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Answer:

The answer is C.

Step-by-step explanation:

The only energy released as a result is equal to two ATP molecules. Organisms can turn glucose into carbon dioxide when oxygen is present. As much as 38 ATP molecules' worth of energy is released as a result.

Why do aerobic processes generate more ATP?

Anaerobic respiration is less effective than aerobic respiration and takes much longer to create ATP. This is so because the chemical processes that produce ATP make excellent use of oxygen as an electron acceptor.

How much ATP is utilized during aerobic exercise?

As a result, only energy equal to two Molecules of ATP is released. When oxygen is present, organisms can convert glucose to carbon dioxide. The outcome is the release of energy equivalent to up of 38 ATP molecules. Therefore, compared to anaerobic respiration, aerobic respiration produces a large amount more energy.

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Answer:

4/3

Step-by-step explanation:

7x + 4 = 10x

4 = 3x

x = 4/3

Answer:

You would add 3x to both sides. Then divide by 10 on both sides.

What to do to isolate the variable term to one side of the equation is to add 3x to both side

Given the equation, -3x + 18 = 7x, we need to isolate the variable term. To do that, we will follow the steps below;

Add 3x to both sides of the equation to have;

-3x + 18 + 3x = 7x + 3x

18 = 7x + 3x

Swap sides

7x + 3x = 18

10x = 18

Divide both sides by 10

10x/10 = 18/10

x = 1.8

From the steps above, what to do to isolate the variable term to one side of the equation is to add 3x to both side

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Scientific notation exists as a method of writing very large or very small numbers. The expression as a number in scientific notation is 6.4 × \($$10^4\).

Utilizing scientific notation, one can express extremely big or extremely small values. When a number between 1 and 10 is multiplied by a power of 10, the result is represented in scientific notation.

To express exceedingly high numbers in a shorter manner, scientists have created a shorthand. Scientific notation is the name of this technique. The foundation of scientific notation is the base-10 powers. The coefficient is defined as the initial number, 1.23.

Given: (8 ×10²) × (3.2 ×\($$10^5\))/4 × 10³

simplifying the above equation, we get

= 800 × 320000/4000

= 64000

= 6.4 × \($$10^4\)

Therefore, the expression as a number in scientific notation is 6.4 × \($$10^4\).

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Answer:

6.4 x 10^4

Step-by-step explanation:

Answer: \(17.68cm\)

Step-by-step explanation:

Using the area formula of a cone, find the height first.

\(A=\pi r(r+\sqrt{h^2+r^2})\)

Solve for h,

Begin by dividing by \(\pi r\)

\(\frac{A}{\pi r}=r+\sqrt{h^2+r^2}\)

Subtract r.

\(\frac{A}{\pi r}-r=\sqrt{h^2+r^2}\)

Square both sides.

\((\frac{A}{\pi r}-r)^2=(\sqrt{h^2+r^2})^2\)

\((\frac{A}{\pi r}-r)^2=h^2+r^2\)

Subtract \(r^2\)

\((\frac{A}{\pi r}-r)^2-r^2=h^2\)

Extract the square root.

\(\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =\sqrt{h^2}\)

\(\sqrt{(\frac{A}{\pi r}-r)^2-r^2 } =h\)

Plug in your values.

\(\sqrt{[\frac{670cm^2}{(3.14)(8cm)}-(8cm)]^2-(8cm)^2 } =h\)

Solve;

\(\sqrt{[\frac{670cm^2}{25.12cm}-(8cm)]^2-(8cm)^2 } =h\)

\(\sqrt{[26.67cm-(8cm)]^2-(8cm)^2 } =h\)

\(\sqrt{(18.67cm)^2-(8cm)^2 } =h\)

\(\sqrt{348.57cm^2-64cm^2}=h\)

\(\sqrt{284.57cm^2}=h\)

\(15.77cm=h\)

------------------------------------------------------------------

Now, to find the slant height use this formula: \(l=\sqrt{h^2+r^2}\)

\(l=\sqrt{(15.77cm)^2+(8cm)^2}\\l=\sqrt{248.69cm^2+64cm^2}\\ l=\sqrt{312.69cm^2}\\ l=17.68cm\)

The linear function that best fits the data is given as follows:

y = 60x.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

When x = 0, y = 0, hence the intercept b of the line is given as follows:

b = 0.

When x increases by 5, y increases by 300, hence the slope m of the line is given as follows:

m = 300/5

m = 60.

Hence the equation is:

y = 60x.

The points on the scatter plot are given as follows:

(0,0) and (5,300).

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The mean and variance of the area A of a circle with a random radius R, uniformly distributed between 0 and 1, can be calculated using mathematical formulas. The mean of A is π/4, and the variance of A is (π^2 - 4)/16.

The area A of a circle is given by the formula A = π * R^2, where R is the radius. Since the radius R is uniformly distributed between 0 and 1, we can express the probability density function (PDF) of R as f(R) = 1 for 0 ≤ R ≤ 1, and f(R) = 0 elsewhere.

To find the mean of A, we need to calculate the expected value of A, denoted as E[A]. Using the formula for expected value, we have E[A] = ∫(A * f(R)) dR = ∫(π * R^2) dR from 0 to 1. Solving this integral gives E[A] = π/4.

To find the variance of A, we need to calculate E[A^2] first. Using the formula for expected value, we have E[A^2] = ∫(A^2 * f(R)) dR = ∫(π^2 * R^4) dR from 0 to 1. Solving this integral gives E[A^2] = π^2/5.

The variance of A can be calculated as Var[A] = E[A^2] - (E[A])^2 = π^2/5 - (π/4)^2 = (π^2 - 4)/16.

Therefore, the mean of A is π/4, and the variance of A is (π^2 - 4)/16 for a circle with a random radius R uniformly distributed between 0 and 1.

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Answer:  slope: 1/4

y-intercept: 0,3

Step-by-step explanation:

To solve for x in the given equation, we need to use the matrix representation of the linear transformation.

Let A be the matrix that represents the linear transformation 2 → 2. Since we know that (1, 2) is mapped to (1 2, 41 52), we can write:

A * (1, 2) = (1 2, 41 52)

Expanding the matrix multiplication, we get:

[ a b ] [ 1 ] = [ 1 ]
[ c d ] [ 2 ]   [ 41 ]
            [ 52 ]

This gives us the following system of equations:

a + 2b = 1
c + 2d = 41
a + 2c = 2
b + 2d = 52

Solving this system of equations, we get:

a = -39/2
b = 40
c = 41/2
d = 5

Now, we can use the matrix A to find the image of (3,8) under the linear transformation:

A * (3,8) = [ -39/2 40 ] [ 3 ] = [ -27 ]
            [ 41/2  5 ] [ 8 ]   [ 206 ]

Therefore, x = (-27, 206).

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The frequencies of the first three allowed modes of vibration are 4.14 Hz, 8.29 Hz, and 12.43 Hz, respectively.

The given problem can be solved using the formula given below; f_n = (n*v)/(2L), where; f_n - frequency v - velocity of the wave L - length of the wire, n - mode number.

Part a: Given; Length of the wire, L = 1.75 m, Mass of the wire, m = 0.100 kg. Tension in the wire, T = 21.0 N`.

To find the frequency of the wire for the first three allowed modes of vibration, we need to calculate the velocity of the wave, v.

We can use the following formula to calculate the velocity of the wave; v = √(T/m), where; T - tension in the wire, m - mass of the wire.

Substituting the given values, v = √(21.0 N / 0.100 kg) = √(210) = 14.5 m/s.

The frequencies of the first three allowed modes of vibration can be found by substituting the values in the given formula.

For n = 1, `f_1 = (1*14.5)/(2*1.75) = 4.14 Hz.

For n = 2,`f_2 = (2*14.5)/(2*1.75) = 8.29 Hz

For n = 3,`f_3 = (3*14.5)/(2*1.75) = 12.43 Hz.

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Answer:

144

Step-by-step explanation:

The equation to find c is:

\((\frac{b}{2} )^{2}\)

So put -24 into b:

\((\frac{-24}{2} )^{2}\)

Which simplifies to:

144

So if you want to test this:

x^2 - 24x + 144

is

(x-12)^2

Answer:

three thirds is one whole

Step-by-step explanation:

The answer is 18 because three thirds is one whole which in this case is 18! Have a nice day!

Answer:

15

Step-by-step explanation:

from the first then it is 0+7=7

and from the last it is 0+8=8

then the number of cars available in the station is 8+7=15

Between 48% and 54% believe that their health is extremely important.

According to the statement

Given that a random sample of 1001 Americans aged 18-24 years showed that 51% believe their health is extremely important.

Here

Sample size n =1001

sample proportion p = 0.51

By these values we calculate the Standard error of proportion.

So, Standard error of proportion = 0.0158.

Since sample size is sufficiently large we can take Z critical value for confidence interval

Z critical value for 95% = 1.96

Margin of error = ±1.96*std error

= ±0.0310

confidence interval = 0.51 ±0.0310

= (0.48, 0.54)

So, Between 48% and 54% believe that their health is extremely important.

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Distance from M to N = 48.24 km

The car speed = 72 km/h

Time spent by the car = t

Time spent for the meeting = 2 hours

Total time spent since the man left town M till when he returns = 1:55pm - 10:00am  =  3 hrs 55 minutes = 3.92 hours

Distance from M to N = Speed of the car  *  Time spent by car

Distance from M to N = 72  x  t

Distance from M to N = 72 t

The man traveled by bus back to town M from town N

If the distance from N to M is 2 km longer than the distance from M to N, it means the car and the bus passed through different routes

Distance from N to M = (Distance from M to N)  +  2..................(*)

Time taken by the bus = (Total time) - (Time taken by car) - (Time spent for the meeting)

Time taken by the bus = 3.92 - t - 2

Time taken by the bus =  1.92 - t

Distance from N to M = Speed of the bus  x Time taken by the bus

Distance from N to M =  40  x  (1.92 - t)...................(**)

Substitute (*) into (**)

(Distance from M to N)  +  2  =  40  x  (1.92 - t)

72t   +   2   =   40(1.92  -  t)

72t  +  2   =   76.8  -  40t

72t  +  40t   =   76.8  -  2

112t     =   74.8

t   =   74.8/112

t   =  0.67 hours

Distance from M to N = 72t

Distance from M to N = 72(0.67)

Distance from M to N = 48.24 km

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Answer:

$35

Step-by-step explanation:

multiply 35 by the number of weeks (6) to get $210, subtract $210 from $250 to get $35

Step-by-step explanation:

well, I see one large rectangle (20×6), and 2 small triangles with their horizontal sides being (20-8-6)/2 = 3 m. and their vertical joined side being 10-6 = 4 m.

the total area is simply the sum of the rectangle and the 2 triangles.

the rectangle is

20×6 = 120 m²

each triangle is

4×3/2 = 2×3 = 6 m²

we have 2 of them, so their combined area is 2×6 = 12 m².

the total area is

120 + 12 = 132 m²

Answer:

f = 5/6 = 0.833  or f = 0

Step-by-step explanation:

Answer:

Step-by-step explanation:

10

The derivative of the function is

A) dw/dz=z^5 (7z-18)

B) dh/dx=192x^11+36x^5-6x^2+19

C) dy/dx=24x^2-38x-15

In mathematics, the derivative of a function measures the sensitivity to change of the function value with respect to a change in its argument. It is the rate of change of a function with respect to a variable.

A) w = z^7 – 3z^6 + 14

dw/dz=7z^6-18z^5

dw/dz=z^5 (7z-18)

B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7

dh/dx=192x^11+36x^5-6x^2+19

C) y = (8x + 5)(x^2 – 3x)

dy/dx=  d/dx  [8x+5]*〖(x〗^2-3x)+(8x+5)*d/dx[x^2-3x]

dy/dx=(8*  d/dx  [x}+d/dx[5])*〖(x〗^2-3x)+(8x+5)*(d/dx[x^2]-3 d/dx[x])

dy/dx=(8*1+0)(x^2-3x)+(8x+5)(2x-3*1)

dy/dx=8(x^2-3x)+(2x-3)(8x+5)

dy/dx=24x^2-38x-15

Note: The question is incomplete. The complete question probably is: Find the derivative of the following function: A) w = z^7 – 3z^6 + 14 B) h(x) = 16x^12 + 6x^6 – 2x^3 + 19x – 7 C) y = (8x + 5)(x^2 – 3x).

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Answer:

-8

Step-by-step explanation:

-21-(-13)

=-21+13

=-8 is the answer......

Answer:

\(-8\)

Step-by-step explanation:

\(-21 - (-13)\)is the same as \(-21+13\), so the answer is \(-8\).

Since the given values for np and nq are not suitable for the normal approximation (np < 5 or nq < 5), we cannot estimate P(fewer than 5) using the normal approximation.

In summary, we can use the normal approximation to estimate P(fewer than 5) when np > 5 and nq > 5.

To estimate P(fewer than 5), we can use the normal approximation to the binomial distribution by considering the mean (μ) and standard deviation (σ) of the binomial distribution. For a binomial distribution with parameters n and p, the mean is given by μ = np and the standard deviation is given by σ = √(npq).

In this case, n = 13 and p = 0.6, so np = 7.8 and nq = 5.2. Since both np and nq are greater than 5, we can proceed with the normal approximation.

To estimate P(fewer than 5), we can use the cumulative distribution function (CDF) of the normal distribution with parameters μ = np and σ = √(npq). We calculate P(X < 5) using the normal distribution and round the result to four decimal places:

P(fewer than 5) = P(X < 5) ≈ Φ((5 - μ) / σ)

Calculating the z-score as (5 - μ) / σ and using the standard normal distribution table or a calculator, we can find the corresponding probability value. However, since the given values for np and nq are not suitable for the normal approximation (np < 5 or nq < 5), we cannot estimate P(fewer than 5) using the normal approximation.

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1. The area of the circle with radius r = 4 is 200.96 square cm. 2. The area of the circle is approximately 113.04 square cm.

A circle's radius is equal to twice its diameter. In other words, if d is the diameter and r is the radius, then d = 2r. On the other hand, a circle's radius is equal to half of its diameter. Finding the circumference or area of a circle are only two examples of computations involving circles for which this connection is crucial.

The area of the circle is given by the formula:

A = πr²

Substituting the value r = 8 we have:

Area = 3.14(8)² = 200.96 square cm

2. For circle with d = 12 cm we have the radius as:

r = 12/2 = 6

A = 3.14(6)² = 113.04 square cm

Hence, the area of the circle with radius r = 4 is 200.96 square cm. 2. The area of the circle is approximately 113.04 square cm.

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The quotient of 30y³ + 50y² - 35y divided by 5y is: 6y² +10y - 7

Hence option c is the correct answer.

Applying long division rule to find quotient,

Dividend is  30y³ + 50y² - 35y and divisor is 5y

Dividing   30y³ + 50y² - 35y  by 5y step by step we get ( +) 30y^3  is divisible by 5y as the remainder is zero and the quotient is (+) 6y^2.

Then at second step we get (+) 50y^2 is divisible 5y as the remainder is zero and the quotient is (+) 10y.

And at the last step we get (-) 35y is divisible by 5y as the remainder is zero and the quotient is (-) 7.

Thus adding up the quotients found at each step of division of   30y³ + 50y² - 35y by 5y is 6y² +10y - 7.

Hence option c is the correct answer.

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Answer:

hi baby its me nick this is my new account

Step-by-step explanation:

The coupon rate for this Pacific Bell bond is 6%, and the maturity date is in 2034. So, the correct option is B: The coupon rate is 6%, and the maturity date is 2034.

The information provided in the bond listing can be interpreted as follows:

Bond issuer: Pacific Bell

Coupon rate: 6.55

Maturity date: 2034

Volume: 511

Closing price: 99-4

Net change: 8

Therefore, the correct answer is: The coupon rate is 6.55 and the maturity date is 2034.

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