Answer:
2
Explanation:
Based on the chemical equation, the number of molecules of hydrogen gas in the reactant side is 2.
This is indicated by the coefficient before reactant.
A molecule is a covalent compound that has discrete or separate units.
So H₂ is made up of two atoms of hydrogen that has been covalently bonded together by sharing their valence electrons.
From the reaction expression:
2 molecules of hydrogen gas combines with 1 molecule of oxygen gas to produce 2 molecules of water.
A 5.00-L tank contains helium gas at 1.50 atm. What is the pressure of the gas when the volume increased to 4.5atm?
Answer:
the pressure of the gas is 1.67 atm when the volume increased to 4.5 L.
Explanation:
Assuming the temperature and the amount of gas remain constant (i.e., the process is isobaric):
Using Boyle's law, we can relate the initial pressure (P1) and volume (V1) to the final pressure (P2) and volume (V2):
P1V1 = P2V2
Plugging in the given values:
P1 = 1.50 atm
V1 = 5.00 L
V2 = 4.5 L
Solving for P2:
P2 = (P1V1)/V2 = (1.50 atm x 5.00 L)/4.5 L = 1.67 atm
PLEASE HELP
C. Balance these fossil-fuel combustion reactions. (1 point)
Answer:
C8H18(g) + 12.5O2(g) -> __8__CO2(g) + 9H2O(g) + heat
CH4(g) + _2___O2(g) -> ____CO2(g) + _2___H2O(g) + heat
C3H8(g) + _5___O2(g) -> _3___CO2(g) + __4__H2O(g) + heat
2C6H6(g) + __15__O2(g) -> __12__CO2(g) + __6__H2O(g) + heat
Explanation:
I hope it helps!
Fossil fuels are natural energy resources formed from the remains of ancient plants and organisms, such as coal, oil, and natural gas, which are burned to release energy.
Balanced reactions are as follows:
C₈H₁₈ (g) + 12.5O₂ (g) → 8CO₂ (g) + 9H₂O(g) + heat
CH₄ (g) + 2O₂ (g) → 1CO₂ (g) + 2H₂O (g) + heat
C₃H₈ (g) + 5O₂ (g) → 3CO₂ (g) + 4H₂O (g) + heat
C₆H₆ (g) + 7.5O₂ (g) → 6CO₂ (g) + 3H₂O (g) + heat
A combustion reaction, also known as a combustion process, is a chemical reaction in which a substance combines with oxygen to produce heat and light. It involves the rapid oxidation of a fuel in the presence of an oxidizer, typically atmospheric oxygen. The reaction releases energy in the form of heat and light.
The general equation for a combustion reaction can be represented as: fuel + oxygen → carbon dioxide + water + energy.
Combustion reactions are essential for various processes, including the burning of fossil fuels for energy production, combustion engines in vehicles, and even the process of respiration in living organisms.
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How many moles of carbon dioxide are present if the sample contains
11.8 x 10^23 atoms of oxygen? Assume all the oxygen atoms are part of
carbon dioxide molecules.
Answer: 0.983 moles of carbon dioxide are present
Explanation:
To determine the number of moles of carbon dioxide (CO₂) present when there are 11.8 x 10²³ atoms of oxygen, we need to consider the molecular formula of carbon dioxide.
The molecular formula of carbon dioxide (CO₂) indicates that there is one carbon atom and two oxygen atoms in each molecule of carbon dioxide.
Given that there are 11.8 x 10²³ atoms of oxygen, we can divide this number by 2 to determine the number of carbon dioxide molecules present, since each molecule of carbon dioxide contains two oxygen atoms.
Number of carbon dioxide molecules = \(\frac{11.8 X 10^2^3 atoms of oxygen }{2}\)
Next, we can use Avogadro's number, which states that there are approximately 6.022 x 10²³molecules per mole, to convert the number of carbon dioxide molecules to moles.
Number of moles of carbon dioxide = (11.8 x 10²³ atoms of oxygen / 2) / (6.022 x 10^23 molecules per mole)
Evaluating this expression, we get:
Number of moles of carbon dioxide = 0.983 moles
If the mass of a stick of butter________ then no mass was created when it melted
Answer:
decreases
Explanation:
Melting is the process of turning solid materials into liquids by introducing heat. If the mass of a stick of butter decreases then no mass was created when it melted.
Melting is the process of a solid changing from a solid to a liquid when heated to a specific temperature. The set temperature at which a solid begins to transform into a liquid is known as the melting point.
A substance will change from a solid to a liquid when the temperature is raised to its melting point. since of this, the substance's volume will grow since its molecules will be spaced more apart.
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Using Graham's Law of Effusion, calculate
the approximate time it would take for
1.0 L of argon gas to effuse, if 1.0 L of
oxygen gas took 12.7 minutes to effuse
through the same opening.
0.070 minutes
0.89 minutes
None of the other answers
14 minutes
12 minutes
The rate of effusion of Argon here is 8.03 min
Data;
Molar mass of Oxygen = 16g/molTime for effusion of oxygen = 12.7 minMolar mass of Argon = 40g/molTime for effusion of Argon = ?Graham's Law of EffusionThis law states that the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.
\(R \alpha \frac{1}{\sqrt{M} }\)
From this,
\(\frac{r_1}{r_2} = \frac{\sqrt{M_2} }{M_1}\)
substituting the values and solving,
\(\frac{R_A_r}{12.7}= \frac{\sqrt{16} }{\sqrt{40} } \\ R_A_r = \frac{12.7*\sqrt{16} }{\sqrt{40} } \\R_A_r = 8.032min\)
The rate of effusion of Argon here is 8.03 min
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NBC PA 400 was published on 11/21/2019 and became effective on 01/01/2020. This standard converges with the international standard Part 4A of the Code of IFAC (CFC, 2019). NBC PA 400 addresses aspects that may interfere with auditor independence and the concept of independence (CFC, 2019). Thus, the Independent Auditor who does not have Independence in relation to the audited organization is not able to carry out an Independent Audit in this organization. Another norm that addressed Independence is NBC PA 290, but it was revoked as of 01/01/2020
In reality, Marina observed that the independent auditor Ulisses does not have an established link with the organization, therefore, situations II and III, regarding the loan by the auditor or even the charging of differentiated fees, did not exist, being one punctual activity carried out by the same, not the establishment of a partnership for example. Only the first alternative is correct.
¿How did the auditor Ulisses Celestino de Goés act?to identify the activity of the base professional is to understand the role of Ulisses, that is, without a direct relationship between the parties, the auditor aimed to carry out adequate control over the activities, seeking to order a series of functions, in addition to an expanded action for carrying out the work.
Completing:
I. Marina analyzed that the Independent Auditor Ulisses Celestino de Goés does not have any type of financial relationship with the audited organization. Marina concluded that in this situation Auditor Ulisses Celestino de Goés was Independent.
II. Marina analyzed that the Independent Auditor Ulisses Celestino de Goés was auditing a Financial Institution in which he was requesting a loan for his company of R$ 50,000.00 (a large amount). Marina concluded that in this situation, in which Ulisses Celestino de Goés requested loans from the Audited organization, Auditor Ulisses Celestino de Goés was Independent.
III. Marina analyzed that the Independent Auditor Ulisses Celestino de Goés charged differentiated fees (a lower amount than the standard charged in other audit services). Marina concluded that in this situation, in which Ulisses Celestino de Goés charged different fees.
which gas is fossil fuel
Answer:
methane
Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp
Determine the number of carbon atoms in 1.00 kg of carbon dioxide.
____X 10__atoms(Enter your answer in scientific notation.)
Determine the number of oxygen atoms in 1.00 kg of carbon dioxide.
____X 10__atoms (Enter your answer in scientific notation.)
Calculate the mass of potassium nitrate that contains 1.00 mol of oxygen atoms.
_____g
—Pls show steps!! I’m so confused and need help—
Answer:
1.37x10²⁵atoms of carbon
2.74x10²⁵ atoms of oxygen.
33.7g of KNO₃
Explanation:
To answer this question you must use molar mass of carbon dioxide (44g/mol) and 1 mole are 6.022x10²³atoms.
1.00kg are 1000g of CO₂. Moles are:
1000g CO₂ * (1mol / 44g) = 22.73 moles of CO₂ = 22.73 moles of carbon.
In atoms:
22.73 moles C * (6.022x10²³atoms / 1mole) = 1.37x10²⁵atoms of carbon
There are 22.73 moles of CO₂ * 2 = 45.45 moles of oxygen are present in the carbon dioxide. In atoms:
45.45 moles Oxygen * (6.022x10²³atoms / 1mole) = 2.74x10²⁵ atoms of oxygen.
1 mole of Potassium nitrate, KNO₃, contains 3 moles of oxygen. 1 mol of oxygen are:
1.00 mol O * (1mol KNO₃ / 3 moles O) = 0.33 moles of KNO₃
As molar mass of KNO₃ is 101.1g/mol:
0.33 moles of KNO₃ * (101.1g / mol) = 33.7g of KNO₃
Answer:
1. 1.37 * 10^25 atoms of carbon
2. 2.74 * 10^25 atoms of oxygen
3. 33.67g of Potassium Nitrate
Explanation:
2. Firstly, we want to know the number of atoms of oxygen in 1 kg of carbon dioxide.
Firstly, we will need to know the number of moles of carbon iv oxide in 1kg of carbon iv oxide
Mathematically;
number of moles = mass/molar mass
molar mass of carbon iv oxide is 44 g/mol
mass here is 1000g (1kg is 1000g)
So the number of moles of CO2 in 1kg of CO2 will be; 1000/44 = 22.73 moles
Now 1 mole of CO2 contains 2 atoms of oxygen, thus 1 mole of CO2 contains 2 moles of oxygen
So the number of moles of oxygen in 1kg CO2 will be 2 * 22.73 = 45.46 moles
Mathematically, 1 mole contains 6.02 * 10^23 atoms
So 45.46 moles will contain =
6.02 * 10^23 * 45.46 = 2.74 * 10^25 atoms of oxygen
1. 1 mole of co2 contains 1 atom of carbon , thus, 1 mole of CO2 will
contain 1 mole of carbon
From above, 1kg of carbon iv oxide contains 22.73 moles , thus 1kg of carbon iv oxide will contain 22.73 moles of carbon too
So the number of atoms will be 22.73 * 6.02 * 10^23 = 1.37 * 10^25 atoms
3. Mass of KNO3 that contains 1 mole of oxygen atom
From the formula of the compound, we can see that 1 mole of KNO3 contains 3 atoms of oxygen which translates to 3 moles of oxygen
So 1 mole of oxygen will translate to 1/3 mole of KNO3
Mathematically;
mass = number of moles * molar mass
Molar mass of KNO3 = 39 + 14 + 3(16) = 39 + 14 + 48 = 101 g/mol
So the mass will be = 1/3 * 101 = 33.67g
Reflect on the learning activities titled “Hypothesis”, “Variables and Hypothesis” and “Constructing a Hypothesis”. Describe some similarities and differences between a question that comes in response to an observation, and a scientific research question? Cite quotes from the readings to support your answer. Where do variables fit into this thinking? In other words, if you imagine a number line with observation questions at one end and scientific research questions at the other, what role do variables play anywhere along this continuum?
The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.
The following quotes from the readings illustrate this distinction:"A scientific question is one that can be answered by using scientific investigation. In contrast, an observation question is one that comes in response to observing or experiencing something in the natural world" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."An important feature of a scientific question is that it should be answerable within a reasonable amount of time and with the resources available" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Research questions can be narrow or broad, depending on the scope of the research" (Constructing a Hypothesis).The concept of variables is crucial to both observation and scientific research questions, but they play different roles depending on where they fall on the continuum. Observation questions are usually less precise and may not require much consideration of variables. On the other hand, scientific research questions are likely to include a rigorous examination of variables and their potential effects."Variables are an essential part of a scientific experiment. They are the things that change in an experiment" (Scientific Inquiry: Variables, Hypotheses, and the Scientific Method)."Variables are important because they can affect the outcome of the research" (Constructing a Hypothesis).In summary, observation questions and scientific research questions share some similarities, but the latter is more specific, has a defined methodology, and may require more consideration of variables.For such more question on Hypothesis
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9. Which of the following gas laws is calculated with the pressure and
volume variables at a constant temperature?
Formula
4 points
P₁V₁ = P₂V₂
P₁ = first pressure
P2 = second pressure
V₁ = first volume
The gas law that is calculated with the pressure and volume variables at a constant temperature is Boyle's Law. Boyle's Law states that the pressure (P) of a gas is inversely proportional to its volume (V) when temperature (T) is held constant.
Mathematically, it is expressed as P₁V₁ = P₂V₂, where P₁ and V₁ represent the initial pressure and volume, and P₂ and V₂ represent the final pressure and volume.According to Boyle's Law, if the volume of a gas is reduced while keeping the temperature constant, the pressure will increase proportionally.
Similarly, if the volume is increased, the pressure will decrease. This relationship holds as long as the temperature remains constant throughout the process. Boyle's Law is one of the fundamental gas laws and provides insights into the behavior of gases under changing pressure and volume conditions at a constant temperature.
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2.00 cm x 8.00 cm x 16.0 cm=
PLEASE HELP!!!
How many calories are in 4,180 joules?
Answer:
To convert joules to calories, you can use the conversion factor:
1 calorie = 4.184 joules
To find out how many calories are in 4,180 joules, divide the given value by the conversion factor:
4,180 joules / 4.184 joules per calorie = 0.9 calories (approximately)
Therefore, there are approximately 0.9 calories in 4,180 joules.
If a chemical reaction is at equilibrium, why is the forward reaction rate not equal to zero?
Answer: At equilibrium, the rates of the forward and reverse reactions are equal. One way to think of it is that the forward and reverse reactions are canceling each other out to produce an equilibrium.
If the rate of a reaction were zero, then the rates of the forward and reverse reactions would be constant. This is only true of the concentrations. For a reaction to reach equilibrium, there has to be some change in the rates of the forward and reverse reactions. If the rates are zero from start to end then no reaction would occur.
Remember, if the forward reaction rate was zero, then the reverse reaction rate would also have to be zero which would produce a total equilibrium that doesn't change at all. Concentrations are constant because equal moles of products from the forward reaction are being turned into reactants by the reverse reaction. This is only at equilibrium.
Hope this helps!
An argon ion laser emits visible radiation with photons of energy 4.071 x 10-19 J. What is the
wavelength of the radiation?
The wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).
Wavelength is a property of any type of wave that refers to the distance between two adjacent points on the wave that is in phase, i.e., at the same point in their respective cycles. It is usually denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters or nanometers.
The energy carried by the photon (E) is related to the wavelength (\(\lambda\)) through the following equation:
\(E=hc/\lambda\); where 'h' is the Plank's Constant and 'c' is the speed of light which is \(3* 10^{-7} m/s\).
We can say that
\(\lambda - hc/E\)
Now after substituting the given values, we get:
\(\lambda = (6.626 * 10^{-34} J.s * 3.00 * 10^8 m/s) / (4.071 * 10^{-19} J)\\\lambda = 4.854 * 10^-7 m\)
Therefore the wavelength of the radiation emitted by the argon ion laser is \(4.854 * 10^-7 m\).
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what is the photoelctric effect?
Explanation:
It is the emission of electron from a metal under the effect of light is known as photo electric effect
I hope this imformation help full for you
How many significant digits should be used to report the answer to each of the following calculations? (2.75518 + 9.01 + 3.3349) / (2.1)
Answer:
2
Explanation:
You write your answer with the same number of significant figures as the number with the smallest amount of figures, in this case, that number is 2.1 so your answer should be written with 2 significant figures.
Chlorine reacts with sodium and with hydrogen.
Compare the structure and bonding in sodium chloride and hydrogen chloride.
Answer:
Sodium Chloride has Ionic bond while Hydrogen Chloride has covalent bond.
Explanation:
Na has 11 electrons (2, 8, 1) and need to give away 1 electron to be stable
Cl has 17 electrons ( 2, 8, 7) and needs 1 electron to be stable.
Na transfers 1 electron to CL to form Ionic bond.
While
Hydrogen has 1 electron and shares with Chlorine to be stable.
Covalent bond involves sharing.
Chlorine reacts with sodium to form ionic sodium chloride while chlorine reacts with hydrogen to form covalent hydrogen chloride.
The nature of bonding between atoms depends on their relative difference in electronegativity.
Chemical bonding is the process by which atoms come together to form compounds.
There are different kinds of chemical bonds;
Ionic or electrovalent bondCovalent bondMetallic bondAn ionic bond is formed when there is high electronegativity difference between the bonding atoms. Typically, this type of bond is formed when the electronegativity difference is about 2.0 and above.
For a covalent bond, an electronegativity difference of about 0.4 - 1.7 is considered a polar covalent bond. Lower values of electronegativity difference corresponds to a nonpolar bond.
The electronegativity difference between sodium and chlorine is about 2.23. This corresponds to a pure ionic bond. The compound is composed of chlorine and sodium ion pairs alternately located in a crystal lattice as shown in the image attached.
The electronegativity difference between chlorine and hydrogen is about 0.96. This corresponds to a polar covalent bond. The negative end of the dipole points towards chlorine while the positive end of the dipole points towards hydrogen.
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Mg(s) + Ni2+(ag) -> Mg2+ (aq) + Ni(s) What is the total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag)? * 10 ( 1.0 mol ,20 mol ,3.0 mol, 4.0 mol
The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.
How to find the number of moles?This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).
In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).
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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.
What is the number of the electrons gained?We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.
In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.
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How many moles are in 1.5 x 10^23 atoms of fluorine?
Answer: 0.125 moles F2
Explanation: 1.5x1023 atoms of F = 0.75x10^23 molecules F2
moles F2 = 0.75x10^23/avogadro number = 0.125 moles
There are 0.25 moles in 1.5 x \(10^{23}\) atoms of fluorine.
Given,
How many moles are in one atom?
In one mole we have,
6.02 x \(10^{23}\) atoms.
1 mole = 6.02 x \(10^{23}\) atoms
Find the number of moles in 1.5 x \(10^{23}\) atoms of fluorine.
We have,
1 mole = 6.02 x \(10^{23}\) atoms
Multiply 1.5 x \(10^{23}\) / 6.02 x \(10^{23}\) on both sides
1.5 x \(10^{23}\) / 6.02 x \(10^{23}\) x 1 mole = 1.5 x \(10^{23}\) / 6.02 x \(10^{23}\) x 6.02 x \(10^{23}\) atoms
1.5/6.02 mole = 1.5 x \(10^{23}\) atoms
0.25 moles = 1.5 x \(10^{23}\) atoms.
Thus there are 0.25 moles in 1.5 x \(10^{23}\) atoms of fluorine.
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For a concave mirror, incident light beams through C will reflect:
(a) back through C
(b) through F
(c) parallel to PA
Answer:
c
Explanation:
Hey guys! Can anyone help me out? I'm not familiar with the formula (equation) at all! :(
CO2 makes up 0.0314% of Earth’s atmosphere. Convert that into parts per million.
Answer:
419 parts per million
Explanation:
The amount of carbon dioxide in Earth's atmosphere reached 419 parts per million in May, its highest level in more than four million years, the National Oceanic and Atmospheric Administration announced on Monday.
Hope it helps <3
after the equilibrium represented above is established, some pure o2(g) is injected into the reaction vessel at constant temperature. after equilibrium is reestablished, which of the following has a lower value compared to its value at the original equilibrium?
The amount of SO₂(g) in the reaction vessel has a lower value compared to its value at the original equilibrium. Option d is correct choice.
Injecting pure O₂(g) into the reaction vessel at a constant temperature will cause the system to shift towards the right side of the equation in order to consume the added O₂. This means that the amount of SO₂(g) in the reaction vessel will decrease, while the amount of SO₃(g) and O₂(g) will increase.
Since the reaction is exothermic, adding O₂(g) will not change the equilibrium constant (Keq) of the reaction, so (A) is not affected. However, the amount of O₂(g) in the reaction vessel will increase, so (C) has a higher value compared to its value at the original equilibrium.
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--The complete question is, 2SO(g) <-> 2SO₂(g) + O₂(g)
After the eq. represented above is established, some pure O₂(g) is injected into the reaction vessel at a constant temperature. After equilibrium is reestablished, which of the following has a lower value compared to its value at the original equilibrium?
A. Keq for the reaction
B. The amount of SO₃(g) in the reaction vessel
C. The amount of O₂(g) in the reaction vessel.
D. The amount of SO₂(g) in the reaction vessel.--
(NH4) (OH) is compound soluble or insoluble?
An inorganic fungicide, microbiocide, and herbicide is ammonium hydroxide. It is very soluble in water and non-volatile.
In Ammonium hydroxide Ammonium Chloride, which hydroxide is insoluble?Because of its extremely high solubility product, magnesium hydroxide, also known as Magnesium hydroxide, is insoluble in Ammonium hydroxide. Nevertheless, when Ammonium Chloride is present, the following reaction occurs, and the magnesium hydroxide dissolves.
Why does water include Ammonium hydroxide?Ammonia is dissolved in water to form ammonium hydroxide (Ammonium hydroxide). The substance, also known as ammonia or ammonia water, is used as a cleaner and in the production of plastics, rubber, fertiliser, and textiles. It is a clear, colourless liquid with a strong to barely detectable ammonia odour.
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describe the temperature and pressure conditions at which the gas behaves like an ideal gas
Under specific temperature and pressure conditions, a gas acts as an ideal gas. Particularly, the optimal conditions for the petrol' behaviour are low pressure and high temperature.
An ideal gas is a hypothetical gas made up of numerous tiny particles moving randomly all the time. Intermolecular forces, molecular size, and volume are all presumptions that apply to ideal gases. Additionally, it is presummated that they collide in completely elastic collisions in which there is no kinetic energy loss. The ideal gas law, PV=nRT, which has P as the pressure, V as the volume, n as the number of moles, R as the gas constant, and T as the temperature, can be used to describe the behaviour of an ideal gas. This law offers a helpful model for how many actual gases behave when exposed to situations like high temperatures and low pressures.
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Which of the following is NOT conserved during the combustion reaction of propane shown below? Select all that apply.
C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
moles of molecules
moles of atoms
atoms
mass
none of the above
The variable that is not conserved during the combustion reaction of propane as shown by the equation would be none of the above.
Recall that the law of conservation says that atom/matter/mass is conserved in the course of reactions, although forms might change.
The number of moles of each atom is conserved because both the reactant and product sides have equal numbers of each atom that make up the compounds.
Unless the reaction is not carried out in an isolated system, the mass should be conserved. In other words, the total mass of the reactants must be equal to the total mass of the products. If the system is not isolated, materials may be exchanged with the surroundings and this might make the mass not to be conserved.
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Draw a structural formula for the major product of the reaction shown.
Draw a structural formula for the major product of the reaction shown:
The structural formula for the major product (2-butene) of the given reaction is as follows:$$\ce{CH3CH2CH=CH2}$$
The given reaction is an acid-catalyzed dehydration reaction.
During the reaction, the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the reactant alcohol (2-butanol) undergo dehydration (loss of water) to form an alkene (2-butene) as the major product.
The reaction is shown below:$$\ce{CH3CH2CH2CH2OH + H2SO4 ->[\Delta] CH3CH2CH=CH2 + H2O}$$To draw the structural formula for the major product of the given reaction, we need to consider the following points:
1. The reactant alcohol (2-butanol) is a four-carbon alcohol with the hydroxyl group (OH) attached to the second carbon atom (C2) of the chain.
2. The product alkene (2-butene) will be a four-carbon alkene with a double bond between the second and third carbon atoms (C2 and C3) of the chain.
The other two carbon atoms will have a single bond with the adjacent carbon atoms and a hydrogen atom each attached to them.
3. The major product will be formed via the elimination of water (dehydration) between the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the second carbon atom (C2) of the reactant alcohol (2-butanol).
4. The acid catalyst (H2SO4) does not participate in the reaction and remains unchanged. It only facilitates the formation of the alkene by providing a proton (H+) to the hydroxyl group (OH) and a medium for the elimination of water.
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Which choice gives the correctly
balanced equation for this reaction?
AgNO3(aq) + Na₂CO3(aq) →
Ag₂CO3(s) + NaNO3(aq)
The reaction's chemically balanced equation is as follows:3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4
Which option provides the reaction's properly balanced equation?The reaction's chemically balanced equation is as follows:3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4A chemical reaction that has the same number of moles in the reactant and product sides is said to have a balanced chemical equation.
Determining that the chemical reaction is a balanced chemical equation, it follows the law of conservation of mass.
The missing image, which is included below, shows what the picture represents:
The side that reacts:
Three molecules each of CH4 and N2Cl4
The component side:
6 molecules of H2, 3 molecules each of CCl4, N2, and 3.
Consequently, the following is the reaction's balanced chemical equation:
3CCl4 + 3N2 + 6H2 = 3CH4 + 3 N2Cl4
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Syrup used for hummingbird feeders is commonly 25% sucrose (C12H22O11) by mass. if you wish to make 1.0 kg of this soltion, what calculate the quantitity of sucrose and the quantitiy of water that you should use.
Calculate the molality (m) of the 25% sucrose solution in the question above,
The density 25% a sucrose solution at room temperature is 1.10 g/mL. calculate the molarity (M) of the 25% sucrose solutino.
Answer:
m
Explanation:
Calculate the amount of copper (in moles) in a 45.2 g pure copper sheet
Answer:
0.712 mol
Explanation:
The easiest way to do this is to use a proportion.
1 mol of copper = 63.5 grams (check this using your periodic table).
x mol of copper = 45.2 grams
1/x = 63.5 / 45.2 Cross multiply
63.5 x = 1 * 45.2 Divide by 63.5
x = 45.2/63.5
x = 0.712 mol Answer to 3 sig digs
Why does the ionization energy decrease as you move down a group on the periodic table?
More neutrons in the nucleus
More electrons in the outer energy level
The size of the atom increases
Answer:
1) As you move down a group, first ionization energy decreases. WHY? Electrons are further from the nucleus and thus easier to remove the outermost one. 2) As you move across a period, first ionization energy increases.
so i think it is b
Explanation: