The plant utilization Baldwin is producing 2,325 units of bill next year be 155%.
What is plant utilization of electricity?The ratio of a piece of equipment's actual use time to its prospective use time is known as the utilisation factor, often referred to as the utilisation factor. The ratio is typically explained as being the sum of the energy used throughout time divided by the maximum amount that might be used.
The "end result" of the production, transmission, and distribution of electric power is utilisation. At the utilisation point, the energy transported by the transmission and distribution system is converted into usable work, light, heat, or a combination of these things.
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A man weighing 800 N is standing on a chair .In order to support the man what force is the chair exerting
Answer:
800 N upward
Explanation:
In order for the man to be able to stand up in the chair, the force would have to be the same as his weight (800 N) pushing in the opposite direction. So, if he is pushing down by standing on it than the force, 800 N, would be pushing upwards.
A resistor is a device that converts chemical energy into electrical energy. Is this true or false?
The device that converts chemical energy into electrical energy is a battery.
On the other hand, the resistor is a passive element that is mainly used to limit the current in a circuit.
A resistor doesn't convert chemical energy into electrical energy.
Therefore, we can conclude that the given statement is false
Assuming the Pressure Gradient Force is the same in both a trough and a ridge, the trough will have the faster winds. True False
False
The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.
However, the winds will not be the same in both features.
In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.
Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.
Here photosynthesis in a nutshell. Can you explain what is happening?
Answer:
Photosynthesis is the process of using water, carbon dioxide and sunlight to produce sugar. The process of photosynthesis requires specialized cellular structures called chloroplasts to capture energy from the Sun and converted into chemical energy.
Explanation:
MAX POINTS!!!
Lab: Kinetic Energy
Assignment: Lab Report
PLEASE GIVE FULL ESSAY
UNHELPFUL ANSWERS WILL BE REPORTED
Title: Kinetic Energy Lab Report
Abstract:
The Kinetic Energy Lab aimed to investigate the relationship between an object's mass and its kinetic energy. The experiment involved measuring the mass of different objects and calculating their respective kinetic energies using the formula KE = 0.5 * mass * velocity^2. The velocities of the objects were kept constant throughout the experiment. The results showed a clear correlation between mass and kinetic energy, confirming the theoretical understanding that kinetic energy is directly proportional to an object's mass.
Introduction:
The concept of kinetic energy is an essential aspect of physics, describing the energy possessed by an object due to its motion. According to the kinetic energy equation, the amount of kinetic energy depends on both the mass and velocity of the object. This experiment focused on exploring the relationship between an object's mass and its kinetic energy, keeping velocity constant. The objective was to determine if an increase in mass would result in a corresponding increase in kinetic energy.
Methodology:
1. Gathered various objects of different masses.
2. Measured and recorded the mass of each object using a calibrated balance.
3. Kept the velocity constant by using a consistent method to impart motion to the objects.
4. Calculated the kinetic energy of each object using the formula KE = 0.5 * mass * velocity^2.
5. Recorded the calculated kinetic energies for each object.
Results:
The data collected from the experiment is presented in Table 1 below.
Table 1: Mass and Kinetic Energy of Objects
Object Mass (kg) Kinetic Energy (J)
----------------------------------------
Object A 0.5 10.0
Object B 1.0 20.0
Object C 1.5 30.0
Object D 2.0 40.0
Discussion:
The results clearly demonstrate a direct relationship between mass and kinetic energy. As the mass of the objects increased, the kinetic energy also increased proportionally. This aligns with the theoretical understanding that kinetic energy is directly proportional to an object's mass. The experiment's findings support the equation KE = 0.5 * mass * velocity^2, where mass plays a crucial role in determining the amount of kinetic energy an object possesses. The constant velocity ensured that any observed differences in kinetic energy were solely due to variations in mass.
Conclusion:
The Kinetic Energy Lab successfully confirmed the relationship between an object's mass and its kinetic energy. The data collected and analyzed demonstrated that an increase in mass led to a corresponding increase in kinetic energy, while keeping velocity constant. The experiment's findings support the theoretical understanding of kinetic energy and provide a practical example of its application. This knowledge contributes to a deeper comprehension of energy and motion in the field of physics.
References:
[Include any references or sources used in the lab report, such as textbooks or scientific articles.]
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Please help!
Tell me types of minor sports except football,
basketball,volleyball,
handball,rugby and waterpolo
ice hokey, indoor soccer
Saul applies a force at 10° to the horizontal to move a heavy box 3 m horizontally. He does 100J of me- chanical work. What is the magnitude of the force he applied?
The magnitude of the force Saul applied to move the heavy box is approximately 32.56 N. We can use the work-energy principle.
To find the magnitude of the force Saul applied, we can use the work-energy principle. The work done on an object is equal to the force applied multiplied by the displacement of the object in the direction of the force. Mathematically, it can be expressed as:
Work = Force x Displacement x cos(theta),
where theta is the angle between the force and the displacement vectors.
In this case, the work done (W) is given as 100 J, the displacement (d) is 3 m, and the angle (theta) is 10°.
100 J = Force x 3 m x cos(10°).
To solve for the force (F), we rearrange the equation:
Force = 100 J / (3 m x cos(10°)).
Using a calculator, we can find the magnitude of the force Saul applied by substituting the values:
Force ≈ 32.56 N.
Therefore, the magnitude of the force Saul applied to move the heavy box is approximately 32.56 N.
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What happens when a proton is placed directly in the path of the proton cannon?
Answer:
Proton is positively charged and is thus, attracted to the negative plate. Hence, it will take the path D after leaving the region between the charged plates.When a proton is placed directly in the path of the proton cannon, it will experience a strong electromagnetic force. The proton cannon emits a beam of protons at high energy and velocity. When the proton in the path of the cannon interacts with the beam, there will be a collision between the two protons.
During the collision, the protons may undergo a process called scattering, where they change direction and momentum. The exact outcome of the collision depends on the energy and angle of the incoming proton, as well as the properties of the target proton. It is possible that the protons may scatter off each other, transferring energy and momentum in the process.
In some cases, the collision may result in the absorption of the incoming proton by the target proton. This can lead to the formation of a more massive particle or the emission of other particles. The specifics of the interaction will depend on the energy and conditions of the proton cannon and the characteristics of the protons involved.
Overall, placing a proton directly in the path of a proton cannon will result in a collision and potential scattering or absorption of the protons, causing changes in their momentum and possibly leading to the creation of other particles.
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♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
Sumin runs 50 meters from her house to the park down the street. She then keeps running in the same direction to her friend's house 150 Meters from the park. She then turns around and goes back to the park. What is Sumin's average velocity during her run if it takes her 2 minutes to complete?
A. 25 m/s
B.2.92 m/s
C.3.33 m/s
D.0.417 m/s
Answer:
d. 0.417 m/s
Explanation:
v= ▲x/t
(350-150)/120 s
= .417 m/s
Which of these samples of water has the most internal energy?
1kg Liquid Water
2kg Steam
1kg Steam
2kg Ice
Answer:
1kg steam will have the maximum energy
Calculate the orbital period of a satellite circling the Earth at an altitude of 3500 km. Answer to the nearest minute. Show your work.
The orbital period of the satellite circling the Earth at an altitude of 3500 km is 163 minutes
How do i determine the orbital period?The orbital period for the satellite circling the Earth at an altitude of 3500 km can be obtained as follow:
Altitude = 3500 kmRadius of earth = 6400 KmSemi-major axis (a) = Radius + Altitude = 6400 + 3500 = 9900 Km = 9900 × 1000 = 9900000 mGravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²Mass of earth (M) = 5.987×10²⁴ KgOrbital period (T) = ?T² = (4π² / GM) × a³
T² = [(4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)] × 9900000³
Take the square root of both sides
T = √[((4 × 3.14²) / (6.67×10¯¹¹ × 5.987×10²⁴)) × 9900000³]
T = 9789.15 s
Divide by 60 to express in minutes
T = 9789.15 / 60
T = 163 minutes
Thus, we can conclude that the orbital period of the satellite is 163 minutes
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In the mechanism shown here, the collar is pin joint on the link AC and is sliding along the link BD. Link AC at this instant is rotating about pin A with an angular velocity of ω
1
=5 rad/s and angular acceleration of α
1
=10rad/s
2
. If AC=AB=1m; determine angular velocity and acceleration of ω
2
and α
2
.
The angular velocity of link BD is 2.89 rad/s and the angular acceleration is 0 rad/s².
The expression for angular acceleration can be calculated by applying the vector method.
Here, the vector method of angular velocity will be applied to get the expression for angular velocity ω2 and angular acceleration α2 as follows:
Step 1:Velocity of the collar relative to B and velocity of point A of the link AB and collar can be written as VB = VA + AB X ω1
Here, AB is perpendicular to the plane of rotation, and the velocity of A relative to the collar is ω1 * AB.
Therefore, AB X ω1 = 0 as AB is parallel to AB. Thus, VB = VA.
Then, the velocity of point B can be given as:
VB = BD X ω2Hence, BD X ω2 = VA, we get: ω2 = VA / BD
Step 2: Acceleration of point A relative to collar: AB X α1 = 0 (AB parallel to the plane of rotation)
AA = AB X ω1 X ω1=0
Acceleration of point A relative to C: AC X α1 = AC X 10α2=0
Since, AC=AB=1m
α2=0
Acceleration of collar C relative to point B: BD X α2=VA
Here, α2 = 0, and VB = VA = 5m/s.
Hence:BD * 0 = 5m/sω2 = VA / BD= 5 / (1.732 x 1)=2.89 rad/s
Thus, the angular velocity of link BD is 2.89 rad/s and the angular acceleration is 0 rad/s².
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pulsed lasers are used for science and medicine produce very brief bursts of electromagnetic energy. a) if the laser light wavelength is 1062 nm and the pulse lasts for 38 ps, how many wavelengths are found within the laser pulse? b) how brief would the pulse need to be to fit only one wavelength?
Answer:
To answer your question:
a) The formula to calculate the number of wavelengths within a laser pulse is:
number of wavelengths = pulse duration / wavelength
Plugging in the values given in the question, we get:
number of wavelengths = 38 ps / 1062 nm
Converting picoseconds to seconds and nanometers to meters, we get:
number of wavelengths = 38 x 10^-12 s / 1062 x 10^-9 m
number of wavelengths = 0.0358
Therefore, there are approximately 0.0358 wavelengths within the laser pulse.
b) To fit only one wavelength, the pulse duration would need to be equal to the wavelength. The formula to calculate the pulse duration is:
pulse duration = wavelength
Plugging in the value given in the question, we get:
pulse duration = 1062 nm
Converting nanometers to picoseconds using the speed of light ©, we get:
pulse duration = wavelength / c
pulse duration = 1062 x 10^-9 m / 3 x 10^8 m/s
pulse duration = 3.54 x 10^-12 s
Therefore, the pulse would need to be approximately 3.54 ps long to fit only one wavelength.
I hope this helps
Determine the total displacement of a dog that runs 15 m north, 6 m south, then 8 m north.
Answer:
the displacement Is 17m north
Explanation:
15-6=9
9+8=17
The total displacement of a dog that runs 15 meters north, 6 meters south, then 8 meters north would be 17 meters because displacement is measured by the shortest distance between the initial and final position of the moving object.
What is displacement?An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.
Displacement describes this shift in location.
Displacement is a vector quantity.
Since the displacement is determined by the smallest distance between the moving object's original and final positions, a dog traveling 15 meters north, 6 meters south, then 8 meters north would move a total of 17 meters.
Thus, the total displacement of the dog comes out to be 17 meters.
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A wooden brick with mass M is suspended at the end of cords as shown above. A bullet with mass m is fired toward the brick with speed v0. The bullet collides with the brick embedding itself into the brick. The brick-bullet combination will swing upward after the collision. Consider the brick, earth, and bullet as part of a system. Express your algebraic answers in terms of quantities given and fundamental constants.
(a) During the collision of the brick and the bullet, compare the magnitude and direction of the impulse acting on the brick to the impulse acting on the bullet. Justify your answer.
(b) Determine the magnitude of the velocity v of the brick-bullet combination just after the collision.
c) Determine the ratio of the final kinetic energy of the brick-bullet combination immediately after the collision to the initial kinetic energy of the brick-bullet combination.
(d) Determine the maximum vertical position above the initial position reached by the brick-bullet combination.
BoldItalicUnderline
Answer: the answer given below
(a) Explanation: The impulse on an object is given by the change in momentum of the object. Before the collision, the bullet has momentum p1 = mv0 and the brick has momentum p2 = 0, since it is stationary. After the collision, the combined bullet-brick system has momentum p3.
Conservation of momentum requires that the total momentum before the collision is equal to the total momentum after the collision:
p1 + p2 = p3
mv0 + 0 = (m + M)V
where V is the velocity of the combined bullet-brick system after the collision. Solving for V, we get:
V = (mv0) / (m + M)
The impulse on the bullet during the collision is equal to the change in momentum of the bullet:
J_bullet = p3 - p1 = (m + M)V - mv0
Substituting the expression for V we found earlier:
J_bullet = (m + M)(mv0) / (m + M) - mv0 = 0
Therefore, the impulse on the bullet is zero during the collision.
On the other hand, the impulse on the brick during the collision is:
J_brick = p3 - p2 = (m + M)V - 0 = (m + M)(mv0) / (m + M) = mv0
Therefore, the magnitude of the impulse acting on the brick is equal to the initial momentum of the bullet, mv0, and it is in the same direction as the initial velocity of the bullet.
In summary, during the collision of the bullet and the brick, the impulse acting on the bullet is zero, while the impulse acting on the brick is mv0 in the direction of the initial velocity of the bullet.
(b) We can use the principle of conservation of momentum to solve for the velocity of the brick-bullet combination just after the collision. The total momentum of the system (bullet, brick, and Earth) is conserved before and after the collision. Initially, only the bullet has momentum, which is given by p1 = m*v0, and the momentum of the brick and Earth is zero. After the collision, the bullet becomes embedded in the brick, and the combined system of the brick-bullet has momentum p2. Since the momentum of the Earth is negligible compared to that of the bullet and brick, we can treat the system as closed and apply conservation of momentum:
p1 = p2
m*v0 = (M + m)*v
where v is the velocity of the combined system just after the collision.
Solving for v, we get:
v = (m*v0) / (M + m)
Therefore, the magnitude of the velocity of the brick-bullet combination just after the collision is:
|v| = |(m*v0) / (M + m)|
The direction of the velocity is upward, as the system swings up after the collision due to the conservation of momentum.
(c) The initial kinetic energy of the system is the kinetic energy of the bullet just before the collision, which is given by:
KE1 = (1/2)mv0^2
The final kinetic energy of the system is the kinetic energy of the combined brick-bullet system just after the collision, which is given by:
KE2 = (1/2)*(M + m)*v^2
Substituting the expression we found for v:
KE2 = (1/2)(M + m)[(mv0) / (M + m)]^2
KE2 = (1/2)(m*v0^2) / (1 + M/m)
The ratio of the final kinetic energy to the initial kinetic energy is:
KE2 / KE1 = [(1/2)(mv0^2) / (1 + M/m)] / [(1/2)mv0^2]
KE2 / KE1 = 1 / (1 + M/m)
Therefore, the ratio of the final kinetic energy of the brick-bullet combination immediately after the collision to the initial kinetic energy of the brick-bullet combination is:
KE2 / KE1 = 1 / (1 + M/m)
(d)To determine the maximum vertical position reached by the brick-bullet combination, we can use conservation of energy, assuming there is no energy loss due to friction or other dissipative forces. At the maximum height, the kinetic energy of the system is zero, and all the initial kinetic energy has been converted to potential energy due to the height above the initial position.
The initial total energy of the system is the sum of the initial kinetic energy of the bullet and the gravitational potential energy of the brick:
E1 = (1/2)mv0^2 + Mgh1
where h1 is the initial height of the brick above the ground, and g is the acceleration due to gravity.
At the maximum height, the final total energy of the system is the potential energy due to the height above the ground:
E2 = (M + m)gh2
where h2 is the maximum height reached by the brick-bullet combination above the initial position.
Since there is no energy loss, we can set the initial energy equal to the final energy:
E1 = E2
Substituting the expressions for E1 and E2 and solving for h2, we get:
(M + m)gh2 = (1/2)mv0^2 + Mgh1
h2 = [(1/2)mv0^2 + Mgh1] / [(M + m)*g]
Simplifying, we get:
h2 = (1/2)v0^2 / g + h1(M/m) / (1 + M/m)
Therefore, the maximum vertical position above the initial position reached by the brick-bullet combination is:
h2 = (1/2)v0^2 / g + h1(M/m) / (1 + M/m)
Hope this helps :)
What is another name for the first law of motion? why is it given that name?
Another name for the first law of motion is the law of inertia. It is given this name because it describes the tendency of an object to remain at rest or in uniform motion in a straight line unless acted upon by an external force.
Inertia is the property of matter that makes it resist changes in motion, whether that motion is at rest or moving at a constant speed in a straight line. The law of inertia is the foundation of classical mechanics, which is the branch of physics that deals with the motion of macroscopic objects. The first law of motion is often attributed to Sir Isaac Newton, who formulated the three laws of motion in the late 17th century.
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Hello people ~
A hollow metal sphere of radius 5 cm is charged so that the potential on its surface is 10 V. The potential at the centre of the sphere is
(a) 0 V
(b) 10 V
(c) Same as at point 5 cm away from the surface
(d) Same as at point 25 cm away from the surface
Answer:
10V
Explanation:
Hollow sphere means two spherical surfaces inside
So charge on the surface =Charge at any point in sphere i.e voltage remains constant.
So
potential at centre=Potential at surface=10V
Option B is correct
A bat strikes a 0.145 kg baseball with force of 5800 N. What acceleration does the baseball experience?
Answer:
40,000 m/s²
Explanation:
The formula is given as Force = mass × acceleration, so then acceleration = Force / mass.
Therefore...
5800 N ÷ 0.145 kg = 40,000 m/s²
The proximal convoluted tubule reabsorbs what percentage of filtered water? 65%
66%
67%
68%
The proximal convoluted tubule reabsorbs approximately 65% of filtered water.
The proximal convoluted tubule (PCT) is a structure in the nephron, which is the functional unit of the kidney responsible for filtering blood and producing urine. The PCT is located in the renal cortex and is the first part of the nephron after the glomerulus.
The PCT plays a crucial role in the process of urine formation by reabsorbing important substances such as glucose, amino acids, and salts from the filtrate back into the bloodstream. This process is known as tubular reabsorption and is essential for maintaining the body's fluid and electrolyte balance.
The PCT has a highly convoluted structure, which increases its surface area and allows for more efficient reabsorption. The cells lining the PCT have numerous microvilli, which further increase their surface area and facilitate the transport of substances across the tubule epithelium.
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9.27 a series rlc bandpass filter has half-power frequencies at 1 khz and 10 khz. if the input impedance at resonance is 6 , what are the values of r, l, and c?
9.27 a series rlc bandpass filter has half-power frequencies at 1 kHz and 10 kHz. if the input impedance at resonance is 6 , Then
the values of R, L, and C are:
R = 0 Ω
L = 22.17 mH
C = 4.057 µF
Half-power frequencies f1 = 1 kHz, f2 = 10 kHz
Input impedance at resonance Z = 6 Ω
We know that the half-power frequencies of a series RLC bandpass filter are given by the following formula:
f1,2 = (1/2π) × √(1/(LC) - R²/(4L²))
At resonance, the impedance is purely resistive, and is given by:
Z = R
Substituting the given values into the above equations, we can solve for the unknowns:
f1 = 1 kHz, f2 = 10 kHz
Z = 6 Ω
f1,2 = (1/2π) × √(1/(LC) - R²/(4L²))
f1 = (1/2π)× √(1/(LC) - R²/(4L²))
f2 = (1/2π) × √(1/(LC) - R²/(4L²))
Z = R
Substituting the values of f1 and f2, we get:
1 kHz = (1/2π) × √(1/(LC) - R²/(4L²))
10 kHz = (1/2π)× √(1/(LC) - R²/(4L²))
Dividing the second equation by the first equation, we get:
10/1 = √[(1/(LC) - R²/(4L²)) / (1/(LC) - R²/(4L²))]
10/1 = 1
This means that R²/(4L²) = 0, and thus R = 0.
Substituting R = 0 into the first equation, we get:
1 kHz = (1/2π) × √(1/(LC))
Squaring both sides, we get:
(1 kHz)² = 1/(4π²LC)
LC = 1/(4π²(1 kHz)²)
LC = 4.057 µF
Substituting this value of LC into the equation for f1 or f2, we get:
1 kHz = (1/2π) ×√(1/(4.057 µF× L))
Squaring both sides and solving for L, we get:
L = 22.17 mH
Therefore, the values of R, L, and C are:
R = 0 Ω
L = 22.17 mH
C = 4.057 µF
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True or False | The three types of organ pipes are reed pipes flue pipes, and rank pipes
The given statement "The three types of organ pipes are reed pipes flue pipes, and rank pipes" is False.
An organ pipe is a musical instrument that produces sound by vibrating columns of air. There are three main types of organ pipes: reed pipes, flue pipes, and hybrid pipes.
Reed pipes produce sound by using a vibrating reed, which is a thin piece of metal that is held in place over a small opening in the pipe. When air is blown through the pipe, it causes the reed to vibrate and produce sound. This type of pipe is commonly found in woodwind instruments such as clarinets and saxophones.
Flue pipes, on the other hand, produce sound by blowing a stream of air across a sharp edge, similar to the way air flows across the edge of a whistle. This type of pipe is commonly found in flutes and recorders.
Hybrid pipes are a combination of reed and flue pipes. They use a reed to excite the air column in the pipe, but the sound is then produced using a flue mechanism.
Rank pipes, as mentioned earlier, are not a type of organ pipe, but rather a way of arranging the pipes within an organ. Rank pipes refer to a set of pipes that are arranged in a specific order, typically according to their pitch or timbre.
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An L C circuit includes a 0.025-μF capacitor and a 340-μH inductor. (a) If the peak capacitor voltage is 190 V, what's the peak inductor current? (b) How long after the voltage peak does the current peak occur?
To calculate the peak inductor current, use the formula I = V / (ωL) with the peak capacitor voltage and inductance. The time delay can be found by calculating the time period T using T = 2π / ω, and then taking T/4 as the delay between the voltage and current peaks.
How can we calculate the peak inductor current and the time delay between the voltage peak?
An L C circuit consists of a 0.025-μF capacitor and a 340-μH inductor. We can use the formula for the peak current in an L C circuit to calculate the peak inductor current.
The formula is given by I = V / (ωL), where I is the peak current, V is the peak voltage across the capacitor, ω is the angular frequency, and L is the inductance.
(a) Using the given values, the peak capacitor voltage is 190 V. Substituting this value into the formula, we get I = 190 / (ω ˣ 340 ˣ10 ⁻⁶.
(b) To determine the time delay between the voltage peak and the current peak, we need to find the time period of the circuit. The time period T is given by T = 2π / ω. Since we know the angular frequency ω, we can calculate the time delay as T/4.
To provide a more precise answer, the values of the angular frequency ω and the time delay would need to be provided.
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The driver of a car made an emergency stop on a straight horizontal road. The wheels locked and the car skidded to a stop. The marks made by the rubber tires on the dry asphalt are 16 meters long, and the cars mass is 1200 kilograms.
1. Determine the weight of the car.
2. Calculate the magnitude of the frictional force the road applied to the car in stopping it.
The weight of the car is 11760N.
The frictional force that the road used to stop the car was 1042.5 N in size.
What is the size of the frictional force acting on the box?The weight of the object resting normal to the surface multiplied by the coefficient of friction for the contacting surfaces yields the friction force's magnitude. Any forces exerted on the box are opposed by the force's parallel direction to the surface.
The weight of the object and the degree of surface abrasion have an impact on the frictional force's magnitude. Increased roughness will result in increased friction force.
Weight of the car is 1200×9.8 = 11760N.
The magnitude of the frictional force the road applied to the car in stopping it is
W = KE
Fr · Δx = 1/2 · m · v²
Fr = 1/2 · m · v²/Δx
Fr = 1/2. 1200. (27.8)²/16
Fr = 1042.5 N.
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why is a pencil bent when bent in water
Answer:
Refraction
Explanation:
A pencil bends when it enters the water media due to the phenomenon of refraction.
Refraction is one of the properties of waves. Refraction of light occurs which it crosses from a region having different density values. Water is denser than air. As light moves from air to wave it becomes refractedCompute the estimated energy expenditure (ml ⋅ kg−1 ⋅ min −1) during horizontal treadmill walking for the following examples:
a. Treadmill speed = 50 m ⋅ min −1 Subject’s weight = 62 kg
b. Treadmill speed = 80 m ⋅ min −1 Subject’s weight = 75 kg
To estimate the energy expenditure during horizontal treadmill walking, we can use the Metabolic Equivalent of Task (MET) method.
MET is a unit that represents the metabolic rate, where 1 MET is equivalent to the energy expenditure at rest. The formula to estimate energy expenditure in METs is:
Energy Expenditure (METs) = Treadmill Speed (m/min) / 3.5
To convert the energy expenditure to ml ⋅ kg^(-1) ⋅ min^(-1), we multiply the MET value by 3.5.
Let's calculate the estimated energy expenditure for the given examples:
a) Treadmill speed = 50 m ⋅ min^(-1), Subject's weight = 62 kg
Energy Expenditure (METs) = 50 / 3.5 ≈ 14.29 METs
Estimated Energy Expenditure = 14.29 METs * 3.5 ml ⋅ kg^(-1) ⋅ min^(-1) ≈ 50 ml ⋅ kg^(-1) ⋅ min^(-1)
b) Treadmill speed = 80 m ⋅ min^(-1), Subject's weight = 75 kg
Energy Expenditure (METs) = 80 / 3.5 ≈ 22.86 METs
Estimated Energy Expenditure = 22.86 METs * 3.5 ml ⋅ kg^(-1) ⋅ min^(-1) ≈ 80 ml ⋅ kg^(-1) ⋅ min^(-1)
Therefore, the estimated energy expenditure during horizontal treadmill walking is approximately 50 ml ⋅ kg^(-1) ⋅ min^(-1) for a treadmill speed of 50 m ⋅ min^(-1) and a subject's weight of 62 kg, and approximately 80 ml ⋅ kg^(-1) ⋅ min^(-1) for a treadmill speed of 80 m ⋅ min^(-1) and a subject's weight of 75 kg.
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A 120 N accelerates an object 1. 2 m/s? What is the mass of the object?
Answer:
m = 100 kg
Explanation:
F = ma
120 = m × 1.2
m = 120 ÷ 1.2
m = 100 kg
An object on a planet has a mass of 243 kg. What is the acceleration of the
object, if the radius of the planet is 2.32 x 10^7 m, and the mass of planet is
6.35 x 10^30 kg? Estimate G as 6.67 x 10^-11 N (m/kg)^2
Answer:
The gravitational acceleration of a planet of mass M and radius R
a = G*M/R^2.
In this case we have:
G = 6.67 x 10^-11 N (m/kg)^2
R = 2.32 x 10^7 m
M = 6.35 x 10^30 kg
Now we can compute:
a = (6.67*6.35/2.32^2)x10^(-11 + 30 - 2*7) m/s^2 = 786,907.32 m/s^2
The acceleration does not depend on the mass of the object.
The acceleration of the object is \(3.01*10^{-23}m/s^{2} \)
The gravitational acceleration of object is computed by formula shown below,
\(acceleration(a)=G\frac{m}{R^{2} } \)
Where G is gravitational constant, m is mass of object and R is radius of planet.
Given that, \(G=6.67*10^{-11}Nm^{2}/Kg^{2} ,m=243Kg,R=2.32*10^{7} m\)
Substitute values in formula.
\(a=6.67*10^{-11}*\frac{243}{(2.32*10^{7})^{2} } \\ \\ a=6.67*10^{-11}*4.51*10^{-13}\\ \\ a=3.01*10^{-23}m/s^{2} \)
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the induced emg in a single loop of wire has a magnitude of 1.48 V when the magnetic dlux is changed 0.850 to 0.110. How much time is required for this change in flux
The time required for the change in magnetic flux is 0.5 seconds.
The induced emf in a single loop of wire is given by the equation ΔΦ/Δt, where ΔΦ represents the change in magnetic flux and Δt represents the change in time. In this case, the change in magnetic flux is given as 0.850 - 0.110 = 0.740 Wb. The magnitude of the induced emf is given as 1.48 V.
To find the time required for this change in flux, we can rearrange the equation to solve for Δt:
Δt = ΔΦ / (induced emf)
Plugging in the given values:
Δt = 0.740 Wb / 1.48 V
Calculating this gives us:
Δt = 0.5 seconds
Therefore, the time required for the change in magnetic flux is 0.5 seconds.
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Which of the following statements is true regarding Newton's First Law? Select all that apply.
A. Newton's First Law is sometimes called the Law of Inertia.
B. According to Newton's First Law, an object at rest will remain at rest.
C.
According to Newton's First Law, a net force is required to cause a change in the motion of an object.
D. According to newton's First Law, an object in motion will continue moving at the same speed in the same direction.
All the following statements are true regarding Newton's First Law, therefore all the given options are correct.
What is Newton's first law?According to Newton's first law, until pushed to alter its condition by the intervention of an external force, every object will continue to be at rest or in uniform motion along a single direction.
Inertia is the propensity to resist changes in a condition of motion. There won't be any net force acting on the item if all the external forces balance each other out. There won't be any net force acting on the item if all the external forces balance each other out.
The item will maintain a constant velocity if there is no net force exerted on it.
As given all the following statements are true for Newton's first law
Newton's First Law is sometimes called the Law of Inertia.
According to Newton's First Law, an object at rest will remain at rest.
According to Newton's First Law, a net force is required to cause a change in the motion of an object.
According to newton's First Law, an object in motion will continue moving at the same speed in the same direction.
Thus, all the given options are correct about Newton's first law.
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magine that you took a road trip. Based on the information in the table, what was the average speed of your car?
Time Mile marker
3:00 pm 32
8:00 pm 155
Imagine that you took a road trip. Based on the information in the table, what was the average speed of your car? 195 Time Mile marker 3:00 pm 28 8:00 pm Express your answer to three significant figures and include the appropriate units.
Based on the information in the table, we can calculate the total distance traveled by subtracting the initial mile marker from the final mile marker. 155 32 123 miles We can calculate the total time traveled by subtracting the starting time from the ending time. 8:00 pm 3:00 pm 5 hours to find the average speed, we can divide the total distance traveled by the total time traveled. 123 miles 5 hours 24.6 miles per hour Therefore, the average speed of the car during the road trip was 24.6 miles per hour.
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