based on the colligative properties of water, what would happen if one were to add a solute to water?

Answer:

Explanation:

Formula

The current = charge / time

The charge is in coulombs

The time has to be in seconds.

1 minute = 60 seconds

2 minutes = 120 seconds.

charge = 180 coulombs

current = 180 / 120

current = 1.5 amperes.

The density of the gas is 0.639 g/L. The molar mass of the gas is 153.5 g/mol.

Given parameters:Mass of the gas = 1.95 g

Volume of the flask = 3.05 LTemperature of the gas = 57°C = 330 KPressure of the gas = 1.05 atm = 106.625 kPa (1 atm = 101.325 kPa)Let's use the Ideal Gas Law formula:PV = nRT where P = pressure of the gas V = volume of the gas n = number of moles of the gasR = gas constant = 8.314 J/mol.KT = temperature of the gasLet's solve for n:n = (PV)/(RT)n = (106.625 kPa × 3.05 L) / (8.314 J/mol.K × 330 K)n = 0.0127 molThe mass and the number of moles of the gas are given:Mass of the gas = 1.95 gn = 0.0127 mol

Let's solve for the density of the gas using the formula:density = mass / volumedensity = 1.95 g / 3.05 Ldensity = 0.639 g/L (rounded to three significant figures)Let's solve for the molar mass of the gas using the formula:molar mass = mass / number of molesmolar mass = 1.95 g / 0.0127 molmolar mass = 153.5 g/mol (rounded to three significant figures)Answer: The density of the gas is 0.639 g/L. The molar mass of the gas is 153.5 g/mol.

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Answer:

from what it is reduced

Answer:

2 ATP molecules are produced

Answer:

2 ATP molecules of ATP are produced

Among the given gases, the gas that shows the greatest deviation from ideal behavior at 25 degrees Celsius and 1 atm is likely to be H2 (hydrogen).

1. Size and shape of molecules: Hydrogen gas (H2) consists of diatomic molecules that are very small in size. The size of the hydrogen molecule is relatively larger compared to other gases such as CH4 (methane), SO2 (sulfur dioxide), and O2 (oxygen). The small size of hydrogen molecules leads to a higher probability of molecular interactions and deviations from ideal behavior.

2. Intermolecular forces: Hydrogen gas has relatively weak intermolecular forces compared to other gases. Although it exhibits London dispersion forces, these forces are not as strong as the dipole-dipole interactions in molecules like SO2 and CH4 or the formation of double bonds in O2. The weaker intermolecular forces in hydrogen contribute to larger deviations from ideal behavior.

Based on the size and shape of molecules as well as the strength of intermolecular forces, hydrogen gas (H2) is expected to show the greatest deviation from ideal behavior among the given gases at 25 degrees Celsius and 1 atm.

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Answer:

1. four in the first energy level, four in the second energy level

2. eight in the first energy level, zero in the second energy level

3. zero in the first energy level, eight in the second energy level

4. two in the first energy level, six in the second energy level *

Explanation:

1. four in the first energy level, four in the second energy level

2. eight in the first energy level, zero in the second energy level

3. zero in the first energy level, eight in the second energy level

4. two in the first energy level, six in the second energy level *

Dry ice, also known as solid carbon dioxide, sublimes when exposed to air.  As dry ice sublimes, it appears to be "smoking" or "fogging" due to the condensation of the gaseous carbon dioxide in the air.

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112.2 milliliters volume of water will drip into the bucket in 44 minutes.

How much space an object or substance takes up. • Measured in cubic meters (m3), liters (L) & milliliters (mL).

Total drop = Drops per minute X time

= 51 drops per minute X 44 minutes

=2244 drop

Volume of water will drip into the bucket in 44 minutes

=Total drop X Volume of each drop

=0.050 milliliters X 2244 drop

=112.2 milliliters

Hence, 112.2 milliliters volume of water will drip into the bucket in 44 minutes.

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Vapour pressure is a measure of the tendency of a material to change into the gaseous or vapour state, and it increases with temperature. The temperature at which the vapour pressure at the surface of a liquid becomes equal to the pressure exerted by the surroundings is called the boiling point of the liquid.

The vapor pressure of a liquid is the point at which equilibrium pressure is reached, in a closed container, between molecules leaving the liquid and going into the gaseous phase and molecules leaving the gaseous phase and entering the liquid phase.

The most common unit for vapor pressure is the torr. 1 torr = 1 mm Hg (one millimeter of mercury). Most materials have very low vapor pressures.

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The reducing agent in the redox reaction represented by the following cell notation is magnesium (Mg) in the cell notation: Mg(s) | Mg2+(aq) || Li+(aq) | Li(s).

In the given cell notation, the species on the left side of the cell notation (Mg) is undergoing oxidation, which means it is losing electrons and being oxidized. The species on the right side (Li) is undergoing reduction, which means it is gaining electrons and being reduced.

In a redox reaction, the reducing agent is the species that donates electrons to another species, causing it to be reduced. In this case, magnesium (Mg) is losing electrons and being oxidized, so it is the reducing agent in the reaction.

It's important to note that the reducing agent is always the species that is being oxidized in a redox reaction, as oxidation and reduction occur simultaneously.

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The benefit of the release of carbon dioxide have on kelp and other producers is its ability to absorb and lock away huge quantities of carbon dioxide.

Kelp is a type of seaweed which being developed for its nutritional value. Kelp is high in antioxidants, including carotenoids and flavonoids, that help fight against disease-causing free radicals. Antioxidant minerals, such as manganese and zinc, help combat oxidative stress and may help protect cardiovascular health and prevent cancer.

Kelp has an ability to absorb and lock away huge quantities of carbon dioxide. Seaweed absorbs CO2 more effectively than trees. It also improves water quality by extracting harmful nutrients such as nitrogen from the sea.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 100 g

volume = 12 mL

We have

\(density = \frac{100}{12} = \frac{25}{3} \\ = 8.333333...\)

We have the final answer as

Hope this helps you

Organic molecules are defined as chemical compounds that contain carbon and hydrogen in distinct ratios and structures.

Organic molecules are the foundation of life, and they are the building blocks of all known biological systems. They are generally composed of carbon, hydrogen, and other elements in distinct ratios and structures.

They are found in living organisms, including humans, animals, plants, and other microorganisms. Organic molecules come in a variety of shapes and sizes, and they serve a variety of functions.

These molecules can be simple or complex, small or large, and they can exist as solids, liquids, or gases depending on their chemical composition. Organic molecules include carbohydrates, proteins, lipids, and nucleic acids.

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Answer:

8.1293534120006496

Explanation:

hope this helps

The concentration of sulfate ion required to begin precipitation of BaSO₄ is \(1.1 x 10^{-8} M\). Any concentration of sulfate ion greater than this will result in precipitation of BaSO₄.

The solubility product constant (Ksp) is an equilibrium constant that represents the concentration of the ions in a saturated solution at a given temperature. When the concentration of any ion exceeds the Ksp, the excess ions begin to form a solid, and precipitation occurs. For BaSO₄, the Ksp value is \(1.1 x 10^{-10}\) at 25°C.

To calculate the concentration of sulfate ion required to begin precipitation of BaSO₄, we can use the Ksp expression and the initial concentration of barium ion:

Substituting the given concentration of barium ion (0.010 M) and the Ksp value, we get:

Therefore, the concentration of sulfate ion required to begin precipitation of BaSO₄ is \(1.1 x 10^{-8}\) M. Any concentration of sulfate ion greater than this will result in precipitation of BaSO₂.

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Answer:

thank you :')

Explanation:

Answer:

Aw and thank you!

Explanation:

Even though you said I am loved, you are loved very much too! Don't you ever forget that! No matter what happens and how you feel remember that you are loved and mean so much to people. What you said to me means a lot to me! Thank you! YOU ARE LOVED!!

Answer:

0.5 M has the weakest concentration.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to remember that the concentration, or molarity, of a solution is given in terms of moles per liters of solution.

In such a way, we can infer that the solution with the weakest concentration is the one with the smallest molarity, that is 0.5 M.

Best regards!

Answer:

the method is fractional distillation

1) a) The apparatus that can be used to separate a mixture of ethanol and water is called a fractional distillation apparatus. It consists of the following components:

b) The method of separation used in this apparatus is called fractional distillation.

2) In fractional distillation, the fractionating column provides additional surfaces for the vaporized components to condense and revalorize.

Distillation flask: This is a round-bottomed flask where the mixture of ethanol and water is initially placed.

Fractionating column: A long column with several glass beads or plates. It provides a large surface area for the vaporized components to condense and revalorize, aiding in the separation process.

Thermometer: It is placed at the top of the fractionating column to monitor the temperature during the distillation process.

Condenser: It is a coiled glass tube connected to the fractionating column. Cold water flows through the condenser, causing the vaporized components to condense back into liquid form.

Receiver flask: This is where the separated components are collected. The receiver flask is placed at the end of the condenser.

b) The method of separation used in this apparatus is called fractional distillation. Fractional distillation is employed when the components of a mixture have similar boiling points. In the case of ethanol and water, they form an azeotropic mixture with a boiling point of around 78.2°C. Simple distillation would not effectively separate these two components because they would boil together and vaporize simultaneously.

In fractional distillation, the fractionating column provides additional surfaces for the vaporized components to condense and revaporize. This repeated condensation and revalorization process allows for more efficient separation. The higher surface area in the fractionating column helps to achieve better separation of the ethanol and water, resulting in a more concentrated sample of ethanol in the distillate collected in the receiver flask.

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Answer:

volcanic eruption.

mark my answer as brainlest......

Answer:

La configuración electrónica del cloruro es 1s2 2s2 2p6 3s2 3p6.

Explanation:

Answer:

Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

A bond that can link a myristoyl anchor to a polypeptide is an ester bond to an internal serine can link a myristoyl anchor to a polypeptide.

The myristoyl anchor is a 14-carbon fatty acid that can be covalently attached to the N-terminus of certain polypeptides via an amide bond. However, in some cases, the myristoyl anchor can also be linked to an internal serine residue via an ester bond. This myristoylation modification is important for the membrane localization and function of many proteins.

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Analytical methods for the determination of trichloroethylene (TCE) and its major metabolites include gas chromatography (GC), liquid chromatography (LC), solid-phase microextraction (SPME), immunoassay techniques, and mass spectrometry (MS).

These methods offer sensitivity, selectivity, and can be applied to various sample matrices. Sample preparation techniques may be used to enhance analysis.

Trichloroethylene (TCE) and its major metabolites, chloral hydrate, trichloroacetic acid, and dichloroacetic acid, can be determined using various analytical methods. Here is a review of some commonly used techniques for their determination:

Gas Chromatography (GC):

GC is widely employed for the analysis of volatile organic compounds like TCE and its metabolites. The sample is vaporized, and the gaseous analytes are separated by chromatography on a capillary column. Detection can be achieved using a flame ionization detector (FID) or mass spectrometry (MS).

Liquid Chromatography (LC):

High-performance liquid chromatography (HPLC) has been utilized for the determination of TCE and its metabolites. Different LC modes, such as reverse phase or ion-exchange chromatography, can be employed depending on the properties of the analytes. UV detection or MS can be used for quantification.

Solid-Phase Microextraction (SPME):

SPME is a sampling technique that combines extraction and sample introduction into a GC or HPLC system. It involves the use of a fiber coated with an adsorbent material to extract analytes from the sample matrix selectively. SPME has been employed for the determination of TCE and its metabolites in water, air, and biological samples.

Immunoassay Techniques:

Enzyme-linked immunosorbent assays (ELISA) and other immunoassay-based methods have been developed for the rapid screening of TCE and its metabolites. These methods rely on specific antibody-antigen interactions for detection and can provide quick results, although they may have limitations in terms of sensitivity and selectivity.

Mass Spectrometry (MS):

MS techniques, such as gas chromatography-mass spectrometry (GC-MS) and liquid chromatography-mass spectrometry (LC-MS), offer high sensitivity and selectivity for the determination of TCE and its metabolites. They provide structural information and can be used for both qualitative and quantitative analysis.

It is important to note that the choice of analytical method depends on factors such as the sample matrix, required sensitivity, specificity, and available instrumentation. Additionally, sample preparation techniques like extraction or derivatization may be employed to enhance the analyte recovery or improve detection limits.

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When an electron is removed from an orbit in the Bohr model Energy is absorbed.

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Answer:

9.012182 u

Explanation:

The time taken for a given amount of 32P to decay to one-eight of its original activity is 42 days.

A substance's half-life is the amount of time it takes for half of it to decompose. Given that each half-life period diminishes the activity by a factor of 2, if a given amount of a material with a half-life of 14 days decays to one-eighth of its initial activity, it must have gone through three half-life periods. Therefore, it would take 14 x 3 = 42 days for a given amount of 32P to decay to one-eighth of its initial activity.

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The ionic radii for the given ions are respectively described:

\(Sc^{3+}\) = 74.5 pm

\(P^{3-}\) = 212 pm

\(Cl^{-}\) = 181 pm

\(Ca^{2+}\) = 100 pm

\(K^{+}\) = 138 pm

\(S^{2-}\) = 184 pm

Therefore, to put them in decreasing order according to the ionic radii, then the order would be:

\(P^{3-}, S^{2-}, Cl^{-}, K^{+}, Ca^{2+}, Sc^{3+}\)

The radius of a single ion in an ionic crystal is denoted by the symbol "\(r_{ion}\)." The distance between ions in a crystal lattice is equal to the sum of the radii of the cation and anion, despite the fact that neither atoms nor ions have clear boundaries. The radius of an ion is commonly expressed in picometers (pm) or angstroms (Å), where 1 Equals 100 pm.

Coordination number, spin state, and other characteristics affect ionic radius. Ionic radius readings are transferrable enough to identify periodic trends. Ionic radii rise with group descent, like other atomic radii. High-spin ions are larger than low-spin ones, and coordination number enhances ionic size. Positive charge decreases ionic radius, while negative charge increases it.

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The diagrammatic expression for the solutions in the two arms of the U-tube separated by a membrane that is permeable to water and glucose but not to sucrose is shown in the image attached below.

When the system illustrated above reaches equilibrium, the sugar concentrations on both sides of the U-tube will be 1.5 M sucrose, 1.5 M glucose

From the image attached, if the system approaches equilibrium;

The movement of the solute(i.e. one molecule of sucrose) have the potential to proceed and move to the other arm of the U-shaped tube but with that, the total overall concentration cannot change in the whole U-tube structure due to the fact that the volume of the solvent(water) is constant.

Similarly, both arms of the U-tube shape have the same concentration as well as the same net Kinetic energy of solutes giving them the isotonic condition property.

Now, at equilibrium, the concentration of the sugar on both sides is:

= \((\dfrac{1M +2M}{2})\)

\(\mathsf{=\dfrac{3M}{2}}\)

= 1.5 M sucrose, 1.5 M glucose

Therefore, we can conclude that the concentration of the sugar on both sides at equilibrium is 1.5 M sucrose, 1.5 M glucose.

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