Based on law of conservation of angular momentum, the rotational speed of the star is equal to 6,000 rev/s.
Given the following data:
Radius of Sun = 7 × 10⁵ km.Mass of star = 2 Mass of Sun (M = 2M).Radius of star = 10 km.Time = 10 days.How to calculate the rotational speed.First of all, we would determine the initial angular speed of the neutron star as follows:
\(\omega_i = \frac{1 \;Rev}{10 \;days} \\\\\omega_i = \frac{1 \;Rev}{10 \times 24 \times 60 \times 60}\\\\\omega_i = 1.157 \times 10^{-6}\;rev/s\)
Mathematically, the moment of inertia of a uniform solid sphere is given by this formula:
\(I=\frac{2}{5} mr^2\)
Where:
I is the moment of inertia.m is the mass.r is the radius.In order to determine the rotational speed of this neutron star, we would apply the law of conservation of angular momentum:
\(L_1 = L_2\\\\I_1\omega_1 = I_2\omega_2\\\\\frac{2}{5} m_1r_1^2 \omega_1 = \frac{2}{5} m_2r_2^2\omega_2\\\\m_1r_1^2 \omega_1 = m_2r_2^2\omega_2\\\\\omega_2 =\frac{r_1^2 \omega_1}{r_2^2}\)
Substituting the given parameters into the formula, we have;
\(\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ (10 )^2}\\\\\\\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ 10 0}\\\\\omega_2 =\frac{566,930}{100}\)
Final angular speed = 5,669 ≈ 6,000 rev/s.
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A candle 4.75 cm tall is 40.0 cm to the left of a plane mirror.
a) Where is the image formed by the mirror?
- to the right of the mirror
- to the left of the mirror
b) What is the height of this image?
(Express your answer in centimeters.)
Answer: A candle 4.75 cm tall is 40.0 cm to the left of a plane mirror. Then, the image formed by the mirror will be to the right of the mirror and the height of this image is same as that of the object.
Explanation: To find the answer, we need to know about the reflection at a plane mirror.
What is the reflection at a plane mirror?There are some points about the reflection at a plane surface.
Distance of image from mirror = distance of object from mirror.Size of the image = size of the object.If object moves with certain velocity, then the image also moves with same velocity in opposite direction.Image formed by a plane mirror will be on the opposite side of the object and which is erect, virtual and laterally inverted.Thus, we can conclude that, a candle 4.75 cm tall is 40.0 cm to the left of a plane mirror. Then, the image formed by the mirror will be to the right of the mirror and the height of this image is same as that of the object.
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In response, a plane mirror is 40.0 cm to the left of a candle that is 4.75 cm tall. The mirror's generated image will then be to the right of the mirror and have the same height as the object.
In order to determine the solution, we must understand how a plane mirror reflects light.
What appears in a plane mirror's reflection?There are a few things to note concerning reflections on flat surfaces.The distance of an object from a plane mirror is equal to the distance of its image.Size of the object equals size of the image.If an object moves at a specific speed, the picture will follow suit and move in the opposite direction at the same speed.The other side of the object will have an erect, virtual, and laterally inverted image created by a plane mirror.As a result, we may say that a flat mirror is 40.0 cm to the left of a candle that is 4.75 cm tall. The mirror's generated image will then be to the right of the mirror and have the same height as the object.
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An invading barbarian whirls a stone in a leather sling. If the sling is 90 cm
long, and the velocity of the stone is 90 m/s, what is the centripetal
acceleration of the stone?
Answer:
56,643.36m/s²Explanation:
Centripetal acceleration is expressed as shown:
a = v²/r
v is the velocity
r is the radius
If the length of the sling is 90cm, hence the circumference of the circular path is 90cm
Since C = 2πr
0.9 = 2πr
r = 0.9/2π
r = 0.9/2(3.14)
r = 0.9/6.28
r = 0.143m
Get the centripetal acceleration:
a = 90²/0.143
a = 56,643.36m/s²
Hence the the centripetal acceleration of the stone is 56,643.36m/s²
Find the change in thermal energy of a 25kg severed clown doll head that heats up from 25°C to 35°C, and has the specific heat of 1,700 J/(kg°C).
Answer:
Q = 425 kJ
Explanation:
Given that,
Mass, m = 25 kg
The clown doll head that heats up from 25°C to 35°C
The specific heat is 1700 J/kg°C
We need to find the internal energy of it. The heat required to raise the temperature is given by the formula as follows :
\(Q=mc\Delta T\\\\Q=25\times 1700\times (35-25)\\\\Q=425000\ J\\\\Q=425\ kJ\)
So, 425 kJ of thermal energy is severed.
Which of the following would you expect to be a strong electrolyte in solution?
The following would expect to be a strong electrolyte in solution (b) KCI is correct option.
When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions. The following compounds are typically strong electrolytes in solution according to this definition:
Al(OH)₃ (aluminum hydroxide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.KCl (potassium chloride) is a strong electrolyte. It completely dissociates into potassium ions (K⁺) and chloride ions (Cl⁻) in solution, resulting in a high concentration of ions and a high electrical conductivity.PbI₂ (lead(II) iodide) is a weak electrolyte. It does not dissociate significantly into ions in solution, resulting in a low electrical conductivity.These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.
Therefore, the correct option is (b).
The complete question is,
Which of the following would be a strong electrolyte in solution?
a) Al(OH)₃ b) KCI c) Pbl₂
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What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.
The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.
Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.
Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.
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in analog technology, a wave is recorded or used in its ______ form.
Answer:
In analog technology, a wave is recorded or used in its Original form.
Explanation:
An appeal of a state appellate court ruling can next be made to:
• A. a state trial court.
• B. the state supreme court.
• C. the U.S. Supreme Court.
• D. a U.S. Court of Appeals.
The decision of the country's highest court may then be appealing to that Supreme Court of both the U. S., but only in cases where the issue involves federal law.
Why is Supreme renowned?In particular, followers of hip-hop, surfing, and post - punk culture will find their clothing appealing. Every person who appreciates streetwear will discover the ideal item thanks to Supreme's wide range of clothing.
Why is Supreme so expensive?Rebellious and distinctive brand image! Despite giving a venture - capital group a 50% ownership in the company, Supreme has been able to keep its skater roots and fan base. To top it all off, the Supremes' emblem is distinctive, outstanding, and simple to recognize.
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a) d = 24 g/mL
v = 1.2 L =
m=? 28.1
? 23.03
mL
Density calculations are 1.2L = 1200mL m = 2.9 x 10^4 g
Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimetre are a typical unit of measurement for density. Another way to state density is in kilogrammes per cubic metre (in metre-kilogram-second or SI units).
For instance, air weighs 1.2 pounds per cubic metre. In textbooks and manuals, the densities of typical solids, liquids, and gases are stated. The relationship between mass and volume can be easily determined using density; for example, the mass of a body is equal to its volume multiplied by the density (M = Vd), whereas the volume is equal to the mass divided by the density (V = M/d).
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An astronaut on the Moon releases a rock from rest and allows it to drop straight downward. If the acceleration due to gravity on the Moon is 1.62m/s2 and the rock falls for 2.4s before hitting the ground, what is its speed just before it lands?
Answer:
speed before landing = 3.9 m/s (3 s.f.)
Explanation:
As rock is released from rest, u = 0 m/s a = 1.62 m/s² t = 2.4 s v = ?
v = u + at
v = 0 + (1.62 x 2.4)
v = 3.888 = 3.9 s (3 s.f.)
Hope this helps!
The speed of the rock before hitting the ground is 3.89 m/s
The given parameters;
acceleration due to gravity on moon, g = 1.62 m/s²
time taken for the object to fall, t = 2.4 s
To find:
the speed of the object before hitting the ground;The maximum height of fall of the rock is calculated as;
\(h = v_0t + \frac{1}{2} gt^2\\\\v_0 = 0\\\\h = \frac{1}{2} gt^2\\\\h = 0.5 \times 1.62 \times 2.4^2 \\\\h = 4.67 \ m\)
The speed of the rock before hitting the ground is calculated as;
\(v_f^2 = v_0 ^2 + 2gh\\\\v_f^2 = 0 + 2\times 1.62 \times 4.67\\\\v_f^2 = 15.13\\\\v_f = \sqrt{15.13} \\\\v_f = 3.89 \ m/s\)
Thus, the speed of the rock before hitting the ground is 3.89 m/s
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A jet needs to reach a "lift-off' speed of 120 m/s before it can leave the ground. How quickly must
the jet accelerate if the run way has a length of 322 m?
The jet must accelerate in 5.37 s if it must reach the lift-off speed
From the question given above, the following data were:
Initial velocity (u) = 0 m/s
Final velocity (v) = 120 m/s
Distance (s) = 322 m
Time (t) =?The time needed for the jet to accerate can be obtained as follow:
\(s = \frac{(v + u)t}{2} \\ \\ 322 = \frac{(120 + 0)t}{2} \\ \\ 322 = \frac{120t}{2} \\ \\ cross \: multiply \\ \\ 120t = 322 \times 2 \\ \\ 120t = 644 \\ \\ divide \: both \: side \: by \: 120 \\ \\ t = \frac{644}{120} \\ \\ \)
t = 5.37Thus, the jet must accelerate in 5.37 s in order to reach the lift-off speed
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As the jet leaves the ground, it accelerates at a rate of 22.4 ms-2.
We have the following information from the question;
Final velocity = 120 m/s
Initial velocity = 0 m/s
Distance covered = 322 m
Acceleration = ?
Using the equation;
v^2 = u^2 + 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
(120)^2 = 0^2 + (2 × a × 322)
14400 = 644a
a = 14400/644
a = 22.4 ms-2
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An object is being shot from a horizontal ground at an incline angle of 30 degree with respect to the ground at a speed of 52 m/s. Find the duration in seconds that the object is above the height of 14 m. Give your answer with one decimal place.
When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.
What is speed?Speed is the time rate at which velocity is changing.
Vertical speed component is
V₀y = 52sin 30°= 26 m/s
Given is the height h=14m
Using second equation of motion,
S=ut+ 1/2 at²
Substituting the values, we get
14 = 26t - 4.9t²
4.9t² - 26t +14 =0
Solving the quadratic equation, we get the time as
taking the positive sign, t =4.698 s
taking the negative sign , t = 0.6082 s
Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.
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An object with a kinetic energy of 250j has a mass of 32 kg what is the velocity of the object?
Taking into account the definition of kinetic energy, the velocity of the object with a kinetic energy of 250 J and a mass of 32 kg is 3.95 m/s².
Deinition of Kinetic energyKinetic energy is the energy possessed by a body or system due to its movement.
Kinetic energy is defined as the amount of work necessary to accelerate a body of a certain mass and in a position of rest, until it reaches a certain speed. Once the final speed is reached, the amount of kinetic energy accumulated will remain constant, that is, it will not vary, unless another force acts on the body again.
Kinetic energy is represented by the following expression:
Ec = 1/2×m×v²
Where:
Ec is kinetic energy, which is measured in Joules (J).m is mass measured in kilograms (kg).v is velocity measured in meters over seconds (m/s).Velocity of the objectIn this case, you know:
Ec= 250 Jm= 32 kgv= ?Replacing in the definition of kinetic energy:
250 J = 1/2× 32 kg×v²
Solving:
250 J÷ (1/2× 32 kg) = v²
15.625 J÷kg = v²
√15.625 J÷kg = v
3.95 m/s² = v
Finally, the velocity of the object is 3.95 m/s².
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What is the speed of a Ball rolling South 50 meters in 2 seconds?
Answer:
25m/s
Explanation:
speed = distance/time = 50/2 = 25
A push broom of mass m is pushed across a rough horizontal floor by a force of magnitude 7 directed at angle theta. The coefficient of friction between the broom and the floor is μ. The frictional force on the broom has magnitude?
the frictional force on the broom has magnitude μ * m * g * cos(theta)
What is frictional force?
The frictional force on the broom can be determined using the equation:
F_friction = μ * F_norm
Where F_friction is the frictional force, μ is the coefficient of friction, and F_norm is the normal force. The normal force is equal to the force exerted on the broom perpendicular to the surface of the floor. Since the broom is being pushed across a horizontal surface, the normal force is equal to the force of gravity, which is equal to the mass of the broom (m) multiplied by the acceleration due to gravity (g).
F_norm = m * g
The force being applied to the broom is 7N and it is at angle theta with the horizontal. The component of this force perpendicular to the surface of the floor is the force that acts on the normal force.
F_norm = 7 * cos(theta)
Therefore,
F_friction = μ * m * g * cos(theta)
So, the frictional force on the broom has magnitude μ * m * g * cos(theta)
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Frequency refers to the number of wavelengths that pass a fixed point in a minute. true or false
A rigid body acted upon by a set of forces . The magnitude of the forces are as follows F1=3N,F2=6N,F3=3N,F4=4N,F5=3Nand F6=3N. Identify the couple among these forces
The forces F3 and F6 form a couple since they are parallel, act in the same directions, and have the same magnitude (both are 3N), but they do not have the same point of application.
A couple is a pair of equal but disjointed forces that act in opposite directions and along parallel lines of force.
The rigid body rotates about its center of mass as a result of the forces acting on it at various places.
We can observe that the forces F3 and F6 in the provided set of forces are parallel, have the same magnitude of 3N, and act in opposite directions.
However, because they are applied to various locations on the rigid body, the body will rotate as a result. The stiff body tends to rotate around its center of mass because of this phenomenon, which is known as a couple.
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Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.
The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.
What is hydrostatic pressure?Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.
The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:
P = ρgh + Po
where:
P is the absolute pressure at the given depth
ρ is the density of the water
g is the acceleration due to gravity (assumed to be 9.81 m/s²)
h is the depth of the ocean
Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)
Substituting the given values, we get:
P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa
P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa
P = 1.002 x 10^8 Pa.
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why is sun considered the center of the solar system
Answer: All the planets in our solar system rotate around it without the sun itself moving therefore all the planets make a cicular shape and the sun is in the middle
Explanation:
an ice skater is moving across a flat and level skating rink and is speeding up. which one of the following statement is true of the ice skater
a) its potential energy is constant
b) its potential energy is increasing
c) its potential energy is decreasing
Answer:
A
Explanation:
The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point:
d
→
L
d
t
=
0
or
→
L
=
→
l
1
+
→
l
2
+
⋯
+
→
l
N
=
constant
.
Note that the total angular momentum
→
L
is conserved. Any of the individual angular momenta can change as long as their sum remains constant. This law is analogous to linear momentum being conserved when the external force on a system is zero.
What do you do to find the manipulated variable in a line graph?
Answer: Days and Height (cm).
Explanation:
what is a shargaff rule
According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.
Who is Chargaff ?Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.
Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.
He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.
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what is the value of pi(8.104)^2 written with correct significant numbers
Answer:206.3
Explanation:
You are piloting a small airplane in which you want to reach a destination that is 750 km due north of your starting location. Once you are airborne, you find that (due to a strong but steady wind) to maintain a northerly course you must point the nose of the plane at an angle of 22 west of true north. From previous flights on this route in the absence of wind, you know that it takes you 3.14 h to make the journey. With the wind blowing, you find that it takes 4.32 h. A fellow pilot calls to ask you about the wind velocity (magnitude and direction). What is your report? FYI so you can check yourself the answers are 101 km/h at 62 degrees east of south.
Answer:
v_wind = 101.46 km / h , θ = 61.8
Explanation:
This is a velocity composition exercise.
Let's do the problem in parts. Let's start by knowing the speed of the plane without air.
v = d / t
v = 750 / 3.14
v = 238.85 km / h
This is the speed of the plane relative to the Earth and it does not change.
In the second part, when there is wind, the travel time is greater than when there is no wind, therefore the wind delays the plane. To be more general, suppose that the wind has two components vₓ and \(v_{y}\)
Let's use trigonometry to find the components of the plane's speed
cos θ = v_N / v
sin θ = v_W / v
v_N = v cos θ
v_W = v sin θ
let's calculate
V _N = 238.85 cos 22 = 221.46 km / h
v_W = -238.85 sin 22 = -89.47
the negative sign is because the plane is going west and the positive sign is the east direction.
As it indicates that the destination of the avine is towards the north, the x component of the wind must be
vₓ - v_W = 0
vₓ = v-w
vₓ = 89.47 km / h
in the direction to the East.
Now let's analyze the component of the wind in the Nort-South direction,
Indicate the travel time, let's calculate the speed that the component must have the speed of the plane
v_total = d / t
v_total = 750 / 4.32
v_total = 173.61 km / h
This is the final speed of the plane, which can be written
v_total = v_n - vy
vy = v_n - v_total
vy = 221.46 - 173.61
vy = 47.85 km
this component is directed towards the south
Let's use the Pythagorean Theorem, to find the magnitude
v_wind² = vₓ² + vy²
v_wind = √ (89.47² + 47.85²)
v_wind = 101.46 km / h
the address will then be found using trigonometry
θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹1 (47.85 / 89.47)
θ = 28.14
Therefore, the magnitude of the wind speed is 101.5 km / h and its direction is 28º south of the East, to give this value
90- θtea = 90- 28.2
θ = 61.8
East of South
The current through a toaster connected to a 120 V source is 8.0 A. What power is dissipated by the toaster?
Answer:
P = 96 Watts
Explanation:
The power dissipated is calculated as
P = VI
Where V is te voltage and I is the current. Replacing V = 120V and I = 8.0A, we get:
P = (120 V)(8.0 A)
P = 96 Watts
Therefore, the answer is 96 Watts
Variable Radius Mass (kg) Period (s) 3 2 Radius (m) 1 2 3 3 Tangential speed (m/s) 3.14 3.14 3.14 3.14 3.14 4 Centripetal Force (N) 29.6 14.8 9.87 7.40 5.92 6 www 8 4 10 5 Analysis: Force vs Circle Radius 1. Looking at the Variable Radius table, what can you conclude about the relationship between the centripetal force and radius? What is the functional form of this relationship?
We can infer from the Variable Radius table that as the radius grows, the centripetal force decreases.
The centripetal force and radius have an inverse connection, which means that as one quantity changes, the other changes proportionally.
The mathematical formula for the functional form of this connection is F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius.
The centripetal force equation, which describes this relationship, is a key idea in comprehending circular motion.
The Variable Radius table reveals that there is an inverse proportionality between the centripetal force and radius. The centripetal force reduces as the radius grows, and vice versa.
The centripetal force equation, F = k/r, where F is the centripetal force, k is a proportionality constant, and r is the radius, describes this relationship.
The travel of planets around the sun or the movement of cars around a curve are only two examples of how comprehending this relationship is crucial to understanding circular motion.
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Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place
Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.
Why is it colder at the bottom of the pool than the top of the pool?
There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;
Heat transfer by radiationHeat transfer by convection Heat transfer by radiationThe surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.
Heat transfer by convectionThe heat from the air is transferred to the pool through convection.
Thus, these two heat transfer processes causes the surface water of the pool to be warm which decreases with depth.
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in fig. 30-45, two straight conducting rails form a right angle. a conducting bar in contact with the rails starts at the vertex at time t 0 and moves with a constant velocity of 5.20 m/s along them. a magnetic field with b 0.350 t is directed out of the page. calculate (a) the flux through the triangle formed by the rails and bar at t 3.00 s and (b) the emf around the triangle at that time. (c) if the emf is at n, where a and n are constants, what is the value of n?
(a) The flux through the triangle formed by the rails and bar at t 3.00 s is calculated to be 85.2 Wb.
(b) The EMF around the triangle at that time is 56.8 V.
(c) If the EMF is at n, where a and n are constants, the value of n is 1.
(a) The height of the triangular area enclosed by the rails and bar is the same as the distance traveled in time t. So, we have d = v * t
where, v = 5.2 m/s
We also note that the base of the triangle is the distance between the intersection points of the bar with the rails which is 2 d. The area of the triangle is
A = 1/2 * b * h = 1/2 * 2 v t * v t = v² t²
As the field is said to be uniform B = 0.35 T
The magnitude of flux is given by,
Ф = B * A = 0.35 * v² t² = 0.35 * 5.2² * t² = 9.46 v² t²
At t = 3 s, we get Ф = 85.2 Wb
(b) The magnitude of EMF is
ε = dФ/dt = 9.46 dt²/dt = 18.9 t
At t = 3 s, ε = 18.9 t = 56.8 V
(c) Our solution part of (b) shows, n = 1
The question is incomplete. The attachment shows the figure.
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why is electromagnet are called temporary magnet
pls its urgent
Answer: because when you remove the battery, the the magnet no longer has electricity flowing through it, therefore the magnetic field disappears. Thats why its called a temporary magnet
Explanation:
Consider a system of two charges of magnitude 2 × 10-7 C and 4.5 × 10-7 C which is acted upon by a force of 0.1 N. What is the distance between the two charges?
To find the distance between two charges, we can use Coulomb's law, which states that the force between two charges is proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for Coulomb's law is:
F = (k * |q1| * |q2|) / r^2
where:
F is the force between the charges,
k is the electrostatic constant (k = 8.99 × 10^9 N m^2/C^2),
|q1| and |q2| are the magnitudes of the charges, and
r is the distance between the charges.
Given:
|q1| = 2 × 10^-7 C
|q2| = 4.5 × 10^-7 C
F = 0.1 N
k = 8.99 × 10^9 N m^2/C^2
We can rearrange the equation to solve for r:
r^2 = (k * |q1| * |q2|) / F
Plugging in the values:
r^2 = (8.99 × 10^9 N m^2/C^2 * 2 × 10^-7 C * 4.5 × 10^-7 C) / 0.1 N
r^2 = (8.99 × 2 × 4.5) * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * (10^9 * 10^-7 * 10^-7) / 0.1
r^2 = 80.91 * 10^(-7 + 9 - 1)
r^2 = 80.91 * 10^1
r^2 = 809.1
Taking the square root of both sides:
r = √809.1
r ≈ 28.46
Therefore, the distance between the two charges is approximately 28.46 units.
What do you think causes the changes in sunrise and sunset times over the course of the year?
Answer:
The combination of Earth's elliptical orbit and the tilt of its axis results in the Sun taking different paths across the sky at slightly different speeds each day. This gives us different sunrise and sunset times each day.
Explanation: