The two primary absorption bands are connected to changes in the energy levels of electrons. In comparison to the band in the region corresponding to longer wavelengths, the band in the shorter wavelength region has a lower absorption.
What is Beta-carotene?Plants have a pigment called beta-carotene that gives them colour. The Latin term for carrot is source of the name beta-carotene. Fruits and vegetables that are yellow or orange derive vibrant colors from it. Additionally, the foods like margarine are colored with beta-carotene.
Beta-carotene transforms into vitamin A in the body (retinol). For clear eyesight and healthy eyes, a robust immune system, and healthy skin and mucous membranes, we require vitamin A. Vitamin A in large levels can be poisonous, but your body only makes as much of the vitamin from beta-carotene as is required. In light of this, beta-carotene is regarded as a secure source of vitamin A.
For smokers, meanwhile, consuming too much beta-carotene can be harmful. It is safe to consume large doses of vitamin A or beta-carotene through food rather than supplements.
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In a particular crash test, an automobile of mass 1245 kg collides with a wall and bounces back off the wall. The x components of the initial and final speeds of the automobile are 18 m/s and 2.9 m/s, respectively. If the collision lasts for 0.11 s, find the magnitude of the impulse due to the collision. Answer in units of kg · m/s. Answer in units of kg · m/s.
Answer:
Δp=-18799.5kg*m/s
Explanation:
Δv=Vf-Vi
Δv=2.9m/s-18m/s
Δv=-15.1m/s
m*Δv=Δp
1245kg*(-15.1m/s)=Δp
Δp=-18799.5kg*m/s
Extra:
Deriving mΔv=Δp
Δp=Pf-Pi
Δp=m*Vf-m*Vi
Δp=m(Vf-Vi)
Vf-Vi=Δv
Δp=m(Δv) or Δp=mΔv
16. If you walk 3 kilometers in 30 minutes, what is your average speed in kilometers per hour?
Answer:
As = 6[km/hr]
Explanation:
First we must convert the units from minutes to hours.
\(30[min]*[\frac{1hr}{60min} ]=0.5[hr]\)
Now the average velocity is defined as the relationship between space and time.
\(As=3/0.5\\As=6[km/hr]\)
A 0.032 g plastic bead hangs from a lightweight thread. Another bead is fixed in position beneath the point where the thread is tied. If both beads have charge q, the moveable bead swings out to the position shown in (Figure 1).
The magnitude of the charge of the given moveable beads is 9.33 nC.
What is the tension in the string?
The tension in the string is calculated as follows;
Tcos45 = mg
where;
T is the tensionm is the massF = Tsin45
\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)
Magnitude of the charge\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)
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A 15 year old boy requires eyeglasses with lenses of 2 diopters power in order to read a book at 25 cm. Five years later he finds that while wearing the same glasses, he must hold a book 40 cm from his eyes. What power of lenses does he require at 20 years in order to read a book at 25 cm?
At 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
How to solve for the power of lenses1/f1 = 1/v - 1/u1
1/f1 = 1/∞ - 1/0.25 (converting 25 cm to meters)
1/f1 = 0 - 4
1/f1 = -4
f1 = -1/4
f1 = -0.25 meters
The initial lens power (P1) is the reciprocal of the focal length:
P1 = 1/f1
P1 = 1/-0.25
P1 = -4 diopters
Now let's calculate the final focal length (f2) using the final distance (v2) of 40 cm:
1/f2 = 1/v2 - 1/u1
1/f2 = 1/0.40 - 1/0.25
1/f2 = 2.5 - 4
1/f2 = -1.5
f2 = -1/1.5
f2 = -0.67 meters
The final lens power (P2) is the reciprocal of the focal length:
P2 = 1/f2
P2 = 1/-0.67
P2 ≈ -1.49 diopters
Therefore, at 20 years old, the boy would require eyeglasses with lenses of approximately -1.49 diopters power in order to read a book at 25 cm.
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A uniformly charged insulating sphere with radius r and charge +Q
lies at the center of a thin-walled hollow cylinder with radius R>r
and length L>2r. The cylinder is non-conducting and carries no net charge.
1:Determine the outward electric flux through the rounded "side" of the cylinder, excluding the circular end caps. (Hint: Choose a cylindrical coordinate system with the axis of the cylinder as its z -axis and the center of the charged sphere as its origin. Note that an area element on the cylinder has magnitude dA=2πRdz
2:Determine the electric flux upward through the circular cap at the top of the cylinder.
3:Determine the electric flux downward through the circular cap at the bottom of the cylinder.
4:Add the results from parts A - C to determine the outward electric flux through the closed cylinder.
5:What result is expected according to Gauss's law?
Note:Express your answers in terms of electric constant ϵ0
and some or all of the variables r, R , L , Q .
According to Gauss' equation, the total flux of an electric field in a confined surface is directly proportional to the charge enclosed.
State Gauss’s law.1)To determine the outward electric flux through the rounded "side" of the cylinder, we can use Gauss's law. We choose a cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The electric field due to the sphere is spherically symmetric, so the electric field lines are parallel to the cylinder's axis and perpendicular to its sides.
E = (1/4πϵ0) (Q/r^2)
where r is the distance from the origin (center of the sphere) to the point on the Gaussian surface.
The area element of the Gaussian surface is dA = 2πRdz, where dz is an element of length along the cylinder's axis. The electric flux through the top and bottom surfaces of the Gaussian surface is then given by:
Φ = ∫E⋅dA = E ∫dA = E(2πR)L
Substituting the expression for the electric field, we have:
Φ = (Q/2ϵ0r^2)(2πRL)
Therefore, the outward electric flux through the rounded "side" of the cylinder is:
Φ = (Q/ϵ0)(R/Lr^2)
2)To determine the electric flux upward through the circular cap at the top of the cylinder, we use a flat Gaussian surface with radius R and height r, centered at the top of the cylinder. The electric field due to the charged sphere is perpendicular to the Gaussian surface, so the electric flux through the top cap is simply the flux through the flat Gaussian surface. The electric field at any point on the Gaussian surface is given by Coulomb's law as:
E = (1/4πϵ0) (Q/R^2)
The area element of the Gaussian surface is dA = πR^2, so the electric flux through the top cap is given by:
Φ = ∫E⋅dA = E ∫dA = EπR^2
Substituting the expression for the electric field, we have:
Φ = (Q/ϵ0)(R/r^2)
3)To determine the electric flux downward through the circular cap at the bottom of the cylinder, we use a similar flat Gaussian surface with radius R and height r, centered at the bottom of the cylinder. The electric flux through the bottom cap is also given by:
Φ = (Q/ϵ0)(R/r^2)
4)Adding the results from parts 1-3, we have the total outward electric flux through the closed cylinder as:
Φ_total = Φ_side + Φ_top + Φ_bottom
= (Q/ϵ0)(R/Lr^2) + 2(Q/ϵ0)(R/r^2)
Simplifying this expression, we have:
Φ_total = (Q/ϵ0) [(2R/r^2) + (R/Lr^2)]
5)According to Gauss's law, the total outward electric flux through a closed surface is proportional to the total charge enclosed within that surface. In this case, the closed surface is the cylindrical Gaussian surface with radius r and length L, centered at the origin (where the charged sphere is located). The charge enclosed within this surface is simply the charge of the sphere, which is +Q. Therefore, we expect the total outward electric flux through the closed cylinder to be:
Φ_total = Q/
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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A truck slows from a velocity of 34 m/s to a stop in 50 m. What was the
truck's acceleration? *
The acceleration/deceleration of the truck is 11.56 m/s^2
Velocity and acceleration Velocity is the rate of change of displacement of a body.Velocity = change in displacement/ time
Acceleration is the rate of change of velocity with time.Acceleration = change in velocity/ time.
The acceleration, velocity and distance travelled of a body is related by the equation below:
v^2 = u^2 + 2aswhere v is the initial velocity
u is the final velocity
a is the acceleration, and
s is the distance travelled
From the data provided:
v = 0
u = 34 m/s
s = 50 m
a = ?
making a subject of the formula
a = -u^2/2s
a = - 34^2 / 2 × 50
a = -11.56 m/s^2
Therefore, the acceleration/deceleration of the truck is 11.56 m/s^2
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Given the displacement vector
D = (5î − 8ĵ) m,
find the displacement vector (in m)
R
so that
D + R = −7Dĵ.
(Express your answer in vector form.)
wow this is rlly hard Idrk but good luck
a)Find the liner momentum of a runner of mass 65kg running with velocity of 6 m/s b)Find the liner momentum of a lorry of mass 8 tonnes moving with velocity of 81 km/h
The linear momentum is given by the product of the mass and the velocity.
a)
Calculating the momentum with a mass of 65 kg and a velocity of 6 m/s, we have:
\(\begin{gathered} p=65\cdot6\\ \\ p=390\text{ kg*m/s} \end{gathered}\)b)
First, let's convert the mass to kg and the velocity to m/s:
\(\begin{gathered} 8\text{ ton}=8\cdot1000\text{ kg}=8000\text{ kg}\\ \\ 81\text{ km/h}=\frac{81}{3.6}\text{ m/s}=22.5\text{ m/s} \end{gathered}\)Now, calculating the momentum, we have:
\(\begin{gathered} p=8000\cdot22.5\\ \\ p=180000\text{ kg*m/s} \end{gathered}\)Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
Larry the Rock was lonely for multiple years. The inertia that Larry possessed intimated those who walked past by it, therefore people never moved Larry.
Larry constantly watched people and cars accelerate past him but sadly he has never had the opportunity to experience acceleration.
But one day, David decides to let Larry experience acceleration and tried to push him. His friend Pancho heard about this and decided to help out. But
because Pancho was not listening in Physics class, he was pushing Larry from the opposite side of David with an equal amount of force and Larry was sad
he still did not get to move.
What type of Equilibrium is Larry going through?
O Static Equilibrium
O Kinetic Equilibrium
O Dynamic Equilibrium
O Geo Equilibrium
O Francesca Equilibrium
First option is correct.Larry the Rock is going through Static Equilibrium.
In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.
Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.
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A prototype electric car is powered by a 400 V battery pack. What is the resistance of the motor circuit when 2.8 x 105 C passes through the circuit in 1.00 h?
Answer:
Resistance = 5.14 Ohms
Explanation:
Given the following data;
Quantity of charge, Q = 2.8*10^5C
Time = 1hour to seconds = 60*60 = 3600 seconds
Voltage = 400V
First of all, we would find the current flowing through
Q = it
2.8*10^5 = I*3600
Current, I = 280000/3600
Current, I = 77.78 Amps
To find the resistance;
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
Voltage = current * resistance
Resistance = voltage/current
Resistance = 400/77.78
Resistance = 5.14 Ohms
The tension in a string from which a 7 kg
object is suspended in an elevator is equal to
74 N.
A) What is magnitude of the acceleration a of
the elevator? The acceleration of gravity is
9.8 m/s^2. Answer in units of m/s^2
B) What is its direction?
Answer:
0.77 m/s^2
Explanation:
Notice that the weight of the 7 kg mass is calculated via:
weight = m * g = 7 * 9.8 N = 68.6 N
Since the tension in the string is larger (74 N), then the elevator is moving upward and the net force on the object is equal to:
74 N - 68.6 N = 5.4 N
Which tells us that the acceleration of the object is:
F = m * a
5.4 N = 7 kg * a
a = 5.4 /7 m/s^2
a = 0.77 m/s^2
and this must be the same as the acceleration of the elevator since object and elevator are moving together.
electrical force is much weaker than the force of gravity true or false.
Answer:
false
Explanation:
The electrical force is much weaker than the force of gravity. False. Thomas Edison argued that our electrical system should use direct current because he felt that alternating current was dangerous.
Answer:
False
Explanation:
electrical force is billions and trillions and trillions times stronger than gravity. Gravity is a weak force compared to electrical force.
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Look at the picture below and identify the atmospheric pressure found within the valley:
please help it is due in 10 min
You drive 200 miles in 3 hours before stopping
for 30 minutes for lunch and gas. After lunch,
you travel 150 miles in an hour and a half. What
was your average speed for the trip?
Answer 55.5mph
explanation
In the figure, an object of mass m moves a distance of 8.0 m on a rough horizontal surface. During this motion the speed changes from 9.0 m/s to 2.0 m/s. What is the coefficient of kinetic friction between the object and the rough surface? m |____ |_____________________
←--------- 8.0 m -------→
a) The angular velocity of the turntable after 0.200 s is 0.430 rev/s. b) the turntable has spun through 0.0088 revolutions in this time interval. c) the tangential speed of a point on the rim of the turntable at t = 0.002 s is 0.094 m/s.
The coefficient of kinetic friction between the object and the rough surface is 0.083. We can use the work-energy principle to solve this problem. According to the principle, the work done by all forces acting on an object is equal to the change in its kinetic energy.
The work done by the force of friction is given by W_friction = -f_k * d, where f_k is the force of kinetic friction and d is the distance traveled. The change in kinetic energy of the object is given by ΔK = K_f - K_i = (1/2) * m * v_\(f^2\) - (1/2) * m * v_\(i^2.\)
Since the object is moving on a horizontal surface, the work done by gravity is zero. Therefore, we have W_friction = ΔK.
Substituting the given values, we get:
-f_k * d = (1/2) * m * v_f^2 - (1/2) * m * v_\(i^2\)
-f_k * 8.0 m = (1/2) * m * (2.0 \(m/s)^2\) - (1/2) * m * (9.0\(m/s)^2\)
Simplifying and solving for f_k, we get:
f_k = (m/8.0 m) * [(1/2) * (2.0 \(m/s)^2\)- (1/2) * (9.0 \(m/s)^2\)]
f_k = 0.813 \(m/s^2\)
The coefficient of kinetic friction is given by μ_k = f_k / N, where N is the normal force. Since the object is moving horizontally, the normal force is equal to the weight of the object, which is N = m * g, where g is the acceleration due to gravity.
Substituting the value of f_k and N, we get:
μ_k = f_k / N = 0.813 \(m/s^2\) / (m * g)
The value of g is approximately 9.8 \(m/s^2\). Therefore, the coefficient of kinetic friction is:
μ_k = 0.083
Therefore, the coefficient of kinetic friction between the object and the rough surface is 0.083.
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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification
The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.
Given:
Object height (h) = 5 cm
Focal length of the convex lens (f) = 10 cm
Object distance (u) = 15 cm (positive since it's on the same side as the incident light)
To determine the nature, position, and size of the image, we can use the lens formula:
1/f = 1/v - 1/u
Substituting the given values:
1/10 = 1/v - 1/15
To simplify the equation, we find the common denominator:
3v - 2v = 2v/3
Simplifying further:
v = 30 cm
The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.
To find the magnification (M), we use the formula:
M = -v/u
Substituting the values:
M = -30 / 15 = -2
The magnification is -2, indicating that the image is inverted and twice the size of the object.
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10. A plane is flying through very dense clouds with no visibility. The pilot's
instruments tell her that she is flying at a heading of 54 knots West by
103 knots South. What is the pilot's total velocity?
The pilot's total velocity is 116.3 knots in the direction of 62.3⁰.
What is the pilot's total velocity?The pilot's total velocity is calculated by applying the principle of relative velocity.
The total velocity is also the resultant velocity and the magnitude of the pilot's total velocity is calculated by applying Pythagoras theorem as follows;
R = √ (V₁² + V₂²)
R = √ (54² + 103²)
R = 116.3 knots
The direction of the velocity vector is calculated as follows;
tan θ = (103 knots) / (54 knots)
θ = tan⁻¹ (103/54)
θ = 62.3⁰
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Jamaal has done an experiment using a mirror to
investigate how light is reflected.
He measures the angle of incidence and the
angle of reflection. Here are his results plotted
on a graph.
a. Which result or results should be repeated?
b. Why?
C. Where should Jamaal draw a line of best fit?
a. The results should be repeated is 40.
b. because because it's not accurate.
c. Jamaal draw a line of best fit at the middle of the reflection angel and incidence angle.
With an example, what is the angle of incidence?The angle created when a sunlight ray strikes a line that is perpendicular to a surface; for instance, a surface facing the sun directly has an angle of incidence of 0, while a surface parallel to the sun (such as sunlight striking a horizontal rooftop) has an angle of incidence of 90°.
The light ray that reflects off the surface is referred to as the reflected ray, and the angle at which the reflected ray reflects off the surface is referred to as the reflection angle. The law of reflection states that the angle of incidence and angle of reflection are equal.
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If I am driving down the highway going north at 50 miles per hour, and another car is driving south at 75 miles per hour. How fast is the car coming toward me?
Its an exam >.
I WILL GIVE BRAINLIEST
You can test the flexibility in the backs of your legs, hips, and lower back with the “sit-and-reach” activity.
true or false
I NEED ANSWER TODAY RN!!!
The diagram shows a car moving along a road.
The force due to the engine is 1500 N and the total drag force is 200 N.
drag force
200N
engine force
1500N
What is the motion of the car?
A constant speed
B decreasing speed
Cincreasing speed
D reversing
Answer:
Increasing speed
Explanation:
Let's check net force
\(\\ \sf\longmapsto F_{net}=1500N-200N\)
\(\\ \sf\longmapsto F_{net}=1300N\)
It is greater than 200NSo car is increasing its speed.
The motion of the car is increasing speed constantly. Thus, the correct option is C.
What is Motion?Motion of an object is a change in the position as compared to a place or an object which is not moving. The place or object which is not moving is called the frame of reference of the object. Motion of an object is a kind of puzzle because of every object in the universe is in motion.
The net force due to the engine is 1500N and the total drag force is 200N.
Net Force = Difference in the forces
Net Force = 1500N - 200N
Net Force = 1300N
The force due to engine is greater than 200N (total drag force). So, the car is in motion with increasing speed.
Therefore, the correct option is C.
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Which factor affects the amount of runoff that occurs in an area?
land use
the water table
the saturation zone
amount of nutrients in soil
Answer:
A. land use
Explanation:
Answer:
a
Explanation:
HELPPPP
i need this done quickly
Answer:
F(Net) = F(a) + F(g) + F(f) + FN.
Why do people do drugs?
People use drugs for many reasons: they want to feel good, stop feeling bad, or perform better in school or at work, or they are curious because others are doing it and they want to fit in. The last reason is very common among teens.Drugs excite the parts of the brain that make you feel good. But after you take a drug for a while, the feel-good parts of your brain get used to it. Then you need to take more of the drug to get the same good feeling. Soon, your brain and body must have the drug just to feel normal. You feel sick, awful, anxious, and irritable without the drug. You no longer have the good feelings that you had when you first used the drug. This is true if you use illegal drugs or if you misuse prescription drugs. Misuse includes taking a drug differently than how your doctor tells you to (taking more or crushing pills to "shoot up" or snort), taking someone else’s prescription, or taking it just to get “high.”
How does the orientation of the bar magnet affect the measured magnetic field strength?
When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.
The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.
The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.
When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet, the magnetic field strength gets affected.
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47. A man stands on a merry-go-round that is rotating at 2.5 rad/s. If the coefficient of static friction between the man’s shoes and the merry-go-round is , how far from the axis of rotation can he stand without sliding?
Without falling off the merry-go-round, the guy can stand up to a distance of roughly 1.42 m from the axis of rotation.
What is the rotational moment formula?This equation demonstrates how the square of the angular velocity and the moment of inertia are inversely related to the kinetic energy of a spinning rigid body.
The sources of the centrifugal force are:
F = m r ω²
The formula for static friction's force is
F_friction = μ_s N
The weight of a man is equal to the normal force N, which is determined by:
N = m g
The centrifugal force equals the static friction force at the point where the man is about to slide, hence we have:
F = F_friction
m r ω² = μ_s N
Substituting N = m g, we get:
r = (μ_s g) / ω²
Substituting μ_s = 0.35, g = 9.81 m/s², and ω = 2.5 rad/s, we get:
r = (0.35 x 9.81 m/s²) / (2.5 rad/s)² ≈ 1.42 m
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5.40×10^21 electrons flow through another appliance in 3.0 minutes.
What is the current drawn by this appliance?
The current drawn by the appliance is 0.048 A.
The problem provides the number of electrons that flow through an appliance and the time it takes for the flow to occur. To find the current drawn by the appliance, we need to use the equation:
current = charge / time
The charge is the total number of electrons that flowed through the appliance, which can be calculated by multiplying the given number of electrons by the charge on one electron (\(-1.6 \times 10^{-19}\) Coulombs).
charge = (\(5.40 \times 10^{24}\) electrons) × (\(-1.6 \times 10^{-19}\) C/electron) = -8.64 C
Note that the charge is negative because electrons have a negative charge.
The time is given as 3.0 minutes, but we need to convert it to seconds to match the unit of charge.
time = 3.0 minutes × 60 seconds/minute = 180 seconds
Now, we can plug in the values into the equation:
current = (-8.64 C) / (180 s) = -0.048 A
The current is negative because the charge is negative, which indicates that the current direction is opposite to the conventional current flow direction (i.e., the direction of positive charge flow). To express the current in the conventional direction, we need to take the absolute value:
current = 0.048 A
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For the vectors A
and B
in use a scale drawing to find the magnitude and direction of a. The vector sum A
+ B
b. The vector difference A
− B
c. From your answers to parts (a) and (b), find the magnitude i) − A
− B
ii) B
− A
the magnitude of B - A is also 70 m, and the direction is 180° minus the direction of A - B. Therefore, the direction of B - A is 217°counterclockwise from the positive x-axis.
Steps
(A) By utilizing A and B as adjacent sides of a parallelogram, we can determine A + B. The vector sum A + B is represented by the parallelogram's diagonal. We calculate the length of the diagonal to be about 20 cm using a scale of 1 cm = 5 m.
The magnitude of A plus B is therefore 20 x 5 or 100 m. We can use a protractor to calculate the direction by measuring the angle between A and B. The direction of A + B is 143° counterclockwise from the positive x-axis since the angle is roughly 143°.
(b) By using A and -B as adjacent sides of a parallelogram, we can determine A - B. The vector difference between A and B is represented by the parallelogram's diagonal.
We calculate the diagonal's length to be 14 cm using the same scale as before. The magnitude of A minus B is therefore 14 x 5 = 70 m. By measuring the angle between A and -B, which is 180° less than the angle between A and B, we may determine the direction.
Since A and -B are at a roughly 37° angle, A and B are located 37° in the opposite direction from the positive x-axis.
(c) We've already determined the direction and magnitude of A - B in part (b). With |A - B| = 70 m and a direction of 37° counterclockwise from the positive x-axis, we can conclude that.
(d) To find B - A, we can use the fact that B - A = -(A - B). Therefore, the magnitude of B - A is also 70 m, and the direction is 180° minus the direction of A - B. Therefore, the direction of B - A is 217° counterclockwise from the positive x-axis.
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