Avery took a wave motion rope and waved it sideways once. What kind of wave did Avery create, transverse, longitudinal, or a pulse?

One example is the Shame Plant.

It exhibits Negative Thigmotropism.

When you touch the plant, its leaves will curl up,

Answer:

The induced current can be increased in the coil in the following ways: By increasing the strength of the magnet. By increasing the speed of the magnet through the coil.

Explanation:

Answer: aaa

Explanation: a

aaa

Answer:

it helps to get rid of gas. and can cut down heartburn.

Answer:

Explanation:

Antacids are medication that neutralize stomach acid to cut down on heartburn, sour stomach, acid indigestion, and stomach upset. Some antacids also contain simethicone, an ingredient that helps your body get rid of gas. Others have ingredients that can lead to diarrhea or constipation.

The change in the momentum of the ball is 3.6 Kgm/s.

The term momentum has to do with the product in the velocity of a body and mass of the body. We have to recall at this point that rate of change of momentum is directly related  to the impressed force and this is in accordance with the Newton second law of motion.

Now we have to look at the few pieces of information that we can be able to glean from  the question;

Mass of the object = 0.300 kg

Initial speed of the object = 40.0 m/s

Final speed of the object = 52.0 m/s

Given that the change in the velocity of the object is given by;

m( v - u)

m = Mass of the object

v = Final speed of the object

u = Initial speed of the object

change in the velocity of the object = 0.300(52 - 40)

= 3.6 Kgm/s

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Answer:

1. c

2. e

3. d

Explanation:

1.

From Einstein's Photoelectric Equation, we know that:

Energy given up by photon = Work Function + K.E of Electron

hc/λ = φ + K.E

where,

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of light source = 200 nm = 2 x 10⁻⁷ m

φ = (5.1 eV)(1.6 x 10⁻¹⁹ J/eV) = 8.16 x 10⁻¹⁹ J

Therefore,

(6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2 x 10⁻⁷ m) - 8.16 x 10⁻¹⁹ = K.E

K.E = (9.939 - 8.16) x 10⁻¹⁹ J

K.E = 1.778 x 10⁻¹⁹ J

The positive answer shows that electrons will be emitted. Since it is clear from the equation the the K.E of electron decreases with the increase in work function. Therefore:

c. less energetic photo-electrons (on average)

2.

The increase in light sources means an increase in the intensity of light. The no. of photons are increased, due to increase of intensity. Thus, more photons hit the metal and they eject greater no. of electrons. Therefore,

e. more photo-electrons ejected

3.

X-rays have smaller wavelength and greater energy than ultraviolet rays. Thus, the photons with greater energy will strike the metal and as a result, electrons with higher energy will be ejected.

d. more energetic photo-electrons (on average)

The kinetic energy is given by:

We know the mass and the maximum speed, plugging their values in the expression above we have:

Therefore, the answer is d.

Answer:

t = 1.02 s

Explanation:

The computation of the time required is shown below:

The package speed for belt is

= 3 -  1

= 2 m/s

Moreover, the decelerative force would be acted on the block i.e u.m.g

So, the decelerative produced

= 0.2 × 9.81

= 1.962 m/s^2

And, final velocity = 0

v = u - at

here

V = 0 = final velocity

 u = 2 m/s

so,

0 = 2 - 1.962 × t

t = 1.02 s

The area of contact between the block and the surface is 50 m².

A body's mass is an inherent quality. Before the discovery of the atom and particle, it was widely considered to be tied to the amount of matter in a physical body.

The measure of matter in a particles or object is represented by the dimensionless quantity mass (symbolised m). The kilogramme is the International System's (SI) preferred unit of mass (kg).

Pressure is defined as force applied on a body per unit area. Pressure is the force perpendicularly applied to an object's surface per unit area over which that force is distributed. Gauge pressure is the pressure in relation to the outside pressure. There are many different units used to express pressure.

Given,

mass(m) = 50kg

pressure (p) = 10N/m²

Taking,

g= 10 m/s²

p= mg/A⇒ 10= 50 × 10/A∴

A= 500/10 = 50 m²

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Answer:

I don't understand the question that up added

Explanation:

what do you mean by ti and tk

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

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ANSWER:

333.4°

STEP-BY-STEP EXPLANATION:

To find angle for a vector:

We substitute the values of this case and the angle would then be:

The angle is 333.4°

Answer:

22/25 m/s^

Explanation:

The magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

In this system, the force of gravity acts on both boxes, but the tension in the rope is the same on both sides of the pulley, so it cancels out. The frictional force acts only on the 20 kg box, opposing its motion to the right.

To find the acceleration of the 20 kg box, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

Net force = mass x acceleration

The net force on the 20 kg box is the force of gravity pulling it down minus the force of friction opposing its motion to the right:

net force = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) = 156.8 N

The net force on the 5 kg box is the force of gravity pulling it down plus the tension in the rope pulling it up:

Net force = (5 kg)(9.8 m/s²) + T

Since the tension is the same on both sides of the pulley, we can set these two equations equal to each other and solve for the tension:

T = (20 kg)(9.8 m/s²) - (0.14)(20 kg)(9.8 m/s²) - (5 kg)(9.8 m/s²) = 93.68 N

Now we can use the net force on the 20 kg box to find its acceleration:

Net force = (20 kg) x acceleration

156.8 N = (20 kg) x acceleration

Acceleration = 7.84 m/s²

Therefore, the magnitude of the acceleration of the 20 kg box as it moves to the right is 7.84 m/s².

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Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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Vessel Mass Acting Downward (mg)

Bayonet Force Acting Above Vessel (Fb)

This force is called buoyancy. Buoyancy pushes objects up. Gravity exerts a downward force on an object determined by the object's mass. Therefore, if the downward force exerted by gravity on an object is less than the buoyant force the object floats.

Since the buoyant force on the body and the weight of the body are equal and opposite, the net force on the body is zero, giving the body a net force to levitate. The wind force acting on a sail moving a boat is an example of Newton's third law of motion. That is, every action has an equal and opposite reaction. But the relationship between force and motion is not as simple as the wind blowing just behind the sails propels the ship forward.

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Mark's work decreases when he climbs the same flight of stairs again in the same amount of time without the cello.

The correct answer is option D.

The amount of work Mark does depends on the weight of the cello, as well as the distance he climbs and the time it takes. Work is calculated using the formula :

Work = Force × Distance.
In the given scenario, Mark is carrying a full-sized cello while climbing the stairs. The weight of the cello adds to the force he exerts. So, the total force Mark exerts is the weight of the cello plus his own weight (375 N).

When Mark climbs the stairs with the cello, he is doing work against the force of gravity.

The work done is equal to the force exerted multiplied by the distance climbed (375 N + weight of cello) × 4 m.

Now, if Mark were to climb the same flight of stairs again in the same amount of time (3 seconds), but this time without the cello, the amount of work he does would decrease. This is because without the cello, the force exerted would only be Mark's weight (375 N), which is less than the total force exerted with the cello.

Therefore, mark's work decreases.

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Answer:

the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

Explanation:

A)

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

\(\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}\)

However; the net electric field i.e the sum of the electric filed produced is represented as:

\(\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}\)

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

\(\mathbf{F = q* E'}\)

\(\mathbf{F = \frac{q*v}{2d}}\) -----    equation (1)

Also ; we know that

\(\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}\)

\(\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}\)

\(\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}\)    -----   equation (2)

Replacing equation 3 into equation (2); we have:

\(\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}\)

\(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

Therefore,  the tension in the cable is \(\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}\)

B)

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

\(\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }\)

The net workdone to raise the plate from separation d to 2d is:

\(\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}\)

\(\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}\)

\(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

the work done by the cable is \(\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}\)

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

\(\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }\)

D) The energy stored in the plate after the  the top plate was raised is as follows:  

\(\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }\)

E) Yes,  work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

\(\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

\(\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}\)

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.

Given :

Object A is 71 degrees and object B is 75 degrees .

To Find :

How will thermal energy flow.

Solution :

We know, by law of thermodynamics thermal energy will flow from higher temperature to lower temperature.

So, in the given question energy will flow from object B from object A.

Hence, this is the required solution.

There are 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

The density of a binary alloy can be calculated using the following equation:

ρ = w1ρ1 + w2ρ2

where,

ρ = density of the alloy

w1 and w2 = weight fractions of the two components (in this case, gold and silver)

ρ1 and ρ2 = densities of the pure components.

We are given that the alloy contains 10% gold and 90% silver by weight, so we can calculate the weight fractions as:

\(w_{Au}\) = 0.10

\(w_{Ag}\) = 0.90

We are also given the densities of pure gold and silver as:

ρ_Au = 19.32 g/\(cm^{3}\)

ρ_Ag = 10.49 g/\(cm^{3}\)

Now we can substitute these values into the density equation to find the density of the alloy:

ρ = \(w_{Au}\)ρ_Au +\(w_{Ag}\)ρ_Ag

ρ = (0.10)(19.32 g/\(cm^{3}\)) + (0.90)(10.49 g/\(cm^{3}\))

ρ = 11.08 g/\(cm^{3}\)

Next, we need to calculate the number of gold atoms per cubic centimeter in the alloy.

To do this, we can use Avogadro's number and the atomic weights of gold and silver:

\(N_A\) = 6.022 × \(10^{23}\) atoms/mol

Aum = 196.97 g/mol

Agm = 107.87 g/mol

The number of gold atoms:

\(n_{Au}\) = (\(w_{Au}\)ρ/ Aum) × \(N_{A}\)

Substituting the values, we get:

\(n_{Au}\) = (0.10 × 11.08 g/\(cm^{3}\)/ 196.97 g/mol) × 6.022 × \(10^{23}\) atoms/mol

\(n_{Au}\) ≈ 3.37 × \(10^{22}\) atoms/\(cm^{3}\)

Therefore, there are approximately 3.37 × \(10^{22}\) gold atoms per cubic centimeter in the silver-gold alloy.

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Answer:

0.10s

Explanation:

the fall time is

4.9/100=.5*9.81*t^2

solve for t

The weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

To calculate the weight of a male African elephant on the moon, we need to use the formula:

Weight = mass × acceleration due to gravity

The mass of the elephant is given as 7,000 kg. However, the acceleration due to gravity on the moon is approximately 1/6th (0.1667) of the acceleration due to gravity on Earth, which is approximately 9.8 m/s².

Weight on the Moon = 7,000 kg × 0.1667 × 9.8 m/s²

Weight on the Moon = 7,000 kg × 1.6386 m/s²

Weight on the Moon ≈ 11,470.2 Newtons

Therefore, the weight of a male African elephant on the moon would be approximately 11,470.2 Newtons.

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Answer:

3/4

Explanation:

Answer:

1.Owen

2.By dropping the balls from the same height

3.She dropped the balls from different heights

4. Perform a second trial

Answer:

An atom is a particle of matter that uniquely defines a chemical element. An atom consists of a central nucleus that is surrounded by one or more negatively charged electrons. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

Explanation:

Simply said, an atom's entire mass is its atomic mass, which is commonly given in atomic mass units, or amu.

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Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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Answer:

oof ok

Explanation:

Thank you :)

Answer:

Which individual or group had perhaps the most profound effect on establishing social work as a specialized practice

Explanation: