balance _NH3+O2→NO+H2O

Answer:gold iron and uranium

Explanation:

Answer:

iron, density: 7.8 g/cm³

aluminum, density: 2.7 g/cm³

silver, density: 10.5 g/cm³

lead, density: 11.3 g/cm³

Explanation:

other ones wrong

Answer:

200.0°C.

Explanation:

The resulatant volume of gas under given conditions is 9.49 liters.

Ideal gas equation gives idea about the behavior of gases at different conditions and it will be represented as:

PV = nRT, where

P = pressure in atm

V = volume in L

n = moles of gas

R = universal gas constant = 0.082 L.atm/K.mol

T = temperature in K

First we calculate the moles of gas by putting the values according to the first condition in the above equation and we have

n = (0.921)(500) / (0.082)(473) = 11.86 moles

Now we calculate the volume of gas by using the above equation and details of the second condition as:

V = (11.86)(0.082)(293) / (30) = 9.49 L

Hence resultant volume of the gas is 9.49L.

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Answer:

ternary

Explanation:

A ternary ionic compound is a polyatomic ionic compound composed of three or more different elements.

An ionic compound is a chemical complex made up of ions that are held together through electrostatic forces. The molecule is essentially neutral, however, it contains positively charged cations as well as negatively charged anions.

An ionic compound with three components is known as a ternary ionic compound. One type of cation including one type of anion are still present in a typical ternary ionic combination. Polyatomic ions are cations, anion, or both.

Therefore, a ternary ionic compound is a polyatomic ionic compound composed of three or more different elements.

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Maintaining close control over the temperature at which municipal solid waste is burned in an incinerator minimizes the emission of harmful pollutants, such as dioxins, furans, and particulate matter.

Maintaining close control over the temperature at which municipal solid waste is burned in an incinerator minimizes the emission of harmful pollutants and greenhouse gases. This is because high temperatures promote complete combustion, which results in fewer emissions of harmful substances such as carbon monoxide, nitrogen oxides, and volatile organic compounds. By minimizing emissions, incineration becomes a more environmentally friendly option for managing solid waste.

Maintaining close control over the temperature at which municipal solid waste is burned in an incinerator minimizes the emission of harmful pollutants, such as dioxins, furans, and particulate matter. By ensuring the incineration process occurs at optimal temperatures, the combustion of solid waste is more complete, reducing the amount of harmful emissions released into the atmosphere.

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Maintaining close control over the temperature at which municipal solid waste is burned in an incinerator minimizes the emission of pollutants such as dioxins, furans, and volatile organic compounds (VOCs).

Maintaining close control over the temperature at which municipal solid waste is burned in an incinerator minimizes the emission of harmful pollutants, such as dioxins, furans, and nitrogen oxides (NOx). By controlling the temperature and ensuring optimal combustion conditions, the formation of these pollutants can be reduced, leading to a cleaner and more environmentally friendly incineration process.

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Propenal and propanone allylic alcohol are the two constitutional isomers that contain carbon-oxygen double bonds.

What exactly are isomers?

Isomers have chemical structures that are nearly identical but have different spatial arrangements.

A double bond connects the carbon and oxygen atoms in this isomer. Because both molecules contain allylic alcohol three carbon atoms, they can be referred to as prop. Propenal and propanone are names derived from the presence of an aldehyde and a ketone functional group.

Propenal and propanone are the two constitutional isomers with carbon-oxygen double bonds.

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The amount of electrical work (per mole) obtained from burning liquid methanol is 666.0 kJ/mol.

What is electrical work?

Electric charges flow across a potential difference or voltage during electrical work, labor carried out by or on an electrical system.

a) The balanced chemical equation for the reaction is:

2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l)

b) The maximum amount of electrical work that may be produced by burning one mole of liquid methanol can be estimated as the reaction's negative Gibbs free energy change, which is given by:

ΔG = ΔH - TΔS

ΔH = enthalpy change of the reaction,

ΔS =entropy change of the reaction,

T = temperature in Kelvin.

The standard formation enthalpies of the reactants and products can be used to calculate the reaction's enthalpy change:ΔH°f(CH3OH,l) = -239.1 kJ/mol

ΔH°f(\(CO_{2}\),g) = -393.5 kJ/mol

ΔH°f(\(H_{2}O\),l) = -285.8 kJ/mol

The enthalpy change of the reaction is, therefore:

ΔH = [ΔH°f(\(CO_{2}\),g) + 2ΔH°f(\(H_{2} O\),l)] - [ΔH°f(\(CH_{3}OH\),l) + 1.5ΔH°f(\(O_{2}\),g)]

ΔH = [-393.5 kJ/mol + 2(-285.8 kJ/mol)] - [-239.1 kJ/mol + 1.5(0 kJ/mol)]

ΔH = -726.3 kJ/mol

The standard entropies of the reactants and products can be used to determine the reaction's entropy change:

ΔS°f(\(CH_{3}OH\),l) = 126.8 J/mol·K

ΔS°f(\(CO_{2}\),g) = 213.6 J/mol·K

ΔS°f(\(H_{2}O\),l) = 69.9 J/mol·K

ΔS°f(\(O_{2}\),g) = 205.0 J/mol·K

The entropy change of the reaction is, therefore:

ΔS = [ΔS°f(\(CO_{2}\),g) + 2ΔS°f(\(H_{2}O\),l)] - [ΔS°f(\(CH_{3}OH\),l) + 1.5ΔS°f(\(O_{2\\\),g)]

ΔS = [213.6 J/mol·K + 2(69.9 J/mol·K)] - [126.8 J/mol·K + 1.5(205.0 J/mol·K)]

ΔS = -201.7 J/mol·K

Assuming T1 = 298 K, the maximum amount of electrical work that can be obtained from burning one mole of liquid methanol is:

ΔG = ΔH - T1ΔS

ΔG = -726.3 kJ/mol - 298 K(-201.7 J/mol·K)

ΔG = -726.3 kJ/mol + 60.3 kJ/mol

ΔG = -666.0 kJ/mol

Therefore, at 298 K and 1 bar, one mole of liquid methanol can burn for a maximum of 666.0 kJ/mol of electrical work.

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The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\). The reaction releases a large amount of energy, but cannot occur spontaneously and requires an input of energy.

a) The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is:

\(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\)

b) To calculate the amount of electrical work that can be obtained from burning liquid methanol, we need to determine the change in Gibbs free energy (ΔG) of the reaction. This can be calculated using the standard Gibbs free energy change (ΔG°) and the reaction quotient (Q):

ΔG = ΔG° + RTln(Q)

where R is the gas constant, T is the temperature in Kelvin, and ln(Q) is the natural logarithm of the reaction quotient.

Assuming standard conditions (298 K and 1 bar), we can use tabulated values of standard Gibbs free energy of formation (ΔG°f) to calculate ΔG° for the reaction:

\($\Delta G^\circ = \sum n \Delta G^\circ_\mathrm{f}(products) - \sum m \Delta G^\circ_\mathrm{f}(reactants)$\)

\($\Delta G^\circ = [2\Delta G^\circ_\mathrm{f}(CO_2) + 4\Delta G^\circ_\mathrm{f}(H_2O)] - [2\Delta G^\circ_\mathrm{f}(CH_3OH) + 3\Delta G^\circ_\mathrm{f}(O_2)]$\)

\($\Delta G^\circ = [-394.4\ \mathrm{kJ/mol} + 4(-285.8\ \mathrm{kJ/mol})] - [-238.8\ \mathrm{kJ/mol} + 3(0\ \mathrm{kJ/mol})]$\)

\($\Delta G^\circ = -726.4\ \mathrm{kJ/mol}$\)

The reaction quotient Q can be calculated from the initial and final concentrations of the reactants and products. Since we are assuming complete combustion, the initial concentration of methanol is equal to the amount of methanol we are burning, which is 1 mole. The final concentrations of the products can be calculated using the stoichiometry of the balanced equation. At equilibrium, Q = Kc, where Kc is the equilibrium constant for the reaction. For complete combustion, the value of Kc is very large, as the reaction goes essentially to completion. Thus, we can consider that Q ≈ ∞and the natural logarithm of Q is then infinity:

ln(Q) ≈ ln(∞) = ∞

Substituting the values into the equation for ΔG, we get:

ΔG = ΔG° + RTln(Q)

ΔG = -726.4 kJ/mol + (8.314 J/mol*K) * (298 K) * ln(∞)

ΔG ≈ -∞

The negative value of ΔG indicates that the reaction is exergonic, meaning it releases energy. However, the value of ΔG is so large that the reaction cannot occur spontaneously. In other words, the reaction requires an input of energy to occur, which means that it cannot be used to obtain electrical work. The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\).

To obtain electrical work from the combustion of liquid methanol, we need to use a fuel cell or a combustion engine, which can harness the energy released by the reaction to generate electricity. The amount of electrical work that can be obtained will depend on the efficiency of the device used and may be less than the total amount of energy released by the reaction.

The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\). The reaction releases a large amount of energy, but cannot occur spontaneously and requires an input of energy.

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The given redox reaction is:

Cr2O7^2- + C2H4O → C2H4O2 + Cr3+

To balance this reaction, we first balance the oxygen atoms by adding H2O on the right side of the equation. The number of H2O molecules added depends on the number of oxygen atoms needed. In this case, we need three O atoms on the right side, so we add three H2O molecules to the right side of the equation:

Cr2O7^2- + C2H4O → C2H4O2 + Cr3+ + 3H2O

Next, we balance the hydrogen atoms by adding H+ ions on the left side of the equation. The number of H+ ions added depends on the number of hydrogen atoms needed. In this case, we need eight H atoms on the left side, so we add eight H+ ions to the left side of the equation:

Cr2O7^2- + C2H4O + 8H+ → C2H4O2 + Cr3+ + 3H2O

Finally, we balance the charge by adding electrons. The number of electrons added depends on the difference in charge on the left and right side of the equation. In this case, the left side has a charge of -2 (from the Cr2O7^2- ion), while the right side has a charge of +3 (from the Cr3+ ion). This means that we need to add 5 electrons to the left side of the equation to balance the charge:

Cr2O7^2- + C2H4O + 8H+ + 5e- → C2H4O2 + Cr3+ + 3H2O

Therefore, the coefficient for water molecules in the balanced version of the given redox reaction is 3.

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Answer:

The density of the liquid is 3 g/mL.

Explanation:

Equation of density:

D = m/v

Plug in the known information:

D = 45 g / 15 mL

Solve:

D = 45 g / 15 mL

D = 3 g/mL

Answer:

100 trillion atoms are in one cell and  so just find how many cells are in a chair and then take 100xthe number and you get your answer

Explanation:

There are uncountable atoms which are present in a chair depending on it's size.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

How long does it take for a tennis ball to fall from a certain height if recorded in different weather?

Explanation:

Can I have brainliest?

Answer:

How far can a ball travel if thrown during different wind speed?

Explanation:

Brainliest Plzzz!!!

You would be most likely to use a slicing machine if you were using the icebox method to produce cookies.

In the icebox method a type of cookie in which the dough is made, rolled into a stick, and refrigerated until the dough hardens. The dough can be removed from the refrigerator, cut into individual pieces, and then baked. The rest of the dough is returned to the refrigerator until needed.

Icebox method, also known as refrigerator cookies, are sliced ​​and baked cookies. The dough is formed into logs, chilled in the refrigerator (also called an icebox), sliced ​​, and then baked.

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ANSWER

the volume of the solution is 2.05 liters

EXPLANATION

Given that;

The concentration of Ca(OH)2 is 0.420M

The grams of Ca(OH)2 is 64.0 grams

Follow the steps below to find the volume of the solution

Step 1; Calculate the number of moles of Ca(OH)2 using the below formula

Recall, that the molar mass of Ca(OH)2 is 74.093 g/mol

Step 2; Find the volume of the solution in liters using the below formula

Therefore, the volume of the solution is 2.05 liters

Answer:

gonna check them rn :) youre not d u mb dont worry (:

Answer:

Your statement is right.

Explanation:

When fuels are burned in vehicle engines, high temperatures are produced. At this high temperature, nitrogen and oxygen from the air combine with each other to produce nitrogen monoxide (NO). When this nitrogen monoxide is released in the air from vehicle exhaust systems, it combines with oxygen present in the air to form nitrogen dioxide (NO2).

The three technologies used to convert biomass energy into heat and electricity are Combustion, Gasification, Anaerobic Digestion.These technologies enable the efficient utilization of biomass resources, reducing reliance on fossil fuels and contributing to renewable energy generation.

Combustion: Biomass combustion is a widely used technology that involves burning biomass materials, such as wood, agricultural residues, or dedicated energy crops, to produce heat and electricity. In this process, biomass is burned in a controlled manner, and the heat generated is used to produce steam, which drives a turbine connected to a generator. The combustion process releases carbon dioxide (CO2), but since biomass is considered a renewable energy source, the CO2 emitted is part of the natural carbon cycle and does not contribute to net greenhouse gas emissions.

Gasification: Biomass gasification is a thermochemical process that converts biomass into a combustible gas known as syngas. The biomass is subjected to high temperatures in a low-oxygen environment, resulting in the production of syngas, which mainly consists of carbon monoxide (CO), hydrogen (H2), and traces of other gases. The syngas can be used directly for heating purposes or for the production of electricity through internal combustion engines, gas turbines, or fuel cells.

Anaerobic Digestion: Anaerobic digestion is a biological process that breaks down biomass, such as animal manure, crop residues, or organic waste, in the absence of oxygen. During the anaerobic digestion process, microorganisms break down the biomass, producing biogas, which is primarily composed of methane (CH4) and carbon dioxide (CO2). The biogas can be combusted to produce heat and electricity, or it can be upgraded to biomethane and injected into the natural gas grid or used as a transportation fuel.

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Answer:

Gas

Explanation:

Because Crude oil can usually be found in the ground as a liquid and in the air is gas can be kerosene.

Answer:

3.70 × 10³ g

Explanation:

To find the mass of the sample, multiply the volume by the density.

(55.1 cm³) × (6.72 g/cm³) = 3.70 × 10³ g

The mass of the sample will be 3.70 × 10³ g.

The term "density" refers to the mass of a material per unit volume. Density is defined by the equation d = M/V, where M stands for mass, and V for volume. Typically, density is measured in grammes per cubic centimetre.

As an illustration, water has a density of 1 gramme per cubic centimetre, whereas Earth has a density of 5.51 gramme per cubic centimetre. Kg/cubic metre is another method to express density (in metre-kilogram-second or SI units).

For instance, the air has a density of 1.2 kilogrammes per cubic metre. Textbooks and manuals provide lists of the densities of common solids, liquids, and gases. The mass of a body may be calculated from its volume using density, and vice versa. The mass is equal to the volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).

By dividing the mass by the acceleration of gravity, one may get a body's weight, which is typical of more practical importance than its mass.

The mass of the sample can be obtained by multiplying the volume by the density.

(55.1 cm³) × (6.72 g/cm³) = 3.70 × 10³ g

Therefore, the mass will be 3.70 × 10³ g

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a) The sphere emits thermal radiation at a rate of 139.75 Watts.

b) The sphere absorbs thermal radiation at a rate of 37.66 Watts.

c) The sphere's net rate of energy exchange is 102.09 Watts.

To calculate the rates of thermal radiation emission and absorption, we can use the Stefan-Boltzmann law, which states that the rate of thermal radiation emitted or absorbed by an object is proportional to its surface area, temperature, and the Stefan-Boltzmann constant.

a) The rate of thermal radiation emitted by the sphere can be calculated using the formula:

Emitting Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(temperature^4 - environment\ temperature^4\))

Plugging in the given values:

Emitting Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((32.2 + 273.15)^4 - (82.9 + 273.15)^4)\)

Emitting Rate ≈ 139.75 Watts

b) The rate of thermal radiation absorbed by the sphere can be calculated in a similar way but using the environment temperature as the object's temperature:

Absorbing Rate = emissivity * surface area * Stefan-Boltzmann constant * (\(environment\ temperature^4 - temperature^4\))

Plugging in the given values:

Absorbing Rate = \(0.924 * (4\pi * (0.457)^2) * 5.67 \times 10^{-8} * ((82.9 + 273.15)^4 - (32.2 + 273.15)^4)\)

Absorbing Rate ≈ 37.66 Watts

c) The net rate of energy exchange is the difference between the emitting rate and the absorbing rate:

Net Rate = Emitting Rate - Absorbing Rate

Net Rate = 139.75 Watts - 37.66 Watts

Net Rate ≈ 102.09 Watts

Therefore, the sphere emits thermal radiation at a rate of 139.75 Watts, absorbs thermal radiation at a rate of 37.66 Watts, and has a net rate of energy exchange of 102.09 Watts.

Note: The units for all the rates are Watts.

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The following statement is true about the given reaction:The statement that is true about the given reaction is:"51g of water is produced for every mole of Na3C6H5O7.

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The displacement reactions produces insoluble precipitates of barium sulfate and cobalt carbonate retrospectively.

Displacement reactions are reactions in which an atom of an element or radical removes and replaces another arim or radical in a substance.

The displacement reaction between zinc sulfate and barium chloride is given below:

\(ZnSO_4(aq) + BaCl_2(aq) \rightarrow ZnCl_2(aq) + BaSO_4(s) \\ \)

The balanced equation for the displacement reaction between aqueous solutions of lithium carbonate and cobalt(Il) acetate is given below as follows:

\(Li_2CO_3(aq) + Co(C_2H_3O_2)_2(aq) \rightarrow 2C_2H_3LiO_2(aq) + CoCO_3(s) \\ \)

Therefore, the displacement reactions produces insoluble precipitates of barium sulfate and cobalt carbonate retrospectively.

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A titration curve is a graph showing the progress of a titration of a mixture of chemicals as a function of the amount of reactant added. A plot of pH vs. quantity of titrant added is a typical titration curve.

The curve's form is determined by the nature of the titrant, the nature of the sample being evaluated, the extent of the acid-base reaction, and the concentration of the reactants. Furthermore, the equivalence point, which is the point at which the quantity of titrant added is just enough to neutralize the sample being titrated, is often indicated on a titration curve. The titration curve for a strong base-weak acid titration and the titration curve for a weak acid-strong base titration differ slightly, with different pH ranges and shapes. In general, the titration curve of a weak acid-strong base titration begins and ends at higher pH values than the titration curve of a strong acid-weak base titration. In addition, the titration curve of a weak acid-strong base titration has a distinct inflection point that is not present in the titration curve of a strong acid-weak base titration.

Finally, the titration curve of a weak acid-strong base titration is shown below. Therefore, let's look at the pH values of NaHCO3 titrated with 1.0 M HCl. 1. pH after 0 mL HCl addedThe pH of NaHCO3, which is a weak base, is slightly basic, or around 8.4.2. pH after 1.0 mL HCl addedWe will see a little decrease in pH when we add 1.0 mL of 1.0 M HCl to 10.0 mL of 1.0 M NaHCO3.3. pH after 9.5 mL HCl addedThe pH of NaHCO3 is about 4.5 at this point. This is the endpoint of the weak acid-strong base titration.4. pH after 10.0 mL HCl addedThe equivalence point is reached after adding 10.0 mL of HCl, which corresponds to the neutralization of 10.0 mL of 1.0 M NaHCO3. The pH at the equivalence point of a weak acid-strong base titration is around 7.0.5. pH after 10.5 mL HCl addedAt this point, the pH of the mixture is more acidic, approximately 3.5.6. pH after 12.0 mL HCl addedThis point will be more acidic than the previous point, and the pH will be around 2.0 to 2.5.

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Answer: Water won't boil at normal atmospheric pressure until 100 C so it will appear fairly neutral until then. Pure water is completely translucent and colorless. It is also tasteless and odorless. Because completely pure water has no electrolytes, it will be a poor conductor of electricity.

Answer:

a

Explanation:

I'll explain along side with potassium (k) and Calcium (Ca). the unit for scandium is SC

Sc = 21

Ca = 20

K =19

k = 1s²,2s²,2p⁶,3s²,3p⁶,3d⁰,4s¹

Ca = 1s²,2s²,2p⁶,3s²,3p⁶,3d⁰,4s²

Sc = 1s²,2s²,2p⁶,3s²,3p⁶,3d¹,4s²

if you notice above Sc has 3d¹ while Ca has 3d⁰. This is because Sc is a transition metal

Transition metals are metals whose d-orbital aré partially filled with electron

Answer:

982.5 kg/m³

Explanation:

When the temperature of a fluid increases, it dilates, and because of the variation of the volume, it's density will vary too. The density can be calculated by the expression:

ρ₁ = ρ₀/(1 + β*(t₁ - t₀))

Where ρ₁ is the final density, ρ₀ the initial density, β is the constant coefficient of volume expansion, t₁ the final temperature, and t₀ the initial temperature.

At t₀ = 4°C, the water desity is ρ₀ = 1,000 kg/m³. The value of the constant for water is β = 0.0002 m³/m³ °C, so, for t₁ = 93°C

ρ₁ = 1,000/(1 + 0.0002*(93 - 4))

ρ₁ = 1,000/(1+ 0.0178)

ρ₁ = 982.5 kg/m³

Answer:

through water

Explanation:

To solve this problem, we need to use the ideal gas law, which relates the pressure, volume, and temperature of a gas to the number of moles of gas present. We can use the balanced chemical equation to determine the number of moles of oxygen produced by the reaction of LICIO4.

The molar mass of LICIO4 is:

LICIO4: Li = 1 x 1 = 1 g/mol, I = 127 g/mol, O4 = 4 x 16 = 64 g/mol

Total molar mass = 1 + 127 + 64 = 192 g/mol

So, 500 g of LICIO4 is equal to:

500 g / 192 g/mol = 2.604 moles of LICIO4

From the balanced chemical equation, we see that for every mole of LICIO4, two moles of oxygen are produced:

1 mol LICIO4 → 2 mol O2

Therefore, 2.604 moles of LICIO4 will produce:

2.604 moles x 2 mol O2/1 mol LICIO4 = 5.208 moles of O2

Now we can use the ideal gas law to calculate the volume of oxygen produced at the given temperature and pressure:

PV = nRT

where P is the pressure (101.5 kPa), V is the volume we want to find, n is the number of moles of oxygen (5.208 moles), R is the ideal gas constant (8.314 J/mol K), and T is the temperature in Kelvin (21°C + 273 = 294 K).

V = (nRT)/P

V = (5.208 mol x 8.314 J/mol K x 294 K)/101.5 kPa

Converting kPa to Pa, we get:

V = (5.208 mol x 8.314 J/mol K x 294 K)/(101.5 x 1000 Pa)

V = 101.92 m3 or 101,920 L

Therefore, the system would produce approximately 101,920 liters of oxygen at the station's standard operating conditions.

Answer:

Tellurium has a higher electronegativity than antimony because it has one more proton which creates a stronger attraction between the protons and electrons.

Explanation:

Hope this helped! Stay safe and goodluck on what you're doing! ♥♥♥