Answer:
At moderate relative humidity levels, typically between 50% and 80%, the corrosion rate often reaches its maximum.
Explanation:
The corrosion rate is influenced by various factors, including temperature, presence of corrosive agents, and, indeed, relative humidity.
Relative humidity refers to the amount of moisture present in the air compared to the maximum amount of moisture the air can hold at a particular temperature.
In general, the corrosion rate tends to increase with increasing relative humidity up to a certain point, after which it may start to decrease.
The specific relative humidity at which a maximum corrosion rate occurs can vary depending on the material being corroded and other environmental factors.
However, it is important to note that high relative humidity alone does not necessarily guarantee the highest corrosion rate.
When the relative humidity is low, the amount of moisture available for the corrosion process is limited. As a result, the corrosion rate tends to be relatively low.
As the relative humidity increases, the availability of moisture for corrosion also increases. The water molecules in the air can provide the necessary medium for electrochemical reactions that drive corrosion processes.
At moderate relative humidity levels, typically between 50% and 80%, the corrosion rate often reaches its maximum.
This range of relative humidity allows for an optimal balance between the availability of moisture and other factors involved in corrosion, such as the concentration of corrosive agents .
In this range, the moisture content is sufficient to promote corrosion reactions, but it is not excessive enough to wash away or dilute the corrosive agents.
However, as the relative humidity continues to rise beyond this optimal range, the corrosion rate may start to decrease.
This is primarily due to the formation of surface films, such as oxides or hydroxides, on the metal's surface.
These films can act as barriers, limiting the direct contact between the metal and the corrosive agents in the environment. As a result, the corrosion rate decreases even though the relative humidity remains high.
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2A 5-kilogram rocket is projected upward from rest by an engine/applied force equivalent to 80-Newtons. After firing for 4-seconds the engine turns off. A. Draw and label all of the forces acting on the rocket at each of the intervals shown above. B. Determine the initial upward acceleration of the rocket during the first 4-seconds.
Answer:
(A). The force acting on the rocket is mg.
(B). The initial upward acceleration of the rocket is 6.2 m/s²
Explanation:
Given that,
Mass of rocket = 5 kg
Force = 80 N
Time = 4 sec
(A). We need to draw the figure
The force acting on the rocket at each of the intervals is shown in figure.
The force acting on the rocket is mg.
(B). We need to calculate the initial upward acceleration of the rocket
Using balance equation
\(ma=F-mg\)
\(a=\dfrac{F-mg}{m}\)
Put the value in the equation
\(a=\dfrac{80-5\times9.8}{5}\)
\(a=6.2\ m/s^2\)
Hence, (A). The force acting on the rocket is mg.
(B). The initial upward acceleration of the rocket is 6.2 m/s²
Giving lots of points
All of the devices below either use or produce electrical energy. Which one converts mechanical energy to electrical energy?
E.Battery
F.Electrical drill
G.Wind turbine
H.Electric guitar
Answer:
wind turbine
Explanation:
Answer:
g wind turbine
Explanation:
look up the song dancing in the sky
What is the far point in m of a person whose eyes have a relaxed power of 53. 6 d? (assume a lens-to-retina distance of 2. 00 cm. )
According to the relaxed power, the far point in meter unit is 0.28 meters.
We need to know about the relaxed power of the eye to solve this problem. Relaxed power can be defined as the ability of the optical device to see. It can be represented by a dioptre unit. The relaxed power formula is
P = 1/di + 1/do
where P is power of the eye, di is distance between eye lens and image and do is distance between eye lens and image.
From question above, the given parameters are
P = 53.6 d
di = 2 cm = 0.02 m
By substituting the given parameters, we can calculate the far point
P = 1/di + 1/do
53.6 = 1/0.02 + 1/do
1/do = 53.6 - 50
1/do = 3.6
do = 1/3.6
do = 0.28 m
Hence, the far point in meter unit is 0.28 meters.
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At a certain time a particle had a speed of 17 m/s in the positive x direction, and 3.0 s later its speed was 28 m/s in the opposite direction. What is the average acceleration of the particle during this 3.0 s interval
Answer:
i wanna say 11 forgive me if wrong.
Explanation:
3. The same laser is now fired at a diffraction grating with 800 lines per cm, again 2.0 m from the screen behind it. a) What is the distance between the slits in the diffraction grating
The laser is fired at a diffraction grating with 800 lines per cm, again 2.0 m from the screen behind it. The distance between the slits in the diffraction grating is 1.25 x 10^(-5) meters.
To determine the distance between the slits in the diffraction grating, we need to use the formula:
d = 1 / N,
where d is the distance between the slits and N is the number of lines per unit length on the grating.
Given that the diffraction grating has 800 lines per cm, we can convert it to lines per meter:
N = 800 lines/cm = 800 lines / (0.01 m) = 80000 lines/m.
Now we can substitute this value into the formula to calculate the distance between the slits:
d = 1 / N = 1 / 80000 lines/m = 1.25 x 10^(-5) m.
Therefore, the distance between the slits in the diffraction grating is approximately 1.25 x 10^(-5) meters.
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a thin layer of gasoline is floating on a thin layer of water in a parking lot. you notice that there are multicolored bands on the surface of the gasoline. which one of the following statements concerning this situation is false? the wavelength that is important for thin-film interference is the wavelength within the film, not the wavelength in a vacuum. the wavelength within a film is determined by multiplying the index of refraction and the vacuum wavelength. the fact that the bands are multicolored indicates that the film has non-uniform thickness. when light travels through a material with a smaller refractive index toward a material with a larger refractive index, reflection at the boundary occurs along with a phase change that is equivalent to one-half of a wavelength in the film. when light travels from a larger toward a smaller refractive index, there is no phase change upon reflection at the boundary.
The statement that is false in this situation is that the fact that the bands are multicolored indicates that the film has non-uniform thickness. In reality,
the multicolored bands on the surface of the gasoline are a result of thin-film interference, which occurs when light waves reflect off the top and bottom surfaces of a thin film.
The thickness of the film affects the way the light waves interfere with each other, leading to the appearance of colored bands. However, the colors do not indicate non-uniform thickness,
but rather the thickness of the film at each point on the surface. The other statements are all true. The wavelength that is important for thin-film interference is the wavelength within the film,
which is determined by multiplying the index of refraction and the vacuum wavelength. When light travels through a material with a smaller refractive index toward a material with a larger refractive index,
reflection at the boundary occurs along with a phase change that is equivalent to one-half of a wavelength in the film. When light travels from a larger toward a smaller refractive index,
there is no phase change upon reflection at the boundary.
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explain why spraying and asphalt road with water will make it easier to walk across and bare feet on a hot sunny day
Spraying an asphalt road with water will make it easier to walk across and bare feet on a hot sunny day because it has a high specific heat capacity.
What is Specific heat capacity?This is referred to as the amount of heat which is required to raise the temperature of the unit mass of a given substance by a given amount.
Water as a compound has a very high specific heat capacity which means that it needs a high amount of heat for the temperature to change. This therefore means that when the water is sprayed on the surface, the road doesn't become too hot and can be walked on with the barefoot which makes it the correct reason.
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(PLS HELP ME NOW!!!!!)
Answer:
D
Explanation:
34 A disk of radius 2.5 cm has a surface charge density of 5.3 mC/m2 on its upper face. What is the magnitude of the electric field produced by the disk at a point on its central axis at distance z
The electric field produced by a disk at a point on its central axis at distance z can be calculated using the formula below
E = σ/2ε[1 - (a2 + z2)1/2]
Where;σ = surface charge density ε
= permittivity of free space
= 8.85 × 10-12 C2/N.ma
= radius of the disk
= 2.5 cm
= 0.025 mz
= distance from the center of the disk to the point of interest Using the values given;
σ = 5.3 mC/m2
= 5.3 × 10-3 C/m2ε
= 8.85 × 10-12 C2/N.ma
= 0.025 m
Now substituting into the formula;
E = (5.3 × 10-3)/(2 × 8.85 × 10-12)[1 - (0.0252 + z2)1/2]
Simplifying;
E = 2.397 × 107[1 - (0.000625 + z2)1/2] N/C
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What are the fundamental characteristics of a vector
Answer:
The two defining characteristics of a vector are its magnitude and its direction.
Explanation:
How fast does a 500kg car need to drive to have 100,000 J of kinetic energy?
Answer:
The car must move at 2 m/s to have a Ke of 2,000 Joules.
Explanation:
Mark me pls
A leftward force of 50 N is applied to an 8 kg
object to move it across a rough surface with a
leftward acceleration of 5 m/s/s. Determine the
gravitational force, normal force, frictional
force, net force, and the coefficient of friction
between the object and the surface.
A leftward force of 50 N is applied to an 8 kg object to move it across a rough surface with a leftward acceleration of 5 \(m/s^{2}\) , its
gravitational force = 78.4 N
normal force = 78.4 N
frictional force = 10 N rightward
net force = 40 N leftward
coefficient of friction = 0.128
given
force = 50 N
mass = 8 kg
acceleration = 5 \(m/s^{2}\)
gravitational force = mg = 8 * 9.8 = 78.4 N
normal force = mg = 78.4 N ( as N= mg )
- F (applied) + frictional force = - F (net )
F (applied) - fr = F (net )
50 - fr = mass * acceleration
50 - fr = 8 * 5
fr = 10 N
Fnet = ma = 8 * (-5) = -40 N
Frictional force = mu * N
10 = mu * 78.4
mu (coefficient of friction ) = 10 / 78.4 = 0.128
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the work done by the brakes during braking is equal to
Answer:
The amount of pressure delivered to them
Explanation:
The frequency of a hummingbird wing - beat during a regular motion that can beat it's wings up to 4800 times per minute?
Answer:
the frequency of the hummingbird is 80 Hz.
Explanation:
Given;
number of times the hummingbird beats its wings, n = 4,800 times
the duration of this motion, t = 1 minute
The frequency of the hummingbird wings is calculated as follows;
\(frequency = \frac{number \ of \ times}{time \ taken} \\\\frequency= \frac{4,800}{1 \min \ \times \ 60s} = 80 \ Hz\)
Therefore, the frequency of the hummingbird is 80 Hz.
Explain why two objects with the same mass, when dropped from the same height, may not reach the ground at the same time
This is because the Earth gives the same acceleration to everything, objects with different masses will still hit the ground at the same time if they are dropped from the same height.
What is Acceleration?Acceleration is defined as the rate of change of velocity of an object, which is a vector quantity as well as direction, with respect to time. The orientation of an object's acceleration is given by the orientation of the net force acting on that object.
Two objects of equal mass cannot reach the ground at the same time when they have different sizes, shapes or densities, as these factors can affect their air resistance and terminal velocity so that they travel at different speeds.
Thus, this is because the Earth gives the same acceleration to everything, objects with different masses will still hit the ground at the same time if they are dropped from the same height.
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An automobile travels on a straight road at 30 km/h How long will it take to travel 40 km
Answer:
the time taken for the automobile to travel the given distance is 80 mins.
Explanation:
Given;
speed of the automobile, v = 30 km/h
distance traveled by the automobile, x = 40 km
The time taken for the automobile to cover the given distance is calculated as;
time = distance / speed
time = 40 / 30
time = 1.3333 hours = 1.3333 hr x 60mins/hr = 80 mins
Therefore, the time taken for the automobile to travel the given distance is 80 mins.
How does charging by conduction work?
Answer:
During charging by conduction, both objects acquire the same type of charge. If a negative object is used to charge a neutral object, then both objects become charged negatively. ... In this case, electrons are transferred from the neutral object to the positively charged rod and the sphere becomes charged positively.
Please answer fast
A 50 kg boy jumps off the front of a 1.5 kg skateboard moving forward. Find the skateboard's velocity
immediately after the boy jumps, assuming that the skateboard's initial velocity is 3.5 m/s and the boy's
velocity when jumping off the front is 5 m/s?
Answer:
The speed is 1.35 m/s
Explanation:
(m1+m2) vi= m1+m2v2
(50+1.5) (3.5)=50 (5+v2) +1.5 v2
180.25= 250+ 51.5 v2
180.25- 250+ 51.5 v2
-69.75= 51.5 v2
v2= -1.35 m
Electrons are important to electric current because they are able to (2 points)
O a carry a positive charge with them as they are transferred from one atoſ to the next creating electric current
Oь
change from a positive charge to a negative charge when transferred from the one atom to the next as the atom becomes an ion
Oc move from one atom to another; the atom that loses an electron becomes positively charged and the atom that gains an electron
becomes negatively charged
Od
shift from one atom to another creating a change in the charge of the atom from a negative to a positive
answer: C
Explanation:
move from one atom to another, the atom that loses an electron becomes positively charged and an atom that gains electrons becomes negatively charged
a = 40
B= 75
m = 50 kg
kt=0.3
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To which mass of m2 will mass ml go down the hill? What will be the
acceleration of m2 (a)?
On which interval of masses m2 will the system rest/not move?
On which mass m2 will the system go backwards (ml up the hill) What
will be the acceleration of ml (a)?
Solve with II. Newton's law.
Answer:
A DAY IN THE LIFE OF METIS JOURNAL, I WROTE IT HOPE U LIKE IT ;))) XD
We, who live in the west, were Nomadic. So we always moved from place to place to hunt buffalo and other fur-bearing animals. And now again we have to shift everything we collected , like, all the essential needs we collected. It’s really hard to shift stuff, But when you move to a new place you get to see new beautiful places. They are just so satisfying to see! It’s like all my work(like the shifting work) is paid off. I love it! We always meet the Hudson’s bay company employees, and give them furs which we took from the bissons and other furry animals we hunted. And in exchange they give us their (Hudson’s Bay company) goods. Which is good! Because then we or I won't be able to enjoy that delicious pemmican!
The one reason that makes me proud of my parents is that because of them I am like a translator for both sides in the fur trade! Anyways coming back to the present. As I said before, we were moving today to another place, But on the way some people along with my father will ride the famous York boats carrying supplies to fur posts. I begged my father to take me with him! And as usual he gave me some silly reason for me to stay. And now since I don’t have anything to do I will-..Nevermind, My mom’s calling me. Okay after helping my mom keep the fur posts into the York boats me , my mom, and the others are just relaxing and enjoying nature just to take a break. Since, I am so obsessed with my Journal notebook today I’m just going to sit here and right what comes to my mind. I’m not like the others who always seem to be talking with someone. I like my own space!
I kind of miss my dad already, but he and his fellow members need to travel the waterways from the red river further west and north to hudson bay. These red river carts also travel the trek back and forth over land to St. Paul, Minnesota and to posts in saskatchewan. Speaking about the red river, the only large settlement in the region is the red colony. About 12000 people lived in this colony around Fort Garry. Some were the original Selkirk settlers or their descendents. They had come from Scotland with lord Selkirk when he established the colony in 1811. Many of these original settlers were poor farmers who had been displaced from their lands in scotland. They had endured many hardships in the early years of settlement, including foods, hunger, and sickness. I love studying about other colonies, cultures , history etc.
Explanation:
write this as your answer you will get extra marks
ANSWER PLEASE 20 POINTS AND MARKED AS BRAINLIEST MY GRADE DEPENDS ON IT PLEASE PLEASE PLEASE
Your friend throws a rock off of a cliff straight down with an initial speed of 7.50 m/s. Using a stopwatch, you determine it takes the rock 4.50 s to hit the ground below. How high is the cliff?
Answer:33.75m
Explanation: If you are throwing a rock down a cliff with a speed of 7.50m/s and it reached the ground in 4.50 seconds the height of the cliff will be 33.75m because 7.50m/s x 4.50s = 33.75
4. A 1.5 m tall man is standing 2m away from the concave lens (remember f is negative) of a peephole with a focal length of 3.0 cm. a) What is the distance to the image in centimeters? b) What is the magnification of the image in meters?
Here,
Size of object = 1.5 m;
Object distance (u) = - 2m = -200cm
focal length (f) = - 3.0 cm
Image distance (v) = ?
Using lens formula
\(\begin{gathered} \frac{1}{f}=\text{ }\frac{1}{v}-\frac{1}{u}; \\ \frac{1}{-3}=\frac{1}{v}-\frac{1}{-200}; \\ \frac{1}{-3}=\text{ }\frac{1}{v}\text{ +}\frac{1}{200} \\ \frac{1}{v}=\text{ -}\frac{1}{3}-\frac{1}{200}=-\text{ }\frac{203}{600} \\ v=\text{ - }\frac{600}{203}=\text{ -2.96 cm} \end{gathered}\)Now magnification is given by
\(Magnification=\text{ }\frac{v}{u}=\text{ }\frac{2.96}{200}=0.0148\)Final answer is :-
Image distance = - 2.96 cm & magnification = 0.0148
A fruit drops from the top of a tree 20m tall. Calculate the time it takes the fruit to reach the ground
Answer:2 seconds
Explanation:
g=10m/s2
h=20m
t=h/g
t=20/10
t=2s
hello I need help with this question. I started it but am confused
Given:
The mass on the table is,
\(m=1.0\text{ kg}\)The hanging mass is,
\(M=1.5\text{ kg}\)THe coefficient of friction is,
\(\mu=0.20\)let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.
we can write,
\(Mg-T=Ma\ldots.\ldots..\ldots\ldots.(1)\)\(ma=T-\mu mg\ldots.\ldots.\ldots..\ldots..(2)\)Adding these equations we get,
\(\begin{gathered} (M+\mu m)g=(M+m)a \\ a=\frac{(M+\mu m)g}{M+m} \end{gathered}\)Substituting the values we get,
\(\begin{gathered} a=\frac{(1.5+0.20\times1.0)9.8}{1.5+1.0} \\ =6.67m/s^2 \end{gathered}\)Hence the acceleration is 6.66 m/s^2.
A charge of 3.877 nC is moved from a position on the y axis of 8.856 cm to a position on the x axis of 1.619 cm while there is a charge 21.524 nC located at the origin. How much work in micro-Joules did it take to move the charge?
Answer:
sa64
Explanation:
a child kicks a soccer ball across the grounds the ball travels 10.0 meters in 0.56 seconds. what is the speed of the ball
a uniform magnetic field of magnitude 1.7 t is directed perpendicular to the plane of a rectangular loop having dimensions 15 cm by 16 cm. find the magnetic flux through the loop.
A uniform magnetic field of magnitude B exists when the magnetic field strength and direction are the same at all points within the region of interest.
Given: Uniform magnetic field of magnitude 1.7 T Dimension of the loop = 15 cm × 16 cm = 0.15 m × 0.16 m = 0.024 m²
Formula used: Φ = BA, where Φ is the magnetic flux, B is the magnitude of magnetic field and A is the area of the loop perpendicular to the magnetic field, here B is perpendicular to the loop.
Φ = BA
where,B = 1.7 T (Given)
A = 0.024 m² (Given)
Φ = 1.7 × 0.024Φ = 0.0408 Wb
Hence, the magnetic flux through the loop is 0.0408 Wb.
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T/F: the universe has been expanding at the same rate since its formation.
The statement is false. The expansion of the universe has not been constant since its formation.
The cosmos has been expanding faster over time, according to the prevalent scientific theory. Observations of far-off supernovae and measurements of cosmic microwave background radiation were used to make this finding.
It sparked the development of the cosmic inflation theory and the idea of dark energy, which is believed to be the cause of the rapid expansion. Throughout the universe's history, the pace of expansion has changed, with periods of slower growth and periods of quicker expansion.
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Suppose an air bubble is trapped in the eudiometer before starting the experiment. After the experiment is finished, the resulting value of r would be.
Answer:
Explanation:
The resulting valie would be too large
a 82.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 43.0 m/s. if both are initially at rest and if the ice is frictionless, how far (in m) does the player recoil in the time it takes the puck to reach the goal 22.0 m away? (enter the magnitude.)
The distance travelled by the player( recoil ) in the time the puck reach the goal is 0.025m.
How to calculate the time taken?Mass of the player;
Mass of puck;
Since they were both at rest initially
Initial velocity of player;
Initial velocity of puck;
Velocity of player after the hit;
Velocity of puck after the hit;
Distance to the goal;
Using conservation of linear momentum:
Now, Since they were both at rest initially
We substitute in our values to find the velocity of the player after the hit ( recoil velocity )
{ The negative sign shows that the velocity of both the player and the puck are in opposite direction }
Hence, recoil velocity of the player is 0.075m/s
Now, we determine the time taken for the puck to trach the goal using the relation between distance, velocity and time .
Time = Distance / Velocity
We substitute our values into the expression
Hence, the time taken for the puck to reach the goal is 0.3333 seconds.
Next, we determine the distance travelled by the player( recoil ) in the time the puck reach the goal using the relation between distance, velocity and time .
Time = Distance / Velocity
We substitute in our values
Therefore, the distance travelled by the player( recoil ) in the time the puck reach the goal is 0.025m.
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