The Assertion mentioned in the question is that the compressive strength of a typical brittle material is significantly higher than its tensile strength.
This statement is correct because brittle materials are those materials that break easily upon the application of a force. Brittle materials do not have any plastic deformation region and have a limited range of elasticity.
Due to this, when a compressive force is applied to a brittle material, it tends to resist the force and does not break easily.
On the other hand, when a tensile force is applied to a brittle material, it tends to break easily as it does not have the ability to stretch.
However, the Reason mentioned in the question, which is not correct, states that the compressive forces act more uniformly across the cross-section of a brittle material than tensile forces.
This statement is not true because the distribution of compressive and tensile forces across the cross-section of a brittle material is similar.
Therefore, the correct option is C, where the Assertion is correct, but the Reason is incorrect.
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The assertion in the question is that a typical brittle material has a compressive strength that is much greater than its tensile strength.
This assertion is true because brittle materials are ones that shatter easily when pressure is applied. Materials that are brittle have a small elastic range and no plastic deformation zone.
Because of this, brittle materials have a tendency to resist compressive forces and do not break easily.
A brittle material, on the other hand, is incapable of stretching, thus when a tensile force is applied to it, it tends to break quickly.
The Reason given in the question, which is incorrect, claims that compressive forces behave more evenly across a brittle material's cross-section than tensile forces do.
This is untrue because brittle materials have similar distributions of compressive and tensile forces across their cross-sections.
The right response is therefore C, where the Assertion is true but the Reason is false.
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During takeoff, the sound intensity level of a jet engine is 160 dB at a distance of 32 m. What is the sound intensity level at a distance of 1.0 km?
If during takeoff, the sound intensity level of a jet engine is 160 dB at a distance of 32 m, the sound intensity level at a distance of 1.0 km is 130.1 dB .
To find the sound intensity level at a distance of 1.0 km, we'll use the formula for sound intensity level:
L2 = L1 - 20 × log10(r2/r1)
Where:
- L1 is the initial sound intensity level (160 dB)
- L2 is the final sound intensity level (which we want to find)
- r1 is the initial distance (32 m)
- r2 is the final distance (1.0 km = 1000 m)
- log 10 is the base-10 logarithm
Calculate the ratio of the distances, r2/r1:
r2/r1 = 1000 m / 32 m = 31.25
Calculate the base-10 logarithm of the distance ratio:
log 10(31.25) = 1.495
Multiply the logarithm by -20:
-20 × 1.495 = -29.9 dB
Subtract this value from the initial sound intensity level, L1:
L2 = 160 dB - 29.9 dB = 130.1 dB
So, the sound intensity level at a distance of 1.0 km is 130.1 dB.
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define newtons first law of motion with examples(class 9 ) plssss itz urgent
Newton's first law of motion states that an object maintains its state motion or that of rest unless subjected to some external force.
It means that if an object is moving then it will not stop until we apply force on it. Similarly, if an object is at rest, then it will not move until we apply force on it. Objects also maintain their speed, it means that their speed will not change unless we apply force.
This is because objects have inertia. Inertia is the measure of the property of the object to oppose any change in its motion. More the mass more the inertia. This is why this law is also known as the law of inertia.
Example:
1. A bag kept on the top of bus, falls backward because it maintains its state of rest and bus starts moving.
A car is moving North at 65 miles per hour. A person is walking due East on a different road. Determine how fast the person is moving at the moment when the person is 50 miles West and 70 miles South of the car and the distance between the person and the car is increasing at a rate of 55 miles per hour.
The persοn is mοving at a speed οf 55 miles per hοur in the Sοuth directiοn when the persοn is 50 miles West and 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur.
How tο determine the speed of the persοn?Tο determine the speed at which the persοn is mοving, we can use the cοncept οf relative velοcity.
Let's cοnsider the hοrizοntal and vertical cοmpοnents separately:
Hοrizοntal Cοmpοnent:
The persοn is walking due East, which is perpendicular tο the Nοrth directiοn οf the car. Therefοre, the hοrizοntal cοmpοnent οf the persοn's velοcity dοes nοt affect the speed at which the persοn is mοving away frοm the car.
Vertical Cοmpοnent:
The persοn is 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur. This indicates that the persοn's vertical pοsitiοn is changing with time. Since the persοn is mοving in the Sοuth directiοn and the distance is increasing, the persοn's speed can be determined by the rate οf change οf the vertical distance.
Given that the distance is increasing at a rate οf 55 miles per hοur, the persοn's speed in the Sοuth directiοn is 55 miles per hοur.
Therefοre, the persοn is mοving at a speed οf 55 miles per hοur in the Sοuth directiοn when the persοn is 50 miles West and 70 miles Sοuth οf the car, and the distance between them is increasing at a rate οf 55 miles per hοur.
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You stand on a merry-go-round which is spinning at f = 0:25 revolutions per second. You are R = 200 cm from the center. (a) Find the angular speed ! At which it is spinning. (b) Find the centripetal acceleration, ac with which it is spinning. (c) What is the minimum coefficient of static friction is between your shoes and the floor that will keep you from slipping off?
Answer:
(a) ω = 1.57 rad/s
(b) ac = 4.92 m/s²
(c) μs = 0.5
Explanation:
(a)
The angular speed of the merry go-round can be found as follows:
ω = 2πf
where,
ω = angular speed = ?
f = frequency = 0.25 rev/s
Therefore,
ω = (2π)(0.25 rev/s)
ω = 1.57 rad/s
(b)
The centripetal acceleration can be found as:
ac = v²/R
but,
v = Rω
Therefore,
ac = (Rω)²/R
ac = Rω²
therefore,
ac = (2 m)(1.57 rad/s)²
ac = 4.92 m/s²
(c)
In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:
Centripetal Force = Frictional Force
m*ac = μs*R = μs*W
m*ac = μs*mg
ac = μs*g
μs = ac/g
μs = (4.92 m/s²)/(9.8 m/s²)
μs = 0.5
(D) âv = at where a = F/m. So we have âv = 10^-14 à 10^-9 ÷ 10^-30 = 10^(-14 + -9 - (-30))
The speed of the electron after it has accelerated for the 10-9 second is most nearly
(A) 10^1 m/s (B) 10^3 m/s (C) 10^5 m/s (D) 10^7 m/s (E) 10^9 m/s
The speed of the electron, after it has accelerated for 10^-9 seconds, is 10^5 m/s. The correct option is C.
Acceleration is the rate at which an object changes its velocity with respect to time. It is a vector quantity, which means it has both magnitude and direction. Mathematically, acceleration is defined as the change in velocity divided by the time taken for that change to occur.
Given:
Acceleration of the electron, a = F/m = 10^-14 N / 9.1 x 10^-31 kg = 1.0989 x 10^17 m/s^2
Time for which electron is accelerated, t = 10^-9 s
Using the equation, âv = at, where âv is the change in velocity, we get:
âv = at = 1.0989 x 10^17 m/s^2 x 10^-9 s = 1.0989 x 10^8 m/s
Therefore, the speed of the electron after it has accelerated for the 10^-9 second is approximately 10^8 m/s, which is closest to option (C) 10^5 m/s.
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* Question Completion Status: Moving to another question will save this response. Question 29 Which one of the following statements is not true? (choose all apply) O UV radiation is a type of ionizing
One statement that is not true is that UV radiation is a type of electromagnetic radiation. It is also a type of ionizing radiation. UV radiation is actually a form of non-ionizing radiation.
UV radiation, or ultraviolet radiation, is a type of electromagnetic radiation that falls between visible light and X-rays on the electromagnetic spectrum. It is often categorized into three types: UVA, UVB, and UVC. Unlike ionizing radiation, such as X-rays and gamma rays, which have enough energy to remove tightly bound electrons from atoms or molecules, UV radiation lacks the necessary energy to ionize atoms or molecules. Instead, it primarily interacts with the outermost electrons of atoms or molecules, leading to chemical reactions and causing biological effects.
UV radiation is commonly associated with sunlight and has various effects on living organisms and materials. It can cause sunburn, premature aging of the skin, and an increased risk of skin cancer. Exposure to excessive UV radiation can also damage the eyes and impair the immune system. It is important to protect oneself from excessive UV exposure by wearing sunscreen, protective clothing, and sunglasses.
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Help me as pleasessss help with 1,2 and 3
what index of refraction halves the wavelength that light has in a vacuum?
a) 1.33
b) 1.50
c) 1.41
d) 2.00
e) 5.00
The index of refraction that halves the wavelength that light has in a vacuum is 2.00. Therefore, the correct option is (d) 2.00.
When light passes from one medium to another, it changes its velocity, and thus its wavelength. The index of refraction is a measure of how much light is bent when passing through a medium and can be calculated using Snell's Law:n1sin θ1=n2sin θ2where n1 and n2 are the indices of refraction of the two media, and θ1 and θ2 are the angles that the light makes with the normal line in the first and second media, respectively.
For a given angle of incidence, we can see that the index of refraction is directly proportional to the sine of the angle of refraction, which means that as the angle of refraction increases, so does the index of refraction. Now, let's assume that light is passing from vacuum (with index of refraction n1=1) to a medium with an unknown index of refraction n2.
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A car starting from rest accelerates at a rate of 8.0 m/s/s. What is its final speed at the end of 4.0 seconds?
Draw conclusions as to how the acceleration is related to the time for the data table.
Time (sec) Displacement (m) Velocity (m/s)
0 0 0
0.5 1.25 5
1 5 10
1.5 11.25 15
a The acceleration is a constant.
B) The acceleration is constantly decreasing.
C) The acceleration is constantly increasing.
D) The acceleration cannot be determined from this data.
Answer:
Its C. The acceleration is constantly increasing
Answer:
It’s a the acceleration is constant
Explanation:
What is a urine specific gravity test?
A laboratory test that shows the concentration of all chemical particles in the urine. After you provide a urine sample, it is tested right away. The healthcare provider uses a dipstick made with a color-sensitive pad. The color the dipstick changes will tell the provider the specific gravity of your urine.
A urine specific gravity test is a simple diagnostic test that measures the density of urine compared to water
What is specific gravity ?Specific gravity is the ratio of the density of a substance to the density of a reference substance, typically water. It is expressed as a dimensionless quantity and is often used in various fields such as physics, chemistry, and mineralogy to quantify the properties of liquids and solids. The specific gravity of a substance is calculated by dividing the density of the substance by the density of water at a specified temperature. Whether anything floats or sinks can be determined by its specific gravity. When measured against water, the specific gravity of solids and liquids determines whether they will float or sink; if it is larger than one, they will sink. If the gas' specific gravity is less than one, it is said to be suspended in air because it is measured in relation to the air on Earth.
A substance with a specific gravity greater than 1 sinks in water, while a substance with a specific gravity less than 1 floats.
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If you needed to measure the length of a room, you should use the unit
Answer:
meters, yards or feet
Explanation:
physicists are analyzing the electric and gravitational interaction between two particles, one with a charge of 2e 2eplus, 2, e, and the other is an electron. the electron exerts both an electric force f ef ef, start subscript, e, end subscript and a gravitational force f gf g f, start subscript, g, end subscript on the other particle. how does the magnitude and direction of f ef ef, start subscript, e, end subscript compare to f gf g f, start subscript, g, end subscript ?
The magnitude of the electric force (\(f_{ef}\)) between the two particles is significantly larger than the magnitude of the gravitational force (\(f_{gf}\)) between them. The direction of the electric force is determined by the charges of the particles, while the direction of the gravitational force is determined by the masses of the particles.
The magnitude of the electric force (\(f_{ef}\)) between two charged particles is given by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, one particle has a charge of 2e (where e is the elementary charge) and the other particle is an electron with a charge of -e. Since the charges are opposite in sign, the electric force between them will be attractive. The magnitude of the electric force will be much larger than the gravitational force due to the small value of the gravitational constant compared to the electrostatic constant. On the other hand, the magnitude of the gravitational force (\(f_{gf}\)) between two particles is given by Newton's law of universal gravitation, which states that the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between them. The masses of the particles involved in this scenario are not provided, but we know that the mass of an electron is much smaller than the mass of a typical particle with a charge of 2e. Therefore, the gravitational force between them will be significantly weaker compared to the electric force.
In summary, the magnitude of the electric force (\(f_{ef}\)) between the charged particles is much larger than the magnitude of the gravitational force (\(f_{gf}\)) between them. The direction of the electric force is determined by the charges of the particles (attractive in this case), while the direction of the gravitational force is determined by the masses of the particles.
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The magnitude of the electric force () between the two particles is significantly larger than the magnitude of the gravitational force () between them. The direction of the electric force is determined by the charges of the particles, while the direction of the gravitational force is determined by the masses of the particles.
The magnitude of the electric force () between two charged particles is given by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, one particle has a charge of 2e (where e is the elementary charge) and the other particle is an electron with a charge of -e.
Since the charges are opposite in sign, the electric force between them will be attractive. The magnitude of the electric force will be much larger than the gravitational force due to the small value of the gravitational constant compared to the electrostatic constant.
On the other hand, the magnitude of the gravitational force () between two particles is given by Newton's law of universal gravitation, which states that the force is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
The masses of the particles involved in this scenario are not provided, but we know that the mass of an electron is much smaller than the mass of a typical particle with a charge of 2e. Therefore, the gravitational force between them will be significantly weaker compared to the electric force.
In summary, the magnitude of the electric force () between the charged particles is much larger than the magnitude of the gravitational force () between them. The direction of the electric force is determined by the charges of the particles (attractive in this case), while the direction of the gravitational force is determined by the masses of the particles.
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How long does it take the moon to rotate on its axis?.
What is the strength of the electric field 0. 020 m from a 12 µC charge? (Use k=) 5. 4 × 106 N/C 2. 7 × 108 N/C 5. 4 × 1012 N/C 2. 7 × 1014 N/C.
The correct answer is 3. 2.7 × 106 N/C.
To determine the strength of the electric field at a certain distance from a charged object, we can use Coulomb's law and the formula for electric field intensity. Coulomb's law states that the force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.
The formula for the electric field intensity (E) due to a point charge is given by:
E = k * (Q / \(r^2\))
Where:
E is the electric field intensity
k is Coulomb's constant (k = 9 x \(10^9\) Nm²/C²)
Q is the charge
r is the distance from the charge
In this case, we are given a charge of 12 µC (microcoulombs) and a distance of 0.020 m. Plugging these values into the formula, we get:
E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²
Simplifying the calculation, we find:
E = (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.020 m)²
= (9 x \(10^9\) Nm²/C²) * (12 x \(10^{-6}\) C) / (0.0004 m²)
= 108 N/C * 12 x \(10^{-6}\) C / 0.0004 m²
= 108 N/C * 0.012 C / 0.0004 m²
= 1296 N/C / 0.0004 m²
= 3240000 N/C
Therefore, the strength of the electric field at a distance of 0.020 m from a 12 µC charge is 3,240,000 N/C.
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two parallel straight current-carrying wires are lying on a table, 12 cm apart. the total magnetic field produced by the currents is zero at a distance of 3 cm from the left wire, in between the wires . which of the following statements are correct? select all that apply.
There are two parallel straight current-carrying wires on a table, 12 cm apart. The total magnetic field produced by the currents is zero at a distance of 3 cm from the left wire, in between the wires.
There are a few possible correct statements based on this information.
1. The currents in the two wires must be equal and opposite in direction. This is because the magnetic field produced by a wire is directly proportional to the current in the wire. Since the total magnetic field is zero at a certain point, the magnetic fields produced by the two wires must cancel each other out. This can only happen if the currents are equal and opposite in direction.
2. The currents in the two wires must be the same magnitude. This is because the wires are parallel and the magnetic field at a certain distance from a wire is inversely proportional to the distance. Therefore, in order for the magnetic fields produced by the two wires to cancel out at a certain point, the currents must be the same magnitude.
3. The magnetic field produced by each wire separately is not zero at the point where the total magnetic field is zero. This is because the two magnetic fields cancel each other out at that point.
In summary, the correct statements are that the currents in the two wires must be equal and opposite in direction, and the currents in the two wires must be the same magnitude. Additionally, the magnetic field produced by each wire separately is not zero at the point where the total magnetic field is zero.
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Compute the height and the balance factor at each node. State whether the tree is an AVL tree or not. If not, list the node(s) where the AVL balance property is not satisfied.
Group of answer choices
No, the tree is not an AVL tree. The node where the AVL balance property is not satisfied is: 68
Yes, the tree is an AVL tree
No, the tree is not an AVL tree. The node(s) where the AVL balance property is not satisfied are: 68, 20 and 25
No, the tree is not an AVL tree. The node(s) where the AVL balance property is not satisfied are: 68 and 20
The correct option is A, No, the tree is not an AVL tree. The node where the AVL balance property is not satisfied is: 68
An AVL (Adelson-Velskii and Landis) tree is a self-balancing binary search tree, which maintains its height to be logarithmic in terms of the number of elements it stores. It was invented in 1962 by two Soviet mathematicians, Georgy Adelson-Velskii and Evgenii Landis. In an AVL tree, the heights of the left and right subtrees of any node differ by at most one.
If the difference is more than one, the tree is restructured using one of four possible rotations to restore the balance factor. The rotations are left-left, left-right, right-right, and right-left. The main advantage of using AVL trees is that their worst-case time complexity for basic operations like search, insert, and delete is O(log n), where n is the number of elements in the tree. This makes AVL trees suitable for applications where efficient searching and insertion of data are crucial.
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what is technology?
Answer:
Technology is the application of scientific knowledge to the practical aims of human life or, as it is sometimes phrased, to the change and manipulation of the human environment.
Please Mark it as brainlist answer.
An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (Just number no units)
Answer:
24 m/s²
Explanation:
The given parameters are;
The initial acceleration of the object, a = 16 m/s²
Let 'm' represent the initial mass of the object
The initial force acting on the object, F = m × a
∴ F = 16 × m = 16·m
When the mass is doubled, we have;
The new mass of the object, m₂ = 2 × m = 2·m
When the net force acting on the object triples, we have;
The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m
From F = m × a, we have;
a = F/m
∴ The new acceleration of the object, a₂ = F₂/m₂
From which, by plugging in the values, we have;
a₂ = 48·m/(2·m) = 24
The new acceleration of the object, a₂ = 24 m/s².
A car of mass 1535 kg collides head-on with a parked truck of mass 2000 kg. Spring mounted bumpers ensure that the collision is essentially elastic. If the velocity of the truck is 17 km/h (in the same direction as the car's initial velocity) after the collision, what was the initial speed of the car
A car of mass 1535 kg collides head-on with a parked truck of mass 2000 kg. Spring mounted bumpers ensure that the collision is essentially elastic. If the velocity of the truck is 17 km/h (in the same direction as the car's initial velocity) after the collision, what was the initial speed of the car 20kmh
What is collision ?A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The following are a few instances of physical encounters that scientists might classify as collisions:
Legs of an insect are said to collide with a leaf when it falls on one.Every contact of a cat's paws with the ground while it strides across a lawn is seen as a collision, as is every brush of its fur with a blade of grass.To learn more about collision from the given link:
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use the nebular theory to explain why the planets revolve around the sun in the same direction
We can use the nebular theory to explain why the planets revolve around the Sun in the same direction, and it is because they inherited the same direction of rotation from the spinning protoplanetary disk during their formation.
The Nebular Theory is a theory about the formation of the Solar System. It proposes that our Solar System formed from a giant cloud of interstellar gas and dust called a nebula. This nebula eventually collapsed due to gravity, and it started to spin. As the nebula spun faster and faster, it flattened out into a disk-like structure called a protoplanetary disk.
Over time, small particles in the disk started to stick together and form larger and larger objects called planetesimals. These planetesimals then collided with each other and merged to form the planets that we see today.
The reason why the planets revolve around the Sun in the same direction is due to the conservation of angular momentum. Angular momentum is a measure of how much an object is rotating or spinning. According to the conservation of angular momentum, the total amount of angular momentum in a system remains constant unless an external torque acts on the system.
In the case of the Solar System, the protoplanetary disk was spinning in a particular direction. As the planets formed from this disk, they inherited the same direction of rotation. This is why all the planets in our Solar System orbit the Sun in the same direction.
Therefore, we can use the nebular theory to explain why the planets revolve around the Sun in the same direction, and it is because they inherited the same direction of rotation from the spinning protoplanetary disk during their formation.
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a rollercoaster car is moving 19.8 m/s on flat ground when it’s hits the brakes. it decelerates at -3.77 m/s^2 over the next 45.8 m. how much time does it take?
Answer:
3.44 s
Explanation:
Given:
Δx = 45.8 m
v₀ = 19.8 m/s
a = -3.77 m/s²
Find: t
Δx = v₀ t + ½ at²
45.8 = 19.8 t + ½ (-3.77) t²
45.8 = 19.8 t − 1.885 t²
1.885 t² − 19.8 t + 45.8 = 0
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ 19.8 ± √((-19.8)² − 4 (1.885) (45.8)) ] / 2(1.885)
t = [ 19.8 ± √(392.04 − 345.332) ] / 3.77
t = 3.44 or 7.06
The first time, 3.44 seconds, is correct.
The second time is the time it would take the car to return to 45.8 m if it continued decelerating after stopping.
Anyone please ??? ASAP 15 points ???
Answer:
1) you could put more force behind it. (increase) 2) have another object interact with that object. (increase or decrease) 3) the object could hit a wall and stop or slow down (decrease)
Sorry if wrong
what is the resistance of an object that produces a current of a 6 A and has a voltage of 30
Answer:
this is the answer the required questions
hope you like this
use the richter scale formula r = log (i / i0) to find the magnitude of an earthquake that has the following intensity. (a) 100 times that of i0
(a) To find the magnitude of an earthquake with intensity 10 thousand times that of I0, we can substitute the given values into the formula R = log (I/I0).
Given:
I = 10,000 * I0
Substituting this value into the formula:
R = log (10,000 * I0/I0)
Simplifying:
R = log (10,000)
Using the logarithmic property log(a * b) = log(a) + log(b):
R = log(10) + log(10,000)
Using the logarithmic property log(base) = 1:
R = 1 + 4
R = 5
Therefore, the magnitude of the earthquake with intensity 10 thousand times that of I0 is 5 on the Richter scale.
(b) Let's differentiate the formula R = log (I/I0) with respect to I and use logarithmic differentiation to find the error in the intensity of the earthquake.
Starting with the equation:
R = log (I/I0)
Taking the natural logarithm of both sides:
ln(R) = ln(log(I/I0))
Differentiating both sides using the chain rule:
1/R * dR = 1/(log(I/I0)) * d(log(I/I0))
Simplifying:
dR/R = (1/I) * dI
We are given that the magnitude has an error of at most 2%:
dR/R = 0.02
Substituting this value into the equation:
0.02 = (1/I) * dI
Solving for dI:
dI = 0.02 * I
Therefore, the error in the intensity of the earthquake is 0.02 times the original intensity (I) of the earthquake.
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electromagnetic waves are ........... by shiny surfaces.
1. reflected
2. refracted
3. absorbed
Answer:
Electromagnetic waves are reflected
Explanation:
Reflection of light (and other forms of electromagnetic radiation) occurs when the waves encounter a surface or other boundary that does not absorb the energy of the radiation and bounces the waves away from the surface. ... This concept is often termed the Law of Reflection.
Electromagnetic waves are reflected by the shiny surfaces. The correct option is 1.
What are electromagnetic waves?These are the rays which mostly come from the Sunlight. It possess energy or defined by energy of photon.
Reflection of light occurs when the waves strike a surface or boundary that does not absorb the energy of the radiation but bounces the waves away from the surface. This is often called the Law of Reflection.
Thus, the Electromagnetic waves are reflected by the shiny surfaces. The correct option is 1.
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You pull a sled with a package on it across a snow-covered flat lawn. If you
apply a force of 46.8 N to the sled, it accelerates at 0.75 m/s2. What is the
combined mass of the package and the sled? (Assume there is no friction.)
A. 62.40 kg
B. 52.50 kg
C. 96.75 kg
D. 35.10 kg
Answer:
m = 62.4 kg
Explanation:
The force applied to the sled, F = 46.8 N
Acceleration of the sled, a = 0.75 m/s²
We need to find the combined mass of the package and the sled. Let it is m. Using definition of force as follows :
F = ma
\(m=\dfrac{F}{a}\\\\m=\dfrac{46.8}{0.75}\\\\m=62.4\ kg\)
So, the mass of the package and the sled is 62.4 kg.
Answer:A
Explanation:
When an electric current exists within a conducting wire, which of the following statements describes the condition of any accompanying electric field? a. Must be zero. b. Must be parallel to current flow. c. Must be anti-parallel (opposite direction) to current flow. d. Must be perpendicular to current flow.
When an electric current exists within a conducting wire. The electric field accompanying an electric current must be perpendicular to the current flow. The correct answer is d.
When an electric current exists within a conducting wire, it creates a magnetic field around the wire. This magnetic field, in turn, creates an electric field perpendicular to the direction of the current flow. This electric field is known as the transverse electric field. The transverse electric field is responsible for many electrical phenomena, including the Hall effect, which occurs when a magnetic field is applied perpendicular to a current-carrying wire.
In the Hall effect, the magnetic field creates a voltage across the width of the wire, which can be measured to determine the magnitude of the magnetic field. Therefore, the electric field accompanying an electric current must be perpendicular to the current flow.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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The scientist who formulated the three laws of planetary motion by analyzing the data on the precise location of planets in the sky was: Group of answer choices
The scientist who formulated the three laws of planetary motion by analyzing the data on the precise location of planets in the sky was Johannes Kepler.
Kepler formulated these laws to understand the motion of planets around the sun. Kepler's three laws of planetary motion are as follows:1. First law: The orbit of each planet around the Sun is an ellipse with the Sun at one of the two foci of the ellipse. Second law: A line that connects a planet to the Sun sweeps out equal areas in equal times.
The square of the time period of any planet is proportional to the cube of the semimajor axis of its orbit. Kepler's laws are considered as the foundation of modern astronomy, as they provided a precise explanation of the motions of the planets around the Sun.
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