At what temperature will water change from a liquid to a solid (freeze)?

Answer:

Neon

Explanation:

\(\\ \sf\longmapsto [Ne]=1s^22s^22p^6\)

Answer:

Name: Neon

Formular: Ne

Explanation:

\(.\)

To classify these molecules based on whether the substituent group is ortho/para directing or meta directing for electrophilic aromatic substitution, you need to first identify the nature of the substituent group. Here's a step-by-step explanation:

1. Identify the substituent group on the aromatic ring.
2. Determine whether the substituent group is electron-donating or electron-withdrawing.
3. Classify the substituent group accordingly:

- Ortho/para directing: If the substituent group is electron-donating, it usually directs the incoming electrophile to the ortho or para position relative to itself. Common examples of ortho/para directing groups include -OH, -NH2, -OCH3, -CH3.

- Meta directing: If the substituent group is electron-withdrawing, it usually directs the incoming electrophile to the meta position relative to itself. Common examples of meta directing groups include -NO2, -CN, -COOH, -SO3H.

Once you have classified the substituent group, you can place it in the appropriate category (either ortho/para directing or meta directing) based on its directing properties.

C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.

In the Millikan oil droplet experiment, the negatively charged oil droplets are subjected to an electric field created by the charged plates. The electric force (Fe) acts on the oil droplet in a direction opposite to the gravitational force (Fg). When Fe is greater than Fg, the electric force overcomes the gravitational force, causing the negatively charged oil droplet to experience an upward force. As a result, the oil droplet moves freely upward toward the negatively charged plate.

Option B is incorrect because if Fe is equal to Fg, the forces balance each other, resulting in a stationary droplet. However, the question states that Fe is increased until it is greater than Fg, implying that the droplet is no longer stationary but moves in response to the electric force.

Therefore, option C is the correct answer, as it describes the effect of an electric field on the motion of a negatively charged oil droplet in the Millikan oil droplet experiment.

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Answer:

The answer is Clay or C!!!

Explanation:

Brainliest Please!!!!!!!!!

Answer:

The control in this experiment is the temperature of the water.

The independent variable is the amount of sugar that is put in.

The dependant variable in this experiment is when the water freezes.

Explanation:

Answer:

3966.82 J

Explanation:

q=sm∆T

q=73×13×4.18

the specific heat for water is 4.18

Answer:

\(\boxed {\boxed {\sf 39,668.2 \ Joules}}\)

Explanation:

We are given the mass and change in temperature, so we must use this formula for heat energy:

\(q=mc \Delta T\)

The mass is 73 grams. Water's specific heat is 4.18 J/g × °C. Let's calculate the change in temperature

Now we know all the variables and can substitute them into the formula.

\(m= 73 \ g \\c= 4.18 \ J/g* \textdegree C \\\Delta T= 13 \ \textdegree C\)

\(q= (73 \ g )(4.18 \ J/g*\textdegree C)(13 \textdegree C)\)

Multiply the first numbers together. The grams will cancel.

\(q= 3051.4 \ J/\textdegree C (13 \textdegree C)\)

Multiply again. This time, the degrees Celsius cancel.

\(q= 39668.2 \ J\)

39,668.2 Joules of heat energy are absorbed.

Reaction stoichiometry is based on chemical equations and the law of conservation of mass.

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Answer:

\(\boxed{\rm Al_{\,(s)}+Fe_2O_{\,(s)} \rightarrow Al_2O_{3\,(s)} + Fe_{\,(s)}}\)

Explanation:

Aluminium metal + iron(I) oxide powder → aluminium oxide solid + iron metal

This is an example of a displacement reaction, with chemical equation:

\(\boxed{\rm Al_{\,(s)}+Fe_2O_{\,(s)} \rightarrow Al_2O_{3\,(s)} + Fe_{\,(s)}}\)

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Answer:

hard to find

Explanation:

Answer:

because actually diamonds is coal.

Explanation:

how diamonds is coal? because when the coal gets very high pressure it turns into diamonds.

The temperature of 2.0 L of water is 42 °C removing thermal energy from the water cause the temperature of the water to increase to 50 °C.

Thermal energy is defined as the internal energy of a system that controls its temperature. Thermal energy is a type of kinetic energy, which is energy brought on by motion, and is brought on by the motion of particles. Solar power plants generate energy through the use of thermal energy.

Q = c × m × Δ T

ΔT = The system's temperature has changed.

The three different processes that lead to heat transmission are described here. When substances are heated, their volume rises, and when they are cooled, it falls.

Thus, the temperature of 2.0 L of water is 42 °C removing thermal energy from the water cause the temperature of the water to increase to 50 °C.

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i don't know if you mean C° to F° but in F° the change would be 123.8°

The artificial sweetener's empirical formula and the molecular formula are C₁₄H₁₈N₂O₅. Therefore, option C is correct.

An empirical formula is a chemical formula for a compound that provides the proportions (ratios) of the elements present but not the exact number or arrangement of atoms.

The empirical formula of an artificial sweetener is given as C₁₄H₁₈N₂O₅ and the molecular mass as 294.34 g/mol.

The molecular formula is written as n×(Empirical formula) where n=(molecular mass)÷ (Empirical mass).

First, find the empirical mass,

\(\begin{aligned}\mathrm{Empirical\;mass\;of\;C_{14}H_{18}N_2O_5}& = 12\times14+1\times18+14\times2+16\times5\\&=\mathrm{294\;g/mol}\end{aligned}\)

Then, we get the n value as follows,

n= 294.34 g/mol÷ 294g/mol

n=1

Then, the molecular formula is, 1×C₁₄H₁₈N₂O₅.

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Answer:

C

Explanation:

edge 2023

Answer:

the answer is 47.9 and ik because I just had that question

The empirical formula of the compound is O₄Pb₃.

An Empirical system is the chemical system of a compound that offers the proportions of the elements gifted within the compound however not the real numbers or arrangement of atoms. This would be the lowest complete variety ratio of the elements within the compound.

Amount of lead (Pb) = 90.6%

⇒and amount of oxygen = 9.4%

taking the whole number ratio

o = 4

Pb = 3

∴ ⇒O: Pb=4:3

O4Pb3 answer.

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Answer:

I think the heat on the surface or the fire under the dish cost evaporation coz when the water got heat tge water evaporate or go to the upper part of dish and cool down then back to the bottom.

Explanation:

Plss correct me if im wrong

Answer:

I need this one asap

Explanation:

Please

The amount of heat energy that will be absorbed by the water from the copper is 37.1 J

Heat lost by copper = heat gained by the water

Thus, we shall determine the heat lost by the copper in order to obtain the heat absorbed by the water

The heat lost by the copper can be obtained as follow:

Q = MCΔT

Q = 11.9 × 0.39 × 8

Q = 37.1 J

Thus, the heat absorbed by the water is 37.1 J

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Answer:

D. Volume

Explanation:

Properties mentioned in the question;

colour = gray

Nonmetallic

Density = 3.8 g/mL

Volume = 48.3 mL

Of the mentioned, which is extensive ?

Extensive properties are those properties that are proportional to the amount of substance present.

The correct option is D. Volume. The other properties do not change with increasing or decreasing amount of the mineral

Sodium chloride is a compound which does not  have a covalent structure.

Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.

Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:

1)Molecular compounds where in atoms are joined by covalent bonds.

2) ionic compounds where atoms are joined by ionic bond.

3)Inter-metallic compounds where atoms are held by metallic bonds

4) co-ordination complexes where atoms are held by co-ordinate bonds.

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It is true that 1,3-butadiene has the chemical formula C4H6 and is a conjugated diene. A popular monomer in the creation of synthetic rubber, polymers, and resins, it is a colourless, flammable gas.

A conjugated diene with the chemical formula C4H6 is 1,3-butadiene. A popular monomer in the creation of synthetic rubber, polymers, and resins, it is a colourless, flammable gas. Because of the butadiene's conjugated double bond system, pi-electrons are delocalized over the whole molecule, giving it special characteristics including high reactivity, a low boiling point, and a propensity for addition reactions. Butadiene is a crucial industrial chemical that is created by the catalytic dehydrogenation of butene or butane. It finds usage in a variety of petrochemical, polymer, and automotive applications.

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A. The overall cellular response is: 2Zn2+ + Fe2+ -> 2Zn + Fe

B. At 25 °C (298 K) and standard conditions, E cell = E °cell. Therefore, ln(K) = 0 and K = 1.

C. After substituting values ​​and evaluating the formula, we can calculate the value of E cell at 25°C.

A. To determine the overall cell reaction, the two half-reactions must be combined and electronically balanced.

Zn2+ + 2e- -> Zn (E = -0.76V)

Fe2+ ​​+ 2e- -> Fe (E = -0.44V)

You can balance the electrons by multiplying the first half reaction by 2 and the second half reaction by 1.

2Zn2+ + 4e- -> 2Zn (doubled)

Fe2+ ​​+ 2e- -> Fe (no change)

Now you can combine half reactions.

2Zn2+ + 4e- + Fe2+ -> 2Zn + Fe

B. The standard cell potential E° cell can be calculated by subtracting the reduction potential at the anode (where oxidation occurs) from the reduction potential at the cathode (where reduction occurs). In this case the anode is the Zn electrode and the cathode is the Fe electrode. E° cell = E° cathode - E° anode

= E°(Fe2+/Fe) - E°(Zn2+/Zn)

= (-0.44V) - (-0.76V)

= 0.32V

C. To calculate ΔG° (the standard change in Gibbs free energy), the following equation can be used:

ΔG° = -n FE° cell

where n is the number of moles of electrons transferred in the equilibrium equation and F is the Faraday constant (96485 C/mol).

In this case n = 2 (from the equilibrium equation).

ΔG° = -2 * F * E° cells

Now we can calculate ΔG°.

ΔG° = -2 * 96485C/mol * 0.32V

= -61750 J/mol

The Nernst equation can be used to calculate the equilibrium constant K for cellular reactions.

E cell = E °cell - (RT / (n F)) * ln(K)

To calculate E cell at 25 °C with specific concentrations of Zn2+ and Fe2+, the Nernst equation can be used.

E cell = E °cell - (RT / (n F)) * ln(Q)

where Q is the reaction quotient given by

Q = ([Zn2+]² / [Fe2+])

Replace the specified concentration:

E cell = E °cell - (RT / (n F)) * ln(([Zn2+]²) / [Fe2+])

E cell = 0.32 V - ((8.314 J/(mol K) * 298 K) / (2 * 96485 C/mol)) * ln((0.10 M)² / (1.0 x 10⁻⁵ M))

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The atomic number of fluorine is 9.

The charge number of an atomic nucleus is known as the atomic number or nuclear charge number of a chemical element. It will be is equal to the proton number of every atom of that element, for ordinary nuclei. Atomic number helps to getting information of elements with the aid of periodic table.

Atomic number = count of proton

It is known that the atomic number of fluorine is 9 . therefore, the answer will be atomic number.

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So, Na (Z=11) has the largest atomic radius among the given elements in the third period.

The element with the largest atomic radius among the given compounds is Na (Z=11) which is a group 1 element and has only one valence electron, leading to a larger atomic radius compared to the other elements in the third period.

1. List the elements given: Al (Z=13), Na (Z=11), Si (Z=14), and Cl (Z=17).
2. Understand that atomic radius generally decreases across a period from left to right due to an increase in effective nuclear charge.
3. Since Na is the farthest left element among the options provided, it has the largest atomic radius.

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Answer:

Explanation:

solidos disueltos totales TDS

okAnswer:

Explanation:

yep

Answer:

4.0 V?

Explanation

Answer: Answer C

Explanation:

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O.

The activation energy for the gas phase decomposition of dichloroethane is 207 kJ. The rate constant at 715 K is 9.82×10-4 /s.

The activation energy for the gas phase decomposition of dichloroethane is 207 kJ. This means that a certain amount of energy, equal to 207 kJ, is required to initiate the reaction. The chemical reaction is as follows: CH3 CHCl2 ---->CH2=CHCl + HCl. The rate constant at 715 K is 9.82×10-4 /s. A rate constant is a measure of the rate of reaction. It is expressed in terms of the concentration of reactants and products in the reaction. Now, we need to calculate the rate constant at a different temperature, which is not given.

To calculate the rate constant at a different temperature, we need to use the Arrhenius equation, which is given by k = Ae^(-Ea/RT), where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant, and T is the temperature in Kelvin. We know the value of Ea, and we can calculate the value of A using the rate constant at 715 K.

Using the given rate constant, we get A = k*e^(Ea/RT) = 9.82×10-4 /s * e^(207000/8.314*715) = 3.17×10^12 /s. Now, we can use this value of A and the given value of Ea to calculate the rate constant at a different temperature.

Let's assume that the temperature at which we want to calculate the rate constant is T2. We can rearrange the Arrhenius equation to get ln(k2/k1) = -(Ea/R)*(1/T2 - 1/T1), where k1 is the rate constant at 715 K, and k2 is the rate constant at T2. Solving for k2, we get k2 = k1*e^-(Ea/R)*(1/T2 - 1/T1). Substituting the given values, we get k2 = 1.36×10-2 /s at T2 = 875 K. Therefore, the rate constant at 875 K is 1.36×10-2 /s.

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The volume of the sample \(V_{2} =53ml\)

To determine the new volume of the gas , we do this by assuming that the gas behaves ideally so  We do this by assuming that the gas behaves ideally so we can use the Combined gas laws.

Boyle's Law, Charles Law, and Gay-Lussac Law are combined to form the Combined gas laws. It claims that a constant exists between the ratio of a gas's absolute temperature to the product of its pressure and volume.

\(\frac{P_{1} V_{1} }{T_{1} }=\frac{P_{2} V_{2} }{T_{2} }\)

where P is the pressure, V is the volume, and T is the temperature in Kelvins. We are given the following values:

\(P_{1} =240\:KPa\:,V_{1} =70\:ml,\:T_{1} =300K,\:P_{2} =160\:KPa,\:T_{2} =150K\)

We proceed with the solution by solving it for \(V_{2}\) -

\(\frac{P_{1} V_{1} }{T_{1} }=\frac{P_{2} V_{2} }{T_{2} }\)

\(\frac{P_{1} V_{1} }{T_{1} }\times\frac{T_{2} }{P_{2} }=V_{2}\)

\(\frac{(200KPa).(70ml) }{300K }\times\frac{150K }{160KPa }=V_{2}\)

\(V_{2} =53ml\)

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The number of moles of gas in the container would be 4.62 moles

According to the ideal gas law:

  PV = nRT, where P = pressure, V, volume, n = mole number, and R = constant = 8.31

In this case, V = 58.953 L, P 467.81 kPa, and T = 719.11 K

Making n the subject:

   n = PV/RT = 58.953 x 467.81/8.31 x 719.11 = 4.62 moles

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Answer:

The answer is Sodium chloride.

Na is sodium and Cl is chlorine.