observed in the wall behind the keyhole of a door.

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Answer: B) It spreads out into multiple shadow regions.

Explanation:

I got it right on edge

The electric field from a sheet of charge is perpendicular to the sheet and has a constant magnitude of Q/(Aeo), where A is the area of the sheet and Q is the charge on the sheet. If the sheet has an area, A=32.93 cm2, and a charge of 20.93 microC, what force, in nanoNewtons, would an electron experience due to this electric field?

Answers

The exercise tells us that the electric field is given by the following equation:

\(\vec{E}=\frac{Q}{A\epsilon_0}\)

And it also gives us, A and Q. Thus, our electric field inside the capacitor is:

\(E=\frac{20.93*10^{-6}}{(32.93*10^{-4})*(8.85*10^{-12})}=718181521.8\frac{V}{m}\)

As we know, the electric force can be written as:

\(F=q.E\)

The charge of an electron is a constant, which is q=1.6*10^(-19) C.

Finally, our force can be written as:

\(F=1.6*10^{-19}*718181521.8=1.149*10^{-19}=0.00001149microN\)

Our final answer is 0.00001149 micro Newtons

A proton is acted on by a uniform electric field of magnitude 253 N/C pointing in the negative z direction. The particie is initially at rest. (a) In what direction will the charge move? (b) Determine the work done by the electric field when the particle has moved through a distance of 2.85 cm from its initial position. x How is work done defined in terms of the displacement and electric field vectors? Did you consider the angle between these two vectors for this situation? ] (c) Determine the change in electric potential energy of the charged particle. Consider the definition of change in electric potential energy in terms of the work done by the electric field. J (d) Determine the speed of the charged particle.

Answers

(a) The proton will move in the positive z direction.

(b) The work done by the electric field is 1.44 × \(10^{-17\) J, and work done is defined as the dot product of the displacement and electric field vectors, taking into account the angle between them.

(c) The change in electric potential energy of the charged particle is also 1.44 × \(10^{-17\) J, which is equal to the negative of the work done by the electric field.

(d) The speed of the charged particle can be determined using the work-energy theorem which is 1.85 * \(10^5\) m/s

(a) Since the electric field is acting in the negative z direction and the proton has a positive charge, it will experience a force in the opposite direction and move in the positive z direction.

(b) The work done by the electric field is defined as the dot product of the displacement vector and the electric field vector:

\(work = |d| * |E| * cos(theta)\)

where |d| is the magnitude of the displacement vector, |E| is the magnitude of the electric field, and theta is the angle between the two vectors. In this case, the electric field and displacement vectors are parallel, so the angle between them is 0 degrees. The work done is given by work = |d| * |E| * cos(0) = |d| * |E|. Plugging in the values, work = (2.85 cm) * (253 N/C) = 721.05 N cm/C or 1.44 × \(10^{-17\) J.

(c) The change in electric potential energy of the charged particle is equal to the negative of the work done by the electric field. Therefore, the change in electric potential energy is also 1.44 × \(10^{-17\) J.

(d) The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. Since the proton starts from rest, the work done by the electric field is equal to the change in kinetic energy. The work done is given by work = (1/2) * m * \(v^2\), where m is the mass of the proton and v is its final velocity. Rearranging the equation, v = \(\sqrt((2 * work) / m)\). Plugging in the values,

\(v = \sqrt((2 * 1.44 * 10^{-17} J) / (1.67 * 10^{-27} kg))\) = 1.31 × \(10^5\) J/kg or 1.85 * \(10^5\) m/s

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0.250 moles of gas are in a piston.The gas does 109 J of work while 240 J of heat are added. What is the change in internal energy?

(Be careful with + and - signs. +W = expansion, +Q =added, +ΔU = temp goes up)


Thank you!

Answers

Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

work "w" will be - ve if work is done by the system, hence w= -109 J

Then substitute into eqn(1)

Change in Internal energy=

= (240 -109 )

= +131J

The change in the internal energy of the system which does 109 J of work while 240 J of heat are added is +131 J

Data obtained from the question Mole of gas = 0.250 moleWork (W) = –109 J (since work is done) Heat (Q) = 240 J (since heat is added) Change in internal energy (ΔU) =?

How to determine the change in the internal energy

The change in the internal energy of the system can be obtained as illustrated below:

ΔU = Q + W

ΔU = 240 + (–109)

ΔU = 240 – 109)

ΔU = +131 J

Thus, the change in the internal energy of the system is +131 J

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Kieran ran 8 laps of the track in 18 minutes. Jevon ran 6 laps of the track. Who had a greater average speed

Answers

Kieran had a greater average speed than Jevon. Let us go into more detail in the explanation below. To compare the average speeds of Kieran and Jevon, we need to find out the speed of each person.

We can use the formula speed = distance/time. Kieran ran 8 laps in 18 minutes, which means he ran 8/18 = 0.44 laps per minute. To find out Kieran's speed, we need to multiply this by the length of one lap. If we assume that the length of one lap is 400 meters, then Kieran's speed is:0.44 laps per minute × 400 meters per lap = 176 meters per minute Jevon ran 6 laps of the track, but we don't know how long it took him.

Therefore, we can't calculate his speed directly. However, we can still compare his speed to Kieran's by using ratios. If we assume that Jevon ran the same length of track as Kieran, then we can write the following equation: Kieran's speed/Jevon's speed = Jevon's time/Kieran's time.

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During the 1980 Mount St. Helens eruption, a ______ was generated by a direct blast traveling more than 150 m/sec and annihilating everything in its path.

Answers

During the 1980 Mount St. Helens eruption, a pyroclastic flow was generated by a direct blast traveling more than 150 m/sec and annihilating everything in its path.

In the 1980 eruption of Mount St. Helens, a devastating pyroclastic flow was generated. A pyroclastic flow is a fast-moving, ground-hugging avalanche of hot gases, ash, and volcanic debris.

It is formed when an explosive eruption column collapses, sending a dense and destructive mixture racing down the volcano's slopes. In this case, the direct blast from the eruption reached speeds of over 150 m/sec, obliterating everything in its path.

Pyroclastic flows are highly dangerous and deadly phenomena, capable of causing widespread destruction and loss of life due to their high temperatures, speed, and destructive force.

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9. How did you come up with your answer for #8?
10. If the falling time of an object is doubled, by what factor does the distance increase? Use
the times 2 seconds and 4 seconds to prove your answer. (Hint: x-v4+1/2af²)
a.
b.

Answers

You come up with 8 by solving for 2

estimate the net force needed to accelerate (a) a 1000-kg car at ½ g; (b) a 200-g apple at the same rate.

Answers

The net force needed to accelerate the 1000-kg car at ½ g is 4900 N, and the net force needed to accelerate the 200-g apple at the same rate is 0.98 N.

To estimate the net force needed to accelerate the objects, we'll use the equation:

Net force (F) = mass (m) × acceleration (a)

For both (a) and (b), we are given the acceleration as ½ g. Since g (the acceleration due to gravity) is approximately 9.8 m/s², ½ g will be 4.9 m/s².

(a) For the 1000-kg car:
1. Convert the mass to kg: 1000 kg (already in kg)
2. Use the equation F = m × a: F = 1000 kg × 4.9 m/s²
3. Calculate the net force: F = 4900 N

(b) For the 200-g apple:
1. Convert the mass to kg: 200 g × (1 kg/1000 g) = 0.2 kg
2. Use the equation F = m × a: F = 0.2 kg × 4.9 m/s²
3. Calculate the net force: F = 0.98 N

So, the net force needed to accelerate the 1000-kg car at ½ g is 4900 N, and the net force needed to accelerate the 200-g apple at the same rate is 0.98 N.

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A typical wavelength of a tsunami is _______. multiple choice 1000 to 2000 km 10 to 20 m 100 to 200 km 1 to 2 m 100 to 200 m

Answers

Of all the multiple choices given, in a tsunami a typical wavelength is 100 to 200 km

The Tsunamis are a series of large waves of extremely long wavelengths and periods produced by a tectonic activity on the seafloor.

It can be caused by:

An undersea volcanic eruptionAn undersea landslideAn undersea earthquake

A typical tsunami causes more than 200 km of wavelength.

What is a wavelength?

In physics, it is the spatial period of a periodic wave. It is the distance between identical points of two consecutive waves.

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A typical wavelength of a tsunami is _______. multiple choice 1000 to 2000 km 10 to 20 m 100 to 200 km

5. Chad wants to investigate whether adding a solute to water affects its boiling point and freezing point. He set up an experiment and recorded the boiling and freezing point in degrees Celsius (°C), his results are in the data table.

EFFECT OF SOLUTE ON BOILING AND FREEZING POINTS

Test
A.Water
B.Water + 10 grams of salt
C.Water + 20 grams of salt
D.Water +30 grams of salt
E.Water + 40 grams of salt
Boiling Point (°C)
A.100.0
B.100.5
C.101.0
D.101.5
E.102.0
Freezing Point (°C)
A.0
B.-2
C.-4
D.-6
E.-8

Based on the data, which statement would be the best conclusion?
A. Adding salt to water decreases the boiling point.
B. Adding any solute to water increases the boiling point.
C. Adding salt to water increases the boiling point and decreases the freezing point.
D. Adding any solute to water increases the boiling point and decreases the freezing point.​

Answers

Answer:

Explanation:

C. Adding salt to water increases the boiling point and decreases the freezing point.

an 8.0 kg object has a moment of inertia of 1.00 kg m2. what torque is needed to give the object an angular acceleration of 1.5 rad/s2?

Answers

The torque required to give the object an angular acceleration of 1.5 rad/s² is 1.5 Nm.

Torque

Objects that move in a translational manner use Newton's II law  (∑F = ma)and objects that move in a rotational manner also use the same concept of Newton's laws, but the quantity use rotational quantity . Then, Newton's Second Law for objects that move in a rotational manner or move in a circle uses the formula:

τ = (the moment inertia) x (the angular acceleration of the object)

With,

τ =  is the total torque acting on the object (Nm)

I = is the moment of inertia of the object (kgm²)

α = is the angular acceleration of the object (r4d/s²)

So, the required torque is:

τ = (1.00 kgm²) (1.5 r4d/s²)

= 1.5 Nm

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what is magnetic effect of current electricity​

Answers

Answer:

The magnetic effect of electric current is known as electromagnetic effect. :)

Explanation:

the magnetic effect which is connected with electricity is called magnetic effect of current.

Calculate the kinetic energy of a body whose mass is 150kg covering a total distance of 115km/hr

Answers

The kinetic energy of a body whose mass is 150kg covering a total distance of 115km/hr is 76,512.27J.

How to calculate kinetic energy?

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

Kinetic energy = ½ mv²

Where;

m = massK.E = kinetic energyv = velocity

According to this question, a body of mass 150kg is covering a total distance of 115km/hr.

115km/hr = 31.94m/s

K.E = ½ × 150 × 31.94²

K.E = 76,512.27J

Therefore, 76,512.27J is the kinetic energy of the body.

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A baseball with a mass of 0.145 kilograms collides with a bat at a velocity of 44 meters/second. the ball bounces off the bat with a speed of 49 meters/second in the opposite direction. what is the impulse? a. 4.32 newton∙seconds b. 7.25 newton∙seconds c. 8.23 newton∙seconds d. 9.42 newton∙seconds e. 13.5 newton∙seconds

Answers

The impulse is 13.5 N-s.

As we know that impulse is a sudden force acting on a body for a short time interval is called Impulse.

                                Δp = FΔt  

Mathematically, the change in momentum will equal impulse.

                                Δp = mΔv

                   →           Δp =  0.145(49-(-44))

                   →           Δp = 0.145(93)

                               Δp =  13.5 Newton-second

Thus, option (e) is correct.

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What was the APRS ID used by EOSS - 280? please if you find the answer in the EOSS 280 put a picture so, I can see it. the answer should only find in EOSS which is Edge of space science 280.​

Answers

The specific APRS ID used by EOSS-280 for a particular flight can only be determined by accessing the flight information on the EOSS website or by contacting EOSS directly.

What was the APRS ID used by EOSS - 280?

EOSS-280 is a callsign used by the Edge of Space Sciences (EOSS), a non-profit organization that conducts high-altitude balloon flights for science and educational purposes. The APRS ID used by EOSS-280 depends on the particular flight and may vary from one mission to another.

APRS stands for Automatic Packet Reporting System, and it is a digital communication protocol used by amateur radio operators to transmit data over radio frequencies. APRS is often used in high-altitude balloon flights to track the balloon's position, altitude, and other data in real-time.

During a typical EOSS balloon flight, the APRS ID used by EOSS-280 would be transmitted over the APRS network and would be visible on websites such as aprs.fi or aprsdirect.com, allowing anyone to track the balloon's progress. However, the specific APRS ID used by EOSS-280 for a particular flight can only be determined by accessing the flight information on the EOSS website or by contacting EOSS directly.

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Explain mantle convection.

Answers

Answer:

Mantle convection is the very slow creeping motion of Earth's solid silicate mantle caused by convection currents carrying heat from the interior to the planet's surface. The Earth's surface lithosphere rides atop the asthenosphere and the two form the components of the upper mantle.

Explanation:

The mass of the part of a rod that lies between its left end and a point x meters to the right is 6x^5kg. The linear density of the rod at 7 meters is kg/ meter and at 1 meters the density is kg/meter

Answers

The mass of the part of a rod that lies between its left end and a point x meters to the right is 6x^5kg. The linear density of the rod at 7 meters is kg/ meter and at 1 meters the density is m(7) / 7 kg/m and m(1) / 1 kg/m.

Let's denote the mass of the part of the rod between its left end and a point x meters to the right as m(x). According to the problem, we have the following information:

m(x) = \(6x^5\) kg (mass of the rod between the left end and a point x meters to the right)

We need to find the linear density of the rod at two different points: x = 7 meters and x = 1 meter.

The linear density (also known as linear mass density or linear mass) is defined as the mass per unit length. Mathematically, it is represented by the symbol λ (lambda). The linear density λ is given by the ratio of mass m to the length L:

λ = m / L

To find the linear density at a specific point, we need to determine the mass of the rod between that point and the left end and divide it by the length between those two points.

At x = 7 meters:

The mass of the rod between the left end and x = 7 meters is given as m(7) = 6(\(7^5\)) kg.

The length between the left end and x = 7 meters is 7 meters.

Therefore, the linear density at x = 7 meters is:

λ(7) = m(7) / 7 kg/m

At x = 1 meter:

The mass of the rod between the left end and x = 1 meter is given as m(1) = 6(\(1^5\)) kg.

The length between the left end and x = 1 meter is 1 meter.

Therefore, the linear density at x = 1 meter is:

λ(1) = m(1) / 1 kg/m

Please note that we need the specific values of m(7) and m(1) to calculate the linear densities at x = 7 meters and x = 1 meter.

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Can someone please help me on this

How do the authors develop the central idea over the course of the

Can someone please help me on thisHow do the authors develop the central idea over the course of the
Can someone please help me on thisHow do the authors develop the central idea over the course of the
Can someone please help me on thisHow do the authors develop the central idea over the course of the
Can someone please help me on thisHow do the authors develop the central idea over the course of the

Answers

The statement that best describes the relationship between how consumers engage with product and service based brands is C. Though product and service brands both seek likes from consumers, consumers are more likely to "like" product brands because they can

accoce the quality of the product more.

How to depict the information

The relationship between how consumers engage with product and service based brands is complex and multifaceted. Both types of brands seek to establish a strong relationship with their consumers through various strategies, such as effective advertising, personalized communication, quality customer service, and social media engagement.

However, the specific strategies employed by product and service brands may differ depending on the nature of their offerings and the preferences of their target audience. For instance, product brands may focus on showcasing the quality, features, and benefits of their products through visual and sensory experiences, while service brands may emphasize the expertise, reliability, and personalization of their services through word-of-mouth recommendations and customer reviews.

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Which statement best describes the relationship between how consumers engage with product and service based brands?

A. Though product and service brands both seek likes from consumers, they have many more effective strategies to attract consumers to their product than social media.

B. Service brands seek likes from consumers more than product brands do because they rely on recommendations from their consumers in order to attract new business.

C. Though product and service brands both seek likes from consumers, consumers are more likely to "like" product brands because they can

accoce the quality of the product more.

The form of energy commonly called light is transferred by
_____ waves

Answers

Answer:

it would be electromagnetic waves

a long solenoid that has 1,170 turns uniformly distributed over a length of 0.395 m produces a magnetic field of magnitude 1.00 10-4 t at its center. what current is required in the windings for that to occur?

Answers

The current required to produce the magnetic field of 1.00 × 10^-4 Tesla in the solenoid is 0.0263 A.


The formula for the magnetic field produced by a long solenoid is given by,

B = μ0ni

where B is the magnetic field, μ0 is the magnetic constant (4π×10−7 T m A−1), n is the number of turns per unit length, and i is the current in the solenoid.

The number of turns (N) in the solenoid is 1170, the length (L) of the solenoid is 0.395 m, and the magnetic field (B) produced by the solenoid is 1.00 × 10−4 T at its center.

Number of turns per unit length (n) is given by,

n=N/L
n=1170/0.395
n=2962.03 turns/m

B = μ0ni
i = B/(μ0n)


i = (1.00 × 10−4)/(4π×10−7×2962.03)
i = 0.0263 A

Therefore, the current required in the windings of the long solenoid to produce a magnetic field of magnitude 1.00 × 10−4 T at its center is 0.0263 A.


A long solenoid has a uniform distribution of 1,170 turns over a distance of 0.395 meters, and produces a magnetic field of 1.00 × 10^-4 Tesla at its center.

B = μ0ni,

where B is the magnetic field, μ0 is the magnetic constant, n is the number of turns per unit length, and i is the current in the solenoid.

The number of turns per unit length of the solenoid. Number of turns per unit length (n) is given by: n = N/L

n = 1170/0.395 = 2962.03 turns/meter. Now that we know the number of turns per unit length, we can use the same formula to calculate the current required to produce the magnetic field of 1.00 × 10^-4 Tesla in the solenoid.

i = B/(μ0n) = (1.00 × 10^-4)/(4π × 10^-7 × 2962.03) = 0.0263 A. Therefore, the current required to produce the magnetic field of 1.00 × 10^-4 Tesla in the solenoid is 0.0263 A.

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a little ball on top of a heavier ball are dropped to the floor, resulting in a spectacular rebound of the small ball. what do we call this?

Answers

Two spheres colliding at slower speeds won't rebound as far as they should.

The "two-ball bounce problem" is frequently used to show how the exacting laws of physics may have unexpected results.

The tennis ball bounces substantially higher than one would anticipate when a basketball is placed on top of it and the two are dropped together—roughly three to four times higher than where they were dropped from.The "two-ball bounce problem" is based on the assumption that there will be two separate, instantaneous collisions: first, the lower ball will hit the floor, then it will bounce back and finally connect with the upper ball. The final velocities of both balls are predicted using Newton's law of restitution and the law of conservation of momentum.

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the electric field between oppositely-charged parallel plates is

Answers

The electric field between oppositely-charged parallel plates is uniform.

In between the oppositely charged parallel plates, the electric field is uniform. The electric field is expressed by the formula E = V / d, where E is the electric field, V is the voltage applied to the plates, and d is the separation between the plates.

In terms of dimensions, the electric field is measured in volts per meter (V/m).

The electric field between two oppositely charged parallel plates is uniform. The electric field produced between two oppositely charged parallel plates is called a uniform field because the field strength between the plates is the same.

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what is the acceleration of a football (.43kg) thrown with a force of 25N

Answers

Answer:

Explanation:

Newton's 2nd Law

F = ma

25 = (0.43)a

a = 58.14 m/s^2

What is the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind?

Answers

Answer:

The speed of mosquito over the ground is \($4m/sec$\).

Explanation:

• Relative velocity is defined as the velocity of an object B in the rest frame of another object A.

• To find the speed of mosquito over the ground, use this formula:

\($${V_{{M \mathord{\left/ {\vphantom {M A}} \right\).

\(\kern-\nulldelimiterspace} A}}} = {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} + {V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}}$$\)

Where \(, $A$\) represents air,\($M$\) represents mosquito and \($G$\) represents ground, thus \(${V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}}$\) represents velocity of air with respect to ground and so on.

\(\\${V_{{M \mathord{\left/ {\vphantom {M A}} \right. \kern-\nulldelimiterspace} A}}} = 2m/sec$ \\${V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}} = - 2m/sec$\)

• Placing the value of the given  in the above formula.

\(& {V_{{M \mathord{\left/ {\vphantom {M A}} \right. \kern-\nulldelimiterspace} A}}} = {V_{{M \mathord{\left/ {\vphantom {M G}} \right.\)

\(\kern-\nulldelimiterspace} G}}} + {V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}} \\ & \Rightarrow 2 = {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} - 2 \\\)

 \(& \Rightarrow {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} = 4m/sec \\\end{align}\]$$\)

• Hence, the speed of mosquito over the ground is \($4m/sec$\).

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We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is

X=0m/s

From the question we are told that

mosquito flying 2 m/s

against a 2 m/s headwind

Generally

The speed over the ground is the Flight Speed minus resistance speed

Generally the equation for the  speed over the ground  is mathematically given as

X=Flight Speed-resistance speed

Therefore

X=2-2

X=0m/s

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Which types of rocks (igneou, sedimentary, metamorphic) tend to have crystalline textures? How does this texture form?

Answers

Answer:

metamorpic rock

Explanation:

it has a crystallin textures

The table represents the speed of a car in a northern direction over several seconds. Column 1 would be on the x-axis, and Column 2 would be on the y-axis. Which best lists the titles of each column? Column 1 0 2 4. 6 8 10 Column 2 5 10 15 20 25 30 Column 1 should be titled "Time," and Column 2 should be titled "Velocity." Column 1 should be titled "Velocity," and Column 2 should be titled "Time." Column 1 should be titled "Time," and Column 2 should be titled "Acceleration." O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."​

The table represents the speed of a car in a northern direction over several seconds. Column 1 would

Answers

Answer:

Explanation:

Since we are looking at speed over a time unit, we have an acceleration graph. The definition of acceleration mathematically is:

\(a=\frac{v_f-v_0}{t}\) (that's the change in velocity over the change in time). The slope of any line in this graph wil represent the acceleration. Slope is rise over run, or y over x. Therefore, if acceleration is velocity over time, then the y axis is the velocity axis and the x axis is the time axis. It makes perfect, beautiful sense!!

The diagram shows a transistor used in a circuit. The transistor in the circuit is used to

The diagram shows a transistor used in a circuit. The transistor in the circuit is used to

Answers

The (NPN) transistor in this circuit is used to switch a current.  When it  switches current ON ... acting like a closed switch ... the light goes on.

It's kind of mystifying WHY all of this technological complexity is necessary.  There's already a switch in the circuit ... (the two little circles above the 1K resistor in the base circuit with the tilted line between them).  That switch could just as well be used, in place of the transistor, to directly switch the current through the light.  Why use one switch to control a transistor to make it behave like another switch ? ?

The only actual necessity for doing this that makes sense is if the switch in the base circuit is a tiny low-power switch, and the transistor is a big moose high-power transistor, controlling a high-current, multi-kilowatt searchlight.

A place you might actually find an application like this would be in your car.  A small current through the ignition switch behind the key is used to turn on a high-power transistor under the hood, which controls the huge current to the starter motor.  That way, they avoid running a 100-Ampere cable in and out of the ignition switch, and needing a several-hundred-Ampere switch in the steering column behind the key.

The diagram shows a transistor used in a circuit. The transistor in the circuit is used to Switch current. Hence option A is correct.

What is transistor ?

The definition of the Transistor is in name itself, it is the transfer of resistance. it has three terminals collector, base and emitter. Emitter is highly impured which emits the charge charrier. Collector is moderately impured which collects charge carrier and Base which is lightly impured which biases the charge carrier. It is connected in common base, common emitter and common collector mode. Common emitter mode is widely used for amplification and switch purpose.

To use transistor as a switch emitter is grounded and collector is at positive potential. When voltage at the base exceed the cut off voltage(0.7 V for silicon), it drives the current from collector to emitter and whatever instrument is connected to it gets on.

In this figure transistor is connected in common emitter mode. when current given to the base it biases the circuit, current gets start to flow from the point of 6V to emitter which at ground. Hence light bulb glows.

when base is open or no voltage is given to it. transistor will be in off state, no current flows from collector to emitter and light bulb will be off state.

Hence option A is correct

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Fitness Log

What steps can you take in your everyday life to properly care for your skeletal system? (Site 1)

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Incorporating physical activity into your everyday routine is one approach to care for your skeletal system.

Walking, running, and climbing stairs are all weight-bearing workouts that can help you grow strong bones and reduce bone loss. Substance misuse should be avoided.

What is the skeletal system?

The human skeleton is the body's internal framework. It is made up of around 270 bones at birth, which lowers to approximately 206 bones by adulthood as certain bones fuse together.

It is to be noted that the skeleton's bone mass accounts for around 14% of total body weight and achieves maximal density around the age of 21.

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16. A student uses 110 N of force to push a box
across a flat room for 7.2 m. Calculate the
amount of work that the student does. Round
your answer to two decimals and show the
correct units of measure.

Answers

Answer:

792J

Explanation:

Use the formula Force × Distance

With 110 newtons being the force and 7.2 meters being the distance

Which gives 792 and work us measured in joules therefore its joules

Work done is the dot product of force and displacement. The work done on the box to push across the surface for 7.2 m by applying a force of 110 N is 792 J.

What is force?

Force is an external agent acting on a body tp change it from the state of motion or rest.  Force is a vector quantity thus, it is characterized by a magnitude and direction.

When force acting on a body results in displacement of the body, it is said to be work done on the body. The work done on the body is the product of force and displacement.

W = F d.

Given the force acting on the box = 110 N

 displacement d = 7.2 m

Work done w = 110 N × 7.2 m

                       = 792 J.

Therefore, the work done on the box is 792 J.

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