Assume that the half-life of an M&M is 15 seconds A. you start with M& M's, how many would be left unchanged after 1 minute? Show all work below

Nuclear Fission

Nuclear fission, subdivision of a heavy atomic nucleus, such as that of uranium or plutonium, into two fragments of roughly equal mass. The process is accompanied by the release of a large amount of energy. In nuclear fission the nucleus of an atom breaks up into two lighter nuclei.

Nuclear fission is a process where the nucleus of an atom is split into two or more smaller nuclei, known as fission products. The fission of heavy elements is an exothermic reaction, and huge amounts of energy are released in the process.

The volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL

The given chemical equation shows that two moles of K3PO4 react with three moles of NiCl2 to form one mole of Ni3(PO4)2 and six moles of KCl. Thus, the stoichiometric ratio of K3PO4 to NiCl2 is 2:3.

To calculate the volume of K3PO4 solution required to completely react with 114 mL of 0.0118 M NiCl2 solution, we need to use the concept of stoichiometry and the equation of concentration, C = n/V, where C is the concentration in moles per liter (M), n is the amount in moles, and V is the volume in liters.

First, we can calculate the amount of NiCl2 in 114 mL of 0.0118 M solution:

n(NiCl2) = C × V = 0.0118 M × 0.114 L = 0.0013452 mol

Next, we can use the stoichiometric ratio to calculate the amount of K3PO4 required:

n(K3PO4) = (2/3) × n(NiCl2) = (2/3) × 0.0013452 mol = 0.0008968 mol

Finally, we can use the equation of concentration to calculate the volume of 0.205 M K3PO4 solution required:

V(K3PO4) = n(K3PO4) / C(K3PO4) = 0.0008968 mol / 0.205 M = 0.00437 L

Therefore, the volume of 0.205 M K3PO4 solution necessary to completely react with 114 mL of 0.0118 M NiCl2 solution is 0.00437 L or 4.37 mL (to three significant figures).

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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ANSWER

EXPLANATION

Generally, heat transfer occurs from a region with higher temperature to a region with lower temperature.

In this situation, the metal has higher temperature than the water.

Hence, the energy will flow from the hot metal to the water

Therefore, the correct option is A

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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At the usual working conditions of 101.5 kPa and 21°C, the chemical oxygen generator system would generate roughly 220.84 litres of oxygen using 500 g of LiClO4.

We may use the ideal gas law and stoichiometry to calculate how many litres of oxygen are created by the chemical oxygen generator system employing 500 g of LiClO4.

We must first determine the moles of LiClO4. LiClO4 has a molar mass of approximately 106.39 g/mol. As a result, 4.704 mol of LiClO4 are produced from 500 g of LiClO4 using the formula: 500 g / 106.39 g/mol

We can see from the chemical equation that 1 mole of LiClO4 results in 2 moles of O2. 4.704 mol of LiClO4 will therefore result in:

2 mol O2 / 1 mol LiClO4 4.704 mol LiClO4 = 9.408 mol O2

The moles of O2 under the specified conditions must then be converted to volume. The ideal gas law, which goes as follows:

PV = nRT

Where:

P = pressure = 101.5 kPa

V = volume (in liters)

n = moles of gas = 9.408 mol

R = ideal gas constant = 8.314 J/(mol·K)

T = temperature = 21°C = 294 K (converted to Kelvin)

Rearranging the equation to solve for V:

V = (nRT) / P

V = (9.408 mol × 8.314 J/(mol·K) × 294 K) / (101.5 kPa × 1000 Pa/kPa)

Simplifying the units:

V = (9.408 × 8.314 × 294) / 101.5

V ≈ 220.84 liters

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Answer:

Isotopes are the atom of an element that have different numbers of neutrons but have a similar number of protons and electrons. The difference in the number of neutrons between the various isotopes means that various isotopes have different masses.

Explanation:

Answer:

3.0 × 10

\(3.0 \times {10}^{23} \)

molecules

Explanation:

there are many molecules

Explanation:

92 protons 92 electrons and 146 neutrons

Answer:

92 protons, 92 electrons, 146 neutrons

Explanation:

U-238 has 92 protons, 92 electrons, 146 neutrons.

The 238 is mass number talking about protons + neutrons. Uranium will always have 92 protons so the rest of the things are neutrons (146). Electrons will always equal protons if the element is neutral (no charge) and since no charge was given the numbers will match

Answer:

DNA , lipids , hydrocarbons, and the opposite would be molecules such as salt and wter

Answer:

True

Explanation:

the correct answer is True

The best way to measure the pH of a natural solution while out in a forest is to use a portable pH meter or pH test strips specifically designed for field use. These instruments provide accurate and reliable pH measurements and are convenient for outdoor applications.

1. Prepare the necessary equipment: Before heading out to the forest, gather the required tools. You will need a portable pH meter or pH test strips, as well as the necessary reagents or calibration solutions if using a pH meter.

2. Collect the sample: Locate the natural solution you want to measure the pH of, such as a stream, pond, or soil. Use a clean container to collect a representative sample of the solution.

3. Calibrate the pH meter (if applicable): If you are using a portable pH meter, it is essential to calibrate it before taking measurements. Follow the manufacturer's instructions to calibrate the meter using the provided calibration solutions.

4. Conduct the measurement: For pH meters, immerse the electrode into the collected sample. Allow some time for the reading to stabilize, and then record the pH value indicated on the meter's display.

5. Using pH test strips: If you are using pH test strips, dip the strip into the collected sample for the recommended amount of time. Remove the strip and compare the color change with the provided color chart. Determine the corresponding pH value from the chart.

6. Repeat for accuracy: To ensure reliability, repeat the measurement process at least once and compare the results. This step helps confirm the accuracy of your measurements.

7. Record and analyze the data: Note down the pH values obtained and any relevant observations. Analyze the data as needed for your research or monitoring purposes.

By following these steps and using the appropriate equipment, you can effectively measure the pH of a natural solution while in a forest setting.

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(a) shows both acidic and basic properties

(b) creates a neutral pH in solution

(c) is an ionic compound formed from an acid-base reaction

(d) can react with acid but not with a base

Answer:Chemistry is important for meeting our needs of food,clothing,shelter,health,energy,and clan air,water,and soil.

1) The pressure is 26.4 torr

2) The time is 24.4 s

A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more simpler substances. In other words, it is the opposite of a synthesis reaction, where two or more substances combine to form a more complex substance.

We know that;

\(lnPt =lnPo - kt\\lnPt = ln(450) - ( 4.5 x 10^-2 * 63)\\Pt = eln(450) - ( 4.5 x 10^-2 * 63)\\Pt = 26.4 torrln[1/3(450)] = ln 450 - (4.5 x 10^-2t)\\5 = 6.1 - 0.045t\\5 - 6.1 = - 0.045t\\t = 24.4 s\)

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Answer: d. Arrangement of grains

Explanation:

Edge:)))

Answer:

3.6

Explanation:

subtract both numbers!

Answer:Approx....

8

⋅

g

⋅

m

L

−

1

....

Explanation:

ρ

,

density

=

Mass

Volume

=

28.5

⋅

g

(

49.10

−

45.50

)

⋅

m

L

=

7.92

⋅

g

⋅

m

L

−

1

....

Explanation:

29 is not the best answer depends on the context and the rules for significant figures.

What is best answer?

The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:

Therefore, 29 is not the best answer.

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Answer:

The correct empirical formula, if the ratio is 1:1:3, is: FeS3

Explanation:

In this case, the empirical formula indicates the simplest whole-number ratio of atoms present in a compound. The ratio 1:1:3 means that for every 1 atom of the first element, there is 1 atom of the second element and 3 atoms of the third element. Among the options provided, FeS3 is the only one that fits this ratio.

To determine the empirical formula of the metal bromide formed, we need to first calculate the amount of chromium reacted and the amount of bromine reacted. The amount of chromium reacted can be calculated using its molar mass, which is 52 g/mol: 19.66 g chromium x (1 mol chromium / 52 g chromium) = 0.378 mol chromium.

Since there is excess bromine, all of the chromium would react with bromine to form the metal bromide. Therefore, the amount of bromine reacted can be calculated using the mass of the metal bromide formed:

110.3 g metal bromide x (1 mol metal bromide / molar mass of metal bromide) = amount of bromine reacted

We don't know the molar mass of the metal bromide yet, but we can use the law of conservation of mass to determine it. The mass of the metal bromide formed must equal the sum of the masses of the chromium and bromine that reacted.

110.3 g metal bromide = 19.66 g chromium + mass of bromine reacted mass of bromine reacted = 90.64 g

Now we can calculate the amount of bromine reacted:

90.64 g bromine x (1 mol bromine / 79.904 g bromine) = 1.133 mol bromine

To determine the empirical formula, we need to find the ratio of the moles of each element in the metal bromide.

Chromium: 0.378 mol
Bromine: 1.133 mol

To get a whole number ratio, we can divide both of these values by the smaller value (0.378 mol):

Chromium: 0.378 mol ÷ 0.378 mol = 1
Bromine: 1.133 mol ÷ 0.378 mol = 3

Therefore, the empirical formula of the metal bromide is CrBr3.

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Concentration: in simple terms, we can say that this is a measure of a solute dissolved in a particular amount of a solvent or of a solution.

We start analyzing these options:

Molarity can be defined as the moles of a solute per liter of a solution.

This is a concentration measurement.

-------------

% by mass can be defined as the mass of a solute per 100 grams of a solution.

It is also a concentration.

------------

Relative saturation: the ratio of the mass of water vapor present to the mass that would be present if the air were saturated at the same conditions of temperature and pressure.

Answer: Molarity and % by mass

Answer:

ΔG = -8.812 kJ/mol

Explanation:

To obtain the free energy of a reaction you can use the expression:

ΔG = ΔG° + RT ln Q

Where:

ΔG° is Standard Gibbs Free energy: -16.7kJ/mol = -16700J/mol

R is gas constant: 8.314472 J/molK

T is absolute temperature (37°C + 273.15 = 310.15K)

And Q is reaction quotient: 21.3

Replacing in the formula:

ΔG = ΔG° + RT ln Q

ΔG = -16700J/mol + 8.314472J/molK*310.15K ln 21.3

ΔG = -8812.4J/mol

To predict the products of such a reaction, see what happens if the chemical breaks into smaller, familiar products such as water, carbon dioxide, or any of the gaseous elements

AgNO3+Na2SO4→AgSO4+2NaNO3 is an exchange reaction.

Na + O2→ Na2O .

is an exchange reaction.

Thus, we refer to these processes as redox. Na is oxidized by losing electrons in reaction (a), while O is reduced by gaining electrons, forming O2-ions.

A single-displacement reaction would be Mg + HBr > MgBr2 + H2 HBr + Mg. In this process, magnesium creates magnesium bromide by swapping out hydrogen from HBr (MgBr2).

The decomposition process CuSO4(aq) + Zn(s) ZnSO4(aq) + Cu(s) is an illustration.

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At equilibrium, the HI concentration is 2.92 mol/L.

For the process H2(g)+CO2(g)updownarrow H2O+CO. at 1660 °C, the equilibrium constant KP is 4. In a 5 liter flask, 0.8 moles each of H2 and CO2 are first injected. Reactions occur in the following order with relation to H2: 1. In experiments 1 and 2, the reaction rate doubles when the initial concentration of H2 is doubled while the initial concentration of Cl2 is held constant.

H2(g) + I2(g) ⇌ 2HI(g)

c = [HI]² / [H2][I2]

At the specified temperature, c = 53.3, hence the following can be written:

53.3 = [HI]^2 / (0.400 mol/L) × (0.400 mol/L)

or, [HI]² = 53.3 × 0.16

or, [HI]² = 8.528

or, [HI] = sqrt(8.528) mol/L

or, [HI] = 2.92 mol/L

As a result, 2.92 mol/L of HI are present at equilibrium.

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Answer:

The answer is letter C

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 75 × 8

We have the final answer as

Hope this helps you

The measurement can be reported with three significant figures as follows: 3.90 mm.

The measurement can be reported with three significant figures as 3.90 mm. The record is a reading from a ruler that shows the specific point where the red line meets and the exact measurement is in three significant figures because none of them can be disregarded.

So, the accurate reading is 3.90. When the accurate reading is used, it ensures that the result of the measurement will be as expected.

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The molecular weight of unknown gas : 23.46 g/mol

Given

A vessel contains 10% of oxygen and 90% of an unknown gas.

diffuses rate of mixed gas = 86 s

diffuses rate of O₂ = 75 s

Required

the molecular weight of unknown gas (M)

Solution

The molecular weight of mixed gas :(M O₂=32 g/mol)

\(\tt 0.1\times 32+0.9\times M=3.2+0.9M\)

Graham's Law :

\(\tt \dfrac{r_{O_2}}{r_{mixed~gas}}=\sqrt{\dfrac{M_{mixed}}{M_{O_2}} }\\\\\dfrac{75}{86}=\sqrt{\dfrac{3.2+0.9M}{32} }\\\\0.76=\dfrac{3.2+0.9M}{32}\\\\24.32=3.2+0.9M\\\\21.12=0.9M\rightarrow M=23.46~g/mol\)