as part of the procedure, you will add benzophenone and nabh4 to a flask containing isopropanol and reflux for 30 min. what temperature will the reaction be run at during those 30 min?

Answer:

B. 8

Explanation:

Ethene, also known as ethylene, is an unsaturated hydrocarbon with the chemical formula C2H4. The molecule contains a double bond between the two carbon atoms, which is formed by sharing of two pairs of electrons. Each carbon atom is also bonded to two hydrogen atoms through single covalent bonds. Therefore, the total number of shared pairs of electrons in ethene is 4 (for the double bond) + 4 (for the four single bonds between carbon and hydrogen atoms) = 8.

The mass of PbI2 precipitated will be 18.00 g

Let's understand this in detail:

The volume of KI solution = 525.2 ml = 0.5252 L

The concentration of KI solution = 2.75 M

The volume of solution = Concentration × Volume

Mass of KI present in 1 L of solution = 2.75 × 166 = 456.5 g/L

Mass of KI present in 0.5252 L of solution = 456.5 × 0.5252 = 240.13 g

Mass of Pb(NO3)2 needed to react with KI = 2 × 240.13 = 480.26 g

The molecular weight of Pb(NO3)2 = 207.2 + (14 × 3) + (16 × 6) = 331.2 g/mol

The number of moles of Pb(NO3)2 = Mass / Molecular weight= 480.26 / 331.2 = 1.449 mol

The balanced chemical equation for the reaction is

2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq)

The number of moles of PbI2 formed = 1.449 / 2 = 0.725 mol

The molecular weight of PbI2 = 207.2 + (2 × 126.9) = 460.9 g/mol

Mass of PbI2 formed = Number of moles × Molecular weight= 0.725 × 460.9 = 334.3 g

Hence, the number of grams of lead (II) iodide will precipitate when 525.2 ml of 2.75 M potassium iodide solution is reacted with an excess lead (II) nitrate solution of 334.3 g.

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The number of grams contained in 3.23 x 10²³ particles of NaOH is 21.6g.

The mass of a substance can be calculated by multiplying the number of moles in that substance by its molar mass as follows:

Mass = no of moles × molar mass

However, the number of moles in 3.23 x 10²³ particles of NaOH compound must first be calculated as follows:

no of moles = 3.23 x 10²³ particles ÷ 6.02 × 10²³

no of moles = 0.54 moles

The mass of NaOH can be calculated as follows:

Molar mass of NaOH = 23 + 16 + 1 = 40g/mol

mass = 0.54 moles × 40g/mol

mass = 21.6g

Therefore, the number of grams contained in 3.23 x 10²³ particles of NaOH is 21.6g.

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Answer:

The Ionic compound is held by ionic bonding and this ionic bond forms between a metal and a non-metal. Here the calcium atom is the metal and the oxygen atom is a non-metal this set of atoms will form an ionic compound.

The molar mass of the gas, given that 3.25 g of the gas occupied 2.56 L is 30.66g/mol

To obtain the molar mass of the gas, we shall first obtain the number of mole of the gas. This can be obtained as follow:

PV = nRT

0.95 × 2.56 = n × 0.0821 × 280

Divide both sides by (0.0821 × 280)

n = (0.95 × 2.56) / (0.0821 × 280)

n = 0.106 mole

Haven obtain the mole of the gas, we shall determine the molar mass of the gas as follow:

Molar mass = mass / mole

Molar mass of gas = 3.25 / 0.106

Molar mass of gas = 30.66g/mol

Thus, the molar mass of the gas is 30.66g/mol

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Answer:

I think gamma, I'm not sure tho

Answer:

If some heat were transferred to the air or Styrofoam cups, the calculated enthalpy would be too low as the energy change in the system, so its C.

Explanation:

Hope this helped

If some heat were transferred to the air or Styrofoam cups, the enthalpy of solution of the unknown salt be too low.

Enthalpy is defined as the total internal energy as well as the volume times pressure of a thermodynamic system. Enthalpy is a thermodynamic system's unit of energy measurement. Enthalpy, a unit used to describe how much heat is present throughout a system, is equal to the system's internal energy plus the product of its volume and pressure.

The predicted enthalpy would be too low if heat were to be lost to the air or styrofoam cup. It would be too low since the projected temperature change would be too small due to heat loss.

Thus, if some heat were transferred to the air or Styrofoam cups, the enthalpy of solution of the unknown salt be too low.

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Citric acid is added to food to add tartness and enhance the flavor. The correct option is b.

Citric acid, a natural compound found in citrus fruits, is commonly added to food for its tart flavor and ability to enhance taste. Here's a step-by-step explanation:

1. Tartness: Citric acid is highly acidic and has a sour taste. When added to food, it provides a sharp, tangy flavor that adds tartness. This tartness can help balance the overall taste profile of a dish, especially in sweet or savory recipes.

2. Flavor enhancement: Citric acid acts as a flavor enhancer, intensifying the existing flavors in food. It has the ability to enhance the perception of other taste sensations, such as sweetness and saltiness, making food taste more vibrant and flavorful.

3. Preservation: Citric acid also acts as a natural preservative in some food products. It has antimicrobial properties that inhibit the growth of certain bacteria and fungi, helping to extend the shelf life of foods and prevent spoilage.

4. pH adjustment: Citric acid can be used to adjust the pH level of certain food products. It is commonly used in canning and preserving processes to create an acidic environment that inhibits bacterial growth and helps maintain product quality and safety.

Overall, the addition of citric acid to food primarily serves to enhance flavor, provide tartness, and potentially contribute to preservation. Option b is the correct one.

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Answer:

don't no answer

Explanation:

d don't no answer

The number of grams of Na₂CO₃ required to neutralize 30 ml of 0.05 N HCl is 1.05 g.

The equation for the neutralization reaction between Na₂CO₃ and HCl is given as follows;

Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂

The molarity of HCl is given as 0.05 N and the volume of HCl used is 30 ml, which is equal to 0.03 L. Therefore, the number of moles of HCl used is given as follows;

The number of moles of HCl = Molarity × Volume = 0.05 N × 0.03 L = 0.0015 mol

Using the equation above, it can be seen that one mole of Na₂CO₃ reacts with two moles of HCl. Therefore, the number of moles of Na₂CO₃ required is;

A number of moles of Na₂CO₃ = 0.0015 mol ÷ 2 = 0.00075 mol

The molar mass of Na₂CO₃ is given as 106 g/mol.

Therefore, the number of grams of Na₂CO₃ required is;

Mass of Na2CO3 = Number of moles of Na2CO3 × Molar mass

Mass of Na2CO3 = 0.00075 mol × 106 g/mol = 0.0795 g ≈ 1.05 g.

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Combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.

CₓHₐ + O2 → CO2 + H2O Since the combustion is complete, so the total mass of the reactants is equal to the total mass of the reactants Therefore, Mass of O2 = (17.9 + 9.14) – 5.9 = 21.14 grams Here, the empirical formula for the hydrocarbon is CₓHₐ. So, now we have to need to determine the number of moles of the O2, CO2, and H2O :- Mole of CO2 = 17.9/44 = 0.4068 Mole of H2O = 9.14/18 = 0.5078 Mole of O2 = 21.14/32 = 0.6606. The empirical formula for the compound containing uranium and fluorine is UF6. Explanation: The empirical formula of a compound represents the lowest whole number ratio of elements in the compound. This ratio is represented by subscripts in the formula. by this information, we can consider that combustion analysis of fluorene, a polycyclic aromatic hydrocarbon used to make dyes, plastics, and pesticides, produces 11.44 g CO2 and 1.80 g H2O. The empirical formula of fluorene C₆H₄.

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Answer:

fewer collisions occur between particles or lowering the temperature

Explanation:

The standard enthalpy change for the reaction 2A+B⇌2C+2D is  664 kJ/mol and The heat that is absorbed when 3.70 mol of A reacts is 2456.8  J

The heat changes that take place as reactants combine to generate a product are measured by the enthalpy of a reaction.

The following formula can be used to determine the enthalpy change of a reaction:

Hess's law states that

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Considering the given reaction: 2A + B ⇌ 2C + 2D  

Enthalpy of reaction =  product's enthalpy - the reactant's enthalpy.

Enthalpy of reaction (ΔH°f) = (2 C + 2 D) - (2 * A + B)

Enthalpy of reaction  (ΔH°f)  = {[2(223) + 2(-523)] - [2(-245) + 2(-387)]}

Enthalpy of reaction  (ΔH°f)  = 664 kJ/mol

ΔH = q ÷ n

ΔH = molar enthalpy (heat) of solution

q = amount of energy (heat) released or absorbed

n = moles of solute

so. q = ΔH xn

q = ΔH xn

q = 664 kJ/mol x 3.70 mol

Q= 2456.8  J

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Answer:

V = 0.41L

Explanation:

\(c=\frac{n}{V}\\n=cV\\14.7=6.0V\\ \\V=0.41l\)

Answer:

NaHCO3 = No. of atoms in one molecule is 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

We double it for two molecules, so 12 Molecules!

Explanation:

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The calculated molar ratio of iron to oxygen in BIFs is 1.452.

Comparing this ratio to the molar ratios of Hematite (1:0.75) and Magnetite (1:0.67), we can see that the calculated value of 1.452 is closest to the Hematite molar ratio of 1:0.75. Therefore, Hematite is the more dominant iron component in BIFs.

To calculate the mass of oxygen contained within BIFs, we'll use the given information:

Total mass of the modern atmosphere = 5.01×10¹⁸ kg

Percentage of oxygen in the modern atmosphere = 21%

Mass of oxygen contained within the modern atmosphere = (5.01×10¹⁸ kg) × (0.21) = 1.051×10¹⁸ kg

Percentage of oxygen contained in BIFs = 6.6% (given)

Mass of oxygen contained within BIFs = (6.6% of 1.051×10¹⁸ kg) = 6.6/100 × 1.051×10¹⁸ kg = 6.9166×10¹⁶ kg

Therefore, the mass of oxygen contained within BIFs is 6.9166 × 10¹⁶ kg.

To calculate the number of moles of oxygen contained within BIFs, we'll use the molecular mass of O₂:

Molecular mass of O₂ = 0.032 kg/mole

Number of moles of oxygen contained within BIFs = (Mass of oxygen in BIFs) / (Molecular mass of O₂)

= (6.9166×10¹⁶ kg) / (0.032 kg/mole) = 2.1614375 × 10¹⁸ moles

Therefore, the number of moles of oxygen contained within BIFs is 2.1614375 × 10¹⁸ moles.

Next, let's calculate the mass of iron in BIFs:

Total mass of BIFs = 5.0×10¹⁷ kg

Percentage of iron in BIFs = 35%

Mass of iron contained within BIFs = (35% of 5.0×10¹⁷ kg) = 35/100 × 5.0×10¹⁷ kg = 1.75×10¹⁷ kg

To calculate the number of moles of iron contained within BIFs, we'll use the atomic mass of iron:

Atomic mass of iron = 0.0558 kg/mole

Number of moles of iron contained within BIFs = (Mass of iron in BIFs) / (Atomic mass of iron)

= (1.75×10¹⁷ kg) / (0.0558 kg/mole) = 3.1367419 × 10¹⁸ moles

Therefore, the number of moles of iron contained within BIFs is 3.1367419 × 10¹⁸ moles.

Finally, let's calculate the molar ratio of iron to oxygen in BIFs:

Molar ratio of iron to oxygen = (Number of moles of iron) / (Number of moles of oxygen)

= (3.1367419 × 10¹⁸ moles) / (2.1614375 × 10¹⁸ moles)

≈ 1.452

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l = 0 → s = 2 electrons, l = 1 → p = 6 electrons, l = 2 → d = 10 electrons, l= 3 → f = 14 electrons.

The smallest elemental component of an atom, the electron has a negative charge. The smallest elemental component of an atom, the electron has a negative charge. In a negative ion, there are an adequate amounts of both electrons and protons.

According to the subatomic particles, the orbit region of space has a higher likelihood of harboring an electron. It is impossible to simultaneously detect the electron's location and velocity (uncertainty principle). Therefore, the theory establishes five electron density to represent one electron, making it simple to recognize it:

→n is the principal quantum number and identify the shell where the electron is.It ranges from 1 to 7, and the consonants K, L, m actually, N, O, P, etc Q stand in for it;

→l is the azimuthal quantum number and identify the subshell (or sublevel) where the electron is. The consonants s, p, d, or f stand in for it, which ranges from 0 to 3;

→ml is the magnetic quantum number, and it represents the orbital. It varies from -l to +l, passing by 0. There can be at least two electrons in each orbital;

→ms is the spin number and represents the spin of the electrons. The range is +1/2 to -1/2.

The sublevel s (l = 0) only has one orbital, enabling it to have at least two electrons; the subarea p (l = 1) has three orbitals, so it can and has at least six electrons; the subarea d (l = 2) has five orbitals, so it can would have had at least ten electrons; and the basement level f (l = 3) has seven orbitals, enabling it to have at least fourteen electrons.

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Answer:

I think its false hope I helped pliz mark brainlist

the bond that magnesium and oxygen is going to be ionic bond

Answer:

4.00 moles of water

Explanation:

The equation of the reaction is:

2 C2H2Cl (9) + 5O2(g) -------> 4CO2 (g) + 2 H20( g) + 2 HCl(g)

To find the limiting reactant,  we find the species that yields the lowest number of moles of water.

From the reaction equation;

2 moles of C2H2Cl  yields 2 moles of water

10 moles of C2H2Cl  yields 10 * 2/2 = 10 moles of water

Similarly;

5 moles of oxygen yields 2 moles of water

10 moles of oxygen will yield 10 *2/5 =4 moles of water

Hence oxygen is the limiting reactant.

10 moles of oxygen yields 4 moles of water.

Answer:

Density=189.9/226ml.

Explanation:

total mass=91.2g.

41.6ml-19ml=22.6ml of the object.

mass of the object=91.2-71.21=18.99g.

so D=M/V.

D=18.99/22.6.

D=189.9g/226ml

Answer: A diamond is a heterogeneous mixture. But it could be considered a element because it is made out of carbon which is an element.

Explanation:

The money and the metals did not rust after putting them in water and vegetable oil respectively as money is made up of alloy and oil on metals prevented the process of corrosion.

Corrosion is defined as a natural process where in the metal reacts with oxygen to form a stable oxide and thus leading to the deterioration of the metal, on exposure of the metal to the environment.

Most common form of corrosion is electrochemical oxidation or rusting wherein iron oxides are formed.Rusting usually produces a metallic oxide and a distinct change in color.Corrosion can also take place in ceramics,polymers but in this case the term degradation of ceramics or polymers is more common.

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Answer:

The correct statement about X-rays are:

X-rays have higher associated energy and can pass through skin and muscle tissue; option A and

Radar waves have a wavelength that is larger and can detect more substantial objects without passing through them; option C.

Explanation:

Gas molecules are assumed to be in constant random motion and to collide perfectly elastically with one another in this theory. They bounce off one another. These particles are assumed to be spherical. There are also no interactions between the molecules.

According to kinetic molecular theory, gas particles are in constant motion and have perfectly elastic collisions. Both Charles' and Boyle's laws can be explained using kinetic molecular theory. The average kinetic energy of a gas particle collection is only proportional to absolute temperature.

Collisions are perfectly elastic; when two molecules collide, their kinetic energies and directions change, but the total kinetic energy remains constant. Collisions do not have a "sticky" effect. The absolute temperature is directly proportional to the average kinetic energy of the gas molecules.

Thus,The two molecules will stay together because they are attracted to each other.

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Answer:

Covalent bond

Explanation:

A covalent bond is formed when two atoms share electrons. The shared electrons are positioned between the nuclei of the bonding atoms.

In the bonding between chlorine and hydrogen, chlorine has seven valence electrons. Hence, it needs one more electron in order for the atom to attain an octet structure. Hydrogen has one valence electron and needs one more electron in order to attain a duplet structure.

The two bonding atoms now share two electrons(provided by each of the bonding atoms) in a covalent bond such that chlorine has a complete octet and hydrogen has a complete duplet.

The process by which water and dissolved particles are forced through the capillary walls into the Bowman's capsule is called filtration.

This occurs in the renal corpuscle of the kidney, where blood flows into the glomerulus, a network of capillaries surrounded by the Bowman's capsule.

The pressure from the blood flowing through the glomerulus forces water and small molecules such as ions, glucose, and amino acids, through the capillary walls and into the Bowman's capsule, while larger molecules such as proteins and blood cells are retained in the capillaries.

This process of filtration is essential for the formation of urine, which is then processed and excreted by the body through the urinary system.

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The major organic product of the bimolecular substitution between (CH3)2CHOH and NaI is (CH3)2CHI with non bonding electrons . The curved-arrow notation mechanism shows the attack of the iodide ion on the carbon atom and the departure of the hydroxyl group as a leaving group.

To draw the major organic product of the bimolecular substitution and the mechanism with curved-arrow notation, follow these steps:

Step 1: Draw curved arrows
Starting with the given reactants, (CH3)2CHOH and NaI, the hydroxyl group (-OH) on the alcohol will be replaced by iodide (I-) in a bimolecular substitution (SN2) reaction. First, draw the (CH3)2CHOH molecule, and then draw a curved arrow from the lone pair of electrons on the iodide ion (I-) to the carbon atom bonded to the hydroxyl group. Next, draw a curved arrow from the bond between the carbon and oxygen atoms to the oxygen atom in the hydroxyl group.

Step 2: Draw the product with electrons
Now, draw the major organic product resulting from the bimolecular substitution. The product will be (CH3)2CHI, with the iodine atom replacing the hydroxyl group. Make sure to show the non-bonding electrons on the iodine and oxygen atoms, and any other atoms with lone pairs (such as the negatively charged oxygen atom in the leaving hydroxide ion, OH-).
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Answer:

When measuring a patient's height growth over 10 years

Explanation: