I apologize, but I am having difficulty understanding your question. Can you please provide more information or clarify the terms and calculations you are requesting. Here's a step-by-step explanation to find a formula for the balance after each month:
1. Start with the initial balance on your MasterCard: $6,000.
2. Each month, you make a minimum payment (let's call it 'P') of the balance.
3. After making the payment, the remaining balance will be Balance - Payment = 6000 - P.
4. Assuming no additional charges and an interest rate (let's call it 'i'), we can calculate the new balance after interest is added.
5. New balance = (Remaining balance) * (1 + i) = (6000 - P) * (1 + i).
6. To find the balance after each month, replace 'n' in the formulation with the number of months that passed.
The formula for the balance after 'n' months would be: (6000 - P) * (1 + i)^n.
Please note that you will need to know the minimum payment percentage ('P') and the interest rate ('i') to calculate the exact balance.
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given f ( x ) = x 2 5 x , find the average rate of change of f ( x ) on the interval [ − 2 , − 2 h ] . your answer will be an expression involving h .
To find the average rate of change of f(x) on the interval [-2, -2h], we need to first find f(-2) and f(-2h) and then use the formula for average rate of change, which is (f(-2h) - f(-2))/(-2h - (-2)).This is the expression for the average rate of change of f(x) on the interval [-2, -2 + h].
Let's start by finding f(-2) and f(-2h):
f(-2) = (-2)^2 + 5(-2) = 4 - 10 = -6
f(-2h) = (-2h)^2 + 5(-2h) = 4h^2 - 10h
Now we can plug these values into the formula for average rate of change:
(f(-2h) - f(-2))/(-2h - (-2)) = [(4h^2 - 10h) - (-6)]/(-2h + 2) = (4h^2 - 10h + 6)/(2 - 2h)
So the expression for the average rate of change of f(x) on the interval [-2, -2h] is (4h^2 - 10h + 6)/(2 - 2h).
Now, we'll substitute these values into the formula:
Average Rate of Change = ((-2 + h)^2 - 5(-2 + h) - ((-2)^2 - 5(-2))) / h
Simplify the expression:
Average Rate of Change = (4 - 4h + h^2 + 10 - 5h - 4 + 10) / h
Combine like terms:
Average Rate of Change = (h^2 - 9h + 20) / h
This is the expression for the average rate of change of f(x) on the interval [-2, -2 + h].
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PLZZ HELP NOWW!!! so im doing algebra and we are doing adding and subracting polynomials and i really need help and there are 3 questions.
Answer:
where are the questions??
Step-by-step explanation:
___Another word for a fraction. pick one of these: Absolute Value Distributive Property Equation Evaluate Equivalent Simplify Expression Integers Like Terms Inequality Reciprocal Coefficient Variable Solution Ratio
if your gross pay was $365 and your net pay was $313.90 what percent of your pay went towards deductions
i dont understand
help please!!!
Step 3: Equations and Inequalities Unit Test
6. Solve for j.
j - 18 = 43
Answer:
j = 61
Step-by-step explanation:
j - 18 = 61
Step One: Add your addend and your total together.
18 + 43 = 61
Step Two/Check: Subtract your original total with one of your original addend to get the second original addend you had before.
61 - 18 = 43
Answer:
j = 61
How does composite area help determine the surface area of a three dimensional figure?
61) A small airplane used 342 gallons on fuel on a
4½ hour trip. How many gallons of fuel were
used for each hour?
A) 1563 gal
155 gal
C)
B) 7-1338
18 gal
5
D) 7-9
19 gal
76 gallons of fuel was used for one hour
A small airplane used 342 gallons of fuel on a trip
The time of the trip is 4 1/2 hours= 4.5 hours
The number of gallons used for the trip in one hour can be calculated as follows
342= 4.5
x= 1
Cross multiply both sides
4.5x= 342
Divide both sides by the coefficient of x which is 4.5
4.5x/4.5= 342/4.5
x= 76
Hence 76 gallons was used for one hour of the trip
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use simpson's rule with n=4 to approximate the solution to part b at x=0.5 to three decimal places.
Using the value of ∫01x3+1dx obtained above, we can approximate the value of∫0.50x3+1dx as:Simpson's Rule ∫abf(x)dx≈b−a3n[f(a)+2∑i=12n−1f(ai)+4∑i=14n−1f(xi)+f(b)]≈15[0+2{(13)3+1}+4{(14)3+1}+13+3]≈0.7828Therefore, the solution to part b at x=0.5 to three decimal places is approximately equal to 0.7828.
The solution to part b at x
=0.5 to three decimal places using Simpson's Rule with n
=4 is given as follows:Approximate the value of∫01x3+1dx, with Simpson's Rule using n
=4 subintervals.Simpson's Rule formula for integrating a function, f(x), with n subintervals is given as:Simpson's Rule ∫abf(x)dx≈b−a3n[f(a)+2∑i
=12n−1f(ai)+4∑i
=14n−1f(xi)+f(b)]where h
=(b−a)n and xi
=a+ih for i
=1,2,3,...,n.Substituting a
=0, b=1, f(x)
=x3+1, and n
=4 in Simpson's Rule formula:∫01x3+1dx≈14[0+2{(13)3+1+(23)3+1}+4{(14)3+1+(34)3+1}+13+3]≈1.1354The value of ∫01x3+1dx is approximately equal to 1.1354, using Simpson's Rule with n
=4 subintervals. We want to approximate the solution to part b at x
=0.5 to three decimal places. Using the value of ∫01x3+1dx obtained above, we can approximate the value of∫0.50x3+1dx as:Simpson's Rule ∫abf(x)dx≈b−a3n[f(a)+2∑i
=12n−1f(ai)+4∑i
=14n−1f(xi)+f(b)]≈15[0+2{(13)3+1}+4{(14)3+1}+13+3]≈0.7828Therefore, the solution to part b at x
=0.5 to three decimal places is approximately equal to 0.7828.
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(1. ) I joking am
(2. ) U that read wrong
(3. ) U read that wrong too
(4. ) You checked
(5. ) U smiled
(7) Ur wondering why your still this reading this
(8. ) You saw that mistake (right on 7)
(10. ) But did u see i skipped 6
(10. ) but u checked
(11. ) and saw you that i doubled 10 and skipped 9
(12. ) And said saw you not u saw
(13. ) I also skipped 2
(14. ) U got tricked
(15. ) Im just wasting ur time carry on reading the maths questions
Answer
the triangle has an angle of 77°
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The second column is labeled f of x with entries 15, 0, 3, 0, negative 3, 0, 15.
Predict which statements are true about the intervals of the continuous function. Check all that apply.
f(x) > 0 over the interval (−, 3).
f(x) ≤ 0 over the interval [0, 2].
f(x) < 0 over the interval (−1, 1).
f(x) > 0 over the interval (–2, 0).
f(x) ≥ 0 over the interval [2, ).
The true statements about the function are:
f(x) ≤ 0 over the interval [0, 2].f(x)>0 over the interval (-2,0)f(x) ≥ 0 over the interval [2,∞)How to determine the true statement?The table of values is given as:
x f(x)
-3 -15
-2 0
-1 3
0 0
1 -3
2 0
3 15
From the table, the function values do not exceed 0 at the interval 0 to 2.
This means that f(x) ≤ 0 over the interval [0, 2].
Also from the table, the function values exceeds 0 at the intervals greater than -2 but less than 0
This means that f(x)>0 over the interval (-2,0)
Also from the table, the function values are at least 0 at the intervals greater than 2
This means that f(x) ≥ 0 over the interval [2,∞)
Hence, the true statements are (b), (d) and (e)
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Answer:
The answers are B, C, and D
Step-by-step explanation:
Edge 2023
A motel clerk counts his $1 and $10 bills at the end of the day. He finds that he has a total of 55 bills having a combined monetary value of $163. Find the number of bills of each denomination that he has.
Answer:
43 dollar bills and 12 ten dollar bills
Step-by-step explanation:
let x = number of $1
y = number of $10
x + 10y = 163
x+y = 55
x = 55 - y
x + 10y = 163
(55-y) + 10y =163
55 - y + 10y = 163
9y = 163 - 55
9y = 108
y = 12
x = 55 - 12
x = 43
T/F: a frequency polygon is a very useful graphic technique when comparing two or more distributions.
The statement ''A frequency polygon is a very useful graphic technique when comparing two or more distributions'' is true because a frequency polygon is a very useful graphic technique for comparing two or more distributions.
A frequency polygon is a line graph that shows the distribution of a dataset.
It is created by plotting the frequency of each data value or interval on the y-axis and the corresponding values or intervals on the x-axis, and then connecting the points with line segments.
By using frequency polygons, it becomes easy to compare the shapes and spread of two or more distributions. We can overlay different frequency polygons on the same graph and compare them.
This helps to identify similarities and differences between the data sets.
For instance, frequency polygons can help identify which data set has a higher mean or median, and which distribution has a greater variance.
In summary, frequency polygons are a useful visual tool for comparing distributions and identifying patterns in data.
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What is the domain? I need help on this problem
The domain of the function \(f(x) = \sqrt{\frac{1}{3}x + 2\) is (d) x ≥ -6
How to determine the domain of the functionFrom the question, we have the following parameters that can be used in our computation:
\(f(x) = \sqrt{\frac{1}{3}x + 2\)
Set the radicand greater than or equal to 0
So, we have
1/3x + 2 ≥ 0
Next, we have
1/3x ≥ -2
So, we have
x ≥ -6
Hence, the domain of the function is (d) x ≥ -6
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Two long parallel wires are 0.400 m apart and carry currents of 4.00 A and 6.00 A. What is the magnitude of the force per unit length that each wire exerts on the other wire? (μ0=4π×10−7T⋅m/A)
The magnitude of the force per unit length that each wire exerts on the other wire is 3 × 10⁻⁷ N/m.
How to determineUsing Ampere's law, the force per unit length (F/L) between two parallel wires carrying currents I1 and I2 and separated by a distance d can be calculated as:
F/L = (μ0 ⨯ I1 ⨯ I2) / (2 ⨯ π ⨯ d)
Where μ0 is the permeability of free space (4π × 10⁻⁷ T⋅m/A),
I1 is the current in the first wire (4.00 A),
I2 is the current in the second wire (6.00 A), and d is the distance between the wires (0.400 m).
F/L = (4π × 10⁻⁷ T⋅m/A ⨯ 4.00 A ⨯ 6.00 A) / (2 ⨯ π ⨯ 0.400 m)
F/L = (24π × 10⁻⁷ T⋅m/A) / (0.800 m)
F/L = 3 × 10⁻⁷ ) T⋅m/A
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Determine all joint probabilities listed below from the following information: P(A) = 0.7, P(A c ) = 0.3, P(B|A) = 0.4, P(B|A c ) = 0.8 P(A and B) = P(A and B c ) = P(A c and B) = P(A c and B c ) =
Given the probabilities P(A) = 0.7, P(Ac) = 0.3, P(B|A) = 0.4, and P(B|Ac) = 0.8, the joint probabilities can be calculated as follows: P(A and B) = 0.28, P(A and Bc) = 0.42, P(Ac and B) = 0.12, and P(Ac and Bc) = 0.18.
The joint probability P(A and B) represents the probability of events A and B occurring simultaneously. It can be calculated using the formula P(A and B) = P(A) * P(B|A). Given that P(A) = 0.7 and P(B|A) = 0.4, we can multiply these probabilities to obtain P(A and B) = 0.7 * 0.4 = 0.28.
It can be calculated as P(A and Bc) = P(A) * P(Bc|A). Since the complement of event B is denoted as Bc, and P(Bc|A) = 1 - P(B|A), we can calculate P(A and Bc) as P(A) * (1 - P(B|A)) = 0.7 * (1 - 0.4) = 0.42.
Finally, P(Ac and Bc) represents the probability of both event A and event B not occurring. It can be calculated as P(Ac and Bc) = P(Ac) * P(Bc|Ac). Using P(Ac) = 0.3 and P(Bc|Ac) = 1 - P(B|Ac), we can calculate P(Ac and Bc) as P(Ac) * (1 - P(B|Ac)) = 0.3 * (1 - 0.8) = 0.18.
Therefore, the joint probabilities are: P(A and B) = 0.28, P(A and Bc) = 0.42, P(Ac and B) = 0.24, and P(Ac and Bc) = 0.18.
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plss helpppssss
6 th grade math
Answer:
Step-by-step explanation:
By the figure, it would mean:
67, 67, 68
72, 72, 73, 76, 76, 77, 78
80, 81, 83, 83, 85, 85, 85, 87, 88
91, 91, 93, 95, 99
a) 2 students
b) 9 students
c) 2 students
Explanation : 5 students (90s) - 3 students (60s) = 2 students
d) 81
Explanation : (67 + 67 + 68 + 72 + 72 + 73 + 76 + 76 + 77 + 78 + 80 + 81 + 83 + 83 + 85 + 85 + 85 + 87 + 88 + 91 + 91 + 93 + 95 + 99) ÷ 24 = 81.33
(1 point) find the interval of convergence for the power series ∑n=2[infinity](x−5)n3n
The interval of convergence for the given power series is (2, 8).
To find the interval of convergence for the given power series. We have the power series:
∑(n=2 to ∞) ((x-5)ⁿ)/(3ⁿ)
To find the interval of convergence, we'll use the Ratio Test. For the Ratio Test, we need to compute the limit:
L = lim (n → ∞) |(a_(n+1)/a_n)|
For our series, a_n = ((x-5)ⁿ)/(3ⁿ). Therefore, a_(n+1) = ((x-5)(n+1))/(3(n+1)). Now, let's compute the ratio:
|(a_(n+1)/a_n)| = |(((x-5)(n+1))/(3(n+1))) / (((x-5)ⁿ)/(3ⁿ))|
Simplify the expression:
|(a_(n+1)/a_n)| = |(x-5)/3|
The series converges if L < 1. So we have:
|(x-5)/3| < 1
Now, we'll solve for x to find the interval of convergence:
-1 < (x-5)/3 < 1
Multiply each term by 3:
-3 < x-5 < 3
Add 5 to each term:
2 < x < 8
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The ratios of the boys to girls in Mrs. Nelson’s is 2 to 3. There are 18 girls in the class. What is the total number of students in Mrs.Nelson’s class
Answer:
30 bcs 3 is 18 girls, therefore 2 is 12 boys
Step-by-step explanation:
2:3
?:18
18/3 ×2 =12
12+18÷30
456, 930, 1860, 3720, ?
c. A circular puzzle is 20 inches in diameter. All of the pieces are about the same size. You want to know about how many pieces there are in the puzzle.
Answer:
There is no exact answer to this question as it depends on the complexity of the puzzle. Generally speaking, a puzzle with a diameter of 20 inches would contain between 1000 and 2000 pieces.
Step-by-step explanation:
a2 = -8 and a5 = -512
Find a10
Answer:
The value of a₁₀ is -1352
Step-by-step explanation:
a₂ = -8
a₅ = -512
Now,
a₂ = -8 can be written as
a + d = -8 ...(1) and
a₅ = -512 can be written as
a + 4d = -512 ...(2)
Now, from equation (2) we get,
a + 4d = - 512
a + d + 3d = - 512
(-8) + 3d = - 512 (.°. a + d = -8)
3d = - 512 + 8
3d = - 504
d = - 504 ÷ 3
d = - 168
Now, for the value of a put the value of d = -168 in equation (1)
a + d = -8
a + (-168) = -8
a - 168 = -8
a = 168 - 8
a = 160
Now, For a₁₀
a₁₀ = a + 9d
a₁₀ = 160 + 9(-168)
a₁₀ = 160 - 1512
a₁₀ = -1352
Thus, The value of a₁₀ is -1352
-TheUnknownScientist
A compressive load of 80,000 lb is applied to a bar with
circular section0.75indiameter and a length of 10 in. if the
modulus of elasticity of the bar material is10,000 ksi and the
Poisson’s ratio i
The decrease in diameter of the bar due to the applied load is -0.005434905d and the final diameter of the bar is 1.005434905d.
A compressive load of 80,000 lb is applied to a bar with a circular section of 0.75 in diameter and a length of 10 in.
if the modulus of elasticity of the bar material is 10,000 ksi and the Poisson's ratio is 0.3.
We have to determine the decrease in diameter of the bar due to the applied load.
Let d be the initial diameter of the bar and ∆d be the decrease in diameter of the bar due to the applied load, then the final diameter of the bar is d - ∆d.
Length of the bar, L = 10 in
Cross-sectional area of the bar, A = πd²/4 = π(0.75)²/4 = 0.4418 in²
Stress produced by the applied load,σ = P/A
= 80,000/0.4418
= 181163.5 psi
Young's modulus of elasticity, E = 10,000 ksi
Poisson's ratio, ν = 0.3
The longitudinal strain produced in the bar, ɛ = σ/E
= 181163.5/10,000,000
= 0.01811635
The lateral strain produced in the bar, υ = νɛ
= 0.3 × 0.01811635
= 0.005434905'
The decrease in diameter of the bar due to the applied load, ∆d/d = -υ
= -0.005434905∆d
= -0.005434905d
The final diameter of the bar,
d - ∆d = d + 0.005434905d
= 1.005434905d
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At the end of 1st Quarter of 2009 the median price of a single-family home in Charleston/No. Charleston was $184,990. Single-family home prices in Charleston/No. Charleston decreased from the 1st Qtr of 2008 by 8.15%. NOTE: Depreciation means a negative value for r. (a). Estimate the median price of a single-family home in the 1st Qtr of 2008.
(b). If the median price of a single-family home falls at the same rate for the next 2 years, estimate the median price of a single-family home in the 1st Qtr of 2011.
The estimated median price of a single-family home in Charleston/No. Charleston in the 1st Quarter of 2008 is $201,048. If the median price continues to decrease at the same rate for the next two years, the estimated median price of a single-family home in the 1st Quarter of 2011 would be $144,458.
(a) To estimate the median price of a single-family home in the 1st Quarter of 2008, we need to calculate the original price before the 8.15% decrease. Let's assume the original price was P. The price after the decrease can be calculated as P - 8.15% of P, which translates to P - (0.0815 * P) = P(1 - 0.0815). Given that the end of 1st Quarter of 2009 median price was $184,990, we can set up the equation as $184,990 = P(1 - 0.0815) and solve for P. This gives us P ≈ $201,048 as the estimated median price of a single-family home in the 1st Quarter of 2008.
(b) If the median price of a single-family home falls at the same rate for the next two years, we can calculate the price for the 1st Quarter of 2011 using the estimated median price from the 1st Quarter of 2009. Starting with the median price of $184,990, we need to apply an 8.15% decrease for two consecutive years. After the first year, the price would be $184,990 - (0.0815 * $184,990) = $169,805.95. Applying the same percentage decrease for the second year, the price would be $169,805.95 - (0.0815 * $169,805.95) = $156,012.32. Therefore, the estimated median price of a single-family home in the 1st Quarter of 2011 would be approximately $144,458.
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Beth spent 1/3 of the time she needed to complete her homework reading a chapter and the remaining 20 minutes writing an essay. How much time did Beth spend doing her homework?A) 20 minutesB) 30 minutesC) 40 minutesD) 60 minutes
hello
beth spent 1/3 of the time needed for her assignment on a chapter and a further 20 minutes writing an essay
let the total time she spent doing her home work be represented by x
total time = reading a chapter + writing an eassy
\(x=\frac{1}{3}x+20\)let's solve the equation and find x
\(\begin{gathered} x-\frac{1}{3}x=20 \\ \frac{3-1}{3}x=20 \\ \frac{2}{3}x=20 \\ 2x=3\times20 \\ 2x=60 \\ \frac{2x}{2}=\frac{60}{2} \\ x=30 \end{gathered}\)Beth spent 30 minutes doing her home work
Please help me.I will give whoever awnsers the most points.
Answer:
$5
Step-by-step explanation:
10%×400 = 40×2=80
5%×400=20
20+80=100
400+100=500
$5
Please help this is due worth 22 points
Answer:
1 is
for 1 disc is $16.50
for 2 disc is $33.00
for 3 disc is $49.50
and
2 is
for 1 book is $6.95
for 2 books is $13.90
for 3 books is $20.85
Step-by-step explanation:
brainliest pls
Which does not belong? 21% 21/100 21:100 21
Answer:
B.21
Step-by-step explanation:
because it's the only whole number.
HURRY. IS it SSS, SAS, AAA
Answer:
SSS I believe sorry if im wrong
Step-by-step explanation:
What is 1.80 m in feet?