Answer: 56.4
Explanation:
v=√γRTM
v=√xT T=127
2/3v = 2/3 √xT √127 = 11.
7.51 x 7.51 = 56.4
hope this helps!
Find another example of separation that is used to extract a material made useful by humans. Describe the process of separation and what we use the separated component for. (4-6 sentences)
If anyone would answer this I’ll answer ur questions for return!
Please and thank you!
Answer:
Salt
Explanation:
Salt plays a crucial role in maintaining human health. It is the main source of sodium and chloride ions in the human diet. Sodium is essential for the nerve and muscle function and is involved in the regulation of fluids in the body. Sodium also plays a role in the body's control of blood pressure and volume. Salt is harvested by seawater or brine is fed into large ponds of water and is drawn out through natural evaporation which allows the salt to be subsequently harvested.
Have a good day and stay safe!
Which type of spectrum can we use to determine the chemical composition of
interstellar gas clouds?
In the electromagnetic spectrum, EM radiation includes radio waves, visible light, and gamma rays.
What is a spectrum?
The characteristic wavelengths of electromagnetic radiation (or a subset thereof) emitted or absorbed by a material, atom, or molecule are called spectra. A spectrum is a state that can vary continuously along a continuum and is not limited to a set of values. After passing through a prism, visible light takes on a rainbow of colors, as the term was originally used scientifically in optics.
We study the electromagnetic radiation, or EM radiation, that interstellar clouds emit and receive from them. The range of this EM radiation includes radio waves, visible light and gamma rays in the electromagnetic spectrum.
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Explain what occurs to satellites when they travel too fast and too slow to keep in orbit
If the satellite goes too slow:
It will crash into it's surrounding things it's orbiting.It would not go forward enough due to pull of gravity.Gravity will pull it back to Earth.The satellite could be knocked or moved closer or farther from the object it is orbiting.If the satellite goes too fast:
It will eventually fly away.It can go forward soo fast.It would go too fastly that gravity can't retain in an orbit.The satellite's inertia would carry it off into space.Two pieces of cloth have the same color and texture. Name another property of cloth that you might use to distinguish between the two materials.
Answer:
3эщ4шнп8х34нп943неп43щ
укр
Explanation:
кпк9геъ09ге
Pls draw me what a velocity time graph would look like : moving at a positive constant speed to then at rest? Thank you!!!
Answer:
See below
Explanation:
Here are a couple of options..... one where the object slows to a rest and the other where the object stops to a rest instantaneously
A racing car traveling with constant increases its speed from 10 m/s; 30 m/s over a distance of 60 mlong does this take? to
Answer:
Explanation:
constant acceleration???
assume it to be so
average speed is (10 + 30) / 2 = 20 m/s
t = d/v = 60/20 = 3 s
When two things are the same temperature:
A They have the same number of molecules incorrect answer
B Their molecules stop moving incorrect answer
C Their molecules move at the same average speed incorrect answer
D Heat transfer between the two things stops
Answer:
its obviously D if all the other says "incorrect answer" XD
Explanation:
Answer:
d :D
Explanation:
How long it take Venus to complete one orbit around the sun
It takes 225 Earth days for Venus to complete one orbit around the sun.
The revolution of a planet around the sun is how we define the year. A year is a time it takes a planet to make one revolution. Venus revolves or orbits around the Sun once every 0.615 Earth years, or once every 224.7 Earth days. Venus travels at an average speed of 78,341 miles per hour or 126,077 kilometers per hour in its orbit around the Sun.
Although the other planets have an elliptical orbit around the sun, Venus's orbit is more circular with an eccentricity of less than 0.01. A day on Venus is equivalent to 242 Earth days, which is very slow. The stronger the pull of the Sun’s gravity, the faster the planet orbits. So, a year on Venus takes 225 Earth Days.
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Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?
The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.
Step 1: Identification of the given data:
- Elevation at point 1 (h1) = 10.0 m
- Elevation at points 2 and 3 (h2 = h3) = 2.00 m
- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)
- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)
Step 2: Determination of the discharge rate:
As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.
Therefore, the discharge rate is 0 cubic meters per second.
Step 3: Determination of the gauge pressure at point 2:
To find the gauge pressure at point 2, we'll use Bernoulli's equation:
P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2
Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.
The equation simplifies to:
Patm + ρgh1 = P2 + ρgh2
We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:
\(P_g_a_u_g_e\) = P2 - Patm
Now let's substitute the given values into the equation:
\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm
\(P_g_a_u_g_e\) = ρgh1
Plugging in the values:
\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)
\(P_g_a_u_g_e\) = 98100 Pa
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A wire of length 26.0 cm carrying a current of 5.77 mA is to be formed into a circular coil and placed in a uniform magnetic field B of magnitude 3.67 mT. If the torque on the coil from the field is maximized, what is the magnitude of that maximum torque
Answer:
The maximum torque is \(\tau_{max} = 1.139 *10^{-7} \ N \cdot m\)
Explanation:
From the question we are told that
The length of the wire is \(l = 26.0 \ cm = 0.26 \ m\)
The current flowing through the wire is \(I = 5.77mA = 5.77 *10^{-3} \ A\)
The magnetic field is \(B = 3.67 \ mT = 3.67 *10^{-3 } T\)
The maximum torque is mathematically evaluated as
\(\tau_{max} = \mu B\)
Where \(\mu\) is the magnetic dipole moment which is mathematically represented as
\(\mu = \frac{I l^2}{4 \pi n }\)
Where \(n\) is the number of turns which from the question is 1
substituting values
\(\mu = \frac{ 5.77 *10^{-3} * 0.26^2}{4 * 3.142* 1 }\)
\(\mu = 3.10 4* 10^{-5} A m^2\)
Now
\(\tau_{max} = 3.104 *10^{-5} * 3.67 *10^{-3}\)
\(\tau_{max} = 1.139 *10^{-7} \ N \cdot m\)
What’s crystalline and it’s uses
Crystalline material are material rangd in regular way it can be used in lasers, optics, high energy physics, biomedical technology.
What is a crystalline?Crystalline material has a wide range of applications, such as in lasers, optics, high energy physics, biomedical technology, and light emitting diodes, which require different types of material.
Something is crystalline if the atoms or ions that compose it are arranged in a regular way this can be explained that crystal has internal order due to the periodic arrangement of atoms in three dimensions however the Gems are seen as amorphous if they are non-crystalline.
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Someone please help!!! I dont understand this at all.
The ions are;
S^2- Gained 2 electrons
Li^+ - Lost one electron
Al^3+ - Lost 3 electrons
Cl^- gained one electron
Sr^2+ Lost two electrons
P^3- gained 3 electrons
How are ions formed?As an atom or molecule acquires or loses one or more electrons, ions are created. Protons and neutrons make up the positively charged nucleus of an atom, which is encircled by negatively charged electrons. An atom typically has a neutral charge because the amount of electrons and protons in it equals one.
The balance between the negatively charged electrons and positively charged protons is upset when an atom receives or loses an electron, creating an ion with a positive or negative charge.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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Determine the normal force
produced by an object with a mass of
35 kg.
Answer:
343.4 N ( 340 N if using two significant digits)
Explanation:
If you are just asking for the normal force for a mass on flat, 0° surface
normal force = mg = 35 * 9.81 = 343.4 N
Why are undergraments usually made of cotton
Giving brainliest someone help pls
Answer: Metalloids
Explanation:
hope this helps!
a ball of diameter 10 cm and mass 10 grams is dropped in a container of water. the cross sectional area of the container is 100 cm2.. what is the change in the height of the water column
Answer:
h = 9.83 cm
Explanation:
Let's analyze this interesting exercise a bit, let's start by comparing the density of the ball with that of water
let's reduce the magnitudes to the SI system
r = 10 cm = 0.10 m
m = 10 g = 0.010 kg
A = 100 cm² = 0.01 m²
the definition of density is
ρ = m / V
the volume of a sphere
V = \(\frac{4}{3} \ \pi r^{3}\)
V = \(\frac{4}{3}\) π 0.1³
V = 4.189 10⁻³ m³
let's calculate the density of the ball
ρ = \(\frac{0.010}{4.189 \ 10^{-3} }\)
ρ = 2.387 kg / m³
the tabulated density of water is
ρ_water = 997 kg / m³
we can see that the density of the body is less than the density of water. Consequently the body floats in the water, therefore the water level that rises corresponds to the submerged part of the body. Let's write the equilibrium equation
B - W = 0
B = W
where B is the thrust that is given by Archimedes' principle
ρ_liquid g V_submerged = m g
V_submerged = m / ρ_liquid
we calculate
V _submerged = 0.10 9.8 / 997
V_submerged = 9.83 10⁻⁴ m³
The volume increassed of the water container
V = A h
h = V / A
let's calculate
h = 9.83 10⁻⁴ / 0.01
h = 0.0983 m
this is equal to h = 9.83 cm
: How is a group of people pulling up on a bucket similar to the way a pulley system works? How is it different?
A group of people pulling up on by pulley is way easier than by pulling directly because a pulley system is a freight lift system that allows objects to be hoisted to higher floors with less force. The pulley mechanism is used for Wells to hoist the bucket out of the well. In order to operate, certain forms of gym equipment use pulleys. In order to lift and position heavy goods, building pulleys are used.
What is pulley?A wheel on an axle or shaft known as a pulley is used to transfer power from the shaft to the cable or belt or to sustain movement and direction change of a taut cable or belt. The supporting shell is known as a block, and the pulley may also be referred to as a sheave or a pulley wheel when it is supported by a frame or shell but does not transmit power to a shaft. For the purpose of locating the cable or belt, a pulley may include a groove or grooves between flanges around its circle. A rope, cable, belt, or chain may serve as the drive component of a pulley system. It is example of simple machines.
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What is VB, the electric potential at point B, located at distance d from one end of the rod (on the x axis)?
The question is missing some parts. Here is the complete question.
A finite rod of length L has a total charge q, distributed uniformly along its length. The rod lies on the x-axis and is centered at the origin. Thus one endpoint is located at (L/2) and the other is located at (L/2). Define the electrical potential to be zero at an infinite distance away from the rod. Throughout this problem, you may use the constant k in place of the expression 1 / \(4\pi\epsilon_{0}\)
Part A (image 1): What is VA, the electric potential at point A (see figure below), is located a distance d above the midpoint of the rod on the y-axis? Express your answer in terms of L, d, q and k.
Part B (image 2): What is VB, the electric potential at point B, located at distance d form one end of the rod (on the x-axis)? give your answer in terms of L, d, q and k.
Answer:
Part A: \(V = \frac{kq}{L}[ln(\frac{L/2+\sqrt{(L/2)^{2}+y^{2}} }{-L/2+\sqrt{(-L/2)^{2}+y^{2}} }) ]\)
Part B: \(V=\frac{kq}{L} ln(\frac{L}{d} )\)
Explanation: Electric Potential (V) is the amount of work done per unit charge to move a charge from point A to B.
For a finite rod with charge uniformly distributed along its length
\(V=\frac{1}{4\pi\epsilon_{0}} \int\ {\frac{\lambda}{r} } \,dl\)
where
λ is charge density and, in this case, is constant: \(\lambda=\frac{q}{L}\)
dl is differential of the rod
r is the distance the point is from the rod
Part A: \(r = \sqrt{(a^{2}+y^{2})}\)
\(V=k \int\ {\frac{\lambda}{\sqrt{(a^{2}+y^{2})}} } \,da\)
\(V=k\lambda \int\ {\frac{1}{{\sqrt{(a^{2}+y^{2})}}} } } \,da\)
\(V=k\lambda \int\ {\frac{1}{{\sqrt{(a^{2}+y^{2})}}} } } \,da\)
\(V=\frac{kq}{L}\int\limits^\frac{L}{2} _\frac{-L}{2} {\frac{1}{\sqrt{(a^{2}+y^{2})} } } \, da\)
\(V=\frac{kq}{L}ln(\frac{L/2+\sqrt{(L/2)^{2}+y^{2}} }{-L/2+\sqrt{(-L/2)^{2}+y^{2}} } )\)
At a point located at y-axis, electric potential is \(V=\frac{kq}{L}ln(\frac{L/2+\sqrt{(L/2)^{2}+y^{2}} }{-L/2+\sqrt{(-L/2)^{2}+y^{2}} } )\)
Part B: r = x
\(V=k \int\limits^L_d {\frac{\lambda}{x} } \, dx\)
\(V=k \frac{q}{L} \int\limits^L_d {\frac{1}{x} } \, dx\)
\(V=k \frac{q}{L} ln(L - d)\)
\(V= \frac{kq}{L} ln(\frac{L}{d} )\)
At a point d from one end, electric potential is \(V= \frac{kq}{L} ln(\frac{L}{d} )\)
A solenoid used to produce magnetic fields for research purposes is 2.5 mm long, with an inner radius of 30 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.4 TT in the center. Part A Given this, how large a current does it carry
Answer:
2.14 A
Explanation:
L = 2.5 mm, N = 1300, B = 1.4 T, find I
B = μ₀N*I/L
so I = B*L/(μ₀N) = 1.4 * 0.0025/(4π x 10⁻⁷ x 1300) = 2.14 A
it's raining in 60 degree and man is walking in an inclined plain of base angle 30 degree find angle with vertical at which the man must hold his umbrella to be safe
If a = (3, 2) and b = (-5, 3), what is a + b ?
(8,-1)
(2,5)
(-2,5)
(8,5)
Answer: a + b = (-2,5)
Explanation: I'm assuming that these are 1-dimensional matrices or vectors.
So,
a + b = [ a(x) + b(x), a(y) + b(y) ]
= [ (3) + (-5) , (2) + (3) ]
= [ (-2) , (5) ]
a +b = (-2,5)
Refer to the picture!
(a) The work done by the donkey on the cart is 59,721.9 J.
(b) The work done by the force of gravity on the cart is -48,434.87 J.
(c) The work done on the cart by friction during this time is 11,315.12 J.
What is the work done by the donkey on the cart?(a) The work done by the donkey on the cart is calculated as follows;
Wd = Fd cosθ
where;
F is the applied force by the donkeyd is the displacementθ is the angle of inclinationWd = 375 N x 163 m x cos(12.3)
Wd = 59,721.9 J
(b) The work done by the force of gravity on the cart is calculated as;
Wg = Fg x d x cosθ
Where;
Fg is the force of gravityd is the displacementθ is the angle between the force of gravity and displacementθ = 90⁰ + 4.03⁰ = 94.03⁰
Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)
Wg = -48,434.87 J
(c) The work done on the cart by friction during this time is calculated as;
Wf = Ff x d x cosθ
where;
Ff is the force of friction;Ff = μmg cosθ
Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)
Ff = 69.59 N
Wf = 69.59 x 163 x cos (4.03)
Wf = 11,315.12 J
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PLEASE HELP ILL MARK BRAINLIEST
A car's velocity as a function of time is given by V (t) = at + B.t?, where a= 3m/s and B=
0.1m/s. Calculate the average acceleration for the time interval
a) t=0 s to t=5 s
b) t=5 tot = 10 s
Enrique filled a bucket with 2,250 milliliters of water. How many liters of
water were in the bucket?
Answer:
2.25 Liters
Explanation:
14. Neglecting air resistance, what maximum height will be reached by a stone thrown straight up with an initial speed of 35 m/s?
(a) 98 m
(b) 18 m
(c) 160 m
(d) 63 m
Answer:
D
Explanation:
The maximum height reached by a stone thrown straight up with an initial speed of 35 m/s can be found using the kinematic equation:
v^2f = v^2i - 2gh
where vf is the final velocity (0 m/s at the maximum height), vi is the initial velocity (35 m/s, the magnitude of the velocity with which the stone is thrown upwards), g is the acceleration due to gravity (-9.8 m/s^2), and h is the maximum height reached by the stone.
Rearranging the equation, we get:
h = (vi^2)/(2g)
Substituting the given values, we have:
h = (35 m/s)^2 / (2 * 9.8 m/s^2)
= 62.6 m
Therefore, the maximum height reached by the stone is approximately 63 m.
The answer is (d).
why is unit of power is called derived unit?
Distance travelled by a body in unit time is called speed. it is a scalar quantity because it can be specified only by magnitude.
Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion
Based on Newton's first and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
What is Newton's first law of motion?
Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
An object with a greater mass will require greater force to be stopped or get moving.
Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.
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PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?
The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N
The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Given:
Initial distance between the planets = 1 million miles
Initial gravitational force = 1,000,000 N
Final distance between the planets = 2 million miles
To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.
Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.
According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:
(F2/F1) = (d1/d2)²
Substituting the given values:
(F2/1,000,000 N) = (1 million miles / 2 million miles)²
Simplifying:
(F2/1,000,000 N) = (1/2)²
(F2/1,000,000 N) = 1/4
F2 = (1/4) * 1,000,000 N
F2 = 250,000 N
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The air flowing over the top of the wing travels
in the same amount of time than the air
flowing beneath the wing.
Answer: Short Answer: NO ( In Most Cases)
Explanation:
If that were true then planes couldn't get off the ground to fly. The front of the wing is cutting/pushing the air. On the top of the wing the air moves faster and on the bottom it moves slower making a upward draft giving the object the ability to fly or glide.