Based on the reading of the Geiger counter, it is likely that the Fiesta Ware plate is emitting beta radiation.
Beta radiation consists of high-energy electrons or positrons that can penetrate through skin and clothing but can be stopped by a thin sheet of metal. This type of radiation is commonly emitted by radioactive materials such as strontium-90, which was often used in the production of Fiesta Ware.
Beta radiation (β) is the transmutation of a neutron into a proton and an electron (followed by the emission of the electron from the atom's nucleus: e − 1 0 ). When an atom emits a β particle, the atom's mass will not change (because there is no change in the total number of nuclear particles).
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two uses of electricity
how many strings of eight english letters are there that contain no vowels, if letters can be repeated?
There are 20,971,520 strings of eight English letters that contain no vowels when letters can be repeated.To calculate the number of strings of eight English letters that contain no vowels.
we need to consider the total number of possible choices for each letter position.
In the English alphabet, there are 26 letters, including five vowels (A, E, I, O, U) and 21 consonants.
Since we want to create strings without vowels, we can choose any of the 21 consonants for each position in the string.
For each of the eight positions in the string, there are 21 choices (consonants) available.
Therefore, the total number of strings can be calculated as:
Total number of strings = Number of choices for each position ^ Number of positions
Total number of strings = 21^8 = 20,971,520
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consider three particles, each of which has mass 2 kg. their locations relative to an origin is given by position vectors
Fi(t) = tē, m, ry(t) = 2t?ē, m, and is(t) = (2tēz +tey) m, where t is a dimensionless quantity representing time in seconds. (a) Determine the location of the center of mass as a function of time. [5] (b) Determine the velocity of the center of mass as a function of time. [5] (c) What is the total momentum of this system of particles at time t=1 s. [5] (d) What is the magnitude of the total external force acting on this system of particles? Is this force constant? [4+1] (e) What would be the answer to part (a), if the mass of each particle were 5 kg? [5]
The location of the center of mass as a function of time is rCM = [(2/3)tē + (1/3)tey, (1/3)t?ē, (1/3)tēz].
The velocity of the center of mass as a function of time is vCM = [(2/3)ē, 0, 0].
The total momentum of the system of particles at time t=1 s is p = (2ē + 4?ē + 2ēz + e?) kg m/s.
(a) To find the center of mass of the three particles, we first need to find the total mass of the system. Since each particle has a mass of 2 kg, the total mass is 6 kg. Then, we can use the formula for the center of mass:
rCM = (m1r1 + m2r2 + m3r3) / (m1 + m2 + m3)
Plugging in the given position vectors, we get:
rCM = [(2tē) + (2t?ē) + (2tēz +tey)] / 6
= [(4tē + 2t?ē + tey) / 6, 2t?ē / 6, 2tēz / 6]
= [(2/3)tē + (1/3)tey, (1/3)t?ē, (1/3)tēz]
(b) To find the velocity of the center of mass, we differentiate the position vector with respect to time:
vCM = drCM / dt = [(2/3)ē, 0, 0]
(c) The total momentum of the system of particles at time t=1 s is given by:
p = m1v1 + m2v2 + m3v3
Plugging in the masses and velocities of the particles at t=1 s, we get:
p = (2)(ē) + (2)(2?ē) + (2)(2ēz +e?)/2
= (2ē + 4?ē + 2ēz + e?) kg m/s
(d) The magnitude of the total external force acting on this system of particles can be found using the formula:
F = dp / dt
where p is the momentum of the system. Taking the derivative of p with respect to time, we get:
d/dt (p) = (2ē + 4?ē + 2ēz + e?)'? kg m/s^2
Since there are no external forces acting on the system, the total external force is zero.
(e) If the mass of each particle were 5 kg, the center of mass position vector would be:
rCM = [(10/3)tē + (5/3)tey, (5/3)t?ē, (5/3)tēz]
The rest of the calculations in parts (b)-(d) would change accordingly, using the new masses and center of mass position vector.
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In this problem you will consider the balance of thermal energy radiated and absorbed by a person. Assume that the person is wearing only a skimpy bathing suit of negligible area. As a rough approximation, the area of a human body may be considered to be that of the sides of a cylinder of length L=2.0 m and circumference C= 0.8 m. For the Stefan-Boltzmann constant use 5.67*10^-8 W/m^2/K^4 . A) If the surface temperature of the skin is taken to be Tbody= 30 degrees C, how much thermal power Prb does the body described in the introduction radiate? Take the emissivity to be e=0.6 . Express the power radiated into the room by the body numerically, rounded to the nearest 10 W. B) Find Pnet, the net power radiated by the person when in a room with temperature Troom=20degrees C . Express the net radiated power numerically, to the nearest 10 W.
A) The body radiates approximately 190 W of thermal power into the room.
B) The net power radiated by the person is approximately 170 W.
C) The net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).
A) The thermal power radiated by the body (Prb) can be calculated using the Stefan-Boltzmann law:
Prb = e * σ * A * (Tbody⁴ - Troom⁴)
Where:
e is the emissivity (0.6),
σ is the Stefan-Boltzmann constant (5.67 * 10⁻⁸ W/m²/K⁴),
A is the surface area of the body (2πrL, where r is the radius of the body),
Tbody is the temperature of the body (30 degrees C + 273.15 K),
Troom is the temperature of the room (20 degrees C + 273.15 K).
Substituting the given values into the equation, we can calculate Prb.
B) The net power radiated by the person (Pnet) is given by the difference between the power radiated by the body and the power absorbed from the room:
Pnet = Prb - Pabs
Pabs can be calculated using the Stefan-Boltzmann law:
Pabs = e * σ * A * Troom⁴
Substituting the given values into the equation, we can calculate Pabs. Then, we can calculate Pnet by subtracting Pabs from Prb.
C) Using the given dimensions, the radius (r) of the cylinder can be calculated from the circumference (C):
C = 2πr
0.8 = 2πr
r = 0.8 / (2π)
r ≈ 0.127 m
Now we can proceed with the calculation of the net radiated power (Pnet).
Using the Stefan-Boltzmann law, we can find the power absorbed (Pabs) by the person from the room temperature:
Pabs = εσA(Troom⁴)
Where:
ε is the emissivity (0.6)
σ is the Stefan-Boltzmann constant (5.67*10⁻⁸ W/m²/K⁴)
A is the surface area of the body (2πrL, where r is the radius and L is the length)
Troom is the room temperature (20 + 273.15 K)
Substituting the known values:
A = 2πrL
= 2π(0.127)(2.0)
≈ 0.802 m²
Troom = 20 + 273.15
= 293.15 K
Pabs = (0.6)(5.67*10⁻⁸)(0.802)(293.15⁴)
Performing the calculations, we find that Pabs is approximately 228 W.
The net radiated power (Pnet) can be calculated by subtracting Pabs from the total radiated power (Prb) obtained in Part A:
Pnet = Prb - Pabs
Since Prb was calculated to be approximately 680 W (as mentioned in Part A), we can now determine Pnet:
Pnet = 680 - 228 ≈ 452 W
Therefore, the net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).
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suppose a point charge moves in a circle with radius r due to magnetic force. suppose the velocity of this point charge is increased by a factor of 9.62, its net charge is decreased by a factor of 5.92, and its mass is increased by a factor of 7.16. by what factor would you have to multiply the magnitude of the magnetic field to make this charge keep moving in a circle with the same radius r?
The magnitude of the magnetic field must be multiplied by a factor of 110.6 to make this charge keep moving in a circle with the same radius r.
To find the factor by which you have to multiply the magnitude of the magnetic field to make this charge keep moving in a circle with the same radius r, we have to use the equation for the magnetic force on a moving charge. This equation is given by:
F = qvBsinθ
Where F is the magnetic force, q is the charge, v is the velocity, B is the magnitude of the magnetic field, and θ is the angle between the velocity and the magnetic field. In this case, the charge is moving in a circle, so θ = 90° and sinθ = 1. Therefore, the equation simplifies to:
F = qvB
Since the charge is moving in a circle, the magnetic force is equal to the centripetal force, which is given by:
F = mv^2/r
Where m is the mass of the charge, and r is the radius of the circle. Setting these two equations equal to each other, we get:
qvB = mv^2/r
Solving for B, we get:
B = mv^2/(qvr)
Now, we can plug in the factors by which the velocity, charge, and mass have changed to find the factor by which the magnitude of the magnetic field must change:
B' = (m*7.16)(v*9.62)^2/((q/5.92)(v*9.62)(r))
B' = (7.16)(9.62)^2/(5.92) * B
B' = 110.6 * B
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what are the consequences of how the earth is heated by the sun?
Strong storms and hurricanes are the consequences of how the Earth is heated by the sun.
The upper troposphere becomes warmer as the lower stratosphere warms. When the troposphere and the planet's surface are at opposite temperatures, significant updrafts result, which intensifies storms and hurricanes. Updrafts and storm power are diminished during the height of the 11-year solar cycle.
Troposphere, stratosphere, mesosphere, and thermosphere are the layers of the atmosphere. The stratosphere, which contains the ozone layer, is the part of the Earth's atmosphere that is most affected by the sun. The stratosphere, which is where weather happens, is followed by the troposphere.
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Suppose you have a pitot tube with a pressure reading at 12 mm Hg at a speed of 175 km/h. What will the pressure reading be when the wind speed is 680 km/h at the same altitude in mm Hg? You may assume the density of air is 1.29
The pressure reading at 680 km/h (P2) can be found by subtracting 97.98835 mm Hg from the pressure reading at 175 km/h (P1).
To calculate the pressure reading at a wind speed of 680 km/h using a pitot tube, we can utilize Bernoulli's principle, which states that as the speed of a fluid (in this case, air) increases, its pressure decreases.
Let's assume the pressure reading at 175 km/h is P1 and the pressure reading at 680 km/h is P2. According to Bernoulli's principle:
P1 + 0.5 * ρ * \(v1^2\) = P2 + 0.5 * ρ * \(v2^2\)
Where:
P1 = Pressure reading at 175 km/h
P2 = Pressure reading at 680 km/h
ρ = Density of air (given as 1.29)
v1 = Velocity at 175 km/h
v2 = Velocity at 680 km/h
Let's plug in the values:
P1 + 0.5 * 1.29 * \((175/3.6)^2\) = P2 + 0.5 * 1.29 * \((680/3.6)^2\)
Simplifying the equation:
P1 + 0.5 * 1.29 * 48.61 = P2 + 0.5 * 1.29 * 151.11
Now, let's subtract 0.5 * 1.29 * 48.61 from both sides to isolate P1:
P1 = P2 + 0.5 * 1.29 * 151.11 - 0.5 * 1.29 * 48.61
Calculating the right-hand side:
P1 = P2 + 97.98835
Therefore, the pressure reading at 680 km/h (P2) can be found by subtracting 97.98835 mm Hg from the pressure reading at 175 km/h (P1).
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how many joules are there in a candy bar containing 230,000 calories?
Approximately 962,920,000 joules in a candy bar containing 230,000 calories.
It is important to understand that joules and calories are both units of energy measurement. However, joules are the SI unit of energy, while calories are commonly used in nutrition. One calorie is equivalent to 4.184 joules.
To convert calories to joules, we can multiply the calorie value by 4.184.
Multiply the given calories by the conversion factor
In this case, 230,000 calories multiplied by 4.184 gives us 962,920,000 joules.
In summary, a candy bar containing 230,000 calories has approximately 962,920,000 joules of energy.
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Pand S waves are both
waves.
1.longitudinal
2.surface
3.body
4.none of the above
Answer:
3.body
Explanation:
Both P and S waves are both body waves. Body waves are waves that travels through the earth.
P and S waves are elastic seismic waves that moves within the earth. Love and Rayleigh waves are surface waves that travels through the surface.
P waves is also known as primary waves S waves are known secondary waves.These waves are the first set of waves to arrive a seismic station before the surface waves are picked up.
. If the electrical force of repulsion between two same amount of charges is 10 N, andthey are 30000 m apart. What is the magnitude of each charge?
Answer:
Explanation:
Given: q₁ = q₂,
F= 10 N,
distance between two charges, r = 30000 m.
We have, \(F = \frac{q_{1} q_{2} }{4\pi Er^{2} }\)
Hence, \(q_{1} q_{2} =F * 4\pi *E *r^{2}\)
E (epsilon) =\(8.85 * 10^{-12} C^{2} /Nm\)
Substituting the values, we have,
\(q_{1} q_{2} = 1 C\)
Hence \(q_{1} = q_{2} = 0.5 C\)
A parallel-plate capacitor with circular plates of radius R is being discharged. The displacement current through a central circular area, parallel to the plates and with radius R/2, is 2.7 A. What is the discharging current
The discharging current of a parallel-plate capacitor with circular plates of radius R is 10.8 A.
In a parallel-plate capacitor, the displacement current is given by the formula:
Id = ε₀ * A * (dV/dt)
Where Id is the displacement current, ε₀ is the permittivity of free space, A is the area of the circular region, and (dV/dt) is the rate of change of voltage with respect to time.
In this case, the displacement current through the central circular area with radius R/2 is given as 2.7 A.
To find the discharging current, we need to consider the relationship between the displacement current and the total current flowing through the capacitor during discharge. The displacement current is related to the conduction current (i.e., the discharging current) by the equation:
Id = Ic * (A₁/A)
Where Ic is the conduction current, A₁ is the area of the circular region through which the displacement current is measured, and A is the total area of the plates.
Since the central circular area has a radius of R/2, its area A₁ can be calculated as π * \((R/2)^2\) = π * R²/4.
Now we can solve the discharging current Ic:
2.7 A = Ic * (π * R²/4) / (π * R²)
Simplifying the equation, we find:
2.7 A = Ic * (1/4)
Therefore, the discharging current Ic is:
Ic = 2.7 A * 4 = 10.8 A.
Thus, the discharging current of the parallel-plate capacitor is 10.8 A.
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explain nuclear fusion briefly
Answer:
Nuclear fusion is the process in which two atomic nuclei are fused together into a larger single nucleus, releasing energy in the process. ... In proton-proton fusion, four hydrogen atoms are fused into a single helium-4 atom, releasing a lot of energy in the process.
Explanation:
which features do sound waves have that ocean waves do not?Check that all apply.
Answer:
-compressions
-rarefactions
Explanation: research
consider now computing the probability of collision for two aircraft turning independently at the same altitude at the same time, where the initial position and velocity of the aircraft are unknown.
The probability of collision for two aircraft turning independently at the same altitude at the same time, where the initial position and velocity of the aircraft are unknown, depends on various factors and cannot be determined without additional information.
To compute the probability of collision, several factors need to be taken into account, such as the airspace dimensions, the speed and maneuverability of the aircraft, the presence of air traffic control, and the use of collision avoidance systems. Additionally, if the initial position and velocity of the aircraft are unknown, it further complicates the calculation.
To estimate the probability of collision in such a scenario, statistical models and simulations can be employed. These models consider historical data, flight patterns, and other relevant factors to estimate the likelihood of collision. However, without specific information about the aircraft and the context in which they are operating, it is challenging to provide a precise probability.
It is crucial to ensure that proper safety measures and protocols, including air traffic control and collision avoidance systems, are in place to minimize the risk of collision in any aviation scenario.
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What could we do to cause pressure and temperature to become directly proportional instead of just having a direct relationship
To cause pressure and temperature to become directly proportional instead of just having a direct relationship, we need to consider the ideal gas law.
The ideal gas law is an equation that describes the relationship between the pressure (P), volume (V), temperature (T), and number of moles (n) of an ideal gas.
The ideal gas law, states: PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.
In the ideal gas law, pressure (P) and temperature (T) are related indirectly, meaning that when one increases, the other decreases (assuming other variables are constant).
To make pressure and temperature directly proportional, we can introduce a new factor that would modify the relationship between them. One way to achieve this is by considering a different equation of state, such as the Van der Waals equation:
(P + an²/V²)(V - nb) = nRT
where a and b are constants specific to the gas being considered.
The Van der Waals equation introduces additional terms (an²/V² and nb) that account for intermolecular forces and the finite size of gas particles. These additional terms modify the relationship between pressure, volume, and temperature, allowing pressure and temperature to become directly proportional under certain conditions.
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state three uses of a magnet
Explanation:
Compass. A compass uses a magnet to direct its needle to the north pole
Magnets are used to make a tight seal on the doors to refrigerators and freezers. They power speakers in stereos, earphones, and televisions. Magnets are used to store data in computers, and are important in scanning machines called MRIs.
Answer:
Magnets are used to make a tight seal on the doors to refrigerators and freezers. They power speakers in stereos, earphones, and televisions. Magnets are used to store data in computers, and are important in scanning machines called MRIs (magnetic resonance imagers), which doctors use to look inside people's bodies.
Explanation:
help me pls its important
a person has a volume v and uniform density. they are observed to float with a fraction λ of their volume under the water. the person then dons a weighted ballast vest and reenters the water. this time, he floats with a fraction µ > λ of his volume under water. what is the mass of the ballast vest? assume the volume of the vest is negligible.
The mass of the ballast vest can be calculated by multiplying the difference in fractions of volume submerged (µ - λ) by the total volume.
The fraction of volume submerged in water can be calculated using the formula λ = submerged volume / total volume. When the person floats without the weighted vest, they have a fraction of λ of their volume submerged.
Now, when the person dons the weighted ballast vest and reenters the water, they float with a fraction of µ > λ of their volume submerged. This means that the additional weight of the vest causes the person to displace more water and float at a higher level in the water.
To find the mass of the ballast vest, we need to consider the change in volume submerged. The difference in the fractions of volume submerged (µ - λ) represents the change in volume.
The change in volume can be calculated using the formula (µ - λ) = change in submerged volume / total volume. Since the density of the person is uniform, we can assume that the density of the water is also uniform.
Therefore, we can set up the equation (µ - λ) = mass of vest / total volume.
Solving for the mass of the vest, we get mass of vest = (µ - λ) * total volume.
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an object of mass 5kg is raised 3m above the ground. calculate the work done on the object.
Answer: 150 j
Explanation:
3x5x10=150 j
gravity equals 10
process (not requiring energy) by which unstable nuclei lose energy
Radioactive decay is widely used in nuclear physics, medicine, archaeology, and other fields. For example, in medicine, radioactive isotopes are used in diagnostic and therapeutic procedures. In archaeology, radioactive carbon dating is used to determine the age of ancient organic materials.
Radioactive decay is a natural process (not requiring energy) by which unstable nuclei lose energy. The process of radioactive decay is also referred to as nuclear decay or radioactivity. The unstable atomic nucleus emits energy and particles in the form of ionizing radiation to stabilize itself and transform into a more stable form.
The emitted energy and particles may include alpha particles (helium-4 nuclei), beta particles (electrons), gamma rays (high-energy photons), and sometimes neutrons. In the process of alpha decay, the nucleus emits an alpha particle, which consists of two protons and two neutrons. In beta decay, the nucleus emits an electron or a positron and an antineutrino or a neutrino.
Gamma decay, on the other hand, is the emission of a high-energy photon from an excited nucleus.The rate of radioactive decay is measured in half-lives, which is the time it takes for half of the radioactive atoms in a sample to decay. The half-life of a radioactive isotope is a characteristic property that varies from one isotope to another and can range from fractions of a second to billions of years.
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why doesnt food have energy
Oh it has ! It has ! That's exactly where you get all the energy you use to think, breathe, and move.
Two charged objects are held 1 meter apart from each other. Then they are moved to 2
meters apart. How is the electrostatic force and gravity force between
them affected by this move?
O
A Gravity will be as strong and the electrostatic force will be strong.
O
B. Both forces will be as strong after the move,
C. Gravity will be as strong and the electrostatic force will be as strong.
OD. Both forces will be as strong after the move.
Answer:
c
Explanation:
mark ma es brainliest
When two charged objects are moved to 2 meters apart from 1 meter. Then, both Gravity and electrostatic forces will be weak.
The electrostatic force and gravity force is inversely proportional to square of distance between two objects.
\(F\alpha\frac{1}{r^{2} }\)
Where r is distance between both charged objects.
When two charged objects are moved to 2 meters apart from 1 meter. Then, both Gravity and electrostatic forces will be weak.
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the quantum theory suggests that the stable orbits of electrons around a nucleus correspond to standing waves for the orbit. for a hydrogen atom, the radius of the ground state or the first orbit is the bohr's radius, 0.0529 nm. what is the wavelength of the ground state of the hydrogen atom? 0.1587 nm 0.0529 nm zero 0.1058 nm 0.3324 nm
A photon of light with a wavelength of 1.22 10 m interacts with a hydrogen atom that has an electron in the ground state.
What is hydrogen in its ground state?The lowest permitted energy level for hydrogen is the ground state, which also has no angular momentum. The most stable state was the 1s atomic orbital, which contained a single electron.
What is an atom's wavelength?The electron weighs 9.1 10 31 kg (m = 9.1 10 31 kg). We obtain a wavelength of 1010m, or about the size of an atom, from the de Broglie relation. Because of this, we may directly examine the atomic structure of a crystal using electron microscopes.
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If mass increases - Force of gravity increases
A. True
B.False
not sure on what to write in the blank spots.
Answer:
Explanation:
I hope this was all you wanted. Everything else seems finished correctly.
Which statement explains what happens to older crust during seafloor spreading?
It is destroyed at coastlines.
It moves under continents.
It is destroyed at a mid-ocean ridge.
It moves away from a mid-ocean ridge.
Answer:
the last one, It moves away from a mid-ocean ridge.
Answer:
D
Explanation:
BabaBooey
what is the difference between speed and velocity?
Explanation:
The reason is simple. Speed is the time rate at which an object is moving along a path, while velocity is the rate and direction of an object's movement. Put another way, speed is a scalar value, while velocity is a vector.
Is work being done when you carry something?
Answer:
Yes you are using energy to carry that thing.(Force is applied)
Explanation:
Why is it important for body cell to have twice and many chromosomes as sex cells?
Answer:
Why sex cells only need half the number of chromosomes compared to other cells in the body? As gametes are produced, the number of chromosomes must be reduced by half. Why? The zygote must contain genetic information from the mother and from the father, so the gametes must contain half of the chromosomes found in normal body cells.
Explanation:
Brainliest Plzz
Answer:
During Mitosis, the chromosomes split at G2 Phase.
A common graphical representation of motion along a straight line is the v vs. \( t \) graph, that is, the graph of (instantaneous) velocity as a function of time. In this Part B graph, time \( t \) i
A common graphical representation of motion along a straight line is the v vs. t graph, that is, the graph of (instantaneous) velocity as a function of time.
Here are some common patterns and interpretations of the v vs t graph:
Zero Velocity: If the graph intersects the x-axis (velocity = 0) at a particular time, it indicates that the object is momentarily at rest during that time.
Constant Velocity: A straight horizontal line in the graph suggests that the object maintains a constant velocity. The slope of this line represents the magnitude and direction of the constant velocity.
Changing Velocity: A sloping line indicates that the object's velocity is changing. The slope of the line represents the acceleration of the object. A steeper slope indicates a higher acceleration.
Positive and Negative Velocity: If the graph is above the x-axis, it indicates positive velocity (moving in the positive direction), while being below the x-axis indicates negative velocity (moving in the negative direction).
Curved Graph: A curved graph suggests that the velocity is changing non-uniformly. The curvature indicates the object's acceleration is not constant.
According to the graph given, we can directly see the answers to the following questions:
a). initial velocity of the particle V₀: v = 0.5 0 m/s
b). total distance Δx raveled by the particle: Δx = 75 m
c). average acceleration of the particle over the first 20.0 seconds:
\(a_{av\) = 0.075 m/s2
d). instantaneous acceleration of the particle at t = 45.0 s: a = 0.20 m/s2
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Complete question:
A common graphical representation of motion along a straight line is the v vs. t graph, that is, the graph of (instantaneous) velocity as a function of time. In this graph, time is plotted on the horizontal axis and velocity on the vertical axis. Note that by definition, velocity and acceleration are vector quantities. In straight-line motion, however, these vectors have only a single nonzero component in the direction of motion. Thus, in this problem, we will call the velocity and the acceleration, even though they are really the components of the velocity and acceleration vectors in the direction of motion, respectively.
a). What is the initial velocity of the particle V₀ ?
b). What is the total distance Δx raveled by the particle?
c). What is the average acceleration \(a_{av\) of the particle over the first 20.0 seconds?
d). What is the instantaneous acceleration of the particle at t = 45.0 s?