The wavelength of an ultrasonic wave with a frequency of 1.0×10^5 Hz, given the speed of sound in air as 340 m/s, is approximately 3.4 mm.
The wavelength of a wave can be calculated using the formula λ = v/f, where λ represents the wavelength, v is the velocity or speed of the wave, and f is the frequency of the wave.
In this case, the frequency is given as 1.0×10^5 Hz, and the speed of sound in air is 340 m/s. By substituting these values into the formula, we can determine the wavelength.
λ = 340 m/s / (1.0×10^5 Hz) = 3.4×10^-3 m = 3.4 mm
Therefore, the wavelength of the ultrasonic wave emitted by bats, with a frequency of 1.0×10^5 Hz, is approximately 3.4 mm.
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A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15 ∘
to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, find the minimum speed at which she can travel without slipping.
A girl rides her cycle round a circular track of diameter 60 m. The track is banked at 15° to the horizontal. The coefficient of friction between the track and the tyres of the cycle is 0.25. Modelling the girl and her cycle as a particle of mass 60 kg moving in a horizontal circle, the minimum speed at which she can travel without slipping is 13.64 m/s.
To find the minimum speed at which the girl can travel without slipping, we need to consider the forces acting on her and her cycle as they move in a circular track.
The forces acting on the girl and her cycle are the gravitational force (mg), the normal force (N), and the frictional force (f). The frictional force provides the centripetal force necessary to keep the girl moving in a circular path.
The normal force can be resolved into two components: the vertical component (N⊥) and the horizontal component (N∥). The vertical component balances the gravitational force, while the horizontal component provides the centripetal force.
Mass of the girl and cycle (m) = 60 kg
Diameter of the circular track (d) = 60 m
Bank angle (θ) = 15 degrees
Coefficient of friction (μ) = 0.25
Find the normal force components:
N⊥ = mg cos(θ)
N∥ = mg sin(θ)
The frictional force:
f = μN⊥
The frictional force (f) provides the centripetal force required for circular motion:
f = m(v² / r)
Here, v is the velocity and r is the radius of the circular track. The radius is:
r = d / 2
Combining the equations, we have:
μN⊥ = m(v² / r)
Substituting the values we have:
μmg cos(θ) = m(v² / (d / 2))
v² = (μmg cos(θ) / m) * (d / 2)
v² = (μg cos(θ)) * (d / 2)
v = √((μg cos(θ)) * (d / 2))
v = √((0.25 * 9.8 * cos(15)) * (60 / 2))
v ≈ 13.64 m/s
Therefore, the minimum speed at which the girl can travel without slipping is approximately 13.64 m/s.
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Using the law of conservation of energy, what is the kinetic energy at B? K.E. = 3, 6, or 4.8
Answer:
3
Explanation:
A passenger on a train approaching a station at 29 m/s hears a bell ringing in the station. Take the speed of sound to be 343 m/s. A The passenger hears the bell at a frequency of 356 Hz. What frequency, in hertz, do the people waiting on the station platform hear?
The people waiting on the station platform hear a frequency of approximately 369.7 Hz.
The observed frequency of a sound wave changes based on the relative motion between the source of the sound and the observer. This effect is known as the Doppler effect. In this scenario, the train is approaching the station, so the observer (the passenger on the train) is moving towards the source of the sound (the bell ringing in the station).
To calculate the frequency heard by the passenger on the train, we can use the Doppler effect equation for sound:
f' = (v + vo) / (v + vs) * f
where f' is the observed frequency, v is the speed of sound, vo is the velocity of the observer, vs is the velocity of the source, and f is the actual frequency of the source.
Given that the passenger hears the bell at a frequency of 356 Hz, and the speed of sound is 343 m/s, we can rearrange the equation to solve for vs (the velocity of the source, which is the train):
vs = (f / f' - 1) * v - vo
Plugging in the values, we have:
vs = (343 / 356 - 1) * 343 - 29
vs ≈ -9.26 m/s
Since the velocity of the source (the train) is negative, it means the train is moving towards the observer on the platform. Now, to find the frequency heard by the people waiting on the station platform, we use the same Doppler effect equation but with the opposite signs for vo and vs:
f' = (v - vo) / (v - vs) * f
Plugging in the values, we have:
f' = (343 - 0) / (343 - (-9.26)) * 356
f' ≈ 369.7 Hz
Therefore, the people waiting on the station platform hear a frequency of approximately 369.7 Hz.
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What happens in the gray zone between solid and liquid?
MORE POINTSSSSSSS TAKE 'EM SOOOONNNNNN
Please Answer the question to get them
Answer:
Hence from liquid to solid or solid to liquid the transition has to cross the grey zone. This grey zone transition is is very crucial which includes the intermolecular forces acting on the molecules and each atoms which makes the change in state from hot to cold and cold to hot.
Explanation:
one treatment of cataracts is to surgically remove the variable lens of the eye. if we assume that the cornea's refractive power focuses objects at infinite distances onto the retina of a person who has had this surgery, what power correcting lenses would they need to be able to read text at a 22-cm near-point distance? again, give your answer in units of diopters, to the nearest tenth of a diopter and with the correct sign.
To read text at a near-point distance of 22 cm, a person who has had cataract surgery would need a corrective lens with a refractive power of +4.5 diopters.
If a person has had the surgical removal of the variable lens of the eye, they would have lost the ability to accommodate (change the shape of the lens to focus on objects at different distances). Therefore, they would require corrective lenses to see clearly at different distances.
To determine the power of the corrective lenses required to read text at a near-point distance of 22 cm, we can use the following formula:
\(1/f = 1/d_o + 1/d_i\)
where:
f = focal length of the corrective lens
\(d_o\) = object distance (distance from the eye to the object)
\(d_i\)= image distance (distance from the eye to the image formed by the corrective lens)
We want to find the power of the corrective lens, which is given by:
\(P=1/f\)
The near-point distance \((d_o)\) is 22 cm = 0.22 m. Since the cornea's refractive power focuses objects at infinite distances onto the retina, we can assume that the object distance is effectively at infinity, i.e., \(d_o = \infty\)
Therefore, the formula becomes:
\(1/f = 1/\infty + 1/d_i\)
\(1/f = 0 + 1/d_i\)
\(f = d_i\)
We want to find the focal length \((d_i)\) of the corrective lens required to form an image of the text at a distance of 22 cm from the eye.
Using the formula, we get:
\(f = d_i = \frac{1}{(1/d_o + 1/d_i)}\)
\(d_i = \frac{1}{(1/d_o + 1/f)}\)
\(d_i = \frac{1}{(1/0.22 + 1/\infty)}\)
\(d_i = 0.22 m\)
Now, we can calculate the power of the corrective lens required as follows:
\(P = 1/f\)
\(P = 1/0.22\)
\(P = +4.5\) diopters (to the nearest tenth of a diopter)
Therefore, the power of the corrective lenses required to read text at a near-point distance of 22 cm is +4.5 diopters (convex lenses).
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what are four methods of acquiring knowledge
The four methods of acquiring knowledge are observation, experience, reasoning, and education.
Observation involves gathering information through the senses and paying attention to what is happening in the environment. Experience involves learning through personal encounters, such as practical work or life events. Reasoning involves using logic and critical thinking to draw conclusions and make decisions.
Education involves acquiring knowledge through formal instruction and learning, such as in a school setting or through reading and studying. All four methods are important and can be used in combination to acquire a deep and well-rounded understanding of a subject.
Observation and experience provide hands-on and practical knowledge, while reasoning and education provide theoretical and abstract knowledge. By using a combination of these methods, individuals can broaden their understanding and knowledge of the world around them.
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write me a presentation of oxygen
Why does a small piece of steel rod sinks while a large steel oil tanker floats?
Plss help thanks! pls include EXPLANATION and EXAMPLES that I can proof to people that has no knowledge
Answer:
Too what i know its because of the air
Explanation:
The steel rod is more dense and doesnt have air whil'st the oil tanker is less dense with lots of air
Label the graph below with the appropriate phrase.Question 5 options:TimeFaster and faster growth as population becomes largerPopulation sizeSlow growth when population is small1.A. 2.B. 3.C4.D
Looking at the graph and its missing parts, we can identify the following items to fill each box:
A. Population Size.
Since the population size is a dependent variable in relation to time, we should use it in the vertical axis.
B. Slow growth when population is small.
In the first part of the graph, the population is small and also grows slowly.
C. Faster and faster growth as population becomes larger.
In the final part of the graph, the population is big and also grows fast.
D. Time
Since the time usually is an independent variable, we should use it on the horizontal axis.
Vedant swims in a 90 m long pool from A to B and returns back to A, in one minute. Calculate his average speed.
Answer:
His average speed is 1.5 meters per second.
Explanation:
Given:
Distance = 90 meters
Time = 1 minute = 60 seconds
equation...
Average Speed = Total Distance / Total Time
so...
Average Speed = 90 meters / 60 seconds
then the answer would be...
Average Speed = 1.5 meters per second
How does gravity control the orbital motions of the planets in the solar system.
Answer:
It keeps them in place because they are being pulled towards the sun and are also moving fast enough to go around it
Explanation:
How much distance does a car travel if it is driving down the road at 50 m/s before hitting
the gas and accelerating at 3 m/s2 for 20 seconds?
Answer:
from second equation of motion
\(S = ut + \frac{1}{2} a {t}^{2} \\ S = (50 \times 20) + (\frac{1}{2} \times 3 \times {20}^{2} ) \\ S = 1000 + 600 \\ S = 1600 \: m\)
you are being asked to design a parallel-plate capacitor having a capacitance of 1.00f and a plate separation of 1.00mm. calculate the required surface area of each plate. is this plate size realistic?
1.1×10^8 m^2 is the required surface area of each plate. is this plate size realistic.
How is the capacitance of a parallel plate capacitor calculated?The formula C=Ad C = A d, where C is the value of the capacitance, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the plates of the parallel capacitor, gives the capacitance for parallel plate capacitors (dependent on its geometry).
C=εoA /d
∴A= Cd / εo
=(1)(10)^-3 /8.86×10 ^(−12)
=1.1×10^8 m^2
hence the surface area of each plate 1.1×10^8 m^2.
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I need to know the why for the two questions.
4. If the moon falls, it does not get closer to earth due to the effect of gravity.
5. On increasing the mass of the sun then the earth's tangential velocity also increases.
4)Similar to how the earth orbits the moon, but because of the speed at which it caught up to the earth, the moon is prevented from colliding with the planet by the force of gravity.
Because of this, even though the moon is edging a tiny bit farther from our planet, it is kept in a pretentious orbit around it.
5) the earth tangential velocity increases if the mass of the sun increased.
Tangential velocity :It is the linear component of any object's speed that is travelling in a circle.
To keep an object moving uniformly in a circle, a stronger centripetal force is needed.4. If the moon falls, it does not get closer to earth due to the effect of gravity.
5. On increasing the mass of the sun then the earth's tangential velocity also increases.
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As you travel up into the mountains of the troposphere, increasing elevation,
the air pressure...
Oa. Decreases because the air gets more dense
O b. Decreases because the air gets less dense
Oc. Increases because the air gets more dense
Od. Increases because the air gets less dense
Answer:
OA
Explanation:
Which label belongs in the area marked x is always constant , includes magnitude , has direction depends on a
reference frame
The marked part x is inside the circle hence, the direction will be same in all points. Therefore, the correct label is x includes a magnitude.
What is scalar quantities?There are two types of physical quantities namely, scalar and vector quantities. Scalar quantities or variables are those which are having magnitude only and not depends upon the direction.
Temperature, volume, refractive index, energy etc. are scalar quantities. Vector quantities are those having both magnitude and direction. Force, acceleration, velocity, work done etc. are vector quantities which depends on the direction.
The marked area x is a point inside a circle. Therefore its path of motion or change is circular and thus does not affects its magnitude. Thus it have no directional change and has a magnitude.
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A 100 kg cyclist travels at 4.5 m/s. A 50 kg gorilla is dropped straight down onto her. What is the new speed of the system?
Mass of cyclist = 100 kg
Mass of gorilla = 50 kg
Initial speed = 4.5 m/s
Let Final speed = s
100 x 4.5 = (100 + 50) x s
450 = 150s
S = 450/150
S = 3
The new speed is 3m/s
QUESTION 1A 102.3 kg archer is standing on level ice (neglect friction) fires a 99 g arrow to the right at 104.2 m/s. What is the recoil speed ofthe archer? (report your answer to at least the thousandth's place)
Conservation of momentum
Pix = Pfx
m1= Archer's mass = 102.3 kg
v1 = Archer's velocity =
m2 = arrow's mass = 99g = 0.099 kg
v2f= arrow's velocity = 104.2 m/s
0= m1 v1 + m2 v2
V1= -( m2/m1) v2
V1 = - (0.099 kg /102.3 kg) *104.2 m/s
V1= - 0.1008 m/s
Can someone please help me? Find the bet force acting on the figure.
Answer:
sorry dont know it is confusing.
Answer:
- 5 N
Explanation:
The bet force is the sum of the all forces are acting on the object and you can see three forces are acting on the box but 2 of them are cancel each other because they have same magnitude but different direction which they are F norm and F grav so if we sum we will have
Fnorm - Fgrav - Ffrict
and the ( -) sign reffers to the lift direction or downward
So you can say the bet force is - 5 N
An engineering team has come to the stage in the engineering design process in which it is iterating to improve the solution. hat is one thing the team might be doing ?
When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:
Prototyping: This involves building a physical or digital prototype that can be tested and refined based on feedback from stakeholders. The team can then use this prototype to identify any design flaws and make the necessary changes.Simulation: Simulation involves creating a virtual model of the solution and testing it under various conditions. The team can use simulation to identify potential problems with the solution before it is built.User testing: User testing involves testing the solution with real users to get feedback on how well it works and how it can be improved. The team can use this feedback to make changes to the design and improve the user experience.Feedback analysis: This involves analyzing feedback from stakeholders, including users, customers, and other members of the team. The team can use this feedback to identify areas for improvement and make changes to the design.The key to iterating to improve the solution is to be open to feedback and willing to make changes. By continuously testing and refining the design, the engineering team can create a solution that meets the needs of stakeholders and achieves the desired outcomes.For such more question on stakeholders
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Two magnets are held apart. Once released, the south pole of one magnet moves toward the north pole of another magnet until the magnets collide. How does the graph reflect the changes in energy that occur?
(1 point)
Kinetic energy is at its peak when the magnets are first released, then it decreases steadily. Energy stored in the magnetic field becomes zero.
The kinetic energy of the system is derived from the thermal energy created by increased velocity. Energy stored in the magnetic field does not change.
Kinetic energy and velocity are at zero when the magnets are held apart, and both increase rapidly when they are released and move together. Energy stored in the magnetic field decreases.
Graph for the two magnets held apart, kinetic energy is highest when the magnets first released, then it decreases steadily. Energy stored in the magnetic field becomes zero.
What is magnetic field?The magnetic field is the field in the space and around the magnet in which the magnetic field can be filled.
Magnetic force is the force of attraction or repulsion between two poles of the two magnets. The magnetic force is also appearing between two electrically charged bodies.
Two magnets held apart. Once released, the south pole of one magnet moves toward the north pole of another magnet until the magnets collide.
The graph reflection of kinetic energy of magnet -
When the two magnets are held apart, then the these magnets are at rest and do not possess any kinetic energy.When, the magnets released, then they started to move each other due to the magnetic force of attraction of opposite poles. Therefore, the kinetic energy between two magnets started to increase with the highest speed.Now, as they started to move towards each other, this speed started to reduced and become zero when they meat each other. Here at this point the energy stored in the magnetic field becomes zero.Therefore, graph for the two magnets held apart, kinetic energy is highest when the magnets first released, then it decreases steadily. Energy stored in the magnetic field becomes zero.
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Pravat exerts a force of 30 N to lift a bag of groceries 0.5 m. How much work did Pravat do on the bag?
Answer:
15 J
Explanation:
Work = Force x Distance
15= 30 x 0.5
Have a blessed day!
Answer:Pravat did 15 J of work
Explanation:
Suppose the velocity of an object moving along a line is positive. are position, displacement, and distance traveled equal? explain. my math lab
No, the object's displacement and distance traveled will be equal; however, because the object's initial position is unknown, the object's position may differ from its displacement and distance traveled.
Because the initial position is not provided, we cannot assert that the displacement or distance equals the position. We might have arrived at a different conclusion if the starting point had been zero, because the distance from zero equals the position.
What precisely do you mean by position, displacement, and distance?
The location of an object (whether a person, a ball, or a particle) at a given point in time is referred to as its position. The displacement of an object is the difference in its position from one time to the next. Distance is the total amount the object has traveled in a certain period of time.
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a 26.0-g object moving to the right at 19.0 cm/s overtakes and collides elastically with a 11.0-g object moving in the same direction at 15.0 cm/s. find the velocity of each object after the collision.
The velocity of first object after the collision is 16.62cm/s and the velocity of second object after collision is 32.783cm/s.
Given initial mass of object (m1) = 26g = 26x10-3kg
initial velocity of object (u1) = 19cm/s = 0.19m/s
mass of second object (m2) = 11g = 11x10-3kg
initial velocity of second object (u2) = 15cm/s = 0.15m/s
Let the velocity of first object after collision = v1
the velocity of second object after collision = v2
These objects are elastically collided. Then from law of conservation of momentum we can see that m1u1+m2u2 = m1v1+m2v2
Here kinetic energy is also conserved. Then
1/2m1u1^2 + 1/2m2u2^2 = 1/2m1v1^2 + 1/2m2v2^2
Then v1 = (m1-m2)/(m1+m2)×v1 + 2×m2/(m1+m2)×v2
v1 = (26-11)/(26+11)×(19) + 2×(11)/(26+11)×(15)
v1 = 7.702 + 8.918 = 16.62cm/s
Then v2 = 2×m1/(m1+m2)×v1 + (m2-m1)/(m1+m2)×v2
v2 = 2×(26)/(26+11)×(19) + (11-26)/(26+11)×(15)
v2 = 26.702 + 6.081 = 32.783cm/s
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why can't we see a galaxy 15 billion light-years away? (assume the universe is 14 billion years old.)
We can't see any galaxies fifteen billion light-years away because looking fifteen billion light-years away means looking to a time before the universe even existed.
How was the universe created?The universe, according to science, began with an explosion of space itself (the explosion is called the Big Bang) around 13.8 billion years ago. Gravity, a fundamental force that pulls masses toward each other, gradually drew matter together to form the first stars and the first galaxies.
Cosmic inflation, which is an extension of the Big Bang, explains why the universe is so homogeneous (or evenly composed) and how galaxies are distributed across space.
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compared to ida, eros, and gaspra, what was odd about mathilde?
A. It was smaller in size
B. It had a different shape
C. It had a different composition
D. It had a different color
The odd feature about Mathilde is that it had a different shape. It has all the features like Ida, Eros, and Gaspra. Thus, option D is correct.
Mathilde is a type of metal body present in the asteroid belt having an irregular shape. It is different from other asteroids because of its highly elongated and heavily cratered structure in space. It is estimated that the diameter of the Mathilde is around 50 kilometers.
Mathilde does not have any defined shape and the color is also very distinct. Due to its high carbon nature, it looks like dark black color. This type of asteroid is more prone to collisions.
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The two processes which produce nuclear changes are _____ and _____.
fizzing
fission
nucleation
fusion
A cart of mass m is moving with speed v on a smooth track when it encounters a vertical loop of radius r, as shown above. the cart moves along the inside of the entire loop without leaving the track. all frictional forces are negligible.Which of the following must be true for the cart to remain on the track when it is at point P?
Therefore for cart to stay here on track when it arrives at point P, the net force applied to it must be greater or equal than for the heaviness of the cart.
Describe force.The force is an impact that has the power to alter an object's motion. A mass-containing object's velocity can be altered by a force. An obvious way to describe force is as a pushed or a pull. A vector quantity is called a force since it has both strength and the direction.
Which force is the most crucial?The strongest force in existence is thought to be the strong force. The gravitation, weak, and electromagnetism forces come after it in lowest to highest.
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a _ is an explanation that unifies the findings of many experiments, and it can be changed when new experimental results need to be explained
That's a pretty good intuitive definition of a theory .
4. A car with a mass of 1000 kg is travelling at an acceleration of 25 m/s2 and hits a wall. What is
the amount of force applied to that wall?"
Answer:
25,000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
mass = 1000 kg
acceleration = 25 m/s²
force = 1000 × 25 = 25,000
We have the final answer as
25,000 NHope this helps you