At t= 0, a particle moving in the xy plane with constant acceleration has a velocity of Vi= (3.00i -2.00j) m/s and is at the origin. At t= 3.00 s, the particle's velocity is V = (9.00i + 7.00j) m/s . Find (a) the acceleration of the particle and (b) its coordinates at any time t.
Answers
Answer:
(a) a = (2i + 4.5j) m/s^2
(b) r = ro + vot + (1/2)at^2
Explanation:
(a) The acceleration of the particle is given by:
\(\vec{a}=\frac{\vec{v}-\vec{v_o}}{t}\\\\\)
vo: initial velocity = (3.00i -2.00j) m/s
v: final velocity = (9.00i + 7.00j) m/s
t = 3s
by replacing the values of the vectors and time you obtain:
\(\vec{a}=\frac{1}{3s}[(9.00-3.00)\hat{i}+(7.00-(-2.00))\hat{j}]\\\\\vec{a}=(2\hat{i}+4.5\hat{j})m/s^2\)
(b) The position vector is given by:
\(\vec{r}=\vec{r_o}+\vec{v_o}t+\frac{1}{2}\vec{a}t^2\)
where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2
Related Questions
a boy pulls his toy on a smooth horizontal surface with a rope inclined at 60° to the horizontal if the effective Force pulling the toy along the horizontal surface is 5-newton calculate the tension in the rope
Answers
Answer:
The tension in the rope is 10 N
Explanation:
The Force Vector
Like all vectors, the force has a magnitude and direction. Vectors can be decomposed into two perpendicular components on both axes.
The tension in the rope (F) can be calculated by using vector decomposition as follows.
The figure included below shows a force F which horizontal component is known to have a value of Fx= 5 Nw. The angle formed by the force and its horizontal component is 60°.
We can use the trigonometric ratio called the cosine to find the magnitude of F as follows:
\(\displaystyle \cos 60^\circ = \frac{5}{F}\)
Solving for F:
\(\displaystyle F = \frac{5}{\cos 60^\circ}\)
\(\displaystyle F = \frac{5}{\frac{1}{2}}\)
Thus, F = 10 N
The tension in the rope is 10 N
What is it called when a sound wave transfers its energy to a new medium?
a. Reflection
b. Transmission
c. Echo
d. Absorption
Answers
Answer:
c. eco
ya que hay trasmisión de energía de un lado al hacer ecos
You and your friend see a ball rolling across the floor to the right. Your friend says
that because it is moving to the right, it must have a net force on it pushing it to
the right. Do you agree with her? Why or why not?
Your answer
Answers
Answer:
unforturnitly
Explanation:
step unstepable
What are the criterions that need for mechanical work?
Answers
Mechanical work is the work done by a force on a mechanical body like machines .
When some mechanical force is applied on the machine the machine does some work which is mechanical work
It's a scaler quantity and have units as Joules(J)
The main criterion is mechanical energy,Force , Displacement (Not mandatory)
A boat crosses a river at 6.65 mph north through a current going 9.87 mph east. What is the resultant velocity of the boat?
Answers
Answer:
V = √ ( 6.65² + 9.87² ) ≈ √ 141.64 = 11.90 mph
Explain how the properties of alpha, beta and gamma radiation affect the level of hazard at different distances.
Answers
Answer:
Radiation can be absorbed by substances in its path. For example, alpha radiation travels only a few centimetres in air, beta radiation travels tens of centimetres in air, and gamma radiation travels very large distances. ... The thicker the substance, the more the radiation is absorbed
Answer:
Radiation can be absorbed by substances in its path. For example, alpha radiation travels only a few centimetres in air, beta radiation travels tens of centimetres in air, and gamma radiation travels very large distances.
How would a neutral and positive ball react to eachother
Answers
Answer:
They would attract one another
Explanation:
The interaction between two like-charged objects is repulsive. ... Positively charged objects and neutral objects attract each other negatively charged objects and neutral objects attract each other.
a hiker of mass 59 kg is going to climb to the top of mount tam, which has an elevation of 2,574 ft.part (a) if the hiker starts climbing at an elevation of 560 ft, what will their change in gravitational potential energy be, in joules, once they reach the top? assume the zero of gravitational potential energy is at sea level.
Answers
457280.13 8 J change in gravitational potential energy is needed.
where
m = 68 kj
H = 2574 ft
where = 32 5 ft
a )if Gravitational potential energy is zero at see level .
then at strating
point,
Equation
G. P . E ( Ui ) = mgh
Change in G PE ;
AU = UJ - Vi
= mgy- mgh = mg ( H-h)
= 68 x9.81 [2574 - 325 0.3048
AU = 457280' 138 Joules
at top
GPE ( Uf ) = mgy
P . E = 0
GPF = Gravitational potential Energy .
at Top ape = 0
b)then change in GPE ;
ΔU = U(top) - Vata
= 0 - [-mg ( 4-h )]
= mg ( H-h j
= 68 * 9 . 81 [ 257 4 - 325 ) 0.3048
ΔU = 45 7280 . 13 8 J.
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FOR CHEMISTRY:
A small package of Reese's Pieces candy contains 234 calories and 12 grams of fat. Assuming the package contains 36 pieces, what is the maximum number of pieces I could eat without exceeding 150 calories?
Answers
The maximum number of 23 pieces a person could eat without exceeding 150 calories.
What are calories?A calorie can be described as unit of energy. The large calorie, food calorie was originally described as the amount of heat required to raise the temperature of 1 Kg of water by one degree Celsius.
The small calorie was defined as the amount of heat required to cause the same increase in one gram of water. In physics and chemistry, the calorie usually refers to a small unit of energy. One calorie is equal to exactly 4.184 Joules.
Given, the 234 calories contained in pieces of candy = 36
Then 150 calories contain by pieces of candy = (36/234) ×150 = 23
Therefore, a maximum number of 23 pieces someone could eat without exceeding 150 calories.
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How long will it take a car to go from a complete stop to 44 km/hr if they are accelerating
at 5m/s²?
Answers
Answer:
Time taken = 2.444sec
Explanation:
Greetings !
Given values :-
Final velocity (Vf) =44km/hr =12.22m/s Initial velocity (Vi) = 0m/sAcceleration (a)= 5m/s²Required values:-
Time taken (t) =?Solution/ work-out:-
Firstly change the km/hr value to m/s
Then, recall the Velocity-Time Equation:
\(vf = vi \: + at\)
substitute known variables into the equation
\((12.22) = (0) + (5)t\)
Solve for time
\(t = 2.444sec\)
Hope it helps!!
I need help with parts ANB of question number two
Answers
Answer:
a.
b.
Explanation:
The change in tire's angular velocity is
\(\Delta\omega=\omega_f-\omega_i\)Now,
\(\begin{gathered} \omega_f=3.9\text{rad}/s \\ \omega_i=-3.9\text{rad}/s \end{gathered}\)Therefore,
\(\Delta\omega=3.9-(-3.9)\)\(\boxed{\Delta\omega=7.8\text{rad}/s\text{.}}\)Part B.
The average angular acceleration is given by
\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}\)Now,
\(\Delta\omega=7.8\text{rad}/s\)and
\(\Delta t=1.85s\)Therefore,
\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}=\frac{7.8}{1.85}\)\(\Rightarrow\boxed{\alpha_{\text{avg}}=4.22\text{rad}/s^2}\)which is our answer!
Why is copper a pure substance? A. Because it is an element B. Because it is a compound C. Because it is a homogenous mixture
Answers
Explanation: usually when they say pure substance they mean pure element.
Hope this helped!! :)
How many words can
you make using the letters in:
Asparagus
Answers
Answer:
You can make 91 words from the letters Asparagus
Explanation:
If you want the know the words are below
Hope this helps!
Sap
Grass
Sugar
Gasp
Aura
Gaps
Spa
Sag
Rap
Gas
Sup
Up
Ups
Raps
Grass
A charged, parallel-plate capacitor is isolated. If the distance separating the plates of the capacitor decreases to half the original distance, what happens to the magnitude of the electric field between the two plates?
Answers
Hi there!
Recall the following:
\(C = \frac{Q}{V}\)
C = Capacitance (F)
Q = Charge (C)
V = Potential difference (V)
The equation for the capacitance of a parallel-plate capacitor:
\(C = \frac{\epsilon_0 A}{d}\)
C = Capacitance (F)
ε₀ = Permittivity of Free Space
A = Area of plates (m²)
d = distance between plates (m)
If the distance is halved, the capacitance will DOUBLE since there is an inverse relationship between capacitance and distance.
Thus, something has to change in regards to the charge or voltage for it to match the doubled capacitance.
Since the capacitor is ISOLATED, it is not connected to a battery, so the voltage is NOT maintained constant. The VOLTAGE will consequentially be changed, while the electric field will be unchanged.
Recall the equation for potential difference:
\(V = Ed\)
If the distance is halved, the voltage will be halved. This is mirrored by the doubled capacitance. Thus, the electric field will remain the SAME.
One of the major differences between our common Physics models of energy change and realistic models of them is
In the Physics models, the acceleration due to gravity is rounded to a non-exact but easier to use number
In the Physics models, the velocities are only calculated at set intervals of time, instead of continuously
In the Physics models, the objects are assumed to have simplified shapes in order to make motion by acceleration easier to calculate
In the Physics models, we do not take into account the energy change by the friction of moving components
Answers
Answer: In the Physics models, we do not take into account the energy change by the friction of moving components
Explanation:
the letter R in the world Warm reminds you that warm air does what
Answers
A rectangular loop of wire that can rotate about an axis through its center is placed between the poles of a magnet in a magnetic field with a strength of 0.40 T. The length of the loop L is 0.16 m and its width w is 0.040 m. What is the magnetic flux through the loop when the plane of the loop is perpendicular to the magnetic field?
Answers
Explanation:
hope this helps you...........
The magnetic flux through the loop when the plane of the loop is perpendicular to the magnetic field is 0.0256 Weber.
What is magnetic field?The magnetic field is the region of space where a charged object experiences magnetic force when it is moving.
The formula for magnetic flux is given as;
φ = BAcosθ
Given, a rectangular loop of wire that can rotate about an axis through its center is placed between the poles of a magnet in a magnetic field with a strength of 0.40 T. The length of the loop L is 0.16 m and its width w is 0.040 m.
Area of the loop = L x w
A = 0.16 x 0.040 m
A = 0.0064 m²
So, flux will be
φ = 0.4 x 0.0064 x cos90°
φ = 0.00256 Wb
Thus, magnetic flux through the loop when the plane of the loop is perpendicular to the magnetic field is 0.0256 Weber.
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Which of the following is a layer of the solid Earth? A. convecting mantle B. Ring of Fire C. biosphere D. atmosphere
Answers
Answer:
It's a cause that's the last layer
Answer:
I believe the answer is A
Explanation:
It is not the ring of fire because the ring of fire is the result of tectonic plates moving. It is not the biosphere because biosphere is the regions of the surface. The convecting mantle is the solid layer of the Earth because the mantle is mostly solid. The atmosphere is a solid plastic layer of the Earth. I hope this helps.
A car travels a distance of 100km in 2 hours. What is the average speed of the car (kn/h) ?
Answers
Answer:
50 km/h
Explanation:
100km/2hours = 50 km/h
A plane is flying horizontally with speed 171 m/s at a height 6520 m above the ground, when a package is dropped from the plane. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, when the package hits the ground, the plane will be 1. directly above the package. 2. ahead of the package. 3. behind the package.
Answers
Answer:
2. Ahead of the package
Explanation:
The plane is going straight without stopping while the package is going straight down.
As the wavelength of a wave gets shorter the frequency does what?
Answers
Answer:
It gets higher
Explanation:
The shorter it is, the higher the frequency.
Observa a tu alrededor y escribe el nombre de diez objetos que se encuentren en movimiento, Luego escribe el de otros diez que pienses que se encuentran en reposo. ¿Qué criterio tuviste en cuenta para considerar que están en reposo?
Answers
Answer:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
Explanation:
Objetos que se encuentran en movimiento:
1) Un automóvil pasando por la calle.
2) Una crustácea que se acerca a mi casa.
3) Un avión volando en el cielo.
4) Un repartidor de comida desplazándose en una bicicleta.
5) Las aspas del ventilador en rotación.
6) Una hojarasca afuera de la casa.
7) La puerta de mi habitación abrirse.
8) Un mosquito entrando por la ventana.
9) Un metrónomo en movimiento.
10) Las hojas de mi cuaderno siendo agitadas por la brisa impulsada por el ventilador.
Objetos que se encuentran en reposo:
1) El semáforo de la esquina.
2) El automóvil de mi madre.
3) Las sillas del comedor.
4) Un jarrón de porcelana.
5) La nevera de la cocina.
6) La mesa de noche de mi habitación.
7) El automóvil de policía en la calle.
8) La impresora de memes.
9) El estante de libros.
10) El cesto de galletas.
Un objeto está en reposo si y solo si la posición de todos sus puntos no ha cambiado con respecto a la posición inicial en el tiempo. Los cambios de posición se manifiestan mediante tres formas:
(i) Traslación.
(ii) Rotación.
(iii) Deformación.
Angela drives on a county highway for 2 hours. She travels 112 miles during this time. She averages 22mph faster on this drive than she does in the city traffic. What is her average speed in the city?
Answers
Angela's average speed in the city traffic is 34 mph.
We are given that Angela drives on a county highway for 2 hours and travels 112 miles during this time. To find her average speed in the city traffic, we need to determine her speed on the county highway.
Let's assume her average speed in the city traffic is x mph. According to the problem, she averages 22 mph faster on the county highway than in the city traffic. Therefore, her speed on the county highway is (x + 22) mph.
We can use the formula for average speed, which is distance divided by time, to set up an equation:
Average speed = Total distance / Total time
For the county highway portion, we have:
(x + 22) mph = 112 miles / 2 hours
Simplifying the equation, we get:
x + 22 = 56
x = 56 - 22
x = 34
Hence, Angela's average speed in the city traffic is 34 mph.
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If 80,000 Joules of heat is absorbed by 210 grams of ice at 0°C, what happens to the ice?
It partially melts and stays at 0°C
It completely melts but stays at 0°C
It completely melts and has a final temperature of 11.2°C
It completely melts and has a final temperature of 22.4°C
It completely melts and has a final temperature of 33.6°C
Answers
Answer:
It completely melts and has a final temperature of 22.4°C
Explanation:
(I am very bad at explaining, I am not a teacher, I am a student but I had exact same question on my test so I wanted to help.)
Okay, well to find the Heat required to melt Ice, we have to use the equation:
Q=(m·cΔT)+(m·hf)
Q= HeatM= MassC= Specific heatΔT= Change in temperature. hf= heat fusionSo we can just plug in the values into the equation and see which one adds up too 80,000. (there is probably a better way i just did it this way)
For this situation, we know that:
Mass=210 gramsSpecific heat = 2.10 (I got this number 2.10 from the internet. The universal number for specific heat of ice is 2.10 J/g°C ) Change in temperature= 0 °C or 11.2 °C or 22.4 °C or 33.6 °C (all the answers) Heat fusion=334 (universal number for heat fusion of melting ice is 334)So we can just change the value of change and temperature and see which one equals 80,000.( I will bold the value of change in temperature.)
Q=(m·cΔT)+(m·hf)
(210g)*(2.10)*(0)+(210)*(334)=70140(210g)*(2.10)*(11.2)+(210)*(334)=75079.2(210g)*(2.10)*(22.4)+(210)*(334)=80018.4(210g)*(2.10)*(33.6)+(210)*(334)=84957.6So which one equals 80,000? Equation #3 with the temperature at 22.4 °C
So the answer would be It completely melts and has a final temperature of 22.4°C.
Hope this makes sense, again I am not a teacher I am so bad at explaining, but I did my best. ;)
A parallel-plate capacitor with circular plates of radius R is being discharged. The displacement current through a central circular area, parallel to the plates and with radius R/2, is 2.7 A. What is the discharging current
Answers
The discharging current of a parallel-plate capacitor with circular plates of radius R is 10.8 A.
In a parallel-plate capacitor, the displacement current is given by the formula:
Id = ε₀ * A * (dV/dt)
Where Id is the displacement current, ε₀ is the permittivity of free space, A is the area of the circular region, and (dV/dt) is the rate of change of voltage with respect to time.
In this case, the displacement current through the central circular area with radius R/2 is given as 2.7 A.
To find the discharging current, we need to consider the relationship between the displacement current and the total current flowing through the capacitor during discharge. The displacement current is related to the conduction current (i.e., the discharging current) by the equation:
Id = Ic * (A₁/A)
Where Ic is the conduction current, A₁ is the area of the circular region through which the displacement current is measured, and A is the total area of the plates.
Since the central circular area has a radius of R/2, its area A₁ can be calculated as π * \((R/2)^2\) = π * R²/4.
Now we can solve the discharging current Ic:
2.7 A = Ic * (π * R²/4) / (π * R²)
Simplifying the equation, we find:
2.7 A = Ic * (1/4)
Therefore, the discharging current Ic is:
Ic = 2.7 A * 4 = 10.8 A.
Thus, the discharging current of the parallel-plate capacitor is 10.8 A.
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Which statement accurately describes electronic tools? Check all that apply
Answers
Answer:
Electronic tools provide more accurate data and this data is more efficient fast and easy to understand
Hope this helps you!!
It is possible for a fault to have a N-S strike and an East dip False True
Answers
True, it is possible for a fault to have a north-south (N-S) strike and an eastward dip.
Faults can have various orientations and dips depending on the tectonic forces and geological conditions in a particular region. The strike refers to the direction of the fault line on the Earth's surface, while the dip indicates the angle at which the fault plane is inclined from the horizontal. Therefore, a fault can have any combination of strike and dip, including an N-S strike and an eastward dip.
Faults are geological fractures where movement has occurred, and their orientations can vary. A fault with a north-south (N-S) strike means it extends in that direction horizontally. The dip refers to the angle of the fault plane from the horizontal. So, it is possible for a fault to have an N-S strike and an eastward dip.
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Which two laws were discovered by Antoine Lavoisier and Joseph Proust
Answers
Answer:
Joseph proust's law of difinite composition
Law of conservation of mass
Explanation:
Dalton's law of multiple proportions is part of the basis for modern atomic theory, along with Joseph Proust's law of definite composition (which states that compounds are formed by defined mass ratios of reacting elements) and the law of conservation of mass that was proposed by Antoine Lavoisier.
Answer:
law of conservation of mass
law of definite proportions
Explanation:
What is the force on a 1025 kg elevator that is falling freely at 9.8 m/sec 2?
Answers
Answer:
Given :-Mass = 1025 kgAcceleration = 9.8 m/s²To Find :-Force
Solution :-We know that
F = mg
F = 1025 × 9.8
F = 10,045 N
Or,
10045/1000 = 10.045 Kilo Newton
\( \\ \)
please help will give 5 points to the best brainlist 30 points
1. A plank balance with outside support has a 30 kg child 3 meters left of the fulcrum and a 45 kg child 2 meters RIGHt of the fulcrum what will happen when the outside support is removed?
A. The right side of the plank will sink
B. Range is not enough info
C.The left side of the plank will sink
D.The plank will be balanced
2. A simple plank balance has a 500 gram weight 50 cm right of the fulcrum where should you place a 200 gram weight to balance it
A. 250 cm left of the fulcrum
B. 100cm left of the fulcrum
C.125 cm left of the fulcrum
D. 20 cm left of the fulcrum
3. A simple plank balance is used to weigh a mystery box when the bod is placed 5 marks left of the fulcrum it is balanced by a 10 kg weight placed 4 marks right of the fulcrum
What is the mass of the mystery box?
A. 10 kg
B. 16 kg
C. 12.5 kg
D. 8 kg
Answers
Based on the principle of moments, the correct options are:
1. If the outside support is removed, the plank will be balanced; option D
2. To balance the simple plank balance, place the 200 gram weight 125 cm left of the fulcrum; option C
3. the mass of the mystery box is 8 kg; option D
What is the principle of moments?The principle of moments is the principle that describes the turning effect produced by forces.
The principle of moments states that for a system of balanced forces, the sum of the clockwise moment about a point equals the sum of the anticlockwise moment about the same point.
The formula for calculating moments about a poit is given below:
Moment = force x perpendicular distance from the fulcrumConsidering the given questions:
1. Assuming the fulcrum is the balance point of the plank balance.
Taking left as anticlockwise and right as clockwise motion
Anticlockwise moment = 30 * 3
Anticlockwise moment = 90
Clockwise moment = 45 * 2
Anticlockwise moment = 90
Therefore, the plank balance is balanced.
2. Assuming the fulcrum is the balance point of the plank balance.
Taking left as anticlockwise and right as clockwise motion
Clockwise moment = 500 * 50
Anticlockwise moment = 25000
Anticlockwise moment = 200 * d
Anticlockwise moment = 200d
200d = 25000
d = 125 cm to the left of the fulcrum
3. Assuming the fulcrum is the balance point of the plank balance.
Taking left as anticlockwise and right as clockwise motion
Clockwise moment = 10 * 4
Anticlockwise moment = 40
let the mass be m
Anticlockwise moment = m * 5
Anticlockwise moment = 5m
5m = 40
m = 8 kg
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