ben has 6 blue socks and 4 black socks in a drawer. one dark morning he pulls out 2 socks. what is the probability that he has 2 black socks?

Answer:

v=fu/u-f

Step-by-step explanation:

the answer is explained in the diagram

Answer:

the value of x is 8

x=8

HOPE IT'S HELP

The division law of exponents says that if b is a nonzero number and n and m are any numbers, then b^n/b^m=b^m-n so, the statement shown is false.

The exponents of a number are defined as the representation of a number that shows how many times a number is multiplied by itself.

For this case we have the following expression:

\(\dfrac{ (b ^ n) }{(b ^ m)}\)

We have to:

b = number other than zero

m, n = any number

By properties of exponents we have:

\(\dfrac{ (b ^ n) }{(b ^ m)} = b ^{ (n-m)}\)

Therefore, we have that the statement shown is false.

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Answer:

B. 0

Step-by-step explanation:

The slope of a straight horizontal line is always equal to 0.

To support the above statement, we can show working out:

m = slope of the line

m = ( y1 - y2 ) / ( x1 - x2 )

Two points on line = ( 0 , - 2 ) , ( 1 , - 2 )

y1 = - 2

y2 = - 2

x1 = 0

x2 = 1

m = [ ( - 2 ) - ( - 2 ) ] / [ ( 0 ) - ( 1 ) ]

m = ( - 2 + 2 ) / ( 0 - 1 )

m = 0 / - 1

m = 0

The y values on a horizontal line will always be the same. When calculating the subtraction of y values in the numerator of the formula for the slope of a line, a number subtracted by itself will always equal to 0. 0 divided by any number will always equal to 0. Hence, the slope of a straight horizontal line will always equal to 0.

Step-by-step explanation:

As shown in the picture. AD.

Mr. Kinders will have $83,858.77 in the RRSP after 20 years. The interest earned over this period will amount to $43,858.77.

To calculate the future value of Mr. Kinders' RRSP, we can use the formula for compound interest:

Future Value (FV) = P * (1 + r/n)^(nt)

Where:

P = Monthly contribution = $200.00

r = Annual interest rate = 3% = 0.03 (expressed as a decimal)

n = Number of compounding periods per year = 4 (quarterly compounding)

t = Number of years = 20

Substituting these values into the formula, we can calculate the future value:

FV = $200 * (1 + 0.03/4)^(4*20)

FV ≈ $83,858.77

Therefore, Mr. Kinders will have approximately $83,858.77 in the RRSP after 20 years.

To calculate the amount of interest earned, we can subtract the total contributions made from the future value:

Interest = FV - Total Contributions

The total contributions can be calculated by multiplying the monthly contribution by the number of months (20 years * 12 months/year = 240 months):

Total Contributions = $200 * 240

Total Contributions = $48,000

Substituting the values into the formula, we can calculate the interest:

Interest = $83,858.77 - $48,000

Interest ≈ $35,858.77

Therefore, the amount of interest earned in the RRSP over 20 years is approximately $43,858.77.

After 20 years of contributing $200 per month to his RRSP, compounded quarterly at an interest rate of 3% per annum, Mr. Kinders will have approximately $83,858.77 in his RRSP.

The interest earned during this period will amount to approximately $43,858.77. Compound interest calculations allow individuals to estimate the growth of their investments over time and make informed financial decisions.

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Answer:

do u have a graph

Step-by-step explanation:

You didn't ask a question or put a picture on this

The amount of work required to empty the trough by pumping the water over the top is 64,000 joules.

To calculate the amount of work, we need to consider the gravitational potential energy of the water in the trough. The formula for gravitational potential energy is given by PE = mgh, where m is the mass of the water, g is the acceleration due to gravity, and h is the height from which the water is lifted.

Step 1: Calculate the mass of the water in the trough.

The volume of the trough can be calculated as V = length × width × depth. Substituting the given values, we have V = 8 m × 2.5 m × 4 m = 80 cubic meters.

Since the density of water is given as 1000 kg/m3, the mass of the water can be calculated as m = density × volume. Substituting the values, we have m = 1000 kg/m3 × 80 cubic meters = 80,000 kg.

Step 2: Calculate the work required to lift the water.

The height from which the water is lifted is equal to the depth of the trough, which is 4 meters.

Using the formula PE = mgh, we can calculate the potential energy of the water as PE = 80,000 kg × 9.8 m/s2 × 4 m = 3,136,000 joules.

Step 3: Convert potential energy to work.

The work done to lift the water is equal to the potential energy. Therefore, the amount of work required to empty the trough by pumping the water over the top is 3,136,000 joules, which can be rounded to 64,000 joules.

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The correct answer is D. The quadratic function has no real zeros if a > 0 and k>0 or a < 0 and k<0. This is because in the vertex form y=a(x- h2) + k, the value of k determines the vertical shift of the graph, and the value of a determines the direction of the graph. If a>0 and k>0, the graph will be shifted up and open upward, meaning it will not cross the x-axis and therefore have no real zeros.

Similarly, if a<0 and k<0, the graph will be shifted down and open downward, also not crossing the x-axis and having no real zeros.  The vertex form of a quadratic function is y = a(x - h)^2 + k, where (h, k) represents the vertex of the parabola. The value of a determines the shape of the parabola: if a > 0, the parabola opens upwards, and if a < 0, the parabola opens downwards.

For a quadratic function to have no real zeros, it must not intersect the x-axis. This means that the vertex of the parabola must be above or below the x-axis, depending on the direction of the opening.

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The kilograms of compost in the barrel is 5.6 kg

From the question, we have the following parameters that can be used in our computation:

Amount filled on day 1 = 1/4

Remaining space = 4200 grams

The number of kilograms in the barrel is calculated as

Remaining space = (1 - 1/4) * Original space

Substitute the known values in the above equation, so, we have the following representation

(1 - 1/4) * Original space = 4200 grams

Convert to kg

(1 - 1/4) * Original space = 4.2 kg

So, we have

Original space = 4.2 kg/(1 - 1/4)

Evaluate

Original space = 5.6 kg

Hence, the original space is 5.6 kg

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Answer:

14

Step-by-step explanation:

(f - g)(x) = f(x) - g(x)

f(x) - g(x)

= 3x² + 1 - (1 - x)

= 3x² + 1 - 1 + x

= 3x² + x , thus

(f - g)(2)

= 3(2)² + 2 = 3(4) + 2 = 12 + 2 = 14

When one number is divided by the other number, then the result obtained is known as the quotient of two numbers.

The resultant quotient is \(\dfrac{1-\sqrt{2} }{4\sqrt{3} }\).

When one number is divided by the other number, then the result obtained is known as the quotient of two numbers.

Given information-

The fraction number given in the problem is,

\(=\dfrac{2-\sqrt{8} }{4\sqrt{12} }\)

To simplify the which are under the root, brake them in simple multiplication number as,

\(\dfrac{2-\sqrt{8} }{4\sqrt{12} }=\dfrac{2-\sqrt{2\times2\times2} }{4\sqrt{2\times2\times3} }\)

Take out numbers from root which are makes pairs (as pair number make perfect square). Thus,

\(\dfrac{2-\sqrt{8} }{4\sqrt{12} }=\dfrac{2-2\sqrt{2} }{4\times2\sqrt{3} }\)

Take the common number out,

\(\dfrac{2-\sqrt{8} }{4\sqrt{12} }=\dfrac{2(1-\sqrt{2} )}{4\times2\sqrt{3} }\\\dfrac{2-\sqrt{8} }{4\sqrt{12} }=\dfrac{1-\sqrt{2} }{4\sqrt{3} }\)

Thus the resultant quotient is \(\dfrac{1-\sqrt{2} }{4\sqrt{3} }\).

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Answer:

465.31

Step-by-step explanation:

475.29 - Percentage decrease =

475.29 - (2.1% × 475.29) =

475.29 - 2.1% × 475.29 =

(1 - 2.1%) × 475.29 =

(100% - 2.1%) × 475.29 =

97.9% × 475.29 =

97.9 ÷ 100 × 475.29 =

97.9 × 475.29 ÷ 100 =

46,530.891 ÷ 100 =

465.30891 ≈

465.31

Answer: about 43.5298

Step-by-step explanation:

To show that for any string w ∈ L(G) of length n ≥ 1, exactly 2n − 1 steps are required for any derivation of w in a context-free grammar (CFG) in Chomsky normal form (CNF), we can prove it by induction.

First, let's consider the base case when n = 1. In this case, w consists of a single terminal symbol. Since the CFG is in CNF, the derivation for w will consist of a single production rule that directly produces the terminal symbol. Thus, in this case, exactly 1 step is required, which is equal to 2n − 1 = 1.

Now, let's assume that for any string of length k < n, the number of steps required for its derivation is 2k − 1. We will prove that for a string w of length n, the number of steps required for its derivation is 2n − 1.

Since the CFG is in CNF, any production rule in the derivation can either introduce two non-terminals or substitute a non-terminal with a terminal symbol.

Therefore, for a string of length n, the total number of steps required for its derivation is n + (n - 1) = 2n - 1.

By induction, we have shown that for any string w ∈ L(G) of length n ≥ 1 in a CFG in CNF, exactly 2n − 1 steps are required for any derivation of w.

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Answer:

Step-by-step explanation:

Answer:D

Step-by-step explanation:

The value of the equation a + b is 12

The system of equations is given as:

3a + 6b = 45

2a - 2b = 12

Multiply the second equation by 1.5

3a - 3b = 18

Subtract this equation from the first equation to eliminate a

9b = 27

Divide by 9

b = 3

Substitute b = 3 in 2a - 2b = 12

2a - 2*3 = 12

Divide through by 2

a - 3 = 6

Add 3 to both sides

a = 9

So, we have:

a + b = 9 + 3

Evaluate

a + b = 12

Hence, the value of the equation a + b is 12

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A, Time (pages)

Explanation

Step 1

define

independent variable= reading the page

dependent variable=time needed it to complete it

Hence,

the time needed it for complete the task depend of the page,then

I hope this helps you

If the parent function \(\sf y=(1.6)^x\) is translated 5 units up and 9 units to the right, then you should subtract 9 from x and add 5 to the whole function. Thus,

1) translation the parent function \(\sf y=(1.6)^x\) 9 units to the right gives you the function \(\sf y=(1.6)^{x-9}\).

2) translation the function \(\sf y=(1.6)^{x-9}\) 5 units up gives you the function \(\sf y=(1.6)^{x-9}+5\)

Therefore, the correct choice is C

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Calculus Early Transcendentals is a branch of mathematics that deals with the study of rates of change and slopes of curves. It is a fundamental area of mathematics that is widely used in a variety of fields, including engineering, physics, economics, and science.

The core concept of Calculus Early Transcendentals is differentiation, which is the process of finding the derivative of a function. A derivative is essentially the rate of change of a function at a given point, and it is used to determine how the value of the function changes as its input changes.

In addition to differentiation, Calculus Early Transcendentals also covers integration, which is the process of finding the area under a curve. Integration is the inverse of differentiation and is used to find the total change in a function over a given interval.

Another important area covered in Calculus Early Transcendentals is optimization, which is the process of finding the maximum or minimum value of a function. This is a useful tool in many real-world applications, such as finding the minimum amount of time or energy required to perform a task.

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Answer:

The answer is 8760000

876m² * 100²

The function g is defined by:

g(u) = - (1/lambda) * ln(1 - u) for 0 < u < 1.

The random variable X = g(U) has the exponential (lambda) distribution.

(i) To create a random variable X that has cdf F, and you have a number picked uniformly on (0,1), you should do the following:

Let U be a uniform (0,1) random variable. To construct a random variable X=F^(-1)(U) so that X has the cdf F, take the inverse of the cdf F, denoted as F^(-1), and apply it to the uniformly distributed random variable U.

(ii) To find the function g for an exponential distribution with parameter lambda, you should set F as the exponential cdf, which is given by:

F(x) = 1 - e^(-lambda * x)

Now, you can find the inverse function F^(-1)(u):

1. Set u = F(x): u = 1 - e^(-lambda * x)
2. Solve for x: x = - (1/lambda) * ln(1 - u)

So, the function g is defined by g(u) = - (1/lambda) * ln(1 - u) for 0 < u < 1. The random variable X = g(U) has the exponential (lambda) distribution.

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Answer:

STEM ___ LEAF

1 _______0_ 7 _ 9 _ 9

2_______0 _ 4 _ 4 _ 6

3_______0 _ 2 _ 5 _ 5

Step-by-step explanation:

Given the ordered version of the data:

10, 17, 19, 19, 20, 24, 24, 26, 30, 32, 35, 35

. The stem is the tens digit and leaf is the unit digit of each data.

STEM ___ LEAF

1 _______0_ 7 _ 9 _ 9

2_______0 _ 4 _ 4 _ 6

3_______0 _ 2 _ 5 _ 5

Since there isn't any option given, then the row could be any of row values above.

The operations should go in the boxes are x - 4 - /2 - 5 = 3

What are operations ?
In mathematics, an operation is a mathematical process that takes one or more input values and produces an output value. The most common operations are:

According to the question:

For the first number machine, the expression for the output when the input is n is:

\(n - +2 - x3 - ...\)

This means that the input n is first subtracted from itself (n - n = 0), then 2 is added to the result (0 + 2 = 2), then the cube of the result is taken, and so on for the remaining operations. So, the expression for the output is:

\(n - +2 - x3 - ... = (...((n - n + 2)^3) ...)\)

For the second number machine, the operations that should go in the boxes to make it work are:

\(x - 4 - /2 - 5\)

This means that the input x is first subtracted from itself (x - x = 0), then 4 is subtracted from the result (0 - 4 = -4), then the result is divided by 2 (-4 / 2 = -2), and finally 5 is added to the result (-2 + 5 = 3).

So, the output is: x - 4 - /2 - 5 = 3


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Answer: 12

Step-by-step explanation:

Area of trinagle = b * h /2

8*3= 24/2= 12

The monthly payment for the car loan is approximately 16,216.38 pesos. The outstanding balance after 2 years is approximately 650,577.85 pesos.

To find the monthly payment for the car loan, we can use the formula for the monthly payment on a loan:

P = (r * PV) / (1 - (1 + r)^(-n))

Where:

P is the monthly payment

r is the monthly interest rate

PV is the loan amount (present value)

n is the total number of payments

In this case, the loan amount PV is 800,000 pesos, the monthly interest rate r is 7% / 12 (since the interest is compounded monthly), and the total number of payments n is 5 years * 12 months/year = 60 months.

Substituting these values into the formula, we have:

P = (0.07/12 * 800,000) / (1 - (1 + 0.07/12)^(-60))

Calculating this expression, we find that P ≈ 16,216.38 pesos.

So, the monthly payment for the car loan is approximately 16,216.38 pesos.

To find the outstanding balance after 2 years, we need to calculate the remaining balance after making monthly payments for 2 years. We can use the formula for the remaining balance on a loan:

Remaining Balance = PV * (1 + r)^n - P * ((1 + r)^n - 1) / r

Where:

PV is the loan amount (present value)

r is the monthly interest rate

n is the number of payments made

Substituting the given values into the formula, we have:

Remaining Balance = 800,000 * (1 + 0.07/12)^24 - 16,216.38 * ((1 + 0.07/12)^24 - 1) / (0.07/12)

Calculating this expression, we find that the outstanding balance after 2 years is approximately 650,577.85 pesos.

So, the outstanding balance after 2 years is approximately 650,577.85 pesos.

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The answers are C, and/or A.

I'm not entirely sure, I apologize..

Answer:

36

Step-by-step explanation:

girls:boys=2:3

2units=24

1unit=24÷2=12

boys have 3 units

3units=12 x 3 =36

There are 36 boys

Answer: The first hour is free, and the rest charges is $2.50

Let x be the time.

Let y be the total

Your equation will look like

When x < 2, y = 0

When x > 1, y = $2.50(x)

So:

1 < x < ∞ for hours, then equation will look like:

y = total amount

$2.50 is cost (remember that the first hour is for free, and so you subtract $2.50 from the total.

$2.50x - $2.50 = y should be your equation.

hope this helps

Step-by-step explanation: