assume the answer to the previous problem is v = 7 m/s (which it isn’t), would the car be on the track at that point?
a. YES
B. NO
C. Not enough information is given

Answers

Answer 1

Not enough information is given to determine if the car be on the track at that point with velocity = 7 m/s. The correct option is C.

To determine if the car would still be on the track at a velocity of 7 m/s, we would need more information about the specific situation. Factors to consider include the track's dimensions, its curvature, the car's maximum allowable speed to maintain control, and the specific forces acting on the car, such as friction and centripetal force.

For example, if the track has a sharp curve, a higher speed might cause the car to lose grip and skid off the track due to insufficient centripetal force. Alternatively, if the track is relatively straight, the car may be able to maintain the 7 m/s speed without any issues. Additionally, the friction between the car's tires and the track surface plays a crucial role in keeping the car on the track. If the friction is insufficient, the car might not stay on the track at the given speed.

In conclusion, without more information about the track's characteristics, the car's properties, and the forces involved, it is impossible to determine if the car would remain on the track at a velocity of 7 m/s.

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Related Questions

The transfer of energy in liquids and gases as groups of molecules move in currents is

Convection
Conduction
Radiation
Convection currents

Answers

Convection is your answer

Suppose you receive $5.00 at the beginning of a week and spend $1.00 each day for
lunch. You prepare a graph of the amount you have left at the end of each day for one
6.
week.
A)
Would the slope of this graph be positive, negative, or zero?
B)
Why?

Answers

The slope would be negative, as you spend 1 dollar a day. It would be -1

Hierarchy of the universe this is due today pls help me

Answers

Answer:

what is the question.

Explanation:

The Universe has a hierarchy: structural stages, from the smallest of quantum particles to the largest of cosmic scaffolding, extending through the entirety of reality. Somewhere in the centre, the galaxies themselves lie.

A car slows down from a velocity of 25 m/s to rest in 5.0 seconds. How far did the car travel during that time?

Answers

Answer:

\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)

Given:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)

By substituting value of v, u & t in the equation we get:

\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)

\( \therefore\)

Distance travelled by car (s) = 62.5 m

The distance  car travel during that time is 62.5 meter.

What is acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Initial velocity (u) = 25 m/s

As the car becomes rest, final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds.

The deceleration of the car: a = (initial speed - final speed)/time interval

= ( 25 m/s - 0 m/s)/5 second

= 5 m/s²

The distance  car travel during that time = ut - at²/2

= 25 × 5.0 meter - (5×5²/2) meter

= 62.5 meter.

Hence, the distance  car travel during that time is  62.5 meter.

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In scenario A, visible light has a wavelength of 694.6 nm. Deteine its frequency, energy per photon, and color. frequency: The visible light in scenario A is energy per photon: J In scenario B, visible light has a frequency of 5.362×1014 s−1. Deteine its wavelength, energy per wavelength: photon, and color. The visible light in scenario B is energy per photon: J In scenario C, visible light is in the middle of the yellow region of the visible spectrum. Estimate its wavelength, frequency, and energy per photon.
wavelength:

Answers

In scenario A, the visible light with a wavelength of 694.6 nm has a frequency of 4.32 × 10¹⁴ s⁻¹, an energy per photon of 2.85 × 10⁻¹⁹ J, and appears red, while in scenario B, the light with a frequency of 5.362 × 10¹⁴ s⁻¹ has a wavelength of approximately 559.2 nm, an energy per photon of 3.35 × 10⁻¹⁹ J, and appears yellow-green, and in scenario C, the light in the middle of the yellow region of the visible spectrum has an estimated wavelength of 570 nm, a frequency of approximately 5.26 × 10¹⁴ s⁻¹, and an energy per photon of approximately 3.48 × 10⁻¹⁹ J.

Scenario A:

The visible light in scenario A with a wavelength of 694.6 nm has a frequency of approximately 4.32 × 10¹⁴ s⁻¹, an energy per photon of approximately 2.85 × 10⁻¹⁹ J, and its color is red.

To determine the frequency of visible light in scenario A, we can use the equation:

c = λν

Where c is the speed of light (approximately 3.00 × 10⁸ m/s), λ is the wavelength (694.6 nm or 6.946 × 10⁻⁷ m), and ν is the frequency. Rearranging the equation, we can solve for ν:

ν = c / λ

ν = (3.00 × 10⁸ m/s) / (6.946 × 10⁻⁷ m) ≈ 4.32 × 10¹⁴ s⁻¹

The energy per photon (E) can be calculated using Planck's equation:

E = hν

Where h is the Planck's constant (approximately 6.63 × 10⁻³⁴ J·s). Plugging in the frequency (ν) we calculated, we can find the energy per photon:

E = (6.63 × 10⁻³⁴ J·s) × (4.32 × 10¹⁴ s⁻¹) ≈ 2.85 × 10⁻¹⁹ J

Based on the wavelength of 694.6 nm, the visible light in scenario A falls within the red region of the visible spectrum.

Scenario B:

In scenario B, with a frequency of 5.362 × 10¹⁴ s⁻¹, the visible light has a wavelength of approximately 559.2 nm, an energy per photon of approximately 3.35 × 10⁻¹⁹ J, and its color is yellow-green.

To determine the wavelength (λ) of visible light in scenario B, we can use the equation:

c = λν

Using the speed of light (c ≈ 3.00 × 10⁸ m/s) and the frequency (ν = 5.362 × 10¹⁴ s⁻¹), we can rearrange the equation to solve for λ:

λ = c / ν

λ = (3.00 × 10⁸ m/s) / (5.362 × 10¹⁴ s⁻¹) ≈ 559.2 nm or 5.592 × 10⁻⁷ m

The energy per photon (E) can be calculated using Planck's equation:

E = hν

Plugging in the frequency (ν) we calculated, along with Planck's constant (h ≈ 6.63 × 10⁻³⁴ J·s), we find the energy per photon:

E = (6.63 × 10⁻³⁴ J·s) × (5.362 × 10¹⁴ s⁻¹) ≈ 3.35 × 10⁻¹⁹ J

Based on the wavelength of approximately 559.2 nm, the visible light in scenario B falls within the yellow-green region of the visible spectrum.

Scenario C:

In scenario C, where visible light is in the middle of the yellow region of the visible spectrum, the estimated wavelength is approximately 570 nm, the frequency is approximately 5.26 × 10¹⁴ s⁻¹, and the energy per photon is approximately 3.48 × 10⁻¹⁹ J.

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A can of condensed mushroom soup is placed on its side at the top of an inclined plane and allowed to roll down the plane. What is the direction of rolling friction acting on the can as it rolls down the incline? What would be the direction of rolling friction if it rolled up the incline?

Answers

The direction of rolling friction acting on the can as it rolls down the incline is opposite to the direction of its motion. If the can rolled up the incline, the direction of rolling friction would also be opposite to the direction of its motion.

When the can of condensed mushroom soup rolls down the incline, the rolling friction acts in the opposite direction of its motion. Rolling friction is the force that opposes the rolling motion of an object and is generated between the rolling object (in this case, the can) and the surface it rolls on (the inclined plane). The frictional force slows down the rolling motion of the can, preventing it from accelerating uncontrollably down the incline. As a result, the rolling friction acts in the opposite direction of the can's motion.

If the can were to roll up the incline instead, the rolling friction would still act in the opposite direction of the can's motion. Regardless of whether the can is rolling up or down the incline, rolling friction always opposes the direction of motion to hinder or slow down the rolling object.

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Which object will have greater acceleration? Why?​

Which object will have greater acceleration? Why?

Answers

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

F = ma 50 N = 10 kg · a 50 = 10a 5 = a

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

F = ma 50 N = 2 kg * a 50 = 2a25 = a

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

a collision between two object referred to as elastic would be characterized by:

Answers

A collision between two object referred to as elastic would be characterized by: Elastic collisions are collisions that conserve both kinetic energy and momentum.

What is momentum?

Momentum is a concept in physics that refers to the quantity of motion an object has. It is expressed as the product of the mass of an object and its velocity. Momentum is a vector quantity, which means it has both a magnitude and a direction. Objects with greater mass have more momentum than those with less mass. The momentum of an object will also increase if its speed increases, and it will decrease if the speed decreases. Momentum is conserved which means the total momentum of an isolated system remains constant over time. Momentum is an important concept in understanding the motion of objects and can help explain why objects change direction when they collide.

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The movement of ocean water is caused by serveal processes______ results in the continual of ocean water facing in a global scale
A- Wind
B-Convection
C-The jet stream
D- Earths rotation

Answers

Answer:

A

Explanation:

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A skater holds her arms outstretched as she spins at 120 rpm. Part A What is the speed of her hands if they are 140 cm apart? Express your answer with the appropriate units

Answers

According to the question the speed of the skater's hands is 528 m/min.

To calculate the speed of the skater's hands, we can use the formula:

Speed = Circumference * Revolutions per minute

Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.

The circumference of a circle is given by the formula:

Circumference = 2 * π * radius.

In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.

Converting the radius to meters, we have 70 cm = 0.7 m.

Now we can calculate the circumference:

Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).

Finally, we can calculate the speed of the skater's hands:

Speed = Circumference * Revolutions per minute

     = 4.4 m * 120 rpm

     = 528 m/min.

Therefore, the speed of the skater's hands is 528 m/min.

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why the unit of work is derived unit?

Answers

Since energy can be measured as work, we can write energy = force x distance. Thus SI derived unit of energy has the units of newtons x meter or kg m2/s2.

hope it is helpful for you keep smiling

why the unit of work is derived unit?

an object that weighs 2.450 n is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period of 0.903 s. what is the spring constant of the spring? a) 2.45 n/m b) 12.1 n/m c) 24.1 n/m d) 0.102 n/m e) 0.610 n/m

Answers

The spring constant of the ideal massless spring is approximately option c- 24.1 N/m.

The spring constant, denoted by "k," is a measure of the stiffness or rigidity of a spring. It defines the relationship between the force applied to a spring and the resulting displacement or deformation of the spring from its equilibrium position.

The period (T) of a simple harmonic oscillator is related to the spring constant (k) and the mass (m) of the object attached to the spring by the equation:

T = 2π√(m/k)

Weight of the object (W) = 2.450 N

Period (T) = 0.903 s

Acceleration due to gravity (g) ≈ 9.8 m/s²

Calculating the mass (m):

m = W/g = 2.450 N / 9.8 m/s² ≈ 0.25 kg

Calculating the spring constant (k):

k = (4π² * 0.25 kg) / (0.903 s)² ≈ 24.1 N/m

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A bullet is shot at some angle above the horizontal at an initial velocity of 87m/s on a level surface. It travels in the air for 13.6 seconds before it strikes the ground 760 m from the shooter. At what angle above the horizontal was the bullet fired? Round to the nearest whole number and include units in your answer Use g= -9.8 m/s2 for the acceleration of gravity.

Answers

Answer: 50°

Explanation:

Given the following :

Initial Velocity of bullet (U) = 87m/s

Time of travel (t) = 13.6s

Horizontal Distance traveled (S) = 760m

Therefore, the horizontal angle of projection of the bullet :

Using the second equation of motion:

S = ut + 0.5at^2

Where a = g = acceleration due to gravity, S = distance traveled, t= time taken and U = Initial Velocity.

The Angle of projection along the horizontal is represented as cosΘ

Acceleration due to gravity after the bullet has hit the ground = 0

Therefore, rewritten the equation :

S = ucosΘ * t + 0.5at^2

760 = 87 * Cosθ * 13.6 + 0.5(0)(13.6)^2

760 = 1183.2 * Cosθ + 0

Cosθ = 760 / 1183.2

Cosθ = 0.6423

Θ = cos^-1(0.6423)

Θ = 50.036460

Θ = 50°

Calculate the wavelength of light that has a frequency of 5.2 x 1012 1/s.

Answers

Answer:

Wavelength = 5.77 * 10^-5 meters.

Explanation:

Given the following data:

Frequency of light = 5.2 *10^12 Hz

We know that the Speed of light = 3.0 * 10^8 m/s

To find the wavelength of light;

Mathematically, wavelength is calculated using this formula;

\( Wavelength = \frac {speed}{frequency} \)

Substituting into the equation, we have;

\( Wavelength = \frac {3*10^{8}}{5.2 *10^{12}} \)

Wavelength = 5.77 * 10^-5 meters.

Vitalpando Winery wants to raise $30 million from the sale of preferred stock. if the winery wants to sell one million shares of preferred stock, what annual dividend will it have to promise if inverstor demand a return of
a. 11% ?
b. 15%?
c. 8% ?
d. 10%?
e. 6% ?
f. 3% ?

Answers

Vitalpando Winery will need to promise an annual dividend of $330,000 if investors demand a return of 11% on their preferred stock. The dividend amounts for the other required return rates are as follows: $450,000 for 15%, $240,000 for 8%, $300,000 for 10%, $180,000 for 6%, and $90,000 for 3%.

To determine the annual dividend required to satisfy the investors' demands for different return rates, we need to multiply the number of shares by the desired return rate. In this case, the winery wants to sell one million shares of preferred stock.

For option (a), where the desired return rate is 11%, the calculation would be: $30,000,000 (total funds required) multiplied by 0.11 (11% expressed as a decimal) divided by 1,000,000 (number of shares). This results in an annual dividend of $330,000.

Similarly, for the other return rates, the calculations are as follows:

(b) $30,000,000 x 0.15 / 1,000,000 = $450,000

(c) $30,000,000 x 0.08 / 1,000,000 = $240,000

(d) $30,000,000 x 0.10 / 1,000,000 = $300,000

(e) $30,000,000 x 0.06 / 1,000,000 = $180,000

(f) $30,000,000 x 0.03 / 1,000,000 = $90,000

Therefore, the annual dividends required to satisfy the investors' demands for the different return rates are as stated above.

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An electromagnetic wave has a frequency of 1.0 < 1014 Hz. What is the
wavelength of the wave? Use the equation 1 = and the speed of light as
V
f
3.0 x 108 m/s.
O A. 3.3 x 10-8 m
B. 3.0 x 1022 m
C. 3.3 x 105 m
0
D. 3.0 x 10-6 m

Answers

Answer:

  D. 3.0 × 10^-6 m

Explanation:

Wavelength is found by dividing the speed of light by the frequency:

  λ = c/f = (3·10^8 m/s)/(1.0·10^14 Hz) = 3.0·10^-6 m

what happens to light when it travels from air into water

Answers

Answer:

Water is more dense than air. When water goes through a denser thing, the light is "bent" more towards the "normal" which is a straight, vertical line.

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Question 8 of 20
You pull a sled with a package on it across a snow-covered flat lawn. If you
apply a force of 77.4 N to the sled, it accelerates at 0.80 m/s? What is the
combined mass of the package and the sled? (Assume there is no friction)
A 96.75 kg
B. 61.92 kg
C. 62.40 kg
D. 52.50 kg
SUBMIT

Answers

The combined mass of the package and the sled is 96.75 kg (A).

non examples of kinetic energy

Answers

Answer:

Anything that isn't moving

Que. I : A mass of 10kg is suspended from the end of a steel of length 2m and radius 1mm, what is the elongation of the rod beyond its original length?

Que 2 : A pressure of sea water increases by 1.0atm for each 10metres increase in the depth. by what what percentage is the density of water increased in the deepest ocean of about 12km; compressibility = 5.0 × 10^-5 ​

Answers

Question 1; The elongation of the steel is approximately 0.3123 mm

Question 2; The percentage the density of water increased in the deepest

ocean is approximately 6.4%

The strategy of obtaining the above solution is presented as follows;

Que. 1; The given parameters are;

The mass of the suspended block, m = 10 kg

The length of the steel, l = 2 m

The radius of the steel, r = 1 mm = 1 × 10⁻³ m

The modulus of elasticity of steel, E = 200 GPa = 200 × 10⁹ Pa

The stress, σ, on the steel due to the mass, m, is given as follows;

\(\mathbf{\sigma = \dfrac{F}{A}}\)

Where;

F = The force acting on the steel = The weight of the mass

A = The cross sectional area of the steel = π·r²

∴ F = 10 kg × 9.81 m/s² = 98.1 N

A = π × (1 × 10⁻³)² = 3.14159 × 10⁻⁶ m²

Therefore;

σ = 98.1 N/(3.14159 × 10⁻⁶ m²) ≈ 31,226,226.2 Pa

We have;

\(\mathbf{ E = \dfrac{\sigma}{\epsilon}}\)

From which we have;

\(\epsilon = \dfrac{\sigma}{E}\)

Where;

= The tensile strain = Δl/l

Δl = The elongation of the steel

Therefore;

∈ = 31,226,226.2/(200 × 10^9) = 0.00015613113

∴ Δl = 0.00015613113 × 2 m = 0.00031226226 m = 0.31226226 mm

The elongation of the steel, Δl = 0.31226226 mm ≈ 0.3123 mm

Question 2

The given parameters are;

The change in pressure per unit depth, Δp = 1.0 atm per 10 meters

The depth of the ocean = 12 km = 12,000 m

The compressibility = 5.0 × 10⁻⁵

The formula for compressibility, C, is presented as follows;

\(C = \dfrac{1}{V} \times \dfrac{\partial V}{\partial P}\)

The change in pressure, \(\partial P\) = 12,000 m × 1.0 atm/(10 m) = 1,200 atm

For a unit volume, V = 1 m³

We get;

\(5 \times 10^{-5} = \dfrac{1}{1} \times \dfrac{\partial V}{1,200}\)

\(\partial V\) = 5 × 10⁻⁵ m³/(atm) × 1,200 = 0.06 m³

The volume occupied 1 m³ at 12,000 km depth = V - \(\partial V\)

∴ The volume occupied 1 m³ at 12,000 km depth = 1 m³ - 0.06 m³ = 0.94 m³

The percentage density increase, \(\partial\)ρ% = (m/0.94 - m/1)/m/1 × 100

∴ (1/0.94 - 1/1)/1/1 × 100 ≈ 6.4%

The percentage increase in density  ≈ 6.4%

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Question 6 (15 points)
According to Newton's second law, when the same force is applied to two objects of
different masses,
the object with greater mass will experience a great acceleration, and the object
with less mass will experience an even greater acceleration.
the object with greater mass will experience a smaller acceleration, and the
object with less mass will experience a greater acceleration.
the object with greater mass will experience a greater acceleration, and the
object with less mass will experience a smaller acceleration.
the object with greater mass will experience a small acceleration, and the object
with less mass will experience an even smaller acceleration.

Answers

Answer:

that would be newtons 3rd law

Explanation:

because its how it is

45. The modern model (view) of the atom
A. suggests that the atom is a solid mass.
B. describes the movement and boundary of electrons as a
cloud.
C. describes the movement of electrons as similar to

Answers

The modern model (view) of the atom describes the movement and boundary of electrons as a cloud. Option(B)

The modern model of the atom, known as the quantum mechanical model, describes the movement and boundary of electrons as a cloud. According to this model, electrons do not follow well-defined paths or orbits like in the previous Bohr model.

Instead, they are described by wave functions, which represent the probability distribution of finding an electron in a particular region around the nucleus. This probability distribution forms a cloud-like shape, known as an electron cloud, which represents the possible locations of the electrons within the atom.

The electron cloud provides information about the regions where electrons are likely to be found and their respective energy levels.

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(ii)
Calculate the amount of energy required to melt 15 kg of ice at 0 °C.
Specific latent heat of fusion of ice = 3.4 x 10J/kg.

Answers

Energy = m x L = 25 x 340 000 = 8.5 M J
(I think there is a power of 5 missing on your number)

The stimuli for kinesthesis is the __________ energy of joint and muscle movement. a. thermal b. electrical c. mechanical d. chemical

Answers

The complete statement is "The stimuli for kinesthesis is the mechanical energy of joint and muscle movement.". Option C. This is further explained below.

What is kinesthesis?

Generally, Kinesthetic helps in this way wherewith one's eyes closed, there is awareness of the locations of the body parts.

In conclusion, mechanical energy of joint and muscle movement is the stimuli for kinesthesis

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which of the following is the correct definition of stream gradient? group of answer choices the drop in elevation of a stream divided by the distance the water travels the increase in discharge of a stream per unit drop in elevation the distance traveled by water in a channel times a drop in elevation the water pressure at the bottom of the stream divided by the stream's width

Answers

Understanding stream gradient is crucial for predicting how a stream may change over time, responding to floods, and managingc water resoures.

Stream gradient is the drop in elevation of a stream divided by the distance the water resoures. It is the change in elevation of a stream over a certain distance, usually measured in feet per mile or meters per kilometer. A steep stream gradient indicates that the stream is flowing downhill at a rapid pace, while a gentle stream gradient suggests that the stream is flowing slowly and has a flatter slope.

Stream gradient plays an important role in determining the velocity of a stream, the type of erosion it causes, and the habitats it supports. High-gradient streamstend to have more turbulence, faster water flow, and more erosion, while low-gradient streams tend to have more deposition, slower water flow, and more sediment accumulation.

Migration is the term used to describe an organism's movement from one habitat or location to another. Moving from one place to another helps organisms boost their chances of surviving. The movement of organisms from one environment to another may be caused by a lack of resources necessary for their survival.

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The correct definition of stream gradient is: the drop in elevation of a stream divided by the distance the water travels. Stream gradient is an important factor in understanding water flow dynamics.

Stream gradient refers to the drop in elevation of a stream divided by the distance the water travels. This means that stream gradient is a measure of how steeply a stream is inclined, and it is calculated by dividing the change in elevation by the distance traveled. The other terms mentioned, water pressure and stream width, are not directly related to stream gradient but may impact other characteristics of the stream, such as flow rate and erosion.

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(a) If rA = 2 m, F = 8 N, and θ = 71°, what is the magnitude of the torque about location A, including units?
(b) If the force were perpendicular tovector rA, but gave the same torque as in the preceding question, what would its magnitude be?

Answers

If rA = 2 m, F = 8 N, and θ = 71°, 14.6 N·m is the magnitude of the torque about location A, including units.

The rotating equivalent of a force in physics and mechanics is called a torque. The moment of force is another name for it. It describes the rate at which the angular momentum of an isolated body would vary. In his famous adage, "Give me a lever and a place to stand, and I will move the Earth," Archimedes, who studied the use of levers, is credited with developing the idea. A torque can be thought of as a twist provided to an object with respect to a specified point, much like a linear force is a push or a pull applied to a body.

(a)τ = rA × F

      = |rA| |F| sinθ

      = 2 m × 8 N × sin(71°)

      ≈ 14.6 N·m

(b) |F| = τ / |rA|

         = 14.6 N·m / 2 m

        = 7.3 N

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A spring with a spring constant of 400 n / M has a mass hung on it so it stretches 8 cm. calculate how much mass the spring is supporting.

Answers

Answer:

3.3kg

Explanation:

Given parameters:

Spring constant = 400N/m

Extension  = 8cm  = 0.08m

Unknown:

Amount of mass the spring is supporting  = ?

Solution:

To solve this problem:

     F  = kE

F is the force

k is the spring constant

E is the extension

  So;

            F  = 400 x 0.08  = 32N

Mass;

       Force  = mass x acceleration due to gravity

          32  = mass x 9.8

  Mass = 3.3kg

The mass the spring is supporting is 3.27 Kg.

We'll begin by calculating the force acting on the spring.

Spring constant (K) = 400 N/mExtension (e) = 8cm = 8 / 100 = 0.08 mForce (F) =?

F = Ke

F = 400 × 0.08

F = 32 N

Finally, we shall determine the mass. This can be obtained as follow:

Force (F) = 32 NAcceleration due to gravity (g) = 9.8 m/s²Mass (m) =?

m = F / g

m = 32 / 9.8

m = 3.27 Kg

Therefore, the mass the spring is supporting is 3.27 Kg

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Elements in the same______
are more chemically similar.
THIS IS URGENT!!!!

Answers

Answer:

group

Explanation:

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They are in the same group

which of the following is not an example of mechanical action? group of answer choices electrically charged beaters of the bells on the clavecin electrique digital sampling machines levers and hammers inside an acoustic piano rotors (tonewheels) of a telharmonium

Answers

Digital sampling machines are not an example of mechanical action.

What is mechanical action?

Mechanical action refers to the physical movement of mechanical components to produce a sound or perform a specific function. This can include a wide range of actions, such as the striking of hammers on strings in a piano, the rotation of tonewheels in a Hammond organ, or the movement of valves in a trumpet.

Mechanical action can also be found in other types of machinery and equipment, and tools such as engines, gears, and levers, where physical movement is used to perform a specific task or function.

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How do you predict the magnet will behave if you break them into 2 pieces, and so on?

Answers

When you break a magnet into smaller pieces, each piece will still behave as a magnet with its own north and south poles.

If you break a magnet into two pieces, each piece will still behave as a magnet with a north and south pole. The

strength of the magnetic field may be weaker in each piece depending on the size and composition of the magnet.

However, if you continue to break the magnet into smaller and smaller pieces, eventually you will reach a point where

the individual pieces will no longer exhibit magnetic properties. This is because the magnetic field is created by the

alignment of electrons within the material, and when the material is too small, the alignment becomes random and the

magnetic field cancels out. Therefore, it is important to consider the size and composition of a magnet when predicting

its behavior.

To predict how a magnet will behave if you break it into 2 pieces, and so on, you can follow these steps:

1. Understand that a magnet has a north and a south pole.

2. Break the magnet into two pieces.

3. Observe that each piece now has its own north and south pole.

4. Predict that if you continue breaking the pieces, each new piece will still have a north and south pole.
In conclusion, when you break a magnet into smaller pieces, each piece will still behave as a magnet with its own north and south poles.

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