At the beginning of the day, the stock market
goes up 30 points. At the end of the day, the
stock market goes down 1201 points. What is
the total change in the stock market from the
beginning of the day to the end of the day?

Answer:

1.2 * 10^3

Step-by-step explanation:

3.12 * 10^8

=========

2.6 * 10^5

Start by doing 3.12 / 1.6 = 1.2 and that is the correct number of sig digs.

Now get the power on the 10. When dividing, the powers subtract.

10^(8 - 5)

10^ 3

The answer is 1.2 * 10^3

To figure out this problem, let's set up an equation first to make it easier:

702.50 = 5.5x + 70

x = amount charged per hour

702.50 = 5.5x + 70

-70                   -70

-----------------------------

632.5 = 5.5x

/5.5       /5.5

--------------------

115   =   x

Owen was charged $115 per hour

Answer:

3

Step-by-step explanation:

the scale is 2 so you need to figure out 3y + 5 = 14

The statement which is true about the function is that the function is negative for all real values of x where x < –3 or x > –1.

A function assigns the value of each element of one set to the other specific element of another set.

The graph of the function is,

\(f(x) = -(x +3)(x - 1)\)

It is positive, its value is above x-axis. For the function above, the solutions are,

\(x+3=0\\x=-3\\x-1=0\\x=1\)

The value of x is lies between,

\(-3 < x < 1\)

Thus, the statement which is true about the function is that the function is negative for all real values of x where x < –3 or x > –1.

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Explanation:

Segment SQ is the result of adding the pieces ST and TQ together

SQ = ST + TQ

SQ = 12.5 + 12.5

SQ = 25

This is the hypotenuse of the right triangle PQS. The diagram shows that the vertical leg of this right triangle is PS = 7.

Use the pythagorean theorem to find the horizontal leg PQ.

a^2 + b^2 = c^2

7^2 + b^2 = 25^2

49 + b^2 = 625

b^2 = 625 - 49

b^2 = 576

b = sqrt(576)

b = 24

Side PQ is 24 inches long.

-----------

We then multiply the length and width of the rectangle to find its area.

area = length*width

area = PS*PQ

area = 7*24

area = 168 square cm

Answer: the answer is 168cm^2 it is correct

Step-by-step explanation:

:)

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of (x-2, y) unit(s) and a across the x-axis.

The coordinates of the triangle are A(8, 8), B(10, 4), C(2, 6), while the triangle A'B'C' is at A'(6, -8), B'(8, -4), C'(0, -6).

If a point O(x, y) is translated a units on the x axis and b units on the y axis, the new coordinate is O'(x+a, y+b).

If a point O(x, y) is reflected across the x axis, the new coordinate is O'(x, -y)

Hence if triangle ABC is translated -2 units on the x axis (2 units left), the new coordinates are A*(6, 8), B*(8, 4), C*(0, 6). If a reflection across the x axis is then done, the new coordinates are A'(6, -8), B'(8, -4), C'(0, -6).

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The proportions of parts produced within specifications by the two shifts at a 4% significance level with the help of an equation.

A formula exists in every equation. Some equations do not have formulae. Equations are designed to be solved for a variable.

(a) To estimate the difference in proportions of parts produced within specifications by the two shifts, we need to calculate the confidence interval.

First, we can calculate the sample proportions of parts produced within specifications for each shift:

For the day shift, the sample proportion is:

p1 = 188/200 = 0.94

p2 = 180/200 = 0.90

p1 - p2 = 0.94 - 0.90 = 0.04

To calculate the confidence interval, we can use the following formula:

(point estimate) ± (critical value) x (standard error)

We will use a 96% confidence level, so our critical value is z* = 2.05 (from the z-table).

The standard error can be calculated as follows:

SE = sqrt((p1*(1-p1)/n1) + (p2*(1-p2)/n2))

where n1 and n2 are the sample sizes.

Substituting in our values, we get:

SE = sqrt((0.94*(1-0.94)/200) + (0.90*(1-0.90)/200))

SE = 0.040

Now we can calculate the confidence interval:

0.04 ± 2.05(0.040)

The confidence interval is (0.003, 0.077).

Therefore, we are 96% confident that the true difference in proportions of parts produced within specifications by the two shifts is between 0.003 and 0.077.

(b) To determine whether the difference in proportions of parts produced within specifications by the two shifts is significantly different from 0, we need to check if 0 is within the confidence interval we calculated.

Since the confidence interval does not include 0, we can conclude that the difference in proportions of parts produced within specifications by the two shifts is significantly different from 0 at a 96% confidence level.

(c) The hypotheses of interest for the significance test are:

H0: p1 - p2 = 0 (There is no difference in proportions of parts produced within specifications by the two shifts)

Ha: p1 - p2 ≠ 0 (There is a difference in proportions of parts produced within specifications by the two shifts)

We will use a significance level of α = 0.04.

To perform the significance test, we need to calculate the test statistic:

z = (p1 - p2 - 0) / SE

where p1, p2, and SE are the same as calculated in part (a).

Substituting in our values, we get:

z = (0.94 - 0.90 - 0) / 0.040

z = 1.00

Using a z-table, we find that the p-value for a two-tailed test with z = 1.00 is approximately 0.317.

Since the p-value is greater than our significance level of 0.04, we fail to reject the null hypothesis.

Therefore, we do not have sufficient evidence to conclude that there is a difference in proportions of parts produced within specifications by the two shifts at a 4% significance level.

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Step-by-step explanation:

10x - 2x = 8x

18x - (7 + 4x) = 18x - 7 - 4x = 14x - 7

= 7(2x - 1)

please pick whatever you think your teacher prefers.

The area of the quarter circle with radius 3ft is \(7.065 ft^2\)

Area of a quarter circle is given by the formula:

\(Area = \frac{\pi r^2}{4}\)

Where r represents the radius of the circle

In the quarter circle shown, the radius, r = 3 feet

π  =  3.14

Substitute π = 3.14 and r = 3 into the formula \(Area = \frac{\pi r^2}{4}\)

\(Area = \frac{3.14 \times 3^2}{4}\\\\Area = \frac{3.14 \times 9}{4}\\\\Area = \frac{28.26}{4}\\\\Area = 7.065 ft^2\)

The area of the quarter circle with radius 3ft is \(7.065 ft^2\)

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Answer:

Insult his favorite anime lol. Works like a charm.

Step-by-step explanation:

Answer:

watch anime with them! and tell them they have taste cause same >_<

Answer:

Step-by-step explanation:

1302 + 1202 = 502

Answer:

1302 + 1202 = 502

Step-by-step explanation:

Cant really explain. 1302 + 1202 = 502

Answer:

I think its a two step

Step-by-step explanation:

welp try your best good luck

Answer:

4 my good sir

Step-by-step explanation:

Answer:

5 foot

Step-by-step explanation:

The percentage change in the index for the period from T to T+1 is 42.85%

Sum of the price of the shares of period T

= 60 + 20 + 18

= 98

Number of shares = 3

For the T period of time = Sum of the price of the shares of period T / Number of shares

Substitute the values in the equation

For the T period of time = 98 / 3

= 32.67

Sum of the price of the shares of period T+1

= 80 + 35 + 25

= 140

Number of shares = 3

For the T+1 period of time = Sum of the price of the shares of period T+1 / Number of shares

Substitute the values in the equation

For the T+1 period of time =  140/ 3

= 46.67

The percentage change = [(46.67 - 32.67) / 32.67] × 100

= (14/32.67)×100

= 42.85 %

Therefore, the percentage change is 42.85%

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The given question is incomplete, the complete question is

You are given the following information regarding prices for a sample of stocks. construct a price-weighted index for these three stocks, and compute the percentage change in the index for the period from t to t 1. do not round intermediate calculations. round your answer to two decimal places.

Answer:

B) 6

Step-by-step explanation:

4^2 = 16

16 - (2+8)

16 - 10

6

Hope this helps! Pls give brainliest!

The total amount by which Todd's biceps will increase in 8 weeks is approximately 29.152 millimeters.

a. To find the rule for the nth term in the sequence representing the amount of muscle increase each week, we can use the given information. The first week's increase is 4 millimeters, and each subsequent week's increase is 90% of the previous week's increase. Therefore, we can establish the rule as follows:

\(a_n = 4 * 0.9^{(n-1)}\)

Where aₙ represents the muscle increase in the nth week.

b. The summation notation using Σ (sigma) for the first 8 terms would be:

= Σ(aₙ) from n = 1 to 8

c. To expand the series and evaluate the amount by which Todd's biceps will increase in 8 weeks, we substitute the values of aₙ from n = 1 to 8 into the summation notation:

= Σ(aₙ) from n = 1 to 8

= a₁ + a₂ + a₃ + a₄ + a₅ + a₆ + a₇ + a₈

Expanding the series using the rule from part a, we have:

\(= 4 * 0.9^{(1-1)} + 4 * 0.9^{(2-1)} + 4 * 0.9^{(3-1)} + 4 * 0.9^{(4-1)} + 4 * 0.9^{(5-1)} + 4 * 0.9^{(6-1)} + 4 * 0.9^{(7-1)} + 4 * 0.9^{(8-1)}\)

\(= 4 + 4 * 0.9 + 4 * 0.9^2 + 4 * 0.9^3 + 4 * 0.9^4 + 4 * 0.9^5 + 4 * 0.9^6 + 4 * 0.9^7\)

Evaluating this expression will give us the total amount by which Todd's biceps will increase in 8 weeks.

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Answer:

\(2.28*10^7\)

Step-by-step explanation:

\((2.4*10^3)(9.5*10^3)=(2.4*9.5)(10^3*10^3)=22.8*10^6=2.28*10^7\)

Answer:

228,000

Step-by-step explanation:

(2.4x10^3) x (9.5x10^3)

(2.4x100) x (9.5x100)

240x950

228,000

Shelly ordered the 16 candy bags.

The operation or process of finding the difference between two numbers or quantities, denoted by a minus sign (−).

We have the information from the question:

Shelly paid a total of $15 for bags of candy she ordered on-line.

The cost of each bag was $0.75

Shipping charge was a flat rate $3.00

We have to find the how many bags of candy did shelly order.

Now, According to the question:

We have to subtract shipping charge from total paid charges, we get:

Total paid - shipping charge

=> 15 - 3

= 12

Number of bags = 12/ 0.75

Number of bags = 16

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Answer:

k = 17

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

k + 10 = 27

Step 2: Solve for k

If one diagonal of a kite is twice as long as the other diagonal and the area of the kite is 240 square inches, then the length of the shorter diagonal is 4√15 inches and the length of the longer diagonal is 8√15 inches.

To find the length of the diagonals, follow these steps:

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Answer:

225

Step-by-step explanation: if you simply multiply 300 by 3 you get 900 and dividing it you get 225 or you can simply divided 300 by 4 and get 75 before multiplying by 3 for 225.

We have: 3 on 4 = 3/4

So: 3 on 4 out of 300 => 3/4 × 300 = 900/4 = 225

Answer: 225

Ok done. Thank to me :>

Answer:

ABC = 37

Step-by-step explanation:

inscribed angle = 1/2 intercepted arc

B = 1/2 ( 74)

B = 37

The expression is zx+x²+2z. The values are x=-4 and z=-6. The expression value we get 28.

Given that,

The expression is zx+x²+2z.

The values are x=-4 and z=-6.

We have to find the expression solution will be.

The expression is zx+x²+2z.

A mathematical expression is a phrase that has a minimum of two numbers or variables and at least one mathematical operation.

=zx+x²+2z

=(-6)(-4)+(-4)²+2(-6)

Square the -4.

=(-6)(-4)+16+2(-6)

Multiply -6 and -4

=24+16+2(-6)

Multiply -6 and 2

=24+16-12

Adding 24 and 16

=40-12

Subtract 40 and 12

=28

Therefore, the expression value we get 28.

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Answer:

The point of intersection of the system of equations is:

(x, y) =  (-2, 1)

The correct system of equations intersect at point A in this graph will be:

\(\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}\)

Thus, the second option is correct.

Step-by-step explanation:

Given the point

Let us check the system of equations to determine whether it intersect at point A in this graph.

Given the system of equations

\(\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}\)

Arrange equation variable for elimination

\(\begin{bmatrix}y-4x=9\\ y+3x=-5\end{bmatrix}\)

so

\(y+3x=-5\)

\(-\)

\(\underline{y-4x=9}\)

\(7x=-14\)

so the system of equations becomes

\(\begin{bmatrix}y-4x=9\\ 7x=-14\end{bmatrix}\)

Solve 7x = -14 for x

\(7x=-14\)

Divide both sides by 7

\(\frac{7x}{7}=\frac{-14}{7}\)

Simplify

\(x = -2\)

For y - 4x = 9 plug in x = 2

\(y-4\left(-2\right)=9\)

\(y+4\cdot \:2=9\)

\(y+8=9\)

Subtract 8 from both sides

\(y+8-8=9-8\)

Simplify

y = 1

Thus, the solution to the system of equations is:

(x, y) = (-2, 1)

From the attached graph, it is also clear that the system of equations intersects at point x = -2, and y = 1.

In other words, the point of intersection of the system of equations is:

(x, y) =  (-2, 1)

Therefore, the correct system of equations intersect at point A in this graph will be:

\(\begin{bmatrix}y=4x+9\\ y=-3x-5\end{bmatrix}\)

Thus, the second option is correct.

Do in completing the square method.

\( {4x}^{2} - 4x + 1 = 0 \\ 4x^{2}-4x=-1 \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4} \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4} \\ x^{2}-x=\frac{-1}{4} \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2} \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4} \\ x^{2}-x+\frac{1}{4}=0 \\ \left(x-\frac{1}{2}\right)^{2}=0 \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0} \)

Now simplify.

\(x-\frac{1}{2}=0 \\ x-\frac{1}{2}=0 \\ \\ \rightarrow \: x=\frac{1}{2} \\ \rightarrow \: x=\frac{1}{2} \)

So, answer is..

\( \boxed{x=\frac{1}{2} }\)

Now rewrite the equation.

\(4 x ^ { 2 } - 4 x + 1 = 0 \\ \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 }\)

Verification :-

\(4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-4\times \left(\frac{1}{2}\right)+1=0 \\ 1-\frac{4}{2}+1=0 \\ 1-2+1=0 \\ -1+1=0 \\ \underline{ 0 = 0} \: \\ \dashrightarrow \text{true}\)

The matching sets for the given orbitals are as follows:

A. 3, 2, -1

C. 5, 1, -1

G. 4, 0, -1

H. 3, 2, 3

In quantum mechanics, each electron in an atom is described by a set of quantum numbers that provide information about its energy level, orbital shape, and orientation. The quantum numbers include the principal quantum number (n), the azimuthal quantum number (l), and the magnetic quantum number (ml).

For the given orbitals, we need to match the orbital names with the sets of quantum numbers. Let's go through each option:

A. The quantum numbers 3, 2, -1 correspond to the orbital name 3dxy. The principal quantum number (n) is 3, the azimuthal quantum number (l) is 2, and the magnetic quantum number (ml) is -1. This describes a d orbital in the xy plane.

C. The quantum numbers 5, 1, -1 correspond to the orbital name 5py. The principal quantum number (n) is 5, the azimuthal quantum number (l) is 1, and the magnetic quantum number (ml) is -1. This describes a p orbital oriented along the y-axis.

G. The quantum numbers 4, 0, -1 correspond to the orbital name 4pz. The principal quantum number (n) is 4, the azimuthal quantum number (l) is 0, and the magnetic quantum number (ml) is -1. This describes a p orbital oriented along the z-axis.

H. The quantum numbers 3, 2, 3 correspond to the orbital name 3dxyz. The principal quantum number (n) is 3, the azimuthal quantum number (l) is 2, and the magnetic quantum number (ml) is 3. This describes a d orbital with complex orientation in space.

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