The apparent brightness of the Sun at the orbit of Venus is about 2612 watts/m².
How to determine apparent brightness?This is because the brightness of the Sun decreases with distance from the Sun, following an inverse square law. At a distance of 67 million km from the Sun, the apparent brightness is reduced by a factor of (1 / 0.723)², which is approximately 1.91.
Therefore, the apparent brightness of the Sun at the orbit of Venus is the product of the solar constant (1361 watts / m²) and this reduction factor, which is approximately 2612 watts / m².
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How much power is required to light a lightbulb at 100V of voltage when the lightbulb has a resistance of 500 Ohms?
Answer:
Power = 20 Watts
Explanation:
Given the following data;
Voltage = 100 V
Resistance = 500 Ohms
To find the power that is required to light a lightbulb;
Mathematically, power can be calculated using the formula;
\( Power = \frac {Voltage^{2}}{resistance} \)
Substituting into the formula, we have;
\( Power = \frac {100^{2}}{500} \)
\( Power = \frac {10000}{500} \)
Power = 20 Watts
how are flow of electrons in a conductor and the direction of conventional current related??
Answer:
flow of electron is just opposite to the flow for current. Electrons flow from the negative terminal to the positive. Conventional current or simply current, behaves as if positive charge carriers cause current flow. Conventional current flows from the positive terminal to the negative.
you blow across the open mouth of an empty test tube and produce the fundamental standing wave in the 14.0-cmcm-long air column in the test tube, which acts as a stopped pipe. the speed of sound in air is 344 m/sm/s.
When you blow across the open mouth of an empty test tube, you create a standing wave in the 14.0 cm-long air column inside the tube. This column of air acts as a stopped pipe. The speed of sound in air is given as 344 m/s. the frequency of the fundamental standing wave in the test tube is 614.3 Hz.
To find the frequency of the fundamental standing wave in the test tube, we can use the formula:
frequency = speed of sound / wavelength
Since the test tube is acting as a stopped pipe, we know that the length of the air column is equal to a quarter of the wavelength of the fundamental standing wave.
So, the wavelength of the fundamental standing wave in the test tube is four times the length of the air column, which is 4 * 14.0 cm = 56.0 cm.
Now, we can substitute the values into the formula:
frequency = 344 m/s / 56.0 cm
Before we can continue, we need to convert the wavelength from centimeters to meters:
56.0 cm = 0.56 m
Now, we can substitute the values and solve for the frequency:
frequency = 344 m/s / 0.56 m = 614.3 Hz
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what is the magnitude of the net force
Answer:
←13
Explanation:
You see the two men pushing it the opposite direction from each other. When you see different net forces you subtract the numbers from each other. So 53- 40=13. You see which value holds the greatest amount and say that the answer you got is supposed to be that side of the net force. The answer is "13 net force to the left, OR ←13"
when dealing with an electrical emergency involving a downed power line, ______
When dealing with an electrical emergency involving a downed power line, it is important to follow certain safety precautions to avoid injury or further damage.
First, stay at least 10 meters (around 33 feet) away from the downed power line and any objects that it may be touching, as they could potentially be electrified.
Next, call 911 to report the downed power line and warn others in the area to stay away.
Do not attempt to move the power line or any objects it may be touching, as this could result in serious injury or death. Wait for emergency responders to arrive and follow their instructions. Remember, safety should always be the top priority in any electrical emergency.
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Convert 142 weeks into years
Answer:
142 weeks/52 weeks per year = 2.7 years
so the answer is 2.7 years
Explanation:
A ball thrown straight upward returns to its original level in 2.5 seconds. A second ball is thrown at an angle of 40 degrees above the horizontal. What is the initial speed ball if it also returns to its original level in 2.5 seconds?
Answer:
The velocity is \(u = 19.1 \ m/s\)
Explanation:
From the question we are told that
The time taken by the ball is t = 2.5 seconds
The angle made with the horizontal is \(\theta = 40^o\)
Generally the vertical component of the initial velocity is mathematically represented as
\(u_y = u sin (\theta )\)
Generally at maximum height of the ball the velocity is v = 0 m/s and the time take to reach this maximum height is
=> \(t_m = \frac{t}{2} = \frac{2.5}{2} = 1.245 \ s\) [This because t is duration for the to a fro travel of the ball]
Generally from kinematic equation
\(v = u_y + gt\)
Here \(g = -9.8 m/s^2\) given that the direction is against gravity
=> \(0 = u sin (40) - 9.8 * [1.25]\)
=> \(0 = 0.6428u - 12.25\)
=> \(u = 19.1 \ m/s\)
PLEASE HELP !!
Elements in period 2 on the periodic table all have blank
electron shells.
Answer:
Two orbitals for their electrons and six in the 2p subshell
Explanation:
Hope this helps :)
A car is initially traveling at 19 m/s and accelerates to 26 m/s to pass a truck. If the car travels 205 m while accelerating, how long did it take?
To find the time it took for the car to accelerate, you can use the formula:
t = (v - u) / a
where t is the time, v is the final velocity, u is the initial velocity, and a is the acceleration.
Plugging in the given values, you get:
t = (26 m/s - 19 m/s) / (205 m / t^2)
You can then rearrange the equation to solve for t:
t = sqrt(205 m / (26 m/s - 19 m/s))
Solving for t, you get:
t = sqrt(205 m / 7 m/s) = sqrt(29.3 s^2) = 5.4 s
So it took the car approximately 5.4 seconds to accelerate from 19 m/s to 26 m/s.
The Northern Hemisphere is experiencing the summer season. Where is most of the direct sunlight located on Earth at that time?(1 point)
Responses
on the Southern Hemisphere
on both hemispheres
on the equator
on the Northern Hemisphere
Uniform Circular Motion: You need to design a wheel for testing purposes such that its rim will have an acceleration of 1.5 g when the rim is moving at 37 m/s while spinning. What should be the diameter of this wheel?
Answer:
We want to have an acceleration of:
A = 1.5*g = 1.5*9.8m/s^2 = 14.7 m/s^2
When the rim is moving at 37m/s while spinning.
Now, in circular motion we have two accelerations.
Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.
Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.
I suppose that in this problem we want to have a centripetal acceleration of 14.7m/s^2
The equation for the centripetal acceleration is:
Ac = v^2/r
Where v = velocity and r = radius.
then we must solve:
14.7m/s^2 = (37m/s)^2/r
r = (37m/s)^2/14.7m/s^2 = 93.13 m
The volume of gas decreases at constant temperature to 80% of the inital value. How does the pressure value change relative to the initial value
Answer:
The pressure value changes 400 % relative to the initial value.
Explanation:
Let suppose that the gas behaves ideally and represents a closed system, that is, a system with no mass interactions so that number of moles is conserved (\(n\)). Since the variables involved in the isothermal process are pressure (\(P\)) and volume (\(V\)). Finally, the process is represented by the following relationship:
\(P_{1}\cdot V_{1} = P_{2}\cdot V_{2}\) (1)
Where:
\(P_{1}, P_{2}\) - Initial and final pressures.
\(V_{1}, V_{2}\) - Initial and final volumes.
If we know that \(P_{1} = P_{o}\), \(V_{1} = V_{o}\) and \(V_{2} = 0.2\cdot V_{o}\), then the final pressure of the closed system is:
\(P_{2} = P_{1}\cdot \left(\frac{V_{1}}{V_{2}} \right)\)
\(P_{2} = 5\cdot P_{o}\)
The pressure value changes 400 % relative to the initial value.
A negative charge of -0.0005 C exerts an attractive force of 9.0 N on a second charge that is 10m away. What is the magnitude of the second charge?
The magnitude of the second charge is calculated using Coulomb's law. The magnitude of the second charge is 0.00022 C.
What is Coulomb's law ?Coulomb's law states the force exerted between two charges is directly proportional to magnitude of charges and inversely proportional to their distance.
F = k q1 q1/r²
where k is a constant equal to 8 × 10⁹ Nm²/C²
Given F = 9 N
q1 = - 0.0005 C
r = 10 m
9 N = - 0.0005 C × q2 × 8 × 10⁹ Nm²/C² /(100 m²)
q2 = 9 N × 100 m² / (- 0.0005 C ×8 × 10⁹ Nm²/C² )
= 0.00025 C
Therefore, the magnitude of the second charge here is 0.00025 C.
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The magnitude of the second charge is 3.6 x 10⁻⁶ C.
What is the magnitude of the charge?The electric charge carried by a single proton, or alternatively, the magnitude of the electric charge carried by a single electron, which has charge e, is the elementary charge, which is often represented as e or occasionally q. This fundamental physical constant is this elemental charge.
The electric force between two point charges is given by Coulomb's law:
F = kq₁q₂ / r²
where F is the force between the charges,
k is Coulomb's constant (9 x 10⁹ N·m²/C²),
q₁ and q₂ are the magnitudes of the charges,
and r is the distance between them.
In this problem, we are given the force between two charges and one of the charges.
We can rearrange Coulomb's law to solve for the magnitude of the second charge:
q₂ = F * r² / (k * q₁)
Substituting the given values, we get:
q₂ = 9.0 N * (10 m)² / (9 x 10⁹ N·m²/C² * 0.0005 C)
q₂ = 3.6 x 10⁻⁶ C
Therefore, the magnitude of the second charge is 3.6 x 10⁻⁶ C.
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a box is 4 m in the air and has 120 J of potential energy. What is the box's mass
Answer: 3 kg
Explanation:
The formula for potential energy is Ug=mgh where Ug is potiental energy, m is mass, g is the acceleration caused by gravity which is either 9.8 m/s^2 or 10m/s^2 depending on your textbook and h is the height and or displacement. So…
120 = m(10)(4)
120=40m
m= 3 kg
Answer:
Explanation:
Given:
h = 4 m
W = 120 J
g = 10m/s²
_________
m - ?
W = m*g*h
m = W / (g*h) = 120 / (10*4) = 3 kg
Two carts, moving at opposite directions, collide and recoil. Which question would help determine if the system of two carts is open or closed? A) Do the carts have the same mass? B) Do the carts have different initial velocities? ) Is energy transferred from one cart to the other? D) Is the total momentum constant before and after the collision?
Answer:D
Explanation:
i’m not sure if that’s right but that’s what i think
When light hits a surface it usually bounces off at a larger angle. True or false? Justify
Answer:That only applies to highly polished surfaces, eg mirrors.
If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.
As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.
Explanation:
I need help asap please
Answer:
I dont know answer Sorry For that thank u
Injuries from motorcycle collisions are primarily from Select one: a. other vehicles hitting them. b. the exposed position of the rider. c. hitting deer. d. driving too fast.
The primary cause of injuries from motorcycle collisions is the exposed position of the rider. (Option B)
Motorcycle collisions often result in injuries due to the vulnerability of the rider's position. Unlike occupants of cars or other vehicles, motorcycle riders lack the protection of an enclosed vehicle, making them more susceptible to injuries. In the event of a collision, riders are directly exposed to external forces and can be thrown from the motorcycle, leading to severe injuries such as fractures, abrasions, head trauma, and spinal cord injuries.
While other factors like other vehicles hitting them or driving too fast can contribute to the severity of injuries, the exposed position of the rider remains the primary cause. Therefore, option B is the correct answer.
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the spacecraft that got the closest to the nucleus of halley's comet and sent back dramatic photographs of what the nucleus looked like was:
The spacecraft that got the closest to the nucleus of Halley's Comet and sent back dramatic photographs of what the nucleus looked like was the European Space Agency's (ESA) Giotto spacecraft.
The Giotto spacecraft was launched on July 2, 1985, and on March 13, 1986, it passed within 596 kilometers (370 miles) of Halley's comet's nucleus. It was able to send back spectacular photographs of the comet's nucleus.
The Giotto mission was a joint European Space Agency (ESA) project with contributions from 14 European countries. It was named after the Italian artist Giotto di Bondone because the probe's camera had the same field of view as the artist's sketch of Halley's comet in 1301.
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2. A solid disk with a mass of 0.165 kg and a radius of 0.215 m that is spinning at 35 rad/s counterclockwise can be stopped by a hand in 0.15 sec. What is the average torque exerted on the disk by the hand? (Hint: first use kinematics, then use Newton's second law)
The average torque exerted on the disk by the hand is -5.49 Nm.
What is torque?
Torque can be defined as a force exerted at a distance from the axis of rotation.
To find the average torque exerted on the disk, we need to calculate the angular acceleration and then use the equation for torque:
Torque = I * alpha, where I is the moment of inertia and alpha is the angular acceleration.
First, let's find the angular acceleration:
Initial angular velocity = 35 rad/s
Final angular velocity = 0 rad/s
Time = 0.15 s
Using the kinematic equation for angular acceleration:
alpha = (Final angular velocity - Initial angular velocity) / Time
alpha = (0 - 35) / 0.15
alpha = -233.33 rad/s^2
Next, let's find the moment of inertia of the solid disk:
I = (1/2) * m * r^2
I = (1/2) * 0.165 kg * (0.215 m)^2
I = 0.0234 kg m^2
Finally, let's find the average torque:
Torque = I * alpha
Torque = 0.0234 kg m^2 * -233.33 rad/s^2
Torque = -5.49 Nm
Therefore, The average torque exerted on the disk by the hand is -5.49 Nm.
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Parallel Circuits:
A) are rarely used in the wiring in homes
B) always need more voltage than series circuits
C) will have positive charges flowing in one branch, negative charges in the other
D) provide more than one path fo current flow
Answer:
D.)
Explanation:
the current separates on each branch according to the resistance it experience.
Answer:D
Explanation:
(PLEASE HELP) : A muon (a particle with the same charge as an electron but with a mass of 1.88×10−28 kg) is traveling at 4.21×107 m/s at right angles to a magnetic field. The muon experiences a force of −5.00×10−12 N.
a. How strong is the magnetic field?
b. What acceleration does the muon experience?
The magnetic force is 0.74T and acceleration of the Moun is calculated as 2.66*10^16 m/s^2
Data;
Force (F) = -5.00*10^-12NVelocity = 4.21*10^7 m/sMass(m) = 1.88 * 10 ^-28 kgMagnetic Field ForceThe formula of magnetic field force is given by
\(F =BqV\)
Let's make the magnetic field force the subject of formula
\(F=BqV\\B = \frac{F}{qV}\\B = \frac{5.00*10^-^1^2}{1.60*10^-^1^9 * 4.21*10^7} \\B = 0.74T\)
The magnetic force is 0.74T
Acceleration of the MounThe acceleration of moun can be calculated as
\(F=ma\\a = F/m\\a = \frac{5.0*10^-^1^2}{1.88*10^-^2^8} \\a = 2.66*10^1^6m/s^2\)
The acceleration of the Moun is calculated as 2.66*10^16 m/s^2
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QUESTION 1 In flow separation, wake is defined as the region of flow trailing the body where the effects of the body on velocity are felt. O True O False QUESTION 2 A pitot tube is used to measure only pressure head in a pipe flow. O True O False QUESTION 3 The depth for nonuniform flow conditions is called normal depth O True O False
In flow separation, wake is defined as the region of flow trailing the body where the effects of the body on velocity are felt. The given statement is true. In flow separation, the wake is the region behind the body where the effects of the body on velocity are felt.
A pitot tube is used to measure only pressure head in a pipe flow. The given statement is false. Pitot tubes are used to measure both the stagnation pressure and the static pressure in a pipe flow.
The depth for nonuniform flow conditions is called normal depth. The given statement is false. Non-uniform flow is a type of fluid flow that is not constant throughout the flow's depth. The water depth in non-uniform flow is referred to as critical depth, not normal depth. The critical depth is the depth of flow at which the specific energy of a channel is a minimum for a given discharge.
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A puppy finds a rawhide bone and begins to pull it with a force, Ft. The free-body diagram is shown.
Which describes what happens to the bone?
Answer:
it begins to move to the right! :)
what mass m2 will allow the following mobile to maintain static equilibrium?
A mass of will allow the following mobile to maintain static equilibrium.
In the given figure, we can clearly see that the rods are horizontal and also it's given that they are in static equilibrium.
Therefore we can conclude that the torque on the points connecting the rods is equal due to 0.1 kg and m1 masses
So,
(0.1 kg) × (0.1 m) = (0.2 m) × (m1)
m1 = 0.05 kg
Applying the same procedure of equating torque with the combined mass of 0.1kg and 0.05 kg and m2,
we get,
(0.15 kg) × (0.2 m) = (0.4 m) × (m2)
m2 = 0.075 kg
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A tank is full of water. Find the work required to pump the water out of the spout. (use 9. 8 m/s2 for g. Use 1000 kg/m3 as the density of water. Assume r = 6 m and h = 2 m. ).
70.934648 MJ of work is needed to pump the water out of the spout.
The tank is shaped like a globe. the distance to the mass's center = h+r =6+2=8
Weight of water in tank = 9.8×π×6³×1000×4/3
= 8.866831×10⁶ N
to empty the tank Work done = 8 × 8.866831×10⁶
=70.934648×10⁶ J
= 70.934648 MJ.
A pump is a mechanical device used to transport fluids (liquids, gases, or occasionally slurries). It commonly converts electrical energy into hydraulic energy. Pumps can be divided into three main categories based on how they move the fluid: direct lift, displacement, and gravity pumps.
Pumps use a mechanism to move the fluid (usually a rotary or reciprocating one) and require energy to operate. Pumps exist in a variety of sizes, from microscopic for use in medical applications to enormous industrial pumps, and they can be powered by a variety of energy sources, including electricity, manual operation, engines, or wind power.
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A Person drops a pile of roof shingles from the top of a roof above the ground. If the time taken to reach the ground was 5 seconds, how high is the roof?
Correct answer get BRAINLIEST and please don’t answer if u don’t know
Answer:
The height of the roof is 4 meters high. Is this the measurement that I was supposed to answer with?
Explanation:
Pace left home at 8 AM to spend the day at an amusement park. He arrived at the park, which was 150 km from his house, at 10 AM. Pace explained that his speed was 38 km/h, which was a/an (accelerated / directional / instantaneous / average) speed, but the fastest speed he went was 60 km/h, which was a/an (directional / instantaneous / accelerated / average) speed.
Answer:
average speed, accelerated speed
Explanation:
Pace was first moving at 38 km/h which was his average speed but the fastest speed he went was 60 km/h so he accelerated.
Name any two medium which states about the weather report.
Answer:
1. Government Agencies
2. Television Stations
Explanation:
Weather reports are needed by members of the public to be alert on daily and future weather trends as this would affect how they arrange their affairs. The weather can affect daily movement. For example, when it rains heavily, movement might become limited. Government agencies such as the National Weather Service (NWS), state the weather report.
Television channels like the Cable News Network have programs dedicated to weather reporting. The reporter states what the weather would be like in different cities and the public take note of that.
What can astronomical objects that have changing magnetic fields do
ok byy make me brilliant