b) if the moon followed the same orbital plane but was twice as far away, would there be solar eclipses?

Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.

The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:

ωn = √(K / M),

where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.

Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.

ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.

Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.

The correct question is given as,

M= 20kg

Fo = 90 N

ω = 6 rad/s

K = 400 N/m

C = 125 Ns/m

Determine the frequency of applied force at which resonance will occur?

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a. The rotational inertia of the rod is 0.0004 kgm²

b. The rotational inertia of a weight is 0.0009025 kgm²

c. The total rotational inertia is 0.002205 kgm²

Rotational inertia is a property of an object which shows its aboility to rotate about an axis.

The rotational inertia of  a rod is given by I = 1/12ML² where

Given that

So, substituting the values of the variables into the equation, we have that

I = 1/12ML²

= 1/12 × 0.030 g × (0.40 cm)²

=  1/12 × 0.030 kg × 0.1600 m²

=  1/12 × 0.0048 kgm²

= 0.0004 kgm²

So, the rotational inertia of the rod is 0.0004 kgm²

The rotational inertia of the weight (as a hoop) is given by I' = 1/2mL' where

Given that

So, substituting the values of the variables into the equation, we have that

I' = 1/2mL'²

= 1/2 × 0.050 g × (0.19 cm)²

= 0.025 kg × 0.0361 m²

= 0.0009025 kgm²

So, the rotational inertia of a weight is 0.0009025 kgm²

The total rotational inertia, I" = rotational inertia of rod + rotational inertia of both weights.

So, I" = I + 2I'

= 0.0004 kgm² + 2 × 0.0009025 kgm²

= 0.0004 kgm² + 0.001805 kgm²

= 0.002205 kgm²

So, the total rotational inertia is 0.002205 kgm²

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Answer:

Height: Weight: Your BMI is , indicating your weight is in the category for adults of your height. For your height, a healthy weight range would be from to pounds....

Explanation:

Answer:

I think its D.....

Answer:

B. The water collects in a low-lying area.

Explanation:

X Mudflow blocking a river can act like a dam, not making any puddles.

X Humans making a dam means the pond can't be formed naturally.

X An ice sheet covers the pond, and if it's connected to any other sheets of ice, it won't be a pond.

Answer:

That the universe is "expanding"

Consider dots painted on the surface of a balloon - if the dots are moving away from one another, the balloon must be expanding.

The number of seconds in the 40 second interval starting at t = 0 during which the voltage is below 0.21m V is: 19.06 - 7.03 = 12.03 s = 12.97 (approx.) Thus, the correct option is (c) 12.97.

The voltage V, in an electric circuit is measured in millivolts (mV) and is given by the formula V=0.2

sin0.1π(t -0.5)+0.3, where t is the time in seconds from the start of an experiment. We have to use the graph of the function to estimate how many seconds in the 40 second interval starting at t = 0 during which the voltage is below 0.21mV.

Graph of the given function is shown below:

Graph of the given function

As per the graph, it is observed that the voltage is below 0.21 mV from 7.03 s to 19.06 s.

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Option D is correct. In venturi meter a converging section of a pipe is used to increase the flow velocity and corresponding pressure drop, from which the fluid flow rate is calculated using Bernoulli's equation.

A venturimeter is a flow measurement device. The meter is connected between two sections of the pipe; the cross-sectional area A of the meter's entrance and exit corresponds to the cross-sectional area of the pipe. The fluid flows from the pipe with speed V between the entrance and exit, and then through a narrow throat with cross-sectional area a with speed v. A venturi works by measuring the difference in pressure between two points. The pressure difference is created by narrowing the pipe, causing the fluid to flow faster. In the larger section of the venturi, the fast moving fluid has a lower pressure than the slower fluid.

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Answer:

Equivalent resistance of the circuit is 116 ohm.

Explanation:

Finding the equivalent resistance of the circuit. Since, 29 ohm resistors are connected in series, so

→ Equivalent resistance = R_1 + R_2 + R_3 + R_4

→ Equivalent resistance = (29 + 29 + 29 + 29) ohm

Answer:

Explanation:

Newton's first law of motion states that an object in motion stays in motion. The orange is moving and then the tray stops making the orange move forward because of inertia.

Answer:

The off the tray due to the inertia of motion

Explanation:

As we suddenly stop, the tray and our body comes to rest instantly they are in contact. The placed on tray and keeps moving due to the inertia of motion and hence roll of your tray

The total charge and total energy in the circuit remain the same, the distribution of charge and energy changes due to the different capacitances of the capacitors.

When the two capacitors are connected in series, the total charge on both capacitors remains the same. Therefore, the voltage drop across capacitor A, which is initially charged to voltage V0, must be equal to the voltage drop across capacitor B, which is initially uncharged.

Using the formula for capacitance (C = Q/V), we can rewrite this equation as:

\(Q/CA = Q/CB\)

\(VA = Q/CA\)

\(VB = Q/CB\)

We also know that CB = 3CA, so we can substitute this into the equation for VB:

\(VB = Q/3CA\)

Since VA and VB are equal, we can set their equations equal to each other and solve for VA:

\(VA = VB\)

\(Q/CA = Q/3CA\)

\(VA = V0/3\)

Therefore, the new voltage across capacitor A (VA) is one-third of the original voltage (V0).

When the capacitors are connected in series, the total capacitance of the circuit decreases, which means that the charge is distributed over a smaller total capacitance. This results in a higher voltage drop across each capacitor.

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The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.

To find the electric field(E) due to a symmetrical surface, Gauss’ Law is used, which is

E x (ds) = q/ε

Here ds = surface area of the surface

And Q = charge enclosed by the surface

As the balloon is spherical with radius a, its area will be 4πa^2

Putting the values in the above equation

E x 4πa^2 = Q/(ε)

E = Q/4πa^2(ε)

The surface charge density(ω) = Q/4πa^2

Hence

E = ω/ε

Thus, The electric field outside the balloon at all points in space is ω/ε where ω = Q/4πa^2.

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Answer:

182 V

Explanation:

We do:V=I.R

V is energy so

I = 7

R = 7+7+3+3+6

V= 7.26

V=182

Answer:

The Answer is C

The speed of light in a vacuum is the same for all frames of reference.

Explanation:

Answer:

C .The speed of light in the vacuum is same for all frames of reference.

Explanation:

A set of abstract coordinate system that explains the position or motion of something mathematically and physically by the set of reference points and geometric points.

What is Special relativity ?

It explains the effect on mass ,time and space by the speed . It also relates the speed of light , mass and energy.

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Answer:

Explanation:

lThe mass of an object given only it's force and acceleration can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question

f = 195 N

a = 2.1 m/s

We have

\(m = \frac{195}{2.1 } = 92.857142... \\ \)

We have the final answer as

Hope this helps you

Answer:

Cold temps. . .

Explanation:

Hope it helps!

The average force the air exerted on the box as it fell is approximately 23.2N.

The formula is F = 0.5*Cd*p*A*v², where F is the force of air resistance, Cd is the drag coefficient of the object, p is the density of air, A is the cross-sectional area of the object, and v is the velocity of the object.

In this case, we can assume that the box is a simple rectangular shape with a cross-sectional area of 0.1m² and a drag coefficient of 1.0 (a conservative estimate for a box-shaped object). We also know that the density of air is approximately 1.2kg/m³.

Using the formula, we can calculate the force of air resistance on the box when it reaches its maximum velocity, which is likely close to the end of its fall. The maximum velocity can be estimated using the equation v² = u² + 2as, where u is the initial velocity (0), a is the acceleration due to gravity (9.8m/s²), and s is the distance fallen (20m). Solving for v, we get v = 19.8m/s.

Plugging in these values, we get:
F = 0.5*1.0*1.2*0.1*19.8²
F = 23.2N

Therefore, the average force the air exerted on the box as it fell is approximately 23.2N.

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Explanation:

Los derechos de las mujeres fueron conquistados a través de importantes luchas llevadas a cabo por mujeres, como el movimiento feminista que tuvo lugar a fines del siglo XIX, cuyo principal reclamo fue el derecho al voto de las mujeres.

Con el tiempo, las mujeres ganaron más derechos y una mayor participación en el mercado laboral y en puestos importantes de la sociedad. Pero aún queda mucho por cambiar, ya que las estadísticas aún muestran que hay pocas mujeres en posiciones de poder en relación a los hombres, y el salario de una mujer que ocupa el mismo puesto que un hombre es siempre menor.

Dado que la sociedad se concibió a través de parámetros sexistas, lo que continúa en la actualidad, es claro que en la pandemia específicamente que generó crisis económicas en todo el mundo, se vio a una gran cantidad de mujeres perder sus empleos, además del expresivo número de casos de violencia doméstica que se agravaron en el período de aislamiento social.

Así que estos hechos solo demuestran que la lucha por la igualdad de género y los derechos de las mujeres aún están en sus inicios, a pesar de muchos logros que las mujeres aún deben luchar por lo básico, que es el apoyo social y político además de una legislación más estricta que castiga con más rigor a las agresoras. Las mujeres deben estar protegidas por la ley y las instituciones y los medios de comunicación deben abordar más el tema y promover el feminismo como una lucha por la igualdad.

An object's mass, rather than its weight is used to indicate the amount of matter it contains because weight is defined as the amount of force due to an existing field (In most cases, gravitational field) that is experienced by the body. The weight of the same body can be different in different environments it's observed.

However, the mass of the body is the exact measure of the amount of matter contained in a body. Which is constant, regardless of the environment, or conditions the body is observed.

Hence, for real-world calculations and experimentation, the mass of the body is considered to represent the amount of matter it contains rather than its weight.

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The area that the flashbulb is focused towards is then illuminated using the light and heat that are produced. As the chemical energy is transformed into both light and heat, creating a powerful and bright light source, this energy transformation is a very effective process.

The methods used to measure temperature from the options you provided are:
1. Calculating the temperature based on thermoelectric responses.
2. The expansion and contraction of mercury in a glass tube.
3. Measuring the wavelengths of electromagnetic energy given off by an object.

A flashbulb's energy transformation entails the translation of chemical energy into electromagnetic energy as well as heat energy in chemical energy.

The flashbulb stores chemical energy, which is then released when the bulb is activated. Then, this energy is transformed into thermal energy, which is the heat produced by the lightbulb, as well as electromagnetic energy, which is the light that the lightbulb emits.

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Answer:

White

Explanation:

Red comes from the lowest energy range of and blue from the highest.

When the ball is situated at a height of 10 meters above the ground, the gravitational energy stored in  ball-Earth system is 49 Joules.

The gravitational energy stored in the ball-Earth system when the ball is lifted to a height of 10 meters can be calculated using the formula:

Gravitational Energy = mass * gravitational acceleration * height

Given:

Mass of the ball (m) = 0.5 kg

Height (h) = 10 meters

Acceleration due to gravity (g) =\(9.8 m/s^{2}\)

Using the given values in the formula:

Gravitational Energy = 0.5 kg * \(9.8 m/s^{2}\) * 10 meters

Gravitational Energy = 49 Joules

Therefore, when the ball is situated at a height of 10 meters above the ground, the gravitational energy stored in the ball-Earth system is 49 Joules.

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--The complete Question is, A ball with a mass of 0.5 kg is lifted to a height of 10 meters above the ground. When the ball is in this elevated position, what is the gravitational energy stored in the ball-Earth system? Assume that the acceleration due to gravity is 9.8 m/s².--

The elements and groups that have properties most similar to chlorine are other halogens, specifically fluorine (F), bromine (Br), iodine (I), and astatine (At). These elements belong to Group 17 (Group VIIA) of the periodic table, also known as the halogens or Group 17 elements.

The halogens share similar chemical properties because they have the same valence electron configuration, specifically one electron short of a complete octet. This results in a strong tendency to gain one electron to achieve a stable configuration, making them highly reactive nonmetals. Like chlorine, fluorine is a highly reactive, pale yellow gas and is the most electronegative element. It exhibits similar reactivity and forms similar types of compounds with other elements.

Bromine is a reddish-brown liquid at room temperature and has properties comparable to chlorine, although it is less reactive. Iodine is a purple solid and is less reactive than chlorine, but still displays similar chemical behavior. Astatine is a highly radioactive element, and due to its rarity and short half-life isotopes, its properties are less well-studied. However, it is expected to exhibit chemical similarities to chlorine. Overall, the elements in Group 17 (halogens) share similar properties to chlorine due to their common electron configuration and their tendency to undergo similar chemical reactions and form analogous compounds.

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The wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. In a dentist's office, an X-ray of a tooth is taken using X-rays that have a frequency of 4.99 × 10^18 Hz. To calculate the wavelength in vacuum of these X-rays, we can use the equation:

wavelength = speed of light / frequency
The speed of light in vacuum is approximately 3 × 10^8 meters per second. Plugging in the given frequency, we get:
wavelength = (3 × 10^8 m/s) / (4.99 × 10^18 Hz)
Simplifying this expression, we get:
wavelength = 6.01 × 10^-11 meters

Therefore, the wavelength in vacuum of these X-rays is approximately 6.01 × 10^-11 meters. It's important to note that X-rays have a very short wavelength, which allows them to penetrate through tissues and bones. However, this also means that they can be harmful if not used carefully and with proper shielding.

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ANSWER

E. No, since work involves a non-zero displacement

EXPLANATION

Work done on an object is given by,

Where W is work, F is the force applied on the object, d is the displacement of the object and θ is the angle between the applied force and the displacement.

Note that if there's no motion, then d = 0. Because d is multiplying the other variables, if d = 0 then work is zero as well.

Hence, the answer is option E.

Answer:

The acceleration that the jet liner that must have is 2.241 meters per square second.

Explanation:

Let suppose that the jet liner accelerates uniformly. From statement we know the initial (\(v_{o}\)) and final speeds (\(v_{f}\)), measured in meters per second, of the aircraft and likewise the runway length (\(d\)), measured in meters. The following kinematic equation is used to calculate the minimum acceleration needed (\(a\)), measured in meters per square second:

\(a = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot d}\)

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v_{f} = 82\,\frac{m}{s}\) and \(d = 1500\,m\), then the acceleration that the jet must have is:

\(a = \frac{\left(82\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}}{2\cdot (1500\,m)}\)

\(a = 2.241\,\frac{m}{s^{2}}\)

The acceleration that the jet liner that must have is 2.241 meters per square second.