Answer:
As the distance between a satellite in a circular orbit and the central object increases, the period of the satellite increases .
Explanation:
Answer:
Increases
Explanation:
Arthur walks 3 km north, and then turns east and walks 4 km. What is distance traveled and his displacement?
The distance travelled by Arthur is 7 km and his displacement is 5 km.
What is the distance covered by Arthur?
The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.
Distance = 3 km + 4 km
Distance = 7 km
The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.
d = √(a² + b)
where;
a is the northward motionb is the eastward motiond = √(3² + 4²)
d = 5 km
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Two resistors, 20 ohms and 30 ohms, are connected in parallel. This combination is connected in a series to an 8 ohms resistor and a battery of e.m.f. 12 volts. What is the current along 20 ohms?
Ohm's law is a fundamental principle in physics and electrical engineering that relates the current flowing through a conductor to the voltage applied across it. It states that the current (I) passing through a conductor is directly proportional to the voltage (V) across the conductor, and inversely proportional to the resistance (R) of the conductor.
The current along 20 ohms in a circuit with two resistors, 20 ohms and 30 ohms, which are connected in parallel, and this combination is connected in a series to an 8 ohms resistor and a battery of e.m.f. 12 volts can be calculated as follows: The equivalent resistance for the two resistors connected in parallel by using the formula 1/Rt = 1/R1 + 1/R2, where R1 and R2 are the resistors in parallel.1/Rt = 1/20 + 1/30 = 3/60 + 2/60 = 5/60Rt = 60/5 = 12 ohms.
The equivalent resistance of the two parallel resistors is 12 ohms.
Now, calculate the total resistance of the circuit by adding the equivalent resistance of the parallel resistors and the 8 ohms resistor.
Rtotal = 12 + 8 = 20 ohmsThe total resistance of the circuit is 20 ohms.
Finally, calculate the current along the 20 ohms resistor using Ohm's law, which states that I = V/R, where V is the voltage of the battery and R is the resistance. I = V/R = 12/20 = 0.6 A.
The current along the 20 ohms resistor is 0.6 A.
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If a 0.55 kg tennis ball is struck by a tennis racket with 12 N of force pointing right, what will be the acceleration on the tennis ball
If a 0.55 kg tennis ball is struck by a tennis racket with 12 N of force pointing right, then the acceleration on the tennis ball will be 21.82m/s²
The acceleration of a tennis ball is determined by the equation
a = F/m, where a is the acceleration, F is the force, and m is the mass. In this example, the force is 12 N and the mass is 0.55 kg. Thus, the acceleration of the tennis ball is 21.82 m/s².
a=12/0.55
=21.82 m/s²
The direction of the acceleration is determined by the direction of the force. Since the force is pointing right, the acceleration will also be pointing right. This means that the speed and velocity of the tennis ball will both increase as it moves in the right direction.
In addition, the acceleration will cause the ball to accelerate and reach a terminal velocity. This means that the speed of the ball will eventually reach a maximum and then remain constant. This is due to the force of gravity and the air resistance caused by the ball moving through the air.
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Briefly discuss:
(i) The principles of detecting thermal neutrons utilizing a Si detector.
(ii) The physics of fast neutron detection.
(iii) The principle of operation of strip detectors for charged particle detection and
their application.
Answer:
(i) Si device are coated with B or Li for neutron detection
(ii) Fast neutrons are normally first slowed down to thermal energies before measurement
(iii) The strip detectors consists of p⁺ and n implants in the region of a very thin (300 to 400 μm) depletion zone though which the neutrons traverse producing a readout based on the generated charges being directed to the cathode, p⁺, material which then transmits the charge to the device electronics
Explanation:
(i) Detection of neurons with only an Si device in not possible due to the large neutrons path in Si such that the silicon needs to be coated with B or Li which readily interact with neutrons. The neutron interaction with the reactive coating produces an alpha particle which can be detected by the semi conductor and a nucleus
(ii) Neutrons having a kinetic energy that is more than 1 MeV which as such has a velocity of more than 15,000 km/s is known as fast neutrons or fission neutrons. The fast neutrons are slowed in a nuclear reactor by neutron moderation to thermal energies
Due their high speed, fast neutrons are normally slowed down which however results in the loss of some vector properties of the neutron
Techniques for fast neutron detection includes,
1) Recoil detectors which are capable of fast neutron detection without moderation
2) Bonner spheres detector first converts the fast moving electron to slow down before detection
3) Scintillation counter are widely used but require the conversion of the neutron to a charged particles before detection
(iii) Strip detectors provide high precision measurement of a particle's crossing point which can be further improved by use of low noise electronics
Applications of silicon strip detectors include
1) Particle tracking in research in particle physics
2) Particle tracking in researches in x-spectroscopy nuclear research
3) Imaging in x-talography
4) Medical research imaging
5) Particle tracking and imaging in astrophysics.
A hematocrit is the process of stopping bleeding
O True
O False
An object placed 23.0 cm in front of a convex mirror produces an image that is one-third the size of the object. What is the focal length of the mirror?(include the proper algebraic sign to reflect the nature of the mirror)
The focal length of the convex mirror is -46.0 cm (negative sign indicating a converging mirror).
To find the focal length of a convex mirror, we can use the mirror formula:
1/f = 1/v - 1/u
where f is the focal length, v is the image distance, and u is the object distance.
Given that the object is placed 23.0 cm in front of the convex mirror, we have u = -23.0 cm (negative sign indicating that the object is on the same side as the incident light).
Let's assume the image distance v is positive since the image is formed on the opposite side of the mirror. We are told that the image is one-third the size of the object. In terms of magnification (m), we have:
m = -v/u = -1/3
Substituting the values into the mirror formula and the magnification formula, we get:
1/f = 1/v - 1/u
-1/3 = -v/23.0 - 1/-23.0
Simplifying the equation, we get:
-1/3 = (-v + 1)/23.0
Cross-multiplying and solving for v, we find:
-v + 1 = -69.0
v = 70.0 cm
Substituting the value of v back into the mirror formula, we can solve for f:
1/f = 1/70.0 + 1/-23.0
1/f = -1/46.0
f = -46.0 cm
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A ray of light travels from air to glass at an angle of incidence of 21∘, the angle of refraction is 24∘. What is the refractive index of glass?
A ray of light travels from air to glass at an angle of incidence of 21∘, the angle of refraction is 24∘. So, 1.52 is the refractive index of glass.
The refractive index of glass can be calculated using Snell's Law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the velocities of light in the two media.
The refractive index of glass can be calculated as follows:
n = sin(i) / sin(r)
where n is the refractive index, i is the angle of incidence, and r is the angle of refraction.
Using the given values, we can substitute them into the equation:
n = sin(21∘) / sin(24∘)
n ≈ 1.52
Therefore, the refractive index of glass is approximately 1.52.
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what is alpha centauri?
Alpha Centauri is the closest star system and closest planetary system to Earth's Solar System at 4.37 light-years (1.34 parsecs) from the Sun.
tyuojprtu
reterrty\(\int\limits^a_b {x} \, dx\)
∑
Write down the relation between force pressure and area
Answer:
Answer: Pressure is directly proportional to force and inversely proportional to area.
Explanation: Pressure is defined as the ratio of force applied to the area of cross section.
Mathematically,
P=\frac{F}{A}P=
A
F
where,
P = Pressure
F = Force applied
A = Area of cross-section
from above it is visible that pressure is directly proportional to the force applied which means that if force increases, pressure increases. It is also inversely proportional to the area of cross-section. So, when area of cross-section increases, pressure decreases.
The units of pressure are N/m^2N/m
2
and S.I. units for this term is Pascal (P).
In this problem you will estimate the heat lost by a typical house, assuming that the temperature inside is Tin = 20°C and the temperature outside is Tout = 0°C. The walls and uppermost ceiling of a typical house are supported by 2 x 6- inch wooden beams (kwood = 0.12 W/(mK)) with fiberglass insulation (kins = 0.04 W/(mK)) in between. The true depth of the beams is actually 5.625 inches, but we will take the thickness of the walls and ceiling to be Lwall = 18 cm to allow for the interior and exterior covering. Assume that the house is a cube of length L=9.0 m on a side. Assume that the roof has very high conductivity, so that the air in the attic is at the same temperature as the outside air. Ignore heat loss through the ground. The effective thermal conductivity of the wall (or ceiling) keff, is the area-weighted average of the thermal conductivities of the wooden beams and the fiberglass insulation that make up each of them. Allowing for the fact that the 2 x 6 beams are actually only 1.625 inches wide and are spaced 16 inches center to center, a calculation of this conductivity for the walls yields koff = 0.048 W/(mK). For simplicity, assume that the ceiling also has the same value of koff H: Submit Part B Let us assume that the winter consists of 150 days in which the outside temperature is 0°C. This will give the typical number of "heating degree days" observed in a winter along the northeastern US seaboard. (The cumulative number of heating degree days is given daily by the National Weather Service and is used by oil companies to determine when they should fill the tanks of their customers.) Given that a gallon (3.4 kg) of oil liberates Qc =1.4 x 10 J when burned, how much oil will be needed to supply the heat lost by conduction from this house over a winter? Assume that the heating system is 75% efficient.
The rate of heat loss is 52.3 kW. The amount of oil needed to supply heat lost by conduction from the house over a winter is approximately 1,156 gallons.
To calculate the rate of heat loss from the house, we can use the formula
Q/t = kA(Tin - Tout)/L
where Q/t is the rate of heat loss, k is the effective thermal conductivity, A is the surface area of the house, Tin is the temperature inside, Tout is the temperature outside, and L is the thickness of the walls and ceiling.
The surface area of the house is
A = 6L² = 6(9.0 m)² = 486 m²
The effective thermal conductivity is given as
koff = 0.048 W/(mK)
The thickness of the walls and ceiling is given as
L = 18 cm = 0.18 m
Substituting these values into the formula, we get
Q/t = (0.048 W/(mK))(486 m²)((20°C) - (0°C))/(0.18 m) = 52,320 W = 52.3 kW
Therefore, the rate of heat loss from the house is 52.3 kW.
To calculate the amount of oil needed to supply the heat lost by conduction over the winter, we need to find the total energy lost over the 150 days. The total energy lost is
E = Qt = (52.3 kW)(24 h/day)(150 days) = 224,280 kWh
Since the heating system is 75% efficient, the amount of oil needed is:
oil = E/(Qcη) = (224,280 kWh)/(1.4 x 10^8 J/g)(0.75) = 1,156 gallons (rounded to 3 significant figures)
Therefore, the amount of oil needed to supply the heat lost by conduction over the winter is approximately 1,156 gallons.
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A 2. 0-kilogram ball traveling north at 4. 0 meters per second collides head on with a 1. 0 kilogram ball traveling south at 8. 0 meters per second. What is the magnitude of the total momentum of the two balls after the collision? *
The magnitude of the total momentum of the two balls after the collision is Zero.
Expecting the collision is elastic, the total momentum is conserved, so the total momentum of the two balls after the collision will be equivalent to the total momentum before the collision.
As a result, all that is required is to determine the total momentum prior to the collision. We have, assuming that north is a positive direction:
the momentum of the ball 1: p₁ = mv = 2 kg × 4 m/s = 8 kg m/s
The momentum of ball 2: p₂ = mv = 1 kg × -8 m/s = -8 kg m/s
total momentum = p₁ + p₂ = 8 kg m/s + (-8 kg m/s) = 0
So, consequently, the total momentum will be zero following the collision.
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Which ones are false?
Organ- the human heart is made up of
cardiac cells then form heart tissue that
make the heart a beating organ
Cell- a single cell is shown in this image and
the nucleus can be seen
Tissue- one single layer of tissue is present
and is comprised of several cells
Organism- the heart is composed of several
systems to make a living unit.
Answer:
organism is false
Explanation:
The heart is an organ and not an organism because,
An organism is a group of systems that performs a specific function.
An organ is a group of tissue that performs a specific function
which of the following do plants need for photosynthesis?
Answer:
They need carbon, sunlight and water.
Explanation:
what is 6.39 times 10 to the 23rd power
Answer:
6.39*(10 to the 23rd)=
6.39*10²³
Which of the following can be considered mechanical energy?
A. a hot bowl of soup
B. plant growth
C. doing bicep curls
C. doing bicep curls.
Explanation:
why? A. is considered thermal energy.
B. is considered solar energy to chemical energy.
give reason
2- The wheel barrow is a liver.
Answer:
In a wheelbarrow, the load is in the middle. The fulcrum is at the end where the wheels touch the ground. The effort is applied at the other end where we hold the wheelbarrow. So, it is classified as a class 2 lever.
Explanation:
Btw, you spelled liver, not lever. Anyway, hope this helped you! The answer is underlined.
Which of the following is NOT an indicator of a chemical reaction?
OPTIONS
A. A phase change
B. A temperature change
C. A color change
D. A gas being created
Answer:
c
Explanation:
The changing of color of a substance is not necessarily an indicator of a chemical change. For example, changing the color of a metal does not change its physical properties. However, in a chemical reaction, a color change is usually an indicator that a reaction is occurring.
The diagram represents a closed energy system consisting of air and equal masses of copper, granite, and water in a perfectly insulated container. The temperatures were taken at the time the materials were placed inside the closed system.
Q1. In the first day after the materials were placed in the system, the temperature of the water would probably ___.
Q2. As time passes, the total energy in the system will _________.
(1) In the first day after the materials were placed in the system, the temperature of the water would probably increase.
(2) As time passes, the total energy in the system will be conserved.
What is law of conservation of energy?
The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
Based on the law of conservation of energy, when equal masses of copper, granite, air and water are in a perfectly insulated container, there will be heat transfer from one object to another.
After several hours, all the objects in the perfectly insulated container, will attain equilibrium temperature.
The equilibrium temperature attained by the objects will be greater than the initial temperature of water, lower than the initial temperature of copper, granite, and air.
Conclusively, we would say that the temperature of water will increase in the first day after the materials were placed in the system.
As time passes, the total energy in the system will be conserved since it is a perfectly insulated container, and no heat energy will be lost.
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At what distance from a 1.00*10^-5 C charge will the electric potential be 10000 V? (Unit = m)
Answer:
9.0 m
Explanation:
Applying
V = kq/r......................... Equation 1
Where V = Electric potential, q = charge, r = distance, k = Coulomb's constant.
make r the subject of the equation
r = kq/V................... Equation 2
From the question,
Given: q = 1.00×10⁻⁵ C, V = 10000 V
Constant: k = 9.0×10⁹ N⋅m²/C²
Substitute these values into equation 2
r = (9.0×10⁹×1.00×10⁻⁵)/10000
r = 9.0 m
Answer:
9.0
Explanation:
In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (For both cases, air is the second medium.)
Answer:
Among those two medium, light would travel faster in the one with a reflection angle of \(32^{\circ}\) (when light enters from the air.)
Explanation:
Let \(v_{1}\) denote the speed of light in the first medium. Let \(v_{\text{air}}\) denote the speed of light in the air. Assume that the light entered the boundary at an angle of \(\theta_{1}\) to the normal and exited with an angle of \(\theta_{\text{air}}\). By Snell's Law, the sine of \(\theta_{1}\!\) and \(\theta_{\text{air}}\!\) would be proportional to the speed of light in the corresponding medium. In other words:
\(\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}\).
When light enters a boundary at the critical angle \(\theta_{c}\), total internal reflection would happen. It would appear as if the angle of refraction is now \(90^{\circ}\). (in this case, \(\theta_{\text{air}} = 90^{\circ}\).)
Substitute this value into the Snell's Law equation:
\(\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}\).
Rearrange to obtain an expression for the speed of light in the first medium:
\(v_{1} = v_{\text{air}} \cdot \sin(\theta_{1})\).
The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.
For \(0 < \theta < 90^{\circ}\), \(\sin(\theta)\) is monotonically increasing with respect to \(\theta\). In other words, for \(\!\theta\) in that range, the value of \(\sin(\theta)\!\) increases as the value of \(\theta\!\) increases.
Therefore, compared to the medium in this question with \(\theta_{c} = 27^{\circ}\), the medium with the larger critical angle \(\theta_{c} = 32^{\circ}\) would have a larger \(\sin(\theta_{c})\). such that light would travel faster in that medium.
When looking at the brightest stars in the night sky, what intrinsic property can we estimate with the unaided eye?.
The intrinsic property that we can estimate with unaided eye, when looking at brightest stars, is temperature .
The intrinsic properties of stars are those which does not depend upon the distance of star from the earth e.g. temperature, mass, diameter, etc.
The temperature can be estimated by an unaided eye as the red stars are known to be cooler than the blue ones. The other intrinsic properties can't be predicted by unaided eye and require special optical instruments to make the observations. By the beginning of the 20th century, astronomers understood how to measure these intrinsic properties. Other than the temperature , the other important intrinsic property is the luminosity which can be determined by measuring the distance of star and its apparent brightness.
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b. Calculate the force exerted by the following objects.
i. A 25kg mass accelerating at 2 m/s²
ii. A 16 kg mass accelerating at 3 m/s²
Answer:
1. 50m/s²
2. 58m/s²
Explanation:
because you can see that
force is equals to mass into acceleration so you can simply multiply it by
F=ma
at noon, ship a is 180 km west of ship b. ship a is sailing east at 40 km/h and ship b is sailing north at 25 km/h. how fast (in km/hr) is the distance between the ships changing at 4:00 p.m.?
The distance between the ships at 4:00 p.m. remains constant, the speed at which the distance is changing is 0 km/hr.
To determine the speed at which the distance between the ships is changing at 4:00 p.m., we need to calculate the rate of change of the distance between them.
Let's first find the positions of the ships at 4:00 p.m.:
Ship A has been sailing for 4 hours at a speed of 40 km/h, so it has traveled a distance of 4 hours × 40 km/h = 160 km east from its initial position.
Ship B has been sailing for 4 hours at a speed of 25 km/h, so it has traveled a distance of 4 hours × 25 km/h = 100 km north from its initial position.
Now we can calculate the distance between the ships at 4:00 p.m. using the Pythagorean theorem:
Distance = √((east-west distance)² + (north-south distance)²)
Distance = √((180 km + 160 km)² + (0 km + 100 km)²)
Distance = √(340 km² + 100 km²)
Distance = √(115600 km²)
Distance = 340 km
Now, let's consider the time from noon to 4:00 p.m., which is 4 hours. To find the rate of change of the distance between the ships, we can calculate the derivative of the distance with respect to time:
d(Distance)/dt = d(340 km)/dt = 0
Since the distance between the ships at 4:00 p.m. remains constant, the speed at which the distance is changing is 0 km/hr.
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What is the difference between speed and velocity? A. Velocity and speed both measure an object's change in position, but velocity only depends upon the object's speed. B. Speed measures an object's change in position, while velocity measures an object's change in position per unit time. C. Velocity measures an object's rate and direction of motion, and speed measures rate only. D. Speed measures an object's change in position per unit time, while velocity measures an object's change in speed per unit time.
Answer:
C. Velocity measures an object's rate and direction of motion, and speed measures rate only.
Velocity is a vector quantity that includes both the speed (magnitude or numerical value of the rate of motion) and direction of motion. On the other hand, speed is a scalar quantity that only measures the numerical value of the rate of motion. In other words, velocity gives us information about the object's speed and the direction in which it is moving, while speed only tells us how fast the object is moving, without any information about the direction.
A boy is pulling his two sisters on a sled.
If one sister weigh 30.0 kg, the other
weights 40.0 kg, and the coefficient of
kinetic friction is 0.120, how much force
is required to pull the sled?
[?] N
Answer:
Explanation:
The oly way we can figure this out is if the boy is pulling the sled at a constant velocity. If not, we need a value for acceleration, and you don't have that here. If the boy is pulling the sled at a constant velocity, then the value for acceleration is 0, making this a really simple problem. I'm going with that, since there is no way to answer you otherwise. If velocity is not constant, please either repost the question or put it in the notes section under the question as it stands. If acceleration is 0, then
F - f = ma becomes
F - f = m(0) which is
F - f = 0 and
F = f which says that the applied force is the same as the frictional force. We need then to find the frictional force, which has an equation of
f = μ\(F_n\) where normal force is the same as the weight of the 2 girls. We will find that, then:
Each girl's mass is different so the normal force/weight equation is
w = (30.0)(9.8) + (40.0)(9.8) to get
w = 290 + 390 and
w = 680. Plug that into the frictional force equation:
f = (.120)(680) so
f = 82N
A cannonball is launched off a 100 m cliff horizontally with an initial velocity of 50 m/s. The goal is to have the cannonball travel a target distance of 400m. Based on this, will the cannonball reach the target distance?
a)
Yes, the cannonball will hit its goal
b)
No, the cannonball will overshoot its goal
c)
No, the cannonball will fall short of the goal
d)
More information is needed to determine the outcome
Answer: It will fall short of its goal.
Explanation: I took the quiz.
No, the cannon ball will fall short of the goal
The given parameters;
height of the cliff, h = 100 minitial horizontal velocity, \(v_0_x\) = 50 m/starget distance of the cannon, R = 400 mThe time taken for the cannon ball to fall from the given height;
\(h = v_0_y t + \frac{1}{2} gt^2\\\\100 = 0 + 0.5\times 9.8 \times t^2\\\\100 = 4.9t^2\\\\t^2 = \frac{100}{4.9} \\\\t = \sqrt{20.41} \\\\t = 4.52 \ s\)
The horizontal distance traveled by the cannon ball at this time is calculated as;
\(X = v_0_x \times t\\\\X = 50 \times 4.52\\\\X = 226 \ m\)
226 m is less than the target distance of 400 m.
Thus, we can conclude that the cannon ball will fall short of the goal.
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for rayleigh winds with an average wind speed of 8m/s: a. how many hours per year do the winds blow at less than 13 m/s?
The winds blow at less than 13 m/s for approximately 8531.3 hours per year.
For Rayleigh winds with an average wind speed of 8m/s: How many hours per year do the winds blow at less than 13 m/s?The Rayleigh wind speed distribution is described by the equation: f(v) = (v/vm²) * e^(-v²/2vm²), where vm is the most probable velocity (or the maximum of the distribution curve).
1. The probability that a wind speed is less than v is given by: P(v) = ∫ f(v') dv' from 0 to v
For this problem, the average wind speed is 8 m/s. Thus, vm = 1.2 * 8 = 9.6 m/s. The probability that a wind speed is less than 13 m/s can be computed as follows:P(13 m/s) = ∫ f(v') dv' from 0 to 13 = (1/vm²) * ∫ v' * e^(-v²/2vm²) dv' from 0 to 13= 1/9.6² * (-e^(-169/184)) + 13/9.6 * √(2/π) * Erf(13/√(2 * 9.6²))= 0.9743 ≈ 97.43%
Therefore, winds blow at less than 13 m/s for P(13m/s) = 97.43% of the time in a year.
We can calculate the number of hours per year using the following formula: Number of hours = Probability * Number of hours in a year= P(13 m/s) * 8760 hours= 0.9743 * 8760= 8531.3 hours (rounded to one decimal place)
Thus, the winds blow at less than 13 m/s for approximately 8531.3 hours per year.
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two long, parallel conductors carry currents in the same direction as shown in figure p30.63. conductor a carries a current of 130 a and is held firmly in position. conductor b carries a current ib and is allowed to slide freely up and down (parallel to a) between a set of nonconducting guides. if the mass per unit length of conductor b is 0.100 g/cm, what value of current ib will result in equilibrium when the distance between the two conductors is 2.20 cm?
Value of current \(I_{b}\) is 82.9 A
What is a current carrying conductor?A conductor carrying current generates a magnetic field around itself. In other words, it behaves like a magnet and develops a force when the magnet is brought into a magnetic field. Magnetic fields also exert equal and opposite forces on conductors through which current flows. A conducting conductor produces its own magnetic field and experiences a force when interacting with an external magnetic field.
When two energized wires are placed parallel to each other, their magnetic fields interact and exert a force between the wires. The force acting on each wire is the same in magnitude but opposite in direction. This is true even if the conductors carry currents of different magnitudes.
mg = \(\frac{4\pi * 10^{-7} }{4\pi }\) × \(\frac{2 I_{a}I_{b} l }{r}\)
Given, Iₐ = 130 A
m = 0.100 g/cm or 0.1×10⁻²g/m
So, by substituting values in the formula:
0.1×10⁻²× 9.8 = 10⁻⁷ ×\(\frac{2 * 130* I_{b} }{2.2 * 10^{-2} }\)
\(I_{b}\) = 82.9 A
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ASAP ASAP ASAP ASAP ASAP!
Using two billiard balls, design an experiment to demonstrate the law of conservation of momentum.
Just needs to be three to force complete sentences. Will mark Brainliest!
The experiments to demonstrate the conservation of momentum with the two billiard balls of known masses, m₁ and m₂, and velocities u₁ and u₂. The balls are then made to collide with velocities v₁ and v₂ after the collision
The momentum before and after the collision is then calculated as follows:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂What is the momentum of a body?The momentum of a body is the product of the mass and the velocity of the object.
Mathematically;
the momentum of a body is determined as follows:
Momentum = mass * velocity
Momentum is conserved if the momentum before and after the collision is equal.
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which energy conversion is taking place as the blades of the windmills rotate?
The energy conversion taking place as the blades of wind turbines rotate is the conversion of kinetic energy of the wind into mechanical energy, which is then converted into electrical energy by a generator
The blades of wind turbines convert the kinetic energy of the wind into mechanical energy, which is then converted into electrical energy by a generator. This process is known as wind energy conversion, where the kinetic energy of the wind is transformed into usable electricity. As the wind blows over the blades of the wind turbine, it causes the blades to rotate.
The rotation of the blades turns a rotor, which is connected to a shaft, and this shaft is connected to a generator. The rotation of the shaft in the generator creates electricity, which can then be stored or transmitted to power homes and businesses.
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