The balanced reaction under neutral conditions is Hg2+ + Zn --> Hg + Zn2+, and the common number of electrons for both half reactions is 2.
To determine how many electrons are needed to find a common number of electrons for each half reaction, follow these steps:
1. Identify the two half reactions:
Oxidation half reaction: Zn --> Zn2+
Reduction half reaction: Hg2+ --> Hg
2. Balance the atoms in each half reaction:
Oxidation half reaction: Zn --> Zn2+ + 2e- (Zn loses 2 electrons)
Reduction half reaction: Hg2+ + 2e- --> Hg (Hg gains 2 electrons)
3. Determine the common number of electrons:
In this case, both half reactions involve the transfer of 2 electrons. Therefore, the common number of electrons for both half reactions is 2.
Now we can combine the balanced half reactions to obtain the balanced equation under neutral conditions:
Hg2+ + Zn --> Hg + Zn2+
In summary, the balanced reaction under neutral conditions is Hg2+ + Zn --> Hg + Zn2+, and the common number of electrons for both half reactions is 2.
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If a sample of coffee had 31.13 grams of caffeine (C8H10N4O2), how many atoms of nitrogen are present?
which of the following is an indicator of a chemical reaction?
A. two different compounds mixing and remaining seperate.
B. changing states of matter (solid to liquid).
C. decreasing in size.
D. increasing in tempurature
Answer:
option . D
Increase in temperature
is an indicator of a chemical reaction
hope it helps
Answer:
answer is D
Explanation:
some signs of a chemical change are a change in colour and the formation of bubbles.
the five conditions of chemical change: colour change, formation of precipitate, formation of a gas ,odor change, temperature change.
I think it will use for you
What is the atomic number of Gold
he atomic weight is the mass of an atom, typically expressed in atomic mass units (amu). For an isotope, it is the mass of the nucleus, that is the mass of the protons and neutrons, as the mass of the electrons are considered negligible. In their natural state only 21 elements exist as single isotopes, that is a sample has nuclei of only one isotope, and these are called the mononuclidic elements. Most elements exist as a mixture of nuclei from multiple isotopes, and these are labeled as the polynuclidic elements. The atomic weight of a monuclidic element is that mass of that nuclide.
Mononuclidic element are those with only one naturally occurring isotope, while polynuclidic elements have multiple isotopes. The atomic weight of a mononuclidic element is equal to the mass of its single isotope.
The atomic weight of an element is the mass of an atom, which is typically expressed in atomic mass units (amu). For an isotope, the atomic weight is the mass of the nucleus, which includes the mass of both the protons and neutrons, but not the electrons, which are considered to have negligible mass. Mononuclidic elements are those that exist in their natural state with only one isotope, meaning that a sample of the element will have nuclei of only one isotope. There are only 21 mononuclidic elements. On the other hand, polynuclidic elements are those that exist as a mixture of nuclei from multiple isotopes, and most elements fall under this category. For mononuclidic elements, the atomic weight is the mass of that particular isotope.
The atomic weight, expressed in atomic mass units (amu), represents the mass of an atom, primarily consisting of protons and neutrons in the nucleus. Isotopes are different forms of an element with varying neutron counts. Mononuclidic elements are those with only one naturally occurring isotope, while polynuclidic elements have multiple isotopes. The atomic weight of a mononuclidic element is equal to the mass of its single isotope.
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What would the final product beaker look like for when nitric acid reacts with strontium hydroxide?
The final product beaker for the reaction between nitric acid and strontium hydroxide would contain strontium nitrate and water. [Precipitation] of strontium nitrate would occur, while water would remain in the solution. The beaker may also contain some excess nitric acid if it was not completely neutralized by strontium hydroxide.
When nitric acid (HNO3) reacts with strontium hydroxide (Sr(OH)2), a neutralization reaction occurs. The balanced chemical equation for this reaction is:
2HNO3 + Sr(OH)2 -> Sr(NO3)2 + 2H2O
In this reaction, the hydrogen ions (H+) from nitric acid react with the hydroxide ions (OH-) from strontium hydroxide to form water (H2O). The remaining components, strontium ions (Sr2+) and nitrate ions (NO3-), combine to form strontium nitrate (Sr(NO3)2), which is a soluble salt.
In the final product beaker, the strontium nitrate would be in the form of dissolved ions since it is soluble in water. Water would be present in the solution as the solvent. If there was any excess nitric acid that was not completely neutralized, it would also be present in the beaker.
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water is a compound not a mixture , even thought it contains hydrogen and oxygen. how can u prove that this is a correct statement
Answer:
Hence, water is a compound because it can only be separated into hydrogen and oxygen atom by chemical reaction.A compound forms whenever two or more atoms form chemical bonds with each other. The chemical formula for water is H2O, which means each molecule of water consists of one oxygen atom chemically bonded to two hydrogen atoms. Thus, water is a compound.
Explanation:
How many kilojoules of heat energy are required to vaporize a 50.0 g sample of water at its boiling point?
Answer:
Answer and Explanation: 1
Moles of water =
50.0
g
×
1
m
o
l
18.0
g
=
2.78
m
o
l
The sequence of heating events can be described as:
1) Heat the liquid water from 25.0 celsius to its standard boiling point at 100 celsius.
We need to use the specific heat capacity of liquid water.
q
1
=
m
w
a
t
e
r
×
c
w
a
t
e
r
×
Δ
T
=
50.0
g
×
4.18
J
/
g
∗
C
×
(
100.0
o
C
−
25.0
o
C
)
=
15675
J
=
15.7
k
J
2) Vaporize the water from liquid at 100 celsius to steam at 100 celsius.
We need to use the enthalpy of vaporization.
q
2
=
Δ
H
v
a
p
×
n
w
a
t
e
r
=
40.7
k
J
1
m
o
l
×
2.78
m
o
l
=
113146
J
=
113
k
J
Total heat required =
q
1
+
q
2
=
15.7
+
113
=
129
k
J
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Texas hill country is largely composed of soft limestone rock. When exposed to carbonic acid in rainwater, limestone can deteriorate and weaken. What affect does this process have on the landforms of Texas hill country?
Answer:
The answer is "It leads to the formation of underground caves"
Explanation:
Texas Hill Land is popular for its rolling hills, good wine, and authentic food. Its Texas Hill Property appeal is no mystery, recognized as being one of the top vacation destinations in the World. Texas Hill Structure is primarily mostly of weak calcareous stone. Calcium may worsen or degrade if exposed to carbon dioxide in rainwater. This practice affects the land of the Texas smoky Mountains leading to the formation of underwater groves.
Choose all the answers that apply. lonic compounds ___.
A. do not dissolve in water
B. have high melting points
C. have low melting points
D.dissolve easily in water
E. conduct electricity when melted
(science class not chemistry)
Answer:
E conduct electricity when melted
Explanation:
They can not produce electricity until dissolved/ melted in water
solve for x
\( \bold{x^{2} + 6x + 5 = 0}\)
ty! ~
Answer:
x²+6x+5=0
On comparing with the equation
ax² + bx + c = 0
a=1, b = 6 and c = 5
Now
b²– 4ac = 6² – 4 x 1 x 5 = 36 - 20 = 16
\(x = \frac{ - b \:± \: \sqrt{b {}^{2} - 4ac } }{2a} \\ \\ x = \frac{ - 6\:± \: \sqrt{16 } }{2 \times 1} \\ \\ x = \frac{ - 6± {4} }{2} \\ \\ x = \frac{ - 6 + {4} }{2} \: \: or \: \: x = \frac{ - 6 - {4} }{2} \\ \\ \implies \: x = \frac{ \cancel-2 }{ \cancel2}^{-1 }\: \: or \: \: x = \frac{ \cancel-10 }{ \cancel2}^{-5}\\ \\ \implies \: { \blue{\fbox{ \: x = - 1 \: \: \: or \: \: \:x = - 5}}}\)
\( {x}^{2} + 6x + 5 = 0 \\ \\ {x}^{2} + 5x + x + 5 = 0 \\ \\ x(x + 5) + 1(x + 5) = 0 \\ \\ (x + 1)(x + 5) = 0.\)
\(x = - 1 \\ x = - 5.\)
In the Fahrenheit temperature scale, water freezes at 32∘F and boils at 212∘F, in the Celsius scale, water freezes at 0∘C and boils at 100∘C, given that the Fahrenheit. temperature F and the Celsius temperature C are related by a linear equation, find F in terms of C. F( G )= Use your equation to find the Fahrenheit temperatures corresponding to 31∘C.21∘C,−9∘C, and −15∘C, to the nearest degree.
The Fahrenheit temperatures corresponding to Celsius 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.
To find the equation relating Fahrenheit temperature (F) to Celsius temperature (C), we can use the given freezing and boiling points of water on both scales.
We know that at the freezing point of water:
Fahrenheit temperature = 32°F
Celsius temperature = 0°C
And at the boiling point of water:
Fahrenheit temperature = 212°F
Celsius temperature = 100°C
We can use these two points to find the equation of the line relating F and C.
First, we find the slope of the line:
Slope = (Change in Fahrenheit temperature) / (Change in Celsius temperature)
= (212°F - 32°F) / (100°C - 0°C)
= 180°F / 100°C
Next, we find the y-intercept of the line:
Using the freezing point of water (0°C, 32°F):
32°F = Slope * 0°C + y-intercept
32°F = 0.18 * 0°C + y-intercept
y-intercept = 32°F
Therefore, the equation relating Fahrenheit temperature (F) to Celsius temperature (C) is:
F = 1.8C + 32
Now, we can use this equation to find the Fahrenheit temperatures corresponding to the given Celsius temperatures:
For 31°C:
F = 1.8 * 31 + 32 = 87.8 ≈ 88°F
For 21°C:
F = 1.8 * 21 + 32 = 69.8 ≈ 70°F
For -9°C:
F = 1.8 * -9 + 32 = 15.8 ≈ 16°F
For -15°C:
F = 1.8 * -15 + 32 = 5 ≈ 5°F
Therefore, the Fahrenheit temperatures corresponding to 31°C, 21°C, -9°C, and -15°C are approximately 88°F, 70°F, 16° F, 5°F.
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What separation method collects vapor
Answer:
evaporation and distilation
Explanation:
Calculate the concentrations of hydronium ion and hydroxide ion at 25°C in: (a) 0.10 M HCl, (b) 1.4 × 10–4 M Mg(OH)2, a strong base. answer with steps please
Ai. The concentration of hydronium ion, [H₃O⁺], is 0.10 M
Aii. The concentration hydroxide ion, [OH⁻] is 1×10⁻¹³ M
Bi. The concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M
Bii. The concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M
A. How do i determine [H₃O⁺] and [OH⁻] of 0.10 M HCl?i. The concentration of hydronium ion, [H₃O⁺] can be obtained as follow:
HCl(aq) + H₂O <=> H₃O⁺(aq) + Cl⁻(aq)
From the above equation,
1 mole of HCl contains 1 mole of H₃O⁺
Therefore,
0.10 M HCl will also contain 0.10 M H₃O⁺
Thus, the concentration of hydronium ion, [H₃O⁺] is 0.10 M
ii. The concentration of hydroxide ion, [OH⁻] can be obtained as follow:
Concentration of hydronium, ion [H₃O⁺] = 0.10 MConcentration hydroxide ion, [OH⁻] =?[H₃O⁺] × [OH⁻] = 10¯¹⁴
0.10 × [OH⁻] = 10¯¹⁴
Divide both side by 3.02×10⁻¹⁰
[OH⁻] = 10¯¹⁴ / 0.10
[OH⁻] = 1×10⁻¹³ M
Thus, concentration of hydroxide ion, [OH⁻] is 1×10⁻¹³ M
B. How do i determine [H₃O⁺] and [OH⁻] for 1.4×10¯⁴ M Mg(OH)₂?First, we shall obtain concentration hydroxide ion, [OH⁻]. Details below:
Mg(OH)₂(aq) <=> Mg²⁺(aq) + 2OH⁻(aq)
From the above equation,
1 mole of Mg(OH)₂ is contains 2 mole of OH⁻
Therefore,
1.4×10¯⁴ M Mg(OH)₂ will contain = 1.4×10¯⁴ × 2 = 2.8×10¯⁴ M OH⁻
Thus, concentration hydroxide ion, [OH⁻] is 2.8×10¯⁴ M
Now, we shall obtain the concentration of hydronium, ion [H₃O⁺]. Details below:
Concentration of hydroxide ion, [OH⁻] = 2.8×10¯⁴MConcentration of hydronium, ion [H₃O⁺] = ?[H₃O⁺] × [OH⁻] = 10¯¹⁴
[H₃O⁺] × 2.8×10¯⁴ = 10¯¹⁴
Divide both side by 2.8×10¯⁴
[H₃O⁺] = 10¯¹⁴ / 2.8×10¯⁴
[H₃O⁺] = 3.57×10⁻¹¹ M
Thus, the concentration of hydronium, ion [H₃O⁺], is 3.57×10⁻¹¹ M
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which metal is more reactive? Mg or Ba
Answer:
These metals are less reactive than the neighbouring alkali metal. Magnesium is less active than sodium; calcium is less active than potassium; and so on. These metals become more active as we go down the column.
Explanation:
Magnesium is more active than beryllium; calcium is more active than magnesium; and so on.
How does electron pair repulsion determine the molecular shape/molecule geometry?.
The number of valence electron pairs in the outermost shell, as determined by the valence shell electron repulsion theory (VSEPR), determines the molecular shape.
By analyzing the repulsion between bond electron pairs in the outermost electron shell, a process known as the molecular shape can determine the shape of a molecule. Because most physical and chemical properties are influenced by molecular shape, it is crucial to study molecular shape or geometry.
The foundation of VSEPR is minimizing the strength of the electron-pair repulsion surrounding the central atom under consideration. The foundation of the VSEPR theory is the notion that the geometry (shape) of a molecule is primarily determined by the repulsion between the pairs of electrons surrounding a central atom.
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draw the structure of the major organic product isolated from the reaction of 1-hexyne with chlorine (1 mol).
The structure of the major organic product isolated from the reaction of 1-hexyne with chlorine (1 mol) is 3-chloro-1-hexene.
When one mol of 1-hexyne reacts with chlorine, the major organic product isolated from the reaction is 3-chloro-1-hexene.
Structure of the major organic product isolated from the reaction of 1-hexyne with chlorine (1 mol):Explanation:1-hexyne is an alkyne containing six carbon atoms and a triple bond between the first and second carbon atoms. When it reacts with chlorine, the triple bond breaks, and a chlorine atom is added to one of the carbons.
This results in the formation of several products.3-chloro-1-hexene is the major organic product that is obtained from this reaction. It is an alkene that contains six carbon atoms, with a chlorine atom attached to the third carbon atom. Its structure is shown below:
Therefore, the structure of the major organic product isolated from the reaction of 1-hexyne with chlorine (1 mol) is 3-chloro-1-hexene.
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Complete the table by filling in the missing information.
Options for A
- pressure, volume
- temperature, pressure
- volume, temperature
Options for B
- pressure, moles of gas
- temperature, moles of gas
- volume, moles of gas
Options for C
- Gay-Lussac’s law
- Charles’s law
- Dalton’s law
Options for D
- V = kT
- V = kP
- V = KP
Options for E
- pressure, volume
- temperature, pressure
- volume, temperature
Options for F
- PT = k
- P = kT
- T = kV
Options for G
- pressure only
- temperature, volume
- number of moles only
- pressure, temperature
Answer:
A. Pressure,Volume
B. Temperature, moles of gas
C. Charles Law
D. V=kT
E. Temperature, Pressure
F. P= kT
G.Number of Moles only
Explanation:
Consider the Solutions A-E:
A - 150 mM NaCl
B - 100 mM glucose + 100 mM NaCl
C - 100 mM Drug X (a small non-polar molecule) + 150 mM NaCl D - 150 mM MgCl2
E - 300 mM fructose
1. What would happen if red blood cells were placed in Solution A
2. What will the tonicity of solutions B, C, D and E be, compared to solution A and each other?
When red blood cells are placed in Solution A, which contains 150 mM NaCl, no significant changes occur because the concentration of sodium chloride is similar to that of the cells' internal environment. The isotonic nature of Solution A ensures that there is no net movement of water across the cell membrane, resulting in the cells maintaining their normal shape and size.
However, when comparing the tonicity of Solutions B, C, D, and E to Solution A and each other, differences arise. Tonicity refers to the osmotic pressure exerted by a solution on a cell and is influenced by the concentration of solutes within the solution. Solutions B and E both contain additional solutes along with NaCl.
Solution B, consisting of 100 mM glucose and 100 mM NaCl, has a higher tonicity compared to Solution A. Glucose cannot freely cross the cell membrane, creating an osmotic gradient that draws water into the red blood cells, causing them to swell.
Solution C contains 100 mM Drug X, a small non-polar molecule, along with 150 mM NaCl. Since Drug X is non-polar, it can freely cross the cell membrane. The presence of Drug X does not significantly affect the tonicity compared to Solution A, as it does not create an osmotic gradient.
In contrast, Solution D, which contains 150 mM MgCl2, has a higher tonicity than Solution A. MgCl2 dissociates into Mg2+ and Cl- ions, both of which cannot cross the cell membrane easily. The higher concentration of impermeable ions creates an osmotic gradient, leading to water loss from the red blood cells and causing them to shrink.
Lastly, Solution E consisting of 300 mM fructose has a higher tonicity compared to Solution A. Fructose cannot freely cross the cell membrane, resulting in an osmotic gradient that draws water into the red blood cells, causing them to swell.
In summary, placing red blood cells in Solution A does not produce significant changes in the cells. However, when comparing the tonicity of Solutions B, C, D, and E to Solution A and each other, variations in osmotic pressure occur due to the presence of different solutes.
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The equivalence point on a weak base/ strong acid titration curves occurs at a pH: a) greater than 7 b) equal to 7 c) less than 7
The equivalence point on a weak base/ strong acid titration curves occurs at a pH c) less than 7
The equivalence point on a weak base/strong acid titration curve occurs when the number of moles of the strong acid added is equal to the number of moles of the weak base in the solution. At the equivalence point, all the weak base has been converted to its conjugate acid. The pH at the equivalence point depends on the strength of the weak base and the strong acid used.
In general, weak bases have a pH greater than 7 because they produce solutions with lower concentrations of H+ ions. When a strong acid is added to a weak base, the pH decreases as the solution becomes more acidic. However, at the equivalence point, all the weak base has been converted to its conjugate acid, which is acidic. Therefore, the pH at the equivalence point for a weak base/strong acid titration is less than 7.
So the answer is (c) less than 7.
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Help help help I will give you 10 points
Answer: D: both teams will remain in place.
Explanation: if both teams have the same amount of force, they will cancel each other out and stay in place.
half life for radioactive decay of 32p is 14.2 days. how many days would be required for a sample of a radiopharmaceutical containing 32p to decreaseto 20% of its initial activity
The initial activity is t = 33.033 ≈ 3 day.
How do you calculate radioactive decay using half-life?Based on the amount of time needed for a reactant's concentration to drop to half its initial value, another method of describing reaction rates is used. The reaction's half-life, abbreviated as t1/2, is defined as this duration.As a result, the reactant concentration must decrease from [A]0 to [A]0/2 within a certain amount of time for a reaction to reach its half-life.A faster reaction will have a shorter half-life than a slower reaction if the two reactions have the same order.A given set of reaction conditions will always result in a constant half-life for a first-order reaction. Second- and zeroth-order reactions are an exception to this rule. Regardless of the reactant concentration, a first-order reaction has an independent half-life.This is clear from the equation that results from rearranging the integrated rate law for a first-order reaction:m = 0.2m × (1/2) t/14,3 ║ 0,2m
m/0,2m = (1/2) t/14,3
5=(1/2) t/14,3
log ab = C ⇔ ac = b
t/14,3 = log (1/2)5
t/14,3 = 2,31 ║× 14.3
t = 33.033 ≈ 3 day.
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Which of the following does NOT move thermal energy
through convection currents on Earth?
a the ocean
b the atmosphere
€ molten rock
Which statement best summarizes how viruses cause disease? A. Viruses absorb nutrients from another organism's body. B. Viruses use living cells to make new viruses. C. Viruses reproduce best in warm, moist environments. D. Viruses use cell parts for nutrients.
Answer:
its not d its b i took the quiz
Explanation:
Because the triple beam balance is zeroed before it is put into use, it measures
A.
volume
B.
weight
C.
the effects of gravity
D.
mass
at rest, sebastian's measured vital capacity is 3600 ml, with an inspiratory reserve volume of 2000 ml and a tidal volume of 600 ml. during exercise, his inspiratory reserve volume was 1800 ml and his expiratory reserve volume was 900 ml. what was his tidal volume during exercise?
Sebastian's measured pulse rate is 3600 ml at rest, with a vital capacity of 600 ml and an inspiratory volume of 2000 ml. His tidal volume is 1800 ml while his reserves for expiration was 900 ml while he was exercising. His vital capacity during exercise ranged from 500 to 3000 ml.
The space covered within an object's borders in three dimensions is referred to as its volume. It is sometimes referred to as the object's capacity. The total square footage an object occupies in three dimensions is indicated by its volume. The term "capacity" indicates something's ability to contain, absorb, or receive by an item (such as a solid substance, gas, or liquid).
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Although I2 is the stable form of iodine at low temperatures, at high temperatures the molecule can dissociate:
Upper I subscript 2 (g) double-headed arrow 2 upper I (g).
What is the equilibrium constant expression for this system?
K subscript e q equals StartFraction StartBracket upper I EndBracket superscript 2 over StartBracket upper I subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper I EndBracket over StartBracket upper I subscript 2 EndBracket EndFraction.
K subscript e q equals StartFraction StartBracket upper I subscript 2 EndBracket over StartBracket upper I EndBracket superscript 2.
Answer:
1. A
2. B
3. Left/Reactants
Explanation:
UWU
Answer:
Question 1 : A
Question 2: B
Question 3: In this system, the equilibrium lies to the ✔ left,and the reaction favors the reactants.
Explanation:
Hope this helps.
Edge 2022
Calculate the theoretical mass percentage of oxygen in potassium chlorate (KClO3).
To calculate the theoretical mass percentage of oxygen in potassium chlorate (KClO3), we need to find the molar mass of KClO3 and the molar mass of oxygen.
The molar mass of KClO3 can be calculated by adding the atomic masses of its constituent elements:
K = 39.10 g/mol
Cl = 35.45 g/mol
O = 3 x 16.00 g/mol = 48.00 g/mol
Molar mass of KClO3 = 39.10 g/mol + 35.45 g/mol + 48.00 g/mol = 122.55 g/mol
The molar mass of oxygen is 16.00 g/mol.
The percentage of oxygen by mass in KClO3 can be calculated using the formula:
(molar mass of oxygen / molar mass of KClO3) x 100
= (16.00 g/mol / 122.55 g/mol) x 100
= 13.05%
Therefore, the theoretical mass percentage of oxygen in potassium chlorate (KClO3) is 13.05%.
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What is the main idea of this text?
A. Some plants, such as mosses, lichens, and orchids, have learned to get water and nutrients from the air.
B. Instead of getting food and water from the soil, parasitic plants have developed roots to cling to a host plant, pierce through its leaves, stem, or trunk, and suck out nutrients.
C. Plants in tropical rainforests have adapted to their warm and wet conditions by making adjustments in how they grow.
D. Water trapped in the crevices of a plant, in combination with warm temperatures, is a breeding ground for bacterial and fungal growth.
C. The main idea of this text is that plants in tropical rainforests have adapted to their warm and wet conditions by making adjustments in how they grow.
This includes how certain plants, such as mosses, lichens, and orchids, have evolved to get their water and nutrients from the air. It also covers parasitic plants that have developed roots to attach to a host plant and extract nutrients, and how plants in tropical rainforests have adapted to their warm and wet conditions. Additionally, the text discusses how water trapped in plant crevices can lead to bacterial and fungal growth. Overall, the text highlights the various ways in which plants have adapted to their surroundings for survival. This adaptation includes various strategies, such as obtaining water and nutrients from the air, developing parasitic roots to obtain nutrients from host plants, and coping with potential bacterial and fungal growth due to trapped water and warm temperatures.
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helppp me!!!
why a multicellular organism needs specialized cells to survive
Answer:
Cells function differently in unicellular and multicellular organisms. A unicellular organism depends upon just one cell for all of its functions while a multicellular organism has cells specialized to perform different functions that collectively support the organism.
How do humans maintain homeostasis ?
Answer:
Homeostasis is generally maintained by a negative feedback loop that includes a stimulus , sensor , control centre , and effector . Negative feedback serves to reduce an excessive response and to keep a variable within the normal range. Negative feedback loops control body temperature and the blood glucose level.