A tank has the shape of an inverted circular cone (point at the bottom) with height 4 feet and radius 4 feet. The tank is full of water weighing 62.5 pounds per cubic foot.We pump out water (to a pipe at the top of the tank) until the water level is 2 feet from the bottom. The work W required to do this is given byW = ?
The work required to pump out the water is 5,012,800 lb·ft.
W = ρghV
where ρ is the density of the water, g is the acceleration due to gravity (9.81 m/s2 or 32.2 ft/s2), h is the height of water above the bottom of the tank, and V is the volume of water.
We must determine the tank's water capacity before we can remedy this issue. The volume of an inverted circular cone is given by V = (1/3)πr2h, where r is the radius and h is the height.
The radius of the tank is 4 ft, and the height is 4 ft, so the volume of the tank is V = (1/3)π(4 ft)2(4 ft) = 64π ft3.
Now we need to calculate the volume of water in the tank after the water level has been lowered to 2 feet from the bottom. Since the shape of the tank is still an inverted circular cone, the volume of water will be V = (1/3)π(4 ft)2(2 ft) = 32π ft3.
Finally, we can use the equation W = ρghV to calculate the work required to pump out the water. The density of water is 62.5 lb/ft3, the acceleration due to gravity is 32.2 ft/s2, the height of the water is 2 ft, and the volume of water is 32π ft3.
Adding these values to the equation results in
W = (62.5 lb/ft3)(32.2 ft/s2)(2 ft)(32π ft3) = 5,012,800 lb·ft
Therefore, the work required to pump out the water is 5,012,800 lb·ft.
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1. A. What is the formula for the Pythagorean Theorem? (1 point)
B. Find the missing leg of the triangle using the Pythagorean Theorem. Remember that drawings may not be to scale (Round to the nearest tenth).
Show your work. (4 points)
20 ft
18 ft
x
Answer:
side 1^2 + side 2 ^2 = hypotenuse ^ 2
18^2 + 20^2 = hypotenuse^2
324 + 400 = 724
hypotenuse^2 = 724
hypotenuse = 26.9072480941474
hypotenuse = 26.9
Step-by-step explanation:
hich is equivalent to RootIndex 5 StartRoot 1,215 EndRoot Superscript x?
243x
1,215 Superscript one-fifth x
1,215 Superscript StartFraction 1 Over 5 x EndFraction
243 Superscript StartFraction 1 Over x EndFraction
The given expression is equivalent to \($(1215)^{x/5}\).
What is a expression? What is a mathematical equation? What is Equation Modelling?A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
We have the following equation -
\($(\sqrt[5]{1215})^{x}\)
For \($\sqrt[a]{x} = x^{1/a}\)
Using the rule, we can write -
\($(\sqrt[5]{1215})^{x}\) = \($(1215)^{x/5}\)
Therefore, the given expression is equivalent to \($(1215)^{x/5}\).
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help me, please!!!!!!!
9514 1404 393
Answer:
2
Step-by-step explanation:
Alex has 10 money units. Annie has 5 money units. The ratio of amounts is ...
Alex : Annie = 10 : 5 = 2 : 1
Alex has 2 times as much money as Annie.
Please help me w this hehehehehh
Answer:
-25x-45y, because if we have got + and -, so we will write minus.
which two numbers have a sum of 11 and product of 28?
This one is really hard I have been stuck for about 3 hours. PLEASE HELP
Given,
The expression is,
\(\sqrt{y}+6xy=5\)Required
The double differentiation of the given function.
Differentiating the expression with respect to x then,
\(\begin{gathered} \frac{d}{dx}\sqrt{y}+6xy=\frac{d}{dx}5 \\ \frac{1}{2\sqrt{y}}\frac{dy}{dx}+6x\frac{dy}{dx}+6y=0 \\ \frac{dy}{dx}(\frac{1}{2\sqrt{y}}+6x)+6y=0 \end{gathered}\)Differentiating the function again with respect to x then,
\(\begin{gathered} \frac{d}{dx}(\frac{dy}{dx}(\frac{1}{2\sqrt{y}}+6x)+\frac{d}{dx}6y=0 \\ \frac{d}{dx}(\frac{1}{2\sqrt{y}}\frac{dy}{dx}+6x\frac{dy}{dx})+\frac{d}{dx}6y=0 \\ \frac{1}{2\sqrt{y}}\frac{d^2y}{dx^2}-(\frac{dy}{dx})^2\frac{1}{4y\sqrt{y}}+6x\frac{d^2y}{dx^2}+6\frac{dy}{dx}+6\frac{dy}{dx}=0 \\ \frac{d^2y}{dx^2}(\frac{1}{2\sqrt{y}}+6x)=\frac{1}{4y\sqrt{y}}(\frac{dy}{dx})^2-12\frac{dy}{dx} \end{gathered}\)Substituting the value of dy/dx then,
\(\begin{gathered} \frac{d}{dx}(\frac{dy}{dx}(\frac{1}{2\sqrt{y}}+6x)+\frac{d}{dx}6y=0 \\ \frac{d}{dx}(\frac{1}{2\sqrt{y}}\frac{dy}{dx}+6x\frac{dy}{dx})+\frac{d}{dx}6y=0 \\ \frac{1}{2\sqrt{y}}\frac{d^2y}{dx^2}-(\frac{dy}{dx})^2\frac{1}{4y\sqrt{y}}+6x\frac{d^2y}{dx^2}+6\frac{dy}{dx}+6\frac{dy}{dx}=0 \\ \frac{d^2y}{dx^2}(\frac{1}{2\sqrt{y}}+6x)=\frac{1}{4y\sqrt{y}}(\frac{dy}{dx})^2-12\frac{dy}{dx} \end{gathered}\)Mr Malone purchase five packages of notebooks for his class to use each packages contains six notebooks how many notebooks does Mr Malone purchase in total
Answer:
30
Step-by-step explanation:
5x6=30
Draw an array to find 21÷3
Answer:
21÷3 =9
3×9=21
Therefore the answer is 9 .
Step-by-step explanation:
Hope it works out!SOMEONE ANSWER THIS PLSSSS
Jack jogs and rides his bike for a total of 75 minutes every day. He rides his bike for 15 minutes longer than he jogs.
Part A: Write a pair of linear equations to show the relationship between the number of minutes Jack jogs (x) and the number of minutes he rides his bike (y) every day. (5 points)
Part B: How much time does Jack spend jogging every day? Show your work. (3 points)
Part C: Is it possible for Jack to have spent 60 minutes riding his bike if he jogs and rides for a total of exactly 75 minutes and rides his bike for 15 minutes longer than he jogs? Explain your reasoning. (2 points)
Answer:
here's the answer to your question
Answer:
for B : he spend 30 minutes jogging and 45 minutes riding his bike
Step-by-step explanation:
75-15=60
60/2=30
jogging (x) =30
30+15=45
riding bike (y) =45
hopefully it help you
Using the standard normal distribution tables, the area under the standard normal curve corresponding to z> -1.62 is
Using the standard normal distribution table, the area under the curve is 0.949 squared units
What is the area under the normal curveThe area under the standard normal curve corresponding to z > -1.62 can be found using a standard normal distribution table. The table gives us the proportion of the area under the standard normal curve that is to the left of a certain z-value. To find the area to the right of -1.62, we subtract the area to the left of -1.62 from 1.
From the standard normal distribution table, the area to the left of -1.62 is approximately 0.051. Therefore, the area to the right of -1.62 is 1 - 0.051 = 0.949.
So, the area under the standard normal curve corresponding to z > -1.62 is approximately 0.949.
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Example 1: Every Number Has an Opposite
Locate the number 8 and its opposite on the number line. Explain how they are related to zero.
-8-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
Exercises 2-3
2. Locate and label the opposites of the numbers on the number line.
9
-2
4
a.
b.
C.
8
Answer:
To locate the number 8 and its opposite on the number line, we can use the given number line:
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
Number 8 is located to the right of zero. Its opposite can be found by moving an equal distance to the left of zero. Since the number line is symmetric about zero, the opposite of 8 would be -8.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑ ↑
So, the opposite of 8 is -8. They are related to zero as equal distances on opposite sides of zero on the number line.
Now, let's address exercises 2-3:
a. To locate the opposite of 9, we need to move an equal distance to the left of zero. The opposite of 9 is -9.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
b. To locate the opposite of -2, we need to move an equal distance to the right of zero. The opposite of -2 is 2.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
c. To locate the opposite of 4, we need to move an equal distance to the left of zero. The opposite of 4 is -4.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
So, the opposites of the given numbers are:
9 → -9
-2 → 2
4 → -4
They are related to zero as equal distances on opposite sides of zero on the number line.
Step-by-step explanation:
10 points!!! ASAP PLEASE HELP FIND THE AREA AND THE PERIMETER!!
Answer:
Area = 559.17 square feet
Perimeter = 94.26 ft
Step-by-step explanation:
Make sure all the units are the same and consistent.
r = radius of semi-circle
= \(\frac{Diameter}{2}\)
= \(\frac{18}{2}\) ft
= 9 ft
Area of composite figure = Area of rectangle + Area of semi-circle:
= [Length × Breadth] + [\(\frac{1}{2}\) × (Area of circle)]
= [24 ft × 18 ft] + [\(\frac{1}{2}\) × (\(\pi r^{2}\))]
= 432 \(ft^{2}\) + [\(\frac{1}{2}\) × (\(\pi 9^{2}\))] \(ft^{2}\)
= 432 + [\(\frac{1}{2}\) × (3.14) ×(81)]
= 559.17\(ft^{2}\)
Perimeter of composite figure =
Circumference of semi-circle + 3 outer sides of rectangle:
= [\(\frac{1}{2}\) × \(2\pi r\)] + [24 + 18 + 24]
= ( \(\pi r\) + 66) ft
= [(3.14)(9) + 66] ft
= 94.26 ft
Two people are planning their wedding. For the reception, they found the the cost C for 50 guests, g is $2150 whereas the cost for 75 guests is $3025. Calculate the slope to find the cost per guest?
The slope which shows the cost per guest is $35 per guest
The given cost for 50 guests is $2150.
The cost for 75 guests is $3025.
It can also be represented as:
(Guest, Cost) =(50, $2150) & (75, $3025)
The slope can now be calculated as
Slope = (y₂ - y₁)/(x₂ - x₁)
Where
(x, y) = (50, $2150) & (75, $3025)
Substituting the given values in the equation as follows:
Slope = (3025 - 2150)/(75 - 50)
Slope = 35
Hence, the slope is $35 per guest.
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a) Work out the percentage population increase from 2001 to 2011.
Give your answer to 1 decimal place.
The percentage population increase from 2001 to 2011 is 50%.
To calculate the percentage population increase from 2001 to 2011, you need the population figures for both years. Let's assume the population in 2001 was 100,000 and in 2011 it was 150,000.
The formula to calculate the percentage increase is:
Percentage Increase = ((New Value - Old Value) / Old Value) * 100
Plugging in the values:
Percentage Increase = ((150,000 - 100,000) / 100,000) * 100 = (50,000 / 100,000) * 100 = 0.5 * 100 = 50%
Therefore, the percentage population increase from 2001 to 2011 is 50%.
Please note that the actual population figures for the respective years need to be used in the calculation to obtain an accurate result. The example above is for illustrative purposes.
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Select the best answer for the question.
4. Reduce the fraction 3648 to its lowest terms.
A. 114
OB. %
OC.34
D. 112/48
The option that represents the lowest terms of the given fraction would be = 3/4. That is option C.
What is a fraction?A fraction is defined as the mathematical expression that shows the parts of a whole quantity.
When the lowest term of a fraction is to be determined, the fraction is being divided in such a way that there won't be a reminder.
The given fraction; = 36/48 =36÷12/48÷12 = 3/4
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Complete question:
Select the best answer for the question.
4. Reduce the fraction 36/48 to its lowest terms.
A. 1/14
OB. %
OC.3/4
D. 112/48
For the triangles described, which of the following statements must be true? In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. In triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°. (1 point) ∠Q≅∠F ∠R≅∠F DE¯¯¯¯¯¯¯¯≅PQ¯¯¯¯¯¯¯¯ ∠E≅∠Q
Answer:
∠Q≅∠F
Step-by-step explanation:
Two triangles are said to be congruent if all the three sides of the triangles are equal and all the three angles are equal.
Given that: In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. In triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°.
Hence we can say that ΔDEF is congruent to ΔPQR. According to the side-angle-side (SAS) triangle congruence theorem: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.
Therefore:
DF = PQ, DE = PR, EF = RQ, ∠D = ∠P, ∠E = ∠R and ∠F = ∠Q
Which of the following expressions are meaningful? Which are meaningless? Explain. (a) (a · b) · c (a · b) · c has ---Select--- because it is the dot product of ---Select--- . (b) (a · b)c (a · b)c has ---Select--- because it is a scalar multiple of ---Select--- . (c) |a|(b · c) |a|(b · c) has ---Select--- because it is the product of ---Select--- . (d) a · (b + c) a · (b + c) has ---Select--- because it is the dot product of ---Select--- . (e) a · b + c a · b + c has ---Select--- because it is the sum of ---Select--- . (f) |a| · (b + c) |a| · (b + c) has ---Select--- because it is the dot product of ---Select--- .
Answer:
(a) (a · b) · c has Meaningless because it is the dot product of two scalars.
(b) (a · b)c has Meaningful because it is a scalar multiple of a scalar and a vector .
(c) |a|(b · c) has Meaningful because it is the product of two scalars .
(d) a · (b + c) has Meaningful because it is the dot product of two vectors .
(e) a · b + c has Meaningless because it is the sum of a scalar and a vector.
(f) |a| · (b + c) has Meaningless because it is the dot product of a scalar and a vector .
Can someone solve this
Answer:
m=5
c=-7
Step-by-step explanation:
m is slope
c is the intercept on the y axis
Mark me brainliest pls
60% of the monthly housing and food budget is for rent. 10% of the budget is for utilities. 30% is for food. What is Amy’s budget for rent? What is the budget for utilities? What is it for a food?
a) Amy's monthly budget for Rent based on the total budget for housing and food is $853.
b) Amy's monthly budget for Utilities based on the total budget for housing and food is $142.
c) Amy's monthly budget for Food based on the total budget for housing and food is $427.
The total budget for Housing, Utilities, and Food for nine months = $12,798
Rent = 60%
Utilities = 10%
Food = 30%
Budget period = 9 months
Budget for rent = $7,679 ($12,798 x 60%)
Monthly budget for Rent = $853 ($7,679/9)
Budget for utilities = $1,280 ($12,798 x 10%)
Monthly budget for Utilities = $142 ($1,280/9)
Budget for food = $3,839 ($12,798 x 30%)
Monthly budget for Food = $427 ($3,839/9)
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Joe ran 2 miles in 16 minutes. At this rate how long did it take him to run 5 miles.
Answer:
40min
Step-by-step explanation:
Since the ratio is 2:16, we want simplify. both 2 and 16 are dividable by 2.
2 / 2 = 1
16 / 2 = 8.
Now we can use the ratio 1 mile per 8 min. We want the rate of how many min to miles, so we'd multiply 5 by 8 which equals 40.
Therefore it takes him 40min to run 5 miles.
Hope this helps!
Write a system of equations to describe the situation below, solve using any method, and fill in the blanks. Today's cafeteria specials at a high school in Ashland are a deluxe turkey sandwich and a chef salad. During early lunch, the cafeteria sold 14 turkey sandwiches and 61 chef salads, for a total of $150. During the late lunch, 14 turkey sandwiches and 25 chef salads were sold, for a total of $78. How much does each item cost? A turkey sandwich costs $ , and a chef salad costs $ .
Answer:
Equation 1: 14t + 61s = 150
Equation 2: 14t + 25s = 78
Use Elimination (x)
(-1) (14t + 25s) = (78) (-1)
-14t - 25s = -78
14t + 61s = 150
+ -14t - 25s = -78
--------------------------
36s = 72
s = 2
Salad costs $2
Then find t
14t + 61(2) = 150
14t + 122 = 150
14t = 28
t = 2
Sandwich costs $2
It is assumed that the test results for a class follow a normal distribution with a mean of 78 and a standard deviation of 36. If you know that a student's grade is greater than 72, what is the probability that it is greater than 84
Answer: 0.4337
Step-by-step explanation:
Let X represents the test results for a class that follow a normal distribution .
Given: Mean \(\mu=78\), Standard deviation \(\sigma=36\)
Then, the probability that it is greater than 84 will be
\(P(X>84)=P(\dfrac{X-\mu}{\sigma}>\dfrac{84-78}{36})\\\\=P(Z>0.167)\ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.167)\\\\=1-0.5663=0.4337\ [\text{By p-value table}]\)
Hence, the required probability = 0.4337
Solve the inequality. m/-5 < or = 4
Answer:
M < or = -20
Step-by-step explanation:
Brainlist please
help meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Answer:
600
Step-by-step explanation:
\(R(1)=400 \\ \\ R(2)=1000 \\ \\ R(2)-R(1)=600\)
What is the value of a?
A. 5 units
B. 5 1/3 units
C. 6 2/3 units
D. 7 units
what is 0.068 as a mixed number
Answer:
17/250Step-by-step explanation:
Two parallel lines are crossed by a transversal.
What is the value of d?
The value of d in the image that shows the two parallel lines that are crossed by the transversal is determined as: 125°.
What is a Transversal?In geometry, a transversal is a line that intersects two or more other lines at distinct points. When a transversal intersects a pair of parallel lines, it creates various angles and relationships between those angles.
The image attached below shows the two parallel lines which are crossed by the transversal, where angle d and 125° are vertical angles.
Since they are vertical angles, they will be equal or congruent to each other. Therefore, the value of d = 125°
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Solve the following equation, explaining what you did in each step of your solution. After solving the equation, show the steps to check your solution. 3x + 2(4 + 6x) = 113
The solution to 3x + 2(4 + 6x) = 113 is x=7
3x + 2(4 + 6x) = 113
We will multiply the 2 with the brackets
3x+8+12x=13
adding the coefficients os x together
15x+8=113
adding -8 on both the sides
15x=105
dividing both the sides by 15
x=105/15
after division we get
x=7
To check our solution
we first put value of x in our original equation
3x7 + 2(4 + 6x7) = 113
we simplify the equation
21+2(4+42)=113
According to BODMAS we first solve the bracket
21+2(46)=113
now we solve the multiplication part
21+92=113
solving this
113=113
∴ LHS=RHS
Hence the solution is correct.
Therefore, the solution to 3x + 2(4 + 6x) = 113 is x=7
BODMAS is an acronym used to remember the order of precedence for operations. It stands for Brackets of Order(exponents) Division, multiplication, Addition, Subtraction
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Red beads come in packages of 10. Blue beads come in packages of 12. Lee wants to buy an equal number of red and blue beads. He thinks he has to buy 10 packages of blue beads and 12 packages of red beads to have the least equal number of each. Is lee correct?
(Needs answer asap)