At last week's track meet, Stacy ran 9/12 of a km, Jules ran 4/5 of a km, and Raul ran 3/4 of a mile. Which two students ran the same distance?

C. The probability of the type I error best defines the notion of the significance position of a thesis test.

The significance position, denoted by alpha( α), is the probability of rejecting the null thesis(H_o) when it's actually true. This is also known as a type I error, which occurs when we inaptly reject a true null thesis.

Option a isn't correct because the probability of rejecting H_o, whether it's true or not, isn't fixed and depends on the sample and the chosen significance position.

Option b isn't correct because it describes the p- value, which is a affiliated conception but not the significance position. The p- value is the probability of observing a sample statistic as extreme or more extreme than the one actually attained, assuming the null thesis is true.

Option d is also not correct because it describes the probability of a type II error, which occurs when we fail to reject a false null thesis. The probability of a type II error is denoted by beta( β) and is told by factors similar as sample size and effect size.

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9514 1404 393

Answer:

  a) 123.4°

  b) 3.3 km

Step-by-step explanation:

In (N, E) coordinates, Boat 1 is located relative to the lighthouse at ...

  2(cos(60°), sin(60°)) = (1.0, 1.732) . . . . . km

Boat 2 is located at ...

  3(cost(340°), sin(340°)) = (2.819, -1.026) . . . . . km

So, relative to Boat 2, Boat 1 is located at ...

  (1, 1.732) -(2.819, -1.026) = (-1.819, 2.758) . . . . . km

This is at a bearing of ...

  arctan(2.758/-1.819) = 123.4°

and a distance of ...

  √(1.819² +2.758²) ≈ 3.304 . . . . . km

a) Boat 2 would need to travel on a bearing of 123.4°.

b) Boat 2 would need to travel 3.3 km.

_____

Additional comment

We use (North, East) coordinates so we don't have to do the mental gyrations necessary to translate to and from (E, N) coordinates. The latter would correctly orient a map relative to the X-Y Cartesian plane. The former are equivalent to flipping the map over and looking at it from the back side. This is a "rigid transformation", so angles and distances remain unchanged.

The measurement that is closest to the value of x, in centimeters, is given as follows:

14.3.

In this problem, we have a right triangle, in which the legs, which are the sides between the angle of 90º, are of 11.9 cm and 7.9 cm.

Then the hypotenuse x, which is the segment connecting both legs, is obtained using the Pythagorean Theorem.

The Pythagorean Theorem states that the measure of the hypotenuse squared is equals to the sum of the squares of the measures of each side.

Then the length of x is calculated as follows:

x² = 11.9² + 7.9²

x = square root of (11.9² + 7.9²)

x = 14.28.

Closest to 14.3, rounding to the nearest tenth, meaning that the third option is correct.  

We suppose that 11.9 cm and 7.9 cm are the measures of the legs.

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The probability that the satellite system operates adequately is 0.7056.

The probability that a component is not functional is 0.4. Therefore, the probability that a component is functional is 1-0.4=0.6.
Using the rule of combinations, there are 6 possible combinations of functional and non-functional components:
1. All 4 components are functional: (0.6)^4=0.1296
2. 3 components are functional: (0.6)^3(0.4)=0.3456
3. 2 components are functional: (0.6)^2(0.4)^2=0.2304
4. 1 component is functional: (0.6)(0.4)^3=0.0256
5. No components are functional: (0.4)^4=0.0256
6. At least 2 components are functional: P(2 or 3 or 4) = 0.1296 + 0.3456 + 0.2304 = 0.7056
Therefore, the probability that the satellite system operates adequately is 0.7056.

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Answer:

x=5

Step-by-step explanation:

     May I have brainiest I'm trying to level up!

                 </3 PureBeauty

Answer:

x=5

Step-by-step explanation:

6x-3 = 3x +12

+3            +3

6x = 3x +15

-3x   -3x

3x = 15

divided both sides by 3 to get your answer

The principal advantage of the Dodge-Romig tables is their simplicity. Therefore, the correct answer is D. simplicity.

The Dodge-Romig tables are statistical sampling tables used in quality control to determine the acceptance or rejection

of a production lot based on sample size and the number of defects found in the sample.

The principal advantage of the Dodge-Romig tables is their simplicity.

They provide a quick and easy method for determining the acceptability of a production lot, without the need for

extensive calculations or statistical knowledge.

This means that they can be used by personnel with limited training in quality control.

The principal advantage of the Dodge-Romig tables is their simplicity. While they can be used for receiving inspection,

their main benefit is in minimizing inspection time and effort by providing clear guidelines for lot sampling and

acceptance based on size and level of defects.

Additionally, their use can facilitate smaller lot sizes and more efficient quality control processes.

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Answer:

$43.24

Step-by-step explanation:

× + .2x = 51.89

1.2x = 51.89

x=51.89÷1.2

x=43.24

43.24 orig

51.89 total

Answer:

680

Step-by-step explanation:

Use the binomial coefficient where you choose \(k=3\) numbers out of \(n=17\) possible numbers and find the total amount of combinations since order does not matter:

\(\displaystyle \binom{n}{k}=\frac{n!}{k!(n-k)!}\\ \\\binom{17}{3}=\frac{17!}{3!(17-3)!}\\\\\binom{17}{3}=\frac{17!}{3!(14)!}\\\\\binom{17}{3}=\frac{17*16*15}{3*2*1}\\\\\binom{17}{3}=680\)

Thus, you can make 680 three-non-repeating-number codes

The factorized expressions is 3(x-4)(x-5).

We are given that;

The expression 3x² - 27x+60​

Now,

1.1.1 After simplification

-3(2x - 4y)² = -12(x-y)²

1.1.2 x+2/3*5x+1

= (3x+5)/(3x+3)

1.2.1 ny + 4z + 4y + nz

= (n+4)(y+z)

1.2.2 3x² - 27x+60

= 3(x-4)(x-5)

Therefore, by the expression the answer will be 3(x-4)(x-5).

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The total pieces at the fruit stand is 60.

Let the number of apples, bananas and oranges sold be 3x, 2x and 1x. We have actual number of bananas. So equating them to find the value of x.

2x = 20

x = 20/2

Performing division

x = 10

So, number of apples = 3x

Number of apples = 3×10

Number of apples = 30

Similarly, number of oranges = 10

Total number of fruits = sum of the number of apples, bananas and oranges

Total number of fruits = 30 + 20 + 10

Total number of fruits = 60

Thus, there are 60 fruits to sell.

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Answer:

Graph 1- No, Graph 2- No, Graph 3- Yes, Graph 4- Yes, Graph 5- No, Graph 6- No

(9.)  The equation is true for all integer n and for any real number x.

(10.) The 3⁴ is greater than n³ when n is greater than or equal to 4.

9. We can solve this by expanding the left side of the equation by using the formula for the sum of a geometric series.

\(\[\large(1-x)\left(1+x^{1}+x^{2}+\ldots+x^{n}\right)=1-x^{n+1}\]\[\large1-x^{n+1}-(x-x^{2}+x^{2}-x^{3}+\ldots+x^{n}-x^{n+1})=1-x^{n+1}\]\)

The first and last terms on the right cancel out leaving us with

\(\[\large-x^{n+1}+(x-x^{2}+x^{2}-x^{3}+\ldots+x^{n}-x^{n+1})=0\]\)

The x terms also cancel out.

\(\[\large-x^{n+1}=-x^{n+1}\]\)

This is true for all integer n and for any real number x.

Therefore, the equation is true for all integer and for real numbers.

10. Let's test n = 4.

\(\[\large3^{4}=81 \space\)

and

\(\space 4^{3}=64\)

Hence 81 is greater than 64,

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Using the center-of-gravity technique, the best site location for the new distribution center in Charlotte is determined to be at coordinates (X, Y) = (27.92, 19.08).

The center-of-gravity technique is used to find the optimal location for a facility based on the distribution of demand. In this case, we will calculate the weighted average of the coordinates (X, Y) of the three sites, with the weights being the number of weekly packages flowing to each site.

To calculate the X-coordinate of the center of gravity, we use the formula:

Xc = (X1 * W1 + X2 * W2 + X3 * W3) / (W1 + W2 + W3)

Similarly, for the Y-coordinate:

Yc = (Y1 * W1 + Y2 * W2 + Y3 * W3) / (W1 + W2 + W3)

Substituting the given values:

Xc = (16 * 26000 + 35 * 12000 + 40 * 10000) / (26000 + 12000 + 10000) ≈ 27.92

Yc = (28 * 26000 + 10 * 12000 + 18 * 10000) / (26000 + 12000 + 10000) ≈ 19.08

Therefore, the best site location for the new distribution center in Charlotte is approximately at coordinates (X, Y) = (27.92, 19.08) based on the center-of-gravity technique.

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Answer:

270

Step-by-step explanation:

Since you have the value of x as 90

3x=3*90

3x=270

-14 is the value of the expression b - 3a at a =6 and b = 4.

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Given an expression b - 3a

For this expression given,

a = 6 and b = 4

Thus the value of expression at given values

=> b - 3a

=> 4 - 3 * 6

=>4 - 18

=> -14

Therefore, the value of the expression b - 3a at a =6 and b = 4 is -14.

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The probability of selecting the correct 6 numbers in the order in which they are selected ≈ 1.22 × 10^-10

The probability of winning in the state lottery if the rules are changed so that you must get the correct 6 numbers in the order in which they are selected can be determined by using the formula for the probability of a specific sequence of events.

The formula for the probability of a specific sequence of events is given as:

P(E1 and E2 and ... and En) = P(E1) × P(E2|E1) × P(E3|E1 and E2) × ... × P(En|E1 and E2 and ... and En−1)

Where E1, E2, ..., En are the events that make up the sequence of events.

The probability of selecting the correct number in the first attempt is given as:1/54

The probability of selecting the correct number in the second attempt is given as:1/53

The probability of selecting the correct number in the third attempt is given as:1/52

The probability of selecting the correct number in the fourth attempt is given as:1/51

The probability of selecting the correct number in the fifth attempt is given as:1/50

The probability of selecting the correct number in the sixth attempt is given as:1/49

Therefore, the probability of selecting the correct 6 numbers in the order in which they are selected is:

P = (1/54) × (1/53) × (1/52) × (1/51) × (1/50) × (1/49)

≈ 1.22 × 10^-10

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Step-by-step explanation:

Her brother has 85 * x stickers.

The confidence level of the interval, extending from 0.399 to 0.501, is 95% with a 5% chance of not containing the true population proportion.

A confidence interval is a range of values that is likely to contain the true population parameter. In this case, the population proportion represents the proportion of marketing students who rated resume inflation as unethical. The interval provided, extending from 0.399 to 0.501, is a 95% confidence interval.

A 95% confidence interval means that if we were to repeat the sampling process multiple times and compute confidence intervals each time, approximately 95% of those intervals would contain the true population proportion. It provides a measure of our confidence in the estimate based on the sample data.

The confidence level is determined by the choice of significance level (alpha), which is typically set at 0.05 (or 5%). This means that there is a 5% chance that the interval does not contain the true population proportion. Therefore, the remaining 95% represents our confidence level.

In summary, the confidence level of the given interval is 95%, indicating that we are 95% confident that the true population proportion of marketing students who find resume inflation unethical falls within the range of 0.399 to 0.501.

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Answer:

205

Step-by-step explanation:

30×7-10+5 = 210-10+5

= 200+5

= 205

Answer:

Use the PEMDAS method. it helps alot

Answer:

this can be the answer

because in given question there is no relation between equations

7/10 of one can; since 7 is less than 10 it would only be a fraction of the can.

( hope this helps! x )

:>

Answer:

Step-by-step explanation:

yeah

Given:

Initial distance is, x=5 feet.

Final distance is, y=15 yards.

The objective is to find the number of times the target has bee set up farther away.

To find the scale factor of new target, convert the final distance into yards.

To find the scale factor consider the multiples as x.

Then,

Hence, the new target is 9 times farther away than old target.

Answer:

θ ≈ 7.43°

Step-by-step explanation:

Given

tan θ = \(\frac{15}{115}\) , then

θ = \(tan^{-1}\) ( \(\frac{15}{115}\) ) ≈ 7.43° ( to 2 dec. places )

Answer: 13512

100332

Step-by-step explanation:

The shortest time for her run is approximately 36 minutes and the longest time is approximately 67 minutes.

To represent Kenzie's situation, we can use an absolute value equation. Let x represent the length of her run in miles.

The equation would then be |x - 6| ≤ 1, which means the distance between x and 6 is less than or equal to 1.

To find the shortest or longest amount of time for Kenzie's run, we need to consider the speed.

The time can be found by dividing the distance by the speed, so the minimum time would be (6 - 1)/6.25 hours,

which is approximately 0.6 hours or 36 minutes.

The maximum time would be (6 + 1)/6.25 hours,

which is approximately 1.12 hours or 67 minutes.

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If the average annual stock return is 11. 3%, the average holds a portfolio of $8600 worth 30 years.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

The usage of percentages is widespread and diverse. For instance, numerous data in the media, bank interest rates, retail discounts, and inflation rates are all reported as percentages. For comprehending the financial elements of daily life, percentages are crucial.

It is given that, the average annual stock return is 11. 3% and you begin your investment portfolio with $2,000,

Suppose the amount he earns in one year is x,

x=  11. 3%. of $2,000

x=220

The portfolio be worth 30 years if the average holds are,

=220 × 30

=$ 6600

The net cost is the sum of the return and the initial investment,

=$ 6600 + $ 2000

=$8600

Thus, if the average annual stock return is 11. 3%, the average holds a portfolio of $8600 worth 30 years.

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