Assignment No. 2 In detail describe the following for predicting yield of ductile materials: (I) Maximum Shearing Stress Criteril, and (2) Maximum Distortion Energy Criteria. Complelely derive the equ

Using APA reference style, the references is attached below from Feldman, R. S. (2013) to American Psychology Association (2020)

APA reference style is a style of citing sources used by the American Psychological Association. It is primarily used in the social sciences and includes guidelines for citing sources both within the text of a document and in the reference list at the end of the document. The guidelines provide a consistent way of citing sources to make it easier for readers to identify and locate the sources cited in a document.

In the given problem, if we need to write the reference using APA style, it will take this format below

Reference Page:

Feldman, R. S. (2013). Psychology and your life (2nd ed.). New York, NY: McGraw Hill Companies.

Frontline. (n.d.). League of denial. Retrieved from https://www.pbs.org/wgbh/frontline/film/league-of-denial/

Friends. (2004). The one after Joey and Rachel kiss [Television series episode]. In D. Crane, & M. Kauffman (Executive producers), Friends. Burbank, CA: Warner Bros. Television.

Silver Linings Playbook. (2012). [Motion Picture]. United States: The Weinstein Company.

U.S. Energy Information Administration. (2013). Annual energy outlook 2013 with projections to 2040. Retrieved from http://www.eia.gov/forecasts/aeo/er/pdf/0383er(2013).pdf

Snickers. (2013, April 2). You’re not you when you’re hungry [Video file]. Retrieved from https://youtu.be/2rF_FRCd_LA

American Psychological Association. (2020). Publication manual of the American Psychological Association (7th ed.). doi:10.1037/0000165-000

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(a) Create the table for the relation Order:

```sql

CREATE TABLE Order (

 Order# INT,

 Odate DATE,

 Cust# INT,

 Ord_Amt DECIMAL(10, 2),

 PRIMARY KEY (Order#),

 FOREIGN KEY (Cust#) REFERENCES Customer(Cust#)

);

```

In this query, we create a table named "Order" with the specified attributes and data types. The Order# attribute is set as the primary key, and the Cust# attribute is set as a foreign key referencing the Cust# attribute in the Customer table.

(b) List Cust#, Cname, City for all the customers:

```sql

SELECT Cust#, Cname, City

FROM Customer;

```

This query selects the Cust#, Cname, and City attributes from the Customer table, displaying all rows in the table.

(c) List the Order# and Ship_date for all orders shipped from Warehouse# "W2":

```sql

SELECT Order#, Ship_date

FROM Shipment

WHERE Warehouse# = 'W2';

```

This query selects the Order# and Ship_date attributes from the Shipment table, filtering the results to only include rows where the Warehouse# is equal to 'W2'.

(d) For all the order items purchased by the customer whose Cust#='C001', list the Order#, Item#, and Qty for those items that have a unit price greater than 100:

```sql

SELECT O.Order#, OI.Item#, OI.Qty

FROM Order O

JOIN Order_Item OI ON O.Order# = OI.Order#

JOIN Item I ON OI.Item# = I.Item#

WHERE O.Cust# = 'C001' AND I.Unit_Price > 100;

```

This query joins the Order, Order_Item, and Item tables based on their corresponding keys and selects the Order#, Item#, and Qty attributes. It includes a condition to filter the results to only include rows where the Cust# is 'C001' and the Unit_Price is greater than 100 in the Item table.

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Answer:

there is someone inside the car

Answer:

The power that fluid supplies to the turbine is 1752.825 kilowatts.

Explanation:

A turbine is a device that works usually at steady state. Given that heat losses exists and changes in kinetic energy are not negligible, the following expression allows us to determine the power supplied by the fluid to the turbine by the First Law of Thermodynamics:

\(-\dot Q_{loss} - \dot W_{out} + \dot m \cdot \left[(h_{in}-h_{out}) + \frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right] = 0\)

Output power is cleared:

\(\dot W_{out} = -\dot Q_{loss} + \dot m \cdot \left[(h_{in}-h_{out})+\frac{1}{2}\cdot (v_{in}^{2}-v_{out}^{2}) \right]\)

If \(\dot Q_{loss} = 0.3\,kW\), \(\dot m = 0.85\,\frac{kg}{s}\), \(h_{in} = 2800\,\frac{kJ}{kg}\), \(h_{out} = 1550\,\frac{kJ}{kg}\), \(v_{in} = 45\,\frac{m}{s}\) and \(v_{out} = 20\,\frac{m}{s}\), then:

\(\dot W_{out} = -0.3\,kW + \left(0.85\,\frac{kg}{s} \right)\cdot \left\{\left(2800\,\frac{kJ}{kg}-1550\,\frac{kJ}{kg} \right)+\frac{1}{2}\cdot \left[\left(45\,\frac{m}{s} \right)^{2}-\left(20\,\frac{m}{s} \right)^{2}\right] \right\}\)

\(\dot W_{out} = 1752.825\,kW\)

The power that fluid supplies to the turbine is 1752.825 kilowatts.

The long slot that is present in a 15-ampere, 125-volt, receptacle is known as the grounded conductor.

The long slot is the grounded conductor that is placed in the receptacle to meet with relevant National Electrical Codes (NEC).

The grounded conductor is meant to connect to the ground either directly or indirectly for safety purposes.

In conclusion, option A is correct.

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Answer:

attached below is the detailed solution

Explanation:

Attached below is a detailed solution a BCD decoder( 4 inputs and 7 outputs ) used to drive a seven digit display

Prime Implicants are gotten from the maximum adjacent cells found in the K -map WHILE essential prime implicants  ( ESI ) are prime implicants that combine with a minimum of one term which cannot be covered by another prime implicant.

D)For a : essential implicants includes all its implicants

  For d : essential implicants includes all its prime implicants

We may calculate the temperature of the bar tip using the boundary conditions and the one-dimensional heat conduction equation: q/A = -k(dT/dx).

Boundary circumstances: Particular actions at x0 = 0 and L: 1. Temperature constant: u(x0,t) = T for t > 0. 2. Insulated end: for t > 0, ux

Q = hA(T s - T air), where (x0,t) = 0

When we combine these equations, we obtain:

(T s - T air) = -(k/h)(dT/dx), where hA(T s - T air)/A = -k(dT/dx).

Assuming that the temperature gradient is constant over the length of the rod and integrating both sides from x = 0 to x = L, we arrive at:

(T s - 20) = -(43.5e-3 / 13)(T s - 300)*0.6 (T s - T air) = -(k/h)(T s - T furnace)*L

Simplifying:

(T s - 20) = -1.008(T s - 300)

T s - 20 = -1.008T s + 302.4 when expanded

When we solve for T s, we obtain T s = 1265.4 K.

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Answer:

The uniform pressure for the necessary axial force  is  W = 945 N

The uniform wear for the necessary axial force is  W = 970.15 N

Explanation:

Solution

Given that:

r₁ = 0.1 m

r₂ = 0.05m

μ = 0.35

p = 12 N or kW

N = 1500 rpm

W = 1000 N

The angular velocity is denoted as  ω= 2πN/60

Here,

ω = 2π *1500/60 = 157.07 rad/s

Now, the power transferred becomes

P = Tω this is the equation (1)

Thus

12kW = T * 157.07 rad/s

T = 76.4 N.m

Now, when we look at the uniform condition, we have what is called the torque that is frictional which acts at the frictional surface of the clutch dented as :

T = nμW R this is the equation (2)

The frictional surface of the mean radius is denoted by

R =2/3 [(r₁)³ - (r₂)³/(r₁)² - (r₂)²]

=[(0.1)³ - (0.05)³/[(0.1)² - (0.05)²]

R is =0.077 m

Now, we replace this values and put them into the equation (2)

It gives us this, 76. 4 N.m = n * 0.35* 1000 N * 0.077 m

n = 2.809 = 3

The number of pair surfaces is = 3

Secondly, we determine the uniform wear.

So, the mean radius is denoted as follows:

R = r₁ + r₂/ 2

=0.1 + 0.05/2

=0.075 m

Now, we replace the values and put it into the equation (2) formula

76. 4 N.m = n *0.35* 1000 N * 0.075 m

n= 2.91 = 3

Again, the number of pair surfaces = 3

However, for the uniform pressure with regards to the number of clutch plates is 3 we can derive the necessary axial force from the equation (2)

76. 4 N.m = 3 * 0.35 * W *0.077 m

W = 945 N

Also, for the uniform wear with regards to the number of clutch plates is 3 we can derive the necessary axial force from the equation (2)

76. 4 N.m = 3 * 0.35 * W *0.075 m

W = 970. 15 N

To meet the necessary criteria for effective fall restraint,the principles are Adequate Anchorage,Proper Fit and Adjustment,Maximum Arrest Force,Compatibility and Integrity and Proper Training and Use.

Fall restraint systems are designed to prevent a person from falling while working at heights. To meet the necessary criteria for effective fall restraint, the system must adhere to several key principles:

1. Adequate Anchorage: The system should be securely anchored to a structure capable of withstanding the anticipated loads. Anchorage points must be structurally sound and capable of supporting the maximum forces that may be exerted during a fall.

2. Proper Fit and Adjustment: The fall restraint system should be properly fitted and adjusted to the individual worker. This includes ensuring that harnesses, belts, and lanyards are correctly sized and adjusted for the user's body type and work requirements.

3. Maximum Arrest Force: The fall restraint system should limit the maximum force exerted on the worker's body in the event of a fall. This helps minimize the risk of injury by reducing the impact force transmitted to the body during a fall arrest.

4. Compatibility and Integrity: All components of the fall restraint system must be compatible with each other and function together as intended. This includes the harness, lanyard, connectors, and anchorages.

Regular inspections and maintenance should be conducted to ensure the integrity of the system.

5. Proper Training and Use: Workers must be adequately trained in the proper use of the fall restraint system. They should understand how to properly don and doff the equipment, inspect it for defects, and recognize when the system is not suitable for use.

By meeting these criteria, fall restraint systems can effectively protect workers at heights, reducing the risk of falls and their associated injuries.

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The system overheat if a fan blows in the wrong direction, preventing airflow through the case.

Air should follow a straight line through the case. In most cases, you want the case fans at the front of the case to draw in air and the ones at the back to blow out air. Because hot air will rise, vents at the top of your case should be used as exhaust fans.

Overheating of a computer is typically brought on by multiple factors. If dust is allowed to accumulate over time, it can obstruct the fans and overheat the CPU or GPU. The fans may go into overdrive if there are too many applications running simultaneously, and if this happens too often, the fans may stop working.

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correct answer to the question is b. 1,500 feet AGL when the Class E airspace is designated in conjunction with an airway that is 4 NM or wider.

When Class E airspace is designated in conjunction with an airway, the floor of the airspace depends on the width of the airway. If the airway is less than 4 nautical miles (NM) wide, then the floor of the Class E airspace is 1,200 feet above ground level (AGL) within 4 NM either side of the airway centerline. If the airway is 4 NM or wider, then the floor of the Class E airspace is 1,500 feet AGL within 4 NM either side of the airway centerline.

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Regardless of how the wires are linked, a rollover cable will reverse all of them.

When a signal on one pair of wires is captured by an adjacent pair of wires, it is said to be experiencing near-end crosstalk. Interference is caused by the sent signal's component that is electromagnetically linked back into the receiving signal.

Networks employ the technique of multiplexing to combine several digital or analogue signals into a single composite signal that is transmitted via a common media, like a radio wave or fibre optic cable.

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Answer:

The velocity at section is approximately 42.2 m/s

Explanation:

For the water flowing through the pipe, we have;

The pressure at section (1), P₁ = 300 kPa

The pressure at section (2), P₂ = 100 kPa

The diameter at section (1), D₁ = 0.1 m

The height of section (1) above section (2), D₂ = 50 m

The velocity at section (1), v₁ = 20 m/s

Let 'v₂' represent the velocity at section (2)

According to Bernoulli's equation, we have;

\(z_1 + \dfrac{P_1}{\rho \cdot g} + \dfrac{v^2_1}{2 \cdot g} = z_2 + \dfrac{P_2}{\rho \cdot g} + \dfrac{v^2_2}{2 \cdot g}\)

Where;

ρ = The density of water = 997 kg/m³

g = The acceleration due to gravity = 9.8 m/s²

z₁ = 50 m

z₂ = The reference = 0 m

By plugging in the values, we have;

\(50 \, m + \dfrac{300 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{(20 \, m/s)^2}{2 \times 9.8 \, m/s^2} = \dfrac{100 \ kPa}{997 \, kg/m^3 \times 9.8 \, m/s^2} + \dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)50 m + 30.704358 m + 20.4081633 m = 10.234786 m + \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

50 m + 30.704358 m + 20.4081633 m - 10.234786 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

90.8777353 m = \(\dfrac{v_2^2}{2 \times 9.8 \, m/s^2}\)

v₂² = 2 × 9.8 m/s² × 90.8777353 m

v₂² = 1,781.20361 m²/s²

v₂ = √(1,781.20361 m²/s²) ≈ 42.204308 m/s

The velocity at section (2), v₂ ≈ 42.2 m/s

Centrifugal force is the force exerted on an object moving in a circular path and directed outward from the center. In order to determine the centrifugal force in pound-force of a centrifuge carrying 50mL of blood, we will need to use the formula for centripetal force:

Centrifugal force = (mass x acceleration)/radius

Here's how to solve the problem:

First, we need to determine the mass of the blood being carried by the centrifuge. We know the volume of blood (50 mL) and the density of blood (0.994 g/mL), so we can use the formula:

mass = volume x density

mass = 50 mL x 0.994 g/mL

mass = 49.7 g

Next, we need to convert the given units to SI units (meters and seconds):

Centripetal acceleration = 64 ft/s^2
1 ft = 0.3048 m
Centripetal acceleration = 64 ft/s^2 x 0.3048 m/ft = 19.5072 m/s^2

Rotational speed = 345 rpm
1 rpm = 1/60 s
Rotational speed = 345 rpm x 1/60 s = 5.75 s^-1

Now we can use the formula to calculate centrifugal force:

Centrifugal force = (mass x acceleration)/radius

The radius of the centrifuge is half the diameter (3.5 inches or 0.0889 meters):

Centrifugal force = (49.7 g x 19.5072 m/s^2)/0.0889 m

Centrifugal force = 10,879.52 N

Finally, we need to convert Newtons to pound-force:

1 N = 0.22481 lb-f
Centrifugal force = 10,879.52 N x 0.22481 lb-f/N

Centrifugal force = 2,442.69 lb-f

Therefore, the centrifugal force in pound-force is 2,442.69 lb-f.

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Based on the present-worth criterion and a 14% MARR, Alternative A should be undertaken as it has a lower present worth compared to Alternative B.

Incremental To determine which alternative should be undertaken based on the present-worth criterion and a 14% MARR, we need to calculate the present worth of each alternative's costs.

For Alternative A:

Initial investment: -$29 million

Annual operating and maintenance costs: -$0.6 million per year for 25 years

Salvage value: +$0.8 million

For Alternative B:

Initial investment: -$13 million

Additional investments: -$17 million in the 10th year, -$10 million in the 15th year

Annual operating and maintenance costs: -$0.25 million for the first 10 years, -$0.35 million from the 11th to the 15th year, -$0.45 million for the final 10 years

Salvage value: +$1.2 million

Using the incremental cost approach, we calculate the present worth of costs for each alternative. We consider the difference in costs between the alternatives over their respective lifetimes.

For Alternative A:

Present worth = -29 + (0.6 * (1 - (1 + 0.14)^-25) / 0.14) + 0.8 / (1 + 0.14)^25

For Alternative B:

Present worth = -13 + (0.25 * (1 - (1 + 0.14)^-10) / 0.14) + (0.35 * (1 - (1 + 0.14)^-5) / 0.14) + (0.45 * (1 - (1 + 0.14)^-10) / 0.14) + 1.2 / (1 + 0.14)^25

Comparing the present worth values of the two alternatives, the alternative with the lower present worth should be undertaken.

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a) The Gantt chart view for the project is shown below. The finish date is April 6, 2023. The critical path is A-B-E-F-H-I-K-L and its duration is 25 days.

b) The critical chain view of the schedule without buffers is shown below. The critical chain is A-C-D-E-G-H-I-J-K-L and its duration is 18 days. Adding the project buffer of 25% of the critical chain duration (4.5 days) and the feeding buffers, the end date is April 10, 2023.

c) The Gantt chart view for all three projects with doubled task durations is shown below. The finish date is May 13, 2023.

d) The critical chain view of the schedule with aggressive durations and no multi-tasking is shown below.

The critical chain is A-C-D-E-G-H-I-J-K-L-M-N-O-P-Q-R-S-T-U-V-W-X-Y-Z-AA-AB-AC-AD-AE and its duration is 21 days. Adding the project buffer of 25% of the critical chain duration (5.25 days) and the feeding buffers, the end date is May 23, 2023.

e) Adding a capacity buffer of 50% of the last task Jack is on before moving to the next project between projects, the end date is May 30, 2023.

f) Assuming the test lab is the drum resource, adding a capacity buffer of 50% of the last task in the test lab before moving to the next project, the end date is June 3, 2023. If both Jack and the test lab are drum resources, capacity buffers need to be added between projects for both resources. The overall end date will depend on the size of the buffers added.

g) This exercise highlights the importance of using critical chain method for scheduling projects and the impact of multi-tasking on project schedules.

Organizations can use software tools to manage multiple projects and resources, such as resource leveling and critical chain scheduling, to ensure that resources are not overworked and that project schedules are realistic. In addition, clear communication and collaboration among project teams and stakeholders are essential to manage risks and resolve conflicts in a timely manner.

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Answer:

219

Explanation:

Unsigned binary number (base two) 1101 1011 converted to decimal system (base ten) positive integer = 219.

Answer:219

Explanation:128+64+16+8+2+1

How to Clean Hand Tools:

Cleaning Power Tools:

Answer:

10.5

Explanation:

Convert to an equation for example P%* X=Y

P is 7.5% X is 140, so the equation Is 7.5 percent * 14= Y

convert 7.5% Into a decimal by removing the percent sign and deviding by 7.5/100= 0.075

Substitute 0.075 for 7.5% in the equation: 7.5%*140=Y becomes 0.075*140= 10.5

It means that the gas with the lowest molecular weight will have the highest effusion rate.

The given gases' effusion rates are listed in order from highest to lowest. The effusion rate of a hydrogen molecule is the highest, whereas that of a hydrocarbon is the lowest.

A gas will effuse faster when it is lighter and more slowly when it is heavier. Helium (He) will have the highest rate of effusion since it has the lowest molecular weight (atomic weight, in this example).

The following equation can be used to compare the rate of effusion for two gases: The effusion rates in this case are inversely related to the square root of the gas molecules' masses. A container contains an amalgam of neon and argon gas.

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Answer:

  0 ft

Explanation:

The equation of the plane can be found from the cross product AC×BC. That vector is ...

  N = (2, 11, -6) × (-3, -6, 4) = (8, 10, 21)

Then the equation of the plane is ...

  8x +10y +21z = 14 . . . . . 14 = N·A

Point P satisfies this equation, so is on the plane. The distance is 0 feet.

  8(9) +10(11) -8(21) = 72 +110 -168 = 14

Answer:

Except what? I'm confused

All of these are true about using adhesive except Bilateral. A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain.

A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain. According to my research on the different terms used when referencing an insurance contract, I can say that all of the answers provided except for Bilateral are considered typical characteristics describing the nature of an insurance contract.

Since an insurance contract is a fund that the insurance company pays in the case of an accident in which the person is injured, there is only one party that agrees to fulfill their side of the bargain and that is the insurance company.

Therefore, All of these are true about using adhesive except Bilateral. A bilateral contract is defined as an agreements between two parties in which each side agrees to fulfill his or her side of the bargain.

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Answer:

A = 1.41 m²

Explanation:

The ara can be found out by using Stefan Boltzman Law:

\(P = \sigma AT^4\)

where,

A = Area = ?

P = Radiation Power = 1200 W

σ = Stefan Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴

T = surface temperature = 350 k

Therefore:

\(1200\ W = (5.6703\ x\ 10^{-8}W/m^2.k^4)(A)(350\ k)^4\\\\A = \frac{1200\ W}{850.9\ W/m^2}\)

A = 1.41 m²

The Tennison Gambit is a lesser-known variation of the Zukertort Opening in chess, where White sacrifices a pawn to gain control of the center and develop their pieces more quickly, but it is considered a risky and aggressive opening.

What is a gambit?
A gambit is a chess opening in which a player sacrifices material, usually a pawn, in order to gain an advantage in position or development. The objective of a gambit is to seize control of the board and create attacking opportunities, often at the cost of some material or positional disadvantage. Gambits are often used as a surprise tactic to disrupt an opponent's plans and force them to react to the new situation on the board.


The Tennison Gambit is a lesser-known variation of the Zukertort Opening in chess, where White sacrifices a pawn in order to gain control of the center and develop their pieces more quickly. The opening moves of the Tennison Gambit are:

Nf3 d5

d4 Nf6

g4?!

At move 3, White gambits the pawn with g4, offering it to Black in exchange for a lead in development and control of the center. The Tennison Gambit is considered a risky and aggressive opening, as it can lead to a difficult position for White if Black successfully defends their advantage.

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Answer:

\(I = 45mA\)

Explanation:

Given

\(I = 90mA\) --- Current

Required

Determine the new current when resistance is doubled

Using \(V = IR\)

Initially, we have:

\(V = 90mA * R\)

When resistance is doubled and voltage remains unaltered, we have:

\(V = I* 2R\)

2R represents the new resistance and I represents the new current

Equate both values of V

\(90mA * R = I* 2R\)

Make I the subject

\(I = \frac{90mA * R}{2R}\)

\(I = \frac{90mA }{2}\)

\(I = 45mA\)

The new current is 45milliAmps

Answer:

The answer is B. Avoid making a large wake.

Explanation:

When passing a fishing boat it is important to maintain a minimal wake due to the dangers a large wake could pose to the fishing boat you are passing, it is part of maintaining safety on the water.

You can not pass on the sides with the fishing lines also, and you are supposed to communicate to the fishing boat before taking the appropriate action.

It is accurate what is said. The compressor, expansion valve, and orifice tube are further protected when an additional filter is installed.

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