At+what+speed,+as+a+fraction+of+ccc,+will+a+moving+rod+have+a+length+55+%%+that+of+an+identical+rod+at+rest?

People may experience:

Headache: can be acute or persistent

Whole body: blackout, fatigue, or poor balance

Cognitive: amnesia, disorientation, or mental confusion

Sleep: sleep disturbances or sleepiness

Gastrointestinal: nausea or vomiting

Also common: irritability, mild depression, ringing in the ears, or sensitivity to light

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Answer:

headache, dizziness, disorientation, and nausea.

Explanation:

A concussion is any sudden impact to the head or acceleration or deceleration without impact. A concussion disrupts normal brain activity and can be dangerous. The symptoms include headache, dizziness, disorientation, and nausea.

At an atomic level, electrostatics is responsible for most of the physical phenomena that we encounter in our everyday life. Every object we see around us, such as chairs, buildings, and people, are made up of atoms, and every atom has electrons that are negatively charged, protons that are positively charged, and neutrons that have no charge.

Electrostatics is the study of electric charges at rest and of the forces and fields associated with these charges. Electrons are held in atoms by the attraction of the positive nucleus for the negative charge of the electrons. This attraction is known as electrostatic force. The protons in the nucleus are also held together by electrostatic forces, which are much stronger than those that bind electrons to the nucleus.
The forces between charged objects are governed by Coulomb's Law. This law states that the force between two charged objects is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges have the same sign, the force is repulsive; if they have opposite signs, the force is attractive.
Electrostatic forces play an important role in many physical phenomena, such as the attraction of dust particles to a TV screen, and the Van de Graaff generator, which uses electrostatic forces to build up very high voltages.

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Scientists create a uniform electric field

\(E⃗ = 1.5×10^6 k^V/m\)in a region of space where\(B⃗ =0⃗.\\\) To find the components of the electric and magnetic fields in the reference frame of a rocket traveling in the positive x-direction at\(1.3×10^6 m/s\), we'll use the Lorentz transformation for electric and magnetic fields.

First, we need to determine the Lorentz factor (γ) for the rocket's speed:
\(γ = 1 / √(1 - v²/c²)\)
where\(v = 1.3×10^6 m/s and c = 3×10^8 m/s\)(speed of light).

\(γ ≈ 1 (since v²/c²\) is very small)

Now, we can use the Lorentz transformation to find the electric and magnetic field components in the rocket's reference frame.

\(E'x = Ex = 0 V/m\) (unchanged)
\(E'y = γ(Ey - vBz) = γ(Ey) = 1.5×10^6 V/m (since Bz = 0)\)
\(E'z = γ(Ez + vBy) = γ(Ez) = 0 V/m (since By = 0)\)

\(B'x = Bx = 0 T\)(unchanged)
\(B'y = γ(By + vEz/c²) = 0 T (since Ez = 0)\)
\(B'z = γ(Bz - vEy/c²) ≈ -vEy/c² = -1.3×10^6 × 1.5×10^6 / 3×10^8 ≈ -6.5×10^-3 T\\\)

The components of the electric field in the rocket's reference frame are: \(0 V/m, 1.5×10^6 V/m, 0 V/m\)
The components of the magnetic field in the rocket's reference frame are: \(0 T, 0 T, -6.5×10^-3 T\)

In two significant figures, your answer is:
Electric field components: \(0, 1.5×10^6, 0 V/m\)
Magnetic field components: \(0, 0, -6.5×10^-3 T\)

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Answer:

the correct answer is C,      E’= 4E

Explanation:

In this exercise you are asked to calculate the electric field at a given point

         E = \(k \frac{q}{r^2}\)

indicates that the field is E for r = 2m

         E = \(\frac{ k q}{4}\)                  (1)

the field is requested for a distance r = 1 m

         E ’= k \frac{q}{r'^2}

         E ’= k q / 1

from equation 1

         4E = k q

we substitute

        E’= 4E

so the correct answer is C

Answer:

Light travels at 3.0 x 108 m/s in a vacuum.

Explanation:

Light travels at 3.0 x 108 m/s in a vacuum.

The highest surface air pressure ever recorded occurred when the air was exceptionally dense and heavy. This typically happens when cold air sinks and accumulates near the surface, creating a high-pressure system.

One notable example of such a system was the Siberian High, which occurred in December 1968. The air pressure recorded in Siberia reached an astonishing 1085.7 millibars, the highest ever recorded on Earth's surface. This extreme pressure was caused by the combination of intense cold and a massive high-pressure system that covered a vast area.

High-pressure systems can have significant impacts on weather patterns, often leading to clear skies and dry weather. However, they can also bring cold temperatures and increased air pollution due to trapped emissions. Overall, understanding how pressure and air density interact is essential for predicting weather patterns and understanding the Earth's atmosphere.

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The average velocity of the car for the entire trip is 0.018 km/h.

The velocity of the trip is determined from the ratio of change of displacement to total time of motion.

The total displacement of the motion = ( 30 m North -  30 m South) + 40 m est = 40 m west = 0.04 km west

The total time of motion = 2.22 hours

The average velocity of the car for the entire trip is calculated as follows;

v = ( 0.04 km ) / ( 2.22 hrs )

v = 0.018 km/h

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Answer:

It is possible by increasing the speed of the tennis ball by a factor of (Mass of the tennis ball)/(Mass of the basketball)

Explanation:

The momentum of a body = The bod's mass × The body's velocity

Therefore, the momentum of a given mass of an object, such as a tennis ball can be increased by increasing the velocity or speed of the object. Whereby the speed of the ball, v₁, is increased such that the momentum of the basketball and the tennis ball will be the same, is given by the following equation

Mass of the basketball × v₂ = Mass of the tennis ball × v₁

Therefore, v₁/v₂ = (Mass of the tennis ball)/(Mass of the basketball)

The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

The terms specific to the observer are e, f, and g. The ecliptic is the path that the Sun appears to follow across the sky throughout the year as viewed from Earth.

The horizon is an imaginary line that marks the point where the sky and the Earth's surface seem to meet. The zenith is an imaginary point directly overhead from the observer's location.

The celestial equator is an imaginary line that runs around the celestial sphere, dividing it into two hemispheres. The north celestial pole is the point directly above the observer's north horizon. The nadir is an imaginary point directly below the observer's location.

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The deceleration of the car is -2 m/sec², indicating that it is slowing down at a rate of 2 meters per second squared.

To calculate the deceleration, you can use the formula

Acceleration (a) = (Final velocity (v) - Initial velocity (u)) / Time taken (t)

In this case, the initial velocity (u) is 30 m/sec, the final velocity (v) is 10 m/sec, and the time taken (t) is 10 sec.

Substituting these values into the formula, we get:

Acceleration (a) = (10 m/sec - 30 m/sec) / 10 sec

= (-20 m/sec) / 10 sec

= -2 m/sec²

The deceleration of the car is -2 m/sec², indicating that it is slowing down at a rate of 2 meters per second squared. The negative sign indicates that the car is decelerating in the opposite direction of its initial motion (southward).

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An atmosphere of helium would have a large effect on the pitch of instruments. For an organ pipe, helium would cause the pitch of the instrument's sound to be higher than normal.

This is because helium is a lighter gas than air, and therefore has a higher speed of sound through it. This increases the frequency of the sound waves, resulting in a higher pitch. For a tuning fork, helium would also cause the pitch of the sound to be higher than normal, however, the effect would be less significant.

This is because the frequency of the sound waves produced by a tuning fork is determined more by the size and shape of the fork, rather than the gas that it is in. Therefore, while the pitch of a tuning fork would be higher in a helium atmosphere, the effect would not be as great as with an organ pipe.

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Answer:

Speed = distance traveled / time

Speed is a "scalar" quantity

Velocity = Vector Distance Traveled / time

Velocity is a vector quantity.

Example:

One can travel one lap around a track at some particular speed and his average speed will be (lap distance / time)

However, his vector velocity would be zero because he ended up where he started with zero displacement.

The path of a charged particle moving parallel to a uniform magnetic field will be straight line

Force on a charged particle moving in a magnetic field can be calculated by = q.(v*B )

q = charge of the particle

v = velocity of the particle

B = magnetic field

theta = angle between v and B

q . (v B sin (theta) )

Since,  particle is parallel to the magnetic field

hence , theta = 0°

so sin(theta) = sin 0° = 0

hence , force = 0

since , there is no force acting on the particle it will remain in that motion in hat it was when it initially came in the magnetic field . Hence It will be moving along a straight line path because the magnetic force on the charged particle is zero.

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Answer:

Newton's Second Law tells us that the more mass an object has, the more force is needed to move it. A larger rocket will need stronger forces (eg. more fuel) to make it accelerate. The space shuttles required seven pounds of fuel for every pound of payload they carry.

Explanation:

The velocity of the canoe is  1.7 m/s.

Momentum in physics is the products of mass and velocity. Now we have to find momentum with the formula; p = mv

a) Initial momentum = (15)8 m/s + 135 = 255 Kgms-1

b) Since momentum is conserved, the total momentum after throwing the anchor is still 255 Kgms-1

c) The final velocity of the boat is obtained from;

255 Kgms-1 = (15Kg + 135 Kg) v

v = 255 Kgms-1/(15Kg + 135 Kg)

v = 1.7 m/s

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The speed of the 600 g glider just before impact is 1.98 m/s.

It is given that: Mass of the stationary air-track glider, m1 = 250 g = 0.25 kg, Length of the spring, l = 30 cm = 0.3 m, Spring constant, k = 25 N/m, Mass of the incoming glider, m2 = 600 g = 0.6 kg, The length of the compressed spring is 22 cm = 0.22 m.

To solve the problem, we can use the principle of conservation of momentum. The momentum of an object is the product of its mass and velocity.

momentum = mass x velocity

Before collision:

In the beginning, the stationary glider is at rest. Hence, its initial momentum is zero. However, the incoming glider has momentum of:

m2 × u (where u is the initial velocity of the incoming glider)

After collision:

The two gliders stick together and move with a common velocity, v. Using the principle of conservation of momentum, we can write:

m2 × u = (m1 + m2) × v

Substituting the given values:

0.6 kg × u = (0.25 kg + 0.6 kg) × v0.6

u = 0.85v

Dividing both sides by 0.85, we get:

v = 0.706 m/s

But we are required to find the speed of the incoming glider just before impact (i.e., u). To find u, we can use the principle of conservation of energy. Since the spring is compressed and not released, the total mechanical energy is conserved.

Initially, the glider had only potential energy stored in the compressed spring. The potential energy stored in the spring is given by the formula:

potential energy = 1/2 k x²

where x is the distance by which the spring is compressed before the collision.

Hence, initially the incoming glider had a potential energy of:

potential energy = 1/2 × 25 N/m × (0.3 m - 0.22 m)²= 0.5 × 25 N/m × (0.08 m)²= 0.04 J

This potential energy is converted into kinetic energy of the two gliders after collision. Hence, we can write:

1/2 (m1 + m2) v² = potential energy

Substituting the values:

1/2 (0.25 kg + 0.6 kg) v² = 0.04 JV² = 0.04 / 0.425V² = 0.0941

Taking square root of both sides:

v = 0.3066 m/s

The speed of the incoming glider just before impact is therefore:

u = 2.29 m/s - 0.3066 m/su = 1.98 m/s

Therefore, the speed of the 600 g glider just before impact is 1.98 m/s.

Note: The question is incomplete. The complete question probably is: One end of a massless, 30-cm -long spring with spring constant 25 n/m is attached to a 250 g stationary air-track glider; the other end is attached to the track. a 600 g glider hits and sticks to the 250 g glider, compressing the spring to a minimum length of 22 cm. What was the speed of the 600 g glider just before impact?

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Answer:

The particles have just enough energy to move past each other.

Answer:

A

Explanation:

Solid's particles cannot move past each other and are stuck in place. Liquid's particles are able to slightly move past each other. And gas's particles move freely.

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Answer:

Movement skills in square dancing transfer to ballroom dancing when they both require you to dance in a rhyme.

Explanation:

Answer:

imma have to say C I'm not sure tho

Answer:

34.51

Explanation:

k=1/2mv² is the kenetic energy equation to fill is in

k=[1/2(0.235)×50]²

Answer:

it increases drag

Explanation:

Answer:

The automobile tire rotates 91 revolutions

Explanation:

Given;

angular acceleration of the automobile, α = 2.13 rad/s²

time interval, t = 23.2-s

To calculate the number of revolutions, we apply the first kinematic equation;

\(\theta = \omega_i \ + \frac{1}{2} \alpha t^2\)

the initial angular velocity is zero,

\(\theta =0\ + \frac{1}{2} (2.13) (23.2)^2\\\\\theta = 573.2256 \ Rad\)

Find how many revolutions that are in 573.2256 Rad

\(N = \frac{\theta}{2 \pi} = \frac{573.2256}{2\pi} \\\\N = 91 \ revolutions\)

Therefore, the automobile tire rotates 91 revolutions

Answer:

Explanation:

Sprouted seeds - are the best for health.

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Answer:

If you're talking about the sun than:

Time, Distance and Shielding Time, distance, and shielding actions minimize your exposure to radiation in much the same way as they would to protect you against overexposure to the sun:

If you're talking about the ocean than:

Water safety precautions for teens and young adults:

Never go into the water if you can’t swim.

If you can’t swim, learn. Any age can receive swimming lessons.

Always wear a life jacket while boating or taking part in boating activities such as tubing or skiing.

Never swim alone or in an unsupervised area.

Know your swimming strength.

Don’t rough house around water. Never push, jump on or hang on to others in or around water.

Never drink alcohol while taking part in water or boating activities. Alcohol affects your motor skills therefore making it harder to swim, float, keep balance or drive.

Explanation:

Answer:

63016

Explanation:

Ri+R2+R3 this is called series circuit

Answer:

200

Explanation:

100+200=300

1/300+1/600=200