Based on the fact that the shunt resistance rshunt forms a parallel combination with the voltmeter resistance rshunt, the req calculated in question 4 should be given by:_________

Answers

Answer 1

Based on the fact that the shunt resistance (Rshunt) forms a parallel combination with the voltmeter resistance (Rv), the equivalent resistance (Req) calculated in question 4 should be given by the reciprocal of the sum of the reciprocals of Rshunt and Rv.

In a parallel combination of resistors, the total resistance (Req) is calculated using the formula: 1/Req = 1/R1 + 1/R2 + 1/R3 + ... + 1/Rn. In this case, Rshunt and Rv are connected in parallel, so their reciprocal values can be added together to determine the reciprocal of Req.

Mathematically, the formula for the equivalent resistance (Req) is:

1/Req = 1/Rshunt + 1/Rv

To find Req, we take the reciprocal of both sides of the equation:

Req = 1/(1/Rshunt + 1/Rv)

Therefore, based on the parallel combination of Rshunt and Rv, the equivalent resistance (Req) can be calculated using the reciprocal of the sum of the reciprocals of Rshunt and Rv.

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<The question is incomplete, so this is answer>


Related Questions

Rahul is carrying a load of 80 kg along a distance of 200 meters in 5 minutes. But the same load is carried by reena to the same distance in 4 minutes. Who had more power? Also show by calculation .​

Answers

Answer:

Reena

Explanation:

200 / 5 = 40 metres in a minute

200 / 4 = 50 metres in a minute,

Therefore Reena is faster

What is the rotational inertia of the following body about the indicated rotation axis? (The masses of the connect ing rods are negligible.)

Answers

The solution would involve identifying the relevant masses and distances, squaring the distances, multiplying by the masses, and summing them up to obtain the total rotational inertia.

When solving a physics problem, the first step is to clearly identify the given information, what is being asked, and any relevant equations or principles that apply. This problem provides a diagram of a rotating body and asks for its rotational inertia about a specific axis.

The problem also specifies that the masses of the connecting rods can be ignored. Rotational inertia, also known as moment of inertia, is a property of a rotating object that depends on its mass distribution and the axis of rotation. It can be calculated using the equation I = ∑mr², where I is the rotational inertia, ∑m is the sum of the masses, and r is the distance from the axis of rotation to each mass element squared.

Given the information in the problem and applying the relevant equation, the rotational inertia of the body about the indicated rotation axis can be calculated. To find the total rotational inertia, the answer would entail determining the pertinent masses and distances, squaring the distances, multiplying by the masses, and adding the results together.

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High beam headlights light above the roadway: Group of answer choices 50'-100' 500'-1800' less than 50' 2000'-8000'

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High-beam headlights typically illuminate a distance of 500'-1800' above the roadway. This means that drivers can see ahead of them for a considerable distance, giving them enough time to react to any obstacles or hazards in their path.

However, it's important to note that the height of the beam can vary depending on the terrain and other factors. In some cases, the beam may be lower, such as in urban areas or on roads with low visibility due to fog or heavy rain. In these situations, drivers may need to rely on other lighting sources or adjust their driving speed accordingly to ensure safety on the roads.
When using high-beam headlights, they typically light up the roadway at a distance of 200-250 meters (approximately 650-820 feet), which falls within the range of 500'-1800'. Remember to switch to low beams when approaching oncoming traffic or when driving behind another vehicle to avoid blinding other drivers. Overall, high beam headlights provide an essential tool for safe and effective driving, allowing drivers to see further and react faster to potential hazard

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Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .

Answers

Answer: Medial rotation

Lateral rotation

Supination

Pronation

Opposition

Explanation:

Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.

Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.

Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.

Pronation is the downward motion of hand to put things down.

Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.

i points A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T -2were is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct? When showing your work to turn in, make sure to show that you found the unit of k using dimensional analysis rather than by looking it up. Show (in the work you turn in) that this is equivalent to the units of N/m. This answer has not been graded yet. 2 2- 2 づ丁2- .C

Answers

Question 1

T=2*pi*sqrt(m/k) 

dimension of T=sec

dimension of 2*pi=nil(dimensionless)

dimension of m=kg

equation dimension

sec=sqrt(kg/k)

sec^2=kg/k

k=kg/sec^2

so dimension of k will be 

MT^(-2) 

dimension of N/m=kgms^(-2)/m=kgs^(-2) so it is same 

Question 2

F=Gm1*m2/r^2

Dimension of F=MLT^(-2)

MLT^(-2)=G*M*M/L^2

G=ML^3T^(-2)/M^2=M^(-1)L^(3)T^(-2)

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i points A spring is hanging down from the ceiling, and an object of mass m is attached to the free end.

What does it mean when there is a curved line going upwards on a graph?

science 8th grade :)

Answers

Answer: it is the asymptote

Explanation: a line that continually approaches a given curve but does not meet it at any finite distance.

16.) A person walks 4 meters east, then walks 3 meters north. Determine distance and
displacement.​

Answers

Answer:

Long question good luck:)

Explanation:

Answer:7

Explanation:

because its the right answer

1.²₁ f(x) dx, where x ≤ n f(x) = { sin (x), -3 sin(x), X > T (Express numbers in exact form. Use symbolic notation and fractions where needed.) 2x 1² f(x) dx = Calculate

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The given problem involves calculating the definite integral of a function f(x) over a specific range. The function f(x) is defined differently for different values of x, and the final result of the definite integral \(1^2\)₁ f(x) dx, where x ≤ n, is -cos(n) - (-cos(1)) + 3cos(T) - 3cos(n) + infinity.

To calculate the definite integral 1²₁ f(x) dx, where x ≤ n, we need to evaluate the integral of the given function f(x) over the specified range. The function f(x) has different definitions depending on the value of x. For x ≤ n, the function is sin(x), and for x > n, the function is -3sin(x). Additionally, the function is defined as 2x for values of x greater than a certain threshold T.

To solve this problem, we need to consider the different intervals of the range separately. First, we integrate sin(x) over the interval 1 to n. The integral of sin(x) is -cos(x), so the value of this part of the integral becomes -cos(n) - (-cos(1)).

Next, we need to integrate -3sin(x) over the interval n to T. The integral of -3sin(x) is 3cos(x), so this part of the integral becomes 3cos(T) - 3cos(n).

Lastly, we integrate 2x over the interval T to infinity. The integral of 2x is \(x^2\), so this part of the integral becomes infinity.

Combining these three parts, the final result of the definite integral \(1^2\)₁ f(x) dx, where x ≤ n, is -cos(n) - (-cos(1)) + 3cos(T) - 3cos(n) + infinity.

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what constant voltage needs to be applied to yield this rate? express your answer with the appropriate units.

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The constant voltage that needs to be applied to yield this rate is approximately 0.47619 H A/s.

Determine the constant voltage?

To calculate the constant voltage required to yield a current rate of 150 A over 210 min in a magnet with an inductance of 40 H, we can use the formula V = L × di/dt.

Given:

Inductance (L) = 40 H

Change in current (di) = 150 A

Change in time (dt) = 210 min = 210 × 60 s = 12,600 s

Substituting the values into the formula:

V = 40 H × (150 A / 12,600 s)

Simplifying the expression:

V = 40 × 150 / 12,600 H A/s

V = 0.47619 H A/s

The formula V = L × di/dt represents the relationship between voltage (V), inductance (L), change in current (di), and change in time (dt). By rearranging the formula, we can solve for voltage (V).

Plugging in the given values of inductance, change in current, and change in time, we calculate the constant voltage required. In this case, the result is approximately 0.47619 H A/s.

Therefore, the required constant voltage to achieve this current rate is approximately 0.47619 H A/s.

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Complete question here:

Magnetic resonance imaging instruments use very large magnets that consist of many turns of superconducting wire. A typical such magnet has What constant voltage needs to be applied to yield this rate? an inductance of 40H. When the magnet is initially Express your answer with the appropriate units. powered up, the current through it must be increased slowly so as not to "quench" the wires out of their superconducting state. One such magnet is specified to have its current increased from 0 A to 150 A over 210 min.

which of the following spectroscopy methods does not involve the interaction of organic molecules with electromagnetic radiation?

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The following spectroscopy method does not involve the interaction of organic molecules with electromagnetic radiation:

Mass Spectrometry (MS): Mass spectrometry is a technique that analyzes the mass-to-charge ratio of ions. It does not directly involve the interaction of organic molecules with electromagnetic radiation. Instead, it involves the ionization of molecules and the measurement of their mass-to-charge ratios using magnetic and electric fields.

On the other hand, the following spectroscopy methods do involve the interaction of organic molecules with electromagnetic radiation: Ultraviolet-Visible Spectroscopy (UV-Vis): UV-Vis spectroscopy measures the absorption or transmission of ultraviolet and visible light by organic molecules.

Infrared Spectroscopy (IR): IR spectroscopy measures the absorption or emission of infrared light by organic molecules. It provides information about the molecular vibrations and functional groups present in the molecules.

Nuclear Magnetic Resonance Spectroscopy (NMR): NMR spectroscopy measures the absorption of radiofrequency radiation by atomic nuclei in organic molecules. It provides information about the molecular structure, connectivity, and environment of the nuclei.

It's important to note that different spectroscopy methods have their own applications and provide complementary information about organic molecules.

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The National Aeronautics and Space Administration (NASA) studies the physiological effects of large accelerations on astronauts. Some of these studies use a machine known as a centrifuge. This machine consists of a long arm, to one end of which is attached a chamber in which the astronaut sits. The other end of the arm is connected to an axis about which the arm and chamber can be rotated. The astronaut moves on a circular path, much like a model airplane flying in a circle on a guideline. The chamber is located 20.0 m from the center of the circle. At what speed must the chamber move so that an astronaut is subjected to 5.64 times the acceleration due to gravity

Answers

Answer:

w = 1,662 rad / s,    v = 33.25 m / s

Explanation:

This this exercise indicates that the acceleration felt by the astronauts is

         a = 5.64 g

in a circular motion the centripetal acceleration is

        a_c = v²/ r

angular and linear variables are related

         v = w r

we substitute

        a_c = w² r

we finally have

         5.64 g = w² r

         w² = 5.64 g / r

let's calculate

         w = \(\sqrt{ \frac{5.64 \ 9.8}{20.0} }\)

         w = 1,662 rad / s

linear velocity is

        v = w r

        v = 1,662 20

         v = 33.25 m / s

When a substance goes directly from a solid state to a gas state, as dry ice
does, ___

A. it's called deposition.

B. the line on the energy-vs. temperature graph is horizontal.

C. it's called sublimation.

D. it's undergoing a phase change.

E.it's called fusion.

Answers

it's called sublimation

Explanation:

it's called sublimation.

C and D are both correct statements.

in rutherford's famous set of experiments the fact that some alpha particles were deflected at large angles indicated that

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In Rutherford's famous set of experiments, the fact that some alpha particles were deflected at large angles indicated that the atom contains a dense, positively charged nucleus.

Rutherford conducted experiments where he bombarded a thin gold foil with alpha particles. According to the prevailing model at the time, the Thomson model, it was believed that the positive charge in an atom was spread uniformly throughout the atom, much like plum pudding.

However, Rutherford's observations revealed that some alpha particles experienced significant deflections and even bounced back at large angles. This unexpected result could not be explained by the Thomson model.

Rutherford proposed a new atomic model known as the nuclear model, suggesting that the atom consists of a tiny, dense, positively charged nucleus at the center and the majority of the atom is empty space. This explained the deflection of alpha particles, as they were repelled or deflected by the positive charge concentrated in the nucleus.

The deflection of alpha particles at large angles indicated the presence of a compact and positively charged nucleus within the atom, leading to a fundamental revision of the understanding of atomic structure.

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As a 15,000 kg jet plane lands on an aircraft carrier, its tail hook snags a cable to slow it down. The cable is attached to a spring with spring constant 60,000 N/m. If the spring stretches 29 m to stop the plane, what was the plane’s landing speed?

Answers

The landing speed of the plane was 78.1 m/s.

When the tail hook of the plane snags the cable, the plane's kinetic energy is transferred to the spring. The amount of energy stored in the spring is equal to the work done by the cable to stop the plane. Using the formula for the potential energy stored in a spring, we can calculate the work done and the initial kinetic energy of the plane. Then, we can use the formula for kinetic energy to find the landing speed of the plane. With a spring constant of 60,000 N/m and a spring displacement of 29 m, the spring has stored 25,020,000 J of potential energy. This is equal to the initial kinetic energy of the plane, which is calculated to be 1/2 mv^2. Solving for v, we get a landing speed of 78.1 m/s.

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What is its average velocity during this 9.0-s interval?

Answers

The average velocity of the freely falling object released from rest that has an instantaneous velocity of 80 m / s at 9 s is 40 m / s

V = ( u + v ) / 2

V = Average velocity

u = Initial velocity

v = Final velocity

u = 0

v = 80 m / s

V = ( 0 + 80 ) / 2

V = 40 m / s

Average velocity is the overall velocity during a given period. It is found using the average value of initial and final velocities is the acceleration is constant.

The given question is incomplete. The complete question is:

If the instantaneous velocity of a freely falling object 9.0 s after it is released from a position of rest is 80 m / s. What is its average velocity during this 9.0-s interval?

Therefore, the average velocity of the freely falling object released from rest is 40 m / s

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The equation provided (from the textbook) first defines the elastic potential energy of a spring as ΔUsp = −(WB + WW), where WB is work the spring does on an attached block and WW is work the spring does on the wall to which it is attached. But WW is ignored in the next step. Why?

Answers

Answer:

The given potential energy of the spring is expressed as follows;

ΔUsp = -(WB + WW)

Where;

WB = Th work done by the spring on the block to which it is attached

WW = The work done by the spring on the wall

We recall that work done, W = Force applied × Distance moved in the direction of the force

The work done by the spring on the block, WB = The spring force × The distance the block moves

The work done by the spring on the wall, WW = The spring force × The distance the wall moves

However, given that the wall does not move, we have;

The distance the wall moves = 0

∴ The work done by the spring on the wall, WW = The spring force × 0 = 0 J

Therefore, WW = 0 J, and the spring does not do work on the wall, and WW can be ignored in the next subsequent) steps

Explanation:


Why is Radiology important in the medical field?

Answers

Answer:

Radiology plays a huge role in disease management by giving physicians more options, tools, and techniques for detection and treatment. Diagnostic imaging allows for detailed information about structural or disease-related changes. With the ability to diagnose during the early stages, patients may be saved.

Explanation:

Men who score high on ________ are especially accurate when it comes to judging their mate value, whereas women who score high on ________ are especially accurate when it comes to judging their mate value.

Answers

Men who score high on self-perceived mate value (SPMV) are especially accurate when it comes to judging their own mate value, whereas women who score high on mate value self-esteem (MVSE) are especially accurate when it comes to judging their own mate value.

Self-perceived mate value (SPMV) refers to an individual's subjective assessment of their own attractiveness and desirability as a potential mate. Men who have a high SPMV tend to have a more accurate perception of their own mate value, meaning they have a good understanding of how desirable they are to potential partners.

Mate value self-esteem (MVSE), on the other hand, refers to an individual's self-esteem specifically related to their perceived mate value. Women who have high MVSE have a more accurate perception of their own mate value, meaning they have a good understanding of how desirable they are as potential partners.

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duc 1. Define the term 'element. 2. If you break down each of the following, how many different atoms would you be able to recover? a) Mercury b) Sodium chloride c) Water d) Carbon dioxide e) Oxygen​

Answers

part a.

An element is described as a pure substance that is composed of only one type of atom. Each element is characterized by a unique atomic number, which corresponds to the number of protons in the nucleus of its atoms.

part b.

a) Mercury -  breaking down mercury would yield only mercury atoms.

b) Sodium chloride -  Breaking down sodium chloride would yield sodium and chlorine atoms in their respective ratios.

c) Water -Breaking down water would yield hydrogen and oxygen atoms in their respective ratios.

d) Carbon dioxide : Breaking down carbon dioxide would yield carbon and oxygen atoms in their respective ratios.

e) Oxygen - breaking oxygen down would yield only oxygen atoms.

More about Elements?

Some facts about elements includes;

Elements found on Earth and Mars are exactly the same.Hydrogen is the most common element found in the universe. Isotopes are atoms of the same element, with different numbers of neutrons.In ancient times the elements referred to fire, earth, water, and air.

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PLEASE HELP!!! WILL MARK BRAINLIEST!! Name and define the four fundamental forces.

Answers

Answer:

Gravity - is a natural phenomenon by which all things with mass or energy—including planets, stars, galaxies, and even light—are brought toward one another.

Strong Interaction - is the mechanism responsible for the strong nuclear force

Weak Interaction - is the mechanism of interaction between subatomic particles that is responsible for the radioactive decay of atoms

Electromagnetism - is a branch of physics involving the study of the electromagnetic force, a type of physical interaction that occurs between electrically charged particles.

Hope this helps!

? assume that the space between the plates is filled with air? (dielectric constant for air is 1.00059)

Answers

A parallel-plate capacitor has plates of area 3.07 x 10⁻⁴ m². So the plate separation is required if the capacitance is to be 1520 pF is  5.717 x 10⁻⁵ m.

The capacitance of parallel plate capacitor, C = (ε0 * K * A)/ d, where ε0 = permittivity of free space, K = dielectric constant, A = Area of the plate separation, d = plate separation.

Given:

Area of plate, A = 3.07 * 10⁻⁴ m²

Capacitance, C = 1520

pF = 1520 * 10⁻¹² F

The dielectric constant of air, K = 1.00059

Rearranging the above formula, we get,

d = (ε₀* K * A)/ C

Substituting the above values in the above formula,

d = (ε₀ * K * A)/ C

d = (8.85 * 10⁻¹² * 1.00059 * 3.07 * 1⁻⁴)/ (1520 * 10⁻¹²)

d = 5.717 * 10⁻⁵ m

Hence, the plate separation required is 5.717 x 10⁻⁵ m.

Complete question:

A parallel-plate capacitor has plates of area 3.07 x 10⁻⁴ m²

What plate separation is required if the capacitance is to be 1520 pF? Assume that the space between the plates is filled with air? (Dielectric constant for air is 1.00059)

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A rocket is launched from the surface of the earth with a speed of 9.0x103 m/s. What is the maximum altitude reached by the rocket? (MEarth=5.98x1024 kg, REarth=6.37x106 m)

Answers

From the Law of conservation of energy, we know that the sum of the kinetic and potential energy of the rocket is the same at the surface of the Earth and at the maximum altitude. Nevertheless, the kinetic energy of the rocket when it is at the maximum altitude is 0:

\(\begin{gathered} K_1+U_1=K_2+U_2 \\ K_2=0 \\ \Rightarrow K_1+U_1=U_2 \end{gathered}\)

The kinetic energy is given by:

\(K=\frac{1}{2}mv^2\)

On the other hand, the gravitational potential energy for big changes in altitude (comparable to the radius of the Earth) is given by the expression:

\(U=-\frac{GMm}{r}\)

Where M is the mass of the Earth, m is the mass of the rocket, r is the distance from the center of the Earth to the rocket and G is the gravitational constant:

\(G=6.67\times10^{-11}N\cdot\frac{m^2}{\operatorname{kg}}\)

At the beggining of the movement, the value of r corresponds to the radius of the Earth:

\(U_1=-\frac{GMm}{R_E}\)

At the end of the movement, the value of r corresponds to the radius of the Earth plus the maximum altitude h:

\(U_2=-\frac{GMm}{R_E+h_{}}\)

Substitute the expressions for U_1, K_1 and U_2 and simplify the equation by eliminating the factor m:

\(\begin{gathered} \frac{1}{2}mv^2-\frac{GMm}{R_E}=-\frac{GMm}{R_E+h} \\ \Rightarrow\frac{1}{2}v^2-\frac{GM}{R_E}=-\frac{GM}{R_E+h} \end{gathered}\)

Isolate the term GM/(R_E+h):

\(\Rightarrow\frac{GM}{R_E+h}=\frac{GM}{R_E_{}}-\frac{1}{2}v^2\)

Divide both sides by the factor GM:

\(\Rightarrow\frac{1}{R_E+h}=\frac{1}{R_E}-\frac{v^2}{2GM}\)

Take the reciprocal to both sides of the equation:

\(\Rightarrow R_E+h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}\)

Isolate h:

\(h=\frac{1}{\frac{1}{R_E}-\frac{v^2}{2GM}}-R_E\)

Substitute the values of each variable: R_E=6.37x10^6m, M=5.98x10^24kg, G=6.67x10^-11 N*m^2/kg^2, and v=9.0x10^-3 m/s:

\(\begin{gathered} h=\frac{1}{\frac{1}{6.37\times10^6m}-\frac{(9.0\times10^3\cdot\frac{m}{s})^2}{2(6.67\times10^{-11}N\cdot\frac{m^2}{kg^2})(5.98\times10^{24}kg)}}-6.37\times10^6m \\ =18.03\times10^6m-6.37\times10^6m \\ =11.7\times10^6m \end{gathered}\)

Therefore, the maximum altitude reached by a rocket with an initial speed of 9.0x10^3m is:

\(11.7\times10^6m\)

a uniform disk of radius 4.4 m and mass 5.9 kg is suspended from a pivot 2.42 m above its center of mass. The acceleration of gravity is 9.8 m/s^2 .
Find the angular frequency, for small oscillations. Answer in units of rad/s.

Answers

The angular frequency for small oscillations of the uniform disk is approximately 1.396 rad/s.

To find the angular frequency for small oscillations of a uniform disk suspended from a pivot, we can use the formula:

Angular frequency (ω) = √(g / reff),

Where:

g is the acceleration due to gravity (9.8 m/s²),

reff is the effective radius of the disk, which is the distance from the pivot to the center of mass of the disk.

In this case, the radius of the disk (r) is given as 4.4 m, and the distance from the pivot to the center of mass (h) is given as 2.42 m.

To find the effective radius (reff), we can use the Pythagorean theorem

reff = √(r² + h²).

Substituting the given values:

reff = √(4.4² + 2.42²)

= √(19.36 + 5.8564)

= √25.2164

≈ 5.021 m.

Now we can calculate the angular frequency:

ω = √(g / reff)

= √(9.8 / 5.021)

= √1.9517

= 1.396 rad/s.

Therefore, the angular frequency for small oscillations of the uniform disk is approximately 1.396 rad/s.

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Discuss how directions fields and Euler's method are related. Draw the direction field and use Euler's method to approximate the solution at t = 10 using step size 1, for the initial value problem y'= -3y, y(0) = 5.

Answers

By Using Euler's method with two steps, we can find the approximate value of Y(2) is 2.125. , where Y is the solution of the initial value problem dy/dx = x - y, and Y(1) = 3.

Euler's method is defined as a numerical technique which is  used to approximate solutions into ordinary differential equations. The method includes dividing the interval of interest into smaller steps and thereafter approximating the solution at each step by using the derivative of the function.

In this case, we are given the initial value problem dy/dx = x - y, with the initial condition Y(1) = 3. To approximate Y(2) using Euler's method with two steps, we will divide the interval [1, 2] into two equal steps.

Step 1:

We start with the initial condition Y(1) = 3. Using the differential equation dy/dx = x - y, we can approximate the value of Y at the midpoint of the interval [1, 2].

Using the step size h = (2 - 1) / 2 = 0.5, we can calculate Y(1.5) as follows:

Y(1.5) ≈ Y(1) + h × (x - y) = 3 + 0.5 × (1.5 - 3) = 3 + 0.5 × (-1.5) = 2.25

Step 2:

Now, using the value of Y(1.5) as the new approximation, we calculate Y(2) using the same process:

Y(2) ≈ Y(1.5) + h × (x - y) = 2.25 + 0.5 × (2 - 2.25) = 2.25 + 0.5 × (-0.25) = 2.125

Thus,  by using Euler's method with two steps, the approximate value of Y(2) is 2.125.

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The complete question is

Use Euler's Method With Two Steps To Approximate Y(2), Where Y Is The Solution Of The Initial Value Problem: Dy : X − Y, Y(1) = 3

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is the most ideal state for that system?

In any thermodynamic system that deals with the transfer of thermal energy, which of thefollowing is

Answers

Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

what is the movement of electrons along a conductor called

Answers

The movement of electrons along a conductor is called an electric current.

When there is a flow of charges or electrons in a particular direction along a conductor, an electric current is said to exist. An electric current is a movement of free electrons through a conductor.

The flow of electrons is driven by a potential difference or voltage between two points, which causes the electrons to move from the point of higher potential to the point of lower potential.

greater the voltage, the greater the current will be. The unit of electric current is the ampere (A).

In conclusion, the movement of electrons along a conductor is called an electric current. The main answer is that it is driven by a potential difference or voltage between two points, which causes the electrons to move from the point of higher potential to the point of lower potential. The unit of electric current is the ampere (A).

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Part B
What were the reactants of the first experiment in the video?
1
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Font Sizes
A -
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: EEE

Answers

Answer:

zinc and hydrochloric acid

Explanation:

Answer:

The reactants he used in the first experiment were zinc metal and hydrochloric acid.

Explanation:

edmentum

Find the length of a microscope having magnifying power 100, if the focal lengths of the objective and eye piece are 2 cm and 5 cm respectively. Assume that the final image is formed at infinity

Answers

Answer:

   L = 40 cm

Explanation:

A microscope is an optical instrument built by two lenses in such a way that the image of the first is formed within the distance of the other (eyepiece), so that the latter creates an enlarged virtual image of the object, for which the magnification of the microscope is the same to the multiplication of the magnification of each lens

    M = - L / f₀ (25 cm /\(f_{e}\))

where fo and fe are the focal lengths of the objective and eyepiece, 25 cm is the near vision distance and L is the length of the microscope

     L = - M f_{o} f_{e} / 25

let's calculate

     L = - (-100) 2 5/25

      L = 40 cm

Cell phones use electromagnetic radiation with energy of about 1.08J/mol photons. Calculate the wavelength and frequency that can be used to describe light with this energy.

Answers

We know that the energy of electromagnetic radiation is given by:

\(E=hf\)

where E is the energy, h is Planck's constant and f is the frequency. Before we can use this formula we need to convert the amount of energy given to J so let's do that:

\(1.08\text{ }\frac{J}{mol}\cdot\frac{1\text{ mol}}{6.022\times10^{23}}=1.793\times10^{-24}J\)

Now that we have the energy of the radiation, we plug it on the energy equation and solve for the frequency:

\(\begin{gathered} 1.793\times10^{-24}=6.63^\times10^{-34}f \\ f=\frac{1.793\times10^{-24}}{6.63\times10^{-34}} \\ f=2.704\times10^9 \end{gathered}\)

Therefore, the frequency of the cell phone electromagnetic radiation is:

\(2.704\times10^9\text{ Hz}\)

Now that we know the frequency we just need to remember that the frequency and wavelength of electromagnetic radiation are related by:

\(\lambda=\frac{c}{f}\)

Then we have:

\(\begin{gathered} \lambda=\frac{3\times10^8}{2.704\times10^9} \\ \lambda=0.111 \end{gathered}\)

Therefore, the wavelength is 0.111 m

What is the mass of a ball that is moving at 25 m/s and has 93.75 kg*m/s of momentum ?

Answers

Answer:

m = 3.75 [kg]

Explanation:

We must remember that momentum is defined as the product of mass by Velocity, therefore it can be represented by means of the following equation.

\(P=m*v\)

where:

P = momentum = 93.75 [kg*m/s]

m = mass [kg]

v = velocity = 25 [m/s]

Now replacing, we can clear the mass:

\(P=m*v\\m=P/v\\m=93.75/25\\m=3.75 [kg]\)

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