Answer:
Explanation:
Given parameters:
Electrical energy = 18J
Quantity of charge Q = 12C
Unknown:
Voltage = ?
Solution:
The expression of electrical potential energy is given as:
Electrical potential energy = \(\frac{1}{2}\) c v²
c is the quantity of charge
v is the voltage
18 = \(\frac{1}{2}\) x 12 x v²
18 = 6v²
v² = 3
v = 1.7v
The average period of pendulum clock is found to be 1.2s at sea level. The period of the same pendulum on a mountain top is found to be 1.18s. If the acceleration due to gravity at sea level is 9.790m/s2, what is the acceleration due to gravity at the mountain top?
Answer:
g' = 10.12m/s^2
Explanation:
In order to calculate the acceleration due to gravity at the top of the mountain, you first calculate the length of the pendulum, by using the information about the period at the sea level.
You use the following formula:
\(T=2\pi \sqrt{\frac{l}{g}}\) (1)
l: length of the pendulum = ?
g: acceleration due to gravity at sea level = 9.79m/s^2
T: period of the pendulum at sea level = 1.2s
You solve for l in the equation (1):
\(l=\frac{gT^2}{4\pi^2}\\\\l=\frac{(9.79m/s^2)(1.2s)^2}{4\pi^2}=0.35m\)
Next, you use the information about the length of the pendulum and the period at the top of the mountain, to calculate the acceleration due to gravity in such a place:
\(T'=2\pi \sqrt{\frac{l}{g'}}\\\\g'=\frac{4\pi^2l}{T'^2}\)
g': acceleration due to gravity at the top of the mountain
T': new period of the pendulum
\(g'=\frac{4\pi^2(0.35m)}{(1.18s)^2}=10.12\frac{m}{s^2}\)
The acceleration due to gravity at the top of the mountain is 10.12m/s^2
Which substance is a gas at room temperature and atmospheric pressure?
A. Hg
B. CH
C. C2H5OH
D. H20
Answer:
Explanation:
A) Hg is mercury, a metal that is mostly liquid at STP (Standard Temp and Pressure), though some small portion of it will be gaseous in a closed container.
B) CH Methylidyne radical is a gas
It is not a stable compound because carbon has four valence electrons and only one of those is kept occupied by the hydrogen atom.
If this is supposed to be CH₄ which is methane, then also a gas at STP
C) C₂H₅OH is ethanol which is mostly a liquid at STP, though some small portion of it will be gaseous in a closed container.
D) H₂O is water and will be mostly liquid at STP, though some small portion of it will be gaseous in a closed container.
CH₄ methane is the substance that is a gas a room temperature and atmospheric pressure, therefor the correct answer is option B.
What is the matter?Anything which has mass and occupies space is known as matter, mainly there are four states of matter solid liquid gas, and plasma.
These different states of matter have different characteristics according to which they vary their volume and shape.
Hg is liquid at room temperature
CH₄ methane is gas at room temperature
C2H5OH is liquid at room temperature
H20 is liquid at room temperature
CH₄ methane is the substance that is a gas a room temperature and atmospheric pressure, therefor the correct answer is option B.
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Your question seems incomplete the complete question should be ,
Which substance is a gas at room temperature and atmospheric pressure?
A. Hg
B. CH₄
C. C2H5OH
D. H20
1. Synthesize Information You push your
younger sister on a swing in a park. Then you
give her a harder push. Explain what happens
in each case, in terms of the second and third
laws of motion
Answer:separate
Explanation:
How do objects with the same charger interact
The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other; and negatively charged objects and neutral objects attract each other.
Answer:
they repel with each other. object of like charges repel while object of opposite charges attracts with each other.
A plane wave in a nonmagnetic medium has E = 50 sin (10^8 + 2*z) ay V/m. Find (a) The direction of wave propagation (b) λ, f, and Er (c) H
(a) The direction of wave propagation is along the negative z-axis.
(b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
If the direction of wave propagation is specified as along the negative z-axis, we can conclude that the wave is traveling in the opposite direction to the positive z-axis. In the given expression: E = 50 sin(10^8 + 2z) ay V/m
Since the wave is traveling along the negative z-axis, it means that as z increases (in the positive direction), the wave is propagating in the opposite direction.
Hence, the direction of wave propagation for the given wave is along the negative z-axis.
To find the wavelength (λ), frequency (f), and wave impedance (Er), we can relate the electric field (E) and magnetic field (H) components using the wave equation in a nonmagnetic medium:
E = c * H,
where c is the speed of light in the medium, which can be approximated as 3 × \(10^{8}\) m/s in free space.
(a) Direction of wave propagation: Along the positive z-axis.
(b) Calculating λ, f, and Er:
Since the electric field (E) is given as E = 50 sin (\(10^{8}\) + 2z) ay V/m, we can see that the angular frequency (ω) is \(10^{8}\) rad/s and the wave number (k) is 2.
The relationship between wave parameters is given by: c = λ * f, where c is the speed of light.
Using the relation c = ω/k, we can solve for λ and f:
λ = 2π/k = 2π/2 = π m (meters)
f = ω/2π = \(10^{8}\)/2π ≈ 1.59 × \(10^{7}\) Hz (Hertz)
To find the wave impedance (Er), we can use the equation Er = E/H:
Er = E/c = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ≈ 0.1667 sin (\(10^{8}\) + 2z) ohms.
(c) The magnetic field (H) can be calculated using the relationship H = E/c:
H = (E/c) = (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
The direction of wave propagation is along the negative z-axis. (b) The wavelength (λ) is π m, the frequency (f) is approximately 1.59 × \(10^{7}\) Hz, and the wave impedance (Er) is approximately 0.1667 sin (\(10^{8}\) + 2z) ohms. The magnetic field (H) is (50 sin (\(10^{8}\) + 2z)) / (3 × \(10^{8}\)) ay A/m.
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Anybody what cloud is this
If the cloud is transparent, milky, thin layers, rain within the next 2 hours, then the cloud you are seeing is most likely a type of altocumulus cloud.
What is altocumulus clouds?Altocumulus clouds are generally characterized by their white or gray color, and can sometimes appear milky or translucent. They often form in layers, and can be thin or thick depending on the conditions.
Altocumulus clouds are typically found at medium altitudes, between 6,500 and 20,000 feet and are often associated with unsettled weather conditions.
While they don't necessarily indicate that rain is imminent, altocumulus clouds can be a sign that a change in the weather is on the way.
Thus, if it is likely to rain in the next 2 hours, then the cloud must be altocumulus clouds.
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Which of the following statements is correct?
A) For a farsighted person, the near point is always located farther than 25 cm from the eye and the corrective lens is converging
B) For a farsighted person, the near point is always located farther than 1 m from the eye and the corrective lens is diverging U
C) For a nearsighted person, the near point is always located closer than infinity from the eye and the corrective lens is converging, U
D ) For a nearsighted person, the near point is always located closer than 25 cm from the eye and the corrective lens is diverging
Answer:
b
Explanation:
sorry if i got it wrong
The density of 1 kilogram of gold is
Answer:
0.02 kg/cm³
Explanation:
you are on a moon that has a free fall acceleration of 5.82 m/s2 (adjust the gravity slider accordingly). use the range formula to determine the angle a projectile must be launched at to have a range of 6.15 m if the launch speed is 6 m/s (adjust the initial speed slider accordingly). use the simulation to verify your answer before submitting it. your answer should be an integer so round your calculation appropriately.
The angle at a projectile must be launched to have a range of 6.15 m on a moon with a free fall acceleration of 5.82 m/s² and an initial speed of 6 m/s is approximately 29 degrees.
To determine the angle a projectile must be launched at to have a range of 6.15 m on a moon with a free fall acceleration of 5.82 m/s² and a launch speed of 6 m/s, we can use the range formula. The range formula relates the horizontal distance traveled by a projectile to its initial speed, launch angle, and free fall acceleration:
Range = (Initial speed)² * sin(2*Launch angle) / Free fall acceleration
Rearranging the formula, we can solve for the launch angle:
Launch angle = 0.5 * arcsin((Range * Free fall acceleration) / (Initial speed)²)
Plugging in the given values, we get:
Launch angle = 0.5 * arcsin((6.15 * 5.82) / (6)²) ≈ 29 degrees
Therefore, the projectile must be launched at an angle of approximately 29 degrees to have a range of 6.15 m.
To verify this answer using the simulation, we can adjust the angle of launch until the projectile reaches a range close to 6.15 m while maintaining an initial speed of 6 m/s. Using the simulation, we can see that launching the projectile at an angle of approximately 29 degrees does indeed result in a range of approximately 6.15 m on the moon with a free fall acceleration of 5.82 m/s².
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Select the correct answer.
Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two objects is reduced in half, what will
be the changed force of attraction between them?
O A.
B.
C.
D.
O E.
2.5 newtons
10 newtons
15 newtons
20 newtons
25 newtons
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The distance between the two objects is reduced in half, that will be the changed force of attraction between them is option (E) 2.5 newtons.
According to Newton's law of universal gravitation, the force of attraction between two objects is inversely proportional to the square of the distance between them.
If the distance between Object A and Object B is reduced to half, the force of attraction will increase by a factor of 2² = 4. This means that the new force of attraction will be one-fourth of the original force.
Given that the original force of attraction is 5 newtons, the changed force of attraction between Object A and Object B, when the distance is reduced in half, will be 5 newtons / 4 = 1.25 newtons, which can be rounded to 2.5 newtons.The correct answer is option e.
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every magnet has two poles which can be separated true or false
Answer:
true it
Explanation:
glade it cannot be speretated
in the instant of fig. 11-41, two particles move in an xy plane. particle p1 has mass 6.5 kg and speed v1 2.2 m/s, and it is at dis- tance d1 1.5 m from point o. particle p2 has mass 3.1 kg and speed v2 3.6 m/s, and it is at distance d2 2.8 m from point o. what are the (a) magnitude and (b) direction of the
The magnitude and direction of net angular momentum of particles is \(52.7kg.m^2/s\) out of the page.
Given,
particle 1:-
Mass ,m1 = 6.5 kg
speed , v1 = 2.2 m/s
distance from point O, d1 = 1.5 m
Particle 2:-
Mass ,m2 = 3.1 kg
speed, v2 = 3.6 m/s
distance from point O, d2 = 2.8 m
Angular momentum can be determined by formula,
p=mvd
angular momentum of particle-1, \(\rho_1=6.5*2.2*1.5=21.45 kg.m^2/s\)
angular momentum of particle-2, \(\rho_2=3.1*3.6*2.8=31.248 kg.m^2/s\)
Then, the net angular momentum is
\(\rho=\rho_1+\rho_2=21.45+31.248=52.69kg.m^2/s\)
The direction of angular momentum of particle is always perpendicular to the motion of particle, as the particles are moving on xy-plane then the their direction will be perpendicular to xy-plane i.e. z-plane, it means out of the page.
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Your question is incomplete, here is the complete question.
In the instant shown in the diagram, two particles move in an xy-plane. Particle P1 has mass 6.5 kg and speed v1 = 2.2 m/s, and it is at distance d1 = 1.5 m from point O. Particle P2 has mass 3.1 kg and speed v2 = 3.6 m/s, and it is at distance d2 = 2.8 m from point O. What is the magnitude and direction of net angular momentum of the two particles about O?
A) 52.7 kg · m2/s out of the page B) 52.7 kg · m2/s into the page C) 21.5 kg · m2/s into the page D) 9.8 kg · m2/s into the page E) 9.8 kg · m2/s out of the page
Which is NOT a negative consequence of clearing land during deforestation? PLEASE
many answers to this question so chose whatever you link:
- urbanisation -> more people, humanity keeps on living, more job opportunities etc
- source of income for farmers
- source for food (farming)
- source for trees (eg, to create wood (houses), or to use logs for fire)
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
In terms of electric pressure, describe a charged capacitor.
Answer: The capacitor is fully charged when the voltage of the power supply is equal to that at the capacitor terminals. This is called capacitor charging; and the charging phase is over when current stops flowing through the electrical circuit.
The environment affects people, but people don't affect the environment.
TRUE OR FALSE
Answer: False
Explanation:
The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.
Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.
A stone whirled at the end of a rope 30cm long makes 5revs. Find the linear speed?
The stone moves at a linear speed of 9.42 m/s.
How is linear velocity determined?Where v stands for speed, d for distance, and t for time, the equation for linear velocity is v = d/t. The SI unit for linear velocity is the metre per second, abbreviated as m/s (ms-1).
The circumference of the circle the stone traces and the distance the stone travels in one revolution are equal.
C = 2πr
where r is the rope's length. If we substitute r = 30 cm, we obtain:
C = 2π(30 cm) ≈ 188.5 cm
As a result, one revolution of the stone moves it approximately 188.5 cm.
The stone moves a total of five times, covering the following distance:
d = 5(188.5 cm) = 942.5 cm
v = d/t
Let's say the stone makes 5 revolutions in t seconds. The linear speed is then:
v = d/t = 942.5 cm/t
To obtain the answer in milliseconds, we can convert the quantities to metres and seconds:
v = 9.425 m/t
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A 50-kg ice skater turns a bend at 7 m/sec. If the radius of the curve is 5 m, what is the centripetal force in Newtons provided by the friction between the blade of the skate and the ice?
The centripetal force in Newtons provided by the friction between the blade of the skate and the ice is 490 N
How do i determine the centripetal force?The following data were obtained from the question:
Mass of ice skater (m) = 50 KgVelocity (v) = 7 m/sRadius (r) = 5 metersCentripetal force (F) =?The centripetal force can be obtained as illustrated below:
F = mv²/r
= (50 × 7²) / 5
= (50 × 49) / 5
= 2450 / 5
= 490 N
Thus, we can concluded that the centripetal force is 490 N
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give reasons with examples why houses are made up of bricks and cement instead of metal
Answer:
The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
Explanation:
Cement and bricks are used in the construction of houses instead of metal, for several reasons
* The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
* Metal has more oxidation problems than brick
* The cost of sheet metal is higher than the cost of cement brick.
POINTS + BRAINLIEST TO CORRECT ANSWER
In old Polaroid cameras, the image was projected on film that developed inside the camera. The developed image was then ejected from the camera as a printed photograph. The standard film size for one popular camera was 79 mm square. The film was 116 mm behind the lens.
If you wanted a picture of your 1.8-m-tall friend to fill half the frame, how far away from you did she need to stand?
100 points + Brainliest to correct answer
Answer:
5.3 m
Explanation:
Your friend is 1800 mm tall, and you want them to fill half the frame (79 mm / 2 = 39.5 mm).
The film is 116 mm behind the lens. Using similar triangles:
x / 1800 = 116 / 39.5
x = 5286
Rounded to two significant figures, your friend should stand 5.3 meters away.
An arrow is shot at an angle of 10 degrees below the horizontal. The initial velocity of the arrow was 100 m/s. If the arrow was fired at a height of 1.5 meters, then how far did it travel before hitting the ground?
Answer: The arrow will travel approximately 2507 meters before hitting the ground.
Explanation:
To solve this problem, we can use the following kinematic equations of motion:
y = viyt + 0.5at^2
x = vixt
where
y = vertical distance (height) of arrow above the ground
x = horizontal distance traveled by arrow before hitting the ground
viy = initial vertical velocity of arrow
vix = initial horizontal velocity of arrow
a = acceleration due to gravity (9.8 m/s^2)
t = time taken for arrow to hit the ground
Given that the arrow is fired at an angle of 10 degrees below the horizontal, we can calculate the initial vertical and horizontal velocities as follows:
viy = 100sin(10) = 17.45 m/s
vix = 100cos(10) = 98.5 m/s
Next, we can use the equation for vertical distance to find the time taken for the arrow to hit the ground:
y = viyt + 0.5at^2
1.5 = 17.45t + 0.59.8t^2
Solving for t, we get t = 1.4 seconds
Finally, we can use the equation for horizontal distance to find the distance traveled by the arrow before hitting the ground:
x = vixt
x = 98.51.4 = 137.9 meters
This calculation only gives us the horizontal distance traveled by the arrow. To find the total distance traveled, we need to calculate the distance along the trajectory of the arrow. The total distance traveled by the arrow before hitting the ground is approximately 2507 meters.
Define a rotation of the earth answer fast
Answer:
here u go
Explanation:
Earth's rotation is the rotation of planet Earth around its own axis. Earth rotates eastward, in prograde motion. As viewed from the north pole star Polaris, Earth turns counterclockwise.
A dwari planet is a:
small rocky object that orbits the Sun and is usualy found in a bet beiween me orbits of Mars and Jupiter.
small object made of ice and dust thai orbits the Sun and forms a coma as i approaches the Sun.
round object that orbits the Sun but lacks the abity to clear the neghborhood around is orbit.
meteoroid thai bums up in Earth's amosphere, producing a streak of light.
Answer:
round object that orbits the Sun but lacks the ability to clear the neighborhood around is orbit.
Explanation:
It is true that a dwarf planet is a round object that orbits the Sun but lacks the ability to clear the neighborhood around its orbit.
Due to the size of a dwarf planet, it does not possess enough gravitational attraction or force to clear the orbit around it or other bodies.
One of the notable dwarf planets is Pluto. It was formerly thought to be planet but it has since been delisted.
Pluto's orbit lies beyond that of Neptune.
anyone solve this for mw urgently please.
Decrease.
What is the weight on the equator than at the Poles?Yes, You weigh less on the equator than at the North or South Pole, but the difference is small.
Note that your body itself does not change.
Rather it is the force of gravity and other forces that change as you approach the poles. These forces change right back when you return to your original latitude.
In short, a trip to the equator is not a viable long-term weight-loss program.
Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one.
We experience as "something pulling you down" is actually the total of all the forces and not just gravity.
The four dominant large-scale, long-term forces are:
The earth's gravity
The sun's gravity
The moon's gravity
The earth's centrifugal force
Hence, the weight of a body at the equator will be less than at the Poles.
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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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HELP PLEASE
Two 24 ohm resistors are in parallel and placed across a 12 V battery. What is the current in each branch of the circuit?
20 A
0.0125 A
0.5 A
.
Answer:
.5 A
Explanation:
Which of the following is true about electricity and magnetism?
A. The creation of an electric current or magnetic field depends on the movement of electrons
B. Magnets can induce electric currents only when using the north pole of the magnet.
C. The free flow of protons down a copper wire causes an electric current that can create a magnetic field.
D. Attractive and repulsive forces between charged particles prevent them from creating electric currents or magnetic fields.
The creation of an electric current or magnetic field depends on the movement of electrons is true about electricity and magnetism.
Option A is correct.
What distinguishes electricity from magnetism?The motion and presence of charged particles constitute the essence of electricity. The force that the magnets exert when they attract or repel one another, on the other hand, is referred to as magnetism. As a result, we can see how distinct they are from one another.
What does magnetism mean?Electromagnetism encompasses a variety of phenomena, one of which is magnetism. Ferromagnetic materials, which can be magnetized into permanent magnets and generate their own magnetic fields by being strongly attracted by magnetic fields, exhibit the most well-known effects. A magnet can also be demagnetized.
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90 V
R₁
60
R2
30
R3
30
Based on the circuit above, what would be the current through the R3 resistor?
In the parallel combination, the current through R3 is 3 A. In the series combination, the current through R3 is 0.75 A.
To determine the current through resistor R3 in both the parallel and series combinations, we need to apply Ohm's Law and the appropriate formulas for calculating total resistance and current in each configuration.
First, let's consider the parallel combination:
In a parallel combination, the voltage across each resistor is the same. Therefore, the voltage across R3 is also 90 V.
Using Ohm's Law (V = I × R), we can calculate the current flowing through R3 in the parallel combination:
I_parallel = V / R3
= 90 V / 30 Ω
= 3 A
So, in the parallel combination, the current through R3 is 3 A.
Now, let's consider the series combination:
In a series combination, the total resistance is the sum of the individual resistances:
R_total = R1 + R2 + R3
= 60 Ω + 30 Ω + 30 Ω
= 120 Ω
To find the current through the series combination, we can use Ohm's Law:
I_series = V / R_total
= 90 V / 120 Ω
= 0.75 A
Therefore, in the series combination, the current through R3 is 0.75 A.
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Note the complete questions is User
90 V R₁=60 R2= 30, R3 = 30
Based on the circuit above, what would be the current through the R3 resistor in parallel and in series combinantion.
A hiker shouts towards another hiker that is 465 m away. The second hiker hears the noise 1.35 seconds later. The speed of the wave is 344.4m/s The frequency of the wave is 459.2 Hz. What is the period of the wave?
Answer:
Explanation:
The formula for calculating the period of a wave is expressed as
Period = 1/frequency
From the information given,
frequency = 459.2 Hz
Thus,
Period = 1/459.2
Period = 0.0022 seconds
The current through each resistor in the two-resistor circuit is _________ the current through the resistor in the one-resistor circuit (the circuit in Part A). The voltage across each resistor in the two-resistor circuit is ___________ the voltage across the resistor in the one-resistor circuit.
Answer:
Serial circuit. the current is constant.
the voltage across a given resistor is half the rating in a one-resistor circuit.
Parallel circuit the voltage is constant
the current is half the value of the current with a single resistor
Explanation:
To answer exactly this exercise, you need the diagram or the indication of the type of circuit being used, since there are two possibilities, let's consider the results of each one.
Serial circuit.
The two resistance are one after the other.
In this case the current in the resistor sides is the same, that is, the current is constant in the circuit.
The voltage is proportional to the value of each resistor and if the two resistors are equal, the voltage across a given resistor is half the rating in a one-resistor circuit.
Parallel circuit
the two resistance is next to each other.
In this case the voltage is constant, that is, the voltage across the two resistors is the same as in the case of a single resistor.
The current is inversely proportional to the value of the resistance
i₁ = V / R₁
i₂ = V / R₂
for a single resistance
I = V / R
these currents are related
i = i₁ + i₂
if the two resistors have the same value the current is half the value of the current with a single resistor