Avaluate 2^3x-1 for x=1

Answers

Answer 1

Answer:

4 or 7 (Check the explanation to see which one your equation actually is.

Step-by-step explanation:

One thing I want to clarify for you, It's Evaluate, not Avaluate.

Okay so, we want to find the value of 2^3x-1 and we know x = 1.

You didn't really clarify if the expression was \(2^{3x-1}\) or \(2^{3x}-1\), so I'll be doing both:

For \(2^{3x-1}\), we should plug in x to get \(2^{3(1)-1}\) and then simplify to get \(2^{2}\).

2 to the power of 2 or \(2^{2}\) is equal to 2 * 2 or 4.

The second one, \(2^{3x}-1\), we should plug in x to get \(2^{3(1)}-1\) and then to become \(2^{3}-1\). 2 to the power of 3 or \(2^{3}\) is 8 and then minus 1 is 7.

Answer 2
The answer to 2^3-1= 7

Related Questions

A new car is bought for $100,000. If the annual depreciation is 10%, find the value of the car after 3 years.

Remaining Amount = 100,000(1 -0.1)3

Answers

The value of the car after 3 years is $79, 000

How to determine the value

To determine the value, we have to use the formula;

Value = Initial value × (1 - Depreciation rate)ⁿ

Substitute the values given, we get;

Remaining value after 3 years = $100,000 × (1 - 0.10)³

Expand the bracket, we get;

Value after 3 years = $100,000 × (0.90)³

Find the cube value and substitute, we have;

Value after 3 years = $100,000 × 0.729

Multiply the values, we have;

Value after 3 years = $72,900

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-2\tfrac{1}{2}-\Big(-4\tfrac{3}{5}\Big)
−2 /2/1 −(−4 3/5)


Answers

The value of the fraction expression -2 1/2 - (-4 3/5) is 2 1/10

How to evaluate the expression

From the question, we have the following parameters that can be used in our computation:

−2 /2/1 −(−4 3/5)

Express properly

So, we have the following representation

-2 1/2 - (-4 3/5)

Remove the brackets

This gives

-2 1/2 - (-4 3/5) = -2 1/2 + 4 3/5

Express the denominator as 10

So, we have

-2 1/2 - (-4 3/5) = -2 5/10 + 4 6/10

Evaluate the difference

-2 1/2 - (-4 3/5) = 2 1/10

Hence, the solution is 2 1/10

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PLEASE!!!!!!!!!!!! Which of the following statements best describes the difference between net income and gross profit? a. Gross profit considers operating expenses while net income does not. b. Net income considers operating expenses while gross profit does not. c. Gross profit deducts taxes while net income does not. d. Net income deducts taxes while gross profit does not.

Answers

Answer:

B ON E2020

Step-by-step explanation:

b.

Net income considers operating expenses while gross profit does not

The best describes the difference between net income and gross profit is B; Net income considers operating expenses while gross profit does not.

What is gross profit?

Gross profit is the profit a firm makes after deducting the costs of manufacturing and selling its products or providing its services from the revenue the company made.

The equation that correctly describes the gross profit will be;

gross profit = (net sales) - (cost of goods sold)

Therefore, the correct option is B

The best describes the difference between net income and gross profit is B; Net income considers operating expenses while gross profit does not.

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graph each equation by using a table -3=5x-y

Answers

The graph of the equation is shown below

Graph of linear equations

From the question, we are to graph the given equation

The given equation is

-3 = 5x - y

To graph the equation,

First we will determine the x-intercept and y-intercept

x-intercept

Put y = 0 in the equation

-3 = 5x - 0

-3 = 5x

x = -3/5

y-intercept

Put x = 0 in the equation

-3 = 5(0) - y

-3 = 0 - y

-3 = -y

y = 3

Using the x-intercepts and y-intercepts, we can plot the graph of the equation.

The graph of the equation is shown below

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graph each equation by using a table -3=5x-y

How many cubic feet of warehouse space are needed for 350 boxes 11in. by 8in. by 12in?

Answers

Answer:

214 cubic feet (rounded to the nearest cubic foot)

Step-by-step explanation:

Step 1  Determine the volume of 1 box

Volume of a box or rectangular prism = dimensions multiplied by each other

Here, the given dimensions are 11 in by 8 in by 12 in

So the volume of one box would be 11 x 8 x 12 = 1056 cubic inches

Step 2 Determine volume of all 350 boxes

Volume of 1 box = 1056

So volume of all 350 boxes = 1056 x 350 = 369600 cubic in

Step 3 Convert cubic in to cubic ft

To convert to cubic feet we divide the amount of cubic inches by 1728 (this is because there are 1728 cubic inches in 1 cubic foot)

369600 / 1728 = 214 cubic feet (to the nearest cubic foot)

214 cubic feet of warehouse space is required for 350 boxes with the dimensions of 11in by 8in by 12in

Simplify 2/4 please and thank you

Answers

Answer:

1/2

Step-by-step explanation:

2/4 is equal to 1/2, because if you divide 4 by 2 you get 2, and if you divide 2 by 2 you get one.

Basically, the simplification process would look something like this...

2/4 ÷ 2/2 = 1/2

Can someone help me with this question?​

Can someone help me with this question?

Answers

Answer:

1. Y

2. YX , YZ

3. X

4. XZ

State where in the ty-plane the hypotheses of the Existence and Uniqueness Theorem are satisfied for the equation y'=(ycot(2t))/(t^2+y^2+1)

Answers

We can conclude that the hypotheses of the Existence and Uniqueness Theorem are satisfied in any rectangular region in the ty-plane that does not contain the curve t² + y² = -1.

Where in the ty-plane the hypotheses of the existence and uniqueness theorem are satisfied

The Existence and Uniqueness Theorem for first-order ordinary differential equations states that if a differential equation of the form y' = f(t, y) satisfies the following conditions in some rectangular region in the ty-plane:

1. f(t, y) is continuous in the region.

2. f(t, y) satisfies a Lipschitz condition in y in the region, i.e., there exists a constant L > 0 such that |f(t, y₁) - f(t, y₂)| ≤ L|y₁ - y₂| for all t and y₁, y₂ in the region.

then there exists a unique solution to the differential equation that passes through any point in the region.

In the case of the differential equation y' = (y cot(2t)) / (t² + y² + 1), we have:

f(t, y) = (y cot(2t)) / (t² + y² + 1)

This function is continuous everywhere except at the points where t² + y² + 1 = 0, which is the curve t² + y² = -1 in the ty-plane. Since this curve is not included in any rectangular region, we can say that f(t, y) is continuous in any rectangular region in the ty-plane.

To check if f(t, y) satisfies a Lipschitz condition in y, we can take the partial derivative of f with respect to y and check if it is bounded in any rectangular region. We have:

∂f/∂y = cot(2t) / (t² + y² + 1) - (2y² cot(2t)) / (t² + y² + 1)²

Taking the absolute value and simplifying, we get:

|∂f/∂y| = |cot(2t) / (t² + y² + 1) - (2y² cot(2t)) / (t² + y² + 1)²|

= |cot(2t) / (t² + y² + 1)| * |1 - (2y² / (t² + y² + 1)))|

Since 0 ≤ (2y² / (t² + y² + 1)) ≤ 1 for all t and y, we have:

1/2 ≤ |1 - (2y² / (t² + y² + 1)))| ≤ 1

Also, cot(2t) is bounded in any rectangular region that does not contain the points where cot(2t) is undefined (i.e., where t = (k + 1/2)π for some integer k). Therefore, we can find a constant L > 0 such that |∂f/∂y| ≤ L for all t and y in any rectangular region that does not contain the curve t² + y² = -1.

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I need help on this question

I need help on this question

Answers

Answer:

a = 62.5

b = 40

c =62.5

d = 70

solve for y:
x^3 + (1/a)y= xy+9

Answers

Step-by-step explanation:

\( {x}^{3} + ( \frac{1}{a} )y = xy + 9\)

\(x {}^{3} + \frac{y}{ay} = xy + 9\)

\(x {}^{3 } = xy + 9 - \frac{y}{ay} \)

\( {x}^{3} - 9 = xy - \frac{y}{ay} \)

\( {x}^{3} - 9 = y(x - \frac{1}{a} )\)

Divide both sides by x-1/a

\( \frac{x {}^{3} - 9}{x - \frac{1}{a} } = y\)

whats 5x5? Maybe will mark brainiest

Answers

Answer:

25

Step-by-step explanation:

5x5 = 25

Answer:

25

Step-by-step explanation:

Let's go through our times tables really quick!

5x1 = 5 (5 + 0)

5x2 = 10 (5 + 5)

5x3 = 15 (5 + 5 + 5 [10 + 5])

5x4 = 20 (5 + 5 + 5 + 5 [15 (5x3) + 5)

As we can see, if we know 5x4, we can easily find 5x5! It's just 5x4 + 5

So, 5x5 is 25

Hope this helped!

Joan’s Nursery specializes in custom-designed landscaping for residential areas. The estimated labour cost associated with a particular landscaping proposal is based on the number of planting of trees, shrubs, and so on to be used for the project. For cost-estimating purposes, managers use two hours of labour time for the planting of a medium-sized tree. Actual times from a sample of 10 planting during the past month follow (times in hours).
1.7 1.5 2.6 2.2 2.4 2.3 2.6 3.0 1.4 2.3
Test to see whether the mean tree-planting time differs from two hours.
State the null and alternative hypothesis

Answers

Answer:

H0 : μ = 2

H1 : μ > 2

We fail to reject the null and conclude that no significant evidence exists to support that mean tree-planting time differs from two hours.

Step-by-step explanation:

Given :

X = 23.71,17.79,29.87,18.78,28.76

Sample mean, xbar = Σx / n = 22/10 = 2.2

Standard deviation, s = 0.516 (calculator)

H0 : μ = 2

H1 : μ > 2

Test statistic :

(xbar - μ) ÷ (s/sqrt(n))

n = 10

Test statistic :

(2.2 - 2) ÷ (0.516/sqrt(10))

0.2 / 0.1631735

Test statistic = 1.23

Using the Pvalue from Tscore calculator, df = n - 1 = 10 - 1 = 9

Pvalue(1.23, 9) = 0.1249

Since, Pvalue > α ; We fail to reject the null and conclude that no significant evidence exists to support that mean tree-planting time differs from two hours.

what is (1/2 + isqrt3/2)^5?

Answers

Answer:

\((\frac{1}{2}+\frac{\sqrt{3}}{2}i)^5=\frac{1}{2}-\frac{\sqrt{3}}{2}i\)

Step-by-step explanation:

Convert 1/2 + i√3/2 to rectangular form

\(\displaystyle z=a+bi=\frac{1}{2}+\frac{\sqrt{3}}{2}i\\\\r=\sqrt{a^2+b^2}=\sqrt{\biggr(\frac{1}{2}\biggr)^2+\biggr(\frac{\sqrt{3}}{2}\biggr)^2}=\sqrt{\frac{1}{4}+\frac{3}{4}}=\sqrt{1}=1\\\\\theta=\tan^{-1}\biggr(\frac{b}{a}\biggr)=\tan^{-1}\biggr(\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}\biggr)=\tan^{-1}(\sqrt{3})=\frac{\pi}{3}\\\\z=\cos\frac{\pi}{3}+i\sin\frac{\pi}{3}\)

Use DeMoivre's Theorem

\(\displaystyle z^n=r^n(\cos(n\theta)+i\sin(n\theta))\\\\z^5=1^5\biggr(\cos\biggr(\frac{5\pi}{3}\biggr)+i\sin\biggr(\frac{5\pi}{3}\biggr)\biggr)\\\\z^5=\frac{1}{2}-\frac{\sqrt{3}}{2}i\)

Right triangle ABC was dilated with a scale factor of 2. How many times larger is the area of triangle DEF than triangle ABC?

Answers

The area of triangle DEF is four times larger than the area of triangle ABC.

We have,

Right triangle ABC was dilated with a scale factor of 2.

When a triangle is dilated with a scale factor of 2, the resulting triangle is enlarged by a factor of 2 in each dimension.

Since area is a two-dimensional measure, it will be enlarged by a factor of the square of the scale factor.

In this case, the scale factor is 2, so the area of triangle DEF will be

=  2²

= 4 times larger than the area of triangle ABC.

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who likes anime??
if you do then what kinds?

Answers

Answer:

de girly typede high sch onesetc.

Answer: meee

Step-by-step explanation: Hunterx.Hunter, Jujutsu Kai.sen, T.okyo Reveng.ers, De.ath Note, Noble.sse, and some more others l.ol

Triangle ABC is graphed below. Translate the figure left 2 units and down 3 units.

Triangle ABC is graphed below. Translate the figure left 2 units and down 3 units.

Answers

Answer:

I think it's maybe  -4

Step-by-step explanation:

MY BROTHER NEEDS HELP FAST OR HE'S GONNA FAIL!!

what is 4,007 + 981 = ???
Show your work

Answers

Answer: The correct answer is 4988.

Step-by-step explanation: 4007+981 = 4988 Add the one to the eight then add the 8 to the tens place and add the 9 to the hundreds place.

THIS IS THE CORRECT ANSWER.

The Venn diagram shows the number of customers who have purchased different types of pets from a pet store, where C represents customers who have purchased cats, D represents customers who have purchased dogs, and F represents customers who have purchased fish.

Circles C, D, and F overlap. Circle C contains 15, circle D contains 21, and circle F contains 12. The overlap of C and F contains 2, the overlap of F and D contains 0, and the overlap of D and C contains 3. The overlap of all 3 circles contains 1. Number 14 is outside of the circles.

How many people are in the set C ∩ D?

4
6
36
38

Answers

The number of people in the set C ∩ D (customers who purchased both cats and dogs) is obtained by adding the overlap of D and C (3) with the overlap of all 3 circles (1), resulting in a total of 4 individuals.

The correct answer is 4.

To determine the number of people in the set C ∩ D (customers who have purchased both cats and dogs), we need to analyze the overlapping regions in the Venn diagram.

Given information:

- Circle C (cats): 15

- Circle D (dogs): 21

- Circle F (fish): 12

- Overlap of C and F: 2

- Overlap of F and D: 0

- Overlap of D and C: 3

- Overlap of all 3 circles: 1

- Number outside of circles: 14

To determine the number of people in the set C ∩ D (customers who have purchased both cats and dogs), we need to consider the overlapping region between circles C and D.

From the information given, we know that the overlap of D and C is 3. Additionally, we have the overlap of all 3 circles, which is 1. The overlap of all 3 circles includes the region where customers have purchased cats, dogs, and fish.

To calculate the number of people in the set C ∩ D, we add the overlap of D and C (3) to the overlap of all 3 circles (1). This gives us 3 + 1 = 4.

Therefore, from the options given correct one is 4.

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Answer: 4

Step-by-step explanation:

trust me bro

4/5 ÷ 7/30 please hellllpppp

Answers

Answer:

\(\frac{24}{7}\) or \(3\frac{3}{7}\)

Step-by-step explanation:

\(\frac{4}{5}\div \frac{7}{30}\)

Step 1: Apply the fraction rule: \(\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}\)

\(=\frac{4}{5}\times \frac{30}{7}\)

Step 2: Cross-cancel common factor: 5

\(=\frac{4}{1}\times \frac{6}{7}\)

Step 3: Multiply fractions: \(\frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}\)

\(=\frac{4\times \:6}{1\times \:7}\)

Step 4: Multiply the numbers: \(4\times \:6=24\)

\(=\frac{24}{1\times \:7}\)

Step 5: Multiply the numbers: \(1\times \:7=7\)

\(=\frac{24}{7}\)

Therefore, the answer is \(\frac{24}{7}\) or in the simplified form; \(3\frac{3}{7}\)

Sebutkeun 3 manfaat ngabiasakaeun tuhu kana aturan!​

Answers

Mannnn idek what u saying lol

In ΔABC, m∠A = 2m∠B and m∠B = 3m∠C.
What is m∠C?

In ABC, mA = 2mB and mB = 3mC.What is mC?

Answers

A triangle is a three-edged polygon with three vertices. The measure of ∠C is 18°.

What is a triangle?

A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.

Let the measure of ∠C be represented by x. Given the measure of ∠A= 2(∠B), while the measure of ∠B=3(∠C). Therefore, the measure of angles can be written as,

∠A = 2(∠B) = 2[3(∠C)] = 6x

∠B = 3x

∠C = x

Now, since the sum of all the angles of a triangle is 180°. Therefore,

∠A + ∠B + ∠C = 180°

6x + 3x + x = 180°

10x = 180°

x = 18°

Hence, the measure of ∠C is 18°.

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given that y various with x, find the equation of direct variation when x=11 and y=14

Answers

Answer:

The equation of direct variation relates two variables that vary proportionally to each other, and can be written as y = kx, where k is the constant of proportionality. To find k, we can plug in the values of x and y given in the problem and solve for k:

y = kx

14 = k(11)

k = 14/11

Now that we know k, we can write the equation of direct variation as:

y = (14/11)x

Therefore, when x = 11 and y = 14, the equation of direct variation is y = (14/11)(11) = 14.

Given f of x is equal to the quantity x plus 3 end quantity over the quantity x squared plus 2 times x minus 3 end quantity and g(x) = x + 2, evaluate (g – f )(2).

Given f of x is equal to the quantity x plus 3 end quantity over the quantity x squared plus 2 times

Answers

The composite function (g - f)(2) when evaluated is 3

Evaluating the composite functions

From the question, we have the following parameters that can be used in our computation:

f(x) = (x + 3)/(x² + 2x - 3)

Also, we have

g(x) = x + 2

The composite function (g - f)(2) is calculated as

(g - f)(2) = g(2) - f(2)

Where, we  have

g(2) = 2 + 2 = 4

Also, we have

f(2) = (2 + 3)/(2² + 2(2) - 3) = 1

So, we have

(g - f)(2) = 4 - 1

Evaluate

(g - f)(2) = 3

hence, the composite function (g - f)(2) when evaluated is 3

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Micah is writing a function that models the height a dolphin reaches when it propels itself from underwater to the surface, leaps through the air, and reenters the water. The model is represented by the equation h=-16t+96t-128, where h is the height in feet above the surface of the water and t is the time in seconds. According to Micha's model, how long will the dolphin be above the surface of the water?

Answers

Answer:

The dolphin will be above the surface of the water for 2 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

\(ax^{2} + bx + c, a\neq0\).

This polynomial has roots \(x_{1}, x_{2}\) such that \(ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})\), given by the following formulas:

\(x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}\)

\(x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}\)

\(\Delta = b^{2} - 4ac\)

The height of the dolphin after t seconds is given by:

\(h(t) = -16t^2 + 96t - 128\)

According to Micha's model, how long will the dolphin be above the surface of the water?

It stays above the surface of the water between the first and the second root. Initially, it is below water, when the first time for which \(h(t) = 0\) it crosses the surface upwards, and then the second time for which \(h(t) = 0\) it crosses the surface downwards.

We have to find these roots. So

\(h(t) = -16t^2 + 96t - 128\)

\(-16t^2 + 96t - 128 = 0\)

Multiplying by -16

\(t^2 - 6t + 8 = 0\)

\(\Delta = (-6)^{2} - 4*1*8 = 36 - 32 = 4\)

\(t_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4\)

\(t_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2\)

4 - 2 = 2

The dolphin will be above the surface of the water for 2 seconds.

I’ll give Brinley stars if I get help

A flying squirrel lives in a nest that is 12 feet up in a tree, but wants to
eat an acorn that is on the ground 9 feet away from the base of his tree.
If the flying squirrel glides from his nest to the acorn, then scurries back
to the base of the tree, and then climbs back up the tree to his nest,
how far will the flying squirrel travel in total?

Answers

It’s the Pythagorean theorem which is a squared+b squared =c squared it works with right triangles to find missing sides. You have a=12 and b=9, so 12^2 is 144 and 9^2 is 81. 81+144=225. The square root of 225 is 15 and that’s your answer

PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST!!!

PLS HELP I DONT UNDERSTAND :( WILL GIVE BRAINLIEST!!!

Answers

Answer:

1. The Mapping diagram does NOT represent a function. Since a function can give only one output for any input but we can see that we have 2 possible outputs for 7

2. There is one number

3. Set A: The Input

4. are multiple mappings

5. Set B: The Output

What is the image point of (2,8) after the transformation rx-axis D₂?

Answers

After transformation, the point (-1,2) in the image would be (-1,-2)

What is composition of transformations?

Each transformation applied to the prior image is combined into a composition of transformations. The result of a translation is identical to a composition of reflections across parallel lines (twice the distance between the parallel lines). The composite transformation is carried out by multiplying the matrix in order from the right to the left side if it is represented as a column. The output from the preceding matrix is multiplied by the new matrix that will follow.

First, we must mirror the point (-1, 2) around the line y=-x.

(X, Y) is the rule (-y,-x)

you obtain (-1,2)—>(-2,1) (-2,1)

At this point, you must rotate (-2,1) by 90 degrees.

(X, Y) is the rule ( -y,x)

so (-2,1)—> (-1,-2) (-1,-2)

After transformation, the point (-1,2) in the image would be (-1,-2)

The complete question is,

What is the image point of (-1,2) after the transformation R 90° ry=-x

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PLEASE ANDWER
y = 10 x + 2
What is x?
Is this proportional?

Answers

Answer:

x the (x) value of the ordered pair, it is proportional.

Step-by-step explanation:

A sample of students is taken from the school’s A honor roll. The school estimates that there are actually 360 students on the A honor roll. Using this sample, how many students on the A honor roll are 8th graders?

6thgraders=15
7thgraders=11
8thgraders=14

Answers

Answer:

Number of 8th Graders = 360 - X  

As you can see this question is not complete and lacks the essential data. But we will try to create a mathematical expression to calculate the number of students on the A honor roll which are from 8th grade.

As we know:

Total number of students on the A honor roll = 360

We are asked to calculate, number of students from 8th grade on the A honor  roll.

So, let's assume that "X" represents all the students who are on the A honor roll except 8th grade.

Mathematical Expression:

Number of 8th Graders = Total number of students on the A honor roll - X

Number of 8th Graders = 360 - X

So, if you know the value of X, you can easily calculate the number of students which are from 8th grade on the A honor roll.

I am not sure if it is wrong I am sorrry.

Write the equation of the line that has slope 3 and passes through the point
(-2,5).

Answers

from
y=mx +c
where m is the slope, c is a constant, and x and y are variables,
we know the slope is 3 so m=3
rewriting it
y=3x +c
to find c we substitute values x=-2 and y=3 into the equation y=3x +c
so
3= 3(-2) + c
c=9
thus, y=3x+ 9
Answer: y = 3x + 11

Explanation:
y = kx+m is the equation of a line. The coefficient of x is the slope i.e 3. So we know that a part of the equation is y = 3x + m.

How to find M?
Well, we already have a point on the equation. Meaning we already have an x and a y. -2 = x and 5 = y.

The equation then becomes 5 = (3 x -2) + m.

Solve for m and the answer will be m = 11.

Now we have both m and K meaning that the whole equation is solved and it’s y = 3x + 11
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