Answer:
The force, exerted by Big Ben on the Empire State Building is 2.66972 × 10⁻⁷ N
Explanation:
The question relates to the force of gravity experienced between two bodies
The given parameters are;
The mass of Big Ben, M₁ = 1 × 10⁸ kg
The mass of the Empire State Building, M₂ = 1 × 10⁹ kg
The distance between the two Big Ben and the Empire State Building, r = 5,000,000 meters
By Newton's Law of gravitation, we have;
\(F=G \times \dfrac{M_{1} \times M_{2}}{r^{2}}\)
Where;
F = The force exerted by Big Ben on the Empire State Building and vice versa
G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
M₁, M₂, and r are the given parameters
By plugging in the values of the parameters and the constant into the equation for Newton's Law of gravitation, we have;
\(F=6.67430 \times 10^{-11} \times \dfrac{1 \times 10^8 \times 1 \times 10^9}{(5,000,000)^{2}} = 2.66972 \times 10^{-7}\)
The force, 'F', exerted by Big Ben on the Empire State Building is F = 2.66972 × 10⁻⁷ N.
Using the picture below, what must take place for the book to move in the direction of the movement arrow?
-A force must be applied to the top of the book to make sure that it is equal to the force of friction.
-The friction of the table must increase and the friction of the book decrease to allow for movement.
-The friction must be removed for any movement to take place.
-A force in the direction of the desired movement must be applied causing the forces to be unbalanced.
For the book to move in the direction of the movement arrow, a force in the direction of the desired movement must be applied causing the forces to be unbalanced.
option D is the correct answer.
What is the Newton's first law of motion?Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless it is acted upon by an external force and it will move in the direction of the applied force.
Also, from Newton's second law of motion, which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
Mathematically, Newton's second law of motion is written as;
F (net) = ma
F - Ff = ma
where;
F is the applied force on the objectFf is the force of friction opposing the motion of the objectm is the mass of the objecta is the acceleration of the object.Thus, for the book to move, the force of friction must be overcame by the applied force and this create an unbalanced force acting on the book. Also, the book will move in the direction of the net force acting on it.
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Ms Jo Jo rubbed two balloons with a piece of wool. What will happen when the balloons are brought near each other?
the total energy of a system is 300j. if the potential energy is 40j what is the kinetic energy if the object started 300m above the ground?
Answer:
43.3 m/s.
Explanation:
Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:
Total energy = Potential energy + Kinetic energy
Kinetic energy = Total energy - Potential energy
Kinetic energy = 300 J - 40 J = 260 J
However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:
Potential energy = mgh
40 J = m(9.81 m/s^2)(300 m)
m = 0.137 kg
Now we can use the kinetic energy to find the velocity:
Kinetic energy = (1/2)mv^2
260 J = (1/2)(0.137 kg)v^2
v^2 = (2*260 J) / 0.137 kg
v = 43.3 m/s (rounded to one decimal place)
Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.
A skydiver with a mass of 70 kg accelerates to Earth at a rate of 9.8 m/s2 due to gravity. What is the force on the skydiver? Explain how you determined the answer and its units.
Explanation:
GIVEN DATA
Mass=70kgAcceleration =9.8m/s2RTF=Forcesince P(momentum)=Mass×Velocity
SOLUTIONFROM NEWTONS SECOND LAW OF MOTION ,F = △P(change in momentum) t(time)F = P2 -P1
t
F= Mv2-Mv1
t
F=M( v2-v1) ,(a=v2-v1)
t t
F= m×aF= 70 × 9.8F= 686 N
ANSWER EXPLANATION IN WORDS
That question is related to Newton's second law of motion, the question ask you to find the force it gives you a mass and a acceleration As we know that the SI unit of acceleration is newton per kilogram or metre per second square It is correct to write metre per second square instead of Newton Per kilogram because because all of them are the SI unit of acceleration so that is the answer we get 686 Newton by Force .
Augustin and Edson are going to a baseball game. to get to the stadium, they travel east on the highway at 120.km/hr for 30. minutes. then they turn onto the stadium parkway and travel south at 60.km/hr for 10 minutes. assume their starting point is at the origin. what is the position of the stadium?
first change in position:D=
Equation:
Variables:
V=
D=
T=
Solution:
Second change in position:
V=
D=
T=
Solution:
The position of the stadium for the first change and second change in position is 60 Km east and 10 Km south respectively.
What is Distance?Distance is defined as the total speed of an object regardless of direction. The S unit of distance is meter (m).
The formula of distance is given as:
Distance = speed × time
Given,
Time = 30 minutes = 30 / 60 = 1/2 hour
Speed = 120 Km/h
Distance = 120 × 1/2
Distance = 60 Km east for first position
Time = 10 minutes = 10 / 60 = 1/6 hour
Speed = 60 Km/h
Distance = 60 × 1/6
Distance = 10 Km south for second position
Thus, the position of the stadium for the first change and second change in position is 60 Km east and 10 Km south respectively.
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I am having a bit of difficulty with this lab question:
_________________________________________
The passage of an occluded front may be accompanied by widespread precipitation and little temperature change at ground level. This is because occluded fronts are a combination of (1). [one / two / three] cold/cool air mass(es), which shifts a (2). [cold / warm / hot] air mass (3). [aloft / sideways / downwards].
_________________________________________
Currently, I have my answers as follows:
1. two cool/cold air masses
2. warm
3. downwards
Could someone help me out and let me know if I am correct? Thanks!
This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.
When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.
In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.
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I need help with thissss
Explanation:
back ground radiation is a natural radiation so basically everything emits background radiation. so if it were harmful, the world wouldn't be here,
so it is false
it knocks electrons out of atoms, this is because ionising radiation is a radiation that had enough energy to remove electrons form the atoms and molecules.
true because exposure to radon can damage biological molecules such as proteins, which leads to abnormal patterns of cell division, which leads to cancer.
hope it is helpful, if not , you can report and let someone else try it out.
do vote, thank you
A massless spring with force constant
580 N/m is fastened at its left end to a vertical
wall, as shown below.
The acceleration of gravity is 9.8 m/s
2
.
7 kg 5 kg
580 N/m
Initially, the 7 kg block and 5 kg block rest
on a horizontal surface with the 7 kg block in
contact with the spring (but not compressing
it) and with the 5 kg block in contact with the
7 kg block. The 7 kg block is then moved to
the left, compressing the spring a distance of
0.2 m, and held in place while the 5 kg block
remains at rest as shown below.
7 kg 5 kg
k 0.2 m
Determine the elastic energy U stored in
the compressed spring.
Answer in units of J.
The elastic potential energy stored in the compressed spring is determined as 11.6 J.
What is the elastic potential energy of the spring?
The elastic potential energy of the spring is the energy stored in the spring and the magnitude is calculated as follows;
U = ( ¹/₂kx² )
where;
k is the spring constantx is the extension of the springThe given parameters include the following;
the spring constant, k = 580 N/m
the extension of the spring, x = 0.2 m
Substitute the given parameters and solve for the elastic potential energy stored in the spring based on the compression produced by the two blocks.
U = ( ¹/₂kx² )
U = ( ¹/₂ ( 580 N/m ) ( 0.2 m )² )
U = 11.6 J
Thus, the elastic potential energy stored in the compressed spring is a function of the spring constant and extension of the spring.
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Compare the values for index of refraction of glass for each trial (values in last column) Is there good agreement between them? Would you conclude that index of refraction is constant for & given medium? Compare your calculated nz with the given index of refraction, nglass. Do they agree? Explain why it does or doesn't"
The calculated average n2 does not agree with the given index of refraction, indicating a potential discrepancy that may be attributed to experimental limitations or errors.
To analyze the agreement between the values for the index of refraction (n2) of glass in each trial, we can observe the trend and variation in the data. From the table, it appears that the values for n2 increase as the angles θ1 and θ2 increase. However, it is difficult to determine the level of agreement between the values without further statistical analysis or calculation of uncertainties.
The conclusion regarding whether the index of refraction is constant for a given medium depends on the level of agreement observed. If the values for n2 in each trial are close to each other and do not deviate significantly, it suggests good agreement and supports the hypothesis of a constant index of refraction.
On the other hand, if there is significant variation and inconsistency among the values, it indicates that the index of refraction may not be constant for the given medium.
To determine the average value of n2 from the provided results, we can calculate the mean of the n2 values:
Average n2 = (1.46 + 1.61 + 1.73 + 1.96 + 2.08 + 2.13) / 6 ≈ 1.85
Comparing the calculated average n2 (1.85) with the given index of refraction of the glass (1.50), we can see that they do not agree. The calculated average n2 is higher than the given value of 1.50. This suggests that there might be some systematic error or uncertainties in the measurements or calculations.
The difference between the calculated and given values could be due to factors such as experimental errors, instrumental limitations, or other sources of uncertainty in the measurement process.
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Complete question is:
Calculate sinθ1, sinθ2 and n2 for each of your results and add them to table 1. Keep your results to 2 or 3 significant figures.
Compare the values for index of refraction of glass for each trial (values in last column). Is there good agreement between them? Would you conclude that index of refraction is a constant for a given medium?
Determine the average value of n2 from your results.
Compare your calculated n2 with the given index of refraction of the glass (1.50). Do they agree? Explain why it does or doesn’t.
Part C
What is likely to happen to the trees if the trend continues?
Answer:
The beetles consume the trees as food. So, if the trend continues, it’s likely that the trees will die out in the coming years
Explanation:
A ball rolls from x = -5 m to x = 0 m in 1 second. What was its average velocity?(Units = m/s)
Don't forget: velocities and displacements to the right are +, to the left are -.
Answer:
\(5\; {\rm m\cdot s^{-1}}\).
Explanation:
Displacement is the change in position. In this example, the position of this ball changed from the initial value of \(x_{0} = (-5)\; {\rm m}\) to the final value \(x_{1} = 0\; {\rm m}\). Subtract the initial position from the final position to find the change in position:
\(\begin{aligned} & (\text{Displacement}) \\ =\; & (\text{Change in Position}) \\ =\; & (\text{Final Position}) - (\text{Initial Position}) \\ =\; & 0\; {\rm m} - (-5)\; {\rm m} \\ =\; & 5\; {\rm m} \end{aligned}\).
Velocity is the rate of change in position. To find average velocity (average rate of change in position), divide the total change in position (displacement) by the time required for the change:
\(\begin{aligned} & (\text{Average Velocity}) \\ =\; & \frac{(\text{Total Change in Position})}{(\text{Time Required})} \\ =\; & \frac{(\text{Displacement})}{(\text{Time Required})}\\ =\; & \frac{5\; {\rm m}}{1\; {\rm s}} \\ =\; & 5\; {\rm m\cdot s^{-1}} \end{aligned}\).
Therefore, the average velocity will be \(5\; {\rm m\cdot s^{-1}}\).
air at 400°c exchange heat with the wall of a rectangular duct of 0.5 by 2m cross section and 5m long. if velocity of the air is 2.5m/s ,find the film coefficient if the temperature of the wall is 30°c then the rate of heat transfer
The film coefficient is a measure of the ability of the fluid to transfer heat from the surface of the duct to the fluid itself. It depends on various factors such as the velocity of the fluid, the properties of the fluid, and the surface geometry.
In this case, the air is at a temperature of 400°c and is flowing through a rectangular duct of dimensions 0.5 by 2m and length 5m at a velocity of 2.5m/s. The temperature of the wall is 30°c. To find the film coefficient, we can use the Nusselt number, which is a dimensionless quantity that relates the convective heat transfer coefficient to the thermal conductivity of the fluid and the distance between the surface and the fluid. The Nusselt number can be calculated using empirical correlations. The rate of heat transfer can be calculated using the formula Q=hA(Th-Tc), where Q is the rate of heat transfer, h is the convective heat transfer coefficient, A is the surface area of the duct, Th is the temperature of the hot fluid, and Tc is the temperature of the cold fluid.
Assuming the flow is turbulent, we can use the Dittus-Boelter equation to calculate the Nusselt number. For a rectangular duct, the Dittus-Boelter equation is given by Nu=0.023\(Re^{0.8Pr^{0.4}}\), where Nu is the Nusselt number, Re is the Reynolds number, and Pr is the Prandtl number. The Reynolds number can be calculated using the formula Re=VD/v, where V is the velocity of the fluid, D is the hydraulic diameter of the duct, and v is the kinematic viscosity of the fluid. Substituting the given values, we get Re=3875, Pr=0.69, and Nu=143.6. Using the formula h=kNu/D, where k is the thermal conductivity of the fluid, we get h=55.48 W/\(m^{2}\)K. Finally, using the formula Q=hA(Th-Tc), where A=5*0.5*2=5\(m^{2}\), Th=400°c, and Tc=30°c, we get Q=69420 W. Therefore, the film coefficient is 55.48 W/m^2K and the rate of heat transfer is 69420 W.
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Explain how work and power are different. Give an example of doing the same amount of work, but producing different amounts of power.
Answer:Work is a measurement of energy.
Power is a measurement of energy per time.
So, power measures how fast work is done.
If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.
An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill
Answer:
work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.
Before your interview ends, make sure to ask these questions:Will you please call me with the hiring decision?Will you please call me with the hiring decision?Is there a target date for the hiring decision?Is there a target date for the hiring decision?Are you interviewing any other applicants?Are you interviewing any other applicants?What is your preferred method for follow-up contact?What is your preferred method for follow-up contact?
Answer:
A and B
Explanation:
got it right
Answer:
Is there a target date for the hiring decision?
What is your preferred method for follow-up contact?
Q3. If each tape represents the distance travelled by the object for 1
second, then what 'quantity' does each piece of tape provide?
One round face of a 3. 25 m, solid, cylindrical plastic pipe is covered with a thin black coating that completely blocks light. The opposite face is covered with a fluorescent coating that glows when it is struck by light. Two straight, thin, parallel scratches, 0. 225 mm apart, are made in the center of the black face. When laser light of wavelength 632. 8 nm shines through the slits perpendicular to the black face, you find that the central bright fringe on the opposite face is 5. 82 mm wide, measured between the dark fringes that border it on either side. What is the index of refraction of the plastic?
The index of refraction of the plastic is approximately 1.52. To find the index of refraction of the plastic, we can use the formula for calculating the fringe width in a double-slit interference pattern.
Given:
Wavelength of laser light (λ) = 632.8 nm = 632.8 × 10\(^(-9)\) m
Distance between the scratches (d) = 0.225 mm = 0.225 × 10\(^(-3)\) m
Width of the central bright fringe (w) = 5.82 mm = 5.82 × 10\(^(-3)\) m
The fringe width (Δy) can be calculated using the formula:
Δy = (λ * L) / d
where L is the distance between the slits and the screen.
In this case, the black face of the cylindrical pipe acts as the double-slit system, and the opposite face with the fluorescent coating acts as the screen. The distance between the slits (d) is equal to the width of the central bright fringe (w), and we need to find L.
L is the distance from the double-slit system (black face) to the screen (fluorescent face). In the cylindrical pipe, L is half of the length of the pipe:
L = (3.25 m) / 2 = 1.625 m
Substituting the values into the formula, we have:
w = (λ * L) / d
Solving for λ, we get:
λ = (w * d) / L
Substituting the given values:
λ = (5.82 × 10^(-3) m * 0.225 × 10^(-3) m) / 1.625 m
Calculating the value:
λ ≈ 8.03 × \(10^(-7)\)m
Now, we can use the index of refraction (n) formula to find the refractive index of the plastic:
n = λ0 / λ
where λ0 is the wavelength of light in vacuum.
Substituting the given values:
n = λ0 / λ = 632.8 × 10^(-9) m / 8.03 × 10^(-7) m
Calculating the value:
n ≈ 1.52
Therefore, the index of refraction of the plastic is approximately 1.52.
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what is the maximum theoretical antenna gain of a common dish antenna at the 2.4 ghz band
The maximum theoretical antenna gain of a common dish antenna at the 2.4 GHz band depends on several factors, such as the design, size, and efficiency of the antenna. However, dish antennas commonly used at the 2.4 GHz band can achieve gains in the range of 20 to 30 decibels (dB).
1. Antenna gain is a measure of how well an antenna can focus and direct the radiated or received electromagnetic energy in a particular direction.
2. The gain of an antenna is typically expressed in decibels (dB) and represents the ratio of the power radiated or received in a specific direction compared to an ideal isotropic radiator (an antenna that radiates equally in all directions).
3. The gain of a dish antenna depends on its design, size, and efficiency. Dish antennas are parabolic in shape and use the principle of reflection to focus the electromagnetic waves towards a specific direction.
4. At the 2.4 GHz band, which is commonly used for Wi-Fi, microwave communication, and other applications, dish antennas can achieve gains in the range of 20 to 30 dB. However, it's important to note that this range is a general estimate and actual antenna gains may vary depending on specific designs and implementations.
5. Higher gains indicate a more focused and directional radiation pattern, which can be beneficial for long-range communications or reducing interference.
6. It is also worth mentioning that the maximum theoretical gain is limited by physical factors, such as antenna size and the wavelength of the operating frequency. As the wavelength becomes smaller (higher frequency), the size of the antenna becomes a limiting factor in achieving higher gains.
7. To determine the specific gain of a dish antenna at the 2.4 GHz band, it is necessary to consider the specific design parameters and characteristics of the antenna in question.
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Hubble's law expresses a relationship between __________. View Available Hint(s)for Part A the recession velocity of a galaxy and the speed at which it is moving away from us the distance of a star from the center of its galaxy and its orbital speed Hubble's constant and the recession velocity of a galaxy the distance of a galaxy and the speed at which it is moving away from us
Hubble's law expresses a relationship between the distance of a galaxy and the speed at which it is moving away from us.
Hubble’s law is the observation in physical cosmology that the movement of galaxies takes place away from the Earth at speeds that are proportional to their distance. In other words, the farther a galaxy is, the faster it would move away from Earth. Furthermore, the determination of the velocity of the galaxies takes place by their redshift, a shift of the light emitted toward the spectrum’s red end. Experts consider the Hubble’s law as the first observational basis for the expansion of the universe. Currently, it serves as one of the pieces of evidence that experts cite most often in support of the Big Bang model. Furthermore, Hubble’s flow refers to the motion of astronomical objects that take place solely due to this expansion.
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Hubble's Law expresses a relationship between the distance of a galaxy and the speed it's moving away from us. The law states that these two quantities are directly proportional, paving the way for the theory that the universe is expanding.
Explanation:Hubble's Law, formulated by astronomer Edwin Hubble, expresses a specific relationship between the distance of a galaxy and the speed at which it is moving away from us. The law states that a galaxy's recession velocity (the speed at which it is moving away) is directly proportional to its distance from us. This concept is commonly expressed in the equation v = H × d, where 'v' is the galaxy's velocity, 'H' is Hubble's constant, and 'd' is the distance of the galaxy from us.
The Hubble's constant, estimated to be about 22 km/s per million light-years, is a crucial factor. This means that if a galaxy is 1 million light-years farther away, it will move away 22 km/s faster. Key evidence supporting this law includes the observed redshift of distant galaxies' spectral lines, implying that they are moving away from us.
Finally, it’s important to note that Hubble's Law is the foundation of the assertion that the universe is expanding. Thus, it profoundly impacts our understanding of the origin and evolution of the universe.
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When light hits a surface it usually bounces off at a larger angle. True or false? Justify
Answer:That only applies to highly polished surfaces, eg mirrors.
If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.
As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.
Explanation:
A loaded railroad car of mass 6000 kg is rolling to the right at 2. 0 m/s when it collides and couples with an empty freight car of mass 3000 kg, rolling to the left on the same track at 3. 0 m/s. What is the velocity of the pair after the collision? (let right be positive, left be negative)
The final velocity of the coupled freight cars after the collision is -1.0 m/s, which means that they are moving to the left with a speed of 1.0 m/s.
To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system of objects is conserved if there are no external forces acting on the system. In this case, the two freight cars are the system, and the collision is assumed to be perfectly elastic, which means that the total kinetic energy of the system is conserved as well.
Let the positive direction be to the right, and the negative direction be to the left. Then, the initial momentum of the system is:
p_initial = m1v1 + m2v2
= 6000 kg * 2.0 m/s + (-3000 kg) * 3.0 m/s
= 6000 kgm/s - 9000 kgm/s
= -3000 kg*m/s
where m1 and v1 are the mass and velocity of the loaded car, and m2 and v2 are the mass and velocity of the empty car. The negative sign indicates that the momentum of the empty car is in the opposite direction to that of the loaded car.
After the collision, the two freight cars will move together as a single unit with a common velocity v_final. Since the total momentum of the system is conserved, we can write:
p_final = (m1 + m2) * v_final
where m1 + m2 is the total mass of the system. Setting the initial and final momenta equal and solving for v_final, we get:
v_final = p_initial / (m1 + m2)
= (-3000 kg*m/s) / (6000 kg + 3000 kg)
= -1.0 m/s
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An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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A student performs an experiment and must measure the lengths of four different objects: a textbook, a pencil, a cup, and a piece of bread. which would be the most appropriate unit of measurement for her to use? kilometer meter centimeter micrometer
Centimeter is the right answer.
When a student performs an experiment and must measure the lengths of four different objects: a textbook, a pencil, a cup, and a piece of bread, centimeter would be the most appropriate unit of measurement for her to use.
The other units are either too small or too big to use for the measurement of the given objects.
KilometerOn considering kilometer we usually use the kilometer unit of measurement for the measurement of distance.
MeterConsidering meter, we can tell that 1 meter = 100 centimeters which is also more when measuring the above given objects.
MicrometerMicrometer is very small to measure the above mentioned objects.
The micrometer is a commonly used unit of measurement for infrared radiation wavelengths, bacterial and biological cell sizes, and for classifying wool according to the diameter of the fibers.
So hence on comparing all the units we can conclude that centimeter is the appropriate unit of measurement to measure a textbook, a pencil, a cup, and a piece of paper.
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A person exerts a force on a box that is at rest on the Earth. The arrows
in the diagrams shown represent the direction of the applied force. Does
the gravitational potential energy of the box change in case A?
Gravity operates as the action force, pulling the book toward the table, and the normal force of the table, acting as the reaction force, pushing the book higher.
What is meant by gravitational potential energy?A massive object's potential energy in relation to another massive object because of gravity is known as gravitational energy or gravitational potential energy. The energy that is released when the items fall toward one another is the potential energy associated with the gravitational field.
The potential energy associated with gravitational force is known as gravitational energy because it takes effort to lift items out of the gravitational pull of the Earth. Water in an elevated reservoir or kept behind a dam is evidence of gravitational potential energy, which is the potential energy resulting from elevated locations.
The book is being pulled toward the table by gravity, which acts as the action force, and is being pushed upward by the table's normal force, which acts as the reaction force.
When an object is present in a gravitational field, it has or can acquire gravitational potential energy, which is the energy that results from a change in position. Gravitational potential energy is an energy that is connected to gravitational force or gravity, to put it simply.
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Which of the following was established by the Continental Congress?
O The Smithsonian
O The Supreme Court
O The US Post Office
O the Continental Army
Answer:
The second Continental Congress started the Continental Army
Explanation:
The Smithsonian was established by the continental congress
The movement of electrically charged particles called electrons that are found orbiting every atom found in nature is the definition of:_________
Answer:
Electricity
Explanation:
The movement or flow of charged particles is what produces electricity and magnetism
Suppose we have determined the orbital period of a planet around its star. If we also know the mass of the star, then we can use the planet's orbital period and the star's mass to calculate __________.
Using the planet's orbital period and the star's mass, you can calculate the planet's orbital radius or its distance from the star.
This is possible through Kepler's Third Law, which states that the square of a planet's orbital period is proportional to the cube of its average distance from the star. Mathematically, this is represented as (T²) ∝ (R³), where T is the orbital period and R is the orbital radius.
By knowing the mass of the star (M), you can also determine the gravitational constant (G) and use these values in the equation derived from Kepler's Third Law: (T² * G * M) / (4π²) = R³. Once you solve for R, you will have calculated the planet's orbital radius.
In summary, knowing the orbital period of a planet and the mass of its star enables you to calculate the planet's distance from the star using Kepler's Third Law. This information can be useful in understanding a planet's climate, potential habitability, and its overall place in the star system.
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in the photoelectric effect, explain why the stopping potential depends on the frequency of the light but not on the intensity.
The photoelectric effect is the phenomenon where electrons are ejected from a metal surface when light of a certain frequency, called the threshold frequency, is shone on it. When electrons are ejected, they have kinetic energy and can be stopped by a potential difference applied across the metal. This potential difference at which the electrons are just stopped is called the stopping potential.
The stopping potential depends on the frequency of the light and not on its intensity because the kinetic energy of the ejected electrons depends on the energy of the incident photons, which is determined by the frequency of the light. Electrons require a minimum energy to escape from the metal surface, and this energy is proportional to the frequency of the light.
On the other hand, the intensity of the light determines the number of photons incident on the metal surface, but it does not affect their energy. Therefore, changing the intensity of the light does not change the stopping potential.
In summary, the stopping potential in the photoelectric effect depends on the frequency of the light because this determines the energy of the incident photons, whereas the intensity of the light does not affect the stopping potential because it only determines the number of photons incident on the metal surface.
In the photoelectric effect, the stopping potential depends on the frequency of the light but not on the intensity because of the following reasons:
1. The energy of individual photons is determined by their frequency, as per the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. Higher frequency photons have higher energy and can more effectively eject electrons from the metal surface.
2. The stopping potential is the minimum voltage needed to prevent ejected electrons from reaching the anode, thus stopping the photoelectric current. As the energy of the ejected electrons is determined by the energy of the photons, the stopping potential will also depend on the frequency of the light.
3. The intensity of light affects the number of photons incident on the metal surface but not their individual energies. Increasing the intensity of light increases the number of electrons ejected but does not change the energy of each electron. Therefore, the stopping potential remains the same, even if the intensity of the light changes.
In summary, the stopping potential in the photoelectric effect depends on the frequency of the light, which determines the energy of the photons and thus the energy of the ejected electrons. The intensity of light does not affect the stopping potential as it only influences the number of electrons ejected, not their energies.
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Pe un reostat sunt scrise valorile R=220 Ω, I=0,8A. Poate fi legat acest reostat la o priza de 220V?
Answer:
di ko alam eh sorey
Explanation:
di ako maalam sa ganyan
the microwave used to heat your food and the cell phones you use are part of the ____.
The microwave used to heat your food and the cell phones you use are part of the electromagnetic spectrum. The electromagnetic spectrum is a range of all types of electromagnetic radiation, including radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. Each type of radiation has a specific wavelength and frequency, determining its energy and application.
Microwaves, which have longer wavelengths and lower frequencies compared to visible light, are used in microwave ovens for heating food. They work by inducing polar molecules, such as water, in the food to rotate, generating heat through friction.
Cell phones, on the other hand, utilize radio waves for communication. Radio waves have even longer wavelengths and lower frequencies than microwaves. Cell phones send and receive signals through antennas by transmitting and detecting radio waves, allowing us to stay connected with others.
Both microwaves and cell phones are examples of everyday technologies that harness the properties of the electromagnetic spectrum to perform essential functions. While they differ in their specific applications, they both showcase the versatility and importance of understanding electromagnetic radiation.
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1. What is a conversion factor?
Answer:
arithmetical multiplier for converting a quantity expressed in one set of units into an equivalent expressed in another.
Explanation: