as the pressure on a pure substance is increased at constant temperature, a phase transition (if any) which is not observed would be

Answer:

There are 7 diatomic elements: hydrogen, nitrogen, oxygen, flourine, chlorine, iodine and bromine

Answer:

see your answer in pic

Explanation:

There can be emissions of radiations like gamma radiation. There can be emission of particles too like alpha particle. Therefore, the nuclear equation for the beta decay of Promethium-165 is

¹⁶⁵Pm\(\rightarrow\)⁰e₋₁  +  ₆₂Sm¹⁶⁵

Nuclear decay is process in which the radioactive element releases particles or radiations. Alpha particles is ⁴₂He. Alpha particle is nothing but helium particle. The kinetics that is related to nuclear decay is of first order.

The nuclear equation for the beta decay of Promethium-165 is

¹⁶⁵Pm\(\rightarrow\)⁰e₋₁  +  ₆₂Sm¹⁶⁵

Beta decay of  Promethium-165 is the emission of electron particle from the given isotope. the product is Samarium  ₆₂Sm¹⁶⁵.

Therefore, the nuclear equation for the beta decay of Promethium-165 is

¹⁶⁵Pm\(\rightarrow\)⁰e₋₁  +  ₆₂Sm¹⁶⁵

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Answer: C

Explanation: Because I just did the test lol.

Chemicals are substances that can be natural or man-made. It can both hurt and help the environment as they pollute water and can also clean water. Thus, option C is correct.

Chemicals are compounds that are synthesized artificially and have various uses and applications in various fields. They can be both beneficial and detrimental to the environment and the ecosystem.

Chemicals like that from factories, pesticides run-off from agricultural fields, drugs, microorganisms, fertilizers, radioactive substances, etc, cause water pollution by acting as contaminants.

On the contrary, chemicals can be used to clean water pollution. Chloramine and chlorine are the most common chemical disinfectants that cleanse contaminated water to make it useful.

Therefore, option C. chemicals can both clean and pollute water.

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Answer:

D - all of the above

Explanation:

Answer:

Helium

Explanation:

I believe helium is what your are looking for, you didn't quite make it clear what you wanted but hope this can be of some use.

Helium has the smallest atomic radius. This is due to trends in the periodic table, and the effective nuclear charge that holds the valence electrons close to the nucleus.

Could I have branliest, heart with 5 stars

Thanks.

The standard enthalpy of reaction is - 41.166 kJ/mol

What is enthalpy of reaction ?

For a chemical reaction, the enthalpy of reaction is the difference in enthalpy between products and reactants

What is enthalpy of formation ?

The enthalpy of formation of a substance is defined as heat change i.e heat evolved or absorbed when 1 mole of substance is formed from its elements under given conditions of temperature and pressure

The standard enthalpy of reaction is

ΔH° reaction = Σ ΔH°f ( products) - Σ ΔH°f (reactants)

                     = [ΔH°f (CO₂ g) + ΔH°f (H₂ g)] - [ ΔH°f (CO g) + ΔH°f (H₂O g)]

                     = [ -393.509 + 0 ] - [(-110.525) + (-241.818) ]

                     =   -393.509 + 352.343

                     = - 41.166 kJ/mol

Thus we can conclude that the standard enthalpy of reaction is - 41.166 kJ/mol

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Note: The correct question for the above solution is

Using the standard enthalpies of formation, what is the standard enthalpy of reaction? CO(g) + H₂O(g) = CO₂(g) + H₂(g)

ΔH°f (CO(g)) = -110.525KJ/mol

ΔH˚f (CO₂ (g)) = −393.509KJ/mol

ΔH°f (H₂O(g)) =-241.818KJ/mol

ΔH°f  (H₂(g)) = 0

Answer:

A. The measure of the amount of space a substance takes up

Explanation:

Ionic bonds, which hold the ions together, result in an ionic compound. In most cases, ionic compounds are created between metal and nonmetal components.

A calcium salt, an inorganic chloride, and an inorganic calcium salt all make up calcium dichloride. It functions as fertilizer. The ionic compound calcium chloride is created when calcium and chlorine interact. It is highly water soluble and liquescent.

Calcium chloride (CaCl2) is mostly created when hydrochloric acid reacts with limestone (CaCO3) (HCl). You can write the chemical equation like this. It is also created as a key by-product in the Solvay process, which involves reacting limestone with NaCl solution to make soda ash Na2CO3.

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Answer:

reactants

Explanation:

Answer:

Explanation:

grips with three basic problems: error; representation, which is the justification of number …

1. Structural isomers are molecules that have the same molecular formula, but different structural arrangements of their atoms.
2. There are two possible structural isomers of butane (C4H10):
n-butane and isobutane:

1. The term "structural isomers" refers to compounds that have the same molecular formula but differ in the arrangement of atoms within their structure. This difference in the arrangement leads to unique physical and chemical properties for each isomer.

2. The structural isomers of butane (C4H10) can be drawn and named as follows:

- Isomer 1: n-Butane
 Structure:
 CH3-CH2-CH2-CH3

 n-Butane is a linear chain of four carbon atoms, with each carbon atom bonded to the necessary number of hydrogen atoms to satisfy the molecular formula C4H10.

- Isomer 2: Isobutane (also known as methylpropane)
 Structure:
     CH3
      |
 CH3-C-CH3
      |
     CH3

 Isobutane has a branched structure, with three carbon atoms forming a chain and the fourth carbon atom connected as a side branch. The molecular formula is still C4H10.

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Answer:

x is calcium and y is chlorine

these are the p block elements

calcium belongs 4 th period and chlorine belongs to period 3rd

they forms ionic bond

chemical formula is

Ca+2 Cl-

CaCl2

Explanation:

give me brainly hope i helped!!!

Answer:

C

Explanation:

increase potential energy ( in motion)

Since liquids are frequently flammable, they will transition into the vapor phase when the temperature is raised high enough.

The total vapor pressure above a mixture of two volatile liquids can be forecast using Raoult's law. In fact, the more volatile molecule will have a larger mole fraction in the vapor phase than in the liquid phase, resulting in a composition of the vapor that differs from that of the two liquids.

Condensation is the term for this action. The pressure exerted by a vapour with its condensed phases (solid or liquid) in a closed system at a specific temperature is referred to as vapour pressure, also known as vapour equilibrium pressure.

The partial pressures of the constituents dictate the composition of the vapour phase in equilibrium with the solution.

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> 2.40 g of NaOH can be used to produce 6.36 g of Na2CO3 through a reaction. To determine the number of grams of Na2CO3 that can be prepared from 2.40 g of NaOH, we need to consider the stoichiometry of the reaction between NaOH and Na2CO3.

By calculating the molar mass of NaOH and Na2CO3 and applying the appropriate conversion factors, we can determine the amount of Na2CO3 that can be obtained.

The balanced chemical equation for the reaction between NaOH and Na2CO3 is:

2 NaOH + Na2CO3 → 2 Na2CO3 + H2O

From the equation, we can see that 2 moles of NaOH react with 1 mole of Na2CO3 to produce 2 moles of Na2CO3.

First, we need to calculate the molar mass of NaOH and Na2CO3:

NaOH: Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol) = 39.99 g/mol

Na2CO3: Na (22.99 g/mol) + C (12.01 g/mol) + 3 O (16.00 g/mol) = 105.99 g/mol

Next, we can set up the following proportion:

2.40 g NaOH / 39.99 g/mol NaOH = x g Na2CO3 / 105.99 g/mol Na2CO3

Solving for x, we get:

x = (2.40 g NaOH / 39.99 g/mol NaOH) * (105.99 g/mol Na2CO3)

Calculating the value of x, we can determine the number of grams of Na2CO3 that can be prepared from 2.40 g of NaOH.

Note: Remember to perform the actual calculations using the given values in order to obtain the specific result.

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Answer:

Explanation:

a )

PbS      +     2PbO   →     3Pb    +     SO₂

                  2 mole       3 moles       1 moles

b )

2 moles of PbO is required to produce 3 moles of Pb

17 moles of PbO is required to produce 3/2 x 17 moles of Pb

= 3/2 x 17 moles of Pb

= 25.5 moles of Pb .

c )

1 mole of  SO₂ needs 2 moles of PbO

27.3 mole of  SO₂ needs 2 x 27.3  moles of PbO

PbO needed = 2 x 27.3 moles

= 54.6 moles .

d )

PbS      +     2PbO   →     3Pb    +     SO₂

1 mole       2 mole    

1 mole  of  PbS requires 2 moles of PbO

17.6 mole  of  PbS requires 2 x 17.6  moles of PbO

PbO required = 2 x 17.6 moles

= 35.2 moles .

PbO available = 36 moles . So PbO is in excess .

Hence PbS is the limiting reagent .

Answer:

The answer is

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume of silver = 0.25 cm³

density = 10.5 g/cm³

The mass is

mass = 10.5 × 0.25 = 2.625

We have the final answer as

Hope this helps you

The physical quantity used to qualitatively assess if a reaction is endothermic or exothermic in calorimetry is heat.

Measurements of heat transferred to or from a substance are determined using calorimetry.

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The physical quantity used to qualitatively assess if a reaction is endothermic or exothermic in calorimetry is heat.

Measurements of heat transferred to or from a substance are determined using calorimetry.

Characteristics of endothermic reaction:

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When doubling the number of the moles of the HCl decrease the rate of HCl production because the acid convertase enzyme is converting HCl back into H⁺ and Cl⁻.

The reaction is as follows :

H⁺  +  Cl⁻  ⇄ HCl

If we double the number of the moles of the HCl , it decreases the rate of the HCl production because of the reason that  the acid convertase enzyme is converting the HCl back into the H⁺ and Cl⁻. The purpose of the  enzyme is to allow the conversion of the reactant to the product and the product back to the reactant

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The resulting NaCl concentration when 274 mL of a 0.740 M NaCl solution is mixed with 597 mL of a 0.390 M NaCl solution can be calculated using the principles of dilution and the volume ratios of the two solutions.

To find the resulting concentration, we can use the equation for dilution:

C1V1 = C2V2

Where C1 and V1 are the initial concentration and volume of the first solution, and C2 and V2 are the final concentration and volume of the diluted solution.

In this case, we have:

C1 = 0.740 M

V1 = 274 mL

C2 = ?

V2 = 274 mL + 597 mL = 871 mL

Substituting the values into the dilution equation:

(0.740 M)(274 mL) = C2(871 mL)

Solving for C2:

C2 = (0.740 M)(274 mL) / (871 mL)

C2 = 0.232 M

Therefore, the resulting NaCl concentration when the two solutions are mixed is 0.232 M.

In summary, by applying the principle of dilution and using the volume ratios of the two solutions, we can determine that the resulting NaCl concentration after mixing 274 mL of a 0.740 M NaCl solution with 597 mL of a 0.390 M NaCl solution is 0.232 M.

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For a crosslinked copolymer consisting of 35 wt% ethylene and 65 wt% propylene, the fraction of ethylene repeat units is 0.220 and the fraction of propylene repeat units is 0.780

Crosslinked copolymers consisting of 35 wt% ethylene and 65 wt% propylene can exhibit similar elastic properties to natural rubber due to their ability to form a highly crosslinked network. The fraction of repeat units in the copolymer can be determined based on the weight percentage of each monomer in the composition.

The repeat unit of the copolymer consists of both ethylene and propylene monomers. The molecular structure of the repeat unit is represented as:

\($-CH_2-CH_2-CH_2-CH(CH_3)-$\)

where the first two carbons are from the ethylene monomer and the last three carbons are from the propylene monomer.

To determine the fraction of repeat units for each monomer, we can first calculate the molecular weight of each monomer:

Ethylene: 28.05 g/mol

Propylene: 42.08 g/mol

Next, we can calculate the total molecular weight of the repeat unit:

(2 × 28.05 g/mol) + (3 × 42.08 g/mol)

= 180.35 g/mol

To determine the fraction of repeat units for each monomer, we can use the following equations:

Fraction of ethylene repeat units = (weight % ethylene / molecular weight of ethylene) / (total weight % / total molecular weight)

Fraction of propylene repeat units = (weight % propylene / molecular weight of propylene) / (total weight % / total molecular weight)

For a copolymer consisting of 35 wt% ethylene and 65 wt% propylene, we can plug in the values and get:

Fraction of ethylene repeat units = \($\frac{\frac{35}{28.05}}{\frac{0.35}{180.35}}$\)

= 0.220

Fraction of propylene repeat units = \($\frac{\frac{65}{42.08}}{\frac{0.35}{180.35}}$\)

= 0.780

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Due to the cancellation of the two opposing dipoles within the molecule, CO2 is a nonpolar molecule. Consequently, the modest dispersion forces are its main intermolecular forces.

What are the forces between molecules?

Intermolecular forces are those that exist between molecules. It differs from an intramolecular force—that is, a force that exists within a molecule—because of this. A force within a molecule would therefore resemble a covalent bond. Intermolecular force is the name for the force that exists between molecules.

What are instances of intermolecular forces?

Intermolecular forces operate between molecules. In contrast, intramolecular pressures are produced by molecules themselves. Intermolecular forces are less powerful than intramolecular forces. Intermolecular forces include the London dispersion force, dipole-dipole interaction, ion-dipole interaction, and van der Waals.

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The number of air molecules in a volume of 1.00 cm3 under the conditions of the vacuum pump is 3.65 * 10-15 moles and those that would be present at the same temperature but at 1.00 atm would be 0, 04 moles

The vacuum pump is a device that extracts gas molecules from a sealed volume, to create a partial vacuum, and is frequently used in industry, especially food.

To perform both calculations considering air as an ideal gas, the equation PV = nrt is used, in which

P = Pressure

V = Volume

n = number of moles

R = Gas constant

t = temperature

Data

t = 300K

V = 1L

P = 9.00 * 10-14 atm

R = 0.082 L Atm / mol °K .

n = ?

PV = nrt

n = PV/rt

n = 9.00 * 10-14. 1 / 0.082 . 300

n = 9.00 * 10-14 / 24.6

n = 3.65 * 10-15 moles

Data

t = 300K

V = 1L

P = 1 atm

R = 0.082 L Atm / mol °K .

n = ?

PV = nrt

n = PV/rt

n=1. 1 / 0.082 . 300

n = 1 / 24.6

n = 0.04 mole

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Answer:

double replacement

Explanation: the two elements on each side switch

If water is replaced with honey, the rheology would change as the viscosity of honey is higher than the viscosity of water. Hence, the correct option is c.

Rheology refers to the study of how materials flow and deform under the influence of external forces. Viscosity is a key factor in rheology, representing a measure of a substance's resistance to flow. Water and honey have different viscosities, with honey generally having a higher viscosity than water.

If water is replaced with honey, the rheology of the system would change. Honey's higher viscosity means it flows more slowly and resists deformation more than water. As a result, the fluid behavior would become thicker and more resistant to flow. The flow rate of the mixture would decrease, and it would require more force or pressure to move the honey compared to water.

This change in rheology can have significant implications in various applications. For example, in cooking or food processing, substituting water with honey in a recipe would affect the texture, thickness, and overall flow properties of the mixture. Similarly, in industrial processes or scientific experiments where rheological control is crucial, replacing water with honey would alter the fluid dynamics and potentially impact the desired outcome.

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Answer:

Miscible

Explanation:

Mixed completely

Explanation:

To reduce costs, powdered aluminium oxide is dissolved in molten cryolite. This ionic compound melts at a lower temperature than aluminium oxide, reducing costs.