Answer:
ans for A)
Ball A being negatively charged and Ball B being neutral
when they come into contact.... electrons from the ball A will transfer to ball B and since they are covered by an electrical conductor... their contact will form a joint pathway for electric charge to be transferred to another object.
Answer: i think A
Explanation:
Can anyone answer this Science question for me NO LINKS !!!!
Answer:
700 N right -->
800- (60+40)
800-100
700 N
How much power is available on a typical 15 amp circuit at home with 110 volts?
Answer:1725 watts
Explanation: Household devices are required to run at 110-125 volts and most are rated at 115 volts so 1725 watts for a 15 amp cord or circuit. You will have to be careful when adding outlets for a 15 amp breaker. Always be sure to consult a licensed electrician before DIY electrical work.
A bicyclist heads east at 20 km/h. After she has traveled 20.8 kilometers, another cyclist sets out in the same direction going 28 km/h. About how long will it take the second cyclist to catch up to the first cyclist
Hence,the time it takes the second cyclist to catch up to the first cyclist will be 2.6 h.
What is velocity?The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component.
\(\rm D_{rel}= V_{rel}\times t_{rel} \\\\ \rm D_{rel}= (V_1-V_2)\times t_{rel} \\\\ T_{rel}=\frac{D_{rel}}{V_1-V_2} \\\\ T_{rel}=\frac{20.8}{28-20} \\\\ T_{rel}= 2.6 \ h\)
The time it takes the second cyclist to catch up to the first cyclist will be 2.6 h.
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Suppose the moon is moving in a circular path of radius 3.8*10^5km about the earth. The period of revolution is 27.5 days. Calculate the moon’s acceleration
Answer:
a ≈ \(2.657360411*10^{-3}\) m/s^2
Explanation:
Let's convert the values into SI unit.
r = 3.8*10^5 km = 3.8*10^8 m
T = 27.5 days = 2376000 seconds
Now, apply the equation \(T = \frac{2\pi r}{v}\)
\(v = \frac{2\pi(3.8e8) }{2376000}\)
v ≈ 1004.886539 m/s
Now, apply the equation \(a = \frac{v^{2} }{r}\)
\(a = \frac{1004.886539^{2} }{3.8e8}\)
a ≈ \(2.657360411*10^{-3}\) m/s^2
The centripetal acceleration of moon is 26.28 x 10⁻¹⁰rad/s².
What is meant by centripetal acceleration ?Centripetal acceleration of an object is the acceleration it acquires while following a circular path.
Here,
Radius of the circular path, r = 3.8 x 10⁸m
Period of revolution, T = 27.5 days = 23.8 x 10⁸s
The expression for angular velocity is given as,
ω = 2\(\pi\)/T
ω = 2 x 3.14/(23.8 x 10⁸)
ω = 2.63 x 10⁻⁹rad/s
Therefore, the centripetal acceleration of moon,
a = rω²
a = 3.8 x 10⁸x (2.63 x 10⁻⁹)²
a = 26.28 x 10⁻¹⁰rad/s²
Hence,
The centripetal acceleration of moon is 26.28 x 10⁻¹⁰rad/s².
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5. the combustion of a single molecule of methane produces about 10 ev of energy. a methane molecule has a mass of 16 amu. the fission of a uranium-235 atom
produces about 189 mev of energy. based on these numbers, about what mass of methane will produce as much energy as a single gram of uranium-235? (one mel
is equal to one million ev.)
oa 19 grams of methane
ob 304 grams of methane.
o c. 71.4 kilograms of methane
od 1,287 kilograms of methane
The mass of methane will produce as much energy as a single gram of uranium-235 1,287 kilograms of methane. Option D is correct.
What is uranium?Uranium, with the atomic number 92 and the symbol U in the periodic table, is a weakly radioactive element. One of the heavy metals that may be used as a concentrated energy source is uranium.
Given data;
⇒One mole of U-235 = 235 grams
=> 1 gram of U-235 = 1/235 moles
⇒1 mole of U-235 = 6.023 x 10²³ atoms
The no of atoms is;
=> 1/235 moles of U-235
⇒N = 6.023 x 10²³/235 atoms
⇒N=25.6 x 10²⁰ atoms
If one atom of U-235 gives is 189 x 10⁶ eV energy,25.6 x 10²⁰ atoms of U-235 gives;
=> 25.6 x 10²⁰ atoms of U-235 gives;
E = 25.6 x 10²⁰ x 189 x 10⁶
E= 4.8 x 10²⁹ eV energy
One methane molecule produces;
E = 10 eV of energy
=> To produce 4.8 x 10²⁹ eV energy, no. of molecules required;
= 4.8 x 10²⁸
6.032 x 10²³ molecules of methane = 16 gms
=> 4.8 x 10²⁸ molecules of methane = 16 x 4.8 x 10²⁸/ 6.032 x 10²³ gms
m= 12.75 x 10⁵ gms
m= 1275 kilograms of methane
m≅ 1287 kilograms of methane
1 gram of U-235 has the same amount of energy as 1287 kilograms of methane.
Hence option D is correct,
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A taut clothesline has length, L, and a mass, M. A transverse pulse is produced by plucking one end of the clothesline. If the pulse makes n round trips along the clothesline in t seconds, find expressions for (a) the speed of the pulse in terms of n, L, and t and (b) the tension F in the clothesline in terms of the same variables and mass M.
The speed of the pulse is v = (2nL) / t and The tension F is F = (4n^2L^2M) / t^2
(a)
Total distance = 2nL
Total time = t
Therefore, the speed of the pulse is:
v = (2nL) / t
(b)
v = sqrt(F/μ)
where μ is the linear mass density of the clothesline, given by:
μ = M/L
Substituting the expression for v from part (a), we get:
(2nL) / t = sqrt(F / (M/L))
Squaring both sides and solving for F, we get:
F = (4n^2L^2M) / t^2
Therefore, The speed of the pulse is v = (2nL) / t and The tension F is F = (4n^2L^2M) / t^2
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a rectangular loop of copper wire is attched to a cart by an insulating rod. the cart is moving at constant speed when it enters a region containing
As the cart moves through the magnetic field, an electromotive force (EMF) is induced in the copper wire loop, according to Faraday's law of electromagnetic induction. This phenomenon is known as electromagnetic induction.
The magnetic field and the moving charges in the wire loop interact to produce the EMF. The right-hand rule states that if you point your fingers in the direction of the magnetic field and your palm in the direction of the induced current, your thumb will point in the direction of the speed of the cart. Positive charges, such as the flow of positive charges in a typical current, are covered by this rule.
The following equation can be used to determine the induced EMF in the copper wire loop:
EMF = B * L * v, where: L is the length of the wire loop that is perpendicular to the magnetic field, B is the strength of the magnetic field (measured in teslas), and v is the electromotive force that is being induced.
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How much gravitational energy does a 65 kg skydiver have 650 m up in the sky?
Answer:
G.P.E = 414050 Joules or 414.05 Kilojoules
Explanation:
Given the following data;
Mass = 65 kg
Height = 650 m
We know that acceleration due to gravity is equal to 9.8m/s²
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
\( G.P.E = mgh\)
Where;
G.P.E represents potential energy measured in Joules.m represents the mass of an object. g represents acceleration due to gravity measured in meters per seconds square. h represents the height measured in meters.Substituting into the equation, we have;
\( G.P.E = 65 * 9.8 * 650 \)
\( G.P.E = 414050 \)
G.P.E = 414050 Joules or 414.05 Kilojoules.
If you wear knee pads while skating,It will take three times as long for you to come to rest when you fall and land on your knees. how does this affect the impulse applied to your knees when you fall?
The long time will decrease the velocity which will equally decrease the impulse applied to your knee.
What is impulse?
The impulse experienced by an object is the change in momentum of the object.
J = ΔP = m(v - u)
where;
J is impulseΔP is change in momentumm is mass of the bodyv is final velocityu is initial velocityv = distance / time
when time of fall becomes 3 times long, the final velocity becomes 3 times smaller
Since the velocity will be reduced, the impulse applied to your knee will decrease as well.
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Why are there no famous women scientists associated with cell theory?
Answer:
there is you just have to look harder
Explanation:
Pls I need help ASAP
Answer:
i dont undertsnad what do u ned hep wit?
Explanation:
If you jog for 1 hr and travel 10 km, the calculation of 10 km/hr describes your.
Answer:
[Speed] or [Velocity (if there is a direction)]
The tubes that go from the trachea into the lungs
Which of the followings forms of energy is released or absorbed in most chemical reactions
Answer:
Heat energy
Explanation:
Explanation:
heat energy or thermal energy
Calcular la magnitud de la fuerza eléctrica entre dos cargas cuyos valores son q1=2 milicoulombs, q2=4 milicoulombs, al estar separadas en el vacío por una distancia de 30 cm
Answer:
Fe = 7.98*10^5N/C
Explanation:
In order to calculate the electric force between the two charges you use the following formula:
\(F_e=k\frac{q_1q_2}{r^2}\) (1)
k: Coulomb's constant = 8.98*10^9Nm^2/C^2
q1 = 2mC = 2*10^-3C
q2 = 4mC = 4*10^-3C
r: distance between the charge = 30cm = 0.3m
You replace the values of the parameters in the equation (1):
\(F_e=(8.98*10^9Nm^2/C^2)\frac{(2*10^{-3}C)(4*10^{-3}C)}{(0.3)^2}\\\\F_e=7.98*10^5\frac{N}{C}\)
The force between the charges q1 and q2 is 7.98*10^5N/C
A RAU80 with 4-lanes and a design radius of 300m requires a spiral-circular curve-spiral transition system, the deflection angle at the Point of Intersection is 16d30m14.0s.
a) Using Superelevation and Minimum Spiral Parameters, emax = 0.06 m/m what is the minimum recommended spiral parameter?
b) Determine the distance P
c) Determine the distance Q
d) Determine the angle Φs
e) Determine the distance Tc
A) Minimum recommended spiral parameter: 150.03m.
b) Distance P: 150.03m.
c) Distance Q: 4.122m.
d) Angle Φs: 16°30'14.0".
e) Distance Tc: 150.03m.
a) Calculation for the minimum recommended spiral parameter:
Design radius (R) = 300 m
Maximum superelevation (e_max) = 0.06 m/m
Spiral Parameter (A) = (R + e_max) / 2
A = (300 m + 0.06 m/m) / 2
A ≈ 150.03 m
b) Calculation for the distance P:
Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.
P ≈ 150.03 m
c) Calculation for the distance Q:
Distance Q represents the length of the circular curve. It is given by the formula:
Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)
Deflection angle at Point of Intersection = 16°30'14.0"
Converting the angle to decimal degrees:
16° + (30'/60) + (14.0"/3600) = 16.504°
Q = 16.504° / (360° / D)
Q ≈ D / 21.814
Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.
Q ≈ 90° / 21.814
Q ≈ 4.122 m
d) Calculation for the angle Φs:
The angle Φs is the deflection angle at the Point of Intersection.
Φs = 16°30'14.0"
e) Calculation for the distance Tc:
Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.
Tc ≈ 150.03 m
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Wich pair of factors affects the force of gravity between objects.
Answer:
Explanation:
Mass of the two objects effects gravity and so does the distance between them squared
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculate the acceleration of the object.
Answer:
a = 6.4 [m/s²]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.
∑F = m*a
where:
∑F = sum of forces (horizontal force = 40 [N] and friction force = 8 [N])
m = mass of the block = 5 [kg]
a = acceleration [m/s²]
Now replacing:
\(40-8=5*a\\32 = 5*a\\a=6.4[m/s^{2} ]\)
Note: the sign of the friction force is negative since this force is acting against the movement of the block.
Which actions most likely cause the domains in a ferromagnetic material to align? Check all that apply. heating the material rubbing the material against a magnet passing electricity around the material placing the material in a magnetic field of opposite polarity placing the material near a strong magnet hitting the material
Answer:
i. rubbing the material against a magnet
ii. placing the material in a magnetic field of opposite polarity
iii. placing the material near a strong magnet
Explanation:
Ferromagnetic materials are majorly metals which can be easily attracted by a magnet. ferromagnetic materials are made up of domains, behaves as minute pieces of magnet. They can be rearranged to align when under the influence of an external magnetic field.
The alignment of the domains in a ferromagnetic material can be caused by either of the following: rubbing the material against a magnet, placing the material in a magnetic field of opposite polarity, placing the material near a strong magnet.
Answer:
B, D, E
Explanation:
edg2020
HELP MEEEEE HURRRYYYY EASYY
What best describes the greatest height a ball will bounce off the ground after being dropped from a height of 50 centimeters?
A. Less than 50 centimeters, as the ball transforms some of its thermal energy into sound energy
B. Less than 50 centimeters, as the ball transforms some of its potential energy into sound energy
C. Greater than 50 centimeters, as the ball transforms some of its thermal energy into potential energy
D. Greater than 50 centimeters, as the ball transforms some of its potential energy into thermal energ
Answer:
C
Explanation:
thats what i think it depends on the amount of force someone dropped the ball with.
Answer: A) "Less than 60 centimeters, as the ball transforms a part of its potential energy into heat energy"
Explanation:
I took the test
two charged particles 1.0 m apart exert an attractive electric force on each other with magnitude 104 n. the magnitudes of the charge on each particle are equal. the separation is then doubled to 2.0 m. what is the magnitude of the force at this distance?
The magnitude of the force at this distance of 2.0 m is 25.6 N.
The force between two charges q1 and q2 separated by a distance r is given by Coulomb's law:
F = k (q1 q2)/r^2
where k is the electrostatic constant (9 x 10^9 Nm^2/C^2).
In this problem, the distance is 1.0 m and the magnitude of the force is 104 N, so we can solve for the charge on each particle:
104 N = (9 x 10^9 Nm^2/C^2) (q1 q2) / 1.0 m^2
q1 q2 = 104 N / (9 x 10^9 Nm^2/C^2)
q1 q2 = 1.2 x 10^-7 C^2
Since the magnitudes of the charges are equal, q1 = q2 = q, so we can solve for q:
q^2 = 1.2 x 10^-7 C^2
q = 3.4 x 10^-4 C
Now that we know the charge on each particle, we can calculate the force when the separation is doubled to 2.0 m:
F = (9 x 10^9 Nm^2/C^2) (q1 q2) / (2.0 m)^2
F = (9 x 10^9 Nm^2/C^2) (3.4 x 10^-4 C)^2 / (2.0 m)^2
F = 25.6 N
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Determine the gravitational energy of your 2 kg physics binder if it is sitting on the ground (height= 0
meters)
Answer:
0J
Explanation:
The gravitational potential energy of the body is 0J because the height is at 0m.
Gravitational potential energy is a form of energy which is highly dependent on the position of a body. The relative position of a body in space accounts for the amount of gravitational potential energy they posses.
A body at height 0m has no gravitational potential energy:Gravitational potential energy = mgh
m is the mass of the body
g is the acceleration due to gravity
h is the height
So, if h = 0, Gravitational potential energy will become 0.
20 POINTS!!
This box of macaroni is used in both parts of this question.
Find the volume of this box of macaroni. Be sure to show your work and label all units.
Answer:
348
Explanation:
because maths ;)
The box of macaroni are in the shape of a cuboid, and the volume of the cuboid in the same unit will be 348 cm.
What is Volume?A three-dimensional space's volume can be calculated. It is frequently expressed in numerical form using SI-derived units or by different imperial units (such as the gallon, quart, and cubic inch). Volume and length are related by the definition of length (cubed). In contrast to how much space the container occupies, the volume of a container is typically thought of as its carrying capacity or the amount of fluid (liquid or gas) that it could hold.
According to the question, the given values are :
Length, l = 16 cm
Width, b = 7.5 cm
Height, h = 2.9 cm
So, the volume of the Cuboid will be, V : l × b × h
V = 16 × 7.5 × 2.9
V = 348 cm³.
Hence, the volume of macaroni box will be 348 cm³.
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(I) A cyclist and her cycle have a total mass of 85kg. Calculate the combined kinetic energy of the cyclist and cycle when travelling at a speed of 12m/s.
(ii) The kinetic energy of the cyclist and cycle increases at an average rate of 180 joules per second. Calculate the time it takes to gain this energy.
The combined kinetic energy of the cyclist and cycle is 6120 J. It takes 34 seconds for the kinetic energy of the cyclist and cycle to increase by 6120 J at a rate of 180 J/s.
What is the kinetic energy equation?Kinetic energy has the following formula: K.E. (= 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilograms-meters squared for every second squared if the mass is measured in kilogrammes and the velocity is measured in metres per second.v
f =12× 15= 310 m/s
The initial velocity is given asv i =6× 5= 35 m/s
The increase in kinetic energy is given as,
ΔKE= 21 m(v f −v i2 )= 21 ×90(( 310 ) 2 −( 35 ) 2 )=375J
Thus, the increase in kinetic energy is 6120J
What is kinetic energy combined?Total mechanical energy is represented by the sum of potential and kinetic energy. The energy an object has as a result of its motion or position is known as mechanical energy. Kinetic energy is the energy of motion, and potential energy is the energy in position or shape.
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400.0 g of a metal absorbs 10000. j of heat energy and its temperature rises from 20.0 ºc to 103.0 ºc. what is the specific heat of the metal?
The correct answer is the specific heat of the metal in question is 0.301 J/g·ºC.
The specific heat of a substance is the amount of heat required to raise the temperature of one gram of the substance by one degree Celsius. To find the specific heat of the metal in this scenario, we need to use the formula:
q = mcΔT
where q is the amount of heat absorbed, m is the mass of the substance, c is its specific heat, and ΔT is the change in temperature.
In this case, we know that the metal absorbed 10000 J of heat energy, had a mass of 400.0 g, and its temperature rose from 20.0 ºC to 103.0 ºC. Therefore, we can plug these values into the formula:
10000 J = (400.0 g) x c x (103.0 ºC - 20.0 ºC)
Simplifying this equation, we get:
10000 J = 33200 g·ºC x c
Dividing both sides by 33200 g·ºC, we get:
c = 0.301 J/g·ºC
Therefore, the specific heat of the metal in question is 0.301 J/g·ºC.
In simpler terms, this means that the metal requires 0.301 J of energy to raise the temperature of one gram of the metal by one degree Celsius.
The specific heat value is an important property of a substance, as it can help us determine how much energy is needed to heat or cool the substance, and how it will behave in different conditions.
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All interactions between the atmosphere and the geosphere involve
gases or particles in air and water
water and living things.
soil and gases or particles in the air
soil and living things
Answer:
The geosphere consists of the solid Earth and the atmosphere consists of the gaseous components in the air. Thus, the answer is C.
Explanation:
Answer:
C
Explanation:
Jibari walks 40. 0 meters east in 120. 0 seconds. He then walks 30. 0 meters west in 60. 0 seconds. What is his average velocity for the trip??
Answer:
0.389 meters per second
Explanation:
1. Get your knowns
a. 40 meters per 120 seconds
b. 30 meters per 60 seconds
2. Add
Total distance = 40 meters + 30 meters = 70 meters
Total time = 120 seconds + 60 seconds = 180 seconds
3. Divide
Average velocity = 70 meters / 180 seconds
= 7 meters / 18 seconds
= 0.388... meters per second
Using the picture below, what must take place for the book to move in the direction of the movement arrow?
-A force must be applied to the top of the book to make sure that it is equal to the force of friction.
-The friction of the table must increase and the friction of the book decrease to allow for movement.
-The friction must be removed for any movement to take place.
-A force in the direction of the desired movement must be applied causing the forces to be unbalanced.
For the book to move in the direction of the movement arrow, a force in the direction of the desired movement must be applied causing the forces to be unbalanced.
option D is the correct answer.
What is the Newton's first law of motion?Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless it is acted upon by an external force and it will move in the direction of the applied force.
Also, from Newton's second law of motion, which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.
Mathematically, Newton's second law of motion is written as;
F (net) = ma
F - Ff = ma
where;
F is the applied force on the objectFf is the force of friction opposing the motion of the objectm is the mass of the objecta is the acceleration of the object.Thus, for the book to move, the force of friction must be overcame by the applied force and this create an unbalanced force acting on the book. Also, the book will move in the direction of the net force acting on it.
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Un depósito de gran superficie se llena de agua hasta una altura de 0,3 m. En el fondo del depósito hay un orificio de 5 cm2 de sección por el que sale el agua con un chorro continuo. A) ¿Qué cantidad de líquido saldrá del depósito expresada en m3/s?
Answer:
a) El caudal de salida del chorro es \(1.213\times 10^{-3}\,\frac{m^{3}}{s}\).
Explanation:
a) Asúmase que el tanque se encuentra a presión atmósferica y que la sima del tanque tiene una altura de 0 metros. La rapidez de salida del chorro del depósito se determined a partir del Principio de Bernoulli, cuya línea de corriente entre la cima y la sima del tanque queda descrita por la siguiente ecuación:
\(\Delta z = \frac{v_{out}^{2}}{2\cdot g}\)
Donde:
\(\Delta z\) - Diferencia de altura, medida en metros.
\(g\) - Constante gravitacional, medida en metros por segundo al cuadrado.
\(v_{out}\) - Rapidez de salida del chorro, medida en metros por segundo.
Se despeja la rapidez de salida del chorro:
\(v_{out} = \sqrt{2\cdot g \cdot \Delta z}\)
Si \(g = 9.807\,\frac{m}{s^{2}}\) y \(\Delta z = 0.3\,m\), entonces la rapidez de salida del chorro es:
\(v_{out} = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.3\,m)}\)
\(v_{out} \approx 2.426\,\frac{m}{s}\)
Ahora, la cantidad de líquido que sale del depósito por unidad de tiempo se obtiene al multiplicar la rapidez de salida del chorro por el área transversal del orificio. Esto es:
\(\dot V_{out} = v_{out}\cdot A_{t}\)
Donde:
\(v_{out}\) - Rapidez de salida del chorro, medida en metros por segundo.
\(A_{t}\) - Área transversal del orificio, medido en metros cuadrados.
\(\dot V_{out}\) - Caudal de salida del chorro, medido en metros cúbicos por segundo.
Dado que \(v_{out} = 2.426\,\frac{m}{s}\) y \(A_{t} = 5\,cm^{2}\), el caudal de salida del chorro es:
\(\dot V_{out} = \left(2.426\,\frac{m}{s} \right)\cdot (5\,cm^{2})\cdot \left(\frac{1}{10000}\,\frac{m^{2}}{cm^{2}} \right)\)
\(\dot V_{out} = 1.213\times 10^{-3}\,\frac{m^{3}}{s}\)
El caudal de salida del chorro es \(1.213\times 10^{-3}\,\frac{m^{3}}{s}\).
The electric potential at a certain point is space is 12 V. What is the electric potential energy of a -3.0 μC charge placed at that point?A) +4 mJB) -4 mJC) +36 mJD) -36 mJE) zero µJ
The energy is negative and in the order of\(10^-6\) J, we can express it as -36 µJ.
Therefore, the correct answer is D) -36 µJ.
We need to find the electric potential energy of a -3.0 µC charge placed at a point with an electric potential of 12 V.
We can use the formula:
Electric potential energy (U) = Charge (q) × Electric potential (V)
First, we need to convert the charge from µC to C:
\(-3.0 \mu C = -3.0 * 10^-6 C\)
Now we can plug the values into the formula:
\(U = (-3.0 * 10^-6 C) * (12 V)\)
\(U = -36 * 10^-6 J.\)
Therefore, the correct answer is D) -36 µJ.
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