balance the following skeleton reaction and identify the oxidizing and reducing agents: include the states of all reactants and products in your balanced equation. you do not need to include the states with the identities of the oxidizing and reducing agents. cro42−(aq) n2o(g) → cr3 (aq) no(g) [acidic]

Answer:

D

Explanation:

You need both, independant and dependant variables for a hypothesis.

The molar mass of the gas, given that 3.25 g of the gas occupied 2.56 L is 30.66g/mol

To obtain the molar mass of the gas, we shall first obtain the number of mole of the gas. This can be obtained as follow:

PV = nRT

0.95 × 2.56 = n × 0.0821 × 280

Divide both sides by (0.0821 × 280)

n = (0.95 × 2.56) / (0.0821 × 280)

n = 0.106 mole

Haven obtain the mole of the gas, we shall determine the molar mass of the gas as follow:

Molar mass = mass / mole

Molar mass of gas = 3.25 / 0.106

Molar mass of gas = 30.66g/mol

Thus, the molar mass of the gas is 30.66g/mol

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We need approximately 0.0981 mL or 2 drops of concentrated nitric acid to fully react with 0.0250 g of copper.

Balanced chemical equation for the reaction of copper with nitric acid is;

Cu(s) + 4HNO₃(aq) → Cu(NO₃)₂(aq) + 2NO₂(g) + 2H₂O(l)

From the equation, we can see that 1 mole of copper reacts with 4 moles of nitric acid. The molarity of the nitric acid is given as 16 M, which means that there are 16 moles of HNO₃ in 1 liter of solution.

First, we convert the mass of copper to moles;

0.0250 g Cu x (1 mol Cu/63.55 g Cu)

= 0.000393 mol Cu

From balanced equation, 1 mole of copper reacts with 4 moles of nitric acid, so we need;

0.000393 mol Cu x (4 mol HNO₃/1 mol Cu)

= 0.00157 mol HNO₃

Now we calculate the volume of 16 M nitric acid required;

0.00157 mol HNO₃ x (1 L/16 mol HNO₃)

= 9.81 x 10⁻⁵ L = 0.0981 mL

To convert this to drops, we use the conversion factor of 20 drops per milliliter;

0.0981 mL x (20 drops/mL) = 1.96 drops

Therefore, we required 0.0981 mL or 2 drops.  

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Answer:

speed

Explanation:

hope it helps

keep smiling

Answer:

From bottom to top, Troposphere, Stratosphere, Mesosphere, Thermosphere, & at the top, Exosphere.

Explanation:

Answer: 3.09 g

Explanation:

To calculate the moles :

\(\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}\)    

\(\text{Moles of} H_2SO_4=\frac{2.70g}{98g/mol}=0.0275moles\)

The balanced chemical equation is

\(2KOH+H_2SO_4\rightarrow 6H_2O+K_2SO_4\)  

According to stoichiometry :

1 mole of \(H_2SO_4\) require 2 moles of \(KOH\)

Thus 0.0275 moles of \(H_2SO_4\) will require=\(\frac{2}{1}\times 0.0275=0.0551moles\)  of \(KOH\)  

Mass of \(KOH=moles\times {\text {Molar mass}}=0.0551moles\times 56g/mol=3.09g\)

Thus 3.09 g of KOH is required to react completely with 2.70 grams of

\(H_2SO_4\)

Based on the electroplating process video:

Electroplating is the process by which a metal is used to coat the surface of another substance.

The process of electroplating is done in order to improve the quality of the material being coated as well as to make it more durable.

In the video, the copper coins were plated with zinc by dipping the coins into a solution of sodium zincate.

The sodium zincate is prepared by dissolving powdered zinc in a sodium hydroxide solution.

The undissolved zinc powder in the solution will form a fine film of zinc over the copper making it looks shiny like zinc.

The zinc-coated coin is then held over a bunsen flame until it turns shiny gold.

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The compound form with a sodium cation and a carbonate anion has the following molecular formula: Na2CO3, and the name is the same as the individual names but now together, Sodium carbonate, letter B

Answer:

1 + (2+3+2)×3

1+7×3

1+21

22

Explanation:

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Answer: 1 + 6 + 9 + 6 = 22

Explanation:

al = 1

c = 6

h = 9

o = 6

Amphoteric substances are those that can act as both acids and bases, depending on the conditions in which they are found.

Amphoteric substances are those that can act as both acids and bases, depending on the conditions in which they are found. In this activity, two examples of amphoteric substances are aluminum hydroxide (Al(OH)3) and zinc hydroxide (Zn(OH)2).
Aluminum hydroxide is a common antacid that is used to neutralize stomach acid in people who experience heartburn or indigestion. It acts as a base when it reacts with the acidic environment of the stomach, neutralizing the acid and reducing the discomfort associated with acid reflux. However, it can also act as an acid when it reacts with a strong base, such as sodium hydroxide. In this case, aluminum hydroxide donates a hydrogen ion (H+) to the base, making it an acid.
Zinc hydroxide is another amphoteric substance that is used in the production of various products, including rubber, paint, and cosmetics. It can act as a base when it reacts with an acid, such as hydrochloric acid, neutralizing the acid and producing water and zinc chloride. However, it can also act as an acid when it reacts with a strong base, such as sodium hydroxide. In this case, zinc hydroxide donates a hydrogen ion (H+) to the base, making it an acid.
In summary, amphoteric substances are important in many chemical reactions and play a vital role in maintaining the pH balance of different systems in the body. Both aluminum hydroxide and zinc hydroxide are examples of amphoteric substances found in this activity, and they can act as both acids and bases depending on the conditions in which they are found.

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Forces can cause objects to accelerate , decelerate , stop , start moving , change direction , change shape , or even turn

Answer:

8820.009 milliliters

Explanation:

The pH of a solution is a measure of the acidity or basicity of the solution. It is defined as the negative logarithm of the hydrogen ion (H+) concentration in the solution. Therefore, the pH of the solution is 3.91.  

To determine the pH of a solution containing potassium acetate and acetic acid, we need to know the concentrations of the two solutes and the ratio of acetic acid to potassium acetate in the solution.

We are given the concentration of the potassium acetate and the ratio of acetic acid to potassium acetate in the solution. To calculate the pH of the solution, we can use the following equation:

pH = -log[H+]

where [H+] is the concentration of hydrogen ions in the solution.

To find the concentration of hydrogen ions in the solution, we can use the following equation:

[H+] = [acetic acid] + [potassium acetate] * ([acetic acid]/[potassium acetate])

Substituting the values we have, we get:

[H+] = (6.84 x \(10^{-2\)) + (0.434 x 6.84 x  \(10^{-2\)) * (0.00072)

[H+] = 6.84 x  \(10^{-2\) + 2.69 x  \(10^{-2\)

[H+] = 9.53 x  \(10^{-2\) mol/L

The pH of the solution can be calculated using the equation:

pH = -log[H+]

Substituting the value of [H+] in the equation, we get:

pH = -log[9.53 x \(10^{-2\)]

pH = 3.91

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The compound C7H14O8 does fit the formal definition of a carbohydrate.

Carbohydrates are organic compounds consisting of carbon, hydrogen, and oxygen atoms. They are characterized by their ratio of hydrogen and oxygen atoms, which is typically 2:1, similar to water (H2O). The general formula for carbohydrates is (CH2O)n, where "n" represents the number of carbon atoms.

In the given compound, C7H14O8, we can see that it contains carbon, hydrogen, and oxygen atoms. The ratio of hydrogen to oxygen atoms is close to 2:1, which is consistent with the general definition of carbohydrates. The presence of carbon and oxygen atoms further supports its classification as a carbohydrate.

However, to definitively confirm if C7H14O8 is a carbohydrate, additional information is needed, such as the arrangement and bonding of its atoms. Carbohydrates can have different structures, including monosaccharides (simple sugars), disaccharides (two sugar units), and polysaccharides (multiple sugar units). Without knowing the specific structure of the compound, it is challenging to determine its exact classification within the carbohydrate family.
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Answer:

In a saturated solution of potassium nitrate (KNO3), the rate of dissolution and the rate of recrystallization are equal. This equilibrium state is reached when the amount of KNO3 that dissolves equals the amount that recrystallizes from the solution.

The equilibrium can be influenced by various factors such as temperature and pressure. For example, if you increase the temperature of the solution, the solubility of potassium nitrate increases, meaning that more KNO3 can dissolve before reaching saturation. This would momentarily increase the rate of dissolution until a new equilibrium is reached where the rates of dissolution and recrystallization are equal again, but at a higher concentration of KNO3.

To summarize, in a saturated solution of KNO3, the rate of dissolving KNO3 is equal to the rate of recrystallization of KNO3. This is a characteristic of dynamic equilibrium in solutions.

The volume of insulation material required is approximately 0.003606 cubic meters (m³).

To calculate the volume of insulation material, we can subtract the volume of the inner pipe (original pipe) from the volume of the outer pipe (original pipe + insulation).

Given:

Length of the pipe, L = 10 m

Radius of the pipe, r = 7 cm = 0.07 m

Thickness of the insulation, dr = 2 mm = 0.002 m

The outer radius of the larger pipe is R = r + dr.

Using the formula for the volume of a cylinder, V = π(R² - r²)L, we can substitute the values and calculate:

V = π((0.07 + 0.002)² - 0.07²) × 10

V ≈ 3.606 × 10⁻³ m³

Therefore, the volume of insulation material required is approximately 0.003606 m³ (cubic meters).

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The OH group being protonated Getting rid of water the old alpha carbon atom undergoes deprotonation.

Amines are organic substances that have a lone pair of nitrogen atoms in them. In essence, they are produced by replacing one or even more hydrogen atoms in ammonia (NH3) with an alkyl or aryl group, giving them the names alkylamines and arylamines, respectively.

come to m  Organic molecules, biologically active aldehydes, trimethylamine, and phenol are examples of essential amines; for such a list of amines, see Class: Amines. Amines are a different name for inorganic ammonia compounds, including monochloramine (NClH2). The amino group is denoted by the substituent -NH2.

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The isomeric C5H12O alcohols can be prepared by lithium aluminum hydride reduction of Carboxylic acid.

Any of a class of chemical compounds known as carboxylic acids in which a carbon (C) atom forms a double bond with an oxygen (O) atom and a single bond with a hydroxyl group (OH). The carbon atom is connected to a hydrogen (H) atom or another univalent combining group via a fourth bond. The carbonyl group (C=O) and hydroxyl group are what give the carboxyl (COOH) group its name. The acidity of the carboxylic acids is their primary chemical property. They are typically milder than the well-known mineral acids but more acidic than other organic molecules with hydroxyl groups.

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Answer:

bases which are not soluble in water do not give the hydroxyl ions and so they are treated differently from soluble bases called alkalis.

The average molecular weight of an amino acid residue in a polypeptide is 110. The approximate molecular weight of insulin, which has 51 amino acids, is 5610 kDa, and the weight of myosine, which has 1750 amino acids, is 192500.

Protein is made up of amino acids, and each amino acid has an individual molecular weight of 128 kDa, but when they make the polypeptide chain, each amino acid loses one molecule of water. Due to the loss of one water molecule, the molecular weight of each amino acid in a polypeptide chain is 110.

Hence, the weight of the insulin is 5610 kDa, and the weight of the myosine is 192500 kDa.

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So, at STP, there are around 891 grammes of nitrogen gas in every 759 litres.

The two stable isotopes of naturally occurring nitrogen (7N) are nitrogen-14 and nitrogen-15, with nitrogen-14 constituting 99.6% of all naturally existing nitrogen. Along with one nuclear isomer, 11mN, fourteen radioisotopes with atomic masses ranging from 10 to 25 are also known.

Assuming "ST" refers to standard temperature and pressure (0°C and 1 atm), we can use the ideal gas law to calculate the mass of nitrogen gas:

PV = nRT

where n is the number of moles, P is the pressure, V is the volume, and T is the temperature, and R is the gas constant.

The temperature and pressure are 273.15 K and 1 atm, respectively, at STP.

To solve for n, the number of moles, we can rearrange the ideal gas law equation as follows:

n = PV / RT = (1 atm) * (759 L) / (0.0821 L·atm/(mol·K) * 273.15 K) = 31.8 mol

Now we can calculate the mass of nitrogen gas:

mass = n * molar mass = 31.8 mol * 28.01 g/mol ≈ 891 g.

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Answer:

Jose is right

Explanation:

As the book is sitting still on the table, it is being acted upon by two forces of equal magnitude and opposite direction. Theses are;

i) The weight of the book

ii) The normal reaction on the book

The weight of the book acts downwards while the normal reaction acts upwards. These two forces exactly counterbalance each other hence the book sits still on the table.

Correct option is A.a fatty acid. The compound CH3(CH2)12CO2H is a fatty acid known as lauric acid. Fatty acids are organic compounds consisting of a carboxylic acid group (CO2H) attached to a long hydrocarbon chain.

Lauric acid has a 12-carbon chain, making it a medium-chain fatty acid. It is commonly found in various natural sources, such as coconut oil and palm kernel oil. Fatty acids serve as building blocks for lipids, including triglycerides and phospholipids.

They play essential roles in energy storage, membrane structure, and as precursors for various biological processes. Lauric acid is known for its antimicrobial properties and is used in soaps, cosmetics, and as a food ingredient.

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Answer:

The mass of MgO formed is 160g

Explanation:

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Answer:

when he collided with the passerby

Explanation:

Answer:

1. Crush the sugar into powder.

2. Heat the water.

3. Dissolve it by stirring continuously

Explanation:

1. Crushing the sugar into powder increases surface area. So it increases the changes of dissolving

2. Heating the water increases the capacity of water to dissolve sugar.

3. Stirring continuously increases randomness of particles so eases mixing up thus increasing dissolving tendency.

pCa when 35 mL of 0.009 M Cat2 is titrated with 0.022 M EDTA = 8.442. Balanced chemical equation when EDTA is added to the Ca²⁺ solution, the equation is shown below: Ca²⁺+ EDTA⁴⁻ → CaEDTA²⁻.  Hence, the correct option is d)10.6

Calculation of pСa  when 35 mL of 0.009 M Cat2 is titrated with 0.022 M EDTA (as for EDTA at pH=10 is 0.35) in a solution buffered to a constant pH= 10 when the volume of EDTA added is 48 mL is shown below: Given, Volume of Ca2+ = 35 ml

Concentration of Ca²⁺ = 0.009 M, Volume of EDTA added = 48 ml

Concentration of EDTA = 0.022 M,

pH = 10KCaY-2

= 5.0 x 10¹⁰

To calculate the pCa we have to follow these steps:

First, write down the balanced chemical equation for the reaction that occurs when EDTA is added to the Ca²⁺ solution, the equation is shown below: Ca²⁺+ EDTA⁴⁻ → CaEDTA²⁻

Kf = [CaEDTA²⁻] / ([Ca²⁺] [EDTA⁴⁻])

Initial concentration of Ca²⁺ = 0.009 M

Initial volume of Ca²⁺ = 35 ml, Initial amount of Ca²⁺ = 0.009 × 35

= 0.315 mmol

Final volume of Ca²⁺ = 35 + 48

= 83 ml

Thus, final concentration of Ca²⁺ = 0.315 / 83

= 0.003795 M

In the presence of excess EDTA, the entire amount of Ca²⁺ reacts with EDTA.

Thus,[EDTA⁴⁻] = 0.022 × 48 / 1000

= 0.001056 mol[Ca²⁺]

= 0.003795 mol,

Kf = 5 × 10¹⁰

We have to calculate the [CaEDTA²⁻] at the end point and then convert it into [Ca²⁺] to calculate pCa. Using the equation of equilibrium constant ;Kf = [CaEDTA²⁻] / ([Ca²⁺] [EDTA⁴⁻])

Here,[CaEDTA²⁻] = unknown[Ca²⁺]

= 0[EDTA]

= 0.001056 mol/L

When the end point is reached, all Ca²⁺ is reacted with EDTA to form CaEDTA²⁻.

Thus, moles of EDTA⁴⁻ used = 0.003795 × 83

= 0.315 mmol

Moles of CaEDTA²⁻ formed = 0.315 mmol

Thus, [CaEDTA²⁻] = moles of CaEDTA²⁻ formed / volume

= 0.315 / 83

= 0.003795 M

Now, substituting these values in the equilibrium constant expression;5 × 10¹⁰ = [0.003795] / [(0.001056) (0)]

Thus, [Ca²⁺] = [CaEDTA²⁻]

= 3.607 × 10⁻⁹ M

We know that pCa = -log [Ca²⁺]

Thus, pCa = -log 3.607 × 10⁻⁹

= 8.442 (approx)

Hence, the correct option is d)10.6

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Answer:

D

Explanation:

Sweat glands remove waste

The correct association that lies between the structure and one of its functions is option D Sweat glands remove waste.

The sweat represents the fluid that comprises of mainly of water also there is much dissolved solid wastage that should be excreted via the sweat glands. It eliminates the excess water and salts also it served the function of colling the body at the time of thermoregulation.

Therefore, the option D is correct.

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